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  • Using .htaccess to change my website URLs

    - by James P
    I have some pages organised like this: http://localhost/index.html http://localhost/download.html http://localhost/contact.html And I need them changed to suit the following URL structure: http://localhost/ http://localhost/download http://localhost/contact Without making sub directories and putting in pages as index.html. As far as I know .htaccess can be used for this, but I have no idea what I need to add to my .htaccess file to make this work. Can anyone provide some help? Thanks.

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  • not rewriting .asp files using htaccess

    - by user2939099
    I have .asp files re-writing themselves to .php files using htaccess and a rewrite rule on another site. it works fine but I am trying to do the same on my other site with one URL and it doesn't work. both have mod_rewrite enabled and on similar servers. (Apache v3.22.17 rev9999 / PHP v5.4.21) <IfModule mod_rewrite.c> RewriteEngine On RewriteRule ^(.+).(asp)$ $1.php [L] </IfModule> this is the full htaccess code.. can you see anything wrong with this?

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  • Apache/mod_rewrite > Tomcat encoding %26 and "&"...

    - by user293479
    Apache is the front-end to my web app then I use mod_rewrite to proxy the request to JBoss. So far this sounds pretty standard, but the problem I am having is: if I access the app directly through jboss @ http://localhost:8080/app/page?raw=foo%26bar&page=1: request.getParameter("raw") = foo&bar If I access the app through Apache @ http://localhost/foo%26bar&page=1 request.getParameter("raw") = foo So somewhere along the way, the %26 is lost and replaced with an & which chops the raw variable. This is my Apache rewrite rule. RewriteRule ^/(.*) \ http://localhost:8080/app/home?raw=$1 [L,P] The Apache access log shows: http://localhost/foo%26bar&page=1 And the rewrite log shows: http://localhost:8080/app/home?raw=foo&bar&page=1 But I want the request to be: http://localhost:8080/app/home?raw=foo%26bar&page=1 I am pretty sure that this also occurs with slashes / too so to me this is some sort of encoding issue. Is there a way to proxy the URL untouched? Can't seem to figure this one out.

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  • How to rewrite a URL with %23 in it?

    - by Jan P.
    I have a (wordpress) blog where after commenting the users are redirected back to the page with an anchor to their comment. Should look like this: http://example.org/foo-bar/#comment-570630 But somehow I get a lot of 404 ins my logfiles for such URLs: http://example.org/foo-bar/%23comment-570630 Is there a way to write a .htaccess rewrite rule to fix this? Bonus question: Any idea why this happens and what I can do about it?

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  • mod_rewrite replace all instances of ampersand with %26 for later

    - by Supernovah
    Hey there! I want to simply not use ampersand in my URL so I can pass ampersands further down into my system when a file is requested. The problem is Apache deals with it differently. I don't know how I already rewrite the requested file to index.php?url=$1 so I can see what it was, but if it has an ampersand in there, it can't continue past it! how can I escape the ampersand or turn it into it's hex equal (%26)? <IfModule mod_rewrite.c> RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*)$ index.php?url=$1 [QSA,L] </IfModule>`

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  • Hiding a HTTP Auth-Realm by sending 404 to non-known IPs?

    - by zhenech
    I have an Apache (2.2) serving a web-app on example.com. That web-app has a debug-page reachable via example.com/debug. /debug is currently protected with a HTTP basic auth. As there is only a very small user-base who has access to the debug-page, I would like to hide it based on IP address and return 404 to clients not accessing from our VPN. Serving a 404 based on IP-address only is easy and is described in http://serverfault.com/a/13071. But as soon I add authentication, the users see a 401 instead of a 404. Basically, what I need is: if ($REMOTE_ADDR ~ 10.11.12.*): do_basic_auth (aka return 401) else: return 404

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  • auth user and exec a node app only with apache?

    - by Blame
    I couldn't find an answer on the web and I'm trying for days now so I hope that someone with more experience with apache can help me out. Iam writing an web editor and the user should be able to edit a file that is on the server in a directory the user has access to. The problem Iam facing is that I need to authenticate against the system users (shadow/passwd). So the user should be able to login whith a system account and then the node app which does all the logic should be started with the users rights. I hope to get this working without any additional script and only with Apache. I found out two things: I can use mod_auth_pam to authenticate the user There is a mod called suEXEC which can exec the node app with a specified user The problem is that I have to hard code which user is used by suEXEC but I want to decide when the user logs in. Is there any way to authenticate a user against the shadow/passwd and then exec a prog with the users rights? I dont want to run the node app as root and the user should only be able to access his own files. Any help would be appreciated! Thanks, Kodak

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  • vsftp login errors 530 login incorrect

    - by mcktimo
    Using Ubuntu 10.04 on an aws ec2 instance. I was happy just using ssh but then a wordpress plugin needs ftp access...I just need ftp access for one site www.sitebuilt.net which is in /home/sitebuil. I installed a vftpd and pam and followed suggestions that got me to the following state /etc/vftpd.conf listen=YES anonymous_enable=NO local_enable=YES write_enable=YES dirmessage_enable=YES use_localtime=YES xferlog_enable=YES connect_from_port_20=YES xferlog_file=/var/log/vsftpd.log secure_chroot_dir=/var/run/vsftpd/empty pam_service_name=vsftpd rsa_cert_file=/etc/ssl/private/vsftpd.pem guest_enable=YES user_sub_token=$USER local_root=/home/$USER chroot_local_user=YES hide_ids=YES check_shell=NO userlist_file=/etc/vsftpd_users /etc/pam.d/vsftpd # Standard behaviour for ftpd(8). auth required pam_listfile.so item=user sense=deny file=/etc/ftpusers onerr=succeed # Note: vsftpd handles anonymous logins on its own. Do not enable pam_ftp.so. # Standard pam includes @include common-account @include common-session @include common-auth auth required pam_shells.so # Customized login using htpasswd file auth required pam_pwdfile.so pwdfile /etc/vsftpd/passwd account required pam_permit.so session optional pam_keyinit.so force revoke auth include system-auth account include system-auth session include system-auth session required pam_loginuid.so /etc/vsftpd_users sitebuil tim /etc/passwd ... sitebuil:x:1002:100:sitebuilt systems:/home/sitebuil:/bin/sh ftp:x:108:113:ftp daemon,,,:/srv/ftp:/sbin/nologin /etc/vsftpd/passwd sitebuil:Kzencryptedpwd /var/log/vftpd.log Wed Feb 29 15:15:48 2012 [pid 20084] CONNECT: Client "98.217.196.12" Wed Feb 29 15:16:02 2012 [pid 20083] [sitebuil] FAIL LOGIN: Client "98.217.196.12" Wed Feb 29 16:12:33 2012 [pid 20652] CONNECT: Client "98.217.196.12" Wed Feb 29 16:12:45 2012 [pid 20651] [sitebuil] FAIL LOGIN: Client "98.217.196.12"

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  • Linux authentication via ADS -- allowing only specific groups in PAM

    - by Kenaniah
    I'm taking the samba / winbind / PAM route to authenticate users on our linux servers from our Active Directory domain. Everything works, but I want to limit what AD groups are allowed to authenticate. Winbind / PAM currently allows any enabled user account in the active directory, and pam_winbind.so doesn't seem to heed the require_membership_of=MYDOMAIN\\mygroup parameter. Doesn't matter if I set it in the /etc/pam.d/system-auth or /etc/security/pam_winbind.conf files. How can I force winbind to honor the require_membership_of setting? Using CentOS 5.5 with up-to-date packages. Update: turns out that PAM always allows root to pass through auth, by virtue of the fact that it's root. So as long as the account exists, root will pass auth. Any other account is subjected to the auth constraints. Update 2: require_membership_of seems to be working, except for when the requesting user has the root uid. In that case, the login succeeds regardless of the require_membership_of setting. This is not an issue for any other account. How can I configure PAM to force the require_membership_of check even when the current user is root? Current PAM config is below: auth sufficient pam_winbind.so auth sufficient pam_unix.so nullok try_first_pass auth requisite pam_succeed_if.so uid >= 500 quiet auth required pam_deny.so account sufficient pam_winbind.so account sufficient pam_localuser.so account required pam_unix.so broken_shadow password ..... (excluded for brevity) session required pam_winbind.so session required pam_mkhomedir.so skel=/etc/skel umask=0077 session required pam_limits.so session required pam_unix.so require_memebership_of is currently set in the /etc/security/pam_winbind.conf file, and is working (except for the root case outlined above).

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  • Route URL laravel 4

    - by nabil l.
    How can I do this in Laravel 4 URL::route('auth.reset', array('kh34KHh4K342')) Instead of http://domain.tld/auth/reset?kh34KHh4K342 I want to get this : http://domain.tld/auth/reset/kh34KHh4K342 EDIT This my routes.php : The problem is because I have two routes with the same name? How do you explain that ? Should i set a different name event is the same kind, and different methods // Set locale $locale = Request::segment(1); if(in_array($locale, Config::get('app.languages'))) { \App::setLocale($locale); } else { $locale = null; } Route::group( array( 'prefix' => $locale ), function () { Route::get('/'), array( 'uses' => 'HomeController@getIndex', 'as' => '/' )); // Auth Route::group( array( 'prefix' => 'auth' ), function () { // Login Route::get( 'login', array( 'before' => 'guest', 'uses' => 'UserController@getLogin', 'as' => 'auth.login' ) ); Route::post( 'login', array( 'before' => 'guest|csrf', 'uses' => 'UserController@postLogin', 'as' => 'auth.login' ) ); Route::get( 'reset/{$token}', array( 'uses' => 'UserController@getReset', 'as' => 'auth.reset' ) ); Route::post( 'reset', array( 'uses' => 'UserController@postReset', 'as' => 'auth.reset' ) ); } );

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  • PostgreSQL pg_hba.conf with "password" auth wouldn't work with PHP pg_connect?

    - by tftd
    I've recently experimented with the settings in pg_hba.conf. I read the PostgreSQL documentation and I though that the "password" auth method is what I want. There are many people that have access to the server PostgreSQL is working on so I don't want the "trust" method. So I changed it. But then PHP stopped working with the database. The message I get is "Warning: pg_connect(): Unable to connect to PostgreSQL server: FATAL: password authentication failed for user "myuser" in /my/path/to/connection/class.php on line 35". It is kind of strange because I can connect via phppgadmin without any problems and also I can connect from my home computer with psql - again without any problems. This is my pg_hba.conf: # TYPE DATABASE USER CIDR-ADDRESS METHOD # "local" is for Unix domain socket connections only local all all password # IPv4 local connections: host all all 127.0.0.1/32 password # IPv6 local connections: host all all ::1/128 password The connection string I'm using with pg_conenct is: $connect_string = "host=localhost port=5432 dbname=mydbname user=auser password=apassword"; $dbConnection = pg_connect($connection_string); Does anybody know why is this happening ? Did I misconfigured something ?

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  • "AND Operator" in PAM

    - by d_inevitable
    I need to prevent users from authenticating through Kerberos when the encrypted /home/users has not yet been mounted. (This is to avoid corrupting the ecryptfs mountpoint) Currently I have these lines in /etc/pam.d/common-auth: auth required pam_group.so use_first_pass auth [success=2 default=ignore] pam_krb5.so minimum_uid=1000 try_first_pass auth [success=1 default=ignore] pam_unix.so nullok_secure try_first_pass I am planning to use pam_exec.so to execute a script that will exit 1 if the ecyptfs mounts are not ready yet. Doing this: auth required pam_exec.so /etc/security/check_ecryptfs will lock me out for good if ecryptfs for some reason fails. In such case I would like to at least be able to login with a local (non-kerberos) user to fix the issue. Is there some sort of AND-Operator in which I can say that login through kerberos+ldap is only sufficient if both kerberos authentication and the ecryptfs mount has succeeded?

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  • How to stop registration attempts on Asterisk

    - by Travesty3
    The main question: My Asterisk logs are littered with messages like these: [2012-05-29 15:53:49] NOTICE[5578] chan_sip.c: Registration from '<sip:[email protected]>' failed for '37.75.210.177' - No matching peer found [2012-05-29 15:53:50] NOTICE[5578] chan_sip.c: Registration from '<sip:[email protected]>' failed for '37.75.210.177' - No matching peer found [2012-05-29 15:53:55] NOTICE[5578] chan_sip.c: Registration from '<sip:[email protected]>' failed for '37.75.210.177' - No matching peer found [2012-05-29 15:53:55] NOTICE[5578] chan_sip.c: Registration from '<sip:[email protected]>' failed for '37.75.210.177' - No matching peer found [2012-05-29 15:53:57] NOTICE[5578] chan_sip.c: Sending fake auth rejection for device <sip:[email protected]>;tag=cb23fe53 [2012-05-29 15:53:57] NOTICE[5578] chan_sip.c: Sending fake auth rejection for device <sip:[email protected]>;tag=cb23fe53 [2012-05-29 15:54:02] NOTICE[5578] chan_sip.c: Registration from '<sip:[email protected]>' failed for '37.75.210.177' - No matching peer found [2012-05-29 15:54:03] NOTICE[5578] chan_sip.c: Registration from '<sip:[email protected]>' failed for '37.75.210.177' - No matching peer found [2012-05-29 21:20:36] NOTICE[5578] chan_sip.c: Registration from '"55435217"<sip:[email protected]>' failed for '65.218.221.180' - No matching peer found [2012-05-29 21:20:36] NOTICE[5578] chan_sip.c: Registration from '"1731687005"<sip:[email protected]>' failed for '65.218.221.180' - No matching peer found [2012-05-30 01:18:58] NOTICE[5578] chan_sip.c: Sending fake auth rejection for device "unknown" <sip:[email protected]>;tag=dEBcOzUysX [2012-05-30 01:18:58] NOTICE[5578] chan_sip.c: Sending fake auth rejection for device "unknown" <sip:[email protected]>;tag=9zUari4Mve [2012-05-30 01:19:00] NOTICE[5578] chan_sip.c: Sending fake auth rejection for device "unknown" <sip:[email protected]>;tag=sOYgI1ItQn [2012-05-30 01:19:02] NOTICE[5578] chan_sip.c: Sending fake auth rejection for device "unknown" <sip:[email protected]>;tag=2EGLTzZSEi [2012-05-30 01:19:04] NOTICE[5578] chan_sip.c: Sending fake auth rejection for device "unknown" <sip:[email protected]>;tag=j0JfZoPcur [2012-05-30 01:19:06] NOTICE[5578] chan_sip.c: Sending fake auth rejection for device "unknown" <sip:[email protected]>;tag=Ra0DFDKggt [2012-05-30 01:19:08] NOTICE[5578] chan_sip.c: Sending fake auth rejection for device "unknown" <sip:[email protected]>;tag=rR7q7aTHEz [2012-05-30 01:19:10] NOTICE[5578] chan_sip.c: Sending fake auth rejection for device "unknown" <sip:[email protected]>;tag=VHUMtOpIvU [2012-05-30 01:19:12] NOTICE[5578] chan_sip.c: Sending fake auth rejection for device "unknown" <sip:[email protected]>;tag=JxZUzBnPMW I use Asterisk for an automated phone system. The only thing it does is receives incoming calls and executes a Perl script. No outgoing calls, no incoming calls to an actual phone, no phones registered with Asterisk. It seems like there should be an easy way to block all unauthorized registration attempts, but I have struggled with this for a long time. It seems like there should be a more effective way to prevent these attempts from even getting far enough to reach my Asterisk logs. Some setting I could turn on/off that doesn't allow registration attempts at all or something. Is there any way to do this? Also, am I correct in assuming that the "Registration from ..." messages are likely people attempting to get access to my Asterisk server (probably to make calls on my account)? And what's the difference between those messages and the "Sending fake auth rejection ..." messages? Further detail: I know that the "Registration from ..." lines are intruders attempting to get access to my Asterisk server. With Fail2Ban set up, these IPs are banned after 5 attempts (for some reason, one got 6 attempts, but w/e). But I have no idea what the "Sending fake auth rejection ..." messages mean or how to stop these potential intrusion attempts. As far as I can tell, they have never been successful (haven't seen any weird charges on my bills or anything). Here's what I have done: Set up hardware firewall rules as shown below. Here, xx.xx.xx.xx is the IP address of the server, yy.yy.yy.yy is the IP address of our facility, and aa.aa.aa.aa, bb.bb.bb.bb, and cc.cc.cc.cc are the IP addresses that our VoIP provider uses. Theoretically, ports 10000-20000 should only be accessible by those three IPs.+-------+-----------------------------+----------+-----------+--------+-----------------------------+------------------+ | Order | Source Ip | Protocol | Direction | Action | Destination Ip | Destination Port | +-------+-----------------------------+----------+-----------+--------+-----------------------------+------------------+ | 1 | cc.cc.cc.cc/255.255.255.255 | udp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 10000-20000 | | 2 | any | tcp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 80 | | 3 | any | tcp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 2749 | | 4 | any | tcp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 443 | | 5 | any | tcp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 53 | | 6 | any | tcp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 1981 | | 7 | any | tcp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 1991 | | 8 | any | tcp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 2001 | | 9 | yy.yy.yy.yy/255.255.255.255 | udp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 137-138 | | 10 | yy.yy.yy.yy/255.255.255.255 | tcp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 139 | | 11 | yy.yy.yy.yy/255.255.255.255 | tcp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 445 | | 14 | aa.aa.aa.aa/255.255.255.255 | udp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 10000-20000 | | 17 | bb.bb.bb.bb/255.255.255.255 | udp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 10000-20000 | | 18 | any | tcp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 1971 | | 19 | any | tcp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 2739 | | 20 | any | tcp | inbound | permit | xx.xx.xx.xx/255.255.255.255 | 1023-1050 | | 21 | any | all | inbound | deny | any on server | 1-65535 | +-------+-----------------------------+----------+-----------+--------+-----------------------------+------------------+ Set up Fail2Ban. This is sort of working, but it's reactive instead of proactive, and doesn't seem to be blocking everything (like the "Sending fake auth rejection ..." messages). Set up rules in sip.conf to deny all except for my VoIP provider. Here is my sip.conf with almost all commented lines removed (to save space). Notice at the bottom is my attempt to deny all except for my VoIP provider:[general] context=default allowguest=no allowoverlap=no bindport=5060 bindaddr=0.0.0.0 srvlookup=yes disallow=all allow=g726 allow=ulaw allow=alaw allow=g726aal2 allow=adpcm allow=slin allow=lpc10 allow=speex allow=g726 insecure=invite alwaysauthreject=yes ;registertimeout=20 registerattempts=0 register = user:pass:[email protected]:5060/700 [mysipprovider] type=peer username=user fromuser=user secret=pass host=sip.mysipprovider.com fromdomain=sip.mysipprovider.com nat=no ;canreinvite=yes qualify=yes context=inbound-mysipprovider disallow=all allow=ulaw allow=alaw allow=gsm insecure=port,invite deny=0.0.0.0/0.0.0.0 permit=aa.aa.aa.aa/255.255.255.255 permit=bb.bb.bb.bb/255.255.255.255 permit=cc.cc.cc.cc/255.255.255.255

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  • In Asp.Net MVC 2 is there a better way to return 401 status codes without getting an auth redirect

    - by Greg Roberts
    I have a portion of my site that has a lightweight xml/json REST API. Most of my site is behind forms auth but only some of my API actions require authentication. I have a custom AuthorizeAttribute for my API that I use to check for certain permissions and when it fails it results in a 401. All is good, except since I'm using forms auth, Asp.net conveniently converts that into a 302 redirect to my login page. I've seen some previous questions that seem a bit hackish to either return a 403 instead or to put some logic in the global.asax protected void Application_EndRequest() that will essentially convert 302 to 401 where it meets whatever criteria. Previous Question Previous Question 2 What I'm doing now is sort of like one of the questions, but instead of checking the Application_EndRequest() for a 302 I make my authorize attribute return 666 which indicates to me that I need to set this to a 401. Here is my code: protected void Application_EndRequest() { if (Context.Response.StatusCode == MyAuthAttribute.AUTHORIZATION_FAILED_STATUS) { //check for 666 - status code of hidden 401 Context.Response.StatusCode = 401; } } Even though this works, my question is there something in Asp.net MVC 2 that would prevent me from having to do this? Or, in general is there a better way? I would think this would come up a lot for anyone doing REST api's or just people that do ajax requests in their controllers. The last thing you want is to do a request and get the content of a login page instead of json.

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  • Multiple dex files define Lcom/google/api/client/auth/oauth/AbstractOAuthGetToken;

    - by Elad Benda
    I have just followed this tutorial: https://developers.google.com/drive/quickstart-android so I don't see a reason for duplicated libs in my project. I have added the drive Client lib via Google plugin for eclipse When I build my android app with this manifest <uses-sdk android:minSdkVersion="15" android:targetSdkVersion="16" /> <uses-permission android:name="android.permission.READ_CALENDAR" /> <uses-permission android:name="android.permission.WRITE_CALENDAR" /> <uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE"/> <uses-permission android:name="android.permission.GET_ACCOUNTS"/> <uses-permission android:name="android.permission.INTERNET" /> <application android:icon="@drawable/todo" android:label="@string/app_name" > <activity android:name=".TodosOverviewActivity" android:label="@string/app_name" > <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> <activity android:name=".TodoDetailActivity" android:windowSoftInputMode="stateVisible|adjustResize" > <intent-filter> <action android:name="android.intent.action.SEND" /> <category android:name="android.intent.category.DEFAULT" /> <data android:mimeType="image/*" /> </intent-filter> </activity> <provider android:name=".contentprovider.MyTodoContentProvider" android:authorities="de.vogella.android.todos.contentprovider" > </provider> </application> I get the following error: [2013-10-27 00:43:58 - Dex Loader] Unable to execute dex: Multiple dex files define Lcom/google/api/client/auth/oauth/AbstractOAuthGetToken; [2013-10-27 00:43:58 - de.vogella.android.todos] Conversion to Dalvik format failed: Unable to execute dex: Multiple dex files define Lcom/google/api/client/auth/oauth/AbstractOAuthGetToken; how can I fix this?

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  • Linux: modpost does not build anything

    - by waffleman
    I am having problems getting any kernel modules to build on my machine. Whenever I build a module, modpost always says there are zero modules: MODPOST 0 modules To troubleshoot the problem, I wrote a test module (hello.c): #include <linux/module.h> /* Needed by all modules */ #include <linux/kernel.h> /* Needed for KERN_INFO */ #include <linux/init.h> /* Needed for the macros */ static int __init hello_start(void) { printk(KERN_INFO "Loading hello module...\n"); printk(KERN_INFO "Hello world\n"); return 0; } static void __exit hello_end(void) { printk(KERN_INFO "Goodbye Mr.\n"); } module_init(hello_start); module_exit(hello_end); Here is the Makefile for the module: obj-m = hello.o KVERSION = $(shell uname -r) all: make -C /lib/modules/$(KVERSION)/build M=$(shell pwd) modules clean: make -C /lib/modules/$(KVERSION)/build M=$(shell pwd) clean When I build it on my machine, I get the following output: make -C /lib/modules/2.6.32-27-generic/build M=/home/waffleman/tmp/mod-test modules make[1]: Entering directory `/usr/src/linux-headers-2.6.32-27-generic' CC [M] /home/waffleman/tmp/mod-test/hello.o Building modules, stage 2. MODPOST 0 modules make[1]: Leaving directory `/usr/src/linux-headers-2.6.32-27-generic' When I make the module on another machine, it is successful: make -C /lib/modules/2.6.24-27-generic/build M=/home/somedude/tmp/mod-test modules make[1]: Entering directory `/usr/src/linux-headers-2.6.24-27-generic' CC [M] /home/somedude/tmp/mod-test/hello.o Building modules, stage 2. MODPOST 1 modules CC /home/somedude/tmp/mod-test/hello.mod.o LD [M] /home/somedude/tmp/mod-test/hello.ko make[1]: Leaving directory `/usr/src/linux-headers-2.6.24-27-generic' I looked for any relevant documentation about modpost, but found little. Anyone know how modpost decides what to build? Is there an environment that I am possibly missing? BTW here is what I am running: uname -a Linux waffleman-desktop 2.6.32-27-generic #49-Ubuntu SMP Wed Dec 1 23:52:12 UTC 2010 i686 GNU/Linux

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  • Converting LDAP from Tomcat to GlassFish

    - by Jon
    Hi, I have a simple web-app that is developed in Netbeans(6.8) and works fine in Tomcat(6) using LDAP(Active Directory). I need to convert this to an EE (JSF2), so I am moving from Tomcat to GlassFish(v3). I have changed the web files to xhtml and configured the xml files. However, I cannot get the GlassFish LDAP configuration to authenticate. I am attaching my old web.xml and server.xml (from Tomcat) snippets and the portions of the new web.xml, sun-web.xml, and the GlassFish configuration. If anyone can help me figure out where I am missing the piece that will allow a user to be authenticated, I would appreciate it. (btw, I am not using roles, just authenticating against the LDAP db is good enought.) As it is right now, my app will prompt me to enter a user when I try to access a file in the 'protected' area and the GlassFish server throws an exception when it fails to authenticate. Because it works under Tomcat, I know I have the right information, I just don't know how to format it to get GlassFish to pass it along. Thanks. TOMCAT FILES: - Tomcat server.xml: web.xml: <web-resource-collection> <web-resource-name>Protected Area</web-resource-name> <description>Authentication Required</description> <url-pattern>/faces/protected/*</url-pattern> </web-resource-collection> <auth-constraint> <role-name>*</role-name> </auth-constraint> * BASIC Please enter your user name and password: GLASSFISH FILES: (I enabled the Security Manager on the Security panel, set the Default Realm to 'LDAPRealm', and added "-Djava.naming.referral=follow" JVM options.) - domain.xml: <auth-realm name="certificate" classname="com.sun.enterprise.security.auth.realm.certificate.CertificateRealm" /> <auth-realm classname="com.sun.enterprise.security.auth.realm.ldap.LDAPRealm" name="LdapRealm"> <property description="()" name="search-bind-password" value="xxxxxxxx" /> <property description="()" name="search-bind-dn" value="cn=xxxxxxxx,ou=Administrators,ou=Information Technology,ou=ITTS,ou=Administrative,ou=xxx,dc=xxxxxx,dc=xxx" /> <property name="jaas-context" value="ldapRealm" /> <property name="base-dn" value="ou=xxx,dc=xxxxxx,dc=xxx" /> <property name="directory" value="ldap://xxxx.xxxxxx.xxx:389" /> <property name="search-filter" value="(&amp;(objectClass=user)(sAMAccountName=%s))" /> </auth-realm> -web.xml: <security-constraint> <display-name>protected</display-name> <web-resource-collection> <web-resource-name>ProtectedArea</web-resource-name> <description/> <url-pattern>/faces/protected/*</url-pattern> </web-resource-collection> <auth-constraint> <description/> <role-name>*</role-name> </auth-constraint> </security-constraint> <security-role> <description/> <role-name>*</role-name> </security-role> <login-config> <auth-method>FORM</auth-method> <realm-name>LDAPRealm</realm-name> <form-login-config> <form-login-page>/faces/login.xhtml</form-login-page> <form-error-page>/faces/loginError.xhtml</form-error-page> </form-login-config> </login-config> sun-web.xml: Here is the exception that it throws: SEVERE: SEC1113: Exception in LdapRealm when trying to authenticate user. javax.security.auth.login.LoginException: javax.security.auth.login.LoginException: User yyyyyyy not found. at com.sun.enterprise.security.auth.realm.ldap.LDAPRealm.findAndBind(LDAPRealm.java:450)

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  • Redirect TS Gateway Authentication to RADIUS Server

    - by Brent
    Hi All, I'm trying to set up an environment for my TS gateway server where the authentication for the initial login to the TS gateway server is handled by a RADIUS server (as determined by NPS), then the user uses standard Windows Auth to log in to their destination machine. I have the server successfully passing the auth to the RADIUS server, but only after it does a Windows auth first. The credentials will not match between the Windows Server and the RADIUS server, so the RADIUS auth always fails, and the TS Gateway server will not forward the request to the RADIUS server unless the Windows Auth succeeds. Does anyone know how to disable the Windows Auth requirement on a TS Gateway server? This is a pretty vanilla SBS 2008 box.

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  • Can I use Apache 2.0 ErrorDocument and Mod Alias to store error pages outside the DocumentRoot?

    - by Pete
    I'd like to store my nicely designed set of http error documents outside the DocumentRoot. Alias /errors /data/opt/apache-httpd-2.0.63/htdocs/errorpages/ <Directory "/data/opt/apache-httpd-2.0.63/htdocs/errorpages/"> order deny,allow allow from all </Directory> ErrorDocument 500 /errors/500.html ErrorDocument 404 /errors/404.html ErrorDocument 401 /errors/default.html ErrorDocument 403 /errors/default.html ErrorDocument 502 /errors/default.html ErrorDocument 503 /errors/default.html However, when I do this, all I get is "The requested URL /errors/default.html resulted in an error." Is it possible to use mod_alias and the ErrorDocument directive together like this in Apache 2.0?

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  • How can I change the flow through this PAM (programmable authentication module) file?

    - by Jamie
    I'd like the PAM module to skip the pam_mount.so line when a unix login succeeds. I've tried various things including: auth [success=2 default=ignore] pam_unix.so nullok_secure auth [success=2 default=ignore] pam_winbind.so krb5_auth krb5_ccache_type=FILE cached_login try_first_pass auth requisite pam_deny.so auth requisite pam_permit.so auth required pam_permit.so auth optional pam_mount.so But can't get it to work. Conversely, when a session shuts down, how can I modify the following os that an unmount command (via pam_mount.so) is avoided during a unix login? session [default=1] pam_permit.so session requisite pam_deny.so session required pam_permit.so session required pam_unix.so session optional pam_winbind.so session optional pam_mount.so

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  • Sudo asks for password twice with LDAP authentication

    - by Gnudiff
    I have Ubuntu 8.04 LTS machine and Windows 2003 AD domain. I have succesfully set up that I can log in with domain username and password, using domain prefix, like "domain+username". Upon login to machine it all works first try, however, for some reason when I try to sudo my logged in user, it asks for the password twice every time when I try sudo. It accepts the password after 2nd time, but not the first time. Once or twice I might think I just keep entering wrong pass the first time, but this is what happens always, any ideas of what's wrong? pam.conf is empty pam.d/sudo only includes common-auth & common-account, and common-auth is: auth sufficient pam_unix.so nullok_secure auth sufficient pam_winbind.so auth requisite pam_deny.so auth required pam_permit.so

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  • Connecting Linux to WatchGuard Firebox SSL (OpenVPN client)

    Recently, I got a new project assignment that requires to connect permanently to the customer's network through VPN. They are using a so-called SSL VPN. As I am using OpenVPN since more than 5 years within my company's network I was quite curious about their solution and how it would actually be different from OpenVPN. Well, short version: It is a disguised version of OpenVPN. Unfortunately, the company only offers a client for Windows and Mac OS which shouldn't bother any Linux user after all. OpenVPN is part of every recent distribution and can be activated in a couple of minutes - both client as well as server (if necessary). WatchGuard Firebox SSL - About dialog Borrowing some files from a Windows client installation Initially, I didn't know about the product, so therefore I went through the installation on Windows 8. No obstacles (and no restart despite installation of TAP device drivers!) here and the secured VPN channel was up and running in less than 2 minutes or so. Much appreciated from both parties - customer and me. Of course, this whole client package and my long year approved and stable installation ignited my interest to have a closer look at the WatchGuard client. Compared to the original OpenVPN client (okay, I have to admit this is years ago) this commercial product is smarter in terms of file locations during installation. You'll be able to access the configuration and key files below your roaming application data folder. To get there, simply enter '%AppData%\WatchGuard\Mobile VPN' in your Windows/File Explorer and confirm with Enter/Return. This will display the following files: Application folder below user profile with configuration and certificate files From there we are going to borrow four files, namely: ca.crt client.crt client.ovpn client.pem and transfer them to the Linux system. You might also be able to isolate those four files from a Mac OS client. Frankly, I'm just too lazy to run the WatchGuard client installation on a Mac mini only to find the folder location, and I'm going to describe why a little bit further down this article. I know that you can do that! Feedback in the comment section is appreciated. Configuration of OpenVPN (console) Depending on your distribution the following steps might be a little different but in general you should be able to get the important information from it. I'm going to describe the steps in Ubuntu 13.04 (Raring Ringtail). As usual, there are two possibilities to achieve your goal: console and UI. Let's what it is necessary to be done. First of all, you should ensure that you have OpenVPN installed on your system. Open your favourite terminal application and run the following statement: $ sudo apt-get install openvpn network-manager-openvpn network-manager-openvpn-gnome Just to be on the safe side. The four above mentioned files from your Windows machine could be copied anywhere but either you place them below your own user directory or you put them (as root) below the default directory: /etc/openvpn At this stage you would be able to do a test run already. Just in case, run the following command and check the output (it's the similar information you would get from the 'View Logs...' context menu entry in Windows: $ sudo openvpn --config client.ovpn Pay attention to the correct path to your configuration and certificate files. OpenVPN will ask you to enter your Auth Username and Auth Password in order to establish the VPN connection, same as the Windows client. Remote server and user authentication to establish the VPN Please complete the test run and see whether all went well. You can disconnect pressing Ctrl+C. Simplifying your life - authentication file In my case, I actually set up the OpenVPN client on my gateway/router. This establishes a VPN channel between my network and my client's network and allows me to switch machines easily without having the necessity to install the WatchGuard client on each and every machine. That's also very handy for my various virtualised Windows machines. Anyway, as the client configuration, key and certificate files are located on a headless system somewhere under the roof, it is mandatory to have an automatic connection to the remote site. For that you should first change the file extension '.ovpn' to '.conf' which is the default extension on Linux systems for OpenVPN, and then open the client configuration file in order to extend an existing line. $ sudo mv client.ovpn client.conf $ sudo nano client.conf You should have a similar content to this one here: dev tunclientproto tcp-clientca ca.crtcert client.crtkey client.pemtls-remote "/O=WatchGuard_Technologies/OU=Fireware/CN=Fireware_SSLVPN_Server"remote-cert-eku "TLS Web Server Authentication"remote 1.2.3.4 443persist-keypersist-tunverb 3mute 20keepalive 10 60cipher AES-256-CBCauth SHA1float 1reneg-sec 3660nobindmute-replay-warningsauth-user-pass auth.txt Note: I changed the IP address of the remote directive above (which should be obvious, right?). Anyway, the required change is marked in red and we have to create a new authentication file 'auth.txt'. You can give the directive 'auth-user-pass' any file name you'd like to. Due to my existing OpenVPN infrastructure my setup differs completely from the above written content but for sake of simplicity I just keep it 'as-is'. Okay, let's create this file 'auth.txt' $ sudo nano auth.txt and just put two lines of information in it - username on the first, and password on the second line, like so: myvpnusernameverysecretpassword Store the file, change permissions, and call openvpn with your configuration file again: $ sudo chmod 0600 auth.txt $ sudo openvpn --config client.conf This should now work without being prompted to enter username and password. In case that you placed your files below the system-wide location /etc/openvpn you can operate your VPNs also via service command like so: $ sudo service openvpn start client $ sudo service openvpn stop client Using Network Manager For newer Linux users or the ones with 'console-phobia' I'm going to describe now how to use Network Manager to setup the OpenVPN client. For this move your mouse to the systray area and click on Network Connections => VPN Connections => Configure VPNs... which opens your Network Connections dialog. Alternatively, use the HUD and enter 'Network Connections'. Network connections overview in Ubuntu Click on 'Add' button. On the next dialog select 'Import a saved VPN configuration...' from the dropdown list and click on 'Create...' Choose connection type to import VPN configuration Now you navigate to your folder where you put the client files from the Windows system and you open the 'client.ovpn' file. Next, on the tab 'VPN' proceed with the following steps (directives from the configuration file are referred): General Check the IP address of Gateway ('remote' - we used 1.2.3.4 in this setup) Authentication Change Type to 'Password with Certificates (TLS)' ('auth-pass-user') Enter User name to access your client keys (Auth Name: myvpnusername) Enter Password (Auth Password: verysecretpassword) and choose your password handling Browse for your User Certificate ('cert' - should be pre-selected with client.crt) Browse for your CA Certificate ('ca' - should be filled as ca.crt) Specify your Private Key ('key' - here: client.pem) Then click on the 'Advanced...' button and check the following values: Use custom gateway port: 443 (second value of 'remote' directive) Check the selected value of Cipher ('cipher') Check HMAC Authentication ('auth') Enter the Subject Match: /O=WatchGuard_Technologies/OU=Fireware/CN=Fireware_SSLVPN_Server ('tls-remote') Finally, you have to confirm and close all dialogs. You should be able to establish your OpenVPN-WatchGuard connection via Network Manager. For that, click on the 'VPN Connections => client' entry on your Network Manager in the systray. It is advised that you keep an eye on the syslog to see whether there are any problematic issues that would require some additional attention. Advanced topic: routing As stated above, I'm running the 'WatchGuard client for Linux' on my head-less server, and since then I'm actually establishing a secure communication channel between two networks. In order to enable your network clients to get access to machines on the remote side there are two possibilities to enable that: Proper routing on both sides of the connection which enables both-direction access, or Network masquerading on the 'client side' of the connection Following, I'm going to describe the second option a little bit more in detail. The Linux system that I'm using is already configured as a gateway to the internet. I won't explain the necessary steps to do that, and will only focus on the additional tweaks I had to do. You can find tons of very good instructions and tutorials on 'How to setup a Linux gateway/router' - just use Google. OK, back to the actual modifications. First, we need to have some information about the network topology and IP address range used on the 'other' side. We can get this very easily from /var/log/syslog after we established the OpenVPN channel, like so: $ sudo tail -n20 /var/log/syslog Or if your system is quite busy with logging, like so: $ sudo less /var/log/syslog | grep ovpn The output should contain PUSH received message similar to the following one: Jul 23 23:13:28 ios1 ovpn-client[789]: PUSH: Received control message: 'PUSH_REPLY,topology subnet,route 192.168.1.0 255.255.255.0,dhcp-option DOMAIN ,route-gateway 192.168.6.1,topology subnet,ping 10,ping-restart 60,ifconfig 192.168.6.2 255.255.255.0' The interesting part for us is the route command which I highlighted already in the sample PUSH_REPLY. Depending on your remote server there might be multiple networks defined (172.16.x.x and/or 10.x.x.x). Important: The IP address range on both sides of the connection has to be different, otherwise you will have to shuffle IPs or increase your the netmask. {loadposition content_adsense} After the VPN connection is established, we have to extend the rules for iptables in order to route and masquerade IP packets properly. I created a shell script to take care of those steps: #!/bin/sh -eIPTABLES=/sbin/iptablesDEV_LAN=eth0DEV_VPNS=tun+VPN=192.168.1.0/24 $IPTABLES -A FORWARD -i $DEV_LAN -o $DEV_VPNS -d $VPN -j ACCEPT$IPTABLES -A FORWARD -i $DEV_VPNS -o $DEV_LAN -s $VPN -j ACCEPT$IPTABLES -t nat -A POSTROUTING -o $DEV_VPNS -d $VPN -j MASQUERADE I'm using the wildcard interface 'tun+' because I have multiple client configurations for OpenVPN on my server. In your case, it might be sufficient to specify device 'tun0' only. Simplifying your life - automatic connect on boot Now, that the client connection works flawless, configuration of routing and iptables is okay, we might consider to add another 'laziness' factor into our setup. Due to kernel updates or other circumstances it might be necessary to reboot your system. Wouldn't it be nice that the VPN connections are established during the boot procedure? Yes, of course it would be. To achieve this, we have to configure OpenVPN to automatically start our VPNs via init script. Let's have a look at the responsible 'default' file and adjust the settings accordingly. $ sudo nano /etc/default/openvpn Which should have a similar content to this: # This is the configuration file for /etc/init.d/openvpn## Start only these VPNs automatically via init script.# Allowed values are "all", "none" or space separated list of# names of the VPNs. If empty, "all" is assumed.# The VPN name refers to the VPN configutation file name.# i.e. "home" would be /etc/openvpn/home.conf#AUTOSTART="all"#AUTOSTART="none"#AUTOSTART="home office"## ... more information which remains unmodified ... With the OpenVPN client configuration as described above you would either set AUTOSTART to "all" or to "client" to enable automatic start of your VPN(s) during boot. You should also take care that your iptables commands are executed after the link has been established, too. You can easily test this configuration without reboot, like so: $ sudo service openvpn restart Enjoy stable VPN connections between your Linux system(s) and a WatchGuard Firebox SSL remote server. Cheers, JoKi

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  • How to configure ubuntu ldap client to get password policies from server?

    - by Rafaeldv
    I have a ldap server on CentOS, 389-ds. I configured the client, ubuntu 12.04, to authenticate on that base and it works very well. But it don't gets the password policies from server. For example, if i set the policy to force user to change the password on first login, ubuntu ignores it and logs him in, always. How can i setup the client to get the policies? Here are the client files: /etc/nsswitch.conf passwd: files ldap group: files ldap shadow: files ldap hosts: files mdns4_minimal [NOTFOUND=return] dns mdns4 networks: files protocols: db files services: db files ethers: db files rpc: db files netgroup: nis sudoers: ldap files common-auth auth [success=2 default=ignore] pam_unix.so nullok_secure auth [success=1 default=ignore] pam_ldap.so use_first_pass auth requisite pam_deny.so auth required pam_permit.so auth optional pam_cap.so common-account account [success=2 new_authtok_reqd=done default=ignore] pam_unix.so account [success=1 default=ignore] pam_ldap.so account requisite pam_deny.so account required pam_permit.so common-password password requisite pam_cracklib.so retry=3 minlen=8 difok=3 password [success=2 default=ignore] pam_unix.so obscure use_authtok try_first_pass sha512 password [success=1 user_unknown=ignore default=die] pam_ldap.so use_authtok try_first_pass password requisite pam_deny.so password required pam_permit.so password optional pam_gnome_keyring.so common-session session [default=1] pam_permit.so session requisite pam_deny.so session required pam_permit.so session optional pam_umask.so session required pam_unix.so session optional pam_ldap.so session optional pam_ck_connector.so nox11 session optional pam_mkhomedir.so skel=/etc/skel umask=0022 /etc/ldap.conf base dc=a,dc=b,dc=c uri ldaps://a.b.c/ ldap_version 3 rootbinddn cn=directory manager pam_password md5 sudoers_base ou=SUDOers,dc=a,dc=b,dc=c pam_lookup_policy yes pam_check_host_attr yes nss_initgroups_ignoreusers avahi,avahi-autoipd,backup,bin,colord,daemon,games,gnats,hplip,irc,kernoops,libuuid,lightdm,list,lp,mail,man,messagebus,news,proxy,pulse,root,rtkit,saned,speech-dispatcher,sshd,sync,sys,syslog,usbmux,uucp,whoopsie,www-data /etc/ldap/ldap.conf BASE dc=a,dc=b,dc=c URI ldaps://a.b.c/ ssl on use_sasl no tls_checkpeer no sudoers_base ou=SUDOers,dc=a,dc=b,dc=c sudoers_debug 2 pam_lookup_policy yes pam_check_host_attr yes pam_lookup_policy yes pam_check_host_attr yes TLS_CACERT /etc/ssl/certs/ca-certificates.crt TLS_REQCERT never

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  • MFMailComposeViewController in landscape

    - by Jatin
    My application is in landscape mod.When i call MFMailComposeViewController through Present model view, it comes in landscape mod.I rotate device and MFMailComposeViewController view goes to portrait mod i want to restrict this rotation it should always be in landscape mod only.Is there any way to do it..

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