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  • C# Finding 2 positions 1-dimArray

    - by Chris
    Hello, In a method i am calculating the longest row of elements. The 1-dim array is filled up with random values (0 or 1). The method looks up the longest row (being 0 or 1, whatever is the longest). Meaning in for example: 1110100 --> the longest row would be 3 (3 * 1) 0110000 --> the longest row would be 4 (4 * 0) My problem is i am trying to perform some type of linear search to show the position of the row in the array. The first example has the longest row of 3 elements (3 times 1). For 1110100 the position in the array would be 0 - 2 (index) For 0110000 the position in the array would be 3 - 6 (index) I have been trying with foreaches, for loops etc..but i cannot seem to get the proper indexes of both. Cannot seem to display both positions properly. For the first example the correct output wouldbe: The largest row of same elements of the array consists of 3 elements on the position 0 - 2. The longest row of elements gets of same elements get calculated as the following: public int BerekenDeelrij (int [] table) ( int count = 0; final int value = 0; int largest = 0; foreach (int value in table) ( if (value == last value) counter + +; else ( largest = Math.Max largest (largest, counter); final value = value count = 1; ) ) Math.Max return (largest, counter); ) Best Regards.

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  • Android App crashing on Back Button (performResumeActivity)

    - by Rutger
    My App consists of 2 Activities at the moment. . the MAIN activity with a Gallery View . a FriendsListActivity with a ListView When the user moves away from the FriendsListActivity with the back button, and returns to the MAIN activity the following error keeps popping up in debug mode. DalvikVM[localhost:8676] Thread [<1 main] (Suspended (exception RuntimeException)) ActivityThread.performResumeActivity(IBinder, boolean) line: 2095 ActivityThread.handleResumeActivity(IBinder, boolean, boolean) line: 2110 BinderProxy(ActivityThread$H).handleMessage(Message) line: 954 ActivityThread$H(Handler).dispatchMessage(Message) line: 99 Looper.loop() line: 123 ActivityThread.main(String[]) line: 3647 Method.invokeNative(Object, Object[], Class, Class[], Class, int, boolean) line: not available [native method] Method.invoke(Object, Object...) line: 507 ZygoteInit$MethodAndArgsCaller.run() line: 839 ZygoteInit.main(String[]) line: 597 NativeStart.main(String[]) line: not available [native method] Thread [<8 Binder Thread #2] (Running) Thread [<7 Binder Thread #1] (Running) With the LogCat 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): FATAL EXCEPTION: main 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): java.lang.RuntimeException: Unable to resume activity {com.package.MAIN/com.package.MAIN.MAIN}: java.lang.NullPointerException 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at android.app.ActivityThread.performResumeActivity(ActivityThread.java:2095) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at android.app.ActivityThread.handleResumeActivity(ActivityThread.java:2110) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:954) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at android.os.Handler.dispatchMessage(Handler.java:99) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at android.os.Looper.loop(Looper.java:123) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at android.app.ActivityThread.main(ActivityThread.java:3647) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at java.lang.reflect.Method.invokeNative(Native Method) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at java.lang.reflect.Method.invoke(Method.java:507) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:839) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:597) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at dalvik.system.NativeStart.main(Native Method) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): Caused by: java.lang.NullPointerException 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at com.package.MAIN.MAIN.onResume(MAIN.java:91) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at android.app.Instrumentation.callActivityOnResume(Instrumentation.java:1149) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at android.app.Activity.performResume(Activity.java:3833) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): at android.app.ActivityThread.performResumeActivity(ActivityThread.java:2085) 03-13 22:01:10.972: ERROR/AndroidRuntime(1038): ... 10 more Further info in the Variables panel states: this: ActivityThread e: NullPointerException cause: NullPointerException detailMessage: null stackTrace: null r: ActivityThread$ActivityClientRecord activity: MAIN detailMessage after one Eclipse Resume: Unable to resume activity (MAIN) The code from the FriendsListActivity looks like this public class FriendsListActivity extends ListActivity { // =========================================================== // Fields // =========================================================== private ArrayList<Friend> friends = new ArrayList<Friend>(); private FriendsArrayAdapter friendsArrayAdapter; private ListView listView; // =========================================================== // onCreate // =========================================================== @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); requestWindowFeature(Window.FEATURE_NO_TITLE); setContentView(R.layout.friends_list); registerForContextMenu(getListView()); setButtonNewFriendClickListener(); } public void generateFriendsList() { FriendsService fs = new FriendsService(this); friends = fs.getFriendsList(); listView = (ListView) findViewById(android.R.id.list); friendsArrayAdapter = new FriendsArrayAdapter( this, R.layout.friend_list_item, friends); listView.setAdapter(friendsArrayAdapter); } @Override public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) { super.onCreateContextMenu(menu, v, menuInfo); MenuInflater inflater = getMenuInflater(); inflater.inflate(R.menu.friends_context_menu, menu); } @Override public boolean onContextItemSelected(MenuItem item) { AdapterContextMenuInfo info = (AdapterContextMenuInfo) item.getMenuInfo(); FriendsService fs = new FriendsService(this); Friend f = new Friend(); f = friends.get(info.position); switch (item.getItemId()) { case R.id.edit: Intent i = new Intent(this, FriendEditActivity.class); i.putExtra("userid", f.userId); startActivity(i); return true; case R.id.delete: fs.deleteFriend(f.userId); generateFriendsList(); return true; default: return super.onContextItemSelected(item); } } // =========================================================== // onPause // =========================================================== protected void onPause() { super.onPause(); finish(); } // =========================================================== // onResume // =========================================================== protected void onResume() { super.onResume(); generateFriendsList(); } // =========================================================== // onStop // =========================================================== protected void onStop() { super.onStop(); } // =========================================================== // onDestroy // =========================================================== @Override protected void onDestroy() { super.onDestroy(); } // =========================================================== // Activity methods // =========================================================== private void setButtonNewFriendClickListener() { Button clickButton = (Button)findViewById(R.id.button_add_friend); clickButton.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { Intent i = new Intent(v.getContext(), FriendNewActivity.class); startActivity(i); } }); } The AndroidManifest looks like this <manifest xmlns:android="http://schemas.android.com/apk/res/android" android:versionCode="1" android:versionName="1.0" package="com.package.mypackage"> <uses-permission android:name="android.permission.CAMERA" /> <uses-permission android:name="android.permission.INTERNET" /> <uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" /> <application android:icon="@drawable/icon" android:label="@string/app_name"> <activity android:name="com.package.mypackage.mypackage" android:label="@string/app_name"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> <activity android:name=".FriendsListActivity"></activity> <activity android:name=".FriendEditActivity"></activity> <activity android:name=".FriendNewActivity"></activity> <activity android:name=".TakePictureActivity"></activity> <activity android:name=".FriendsService"></activity> <activity android:name=".MyService"></activity> </application> <uses-sdk android:minSdkVersion="9" /> The MAIN activity looks like this: package com.package.mypackage; import java.util.ArrayList; import com.package.domain.Domain; import com.package.service.MyService; import com.package.viewadapter.myImageAdapter; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.view.Window; import android.widget.AdapterView; import android.widget.AdapterView.OnItemClickListener; import android.widget.AdapterView.OnItemLongClickListener; import android.widget.Button; import android.widget.Gallery; import android.widget.Toast; public class myActivity extends Activity { // =========================================================== // Fields // =========================================================== private MyImageAdapter myImageAdapter; private ArrayList<Domain> domain = new ArrayList<Domain>(); // =========================================================== // onCreate // =========================================================== @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); requestWindowFeature(Window.FEATURE_NO_TITLE); setContentView(R.layout.main); /* Set Buttons to listen for any click event. */ setButtonFriendsClickListener(); setButtonCameraClickListener(); setButtonPreferencesClickListener(); } // =========================================================== // onStart // =========================================================== @Override public void onStart() { super.onStart(); /* Find the gallery defined in the main.xml */ Gallery g = (Gallery) findViewById(R.id.gallery); /* Show a Toast message when image is clicked */ g.setOnItemClickListener(new OnItemClickListener() { @Override public void onItemClick(AdapterView<?> parent, View v, int position, long id) { MyImageAdapter image_ID = new MyImageAdapter(myActivity.this, position, null); if (image_ID.getItemId(position) == 0) { Toast test_toast = Toast.makeText(myActivity.this, "This is the New Image click", Toast.LENGTH_SHORT); test_toast.show(); } else { Toast test_toast = Toast.makeText(myActivity.this, "The clicked image has image number " + image_ID.getItemId(position) + " in the imageadapter.", Toast.LENGTH_SHORT); test_toast.show(); } } }); g.setOnItemLongClickListener(new OnItemLongClickListener() { @Override public boolean onItemLongClick(AdapterView<?> parent, View v, int position, long id) { MyImageAdapter image_ID = new MyImageAdapter(myActivity.this, position, null); Toast test_toast = Toast.makeText(myActivity.this, "The long clicked image has image number " + image_ID.getItemId(position) + " in the imageadapter.", Toast.LENGTH_SHORT); test_toast.show(); return true; } }); } // =========================================================== // onPause // =========================================================== protected void onPause() { super.onPause(); } // =========================================================== // onResume // =========================================================== protected void onResume() { super.onResume(); generateMyGallery(); } // =========================================================== // onStop // =========================================================== protected void onStop() { super.onStop(); } // =========================================================== // onDestroy // Is also called when user changes from horizontal // to vertical orientation and back // =========================================================== @Override protected void onDestroy() { super.onDestroy(); } // =========================================================== // Save and Restore UI states // =========================================================== @Override protected void onRestoreInstanceState(Bundle savedInstanceState) { super.onRestoreInstanceState(savedInstanceState); } protected void onSaveInstanceState(Bundle outState) { super.onSaveInstanceState(outState); } // =========================================================== // Main Activity methods // =========================================================== public void generateMyGallery() { MyService cs = new MyService(this); domain = cs.getDomainList(); // Add the new_image drawable to the ArrayList Domain d = new Domain(); d.photoLocation = "drawable"; d.photoName = "new_image"; d.extra1 = "no_text"; d.extra2 = "no_text"; domain.add(0, d); myImageAdapter = new MyImageAdapter(this, R.layout.text_overlay_image_view, domain); /* Find the gallery defined in the main.xml */ Gallery g = (Gallery) findViewById(R.id.gallery); g.setSpacing(10); /* Apply a new (custom) ImageAdapter to it. */ g.setAdapter(myImageAdapter); g.setSelection(1); } private void setButtonFriendsClickListener() { Button clickButton = (Button)findViewById(R.id.button_friends_list); clickButton.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { setContentView(R.layout.friends_list); Intent myIntent = new Intent(v.getContext(), FriendsListActivity.class); startActivity(myIntent); } }); } private void setButtonCameraClickListener() { Button clickButton = (Button)findViewById(R.id.button_take_picture); clickButton.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { setContentView(R.layout.take_picture); Intent myIntent = new Intent(v.getContext(), TakePictureActivity.class); startActivity(myIntent); } }); } private void setButtonPreferencesClickListener() { Button clickButton = (Button)findViewById(R.id.button_preferences); clickButton.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { Intent myIntent = new Intent(v.getContext(), MyPreferencesActivity.class); startActivity(myIntent); } }); } }; Anyone has an idea why the App crashes. Any help is much appreciated. I did find out that, when I finish() the MAIN activity when I start the FriendListActivity and restart the MAIN activity when closing the FriendListActivity, that the crash does not occur. However, this basically restarts the App and that is not the intention. Thanks all, I got the problem solved. This is what I did. . When moving all gallery related actions to the onCreate, the creash didn't happen anymore. But then after returning to the MAIN activity, the activity wasn't shown. . I then moved all the onCreate (except the super), the generateGallery, and the onStart() to the onResume. Now it works fine!

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  • Relatively simple task: How do I pass back the selected item from one activity to another?

    - by Brian D
    I have two activities: one displays an image and a button, the other displays a photo gallery. I want to be able to select any of the images in the gallery and then display them on the first activity in place of the default image. public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.gallery); Gallery g = (Gallery) findViewById(R.id.gallery); g.setAdapter(new ImageAdapter(this)); g.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView parent, View v, int position, long id) { Toast.makeText(PhotoGallery.this, "Position: " + id, Toast.LENGTH_SHORT).show(); Intent intent=new Intent(); intent.putExtra("PictureID", position); setResult(RESULT_OK, intent); finish(); } }); } Am I even close here? I'm not quite sure what to do with any string or int I would attach to the Intent -- can I attach the object itself? I'd much rather pass back at minimum the string name of the resource (image), but the only thing I can seem to figure out right now is how to pass back the position of the picture ... not a great solution. I can clarify more if necessary -- thanks.

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  • Split node list to parts.

    - by Kalinin
    xml: <mode>1</mode> <mode>2</mode> <mode>3</mode> <mode>4</mode> <mode>5</mode> <mode>6</mode> <mode>7</mode> <mode>8</mode> <mode>9</mode> <mode>10</mode> <mode>11</mode> <mode>12</mode> i need to separate it on parts (for ex. on 4): xslt: <xsl:variable name="vNodes" select="mode"/> <xsl:variable name="vNumParts" select="4"/> <xsl:variable name="vNumCols" select="ceiling(count($vNodes) div $vNumParts)"/> <xsl:for-each select="$vNodes[position() mod $vNumCols = 1]"> <xsl:variable name="vCurPos" select="(position()-1)*$vNumCols +1"/> <ul> <xsl:for-each select="$vNodes[position() >= $vCurPos and not(position() > $vCurPos + $vNumCols -1)]"> <li><xsl:value-of select="."/></li> </xsl:for-each> </ul> </xsl:for-each> this code is written by Dimitre Novatchev - great coder)) but for the number of nodes less then number of parts (for ex. i have 2 modes) this code does not work - it outputs nothing. How it upgrade for that case (without choose construction)?

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  • Why does my DIV clip its child DIV when jQuery moves it in IE?

    - by Ben Saufley
    I have two divs, both with position:absolute;, one inside the other. The parent isn't in a place where it can be set as position:relative without an extra layer of complexity (there are a lot of other elements around it that I'd have to account for to put it where it needs to be, which is at the very top of the page, over everything). The child element is made to stick off the bottom of the parent. In Chrome, Safari, Firefox, it all works splendidly. In IE, it works until jQuery moves the parent element - at which point the parent element clips the child, so you can barely see the top of the child. I feel like I've read about this, about IE clipping child elements, but I can't seem to find an answer that applies to my case. It's pretty simple, basically: <div id="parent" style="position:absolute;top:0;left:0;"> [content] <div id="tab" style="position:absolute;bottom:-30px;left:0;width:64px;height:32px;background-image:(...);"></div> </div> <script> $(document).ready( function() { $("#tab").click(function() { $("#parent").animate({"top":"-50px"},300); }); }); </script>

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  • Backbone.js routes not firing

    - by drale2k
    I have a Base Router where i define some functions that need to be run everywhere. Every Router extends this Router. Now my problem is, that none of my routes defined in this Base router, actually fire. Every other route in other Routers work fine. I have created a test route called 'a' which calls method 'b', which should fire an alert but nothing happens. Here is the code: (This is Coffeescript, don't pay attention to the indentation, it's fine in my file) class Etaxi.Routers.Base extends Backbone.Router routes: 'register' : 'registerDevice' 'a' : 'b' b: -> alert "a" initialize: -> @registerDevice() unless localStorage.device_id? @getGeolocation() registerDevice: -> @collection = new Etaxi.Collections.Devices() @collection.fetch() view = new Etaxi.Views.RegisterDevice(collection: @collection) $('#wrapper').append(view.render().el) getGeolocation: -> navigator.geolocation.getCurrentPosition (position) -> lat = position.coords.latitude lng = position.coords.longitude #$('#apphead').tap -> # alert 'Position: ' + lat + " ," + lng So when i visit '/register' or '/a' it should fire the appropriate method but it does not. I wonder if it has something to do with the fact that other Router extend from this Router? Would be wired but it is the only thing i can think of because every other Router works fine.

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  • CSS to specify positions over a scanned document

    - by itsols
    I'm trying to write the CSS rules to position text over a scanned document. Reason: The document is a pre-printed form. I am trying to position the text on-screen so that it relates to the 'spaces' on the actual form. Issue: Although I position the values using centimeters, they don't seem to get aligned with the ones on the actual page. I can see this misalignment since my scanned image is in the background of the page. What I've tried: I used a ruler to physically measure the locations and specify them with CSS. But on-screen, it doesn't tally. I used the scanned image to position the CSS values. Then the printout is not correct. I even scaled the scanned page using Inkscape to the exact dimensions in centimeters and took into account all margins, etc... What I need: I am trying to correctly show the output values on-screen AND have them print in the correct manner as well. I know that using two CSS sheets (one for print) is an option. But I'm developing this program away from where the actual printing is to be done. So is there a convenient way of matching the exact screen locations with those on the actual/final prinout? Thanks!

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  • Background Image Overlapped Problem with jQuery

    - by Devyn
    Hi, Here is my working page. I attached buttons to white bishop and you can move around but left images are overlapped by right images. I think the problem is with CSS. The brief structure is here. <script> $(document).ready(function(){ $('#top').click(function(){ $('#p81').animate({top: "-=64px"}, 100); }); </script> <style> div.chess_board{ height: 512px; position: relative; width: 512px; } div.chess_square{ height:64px; position: absolute; width:64px; } div.chess_square.white { background: none repeat scroll 0 0 #ffffff; } . . . div.chess_piece{ background-image: url("sprite.png"); height: 64px; width: 64px; position: absolute; } div.chess_piece.bishot.white{ background-position: -64px 0; } </style> <div class="chess_board"> <div id="b81" class="chess_square white" style="top: 448px; left: 64px;"> <div class="chess_square_inner"></div> <div id="p81" class="chess_piece bishot white"></div> </div> </div> <input type="button" id="top" value="top" />

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  • Unknown ListView Behavior

    - by st0le
    I'm currently making a SMS Application in Android, the following is a code snippet from Inbox Listactivity, I have requested a cursor from the contentresolver and used a custom adapter to add custom views into the list. Now, in the custom view i've got 2 TextViews (tvFullBody,*tvBody*)... tvFullBody contains the Full SMS Text while tvBody contains a short preview (35 characters) The tvFullBody Visibility is by default set to GONE. My idea is, when the user clicks on a list item, the tvBody should dissappear(GONE) and the tvFullBody should become visible (VISIBLE). On Clicking again, it should revert back to its original state. //isExpanded is a BitSet of the size = no of list items...keeps track of which items are expanded and which are not @Override protected void onListItemClick(ListView l, View v, int position, long id) { if(isExpanded.get(position)) { v.findViewById(R.id.tvFullBody).setVisibility(View.GONE); v.findViewById(R.id.tvBody).setVisibility(View.VISIBLE); }else { v.findViewById(R.id.tvFullBody).setVisibility(View.VISIBLE); v.findViewById(R.id.tvBody).setVisibility(View.GONE); } isExpanded.flip(position); super.onListItemClick(l, v, position, id); } The Code works as it is supposed to :) except for an undesired sideeffect.... Every 10th (or so) List Item also gets "toggled". eg. If i Expand the 1st, then the 11th, 21th list items are also expanded...Although they remain off screen, but on scrolling you get to see the undesired "expansion". By my novice analysis, i'm guessing Listview keeps track of 10 list items that are currently visible, upon scrolling, it "reuses" those same variables, which is causing this problem...(i didn't check the android source code yet.) I'd be gratefull for any suggestion, on how i should tackle this! :) I'm open to alternative methods aswell....Thanks in advance! :)

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  • expand floating object when floating object within expands

    - by Scarface
    Hey guys, quick question, I have a link when clicked drops down a list. This list is floated to the right to position it properly. This list is in another box that has been floated. My problem is that when the list expands, the box does not and the list comes out of the container box, unless the list is not floated. However floating it seems like the only way to get it to the position I want. If anyone has any ideas on how to solve this problem I would appreciate it. .container-box { margin-top:0px; float:left; padding-left:5px; position:relative; } #box-within { float:right; font-weight:bold; max-height:250px; display: none; background-color:#fff; overflow: auto; width:325px; padding:5px; position:relative; }

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  • problem with a very simple tile based game

    - by newbieguy
    Hello, I am trying to create a pacman-like game. I have an array that looks like this: array: 1111111111111 1000000000001 1111110111111 1000000000001 1111111111111 1 = Wall, 0 = Empty space I use this array to draw tiles that are 16x16 in size. The Game character is 32x32. Initially I represented the character's position in array indexes, [1,1] etc. I would update his position if array[character.new_y][charater.new_x] == 0 Then I translated these array coordinates to pixels, [y*16, x*16] to draw him. He was lining up nicely, wouldn't go into walls, but I noticed that since I was updating him by 16 pixels each, he was moving very fast. I decided to do it in reverse, to store the game character's position in pixels instead, so that he could use less than 16 pixels per move. I thought that a simple if statement such as this: if array[(character.new_pixel_y)/16][(character.new_pixel_x)/16] == 0 would prevent him from going into walls, but unfortunately he eats a bit of the bottom and right side walls. Any ideas how would I properly translate pixel position to the array indexes? I guess this is something simple, but I really can't figure it out :(

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  • Parent-child height problem

    - by Vector
    I have a parent div that has position: relative and his child has position: absolute. Such positions is a must. The problem is the parent does not stretch to the height of the child. The question is how to make it stretch to the height of the child? The mark-up is similar to this: <!DOCTYPE HTML> <html> <head> <style> .parent { position: relative; border: solid 1px red; } .child { position: absolute; border: solid 1px red; } </style> </head> <body> <div class="parent"> <div class="child">Hello World!</div> </div> </body> </html>

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  • jQuery relative positioned hover

    - by danixd
    I want a link to the next or previous image to appear when hovering over the main image, only I want the next link to appear when hovered over the right hand side, and previous on the left. I have looked at jQuery's .position() and I don't think I am understanding it very well. At the moment all I have is general mouseenter/mouseleave events, which show both links when the image is hovered. jQuery(document).ready(function($) { $('.nav-controls a').hide(); $('#slideshow').mouseenter(function() { $('.nav-controls a').fadeIn(500); }); $('#slideshow').mouseleave(function() { $('.nav-controls a').fadeOut(500); }); }); I'd image it to be something like: jQuery(document).ready(function($) { $('.nav-controls a').hide(); var image = $('#slideshow'); var left = image.position().left(0); var right = image.position().left(50%); left.mouseenter(function() { $('.nav-controls a.previous').fadeIn(500); }); left.mouseleave(function() { $('.nav-controls a.previous').fadeOut(500); }); right.mouseenter(function() { $('.nav-controls a.next').fadeIn(500); }); right.mouseleave(function() { $('.nav-controls a.next').fadeOut(500); }); }); Not sure if I should be using position, if I am using it correctly. Any tips would be great. Edit: I do not want to add unnecessary markup in the form of divs, for the left/right selectors.

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  • Div appearing outside its parent, bizarre sizing problems...

    - by SLC
    I have a list, which is going to be a menu. I want to position it absolutely at the very top of the page. My code looks like this: <div id="sitenavmenu"> <div id="sitenavmenu-content"> <ul id="sitenavmenu-content-menu"> <li>Register</li> <li><%: Html.ActionLink("About", "About", "Home")%></li> <li>Contact Us</li> </ul> </div> </div> My CSS looks like this: #sitenavmenu { position:absolute; margin-left:300px; top:2px; width:500px; } #sitenavmenu-content-menu li { list-style-type:none; display:inline; padding-right:5px; font-size:small; } The problem I have is, if I don't position it absolutely, it looks fine. As soon as I position it absolutely (as it is shown above), the sitenavmenu div changes size, and although it shifts to the top, the sitenavmenu-content div appears below it. There is no other CSS as I have only just started, and I have checked padding etc. and everything is zero. I just can't figure out why it's not working, and I don't want to hack it. Edit: It's something to do with the height of #sitenavmenu. If I leave it, then the sitenav-content ends up horizontally centered in it, although #sitenavmenu is much taller. If I make them both the same size, so they should sit on top of each other, then the #sitenavmenu-content sits below.

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  • How do I make an iframe 100% height of a containing div in Firefox?

    - by David
    I'm having some trouble figuring out how to extend an iframe to 100% of it's container element in Firefox and IE (it works fine in Chrome). From searching around, it makes sense that there has to be a width specified on the containing div (and possibly body and html as well). However, I have done that, and the iframe is still not extending. Do all of the parent divs have to have a specified width and position for this to work, or just the containing parent? Any fix for this would be greatly appreciated! Here's what I have: <!DOCTYPE html> <html> <head> <style> html, body {margin:0; padding:0; height:100%} #container {width: 1000px; min-height: 550px; position: relative} #smallContainer {position:relative} /*no width specified*/ #iframeContainer {height: 100%; position: relative} #iframe {height: 100%; width: 100%; display: block} </style> </head> <body> <div id="container"> <div id="smallContainer"> <div id="iframeContainer"> <iframe id="iframe" src="foo.com"></iframe> </div> </div> </div> </body> </html>

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  • How to merge arraylist element ?

    - by tiendv
    I have a string example = " Can somebody provide an algorithm sample code in your reply ", after token and do some i want on string example i have arraylist like : ArrayList <token > arl = " "Can somebody provide ", "code in your ", "somebody provide an algorith", " in your reply" ) "Can somebody provide ", i know position start and end in string test : star = 1 end = 3 " code in your ", i know position stat = 7 end = 10, "somebody provide an algorith", i know position stat = 7 end = 10, "in your reply" i know position stat = 11 end = 14, we can see,some element in arl overlaping :"Can somebody provide "," code in your ","somebody provide an algorith". The problem here is how can i merge overlaping element to recived arraylist like ArrayList result ="" Can somebody provide an algorithm sample code","" in your reply""; Here my code : but it only merge fist elecment if check is overloaping public ArrayList<TextChunks> finalTextChunks(ArrayList<TextChunks> textchunkswithkeyword) { ArrayList<TextChunks > result = (ArrayList<TextChunks>) textchunkswithkeyword.clone(); //System.out.print(result.size()); int j; for(int i=0;i< result.size() ;i++) { int index = i; if(i+1>=result.size()){ break; } j=i+1; if(result.get(i).checkOverlapingTwoTextchunks(result.get(j))== true) { TextChunks temp = new TextChunks(); temp = handleOverlaping(textchunkswithkeyword.get(i),textchunkswithkeyword.get(j),resultSearchEngine); result.set(i, temp); result.remove(j); i = index; continue; } } return result; } Thanks in avadce

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  • Using sortable_element in Rails on a list generated by a find()

    - by Eli B.
    Hey all, I'm trying to use the scriptaculous helper method sortable_element to implement a drag-and-drop sortable list in my Rails application. While the code for the view looks pretty simple, I'm really not quite sure what to write in the controller to update the "position" column. Here's what I've got in my view, "_show_related_pgs.erb": <ul id = "interest_<%=@related_interest.id.to_s%>_siblings_list"> <%= render :partial => "/interests/peer_group_map", :collection => @maps, :as => :related_pg %> </ul> <%= sortable_element("interest_"+@related_interest.id.to_s+"_siblings_list", :url => {:action => :resort_related_pgs}, :handle => "drag" ) %> <br/> And here's the relevant line from the partial, "interests/peer_group_map.erb" <li class = "interest_<%=@related_interest.id.to_s%>_siblings_list" id = "interest_<%=related_pg.interest_id.to_s%>_siblings_list_<%=related_pg.id.to_s%>"> The Scriptaculous UI magic works fine with these, but I am unsure as to how to change the "position" column in the db to reflect this. Should I be passing the collection @maps back to the controller and tell it to iterate through that and increment/decrement the attribute "position" in each? If so, how can I tell which item was moved up, and which down? I couldn't find anything specific using Chrome dev-tools in the generated html. After each reordering, I also need to re-render the collection @maps since the position is being printed out next to the name of each interest (I'm using it as the "handle" specified in my call to sortable_element() above) - though this should be trivial. Any thoughts? Thanks, -e

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  • Shortest Distance From An Array

    - by notyou61
    I have an ajax function which returns the latitudes and longitudes of locations stored in a database. These are returned and placed in an array. A calculation is performed to return their distance from the users current location based on the latitude/longitude. I would like to return only the record with the shortest calculated distance. My code is as follows: Ajax Success // Success success: function (data) { // Obtain Log/Lat navigator.geolocation.getCurrentPosition(function(position) { // Obtain Current Position Lat/Lon glbVar.latitude = position.coords.latitude; glbVar.longitude = position.coords.longitude; // Console Log //console.log('Lat: ' + glbVar.latitude + ' Lon: ' + glbVar.longitude); // Obtain Location Distances for ( var i = 0; i < data.length; i++ ) { // Location Instances var varLocation = data[i]; // Location Distance varLocation.distance = calculateDistance(glbVar.longitude, glbVar.latitude, varLocation.locationLongitude, varLocation.locationLatitude); } // Sort Locations By Distance var sortedData = data.sort(function(a, b) { // Return Locations return a.distance - b.distance; }); // Output Results $.map(sortedData, function(item) { // Obtain Location Distance varLocationsDistance = calculateDistance(glbVar.longitude, glbVar.latitude, item.locationLongitude, item.locationLatitude); // Obtain Location Radius Assignment if (varLocationsDistance <= varLocationRadius) { // Function Return functionReturn = $({locationID : item.locationID + ', Distance : ' + varLocationsDistance + ' m'}); // Return // Function to get the Min value in Array Array.min = function( sortedData ){ functionReturn = Math.min.apply( Math, sortedData ); // console.log(functionReturn); }; } }); }); } The calculateDistance function returns the distance from the users current location and those from the database. The varLocationsDistance <= varLocationRadius "If" statement returns records within a certain distance radius (100 meters), within that statement I would like to return the shortest distance. I am a self taught amateur web developer and as a result may not have provide enough information for an answer, please let me know. Thanks,

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  • <span> containing 3 overlapping images has 3x the necessary width

    - by Nathan Parrish
    Hi guys, I have a element, containing three overlapping images. Inspecting the element in Chrome shows this: <span id=?"span1">? <img id=?"img1" src=?"images/?progressbar.gif" width=?"120" style=?"position:? relative;? z-index:? 3;?">? <img id=?"img2" src=?"images/?progressbar.gif" style=?"width:? 120px;? height:? 12px;?? position:? relative;? left:? -120px;? z-index:? 2;?">? <img id=?"img3" src=?"images/?progressbar.gif" style=?"width:? 120px;? height:? 12px;? position:? relative;? left:? -240px;? z-index:? 1;?">? </span>? The important point is that the second two images are given a relative position, shifting them to the left so they perfectly overlap the first. But the span itself is still 360 pixels wide (3 x 120 pixels per image). So how can I achieve this effect while keeping the span width tightly bounded around the images? Thanks!

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  • Can you target Google Chrome? (Yes, you can)

    - by Kyle Sevenoaks
    Hi, I need to position this update button on www.euroworker.no/order (you'll have to add an item to the cart, use the Kjøp button to add and Handlevogn to view the cart). Works in FF and IE. (Although there is another alignment problems with IE) but not in Chrome or Safari. I had it working before, but the only thing I can think of to do is target safari and Chrome. Is this possible? Here's the CSS and HTML(Smarty) for you. HTML(Smarty): {capture assign="cartUpdate"} <div id="cartUpdate"><!--<input type="submit" class="submit" value="{tn _update}" />--> <button type="submit" class="submit" id="oppdatersubmit" name="saveFields" title="Oppdater" value="">&nbsp;</button> </div> {/capture} {assign var="cartUpdate" value=$cartUpdate|@str_split:10000} {php}$GLOBALS['cartUpdate'] = $this->get_template_vars('cartUpdate'); $this->assign_by_ref('GLOBALS', $GLOBALS);{/php} {form action="controller=order action=update" method="POST" enctype="multipart/form-data" handle=$form id="cartItems"} CONTENT {/form} And the CSS: #oppdatersubmit { background-image:url(../../upload/oppdater.png); background-repeat:no-repeat; background-position:left; background-color:none; border:none; overflow:hidden; outline:none; white-space: nowrap; width:77px; height:25px; cursor:pointer; position:absolute; } #cartUpdate { position:absolute; width:160px; height:30px; left:580px; bottom:130px; } Need to change these for Chrome and Safari. Thanks.

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  • How can I define an irregular area of the screen and find the closest point to the mouse in that area?

    - by JonathonG
    I'm looking for a method to define an area of the screen that the mouse cannot leave. I have been directed by rob mayoff, the answerer of this question, that I can use a Quartz Event Tap to detect mouse events. This puts me part of the way to the solution to THIS question. I need to define an irregular area of the screen, not just a rectangle, that the mouse cannot leave. I have been researching this and the only idea I can come up with is using a bitmap to define the irregular area, as it will be very oddly shaped. However, I am open to solutions other than using a bitmap. Since this must be done on a Mac, I've determined that I will have to use objective C / Cocoa . I need to know how to define the area and, equally importantly, how to find the closest point in the area to the mouse (so that I can move the mouse to it if the mouse tries to move outside of the area). This is similar to what the restricted area will look like: [edit:] Okay, I've come up with part of the answer to this. If I can do a basic (light-weight) point collision detection on the image mask, I can use a simple algorithm to detect the closest point to the mouse on the black area of the image. I could do this by calculating distance between a pre-defined point (P) inside the black area of the image and the target mouse position (T), taking the midpoint (M), then checking if the midpoint is inside or outside of the shape (black or white, respectively). If M is inside the shape, then move the P to M, otherwise move T to the M, continuously recalculate this until the distance between T and P is 1 pixel or less, then move the mouse to the final calculated position. All of that being said, I still need some way to test the position of the mouse against that same position on the bitmap (assume the bitmap is the same resolution as the monitor), and check if that point is black or white. All of this needs to be done in the background, without this application actually having focus, or the bitmap being visible... is this possible?

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  • How to get two TD cells side by side WITHOUT using css

    - by Joe
    Hi, in the following HTML snippet, I would like the two cells be placed side by side with NO spaces between them; without using css if possible. If the leftmost position of the 2nd one is the rightmost position of the 1st, why WOULD they have any space between? thx. <TR> <TD style="position:absolute; top:98px; left:0px; right:56px; bottom:126px; font-size: 7pt; background-color:Lime; text-align: center; font-family: Arial;" cellpadding="0" cellspacing="0">ABC</TD> <TD style="position:absolute; top:98px; left:56px; right:112px; bottom:126px; font-size: 7pt; background-color:Lime; text-align: center; font-family: Arial;" cellpadding="0" cellspacing="0">123</TD>

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  • Absolutely positioned element moved by margin of another element

    - by user1505528
    Here is my jsFiddle for the following question: http://jsfiddle.net/arelia/Rruxf/ I'd like to have a header that stays at the very top of the body and a footer that stays at the very bottom of the body. I have a content div (position: relative) between the header and footer, and when I set a margin around the div my absolutely positioned header and footer move from their top/bottom positions by the height of that margin (this also happened when I tried setting a margin above and below the paragraphs in the div). In the fiddle you can see that the footer is not attached to the bottom even though it's absolutely positioned (I went ahead and made the header static since static gives the intended result). How do I position the header and footer to the top and bottom of the body and not have the content in the middle move those two elements? If the position: absolute elements are moved out of the flow why would anything affect their position at all? I've tried searching here and Google for "CSS margin affects absolute" and a few other phrases to no avail. I discovered this while playing around with it some more in developer tools: Metrics show the body is the height of the html element minus the amount of one margin (the margin that's still affecting the footer). So, the body must be stretching to the height of the content div since there is nothing else within the document flow within the body to define its height. But that height ends where the content ends instead of after the margin. Shouldn't it include the margin? If I make the height of the body 100%, the footer positions itself to the bottom of the viewport and then stays fixed in that spot when I scroll. Why isn't it attaching itself to the bottom of the body instead of the bottom of the viewport?

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  • Jquery image slider window resize scaling issue

    - by eb_Dev
    Hi, I have created image gallery slider, the images of which scale with the window size. My problem is I can't seem to create the right formula to ensure that the slider is at the right position when the window is scaled. If I am at the first image and the slider 'left' offset is 0 then the scaling works fine and my offset is correct, however when I am on image two and my slider is offset by say -1500 and then the window is resized, the slider is then at the wrong offset. Taking this into account I figured I could just add / subtract the new window size difference from the slider offset and therefore have everything in the right position. I was wrong. It works for the first two images but then If I am at the end of my slider on the last image I get a nice big gap between the end of the last image and the border of the page. Can someone please show my where I am going wrong please? I've spent days on this :( The relevant code is as follows: $(window).bind('resize', function(event, delta) { /* Resize work images - resizes all to document width */ resizeWorkImages('div.page.work div#work ul'); /* Position slider controls */ positionSliderControls(); /* Get the difference between the old window width and the new */ var windowDiff = (gLastWindowWidth - $(window).width()) * -1; /* Apply difference to slider left position */ var newSliderLeftPos = stripPx($('div.page.work div#work ul').css('left')) - windowDiff; /* Apply to slider */ $('div.page.work div#work ul').css('left',newSliderLeftPos+'px') /* Update gSlider settings */ gSlider.update(); /* Record new window width */ gLastWindowWidth = $(window).width(); }); Thanks, eb_dev

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  • Ruby on Rails sortable list

    - by mdgrech
    I created a sortable list in my RoR project, unfortunately it's not saving the list position. Upon page refresh the items return to their normal spot. I've pasted the code below or you can git it: git://github.com/mdgrech/23notes-.git app/views/notes/index.html.erb ///////////////////////////////////////////////////////////////////////////////////////////// <div id="newNoteDiv"></div> <ul id="notesList"> <% for note in @notes %> <li id="<%=h note.position %>"> <span class="handle">[drag]</span> <div id="listContent"> <h3><%= link_to note.title, edit_note_path(note) %></h3> <p><%=h note.content %></p> <%= link_to "Destroy", note, :confirm => 'Are you sure?', :method => :delete %> </div> </li> <% end %> </ul> <%= sortable_element("notesList", :url => sort_notes_path, :handle => "handle" ) %> app/controllers/notes_controller.rb ////////////////////////////////////////////////////////////////////////////////////////// def index @notes = Note.all(:order => "position") end def sort params[:notes].each_with_index do |id, index| Note.update_all(['position=?', index+1], ['id=?', id]) end render :nothing => true end config/routes.rb ////////////////////////////////////////////////////////////////////////////////////////// map.resources :notes, :collection => { :sort => :post } map.root :notes app/models/note.rb ////////////////////////////////////////////////////////////////////////////////////////// class Note < ActiveRecord::Base acts_as_list end

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