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  • Expected Expression

    - by coffeeaddict
    I cannot figure out what I did or did not do here syntactically to cause this error. I don't see what's missing: function ShowWaitMessage(button) { var isValid; if (buttonSelected()) { showWaitMessage(button, "showMessage1"); isValid = true; } else { Page_ClientValidate(); if (Page_IsValid) { showWaitMessage(button, "showMessage2"); isValid = true; } } return isValid; }

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  • Where I get wrong?

    - by Ole Jak
    I have PHP code like this require_once( "includes" . DIRECTORY_SEPARATOR . "constants.php"); $userID = validKey( $key ); $query = "select a.username, b.streamID from user a, streams b where a.id = b.userID;)"; $connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysql_error()); } $db_select = mysql_select_db(DB_NAME,$connection); if (!$db_select) {die( "Database selection failed: " . mysql_error()); } $generated_table = mysql_fetch_array(mysql_query($query, $connection)); // line (*) print_r($generated_table); But PHP gives me error/worning and does not print anything out Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given on line (*) 1) Why It does not printed me anything out 2) Where am I wrong?

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  • Turning logical expression around

    - by BluePrint
    I have the following code: bool s = true; for (...; ...; ...) { // code that defines A, B, C, D // and w, x, y, z if (!(A < w) && s == true) { s = false; } if (!(B < x) && s == true) { s = false; } if (!(C < y) && s == true) { s = false; } if (!(D < z) && s == true) { s = false; } } This code is working well. However, I want to, for several (unimportant) reasons, change the code so that I can initiate s = false; and set it to true inside the if-statement. It tried the following: bool s = false; for (...; ...; ...) { // code that defines A, B, C, D // and w, x, y, z if (A >= w && s == false) { s = true; } if (B >= x && s == false) { s = true; } if (C >= y && s == false) { s = true; } if (D >= z && s == false) { s = true; } } However, this is not working properly as the code above is working. I know thought wrong somewhere in the logic, but I can't figure out where. Does anbyone see my probably obvious error? EDIT: Added three more if-statemets. Missed them since they were commented away.

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  • regular expression - function body extracting

    - by Altariste
    Hi, In Python script,for every method definition in some C++ code of the form: return_value ClassName::MethodName(args) {MehodBody} ,I need to extract three parts: the class name, the method name and the method body for further processing. Finding and extracting the ClassName and MethodName is easy, but is there any simple way to extract the body of the method? With all possible '{' and '}' inside it? Or are regexes unsuitable for such task?

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  • python and regular expression with unicode

    - by bsn
    I need to delete some unicode symbols from the string '?????? ??????? ???????????? ??????????' I know they exist here for sure. I try: re.sub('([\u064B-\u0652\u06D4\u0670\u0674\u06D5-\u06ED]+)', '', '?????? ??????? ???????????? ??????????') but it doesn't work. String stays the same. ant suggestion what i do wrong?

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  • Why is writeSTRef faster than if expression?

    - by wenlong
    writeSTRef twice for each iteration fib3 :: Int -> Integer fib3 n = runST $ do a <- newSTRef 1 b <- newSTRef 1 replicateM_ (n-1) $ do !a' <- readSTRef a !b' <- readSTRef b writeSTRef a b' writeSTRef b $! a'+b' readSTRef b writeSTRef once for each iteration fib4 :: Int -> Integer fib4 n = runST $ do a <- newSTRef 1 b <- newSTRef 1 replicateM_ (n-1) $ do !a' <- readSTRef a !b' <- readSTRef b if a' > b' then writeSTRef b $! a'+b' else writeSTRef a $! a'+b' a'' <- readSTRef a b'' <- readSTRef b if a'' > b'' then return a'' else return b'' Benchmark, given n = 20000: benchmarking 20000/fib3 mean: 5.073608 ms, lb 5.071842 ms, ub 5.075466 ms, ci 0.950 std dev: 9.284321 us, lb 8.119454 us, ub 10.78107 us, ci 0.950 benchmarking 20000/fib4 mean: 5.384010 ms, lb 5.381876 ms, ub 5.386099 ms, ci 0.950 std dev: 10.85245 us, lb 9.510215 us, ub 12.65554 us, ci 0.950 fib3 is a bit faster than fib4.

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  • C++: Print only one char

    - by Martijn Courteaux
    Hi, When I read one char* from std::cin and I want to write it to std::cout, it prints until it finds a \0 in memory. So what did was: char c; cin >> c; char* pChar = &c; pChar++; *pChar = '\0'; println(&c); // My own method: void println(char * str) { cout << str << endl; } But I don't think this is a safe action. Is there a safer way to do this?

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  • Regex if-else expression

    - by craig
    I'm trying to extract the # of minutes from a text field using Oracle's REGEXP_SUBSTR() function. Data: Treatment of PC7, PT1 on left. 15 min. 15 minutes. 15 minutes 15 mins. 15 mins 15 min. 15 min 15min 15 In each case, I'm hoping to extract the '15' part of the string. Attempts: \d+ gets all of the numeric values, including the '7' and '1', which is undesirable. (\d)+(?=\ ?min) get the '15' from all rows except the last. (?((\d)+(?=\ ?min))((\d)+(?=\ ?min))|\d+), an if-else statement, doesnt' match anything. What is wrong with my if-else statement?

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  • Matching Word with regular expression

    - by lbar
    I have the following text file: ... "somewords MYWORD";123123123123 "someother MYWORDOTHER";456456456456 "somedifferent MYWORDDIFFERENT";789789789 ... i need to match the word MYWORD, MYWORDOTHER, MYWORDDIFFERENT and then substitute the space before this word with ";". Someone can figure out a regex? I have done something like that: +[^ ][^ ][^ ][^ ][^ ][^ ][^ ]"; but this works only with a specific word lenght. I need to modify to get any word of any leght. Any help? Thank you.

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  • Regular Expression to match a string

    - by Adam Witko
    Hi, I've got two possible string inputs that my application will receive, and if it matches the following two strings, I need it regex.ismatch() to return true: "User * has logged out" "User * has joined" I'm not that good at regex and just can't figure out how to go about matching the above. Any help would be great!!!

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  • Zend Framework How can I print a logged in user name from a Zend_Session_Namespace

    - by IrishStudent76
    Hi all I have created the following login controller for my site and it works fine in relation to logging users in a logging them out. The thing I want to do is echo the logged in users name into the FlashMessenger for the success page how ever as my code stands I only get the following message when redirected to the success page, "you have been successfully logged in as Array". Can I also ask the following does the line $session-user =$adaptergetResultArray('Password'); create an array of user information less the password value from the database. Many Thanks in advance, IrishStudent76 <?php class LoginController extends Zend_Controller_Action { public function init(){ $this->view->doctype('XHTML1_STRICT'); } // login action public function loginAction() { $form = new PetManager_Form_Login; $this->view->form = $form; /* check for valid input from the form and authenticate using adapter Add user record to session and redirect to the original request URL if present */ if ($this->getRequest()->isPost()) { if ($form->isValid($this->getRequest()->getPost())) { $values = $form->getValues(); $adapter = new PetManager_Auth_Adapter_Doctrine( $values['username'], $values['password'] ); $auth = Zend_Auth::getInstance(); $result = $auth->authenticate($adapter); if ($result->isValid()) { $session = new Zend_Session_Namespace('petmanager.auth'); $session->user = $adapter->getResultArray('Password'); if (isset($session->requestURL)) { $url = $session->requestURL; unset($session->requestURL); $this->_redirect($url); } else { $this->_helper->getHelper('FlashMessenger') ->addMessage('You have been successfully logged in as '.$session- >user); $this->_redirect('/login/success'); } } else { $this->view->message = 'You could not be logged in. Please try again.'; } } } } public function successAction() { if ($this->_helper->getHelper('FlashMessenger')->getMessages()) { $this->view->messages = $this->_helper ->getHelper('FlashMessenger') ->getMessages(); } else { $this->_redirect('/login'); } } public function logoutAction() { Zend_Auth::getInstance()->clearIdentity(); Zend_Session::destroy(); $this->_redirect('/'); } }

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  • C#: Using regular expression (Regex) to duplicate a specific character in a string

    - by user3703944
    Anyone know how to use regex to duplicate a specific character in a string? I have a path that is entered like this: C:/Example/example I would like to use regex (or any other method) to display it like this: C://Example//example Is it possible? This is where I'm getting the file path private void btnSearchImage_Click_1(object sender, EventArgs e) { OpenFileDialog ofd = new OpenFileDialog(); ofd.Filter = "Image Files(*.jpg; *.jpeg; *.gif; *.bmp)|*.jpg; *.jpeg; *.gif; *.bmp"; if (ofd.ShowDialog() == System.Windows.Forms.DialogResult.OK) { string filenName = ofd.FileName; pictureBox1.Image = new Bitmap(filenName); string path = filenName; txtimgPath.Text = path; } } Thanks

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  • Regular expression - skip string in quotes using sed

    - by milano
    I have string like this: "Some standard text CONST_INSIDE_QUOTES" blah blah CONST "There might be another quotes" The thing is, that i want to replace all constants in string with some text, but it mustn't be applied on constants inside text in quotes. I have this regex: sed "s/([A-Z][A-Z0-9_]*)([^a-z])/<span class=\"const\"\1<\/span\2/g" which of course works for all consts. Any ideas how to exclude its apply on quotes constants? Unfortunately sed only...

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  • Regular expression help

    - by dmr
    I need to do a find and replace in Notepad of Err.Number, canBeAnything, canBeAnything, Err.Description (where canBeAnything is just what it says) with Err.Number, "canBeAnything", "canBeAnything", Err.Description (basically, put quotes around canBeAnything) I got as far as the find Err.Number, .+, .+, Err.Description But I'm stuck on the replace. Any suggestions?

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  • boolean VB expression returning false for integer 1

    - by Bill
    This is probably a really basic (no pun intended) question, but I can't seem to find an answer anywhere. Why does the result of func1 return False and func2 returns True? On every other test I have done, integer 1 is converted to boolean true and 0 to false. Works ok if I just set rtnValue to 1 or 0. Public Function func1() As Boolean Dim rtnValue As Integer = 0 Return rtnValue = 1 End Function Public Function func2() As Boolean Dim rtnValue As Integer = 0 Return rtnValue = 0 End Function

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  • Regular expression - stop at first match

    - by publicRavi
    My pattern looks something like <xxxx location="file path/level1/level2" xxxx some="xxx"> I am only interested in the part in quotes assigned to location. Shouldn't it be as easy as below without the greedy switch? Does not seem to work :( /.*location="(.*)".*/

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  • Regular expression problem

    - by sYl3r
    Hi, How can I search a whole string for a specific match. It'll contain both characters with int or decimal numbers eg A12B32.25C-456D-75.E75 I'll know that this will start with A and ends with E I think I can use "^" and "$" right? but i'm bit lost in other parts to check for character and int or decimal. I'll be glad if you can give the regex and explain it a bit :). PS. D-75. is not mistyped... Thanks in advance.

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