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  • Defining a function that is both a generator and recursive [on hold]

    - by user96454
    I am new to python, so this code might not necessarily be clean, it's just for learning purposes. I had the idea of writing this function that would display the tree down the specified path. Then, i added the global variable number_of_py to count how many python files were in that tree. That worked as well. Finally, i decided to turn the whole thing into a generator, but the recursion breaks. My understanding of generators is that once next() is called python just executes the body of the function and "yields" a value until we hit the end of the body. Can someone explain why this doesn't work? Thanks. import os from sys import argv script, path = argv number_of_py = 0 lines_of_code = 0 def list_files(directory, key=''): global number_of_py files = os.listdir(directory) for f in files: real_path = os.path.join(directory, f) if os.path.isdir(real_path): list_files(real_path, key=key+' ') else: if real_path.split('.')[-1] == 'py': number_of_py += 1 with open(real_path) as g: yield len(g.read()) print key+real_path for i in list_files(argv[1]): lines_of_code += i print 'total number of lines of code: %d' % lines_of_code print 'total number of py files: %d' % number_of_py

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  • Outlook macro runs through 250 iterations before failing with error [migrated]

    - by Senoculus
    Description: I have an Outlook macro that loops through selected emails in a folder and writes down some info to a .csv file. It works perfectly up until 250 before failing. Here is some of the code: Open strSaveAsFilename For Append As #1 CountVar = 0 For Each objItem In Application.ActiveExplorer.Selection DoEvents If objItem.VotingResponse <> "" Then CountVar = CountVar + 1 Debug.Print " " & CountVar & ". " & objItem.SenderName Print #1, & objItem.SenderName & "," & objItem.VotingResponse Else CountVar = CountVar + 1 Debug.Print " " & CountVar & ". " & "Moving email from: " & Chr(34) & objItem.SenderName & Chr(34) & " to: Special Cases sub-folder" objItem.Move CurrentFolderVar.Folders("Special Cases") End If Next Close #1 Problem After this code runs through 250 emails, the following screenshot pops up: http://i.stack.imgur.com/yt9P8.jpg I've tried adding a "wait" function to give the server a rest so that I'm not querying it so quickly, but I get the same error at the same point.

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  • Shutting down Ubuntu 11.10 with power button without x11-session

    - by RJdaMoD
    when pressing the power-button inside a (gnome-)session, ubuntu asks me what to do and shuts down after 60 seconds anyway. No problem so far. But if i'm not logged in in a gnome-session (for example in the login screen), or just change to a tty, then the power-button won't work. But i remember that i worked in 11.04. So what's changed and how to restore? Background: I use my machine as a print server. If im not home and my wife wants to print sth., she used to switch on my machine, print via her laptop, and then just shut it down by power-button. Beginning of march i was on a business tour, and she called me that she could not shutdown my machine anymore. I shut it down by ssh, but this seems not the favorable way to me. I already had a look in /etc/acpi/powerbtn.sh and think that the line if pidof x $PMS > /dev/null; then exit is the cause for this since it aborts the script when no gui-power-manager is found. Is that right? But that does not explain with the power-button does not work when switching from the x11-session to a tty, although this would not be critical to me. Thanks in advance Greetings RJ

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  • Printing Off Center or Images Offset After Upgrade to 14.04 LTS (Brother HL-2240)

    - by fortitude
    :) I have a very frustrating problem with my Brother HL-2240 under Ubuntu 14.04. Bear in mind this was working perfectly under Ubuntu 13.10. In Firefox, when I print a webpage, all of the images are off center and cut off, this is a big deal for my work. In Google Chrome, when I print a webpage, the page is off center, toward the right margin. In Opera, when I print a webpage, all of the white areas within the margins are black, using a lot of toner. PDF opened in document viewer, prints off center. Steps I have taken to troubleshoot: 1) Playing with the printer settings, resetting to defaults, etc. 2) Un-installing the Brother driver and re-installing (linux-brprinter-installer-2.0.0-1 from the Brother website), which works perfectly in Ubuntu 13.10. I see a similar, un-answered question, here. Hopefully this question provides some additional clarity to the matter. If anyone would like some additional detail because she or he is willing to help, please let me know. I can scan output from the printer to show you. Thank you.

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  • GeoTools Demo Embedded in an Application Framework via Maven

    - by Geertjan
    GeoTools 8.4 was very recently released, according to its active blog, and to celebrate here's a starting point for working with GeoTools on the NetBeans Platform: The sources of the above are below, as a Maven project, so this project can be used in any IDE or command line: http://java.net/projects/nb-api-samples/sources/api-samples/show/versions/7.3/tutorials/geospatial/geotools/MyGeospatialSystem Though quite dated, the GeoTools NetBeans Quick Start is very helpful, especially since it used Maven too, but not the NetBeans Platform, unlike the above sample. From the point of view of NetBeans Platform developers, the GeoTools JMapPane class is very useful, providing the integration point between GeoTools and the rest of the NetBeans Platform application. Being integrated into the NetBeans Platform means that a host of standard features are now available to the GeoTools features, e.g., print functionality, which only requires a runtime dependency on the NetBeans Print API, together with the "print.printable" client property put into constructor of the TopComponent: By the way, I've spent some time now and again being confused about the difference between GeoTools and GeoToolkit. Here's an interesting starting point to beginning to understand the differences and history between them. Soon I'd like to have an example similar for the above for GeoToolkit.

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  • ???????????/??????????????????|WebLogic Channel|??????

    - by ???02
    ?WebLogic Server???????????????????――???????WebLogic Server???????????????1???????????????????????????????????·????????????????????2011?11????????Oracle DAB & Developers Days 2011??????????????????????????WebLogic Server???????????????????????????????????????????????/?????????????????????????(???)????????????3??????????????????――??????????????????2????????·????????3?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????? ???????????????????????????????????????????8?????????????????5???????3?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????? ??????????300~3,500?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????·????????????????????????????????????????????????????¦???????????·??????????――?????·??????·???????????WebLogic????? ???????????????300??????????????????????????????????????????????????300???????????????????????????????????????????????????????????????????????????????(??????500???)???????????????????????????????????????????????????????????????????·??????????????????????????????????????¦????????????WebLogic Server - ???????·???????????4???????????????????????――???????????? ????????????????????????????????????????????????JDBC???????????????????JDBC??????????????????????JDBC????????????????????????????????????????????????????????? ??????????????????????????????????300????????500????????0????????100????????????????????????????????????????????????????????0??????????????????????????????????????????????????????????? ?????????????????????????????????????????????????????????JDBC????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????·?????????????????????????????¦?????Pick-Up???????WebLogic Server JDBC???·???????(10.3.4) ????????????????????????????????????????????????????????????????????????????? ??????????????????????????????????????????300?????????????????100???????????????????????????????????????????????????????????????????????????0??????????????????????????????????????????????????????????????????????????????????????????????? ????1????1????????????????????????????????????(???????????????)??????????????????????????????????????????????????????????????????? ??????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????? ???????????????????JDBC??????????????????????????????????JDBC???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????·????????????????????????????????????????????????????????????????MBean???????WebLogic Server???????? ?????????????????????????????MBean???????????? ??????????????MBean??????????????MBean???????????????????PendingUserRequestCount)??????????????????????·?????(ExecuteThreadIdleCount)????·??????????????????????·?????(StandbyThreadCount)?????????????????????·?????????????????(ExecuteThreadTotalCount)??????????????????????????????????????????????????????=????????-??????·??????-?????·????? ? ????????????MBean??????????????MBean???????????????(ActiveConnectionsCurrentCount)?????????????????????????????????????(ActiveConnectionsHighCount)????????????????????????????????????????????????????????????(WaitingForConnectionCurrentCount)?????????????????????????????(WaitingForConnectionHighCount)?????????????????????????????????????????????(?)(WaitSecondsHighCount)???????????????????????????????????? ????????????????????????WebLogic Server???????????????????????? ???????MBean????????WebLogic Server????????????????????WebLogic Scripting Tool(WLST)?????????????????????????????????????WLST????????????connect('weblogic','welcome1','t3://localhost:7001')import timeimport tracebackserverRuntime()print "Day,Time,State,CurrCapacity,ActiveConnectionsCurrentCount,WaitingForConnectionCurrentCount"while(true): try: oJDBCDataSourceRuntime = getMBean('JDBCServiceRuntime/<????>/JDBCDataSourceRuntimeMBeans/<???????>') oState = oJDBCDataSourceRuntime.getState() oCurrCapacity = oJDBCDataSourceRuntime.getCurrCapacity() oActiveConnectionsCurrentCount = oJDBCDataSourceRuntime.getActiveConnectionsCurrentCount() oWaitingForConnectionCurrentCount = oJDBCDataSourceRuntime.getWaitingForConnectionCurrentCount() print time.strftime('%Y-%m-%d,%H:%M:%S') + "," + str(oState) + "," + str(oCurrCapacity) + "," + str(oActiveConnectionsCurrentCount) + "," + str(oWaitingForConnectionCurrentCount) time.sleep(1) except: print "<<<error>>>" traceback.print_exc() disconnect() break ?????????test.py??????/????????????????$ java weblogic.WLST test.py...?...Day,Time,State,CurrCapacity,ActiveConnectionsCurrentCount,WaitingForConnectionCurrentCount2011-10-31,22:39:01,Running,10,0,02011-10-31,22:39:02,Running,10,0,02011-10-31,22:39:03,Running,12,9,02011-10-31,22:39:04,Running,22,18,02011-10-31,22:39:05,Running,29,15,02011-10-31,22:39:06,Running,29,14,02011-10-31,22:39:07,Running,16,15,02011-10-31,22:39:08,Running,19,15,02011-10-31,22:39:09,Running,19,15,02011-10-31,22:39:10,Running,19,14,02011-10-31,22:39:11,Running,19,15,02011-10-31,22:39:12,Running,19,14,02011-10-31,22:39:13,Running,19,0,0 WLST??????WebLogic Channel?????????·???????! ?WebLogic Scripting Tool????WebLogic Server???/?????????????????????????????????????¦????????·???????! ?WebLogic Scripting Tool????WebLogic Server???/???????¦Oracle DAB & Developers Days 2011????????????????????WebLogic Server??????????????

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  • Oauth for Google API example using Python / Django

    - by DrDee
    Hi, I am trying to get Oauth working with the Google API using Python. I have tried different oauth libraries such as oauth, oauth2 and djanog-oauth but I cannot get it to work (including the provided examples). For debugging Oauth I use Google's Oauth Playground and I have studied the API and the Oauth documentation With some libraries I am struggling with getting a right signature, with other libraries I am struggling with converting the request token to an authorized token. What would really help me if someone can show me a working example for the Google API using one of the above-mentioned libraries. EDIT: My initial question did not lead to any answers so I have added my code. There are two possible causes of this code not working: 1) Google does not authorize my request token, but not quite sure how to detect this 2) THe signature for the access token is invalid but then I would like to know which oauth parameters Google is expecting as I am able to generate a proper signature in the first phase. This is written using oauth2.py and for Django hence the HttpResponseRedirect. REQUEST_TOKEN_URL = 'https://www.google.com/accounts/OAuthGetRequestToken' AUTHORIZATION_URL = 'https://www.google.com/accounts/OAuthAuthorizeToken' ACCESS_TOKEN_URL = 'https://www.google.com/accounts/OAuthGetAccessToken' CALLBACK = 'http://localhost:8000/mappr/mappr/oauth/' #will become real server when deployed OAUTH_CONSUMER_KEY = 'anonymous' OAUTH_CONSUMER_SECRET = 'anonymous' signature_method = oauth.SignatureMethod_HMAC_SHA1() consumer = oauth.Consumer(key=OAUTH_CONSUMER_KEY, secret=OAUTH_CONSUMER_SECRET) client = oauth.Client(consumer) request_token = oauth.Token('','') #hackish way to be able to access the token in different functions, I know this is bad, but I just want it to get working in the first place :) def authorize(request): if request.GET == {}: tokens = OAuthGetRequestToken() return HttpResponseRedirect(AUTHORIZATION_URL + '?' + tokens) elif request.GET['oauth_verifier'] != '': oauth_token = request.GET['oauth_token'] oauth_verifier = request.GET['oauth_verifier'] OAuthAuthorizeToken(oauth_token) OAuthGetAccessToken(oauth_token, oauth_verifier) #I need to add a Django return object but I am still debugging other phases. def OAuthGetRequestToken(): print '*** OUTPUT OAuthGetRequestToken ***' params = { 'oauth_consumer_key': OAUTH_CONSUMER_KEY, 'oauth_nonce': oauth.generate_nonce(), 'oauth_signature_method': 'HMAC-SHA1', 'oauth_timestamp': int(time.time()), #The timestamp should be expressed in number of seconds after January 1, 1970 00:00:00 GMT. 'scope': 'https://www.google.com/analytics/feeds/', 'oauth_callback': CALLBACK, 'oauth_version': '1.0' } # Sign the request. req = oauth.Request(method="GET", url=REQUEST_TOKEN_URL, parameters=params) req.sign_request(signature_method, consumer, None) tokens =client.request(req.to_url())[1] params = ConvertURLParamstoDictionary(tokens) request_token.key = params['oauth_token'] request_token.secret = params['oauth_token_secret'] return tokens def OAuthAuthorizeToken(oauth_token): print '*** OUTPUT OAuthAuthorizeToken ***' params ={ 'oauth_token' :oauth_token, 'hd': 'default' } req = oauth.Request(method="GET", url=AUTHORIZATION_URL, parameters=params) req.sign_request(signature_method, consumer, request_token) response =client.request(req.to_url()) print response #for debugging purposes def OAuthGetAccessToken(oauth_token, oauth_verifier): print '*** OUTPUT OAuthGetAccessToken ***' params = { 'oauth_consumer_key': OAUTH_CONSUMER_KEY, 'oauth_token': oauth_token, 'oauth_verifier': oauth_verifier, 'oauth_token_secret': request_token.secret, 'oauth_signature_method': 'HMAC-SHA1', 'oauth_timestamp': int(time.time()), 'oauth_nonce': oauth.generate_nonce(), 'oauth_version': '1.0', } req = oauth.Request(method="GET", url=ACCESS_TOKEN_URL, parameters=params) req.sign_request(signature_method, consumer, request_token) response =client.request(req.to_url()) print response return req def ConvertURLParamstoDictionary(tokens): params = {} tokens = tokens.split('&') for token in tokens: token = token.split('=') params[token[0]] = token[1] return params

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  • Quick guide to Oracle IRM 11g: Classification design

    - by Simon Thorpe
    Quick guide to Oracle IRM 11g indexThis is the final article in the quick guide to Oracle IRM. If you've followed everything prior you will now have a fully functional and tested Information Rights Management service. It doesn't matter if you've been following the 10g or 11g guide as this next article is common to both. ContentsWhy this is the most important part... Understanding the classification and standard rights model Identifying business use cases Creating an effective IRM classification modelOne single classification across the entire businessA context for each and every possible granular use caseWhat makes a good context? Deciding on the use of roles in the context Reviewing the features and security for context roles Summary Why this is the most important part...Now the real work begins, installing and getting an IRM system running is as simple as following instructions. However to actually have an IRM technology easily protecting your most sensitive information without interfering with your users existing daily work flows and be able to scale IRM across the entire business, requires thought into how confidential documents are created, used and distributed. This article is going to give you the information you need to ask the business the right questions so that you can deploy your IRM service successfully. The IRM team here at Oracle have over 10 years of experience in helping customers and it is important you understand the following to be successful in securing access to your most confidential information. Whatever you are trying to secure, be it mergers and acquisitions information, engineering intellectual property, health care documentation or financial reports. No matter what type of user is going to access the information, be they employees, contractors or customers, there are common goals you are always trying to achieve.Securing the content at the earliest point possible and do it automatically. Removing the dependency on the user to decide to secure the content reduces the risk of mistakes significantly and therefore results a more secure deployment. K.I.S.S. (Keep It Simple Stupid) Reduce complexity in the rights/classification model. Oracle IRM lets you make changes to access to documents even after they are secured which allows you to start with a simple model and then introduce complexity once you've understood how the technology is going to be used in the business. After an initial learning period you can review your implementation and start to make informed decisions based on user feedback and administration experience. Clearly communicate to the user, when appropriate, any changes to their existing work practice. You must make every effort to make the transition to sealed content as simple as possible. For external users you must help them understand why you are securing the documents and inform them the value of the technology to both your business and them. Before getting into the detail, I must pay homage to Martin White, Vice President of client services in SealedMedia, the company Oracle acquired and who created Oracle IRM. In the SealedMedia years Martin was involved with every single customer and was key to the design of certain aspects of the IRM technology, specifically the context model we will be discussing here. Listening carefully to customers and understanding the flexibility of the IRM technology, Martin taught me all the skills of helping customers build scalable, effective and simple to use IRM deployments. No matter how well the engineering department designed the software, badly designed and poorly executed projects can result in difficult to use and manage, and ultimately insecure solutions. The advice and information that follows was born with Martin and he's still delivering IRM consulting with customers and can be found at www.thinkers.co.uk. It is from Martin and others that Oracle not only has the most advanced, scalable and usable document security solution on the market, but Oracle and their partners have the most experience in delivering successful document security solutions. Understanding the classification and standard rights model The goal of any successful IRM deployment is to balance the increase in security the technology brings without over complicating the way people use secured content and avoid a significant increase in administration and maintenance. With Oracle it is possible to automate the protection of content, deploy the desktop software transparently and use authentication methods such that users can open newly secured content initially unaware the document is any different to an insecure one. That is until of course they attempt to do something for which they don't have any rights, such as copy and paste to an insecure application or try and print. Central to achieving this objective is creating a classification model that is simple to understand and use but also provides the right level of complexity to meet the business needs. In Oracle IRM the term used for each classification is a "context". A context defines the relationship between.A group of related documents The people that use the documents The roles that these people perform The rights that these people need to perform their role The context is the key to the success of Oracle IRM. It provides the separation of the role and rights of a user from the content itself. Documents are sealed to contexts but none of the rights, user or group information is stored within the content itself. Sealing only places information about the location of the IRM server that sealed it, the context applied to the document and a few other pieces of metadata that pertain only to the document. This important separation of rights from content means that millions of documents can be secured against a single classification and a user needs only one right assigned to be able to access all documents. If you have followed all the previous articles in this guide, you will be ready to start defining contexts to which your sensitive information will be protected. But before you even start with IRM, you need to understand how your own business uses and creates sensitive documents and emails. Identifying business use cases Oracle is able to support multiple classification systems, but usually there is one single initial need for the technology which drives a deployment. This need might be to protect sensitive mergers and acquisitions information, engineering intellectual property, financial documents. For this and every subsequent use case you must understand how users create and work with documents, to who they are distributed and how the recipients should interact with them. A successful IRM deployment should start with one well identified use case (we go through some examples towards the end of this article) and then after letting this use case play out in the business, you learn how your users work with content, how well your communication to the business worked and if the classification system you deployed delivered the right balance. It is at this point you can start rolling the technology out further. Creating an effective IRM classification model Once you have selected the initial use case you will address with IRM, you need to design a classification model that defines the access to secured documents within the use case. In Oracle IRM there is an inbuilt classification system called the "context" model. In Oracle IRM 11g it is possible to extend the server to support any rights classification model, but the majority of users who are not using an application integration (such as Oracle IRM within Oracle Beehive) are likely to be starting out with the built in context model. Before looking at creating a classification system with IRM, it is worth reviewing some recognized standards and methods for creating and implementing security policy. A very useful set of documents are the ISO 17799 guidelines and the SANS security policy templates. First task is to create a context against which documents are to be secured. A context consists of a group of related documents (all top secret engineering research), a list of roles (contributors and readers) which define how users can access documents and a list of users (research engineers) who have been given a role allowing them to interact with sealed content. Before even creating the first context it is wise to decide on a philosophy which will dictate the level of granularity, the question is, where do you start? At a department level? By project? By technology? First consider the two ends of the spectrum... One single classification across the entire business Imagine that instead of having separate contexts, one for engineering intellectual property, one for your financial data, one for human resources personally identifiable information, you create one context for all documents across the entire business. Whilst you may have immediate objections, there are some significant benefits in thinking about considering this. Document security classification decisions are simple. You only have one context to chose from! User provisioning is simple, just make sure everyone has a role in the only context in the business. Administration is very low, if you assign rights to groups from the business user repository you probably never have to touch IRM administration again. There are however some obvious downsides to this model.All users in have access to all IRM secured content. So potentially a sales person could access sensitive mergers and acquisition documents, if they can get their hands on a copy that is. You cannot delegate control of different documents to different parts of the business, this may not satisfy your regulatory requirements for the separation and delegation of duties. Changing a users role affects every single document ever secured. Even though it is very unlikely a business would ever use one single context to secure all their sensitive information, thinking about this scenario raises one very important point. Just having one single context and securing all confidential documents to it, whilst incurring some of the problems detailed above, has one huge value. Once secured, IRM protected content can ONLY be accessed by authorized users. Just think of all the sensitive documents in your business today, imagine if you could ensure that only everyone you trust could open them. Even if an employee lost a laptop or someone accidentally sent an email to the wrong recipient, only the right people could open that file. A context for each and every possible granular use case Now let's think about the total opposite of a single context design. What if you created a context for each and every single defined business need and created multiple contexts within this for each level of granularity? Let's take a use case where we need to protect engineering intellectual property. Imagine we have 6 different engineering groups, and in each we have a research department, a design department and manufacturing. The company information security policy defines 3 levels of information sensitivity... restricted, confidential and top secret. Then let's say that each group and department needs to define access to information from both internal and external users. Finally add into the mix that they want to review the rights model for each context every financial quarter. This would result in a huge amount of contexts. For example, lets just look at the resulting contexts for one engineering group. Q1FY2010 Restricted Internal - Engineering Group 1 - Research Q1FY2010 Restricted Internal - Engineering Group 1 - Design Q1FY2010 Restricted Internal - Engineering Group 1 - Manufacturing Q1FY2010 Restricted External- Engineering Group 1 - Research Q1FY2010 Restricted External - Engineering Group 1 - Design Q1FY2010 Restricted External - Engineering Group 1 - Manufacturing Q1FY2010 Confidential Internal - Engineering Group 1 - Research Q1FY2010 Confidential Internal - Engineering Group 1 - Design Q1FY2010 Confidential Internal - Engineering Group 1 - Manufacturing Q1FY2010 Confidential External - Engineering Group 1 - Research Q1FY2010 Confidential External - Engineering Group 1 - Design Q1FY2010 Confidential External - Engineering Group 1 - Manufacturing Q1FY2010 Top Secret Internal - Engineering Group 1 - Research Q1FY2010 Top Secret Internal - Engineering Group 1 - Design Q1FY2010 Top Secret Internal - Engineering Group 1 - Manufacturing Q1FY2010 Top Secret External - Engineering Group 1 - Research Q1FY2010 Top Secret External - Engineering Group 1 - Design Q1FY2010 Top Secret External - Engineering Group 1 - Manufacturing Now multiply the above by 6 for each engineering group, 18 contexts. You are then creating/reviewing another 18 every 3 months. After a year you've got 72 contexts. What would be the advantages of such a complex classification model? You can satisfy very granular rights requirements, for example only an authorized engineering group 1 researcher can create a top secret report for access internally, and his role will be reviewed on a very frequent basis. Your business may have very complex rights requirements and mapping this directly to IRM may be an obvious exercise. The disadvantages of such a classification model are significant...Huge administrative overhead. Someone in the business must manage, review and administrate each of these contexts. If the engineering group had a single administrator, they would have 72 classifications to reside over each year. From an end users perspective life will be very confusing. Imagine if a user has rights in just 6 of these contexts. They may be able to print content from one but not another, be able to edit content in 2 contexts but not the other 4. Such confusion at the end user level causes frustration and resistance to the use of the technology. Increased synchronization complexity. Imagine a user who after 3 years in the company ends up with over 300 rights in many different contexts across the business. This would result in long synchronization times as the client software updates all your offline rights. Hard to understand who can do what with what. Imagine being the VP of engineering and as part of an internal security audit you are asked the question, "What rights to researchers have to our top secret information?". In this complex model the answer is not simple, it would depend on many roles in many contexts. Of course this example is extreme, but it highlights that trying to build many barriers in your business can result in a nightmare of administration and confusion amongst users. In the real world what we need is a balance of the two. We need to seek an optimum number of contexts. Too many contexts are unmanageable and too few contexts does not give fine enough granularity. What makes a good context? Good context design derives mainly from how well you understand your business requirements to secure access to confidential information. Some customers I have worked with can tell me exactly the documents they wish to secure and know exactly who should be opening them. However there are some customers who know only of the government regulation that requires them to control access to certain types of information, they don't actually know where the documents are, how they are created or understand exactly who should have access. Therefore you need to know how to ask the business the right questions that lead to information which help you define a context. First ask these questions about a set of documentsWhat is the topic? Who are legitimate contributors on this topic? Who are the authorized readership? If the answer to any one of these is significantly different, then it probably merits a separate context. Remember that sealed documents are inherently secure and as such they cannot leak to your competitors, therefore it is better sealed to a broad context than not sealed at all. Simplicity is key here. Always revert to the first extreme example of a single classification, then work towards essential complexity. If there is any doubt, always prefer fewer contexts. Remember, Oracle IRM allows you to change your mind later on. You can implement a design now and continue to change and refine as you learn how the technology is used. It is easy to go from a simple model to a more complex one, it is much harder to take a complex model that is already embedded in the work practice of users and try to simplify it. It is also wise to take a single use case and address this first with the business. Don't try and tackle many different problems from the outset. Do one, learn from the process, refine it and then take what you have learned into the next use case, refine and continue. Once you have a good grasp of the technology and understand how your business will use it, you can then start rolling out the technology wider across the business. Deciding on the use of roles in the context Once you have decided on that first initial use case and a context to create let's look at the details you need to decide upon. For each context, identify; Administrative rolesBusiness owner, the person who makes decisions about who may or may not see content in this context. This is often the person who wanted to use IRM and drove the business purchase. They are the usually the person with the most at risk when sensitive information is lost. Point of contact, the person who will handle requests for access to content. Sometimes the same as the business owner, sometimes a trusted secretary or administrator. Context administrator, the person who will enact the decisions of the Business Owner. Sometimes the point of contact, sometimes a trusted IT person. Document related rolesContributors, the people who create and edit documents in this context. Reviewers, the people who are involved in reviewing documents but are not trusted to secure information to this classification. This role is not always necessary. (See later discussion on Published-work and Work-in-Progress) Readers, the people who read documents from this context. Some people may have several of the roles above, which is fine. What you are trying to do is understand and define how the business interacts with your sensitive information. These roles obviously map directly to roles available in Oracle IRM. Reviewing the features and security for context roles At this point we have decided on a classification of information, understand what roles people in the business will play when administrating this classification and how they will interact with content. The final piece of the puzzle in getting the information for our first context is to look at the permissions people will have to sealed documents. First think why are you protecting the documents in the first place? It is to prevent the loss of leaking of information to the wrong people. To control the information, making sure that people only access the latest versions of documents. You are not using Oracle IRM to prevent unauthorized people from doing legitimate work. This is an important point, with IRM you can erect many barriers to prevent access to content yet too many restrictions and authorized users will often find ways to circumvent using the technology and end up distributing unprotected originals. Because IRM is a security technology, it is easy to get carried away restricting different groups. However I would highly recommend starting with a simple solution with few restrictions. Ensure that everyone who reasonably needs to read documents can do so from the outset. Remember that with Oracle IRM you can change rights to content whenever you wish and tighten security. Always return to the fact that the greatest value IRM brings is that ONLY authorized users can access secured content, remember that simple "one context for the entire business" model. At the start of the deployment you really need to aim for user acceptance and therefore a simple model is more likely to succeed. As time passes and users understand how IRM works you can start to introduce more restrictions and complexity. Another key aspect to focus on is handling exceptions. If you decide on a context model where engineering can only access engineering information, and sales can only access sales data. Act quickly when a sales manager needs legitimate access to a set of engineering documents. Having a quick and effective process for permitting other people with legitimate needs to obtain appropriate access will be rewarded with acceptance from the user community. These use cases can often be satisfied by integrating IRM with a good Identity & Access Management technology which simplifies the process of assigning users the correct business roles. The big print issue... Printing is often an issue of contention, users love to print but the business wants to ensure sensitive information remains in the controlled digital world. There are many cases of physical document loss causing a business pain, it is often overlooked that IRM can help with this issue by limiting the ability to generate physical copies of digital content. However it can be hard to maintain a balance between security and usability when it comes to printing. Consider the following points when deciding about whether to give print rights. Oracle IRM sealed documents can contain watermarks that expose information about the user, time and location of access and the classification of the document. This information would reside in the printed copy making it easier to trace who printed it. Printed documents are slower to distribute in comparison to their digital counterparts, so time sensitive information in printed format may present a lower risk. Print activity is audited, therefore you can monitor and react to users abusing print rights. Summary In summary it is important to think carefully about the way you create your context model. As you ask the business these questions you may get a variety of different requirements. There may be special projects that require a context just for sensitive information created during the lifetime of the project. There may be a department that requires all information in the group is secured and you might have a few senior executives who wish to use IRM to exchange a small number of highly sensitive documents with a very small number of people. Oracle IRM, with its very flexible context classification system, can support all of these use cases. The trick is to introducing the complexity to deliver them at the right level. In another article i'm working on I will go through some examples of how Oracle IRM might map to existing business use cases. But for now, this article covers all the important questions you need to get your IRM service deployed and successfully protecting your most sensitive information.

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  • Powerpoint 2010 crash on quickstyle menu

    - by Marcus Lindblom
    Windows 7 64-bit, recent install, added Office 2010. When I create some boxes and open the quick-style menu, it crashes (or stops responding, in windowese, and then it sends an error report). I've run the "Repair" from the installer, but it didn't help. There's nothing in Windows Update I've Googled and searched on Microsoft's site, but n Any other ideas? (It's not related to this ppt crash question as that concerns PPT 2007. Error in event log: Faulting application name: POWERPNT.EXE, version: 14.0.4754.1000, time stamp: 0x4b967cf2 Faulting module name: KERNELBASE.dll, version: 6.1.7600.16385, time stamp: 0x4a5bdfe0 Exception code: 0xe0000003 Fault offset: 0x000000000000aa7d Faulting process id: 0xee8 Faulting application start time: 0x01cb9dc710fd76d8 Faulting application path: C:\Program Files\Microsoft Office\Office14\POWERPNT.EXE Faulting module path: C:\Windows\system32\KERNELBASE.dll Report Id: 58766562-09ba-11e0-90d1-00215a139192 And: Fault bucket , type 0 Event Name: APPCRASH Response: Not available Cab Id: 0 Problem signature: P1: POWERPNT.EXE P2: 14.0.4754.1000 P3: 4b967cf2 P4: KERNELBASE.dll P5: 6.1.7600.16385 P6: 4a5bdfe0 P7: e0000003 P8: 000000000000aa7d P9: P10: Attached files: C:\Users\marcusl\AppData\Local\Temp\CVR86DD.tmp.cvr C:\Users\marcusl\AppData\Local\Temp\WERC765.tmp.WERInternalMetadata.xml These files may be available here: C:\Users\marcusl\AppData\Local\Microsoft\Windows\WER\ReportArchive\AppCrash_POWERPNT.EXE_d45f313d77f7e52cc8682b2b64cc3898127c2c_1106e3ac Analysis symbol: Rechecking for solution: 0 Report Id: 58766562-09ba-11e0-90d1-00215a139192 Report Status: 1

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  • Python: How to read huge text file into memory

    - by asmaier
    I'm using Python 2.6 on a Mac Mini with 1GB RAM. I want to read in a huge text file $ ls -l links.csv; file links.csv; tail links.csv -rw-r--r-- 1 user user 469904280 30 Nov 22:42 links.csv links.csv: ASCII text, with CRLF line terminators 4757187,59883 4757187,99822 4757187,66546 4757187,638452 4757187,4627959 4757187,312826 4757187,6143 4757187,6141 4757187,3081726 4757187,58197 So each line in the file consists of a tuple of two comma separated integer values. I want to read in the whole file and sort it according to the second column. I know, that I could do the sorting without reading the whole file into memory. But I thought for a file of 500MB I should still be able to do it in memory since I have 1GB available. However when I try to read in the file, Python seems to allocate a lot more memory than is needed by the file on disk. So even with 1GB of RAM I'm not able to read in the 500MB file into memory. My Python code for reading the file and printing some information about the memory consumption is: #!/usr/bin/python # -*- coding: utf-8 -*- import sys infile=open("links.csv", "r") edges=[] count=0 #count the total number of lines in the file for line in infile: count=count+1 total=count print "Total number of lines: ",total infile.seek(0) count=0 for line in infile: edge=tuple(map(int,line.strip().split(","))) edges.append(edge) count=count+1 # for every million lines print memory consumption if count%1000000==0: print "Position: ", edge print "Read ",float(count)/float(total)*100,"%." mem=sys.getsizeof(edges) for edge in edges: mem=mem+sys.getsizeof(edge) for node in edge: mem=mem+sys.getsizeof(node) print "Memory (Bytes): ", mem The output I got was: Total number of lines: 30609720 Position: (9745, 2994) Read 3.26693612356 %. Memory (Bytes): 64348736 Position: (38857, 103574) Read 6.53387224712 %. Memory (Bytes): 128816320 Position: (83609, 63498) Read 9.80080837067 %. Memory (Bytes): 192553000 Position: (139692, 1078610) Read 13.0677444942 %. Memory (Bytes): 257873392 Position: (205067, 153705) Read 16.3346806178 %. Memory (Bytes): 320107588 Position: (283371, 253064) Read 19.6016167413 %. Memory (Bytes): 385448716 Position: (354601, 377328) Read 22.8685528649 %. Memory (Bytes): 448629828 Position: (441109, 3024112) Read 26.1354889885 %. Memory (Bytes): 512208580 Already after reading only 25% of the 500MB file, Python consumes 500MB. So it seem that storing the content of the file as a list of tuples of ints is not very memory efficient. Is there a better way to do it, so that I can read in my 500MB file into my 1GB of memory?

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  • How can I handle UTF-8 while posting to a vBulletin board with WWW::Mechanize?

    - by MrMirror
    I have a problem with some automating posting to bulletin board... If I send the posting form to the vBulletin board, I get corrupted entities. Feel free to copy-paste the script and try it... It looks like the board's expecting some decoded utf8, but if I send the message decoded the entities are still wrong. #!/usr/bin/perl use strict; use warnings; use WWW::Mechanize; use Digest::MD5 qw(md5_hex); my $mech = WWW::Mechanize->new(); my $base_url = 'http://www.boerse.bz/'; my $username = 'MrMirror'; my $password = 'test'; $mech->get($base_url); print "Login\n"; $mech->form_number(1); $mech->field('vb_login_username' => $username); $mech->field('vb_login_password' => $password); $mech->field('vb_login_md5password' => md5_hex($password)); $mech->field('vb_login_md5password_utf' => md5_hex($password)); $mech->submit(); unless ($mech->content() =~ m!Weiterleitung!gi) { print "No Rediction!\n"; exit; } print "Redict\n"; $mech->get($base_url); unless ($mech->content() =~ m!Logout!gi) { print "Login Failed!\n"; exit; } $mech->get($base_url .'/newthread.php?do=newthread&f=173'); $mech->form_number(3); $mech->field('subject' => 'MrMirror makes some testing ä ö ü ß'); $mech->field('message' => "ä ö ü ß"); ### everything allright here $mech->dump_forms(); ### preview submit, don't wanna spam around ;) $mech->click('preview'); print "\n\n\n---------------------------------------------------------------------\n\n\n"; ### same form, wrong entities :( $mech->dump_forms();

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  • How to make and use first object in Objective C to store sender tag

    - by dbonneville
    I started with a sample program that simply sets up a UIView with some buttons on it. Works great. I want to access the sender tag from each button and save it. My first thought was to save it to a global variable but I couldn't get it to work right. I thought the best way would be to create an object with one property and synthesize it so I can get or set it as needed. First, I created GlobalGem.h: #import <Foundation/Foundation.h> @interface GlobalGem : NSObject { int gemTag; } @property int gemTag; -(void) print; @end Then I created GlobalGem.m: #import "GlobalGem.h" @implementation GlobalGem @synthesize gemTag; -(void) print { NSLog(@"gemTag value is %i", gemTag); } @end The sample code I worked from doesn't do anything I can see in "main" where the program initializes. They just have their methods and are set up to handle IBOutlet actions. I want to use this object in the IBOutlet methods. But I don't know where to create the object. In the viewDidLoad, I tried this: GlobalGem *aGem = [[GlobalGem alloc]init]; [aGem print]; I added reference to the .h file of course. The print method works. In the nslog I get "gemTag value is 0". But now I want to use the instance aGem in some of the IBOutlet actions. For instance, if I put this same method in one of the outlet actions like this: - (IBAction)touchButton:(id)sender { [aGem print]; } ...I get a build error saying that "aGem is undeclared". Yes, I'm new to objective c and am very confused. Is the instance I created, aGem, in the viewDidLoad not accessible outside of that method? How would I create an instance of a Class that I can store a variable value that any of the IBOutlet methods can access? All the buttons need to be able to store their sender tag in the instance aGem and I'm stuck. As I mentioned earlier, I was able to write the sender tag to a global variable I declared in the UIView .h file that came with the program, but I ran into issues using it. Where am I off?

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  • A python random function acts differently when assigned to a list or called directly...

    - by Dror Hilman
    I have a python function that randomize a dictionary representing a position specific scoring matrix. for example: mat = { 'A' : [ 0.53, 0.66, 0.67, 0.05, 0.01, 0.86, 0.03, 0.97, 0.33, 0.41, 0.26 ] 'C' : [ 0.14, 0.04, 0.13, 0.92, 0.99, 0.04, 0.94, 0.00, 0.07, 0.23, 0.35 ] 'T' : [ 0.25, 0.07, 0.01, 0.01, 0.00, 0.04, 0.00, 0.03, 0.06, 0.12, 0.14 ] 'G' : [ 0.08, 0.23, 0.20, 0.02, 0.00, 0.06, 0.04, 0.00, 0.54, 0.24, 0.25 ] } The scambling function: def scramble_matrix(matrix, iterations): mat_len = len(matrix["A"]) pos1 = pos2 = 0 for count in range(iterations): pos1,pos2 = random.sample(range(mat_len), 2) #suffle the matrix: for nuc in matrix.keys(): matrix[nuc][pos1],matrix[nuc][pos2] = matrix[nuc][pos2],matrix[nuc][pos1] return matrix def print_matrix(matrix): for nuc in matrix.keys(): print nuc+"[", for count in matrix[nuc]: print "%.2f"%count, print "]" now to the problem... When I try to scramble a matrix directly, It's works fine: print_matrix(mat) print "" print_matrix(scramble_matrix(mat,10)) gives: A[ 0.53 0.66 0.67 0.05 0.01 0.86 0.03 0.97 0.33 0.41 0.26 ] C[ 0.14 0.04 0.13 0.92 0.99 0.04 0.94 0.00 0.07 0.23 0.35 ] T[ 0.25 0.07 0.01 0.01 0.00 0.04 0.00 0.03 0.06 0.12 0.14 ] G[ 0.08 0.23 0.20 0.02 0.00 0.06 0.04 0.00 0.54 0.24 0.25 ] A[ 0.41 0.97 0.03 0.86 0.53 0.66 0.33.05 0.67 0.26 0.01 ] C[ 0.23 0.00 0.94 0.04 0.14 0.04 0.07 0.92 0.13 0.35 0.99 ] T[ 0.12 0.03 0.00 0.04 0.25 0.07 0.06 0.01 0.01 0.14 0.00 ] G[ 0.24 0.00 0.04 0.06 0.08 0.23 0.54 0.02 0.20 0.25 0.00 ] but when I try to assign this scrambling to a list , it does not work!!! ... print_matrix(mat) s=[] for x in range(3): s.append(scramble_matrix(mat,10)) for matrix in s: print "" print_matrix(matrix) result: A[ 0.53 0.66 0.67 0.05 0.01 0.86 0.03 0.97 0.33 0.41 0.26 ] C[ 0.14 0.04 0.13 0.92 0.99 0.04 0.94 0.00 0.07 0.23 0.35 ] T[ 0.25 0.07 0.01 0.01 0.00 0.04 0.00 0.03 0.06 0.12 0.14 ] G[ 0.08 0.23 0.20 0.02 0.00 0.06 0.04 0.00 0.54 0.24 0.25 ] A[ 0.01 0.66 0.97 0.67 0.03 0.05 0.33 0.53 0.26 0.41 0.86 ] C[ 0.99 0.04 0.00 0.13 0.94 0.92 0.07 0.14 0.35 0.23 0.04 ] T[ 0.00 0.07 0.03 0.01 0.00 0.01 0.06 0.25 0.14 0.12 0.04 ] G[ 0.00 0.23 0.00 0.20 0.04 0.02 0.54 0.08 0.25 0.24 0.06 ] A[ 0.01 0.66 0.97 0.67 0.03 0.05 0.33 0.53 0.26 0.41 0.86 ] C[ 0.99 0.04 0.00 0.13 0.94 0.92 0.07 0.14 0.35 0.23 0.04 ] T[ 0.00 0.07 0.03 0.01 0.00 0.01 0.06 0.25 0.14 0.12 0.04 ] G[ 0.00 0.23 0.00 0.20 0.04 0.02 0.54 0.08 0.25 0.24 0.06 ] A[ 0.01 0.66 0.97 0.67 0.03 0.05 0.33 0.53 0.26 0.41 0.86 ] C[ 0.99 0.04 0.00 0.13 0.94 0.92 0.07 0.14 0.35 0.23 0.04 ] T[ 0.00 0.07 0.03 0.01 0.00 0.01 0.06 0.25 0.14 0.12 0.04 ] G[ 0.00 0.23 0.00 0.20 0.04 0.02 0.54 0.08 0.25 0.24 0.06 ] What is the problem??? Why the scrambling do not work after the first time, and all the list filled with the same matrix?!

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  • Selecting MediaTray in Java printing

    - by Rocket Surgeon
    I am trying to programmatically select a different media tray using Java Printing API. However, my document always gets printed to the default (TOP) media tray. I checked if the MediaTray attributes are supported using "isAttributeValueSupported()" method on javax.print.PrintService interface and I am getting the result as "true" for each MediaTray I pass. Here is my code: public void print( String printerName, com.company.services.document.transferobject.MediaTray tray, byte[] document) { String methodName = "print: "; logger.sendEvent(CLASS_NAME + methodName + "Start", EventType.INFO, this); if (printerName == null || "none".equals(printerName) || "?".equals(printerName) || "null".equals(printerName)) { logger.sendEvent("Please supply printer name, currently printerName is "+printerName, EventType.INFO, this); return; } DocFlavor flavor = DocFlavor.BYTE_ARRAY.AUTOSENSE; AttributeSet attributeSet = new HashAttributeSet(); attributeSet.add(new PrinterName(printerName, null)); javax.print.PrintService service = getService(printerName); if (service.isAttributeValueSupported(MediaTray.TOP, flavor, null)) { System.out.println("---------->>>>>>>>>Yes TOP" + " : Value : " + MediaTray.TOP.getValue()); } else { System.out.println("---------->>>>>>>>>Nope"); } if (service.isAttributeValueSupported(MediaTray.BOTTOM, flavor, null)) { System.out.println("---------->>>>>>>>>Yes BOTTOM" + " : Value : " + MediaTray.BOTTOM.getValue()); } else { System.out.println("---------->>>>>>>>>Nope"); } if (service.isAttributeValueSupported(MediaTray.MIDDLE, flavor, null)) { System.out.println("---------->>>>>>>>>Yes MIDDLE" + " : Value : " + MediaTray.MIDDLE.getValue()); } else { System.out.println("---------->>>>>>>>>Nope"); } if (service.isAttributeValueSupported(MediaTray.MANUAL, flavor, null)) { System.out.println("---------->>>>>>>>>Yes MANUAL" + " : Value : " + MediaTray.MANUAL.getValue()); } else { System.out.println("---------->>>>>>>>>Nope"); } if (service.isAttributeValueSupported(MediaTray.SIDE, flavor, null)) { System.out.println("---------->>>>>>>>>Yes SIDE" + " : Value : " + MediaTray.SIDE.getValue()); } else { System.out.println("---------->>>>>>>>>Nope"); } DocPrintJob printJob = service.createPrintJob(); try { byte[] textStream = document; PrintRequestAttributeSet pras = new HashPrintRequestAttributeSet(); pras.add(DocumentServiceConstant. DEFAULT_ONE_PRINT_COPY); pras.add(Sides.ONE_SIDED); Media standardTray= toStandardTray(tray); if (null != standardTray) { pras.add(standardTray); } Doc myDoc = new SimpleDoc(textStream, flavor, null); printJob.print(myDoc, pras); logger.sendEvent( " successfully printed ............ ", EventType.INFO, this); } catch (Throwable th) { logger.sendEvent(" Throwable : "+th.getLocalizedMessage(), EventType.INFO, this); ExceptionUtility .determineExceptionForServiceClient(th); } logger.sendEvent(CLASS_NAME + methodName + "END: ", EventType.INFO, this); } Any help will be greatly appreciated!

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  • How do I catch the error from my printer with PrintDocument?

    - by Scottie
    I am using the PrintDocument class to print to my Brother label printer. When I execute the Print() method, the printer starts flashing a red error light, but everything else returns successful. I can run this same code on my laser printer and everything works fine. How can I see what is causing the error on my label printer? Code: public class Test { private Font printFont; private List<string> _documentLinesToPrint = new List<string>(); public void Run() { _documentLinesToPrint.Add("Test1"); _documentLinesToPrint.Add("Test2"); printFont = new Font("Arial", 10); var pd = new PrintDocument(); pd.DefaultPageSettings.Margins = new Margins(25, 25, 25, 25); pd.DefaultPageSettings.PaperSize = new PaperSize("Label", 400, 237); var printerSettings = new System.Drawing.Printing.PrinterSettings(); printerSettings.PrinterName ="Brother QL-570 LE"; pd.PrinterSettings = printerSettings; pd.PrinterSettings.Copies = 1; pd.PrintPage += new PrintPageEventHandler(this.pd_PrintPage); pd.Print(); } // The PrintPage event is raised for each page to be printed. private void pd_PrintPage(object sender, PrintPageEventArgs ev) { float linesPerPage = 0; float yPos = 0; int count = 0; float leftMargin = ev.MarginBounds.Left; float topMargin = ev.MarginBounds.Top; string line = null; // Calculate the number of lines per page. linesPerPage = ev.MarginBounds.Height / printFont.GetHeight(ev.Graphics); // Print each line of the file. while ((count < linesPerPage) && (count < _documentLinesToPrint.Count)) { line = _documentLinesToPrint[count]; yPos = topMargin + (count * printFont.GetHeight(ev.Graphics)); ev.Graphics.DrawString(line, printFont, Brushes.Black, leftMargin, yPos, new StringFormat()); line = null; count++; } // If more lines exist, print another page. if (line != null) ev.HasMorePages = true; else ev.HasMorePages = false; } }

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  • How can I make my Perl Jabber bot an event-driven program?

    - by TheGNUGuy
    I'm trying to make a Jabber bot and I am having trouble keeping it running while waiting for messages. How do I get my script to continuously run? I have tried calling a subroutine that has a while loop that I, in theory, have set up to check for any messages and react accordingly but my script isn't behaving that way. Here is my source: http://pastebin.com/03Habbvh # set jabber bot callbacks $jabberBot-SetMessageCallBacks(chat=\&chat); $jabberBot-SetPresenceCallBacks(available=\&welcome,unavailable=\&killBot); $jabberBot-SetCallBacks(receive=\&prnt,iq=\&gotIQ); $jabberBot-PresenceSend(type="available"); $jabberBot-Process(1); sub welcome { print "Welcome!\n"; $jabberBot-MessageSend(to=$jbrBoss-GetJID(),subject="",body="Hello There!",type="chat",priority=10); &keepItGoing; } sub prnt { print $_[1]."\n"; } #$jabberBot-MessageSend(to=$jbrBoss-GetJID(),subject="",body="Hello There! Global...",type="chat",priority=10); #$jabberBot-Process(5); #&keepItGoing; sub chat { my ($sessionID,$msg) = @_; $dump-pl2xml($msg); if($msg-GetType() ne 'get' && $msg-GetType() ne 'set' && $msg-GetType() ne '') { my $jbrCmd = &trimSpaces($msg-GetBody()); my $dbQry = $dbh-prepare("SELECT command,acknowledgement FROM commands WHERE message = '".lc($jbrCmd)."'"); $dbQry-execute(); if($dbQry-rows() 0 && $jbrCmd !~ /^insert/si) { my $ref = $dbQry-fetchrow_hashref(); $dbQry-finish(); $jabberBot-MessageSend(to=$msg-GetFrom(),subject="",body=$ref-{'acknowledgement'},type="chat",priority=10); eval $ref-{'command'}; &keepItGoing; } else { $jabberBot-MessageSend(to=$msg-GetFrom(),subject="",body="I didn't understand you!",type="chat",priority=10); $dbQry-finish(); &keepItGoing; } } } sub gotIQ { print "iq\n"; } sub trimSpaces { my $string = $_[0]; $string =~ s/^\s+//; #remove leading spaces $string =~ s/\s+$//; #remove trailing spaces return $string; } sub keepItGoing { print "keepItGoing!\n"; my $proc = $jabberBot-Process(1); while(defined($proc) && $proc != 1) { $proc = $jabberBot-Process(1); } } sub killBot { print "killing\n"; $jabberBot-MessageSend(to=$_[0]-GetFrom(),subject="",body="Logging Out!",type="chat",priority=10); $jabberBot-Process(1); $jabberBot-Disconnect(); exit; }

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  • how to refresh list of photos after uploadify jquery

    - by robert
    hello, I want to do a sort of photo editor, i use uploadify to upload images here are my files: http://www.mediafire.com/?nddjyzyygj5 the problem is: after upload the images i dinamicaly generate a thumb .. When I click on it it show me the large pictures in another page, i want to show the picture in a div or a paragraf! after I refresh the page is working! why? from my php script i recive only the image name (response) after UploadifyComplete i append this: jQuery("#" + jQuery(this).attr('id') + ID).html('<a href="uploads/' + response + '"><img width="60px" height="60px" src="uploads/' + response + '" alt="' + response + '" /></a>'); to this: jQuery(queue).append('<li class="uploadifyQueueItem">\ <span class="fileName">' + fileName + ' (' + byteSize + suffix + ')</span>\ <div class="uploadifyProgress">\ <div id="' + jQuery(this).attr('id') + ID + 'ProgressBar" class="uploadifyProgressBar"><!--Progress Bar--></div>\ </div>\ </li>'); } and the result will be: <div class="uploadifyQueue"> <ul id="mainftpQueue"> <li class="uploadifyQueueItem"> <a href="uploads/Winter.jpg"><img height="60px" width="60px" alt="Winter.jpg" src="uploads/Winter.jpg"></a> </li> </ul> </div> i putt all the images in 1 php array after all images uploaded i want to refresh the div where this code is: <div class="uploadifyQueue"> <?php if ($_SESSION['files']){ print '<ul id="mainftpQueue">'."\n"; foreach($_SESSION['files'] as $image ): print '<li class="uploadifyQueueItem">'."\n"; print '<a href="uploads/'.$image.'"><img height="60px" width="60px" alt="'.$image.'" src="uploads/'.$image.'"></a>'."\n"; print "</li>\n"; endforeach; print "</ul>\n"; } ?> </div> i try with: $('#mainftpQueue').load(location.href+" #mainftpQueue>*",""); $('#mainftpQueue').load("/ #mainftpQueue li"); buth no succes sorry 4 my bad english.. if any 1 can edit this thanks

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  • Strange problems with PHP SOAP (private variable not persist + variables passed from client not work

    - by Tamas Gal
    I have a very strange problems in a PHP Soap implementation. I have a private variable in the Server class which contains the DB name for further reference. The private variable name is "fromdb". I have a public function on the soap server where I can set this variable. $client-setFromdb. When I call it form my client works perfectly and the fromdb private variable can be set. But a second soap client call this private variable loses its value... Here is my soap server setup: ini_set('soap.wsdl_cache_enabled', 0); ini_set('session.auto_start', 0); ini_set('always_populate_raw_post_data', 1); global $config_dir; session_start(); /*if(!$HTTP_RAW_POST_DATA){ $HTTP_RAW_POST_DATA = file_get_contents('php://input'); }*/ $server = new SoapServer("{$config_dir['template']}import.wsdl"); $server-setClass('import'); $server-setPersistence(SOAP_PERSISTENCE_SESSION); $server-handle(); Problem is that I passed this to the server: $client = new SoapClient('http://import.ingatlan.net/wsdl', array('trace' = 1)); $xml=''; $xml.=''; $xml.=''; $xml.=''; $xml.='Valaki'; $xml.=''; $xml.=''; $xml.=''; $xml.=''; $tarray = array("type" = 1, "xml" = $xml); try{ $s = $client-sendXml( $tarray ); print "$s"; } catch( SOAPFault $exception){ print "--- SOAP exception :{$exception}---"; print "LAST REQUEST :"; var_dump($client-_getLastRequest()); print "---"; print "LAST RESPONSE :".$client-_getLastResponse(); } So passed an Array of informations to the server. Then I got this exception: LAST REQUEST : <?xml version="1.0" encoding="UTF-8"?> <SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"><SOAP-ENV:Body><type>Array</type><xml/></SOAP-ENV:Body></SOAP-ENV:Envelope> Can you see the Array word between the type tag? Seems that the client only passed a reference or something like this. So I totaly missed :(

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  • How to display specific data from a file

    - by user1067332
    My program is supposed to ask the user for firstname, lastname, and phone number till the users stops. Then when to display it asks for the first name and does a search in the text file to find all info with the same first name and display lastname and phones of the matches. import java.util.*; import java.io.*; import java.util.Scanner; public class WritePhoneList { public static void main(String[] args)throws IOException { BufferedWriter output = new BufferedWriter(new FileWriter(new File( "PhoneFile.txt"), true)); String name, lname, age; int pos,choice; try { do { Scanner input = new Scanner(System.in); System.out.print("Enter First name, last name, and phone number "); name = input.nextLine(); output.write(name); output.newLine(); System.out.print("Would you like to add another? yes(1)/no(2)"); choice = input.nextInt(); }while(choice == 1); output.close(); } catch(Exception e) { System.out.println("Message: " + e); } } } Here is the display code, when i search for a name, it finds a match but displays the last name and phone number of the same name 3 times, I want it to display all of the possible matches with the first name. import java.util.*; import java.io.*; import java.util.Scanner; public class DisplaySelectedNumbers { public static void main(String[] args)throws IOException { String name; String strLine; try { FileInputStream fstream = new FileInputStream("PhoneFile.txt"); // Get the object of DataInputStream DataInputStream in = new DataInputStream(fstream); BufferedReader br = new BufferedReader(new InputStreamReader(in)); Scanner input = new Scanner(System.in); System.out.print("Enter a first name"); name = input.nextLine(); strLine= br.readLine(); String[] line = strLine.split(" "); String part1 = line[0]; String part2 = line[1]; String part3 = line[2]; //Read File Line By Line while ((strLine= br.readLine()) != null) { if(name.equals(part1)) { // Print the content on the console System.out.print("\n" + part2 + " " + part3); } } }catch (Exception e) {//Catch exception if any System.out.println("Error: " + e.getMessage()); } } }

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  • Writing to a xml file in java

    - by user243680
    import java.io.*; import javax.xml.parsers.*; import javax.xml.transform.*; import javax.xml.transform.dom.*; import javax.xml.transform.stream.*; import org.w3c.dom.*; public class CreatXMLFile { public static void main(String[] args) throws Exception { BufferedReader bf = new BufferedReader(new InputStreamReader(System.in)); // System.out.print("Enter number to add elements in your XML file: "); // String str = bf.readLine(); int no=2; // System.out.print("Enter root: "); String root = "SMS"; DocumentBuilderFactory documentBuilderFactory =DocumentBuilderFactory.newInstance(); DocumentBuilder documentBuilder =documentBuilderFactory.newDocumentBuilder(); Document document = documentBuilder.newDocument(); Element rootElement = document.createElement(root); document.appendChild(rootElement); // for (int i = 1; i <= no; i++) // System.out.print("Enter the element: "); // String element = bf.readLine(); String element ="Number"; System.out.print("Enter the Number: "); String data = bf.readLine(); Element em = document.createElement(element); em.appendChild(document.createTextNode(data)); rootElement.appendChild(em); String element1 ="message"; System.out.print("Enter the SMS: "); String data1 = bf.readLine(); Element em1 = document.createElement(element1); em1.appendChild(document.createTextNode(data1)); rootElement.appendChild(em1); TransformerFactory transformerFactory = TransformerFactory.newInstance(); Transformer transformer = transformerFactory.newTransformer(); DOMSource source = new DOMSource(document); StreamResult result = new StreamResult(System.out); transformer.transform(source, result); } } i am working on the above code and it gives the following output run: Enter the Number: 768678 Enter the SMS: ytu <?xml version="1.0" encoding="UTF-8" standalone="no"?><SMS><Number>768678</Number><message>ytu</message></SMS>BUILD SUCCESSFUL (total time: 8 seconds) Now i want to write the output generated(<?xml version="1.0" encoding="UTF-8" standalone="no"?><SMS><Number>768678</Number><message>ytu</message></SMS>) to a XML file on the hard disk.How do i do it?

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  • Converting Audio To Video Output and Attaching Text?

    - by ZeeMan
    I am currently working on a project and before i get started i thought it'd be nice to check with stackOverflow community, and see maybe they can help me with this. The Idea: I have about a thousand MP3 files that i need to convert into Video files to be upload on Youtube for my work. Here is where it gets tricky i need to also attach the Text associated with the Audio to the Video as an Image. I was thinking .ppt. The Problem: I can do this one audio file at a time but it would take me a zillion years. lol!! The Question: Can I Create Some Kind Of Program Using Let's Say XML or JavaScript Or XHTML or some other programming language to do a MASS content creation and all i have to do is feed it the Information?? possibly a script?? or is it possible to create an example .ppt file and then hack it so that i can have it reproduce itself with different information?? The Note: Thanks U In Advance For Helping Out!!! Regards, ZeeMan!!!

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  • Help with method logic in Java, hw

    - by Crystal
    I have a Loan class that in its printPayment method, it prints the amortization table of a loan for a hw assignment. We are also to implement a print first payment method, and a print last payment method. Since my calculation is done in the printPayment method, I didn't know how I could get the value in the first or last iteration of the loop and print that amount out. One way I can think of is to write a new method that might return that value, but I wasn't sure if there was a better way. Here is my code: public abstract class Loan { public void setClient(Person client) { this.client = client; } public Person getClient() { return client; } public void setLoanId() { loanId = nextId; nextId++; } public int getLoanId() { return loanId; } public void setInterestRate(double interestRate) { this.interestRate = interestRate; } public double getInterestRate() { return interestRate; } public void setLoanLength(int loanLength) { this.loanLength = loanLength; } public int getLoanLength() { return loanLength; } public void setLoanAmount(double loanAmount) { this.loanAmount = loanAmount; } public double getLoanAmount() { return loanAmount; } public void printPayments() { double monthlyInterest; double monthlyPrincipalPaid; double newPrincipal; int paymentNumber = 1; double monthlyInterestRate = interestRate / 1200; double monthlyPayment = loanAmount * (monthlyInterestRate) / (1 - Math.pow((1 + monthlyInterestRate),( -1 * loanLength))); System.out.println("Payment Number | Interest | Principal | Loan Balance"); // amortization table while (loanAmount >= 0) { monthlyInterest = loanAmount * monthlyInterestRate; monthlyPrincipalPaid = monthlyPayment - monthlyInterest; newPrincipal = loanAmount - monthlyPrincipalPaid; loanAmount = newPrincipal; System.out.printf("%d, %.2f, %.2f, %.2f", paymentNumber++, monthlyInterest, monthlyPrincipalPaid, loanAmount); } } /* //method to print first payment public double getFirstPayment() { } method to print last payment public double getLastPayment() { }*/ private Person client; private int loanId; private double interestRate; private int loanLength; private double loanAmount; private static int nextId = 1; } Thanks!

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  • Please , Explain these java code ..?

    - by soma
    I want understand these code before java lab exam especially methode import javax.swing.; import java.util.; import java.text.*; public class EnglishCalendar { public static String[] months = { "January" , "February" , "March", "April" , "May" , "June", "July" , "August" , "September", "October" , "November" , "December" }; public static int days[] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }; private void showMonth(int m, int y) { int lead_spaces = 0; if (m < 0 || m > 11) { System.out.println("It should be 1 to 12"); } else { System.out.println(); System.out.println(" " + months[m] + " " + y); System.out.println(); GregorianCalendar cal = new GregorianCalendar(y, m, 0); System.out.println("Su Mo Tu We Th Fr Sa "); lead_spaces = cal.get(Calendar.DAY_OF_WEEK); int day_of_month = days[m]; if (cal.isLeapYear(cal.get(Calendar.YEAR)) && m == 1){ day_of_month++;} for (int i = 0; i < lead_spaces; i++) { System.out.print(" "); } for (int i = 1; i <= day_of_month; i++) { if (i < 10) System.out.print(" "); System.out.print(i); if ((lead_spaces + i) % 7 == 0) { System.out.println(); } else { System.out.print(" "); } } System.out.println(); } } private static void doSimpleDateFormat() { Calendar now = Calendar.getInstance(); SimpleDateFormat formatter = new SimpleDateFormat("E yyyy.MM.dd 'at' hh:mm:ss a zzz"); System.out.print(" \n It is now : " + formatter.format(now.getTime())); System.out.println(); } public static void main(String[] args) { String mo = JOptionPane.showInputDialog("Month"); String ye = JOptionPane.showInputDialog("Year"); int mon = new Integer(mo).intValue(); int yea = new Integer(ye).intValue(); EnglishCalendar k = new EnglishCalendar(); k.showMonth(mon - 1 , yea); doSimpleDateFormat(); } }

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  • Displaying individual elements of an object in an Arraylist through a for loop?

    - by user1180888
    I'm trying to Display individual elements of an Object I have created. It is a simple Java program that allows users to add and keep track of Player Details. I'm just stumped when it comes to displaying the details after they have been added already. here is what my code looks like I can create the object and input it into the arraylist no problem using the case 2, but when I try to print it out I want to do something like System.out.println("Player Name" + myPlayersArrayList.PlayerName + "Player Position" + myPlayerArrayList.PlayerPosition + "Player Age" + "Player Age"); I know that is not correct, but I dont really know what to do, if anyone can be of any help it would be greatly appreciated. Thanks System.out.println("Welcome to the Football Player database"); System.out.print(System.getProperty("line.separator")); UserInput myFirstUserInput = new UserInput(); int selection; ArrayList<Player> myPlayersArrayList = new ArrayList<Player>(); while (true) { System.out.println("1. View The Players"); System.out.println("2. Add A Player"); System.out.println("3. Edit A Player"); System.out.println("4. Delete A Player"); System.out.println("5. Exit ") ; System.out.print(System.getProperty("line.separator")); selection = myFirstUserInput.getInt("Please select an option"); System.out.print(System.getProperty("line.separator")); switch(selection){ case 1: if (myPlayersArrayList.isEmpty()) { System.out.println("No Players Have Been Entered Yet"); System.out.print(System.getProperty("line.separator")); break;} else {for(int i = 0; i < myPlayersArrayList.size(); i++){ System.out.println(myPlayersArrayList); } break; case 2: { String playerName,playerPos; int playerAge; playerName = (myFirstUserInput.getString("Enter Player name")); playerPos = (myFirstUserInput.getString("Enter Player Position")); playerAge = (myFirstUserInput.getInt("Enter Player Age")); myPlayersArrayList.add(new Player(playerName, playerPos, playerAge)); ; break; }

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  • how can I create macro definitions for the lines commented in the code.

    - by yaprak
    #include <stdio.h> //Here use a macro definition that assigns a value to SIZE (for example 5) int main() { int i; int array[SIZE]; int sum=0; for(i=0; i<SIZE; i++) { //Here use a macro definition named as CALCSUM to make the //following addition operation for the array printf("Enter a[%d] = ",i); scanf("%d", &array[i]); sum+=array[i]; //Here use a macro definition named as VERBOSE to print //what program does to the screen printf("The user entered %d\n", array[i]); // // //If the macro definition CALCSUM is not used, the program //should assign 0 to the i-th element of the array array[i]=0; //Here, again use VERBOSE to print what program does to the screen printf("a[%d] is assigned to zero\n", i); // // } //If CALCSUM is defined, print the summation of the array elements to the screen printf("Summation of the array is %d\n",sum); // //If CALCSUM is not defined, but VERBOSE mode is used, print the following printf("All the elements in the array are assigned to zero\n"); // printf("Program terminated\n"); return 0; } When CALCSUM is defined, the program will sum up the values of each element in the given array. If CALCSUM is not defined, each array element will be assigned to zero. Besides, when VERBOSE mode is defined, the program will make print statements pointed out active. [root@linux55]# gcc code.c [root@linux55]# ./a.out Program terminated [root@linux55]# gcc code.c -D CALCSUM [root@linux55]# ./a.out Enter a[0] = 3 Enter a[1] = 0 Enter a[2] = 2 Enter a[3] = 5 Enter a[4] = 9 Summation of the array is 19 Program terminated [root@linux55]# gcc code.c -D CALCSUM -D VERBOSE [root@linux55]# ./a.out Enter a[0] = 2 The user entered 2 Enter a[1] = 10 The user entered 10 Enter a[2] = 3 The user entered 3 Enter a[3] = 8 The user entered 8 Enter a[4] = 1 The user entered 1 Summation of the array is 24 Program terminated [root@linux55]# gcc code.c -D VERBOSE [root@linux55]# ./a.out a[0] is assigned to 0 a[1] is assigned to 0 a[2] is assigned to 0 a[3] is assigned to 0 a[4] is assigned to 0 All the elements in the array is assigned to zero Program terminated

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