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  • subscripts and superscripts in SVG

    - by peter.murray.rust
    I am trying to display sub- and superscripts with SVG using the following code from this site <svg xmlns="http://www.w3.org/2000/svg" version="1.1"> <g> <text x = "10" y = "25" font-size = "20"> <tspan> e = mc <tspan baseline-shift = "super">2</tspan> </tspan> <tspan x = "10" y = "60"> T <tspan baseline-shift = "sub">i+2</tspan> =T <tspan baseline-shift = "sub">i</tspan> + T <tspan baseline-shift = "sub">i+1</tspan> </tspan> </text> </g> but the sub/superscripts do not display in IE or Firefox. Is this unimplemented or is there another problem? [Are you able to see the subscripts displayed properly?]

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  • How to get an embedded function to run multiple times

    - by Guy Montag
    The question I have is how to I get multiple instances of a function to run. Here is my function below - A simple fade function. Problem I'm having is that when it is called a second time it abandons the first call. So if a user clicks on a button it will display a message which fades. If the user clicks on another button the previous fading message just stops at the current opacity level. Try it here - www.arcmarks.com ( please do not repost this domain name) click on SignUp and than quickly click on SignIn with out typing anything. You will see the previous message simply halts. ? What is the stopping mechanism? Where did the previous function go? The function function newEffects(element, direction, max_time ) { newEffects.arrayHold = []; newEffects.arrayHold[element.id] = 0; function next() { newEffects.arrayHold[element.id] += 10; if ( direction === 'up' ) { element.style.opacity = newEffects.arrayHold[element.id] / max_time; } else if ( direction === 'down' ) { element.style.opacity = ( max_time - newEffects.arrayHold[element.id] ) / max_time; } if ( newEffects.arrayHold[element.id] <= max_time ) { setTimeout( next, 10 ); } } next(); return true; }; The Call newEffects(this.element, 'down', 4000 );

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  • Why I can't get all UDP packets?

    - by Jack
    My program use UdpClient to try to receive 27 responses from 27 hosts. The size of the response is 10KB. My broadband incoming bandwidth is 150KB/s. The 27 responses are sent from the hosts almost at the same time and for every 10 secs. However, I can only receive 8 - 17 responses each time. The number of responses that I can receive is quite dynamic but within the range. Can anyone tell me why? why can't I receive all? I understand UDP is not reliable. but I tried receiving 5 - 10 responses at the same time, it worked. I guess the network links are not so bad. The code is very simple. ON the 27 hosts, I just use UdpClient to send 10KB to my machine. On my machine, I have one UdpClient receive datagrams. Each time I get a data, I create a thread to handle it (basically handling it means just print out "I received 10KB", but it runs in a thread). listener = new UDPListener(Port); listener.Start(); while (true) { try { UDPContext context = listener.Accept(); ThreadPool.QueueUserWorkItem(new WaitCallback(HandleMessage), context); } catch (Exception) { } } If I reduce the size of the response down to 3KB, the case gets much better that roughly 25 responses can be received. Any more idea? UDP buffer problems???

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  • Code Golf: Numeric Ranges

    - by SLaks
    Mods: Can you please make this Community Wiki? Challenge Compactify a long list of numbers by replacing consecutive runs with ranges. Example Input 1, 2, 3, 4, 7, 8, 10, 12, 13, 14, 15 Output: 1 - 4, 7, 8, 10, 12 - 15 Note that ranges of two numbers should be left as is. (7, 8; not 7 - 8) Rules You can accept a list of integers (or equivalent datatype) as a method parameter, from the commandline, or from standard in. (pick whichever option results in shorter code) You can output a list of strings by printing them, or by returning either a single string or set of strings. Reference Implementation (C#) IEnumerable<string> Sample(IList<int> input) { for (int i = 0; i < input.Count; ) { var start = input[i]; int size = 1; while (++i < input.Count && input[i] == start + size) size++; if (size == 1) yield return start.ToString(); else if (size == 2) { yield return start.ToString(); yield return (start + 1).ToString(); } else if (size > 2) yield return start + " - " + (start + size - 1); } }

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  • How do i selext text nodes using XSL

    - by user323719
    How do i select all the text nodes within a specific element node using XSL? Input xml: <node1 id="1"> <node2 id="2"> <node3 id="3" /> <node4 id="4"> <node5 id="5">Text node1</node5> <node6 id="6">Text node2</node6> </node4> </node2> <node7 id="7">Text node3 <node8 id="8">Text node4</node8> <node9 id="9">Text node5</node9> </node7> <node10 id="10">Text node6</node10> <node11 id="11">Text node3 <node12 id="12">Text node4</node12> <node13 id="13">Text node5</node13> </node11> </node1> Input Param: List of ids of the element nodes whose txt nodes are to be retrieved. <nodes><node>4</node><node>7</node><node>10</node></nodes> Expected Output: Text node1 Text node2 Text node3 Text node4 Text node5 Text node6 How can this be achieved using XSL? Please share your ideas.

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  • Loop to check all 14 days in the pay period

    - by Rachel Ann Arndt
    Name: Calc_Anniversary Input: Pay_Date, Hire_Date, Termination_Date Output: "Y" if is the anniversary of the employee's Hire_Date, "N" if it is not, and "T" if he has been terminated before his anniversary. Description: Create local variables to hold the month and day of the employee's Date_of_Hire, Termination_Date, and of the processing date using the TO_CHAR function. First check to see if he was terminated before his anniversary. The anniversary could be on any day during the pay period, so there will be a loop to check all 14 days in the pay period to see if one was his anniversary. CREATE OR replace FUNCTION Calc_anniversary( incoming_anniversary_date IN VARCHAR2) RETURN BOOLEAN IS hiredate VARCHAR2(20); terminationdate VARCHAR(20); employeeid VARCHAR2(38); paydate NUMBER := 0; BEGIN SELECT Count(arndt_raw_time_sheet_data.pay_date) INTO paydate FROM arndt_raw_time_sheet_data WHERE paydate = incoming_anniversary_date; WHILE paydate <= 14 LOOP SELECT To_char(employee_id, '999'), To_char(hire_date, 'DD-MON'), To_char(termination_date, 'DD-MON') INTO employeeid, hiredate, terminationdate FROM employees, time_sheet WHERE employees.employee_id = time_sheet.employee_id AND paydate = pay_date; IF terminationdate > hiredate THEN RETURN 'T'; ELSE IF To_char(SYSDATE, 'DD-MON') = To_char(hiredate, 'DD-MON')THEN RETURN 'Y'; ELSE RETURN 'N'; END IF; END IF; paydate := paydate + 1; END LOOP; END; Tables I am using CREATE TABLE Employees ( EMPLOYEE_ID INTEGER, FIRST_NAME VARCHAR2(15), LAST_NAME VARCHAR2(25), ADDRESS_LINE_ONE VARCHAR2(35), ADDRESS_LINE_TWO VARCHAR2(35), CITY VARCHAR2(28), STATE CHAR(2), ZIP_CODE CHAR(10), COUNTY VARCHAR2(10), EMAIL VARCHAR2(16), PHONE_NUMBER VARCHAR2(12), SOCIAL_SECURITY_NUMBER VARCHAR2(11), HIRE_DATE DATE, TERMINATION_DATE DATE, DATE_OF_BIRTH DATE, SPOUSE_ID INTEGER, MARITAL_STATUS CHAR(1), ALLOWANCES INTEGER, PERSONAL_TIME_OFF FLOAT, CONSTRAINT pk_employee_id PRIMARY KEY (EMPLOYEE_ID), CONSTRAINT fk_spouse_id FOREIGN KEY (SPOUSE_ID) REFERENCES EMPLOYEES (EMPLOYEE_ID)) / CREATE TABLE Arndt_Raw_Time_Sheet_data ( EMPLOYEE_ID INTEGER, PAY_DATE DATE, HOURS_WORKED FLOAT, SALES_AMOUNT FLOAT, CONSTRAINT pk_employee_id_pay_date_time PRIMARY KEY (EMPLOYEE_ID, PAY_DATE), CONSTRAINT fk_employee_id_time FOREIGN KEY (EMPLOYEE_ID) REFERENCES EMPLOYEES (EMployee_ID)); error FUNCTION Calc_Anniversary compiled Warning: execution completed with warning

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  • Thread mutex behaviour

    - by Alberteddu
    Hi there, I'm learning C. I'm writing an application with multiple threads; I know that when a variable is shared between two or more threads, it is better to lock/unlock using a mutex to avoid deadlock and inconsistency of variables. This is very clear when I want to change or view one variable. int i = 0; /** Global */ static pthread_mutex_t mutex = PTHREAD_MUTEX_INITIALIZER; /** Thread 1. */ pthread_mutex_lock(&mutex); i++; pthread_mutex_unlock(&mutex); /** Thread 2. */ pthread_mutex_lock(&mutex); i++; pthread_mutex_unlock(&mutex); This is correct, I think. The variable i, at the end of the executions, contains the integer 2. Anyway, there are some situations in which I don't know exactly where to put the two function calls. For example, suppose you have a function obtain(), which returns a global variable. I need to call that function from within the two threads. I have also two other threads that call the function set(), defined with a few arguments; this function will set the same global variable. The two functions are necessary when you need to do something before getting/setting the var. /** (0) */ /** Thread 1, or 2, or 3... */ if(obtain() == something) { if(obtain() == somethingElse) { // Do this, sometimes obtain() and sometimes set(random number) (1) } else { // Do that, just obtain(). (2) } } else { // Do this and do that (3) // If # of thread * 3 > 10, then set(3*10) For example. (4) } /** (5) */ Where I have to lock, and where I have to unlock? The situation can be, I think, even more complex. I will appreciate an exhaustive answer. Thank you in advance. —Alberto

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  • "Function object is unsubscriptable" in basic integer to string mapping function

    - by IanWhalen
    I'm trying to write a function to return the word string of any number less than 1000. Everytime I run my code at the interactive prompt it appears to work without issue but when I try to import wordify and run it with a test number higher than 20 it fails as "TypeError: 'function' object is unsubscriptable". Based on the error message, it seems the issue is when it tries to index numString (for example trying to extract the number 4 out of the test case of n = 24) and the compiler thinks numString is a function instead of a string. since the first line of the function is me defining numString as a string of the variable n, I'm not really sure why that is. Any help in getting around this error, or even just help in explaining why I'm seeing it, would be awesome. def wordify(n): # Convert n to a string to parse out ones, tens and hundreds later. numString = str(n) # N less than 20 is hard-coded. if n < 21: return numToWordMap(n) # N between 21 and 99 parses ones and tens then concatenates. elif n < 100: onesNum = numString[-1] ones = numToWordMap(int(onesNum)) tensNum = numString[-2] tens = numToWordMap(int(tensNum)*10) return tens+ones else: # TODO pass def numToWordMap(num): mapping = { 0:"", 1:"one", 2:"two", 3:"three", 4:"four", 5:"five", 6:"six", 7:"seven", 8:"eight", 9:"nine", 10:"ten", 11:"eleven", 12:"twelve", 13:"thirteen", 14:"fourteen", 15:"fifteen", 16:"sixteen", 17:"seventeen", 18:"eighteen", 19:"nineteen", 20:"twenty", 30:"thirty", 40:"fourty", 50:"fifty", 60:"sixty", 70:"seventy", 80:"eighty", 90:"ninety", 100:"onehundred", 200:"twohundred", 300:"threehundred", 400:"fourhundred", 500:"fivehundred", 600:"sixhundred", 700:"sevenhundred", 800:"eighthundred", 900:"ninehundred", } return mapping[num] if __name__ == '__main__': pass

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  • Why is it that an int in C++ that isnt initialized (then used) doesn't return an error?

    - by omizzle
    I am new to C++ (just starting). I come from a Java background and I was trying out the following piece of code that would sum the numbers between 1 and 10 (inclusive) and then print out the sum: /* * File: main.cpp * Author: omarestrella * * Created on June 7, 2010, 8:02 PM */ #include <cstdlib> #include <iostream> using namespace std; int main() { int sum; for(int x = 1; x <= 10; x++) { sum += x; } cout << "The sum is: " << sum << endl; return 0; } When I ran it it kept printing 32822 for the sum. I knew the answer was supposed to be 55 and realized that its print the max value for a short (32767) plus 55. Changing int sum; to int sum = 0; would work (as it should, since the variable needs to be initialized!). Why does this behavior happen, though? Why doesnt the compiler warn you about something like this? I know Java screams at you when something isnt initialized. Thank you.

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  • pyPDF - Retrieve page numbers from document

    - by SquidneyPoitier
    At the moment I'm looking into doing some PDF merging with pyPdf, but sometimes the inputs are not in the right order, so I'm looking into scraping each page for its page number to determine the order it should go in (e.g. if someone split up a book into 20 10-page PDFs and I want to put them back together). I have two questions - 1.) I know that sometimes the page number is stored in the document data somewhere, as I've seen PDFs that render on Adobe as something like [1243] (10 of 150), but I've read documents of this sort into pyPDF and I can't find any information indicating the page number - where is this stored? 2.) If avenue #1 isn't available, I think I could iterate through the objects on a given page to try to find a page number - likely it would be its own object that has a single number in it. However, I can't seem to find any clear way to determine the contents of objects. If I run: pdf.getPage(0).getContents() This usually either returns: {'/Filter': '/FlateDecode'} or it returns a list of IndirectObject(num, num) objects. I don't really know what to do with either of these and there's no real documentation on it as far as I can tell. Is anyone familiar with this kind of thing that could point me in the right direction?

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  • How to make cycle over cycles in Java?

    - by Roman
    I would like to make a cycle over the following elements: [1,2,11,12,21,22,111,112,121,122,....,222222] or for example [1,2,3,11,12,13,21,22,23,31,32,33,111,112,113,... 333333333] How can I make it in Java? In my particular case I use 4 digits (1,2,3,4) and the length of the last number can be from 1 to 10. I managed to do it in Python and PHP. In the first case I used list over lists. I started from [[1],[2],] then for every element of the list I added 1 and 2, so I got [[1,1],[1,2],[2,1],[2,2]] and so on: nchips = sum(chips) traj = [[]] last = [[]] while len(last[0]) < nchips: newlast = [] for tr in last: for d in [1,2,3,4]: newlast.append(tr + [d]) last = newlast traj += last When I did it in PHP I used number with base 3. But it was a tricky and non elegant solution. for ($i=-1; $i<=$n; $i+=1) { if ($i>-1) { $n5 = base_convert($i,10,5); $n5_str = strval($n5); $tr = array(); $found = 0; for ($j=0; $j<strlen($n5_str); $j+=1) { $k = $n5_str[$j]; if ($k==0) { $found = 1; break; } array_push($tr,$k); } if ($found==1) continue; } else { $tr = array(); } } Can it be done easily in Java?

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  • Optimization of SQL query regarding pair comparisons

    - by InfiniteSquirrel
    Hi, I'm working on a pair comparison site where a user loads a list of films and grades from another site. My site then picks two random movies and matches them against each other, the user selects the better of the two and a new pair is loaded. This gives a complete list of movies ordered by whichever is best. The database contains three tables; fm_film_data - this contains all imported movies fm_film_data(id int(11), imdb_id varchar(10), tmdb_id varchar(10), title varchar(255), original_title varchar(255), year year(4), director text, description text, poster_url varchar(255)) fm_films - this contains all information related to a user, what movies the user has seen, what grades the user has given, as well as information about each film's wins/losses for that user. fm_films(id int(11), user_id int(11), film_id int(11), grade int(11), wins int(11), losses int(11)) fm_log - this contains records of every duel that has occurred. fm_log(id int(11), user_id int(11), winner int(11), loser int(11)) To pick a pair to show the user, I've created a mySQL query that checks the log and picks a pair at random. SELECT pair.id1, pair.id2 FROM (SELECT part1.id AS id1, part2.id AS id2 FROM fm_films AS part1, fm_films AS part2 WHERE part1.id <> part2.id AND part1.user_id = [!!USERID!!] AND part2.user_id = [!!USERID!!]) AS pair LEFT JOIN (SELECT winner AS id1, loser AS id2 FROM fm_log WHERE fm_log.user_id = [!!USERID!!] UNION SELECT loser AS id1, winner AS id2 FROM fm_log WHERE fm_log.user_id = [!!USERID!!]) AS log ON pair.id1 = log.id1 AND pair.id2 = log.id2 WHERE log.id1 IS NULL ORDER BY RAND() LIMIT 1 This query takes some time to load, about 6 seconds in our tests with two users with about 800 grades each. I'm looking for a way to optimize this but still limit all duels to appear only once. The server runs MySQL version 5.0.90-community.

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  • Problem with reading and writing to binary file in C++

    - by Reem
    I need to make a file that contains "name" which is a string -array of char- and "data" which is array of bytes -array of char in C++- but the first problem I faced is how to separate the "name" from the "data"? newline character could work in this case (assuming that I don't have "\n" in the name) but I could have special characters in the "data" part so there's no way to know when it ends so I'm putting an int value in the file before the data which has the size of the "data"! I tried to do this with code as follow: if((fp = fopen("file.bin","wb")) == NULL) { return false; } char buffer[] = "first data\n"; fwrite( buffer ,1,sizeof(buffer),fp ); int number[1]; number[0]=10; fwrite( number ,1,1, fp ); char data[] = "1234567890"; fwrite( data , 1, number[0], fp ); fclose(fp); but I didn't know if the "int" part was right, so I tried many other codes including this one: char buffer[] = "first data\n"; fwrite( buffer ,1,sizeof(buffer),fp ); int size=10; fwrite( &size ,sizeof size,1, fp ); char data[] = "1234567890"; fwrite( data , 1, number[0], fp ); I see 4 "NULL" characters in the file when I open it instead of seeing an integer. Is that normal? The other problem I'm facing is reading that again from the file! The code I tried to read didn't work at all :( I tried it with "fread" but I'm not sure if I should use "fseek" with it or it just read the other character after it. Forgive me but I'm a beginner :(

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  • Aquireing the entire string sent to the shell for execution

    - by user294567
    I have a bash script that looks like this (called job_result.sh): #!/bin/bash $* && zenity --title "Job result" --info --text "SUCSESS: Job '$*'completed" && while pidof zenity > /dev/null; do /usr/bin/wmctrl -a "Job Result" && sleep 2; done When i execute it with: $ ./job_result.sh echo "arf" && sleep 10 I want the following to happen: $ echo "arf" && sleep 10 && zenity --title "Job result" --info --text "SUCSESS: Job '$*'completed" && while pidof zenity > /dev/null; do /usr/bin/wmctrl -a "Job Result" && sleep 2; done But it seems the following is happening: $ echo "arf" && zenity --title "Job result" --info --text "SUCSESS: Job '$*'completed" && while pidof zenity > /dev/null; do /usr/bin/wmctrl -a "Job Result" && sleep 2; done Question: How do i get hold of the entire shell argument? And not just the part until &&?

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  • Tricky SQL query - need to get time frames

    - by Andrew
    I am stumbled upon a problem, when I need a query which will produce a list of speeding time frames. Here is the data example [idgps_unit_location] [dt] [idgps_unit] [lat] [long] [speed_kmh] 26 10/18/2012 18:53 2 47 56 30 27 10/18/2012 18:53 2 49 58 31 28 10/18/2012 18:53 2 28 37 15 29 10/18/2012 18:54 2 56 65 33 30 10/18/2012 18:54 2 152 161 73 31 10/18/2012 18:55 2 134 143 64 32 10/18/2012 18:56 2 22 31 12 36 10/18/2012 18:59 2 98 107 47 37 10/18/2012 18:59 2 122 131 58 38 10/18/2012 18:59 2 91 100 44 39 10/18/2012 19:00 2 190 199 98 40 10/18/2012 19:01 2 194 203 101 41 10/18/2012 19:02 2 182 191 91 42 10/18/2012 19:03 2 162 171 78 43 10/18/2012 19:03 2 174 183 83 44 10/18/2012 19:04 2 170 179 81 45 10/18/2012 19:05 2 189 198 97 46 10/18/2012 19:06 2 20 29 10 47 10/18/2012 19:07 2 158 167 76 48 10/18/2012 19:08 2 135 144 64 49 10/18/2012 19:08 2 166 175 79 50 10/18/2012 19:09 2 9 18 5 51 10/18/2012 19:09 2 101 110 48 52 10/18/2012 19:09 2 10 19 7 53 10/18/2012 19:10 2 32 41 20 54 10/18/2012 19:10 1 54 63 85 55 10/19/2012 19:11 2 55 64 50 I need a query that would convert this table into the following report that shows frames of time when speed was 80: [idgps_unit] [dt_start] [lat_start] [long_start] [speed_start] [dt_end] [lat_end] [long_end] [speed_end] [speed_average] 2 10/18/2012 19:00 190 199 98 10/18/2012 19:02 182 191 91 96.66666667 2 10/18/2012 19:03 174 183 83 10/18/2012 19:05 189 198 97 87 1 10/18/2012 19:10 54 63 85 10/18/2012 19:10 54 63 85 85 Now, what have I tried? I tried putting this into separate tables, queries and do some joins... Nothing works and I am very frustrated... I am not even sure if this could be done via the query. Asking for the expert help!

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  • Update a portion UIView

    - by Brett
    Hi; I'm using -setNeedsDisplayinRect to update only a part of my UIView. However, all of my drawing done previously to calling this method is erased. Here is my code in the UIView subclass: -(void)drawRect:(CGRect)rect{ CGContextRef context = UIGraphicsGetCurrentContext(); CGContextSetRGBFillColor(context, r, g, b, 1); CGContextSetRGBStrokeColor(context, r, g, b, 1); CGRect arect = CGRectMake(x,y,1,1); CGContextFillRect(context, arect); NSLog(@"drawing"); } and in the view controller: -(void)drawView{ drawingView = [[DrawingView alloc]init]; x=10; y=10; r=0; g=0; b=0; [drawingView setNeedsDisplayInRect:CGRectMake(x, y, 1, 1)]; x=20; y=20; r=0; g=0; b=0; [drawingView setNeedsDisplayInRect:CGRectMake(x, y, 1, 1)]; } I end up with a screen where there is only one pixel at 20,20. Any help with this is so much appreciated. I am a beginner with XCode and am trying to complete a class project asap.

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  • How do I redirect standard output to a file in Perl? [closed]

    - by rockyurock
    I want to send standard output to the file "my_output.txt" but failed. Here's the output: inside value loop ------------------------------------------------------------ Server listening on UDP port 5001 Receiving 1470 byte datagrams UDP buffer size: 108 KByte (default) ------------------------------------------------------------ [ 3] local 192.168.16.2 port 5001 connected with 192.168.16.1 port 3189 [ ID] Interval Transfer Bandwidth Jitter Lost/Total Datagrams [ 3] 0.0- 5.0 sec 2.14 MBytes 3.61 Mbits/sec 0.369 ms 0/ 1528 (0%) inside value loop3 clue1 clue2 inside value loop4 one iperf completed *************************************** When I enable the local *STDOUT; in below code then I could see the above output on command prompt display (ofcourse server is sending some data): my $file = 'my_output.txt'; use Win32::Process; print"inside value loop\n"; # redirect stdout to a file #local *STDOUT; open STDOUT, '>', $file or die "can't redirect STDOUT to <$file> $!"; Win32::Process::Create(my $ProcessObj, "D:\\IOT_AUTOMATION_UTILITY\\_SATURDAY_09-04-10\\adb_cmd.bat", "adb shell /data/app/iperf -u -s -p 5001", 0, NORMAL_PRIORITY_CLASS, ".") || die ErrorReport(); #$alarm_time = $IPERF_RUN_TIME+10; #20sec #$ProcessObj->Wait(40); #print"inside value loop2\n"; #sleep $alarm_time; sleep 40; $ProcessObj->Kill(0); sub ErrorReport{ print Win32::FormatMessage( Win32::GetLastError() ); }

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  • Goldbach theory in C

    - by nofe
    I want to write some code which takes any positive, even number (greater than 2) and gives me the smallest pair of primes that sum up to this number. I need this program to handle any integer up to 9 digits long. My aim is to make something that looks like this: Please enter a positive even integer ( greater than 2 ) : 10 The first primes adding : 3+7=10. Please enter a positive even integer ( greater than 2 ) : 160 The first primes adding : 3+157=160. Please enter a positive even integer ( greater than 2 ) : 18456 The first primes adding : 5+18451=18456. I don't want to use any library besides stdio.h. I don't want to use arrays, strings, or anything besides for the most basic toolbox: scanf, printf, for, while, do-while, if, else if, break, continue, and the basic operators (<,, ==, =+, !=, %, *, /, etc...). Please no other functions especially is_prime. I know how to limit the input to my needs so that it loops until given a valid entry. So now I'm trying to figure out the algorithm. I thought of starting a while loop like something like this: #include <stdio.h> long first, second, sum, goldbach, min; long a,b,i,k; //indices int main (){ while (1){ printf("Please enter a positive integer :\n"); scanf("%ld",&goldbach); if ((goldbach>2)&&((goldbach%2)==0)) break; else printf("Wrong input, "); } while (sum!=goldbach){ for (a=3;a<goldbach;a=(a+2)) for (i=2;(goldbach-a)%i;i++) first = a; for (b=5;b<goldbach;b=(b+2)) for (k=2;(goldbach-b)%k;k++) sum = first + second; } }

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  • Determining where in the code an error came from - iPhone

    - by Robert Eisinger
    I'm used to Java programming where an error is thrown and it tells you at what line the error was thrown from which file. But with Objective-C in XCode, I can't ever tell where the error comes from. How can I figure out where the error came from? Here is an example of a crash error: 2011-01-04 10:36:31.645 TestGA[69958:207] *** Terminating app due to uncaught exception 'NSRangeException', reason: '*** -[NSMutableArray objectAtIndex:]: index 0 beyond bounds for empty array' *** Call stack at first throw: ( 0 CoreFoundation 0x01121be9 __exceptionPreprocess + 185 1 libobjc.A.dylib 0x012765c2 objc_exception_throw + 47 2 CoreFoundation 0x011176e5 -[__NSArrayM objectAtIndex:] + 261 3 TestGA 0x000548d8 -[S7GraphView drawRect:] + 5763 4 UIKit 0x003e16eb -[UIView(CALayerDelegate) drawLayer:inContext:] + 426 5 QuartzCore 0x00ec89e9 -[CALayer drawInContext:] + 143 6 QuartzCore 0x00ec85ef _ZL16backing_callbackP9CGContextPv + 85 7 QuartzCore 0x00ec7dea CABackingStoreUpdate + 2246 8 QuartzCore 0x00ec7134 -[CALayer _display] + 1085 9 QuartzCore 0x00ec6be4 CALayerDisplayIfNeeded + 231 10 QuartzCore 0x00eb938b _ZN2CA7Context18commit_transactionEPNS_11TransactionE + 325 11 QuartzCore 0x00eb90d0 _ZN2CA11Transaction6commitEv + 292 12 QuartzCore 0x00ee97d5 _ZN2CA11Transaction17observer_callbackEP19__CFRunLoopObservermPv + 99 13 CoreFoundation 0x01102fbb __CFRUNLOOP_IS_CALLING_OUT_TO_AN_OBSERVER_CALLBACK_FUNCTION__ + 27 14 CoreFoundation 0x010980e7 __CFRunLoopDoObservers + 295 15 CoreFoundation 0x01060bd7 __CFRunLoopRun + 1575 16 CoreFoundation 0x01060240 CFRunLoopRunSpecific + 208 17 CoreFoundation 0x01060161 CFRunLoopRunInMode + 97 18 GraphicsServices 0x01932268 GSEventRunModal + 217 19 GraphicsServices 0x0193232d GSEventRun + 115 20 UIKit 0x003b842e UIApplicationMain + 1160 21 TestGA 0x00001cd8 main + 102 22 TestGA 0x00001c69 start + 53 23 ??? 0x00000001 0x0 + 1 So from looking at this, where is the error coming from and from which class is it coming from?

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  • Why might this work on my server but not my schools?

    - by Doug
    I created a captcha just now, and it works PERFECTLY on my own server. On the school's server, it doesn't generate an image. Why might this be? The difference in code is one line. *Edit:*Originally, it was working, but I deleted the directory by mistake and I do not know why did it suddenly work in the first place. Source code on school server: <?php session_save_path("/ichanged/this/path/for/this/post/"); session_start(); $img=imagecreatefromjpeg("bg.jpg"); if( empty($_SESSION['captcha_numbers']) ) { $captcha_numbers = 'error'; } else { $captcha_numbers = $_SESSION['captcha_numbers']; } $image_numbers=$captcha_numbers; $red=rand(100,150); $green=rand(100,255); $blue=rand(100,255); $color=imagecolorallocate($img,255-$red,255-$green,255-$blue); $text=imagettftext($img,12,rand(-7,7),rand(10,20),rand(20,30),$color,"fonts/M04.TTF",$image_numbers); header("Content-type:image/jpeg"); header("Content-Disposition:inline ; filename=secure.jpg"); imagejpeg($img); ?> Source code on my server: <?php session_start(); $img=imagecreatefromjpeg("bg.jpg"); if( empty($_SESSION['captcha_numbers']) ) { $captcha_numbers = 'error'; } else { $captcha_numbers = $_SESSION['captcha_numbers']; } $image_numbers=$captcha_numbers; $red=rand(100,150); $green=rand(100,255); $blue=rand(100,255); $color=imagecolorallocate($img,255-$red,255-$green,255-$blue); $text=imagettftext($img,12,rand(-7,7),rand(10,20),rand(20,30),$color,"fonts/M04.TTF",$image_numbers); header("Content-type:image/jpeg"); header("Content-Disposition:inline ; filename=secure.jpg"); imagejpeg($img); ?>

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  • switch from glOrtho to gluPerspective

    - by Knitex
    I have a car draw at (0,0) and some obstacles set up but right now my main concern is switching from glPerspective to glOrtho and vice-versa. All that i get when i switch from perspective to ortho is a black screen. void myinit(){ glClearColor(0.0,0.0,0.0,0.0); glMatrixMode(GL_PROJECTION); glLoadIdentity(); gluPerspective(60,ww/wh,1,100); glMatrixMode(GL_MODELVIEW); glLoadIdentity(); gluLookAt(-5,5,3,backcarx,topcarx,0,0,0,1); } void menu(int id){ /*menu selects if you want to view it in ortho or perspective*/ if(id == 1){ glClear(GL_DEPTH_BUFFER_BIT); glViewport(0,0,ww,wh); glMatrixMode(GL_PROJECTION); glLoadIdentity(); glOrtho(-2,100,-2,100,-1,1); glMatrixMode(GL_MODELVIEW); glutPostRedisplay(); } if(id == 2){ glMatrixMode(GL_PROJECTION); glLoadIdentity(); gluPerspective(60,ww/wh,1,100); glMatrixMode(GL_MODELVIEW); glLoadIdentity(); viewx = backcarx - 10; viewy = backcary - 10; gluLookAt(viewx,viewy,viewz,backcarx,topcarx,0,0,0,1); } } i've tried using the clear depth buffer and still doesnt work.

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  • Calculate distances and sort them

    - by Emir
    Hi guys, I wrote a function that can calculate the distance between two addresses using the Google Maps API. The addresses are obtained from the database. What I want to do is calculate the distance using the function I wrote and sort the places according to the distance. Just like "Locate Store Near You" feature in online stores. I'm going to specify what I want to do with an example: So, lets say we have 10 addresses in database. And we have a variable $currentlocation. And I have a function called calcdist(), so that I can calculate the distances between 10 addresses and $currentlocation, and sort them. Here is how I do it: $query = mysql_query("SELECT name, address FROM table"); while ($write = mysql_fetch_array($query)) { $distance = array(calcdist($currentlocation, $write["address"])); sort($distance); for ($i=0; $i<1; $i++) { echo "<tr><td><strong>".$distance[$i]." kms</strong></td><td>".$write['name']."</td></tr>"; } } But this doesn't work very well. It doesn't sort the numbers. Another challenge: How can I do this in an efficient way? Imagine there are infinite numbers of addresses; how can I sort these addresses and page them?

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  • Calling a method at a specific interval rate in C++

    - by Aetius
    This is really annoying me as I have done it before, about a year ago and I cannot for the life of me remember what library it was. Basically, the problem is that I want to be able to call a method a certain number of times or for a certain period of time at a specified interval. One example would be I would like to call a method "x" starting from now, 10 times, once every 0.5 seconds. Alternatively, call method "x" starting from now, 10 times, until 5 seconds have passed. Now I thought I used a boost library for this functionality but I can't seem to find it now and feeling a bit annoyed. Unfortunately I can't look at the code again as I'm not in possession of it any more. Alternatively, I could have dreamt this all up and it could have been proprietary code. Assuming there is nothing out there that does what I would like, what is currently the best way of producing this behaviour? It would need to be high-resolution, up to a millisecond. It doesn't matter if it blocks the thread that it is executed from or not. Thanks!

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  • Unreasonable errors in merge sort

    - by Alexxx
    i have the following errors - please help me to find the error: 9 IntelliSense: expected a '}' 70 4 it points on the end of the code - but there are no open { anywhere!! so why?? 8 IntelliSense: expected a ';' 57 1 it points on the { after the void main but why to put ; after the { of the void main?? Error 7 error C1075: end of file found before the left brace '{' at 70 1 points to the beginig of the code - why??? #include <stdio.h> #include <stdlib.h> void merge(int *a,int p,int q,int r) { int i=p,j=q+1,k=0; int* temp=(int*)calloc(r-p+1, sizeof(int)); while ((i<=q)&& (j<=r)) if(a[i]<a[j]) temp[k++]=a[i++]; else temp[k++]=a[j++]; while(j<=r) // if( i>q ) temp[k++]=a[j++]; while(i<=q) // j>r temp[k++]=a[i++]; for(i=p,k=0;i<=r;i++,k++) // copy temp[] to a[] a[i]=temp[k]; free(temp); } void merge_sort(int *a,int first, int last) { int middle; if(first < last) { middle=(first+last)/2; merge_sort(a,first,middle); merge_sort(a,middle+1,last); merge(a,first,middle,last); { } void main() { int a[] = {9, 7, 2, 3, 5, 4, 1, 8, 6, 10}; int i; merge_sort(a, 0, 9); for (i = 0; i < 10; i++) printf ("%d ", a[i]);

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  • FLVs on timeline are glitching out

    - by TandemAdam
    I have a Movieclip with about five FLV movies embedded on its timeline, one after another. I am loading multiple instances (about 5-10) of this movieclip onto the stage. Once added to the stage, they each play there timelines in a loop. The problem is that when one of the instances switch over to playing a new FLV, then some of the other instances "glitch out"! See this image for what the glitch looks like: This glitch also happens when they first start playing (first load). More details of Flash: 24fps FlashPlayer 10 Actionscript 3 More details of the FLVs: Encoded with On2 VP6 24fps transparent background (alpha channel) dimensions 640x480 filesize are about 150KB each FLVs are imported using option: "Embed video in SWF and play in timeline" Has anyone seen this before? Does anyone have a reason for why this might be happening? And any possibly ways to stop it from happening. EDIT* It seems to only "glitch" when an FLV is started from a random frame (a frame that is not the first frame). I don't think it always does it, but it does it quite often.

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