Search Results

Search found 10691 results on 428 pages for 'batch insert'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 79/428 | < Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >

  • insert VBS variable within a single-quoted WMI query

    - by jiaoziren
    Hi all, I am really frustrated by the snippet below: Dim objFSO, varSrc, varDest, varExt Set objFSO = CreateObject("Scripting.FileSystemObject") varSrc = WScript.Arguments(0) varDest = WScript.Arguments(1) varExt = WScript.Arguments(2) If objFSO.FolderExists(varSrc) Then WScript.Echo varSrc strComputer = "." Set objWMIService = GetObject("winmgmts:" _ & "{impersonationLevel=impersonate}!\\" & strComputer & "\root\cimv2") Set colMonitoredEvents = objWMIService.ExecNotificationQuery _ ("SELECT * FROM __InstanceCreationEvent WITHIN 10 WHERE " _ & "Targetinstance ISA 'CIM_DirectoryContainsFile' AND " _ & "TargetInstance.GroupComponent= " _ & "'Win32_Directory.Name=""c:\\\\kk ""'") Do Set objLatestEvent = colMonitoredEvents.NextEvent WScript.Echo objLatestEvent.TargetInstance.PartComponent Loop Else WScript.Echo "Bazinga" End If I tried to replace c:\\kk with varSrc however it seems impossible for WSH to recognize it in WMI query - not to mention it was within a single quote! I have tried chr(34) and it didn't work. Please help if possible. Much appreciated!

    Read the article

  • Mysql_insert_id with Doctrine

    - by Industrial
    Hi! I have a couple of tables (mySQL) that i would like to update with the help of Doctrine. The products table id is auto-incrementing, and here's a brief description on what I would like to do: $prod = new Products(); $prod->type = '0'; $categ = new CategoriesToProducts(); $categ->cat = '111'; $categ->product = $prod->id; $conn = Doctrine_Manager::connection(); $conn->flush(); How can I do this while using flush? Using a regular save is an alternative, but there will be multiple transactions while doing such. I have tried to find a Mysql_insert_id version for doctrine, but without any luck. Thanks!

    Read the article

  • Insert Image on Excel using Open XML

    - by Pankaj
    Hello All I am using this toolkit to write Excel.Every thing is fine with this, but i am not getting how can i inset image and also put style on some rows on my excel http://excelpackage.codeplex.com/wikipage?title=Creating%20an%20Excel%20spreadsheet%20from%20scratch&referringTitle=Home i am using c#

    Read the article

  • Program freezing when syncing a ldap database (100+ entries added)

    - by djerry
    Hey guys, I'm updating a ldap database. I need to add a list of users to the db. I've written a simple foreach loop. There are about 180 users i need to add, but at the 128th user, the program freezes. I know ldap is really used for querying (fast), and that adding and modifying entries will not go as smooth as a search query, but is it normal that the program freezes while doing this? I'll post some code just in case. public static void SyncLDAPWithMySql(Novell.Directory.Ldap.LdapConnection _conn) { List<User> users = GetUsers(); int iteller = 0; foreach (User user in users) { if (!UserAlreadyInLdap(user, _conn)) { TelUser teluser = new TelUser(); teluser.Telephone = user.E164; teluser.Uid = user.E164; teluser.Company = "/"; teluser.Dn = ""; teluser.Name = "/"; teluser.DisplayName = "/"; teluser.FirstName = "/"; TelephoneDA.InsertUser(_conn, teluser ); } Console.WriteLine(iteller + " : " + user.E164); iteller++; } } private static bool UserAlreadyInLdap(User user, Novell.Directory.Ldap.LdapConnection _conn) { List<TelUser> users = TelephoneDA.GetAllEntries(_conn); foreach (TelUser teluser in users) { if (teluser.Telephone.Equals(user.E164)) return true; } return false; } public static int InsertUser(LdapConnection conn, TelUser user) { int iResponse = IsTelNumberUnique(conn, user.Dn, user.Telephone); if (iResponse == 0) { LdapAttributeSet attrSet = MakeAttSet(user); string dnForPhonebook = configurationManager.AppSettings.Get("phonebookDn"); LdapEntry ent = new LdapEntry("uid=" + user.Uid + "," + dnforPhonebook, attrSet); try { conn.Add(ent); } catch (Exception ex) { Console.WriteLine(ex.Message); } } return iResponse; } Am i adding too many entries at a time??? Thanks in advance.

    Read the article

  • asp.net mvc DataViewModel Problem no insert and edit

    - by mazhar
    using the code DataViewModel with one form for create and edit with partial view , in the code below In the create*I am not able to enter the values to the database*,In the edit Mode I am not able to display the value as well in the textboxes for edit public class OrganizationGroupFormViewModel { // Properties public OrganizationGroup OrganizationGroup { get; private set; } public OrganizationGroupFormViewModel(OrganizationGroup organizationGroup) { OrganizationGroup = organizationGroup; } } public class OrganizationGroupsController : Controller { // // GET: /OrganizationGroups/ OrganizationGroupsRepository OrganizationGroupRepository = new OrganizationGroupsRepository(); OrganizationUsersDataContext _db = new OrganizationUsersDataContext(); public ActionResult Create() { try { OrganizationGroup OrgGroup = new OrganizationGroup() { int_CreatedBy=1, dtm_CreatedDate=DateTime.Now }; return View(new OrganizationGroupFormViewModel(OrgGroup)); } catch { return View(); } } [HttpPost] public ActionResult Create(OrganizationGroup OrgGroup) { if (ModelState.IsValid) { OrgGroup.int_CreatedBy = 1; OrgGroup.dtm_CreatedDate = DateTime.Now; OrganizationGroupRepository.Add(OrgGroup); OrganizationGroupRepository.Save(); return RedirectToAction("Details", new { id = OrganizationGroupRepository.int_OrganizationGroupId }); } return View(new OrganizationGroupFormViewModel(OrgGroup)); } // // GET: /OrganizationGroups/Edit/5 public ActionResult Edit(int id) { try { var OrgGroup = _db.OrganizationGroups.First(m => m.int_OrganizationGroupId == id); if (ModelState.IsValid) { OrgGroup.int_ModifiedBy = 1; OrgGroup.dtm_ModifiedDate = DateTime.Now; } return View(new OrganizationGroupFormViewModel(OrgGroup)); } catch { return View(); } } // // POST: /OrganizationGroups/Edit/5 [HttpPost] public ActionResult Edit(int id, FormCollection collection) { try { var OrgGroup = _db.OrganizationGroups.First(m => m.int_OrganizationGroupId == id); if (ModelState.IsValid) { OrgGroup.int_ModifiedBy = 1; OrgGroup.dtm_ModifiedDate = DateTime.Now; TryUpdateModel(OrgGroup); OrganizationGroupRepository.Save(); } return RedirectToAction("Details", new { id = OrgGroup.int_OrganizationGroupId }); } catch { return View(); } } Create View; <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<Egovst.Controllers.OrganizationGroupFormViewModel>" %> Create Organization Group <h2>Create</h2> <%= Html.ValidationSummary(true) %> <div> <% Html.RenderPartial("OrganizationGroup"); %> </div> Organization Group User Control <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<Egovst.Controllers.OrganizationGroupFormViewModel>" %> <% using (Html.BeginForm()) {%> <%= Html.ValidationSummary(true) %> <fieldset> <legend>Fields</legend> <div class="editor-label"> Organization Group Name: </div> <div class="editor-field"> <%= Html.TextBoxFor(model => model.OrganizationGroup.vcr_OrganizationGroupName)%> <%= Html.ValidationMessageFor(model => model.OrganizationGroup.vcr_OrganizationGroupName)%> </div> <div class="editor-label"> Organization Group Description: </div> <div class="editor-field"> <%= Html.TextAreaFor(model => model.OrganizationGroup.vcr_OrganizationGroupDesc)%> <%= Html.ValidationMessageFor(model => model.OrganizationGroup.vcr_OrganizationGroupDesc)%> </div> <p> <input type="submit" value="Save" /> </p> </fieldset> <% } %>

    Read the article

  • How to run a program on a specific remote computer

    - by lucc
    Hi, I have got this working line of code I would like to run via VBScript a share program on a remote computer in a domain environment. The first part is ok where it is asking me to enter a computer name, but the problem is in the second part. I don't know how to run the program on the remote computer that I've entered in the first part. computer = inputbox ("What computer do you wish to check? (Press Enter if this computer)","Computer") set WMI = GetObject("WinMgmts://" & computer) If computer="" then computer = "this computer" Dim objShell Set objShell = WScript.CreateObject( "WScript.Shell" ) objShell.Run("""\\compname\Share\progr.exe""") Set objShell = nothing After running this script, it runs the program on my computer, not on the remote computer. I want to run the program on a specific computer that I have entered from keyboard. Please help. Thank you.

    Read the article

  • Update query for Access Database for certain Parameters

    - by nitinkhanna
    Hi, I am using MS Access as a database and using c#, .net for updating some records in it. But it is giving error saying "No value given for one or more required parameters." There are 5 colums in Table and I want to update only 2, for that I have written the query like "update User_DTL set user_role_id = '" + _UserRole + "', auth_id ='" + _authId + "'" + " WHERE Id = '" + _Id + "' "; where _UserRole, _authId, _Id are strings. What may be the error. Do I need to give every parameter in update statement or there is some other way. Thanks

    Read the article

  • Mod_Rewrite: Insert "/" between variables and values in URL

    - by Abs
    Hello all, I am attempting clean useful URLs using mod_rewrite. I am sure this is a common question but I am not so hot with mod_rewrite: I have this URL: http://mysite.com/user.php?user=fatcatmat&sort=popularv I want to be able to rewrite it like this: http://mysite.com/user/user/fatcatmat/sort/popularv (Is there a way to remove duplicates in a URL?) I think I have managed to do the removal of the PHP extension. RewriteRule ^(.*)\$ $1.php [nc] Is the above correct? For the separate pages, I would have something like this. RewriteRule ^/?user(/)?$ user.php Main Question: Its a bit tedious to do all the above but is there a MEGA rewrite rule that will just place "/" in between variables and their values and remove the .php extension from all pages? Thank you for any help.

    Read the article

  • how to insert page view of a node in another page in drupal

    - by sprugman
    I have a list of node ids and I want to display the 'page' view of each one. For various reasons, I don't want to do this with views, and don't think I should need a module. Just an API call to theme('node'). Something like: $nids = array(3,4,5); foreach ($nids as $nid) { $node = node_load($nid); $result .= theme('node', $node); } but I'm not getting back the full page view of the node. I added this to my node-[type].tpl.php file: if ($page) print "PAGE MODE "; else print "NOT PAGE "; if ($teaser) print "TEASER MODE "; else print "NOT TEASER "; and got: NOT PAGE NOT TEASER I seem to be in some kind of limbo. I suspect there's an argument that I add to the theme function, but the terms are all so general (theme, teaser, page, node), I'm having trouble with my google-fu.

    Read the article

  • converting bash script to .bat

    - by Robokop
    #!/bin/bash function usage(){ cat <<EOF USAGE: $0 [strategylist] valid strategies are: ALLD ALLC TitForTat JOSS WeightedRandom Tester EOF exit 1 } [ -z $1 ] && usage javac robsAgents/*.java robsAgents/behaviours/*.java agentlist='leader:robsAgents.TournamentLeader' agentlist=$agentlist";$1:robsAgents.Contestant" while shift; do agentlist=$agentlist";$1:robsAgents.Contestant" done java jade.Boot -gui -host 127.0.0.1 "$agentlist" i have above bash script and have no access to a windows computer and i need to convert it to a .bat file, but don't even know how to do the shift and argument parsing

    Read the article

  • Export MySQL Data as Insert Statements

    - by gav
    Hi All, I'm working in Ubuntu with MySql and I also have Query Browser and Administrator installed, I'm not afraid of the command line either if it helps. I want simply to be able to run a query and see a result set but then convert that result set into a series of commands that could be used to create the same rows in a table of an identical schema. I hope the question makes sense, it's quite a simple problem and one that must have been solved but I can't for the life of me work out where this kind of conversion is made available. Thanks in advance, Gav

    Read the article

  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) objects = OpenCvManager() the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

    Read the article

  • Get the identity value from an insert via a .net dataset update call

    - by DeveloperMCT
    Here is some sample code that inserts a record into a db table: Dim ds As DataSet = New DataSet() da.Fill(ds, "Shippers") Dim RowDatos As DataRow RowDatos = ds.Tables("Shippers").NewRow RowDatos.Item("CompanyName") = "Serpost Peru" RowDatos.Item("Phone") = "(511) 555-5555" ds.Tables("Shippers").Rows.Add(RowDatos) Dim custCB As SqlCommandBuilder = New SqlCommandBuilder(da) da.Update(ds, "Shippers") It inserts a row in the Shippers Table, the ShippersID is a Indentity value. My question is how can i retrieve the Identity value generated when the new row is inserted in the Shippers table. I have done several web searches and the sources I've seen on the net don't answer it speccifically or go on to talk about stored procedures. Any help would be appreciated. Thanks!

    Read the article

  • Django forms I cannot save picture file

    - by dana
    i have the model: class OpenCv(models.Model): created_by = models.ForeignKey(User, blank=True) first_name = models.CharField(('first name'), max_length=30, blank=True) last_name = models.CharField(('last name'), max_length=30, blank=True) url = models.URLField(verify_exists=True) picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True) bio = models.CharField(('bio'), max_length=180, blank=True) date_birth = models.DateField(blank=True,null=True) domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices) specialisation = models.CharField(('specialization'), max_length=30, blank=True) degree = models.CharField(('degree'), max_length=30, choices = degree_choices) year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices) lyceum = models.CharField(('lyceum'), max_length=30, blank=True) faculty = models.ForeignKey(Faculty, blank=True,null=True) references = models.CharField(('references'), max_length=30, blank=True) workplace = models.ForeignKey(Workplace, blank=True,null=True) the form: class OpencvForm(ModelForm): class Meta: model = OpenCv fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references'] and the view: def save_opencv(request): if request.method == 'POST': form = OpencvForm(request.POST, request.FILES) # if 'picture' in request.FILES: file = request.FILES['picture'] filename = file['filename'] fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb') fd.write(file['content']) fd.close() if form.is_valid(): new_obj = form.save(commit=False) new_obj.picture = form.cleaned_data['picture'] new_obj.created_by = request.user new_obj.save() return HttpResponseRedirect('.') else: form = OpencvForm() return render_to_response('opencv/opencv_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

    Read the article

  • .bat file to update loopback controller to external ip

    - by cable729
    Okay, so I've figured out how to get my external ip using wget: wget -q -O - http://whatismyip.com/automation/n09230945.asp that outputs the ip to the command console. adding currentip.txt to the end will write it to a text file. But what I want to do is use netsh interface ip set address name="Local Area Connection 2" source=static addr=[WHAT DO I PUT HERE] Also, a way to make the command prompt not flash would be nice too :)

    Read the article

  • Insert Registration Data in MySQL using PHP

    - by J M 4
    I may not be asking this in the best way possible but i will try my hardest. Thank you ahead of time for your help: I am creating an enrollment website which allows an individual OR manager to enroll for medical testing services for professional athletes. I will NOT be using the site as a query DB which anybody can view information stored within the database. The information is instead simply stored, and passed along in a CSV format to our network provider so they can use as needed after the fact. There are two possible scenarios: Scenario 1 - Individual Enrollment If an individual athlete chooses to enroll him/herself, they enter their personal information, submit their payment information (credit/bank account) for processing, and their information is stored in an online database as Athlete1. Scenario 2 - Manager Enrollment If a manager chooses to enroll several athletes he manages/ promotes for, he enters his personal information, then enters the personal information for each athlete he wishes to pay for (name, address, ssn, dob, etc), then submits payment information for ALL athletes he is enrolling. This number can range from 1 single athlete, up to 20 athletes per single enrollment (he can return and complete a follow up enrollment for additional athletes). Initially, I was building the database to house ALL information regardless of enrollment type in a single table which housed over 400 columns (think 20 athletes with over 10 fields per athlete such as name, dob, ssn, etc). Now that I think about it more, I believe create multiple tables (manager(s), athlete(s)) may be a better idea here but still not quite sure how to go about it for the following very important reasons: Issue 1 If I list the manager as the parent table, I am afraid the individual enrolling athlete will not show up in the primary table and will not be included in the overall registration file which needs to be sent on to the network providers. Issue 2 All athletes being enrolled by a manager are being stored in SESSION as F1FirstName, F2FirstName where F1 and F2 relate to the id of the fighter. I am not sure technically speaking how to store multiple pieces of information within the same table under separate rows using PHP. For example, all athleteswill have a first name. The very basic theory of what i am trying to do is: If number_of_athletes 1, store F1FirstName in row 1, column 1 of Table "Athletes"; store F1LastName in row 1, column 2 of Table "Athletes"; store F2FirstName in row 2, column 1 of Table "Athletes"; store F2LastName in row 2, column 2 of table "Athletes"; Does this make sense? I know this question is very long and probably difficult so i appreciate the guidance.

    Read the article

  • I insert new parent row and child rowstate changes from Added to unchanged

    - by Joel
    rowsUpdated is an int32 to count how many rows are updated rowsToUpdate = dataset.ParentTable.Select("", "", dataviewRowState.Added) if rowsToUpdate isNot Nothing then for each row as datarow in RowsToUpdate changes the rowstate: rowsUpdated = rowsUpdated + ParentTableAdapter.update(row) Next row End if I'm sure it's something I'm over looking but I just can't see it. Thanks in advance, Joel

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >