Search Results

Search found 4967 results on 199 pages for 'bourne shell'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 79/199 | < Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >

  • Will Unity allow users to change the color/appearance of the top-Panel?

    - by Sam
    I'm very excited by the functional design principles and keyboard shortcuts that are being implemented for Unity. And function of use is more important to me than looks. However, after experiencing the aesthetic beauty of the display of the top panel in gnome-shell, I was wondering if users would be able to alter the color of Unity's top panel? IMHO it does not look as good as the gnome-shell implementation (or mac OS X/iPad). I think if an alternate color/appearance were chosen for the panel, it would make a big difference aesthetically. Is there a way to make it Black like gnome-shell? Or are the color choices limited to theme-designs as pointed out in this answer? For efficiency and clarity, the Panel should be better differentiated from application controls. The panel should be a different color because it has a "constant (always present) state," unlike application controls. For contrast and easy-recognition, I would like to make the Panel black (like gnome-shell) but make the application controls (e.g., those of Firefox) "Inverted"

    Read the article

  • How To Log Into The Desktop, Add a Start Menu, and Disable Hot Corners in Windows 8

    - by Chris Hoffman
    If you don’t have a touchscreen computer and spend all your time on the desktop, Windows 8’s new interface can seem intrusive. Microsoft won’t allow you to disable the new interface, but Classic Shell provides the options Microsoft didn’t. In addition to providing a Start button, Classic Shell can take you straight to the desktop when you log in and disable the hot corners that activate the charms and metro app switcher. There are other programs that do this, but Classic Shell is free and open-source. Many of the alternatives, such as Start8 and RetroUI, are commercial apps that cost money. We’ve covered Classic Shell in the past, but it’s come a long way since then. How Hackers Can Disguise Malicious Programs With Fake File Extensions Can Dust Actually Damage My Computer? What To Do If You Get a Virus on Your Computer

    Read the article

  • Screen resolution is too low with open source drivers on Ubuntu 12.10

    - by Chintan Parikh
    I'm on an AMD graphics card. When I use the open source xserver-xorg-video-radeon driver, Gnome shell works fine but my screen resolution can't be set higher than 1024x768. However, when I'm on the closed source fglrx drivers, the screen resolution works fine, but gnome shell doesn't (it goes to gnome classic for some reason). Does anyone know how I can either get gnome shell to work with fglrx, or how I can set my screen resolution with xserver-xorg-video-radeon?

    Read the article

  • LDAP loginShell on platforms with different paths

    - by neoice
    I'm using LDAP to deal with users and authentication across my network. I'm now adding FreeBSD hosts and have hit a problem with login shells. on Linux, shells tend to be in /bin/$shellname, so setting my login shell in LDAP to /bin/zsh works perfectly. on FreeBSD, /bin/zsh doesnt exist, I need to use /usr/local/bin/zsh. is there a solution to this? I imagine I might be able to make some sort of login-shell.sh script that LDAP passes out as the "shell" and then use the script to determine the actual shell for the user, but I'm not a fan of that idea. I'm using Debian and FreeBSD, both with a standard OpenLDAP/PAM/nss setup. edit: it looks like using /bin/sh and adding an exec $shell to .profile would "work", but that doesnt scale very well.

    Read the article

  • What''s the "earliest" place one can set an environment variable during Linux boot process?

    - by amn
    I know I can set a variable in a shell startup file, but the thing is, I am trying to set up a POSIX-compatible environment, and a POSIX shell does not parse any startup files other than the one specified by the environment variable ENV. This presents a problem - currently my login starts the shell as bash, which I will try to replace with sh so Bash runs as POSIX shell - however then it will not parse the default startup files and I need ENV set to specify these. Which means as far as I understand that I need to specify ENV before login starts the shell, correct? Now, how would I do that? I hope my question is clear, if not I will gladly redact it.

    Read the article

  • How to avoid coupling when using regions in Composite WPF

    - by emddudley
    I have an application designed using Microsoft's Composite Application Library. My shell has several regions defined so that I can inject content from separate modules. I'm looking for a design pattern that will reduce the coupling that these regions introduce. In all examples I have seen, regions are defined and accessed using a string in a static class in the infrastructure project.: <ItemsControl cal:RegionManager.RegionName="{x:Static inf:RegionNames.TabRegion}"> public static class RegionNames { public const string TabRegion = "TabRegion"; } This introduces an dependency on the shell from the infrastructure project, because the infrastructure project is now defining some of the shell's capabilities. The CAL RegionManager throws an exception if you attempt to access a region which is not defined, so I must ensure that the infrastructure and shell projects are kept in sync. Is there a way to isolate the shell's regions so that they are defined only within the shell (no region names in the infrastructure project)? Is there a way to make regions optional, so that shells can be swapped out even if they don't have all the same regions? (An example: One shell has menu and toolbar regions, another only has the menu... modules should be able to inject into the toolbar if it's available, without failing when it's not)

    Read the article

  • Can't get SWT Display on Mac OS X.

    - by Mattias Holmqvist
    I'm running Mac OS X Snow Leopard and wan't to access the Display from the activator in an OSGi bundle. Below is the start method for my activator: @Override public void start(BundleContext context) throws Exception { ExecutorService service = Executors.newSingleThreadExecutor(); service.execute(new Runnable() { @Override public void run() { Display display = Display.getDefault(); Shell shell = new Shell(display); Text helloText = new Text(shell, SWT.CENTER); helloText.setText("Hello SWT!"); helloText.pack(); shell.pack(); shell.open(); while (!shell.isDisposed()) { if (!display.readAndDispatch()) display.sleep(); } display.dispose(); } }); } Calling this code in a Windows environment works fine, but deploying on Mac OS X I get the following output: 2009-10-14 17:17:54.050 java[2010:10003] *** __NSAutoreleaseNoPool(): Object 0x101620d20 of class NSCFString autoreleased with no pool in place - just leaking 2009-10-14 17:17:54.081 java[2010:10003] *** __NSAutoreleaseNoPool(): Object 0x100119240 of class NSCFNumber autoreleased with no pool in place - just leaking 2009-10-14 17:17:54.084 java[2010:10003] *** __NSAutoreleaseNoPool(): Object 0x1001024b0 of class NSCFString autoreleased with no pool in place - just leaking 2009-10-14 17:17:54.086 java[2010:10003] *** __NSAutoreleaseNoPool(): Object 0x7fff701d7f70 of class NSCFString autoreleased with no pool in place - just leaking 2009-10-14 17:17:54.087 java[2010:10003] *** __NSAutoreleaseNoPool(): Object 0x100113330 of class NSCFString autoreleased with no pool in place - just leaking 2009-10-14 17:17:54.092 java[2010:10003] *** __NSAutoreleaseNoPool(): Object 0x101624540 of class NSCFData autoreleased with no pool in place - just leaking . . . I've used the -XstartOnFirstThread VM argument without any luck. I'm on 64-bit Cocoa but I've also tried 32-bit Cocoa. When trying on Carbon I get the following error: Invalid memory access of location 00000020 eip=9012337c When debugging into the Display class I can see that the Displays[] array only contains null references.

    Read the article

  • how to recover my xml default icon?

    - by moonway
    My XML files are showing the unknown programs icon, you can see in this picture: i cant revise its icon why? i look it up in the registry i find no error look at the following Windows Registry Editor Version 5.00 [HKEY_CLASSES_ROOT.xml] @="xmlfile" "Content Type"="text/xml" "PerceivedType"="text" [HKEY_CLASSES_ROOT.xml\PersistentHandler] @="{7E9D8D44-6926-426F-AA2B-217A819A5CCE}" Windows Registry Editor Version 5.00 [HKEY_CLASSES_ROOT\xmlfile] @="@C:\Windows\System32\msxml3r.dll,-1" "EditFlags"=hex:00,00,00,00 "FriendlyTypeName"=hex(2):40,00,25,00,53,00,79,00,73,00,74,00,65,00,6d,00,52,\ 00,6f,00,6f,00,74,00,25,00,5c,00,53,00,79,00,73,00,74,00,65,00,6d,00,33,00,\ 32,00,5c,00,6d,00,73,00,78,00,6d,00,6c,00,33,00,72,00,2e,00,64,00,6c,00,6c,\ 00,2c,00,2d,00,31,00,00,00 [HKEY_CLASSES_ROOT\xmlfile\BrowseInPlace] [HKEY_CLASSES_ROOT\xmlfile\CLSID] @="{48123BC4-99D9-11D1-A6B3-00C04FD91555}" [HKEY_CLASSES_ROOT\xmlfile\DefaultIcon] @="C:\Windows\System32\msxml3.dll,0" [HKEY_CLASSES_ROOT\xmlfile\shell] @="open" [HKEY_CLASSES_ROOT\xmlfile\shell\edit] [HKEY_CLASSES_ROOT\xmlfile\shell\edit\command] @="\"C:\Program Files\Common Files\Microsoft Shared\OFFICE11\MSOXMLED.EXE\" /verb edit \"%1\"" [HKEY_CLASSES_ROOT\xmlfile\shell\Open] [HKEY_CLASSES_ROOT\xmlfile\shell\Open\Command] @="\"C:\Program Files\Common Files\Microsoft Shared\OFFICE11\MSOXMLED.EXE\" /verb open \"%1\"" [HKEY_CLASSES_ROOT\xmlfile\shell\Open\ddeexec] @="" [HKEY_CLASSES_ROOT\xmlfile\ShellEx] [HKEY_CLASSES_ROOT\xmlfile\ShellEx\IconHandler] @="{AB968F1E-E20B-403A-9EB8-72EB0EB6797E}" can you find something wrong or you can paste your reg hehe i need default reg about xml which is with default associated exe all right!

    Read the article

  • Why does Celery work in Python shell, but not in my Django views? (import problem)

    - by TIMEX
    I installed Celery (latest stable version.) I have a directory called /home/myuser/fable/jobs. Inside this directory, I have a file called tasks.py: from celery.decorators import task from celery.task import Task class Submitter(Task): def run(self, post, **kwargs): return "Yes, it works!!!!!!" Inside this directory, I also have a file called celeryconfig.py: BROKER_HOST = "localhost" BROKER_PORT = 5672 BROKER_USER = "abc" BROKER_PASSWORD = "xyz" BROKER_VHOST = "fablemq" CELERY_RESULT_BACKEND = "amqp" CELERY_IMPORTS = ("tasks", ) In my /etc/profile, I have these set as my PYTHONPATH: PYTHONPATH=/home/myuser/fable:/home/myuser/fable/jobs So I run my Celery worker using the console ($ celeryd --loglevel=INFO), and I try it out. I open the Python console and import the tasks. Then, I run the Submitter. >>> import fable.jobs.tasks as tasks >>> s = tasks.Submitter() >>> s.delay("abc") <AsyncResult: d70d9732-fb07-4cca-82be-d7912124a987> Everything works, as you can see in my console [2011-01-09 17:30:05,766: INFO/MainProcess] Task tasks.Submitter[d70d9732-fb07-4cca-82be-d7912124a987] succeeded in 0.0398268699646s: But when I go into my Django's views.py and run the exact 3 lines of code as above, I get this: [2011-01-09 17:25:20,298: ERROR/MainProcess] Unknown task ignored: "Task of kind 'fable.jobs.tasks.Submitter' is not registered, please make sure it's imported.": {'retries': 0, 'task': 'fable.jobs.tasks.Submitter', 'args': ('abc',), 'expires': None, 'eta': None, 'kwargs': {}, 'id': 'eb5c65b4-f352-45c6-96f1-05d3a5329d53'} Traceback (most recent call last): File "/home/myuser/mysite-env/lib/python2.6/site-packages/celery/worker/listener.py", line 321, in receive_message eventer=self.event_dispatcher) File "/home/myuser/mysite-env/lib/python2.6/site-packages/celery/worker/job.py", line 299, in from_message eta=eta, expires=expires) File "/home/myuser/mysite-env/lib/python2.6/site-packages/celery/worker/job.py", line 243, in __init__ self.task = tasks[self.task_name] File "/home/myuser/mysite-env/lib/python2.6/site-packages/celery/registry.py", line 63, in __getitem__ raise self.NotRegistered(str(exc)) NotRegistered: "Task of kind 'fable.jobs.tasks.Submitter' is not registered, please make sure it's imported." It's weird, because the celeryd client does show that it's registered, when I launch it. [2011-01-09 17:38:27,446: WARNING/MainProcess] Configuration -> . broker -> amqp://GOGOme@localhost:5672/fablemq . queues -> . celery -> exchange:celery (direct) binding:celery . concurrency -> 1 . loader -> celery.loaders.default.Loader . logfile -> [stderr]@INFO . events -> OFF . beat -> OFF . tasks -> . tasks.Decayer . tasks.Submitter Can someone help?

    Read the article

  • Bash Shell; read command; using Cygwin on Windows 7

    - by user312397
    Okay so I am having this problem. I write up a script to be run in cygwin on Windows. I've tried a bunch of basic example scripts in case it was my scripts problem. So I tried this: #!/bin/bash echo -e "Enter your name and press [ENTER]: \c" read var_name echo "Your name is: $var_name" Then I will run it and I enter a name for var_name. I get this: $ ./project1.sh Enter your name and press [ENTER]: Jake ': not a valid identifierad: `var_name Your name is: So as far as I understand it I am having a problem with read. I am trying to work on a project for my class, but I can't seem to figure out why it won't read it. I followed the book with no triumph then resorted to these examples on the web that do not seem to work for me either. Does anyone have any idea if it is my setup or if I am missing something, thanks.

    Read the article

  • Can I have a shell alias evaluate a history substitution command?

    - by Brandon
    I'm trying to write an alias for cd !!:1, which takes the 2nd word of the previous command, and changes to the directory of that name. For instance, if I type rails new_project cd !!:1 the second line will cd into the "new_project" directory. Since !!:1 is awkward to type (even though it's short, it requires three SHIFTed keys, on opposite sides of of the keyboard, and then an unSHIFTed version of the key that was typed twice SHIFTed), I want to just type something like cd- but since the !!:1 is evaluated on the command line, I (OBVIOUSLY) can't just do alias cd-=!!:1 or I'd be saving an alias that contained "new_project" hard-coded into it. So I tried alias cd-='!!:1' The problem with this is that the !!:1 is NEVER evaluated, and I get a message that no directory named !!:1 exists. How can I make an alias where the history substitution is evaluated AT THE TIME I ISSUE THE ALIAS COMMAND, not when I define the alias, and not never? (I've tried this in both bash and zsh, and get the same results in both.)

    Read the article

  • Delphi 7: how to execute shell command and check the result?

    - by mawg
    I'm using Delphi 7 and can't predict the target version of Windows. I need to create a database (probably MySql, but might be something else) and define some table structures. I do not need to populate any data. Unfortunately, all of the ADO components seem to expect that a database already exists and they will then allow you to manipulate it. So, since it's only a few simple commands, I thought that I might as well use ShellExectute(). Agree? Disagree? Can anyone give me a sample code which will attempt to run "MySql --version" and let me check the result? After that I should be able to figure it out for myself. Thanks.

    Read the article

  • Could not find rake-10.1.0 in any of the sources

    - by spuder
    I've got a ruby on rails application (gitlab) which is installed via puppet. Everything on the test system runs fine, but production generates an error about rake Running /home/git/gitlab-shell/bin/check Could not find rake-10.1.0 in any of the sources Run bundle install to install missing gems. Here is the full rake check: root@gitlab:/home/git# sudo -u git -H bundle exec rake gitlab:check RAILS_ENV=production Checking Environment ... Git configured for git user? ... yes Has python2? ... yes python2 is supported version? ... yes Checking Environment ... Finished Checking GitLab Shell ... GitLab Shell version >= 1.7.1 ? ... OK (1.7.1) Repo base directory exists? ... yes Repo base directory is a symlink? ... no Repo base owned by git:git? ... yes Repo base access is drwxrws---? ... yes update hook up-to-date? ... yes update hooks in repos are links: ... Could not find rake-10.1.0 in any of the sources Run `bundle install` to install missing gems. gitlab-shell self-check failed Try fixing it: Make sure GitLab is running; Check the gitlab-shell configuration file: sudo -u git -H editor /home/git/gitlab-shell/config.yml Please fix the error above and rerun the checks. Checking GitLab Shell ... Finished Checking Sidekiq ... Running? ... yes Number of Sidekiq processes ... 1 Checking Sidekiq ... Finished Checking GitLab ... Database config exists? ... yes Database is SQLite ... no All migrations up? ... yes GitLab config exists? ... yes GitLab config outdated? ... no Log directory writable? ... yes Tmp directory writable? ... yes Init script exists? ... yes Init script up-to-date? ... yes projects have namespace: ... Spencer Owen / bar ... yes Projects have satellites? ... Spencer Owen / bar ... can't create, repository is empty Redis version >= 2.0.0? ... yes Your git bin path is "/usr/bin/git" Git version >= 1.7.10 ? ... yes (1.8.4) Checking GitLab ... Finished The step 'gitlab-shell check' effectively runs the following command. If I run that command manually, everything passes. root@gitlab:/home/git/gitlab# sudo -u git -H /home/git/gitlab-shell/bin/check Check GitLab API access: OK Check directories and files: /home/git/repositories: OK /home/git/.ssh/authorized_keys: OK I have verified that rake is in fact installed root@gitlab:/home/git/gitlab# gem install rake -v 10.1.0 root@gitlab:/home/git/gitlab# bundle install root@gitlab:/home/git/gitlab# sudo -u git -H gem install rake -v 10.1.0 root@gitlab:/home/git/gitlab# sudo -u git -H bundle install Ruby is installed with update alternatives root@gitlab:/home/git/gitlab# sudo -u git -H ruby --version ruby 1.9.3p0 (2011-10-30 revision 33570) [x86_64-linux] root@gitlab:/home/git/gitlab# sudo -u git -H ls -l `which ruby` lrwxrwxrwx 1 root root 22 Oct 8 20:26 /usr/bin/ruby -> /etc/alternatives/ruby root@gitlab:/home/git/gitlab# sudo -u git -H gem --version 2.1.10 root@gitlab:/home/git/gitlab# sudo -u git -H ls -l `which gem` lrwxrwxrwx 1 root root 21 Oct 10 20:50 /usr/bin/gem -> /etc/alternatives/gem I've tried the solution mentioned below, to allow shared gems http://stackoverflow.com/questions/19284914/bundle-exec-fails-with-could-not-find-rake-10-1-0-in-any-of-the-sources http://stackoverflow.com/questions/18978002/could-not-find-rake-with-bundle-exec root@gitlab:/home/git/gitlab# cat /home/git/gitlab/.bundle/config --- BUNDLE_FROZEN: '1' BUNDLE_PATH: vendor/bundle BUNDLE_WITHOUT: development:test:postgres BUNDLE_DISABLE_SHARED_GEMS: '1' I've exhausted google, so I'm hoping for someone more familiar with ruby to offer any ideas how to resolve the error. Could not find rake-10.1.0 in any of the sources

    Read the article

  • How do I create a Launcher in Ubuntu 9.1 that runs a shell script?

    - by mkelley33
    Here's my situation: New to Ubuntu (just nstalled 9.10 Karmic Koala 64 bit) Purpose: to easily run PyCharm without too much typing (ie. cd... ./pycharm.sh) Want to create desktop Launcher instead of terminal & typing (without resorting to the "Run in Terminal" option) Tried to create Launcher to executes .sh script in Document directory Right-clicked Desktop Create Launcher a. Type == Application; Browse [insert absolute path to .sh script]; no luck b. Type == Application in Terminal; Browse ...ditto I'm open to any other alternatives that involve as little typing as possible. I would like to just start Ubuntu, click Launcher icons, and have terminals spring to life, running the intended scripts. Crazy? No. Lazy? Probably. Productive? Hopefully :)

    Read the article

  • shell command to find a process id and attach to it?

    - by lallous
    Hello I want to attach to a running process using 'ddd', what I manually do is: # ps -ax | grep PROCESS_NAME Then I get a list and the pid, then I type: # ddd PROCESS_NAME THE_PID Is there is a way to type just one command directly? Remark: When I type ps -ax | grep PROCESS_NAME <- grep will match both the process and grep command line itself.

    Read the article

  • How to give focus to default program of shell-opened file, from Java ?

    - by Rabarberski
    From within Java, I am opening an Excel file with the default file handler (MS Excel, in this case :-) ) using the method described in this stackoverflow question: Desktop dt = Desktop.getDesktop(); dt.open(new File(filename)); However, the Excel program doesn't get the focus. Is there any easy way to do so? Edit: There is a related stackoverflow question for C#, but I didn't find any similar Java method.

    Read the article

  • How to run a GUI app from ssh shell?

    - by karramba
    I can access my linux box by ssh and by vnc. I want to run a GUI application, but directly from ssh, I don't want to access through VNC and click around. So, after logging in using ssh, I want to issue a magic command, so that when I log in through VNC I will see my GUI app running. How can I do this?

    Read the article

  • Can I use a local::lib if local::lib isn't installed globally and without eval-ing it in shell?

    - by xenoterracide
    I have a problem, I want to use local::lib; in a script. But because I need to use this script many places, I don't want to try adding the eval to bashrc, every time I install this script to a server. and I can't get local::lib installed globally (in the default @INC) on the servers. Is there any way I can use local::lib from within the script so that it knows where the module local::lib is without the eval that local::lib recommends and without installing it into a directory in the default @INC on the server?

    Read the article

  • How would I write this shell script as a Windows batch script?

    - by Jeremy Banks
    I haven't had a chance to test this script, I'm just using it as a suitable pseudocode. It's just supposed to copy all files in the current directory into a timestamped subdirectory. ID="$(date +%Y%b%d%H%M%S)" COMMITABLE="$(ls | egrep --invert-match ^(STATES|PARENT)\$)" STATE_PATH="$(pwd)/STATES/$ID" mkdir --parents "$STATE_PATH" cp $COMMITABLE "$STATE_PATH" ln -s "$STATE_PATH" PARENT

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >