Search Results

Search found 9275 results on 371 pages for 'condition variables'.

Page 79/371 | < Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >

• Ruby - Is there a way to overwrite the __FILE__ variable?

  - by Markus Orrelly

  I'm doing some unit testing, and some of the code is checking to see if files exist based on the relative path of the currently-executing script by using the FILE variable. I'm doing something like this: if File.directory?(File.join(File.dirname(__FILE__),'..','..','directory')) blah blah blah ... else raise "Can't find directory" end I'm trying to find a way to make it fail in the unit tests without doing anything drastic. Being able to overwrite the __ FILE __ variable would be easiest, but as far as I can tell, it's impossible. Any tips?

  Read the article

• How to assign a string value to a string variable in C++

  - by Phenom

  Shouldn't this work? string s; s = "some string";

  Read the article

• uninitialized local variable

  - by blitzeus

  This code compiles and runs though gives a Microsoft compiler error that I cant fix warning C4700: uninitialized local variable 'ptr4D' used. This is in the last line of the code, I think #include <iostream> using namespace std; const int DIM0 = 2, DIM1 = 3, DIM2 = 4, DIM3 = 5; void TestDeclar(); int main(){ TestDeclar(); cout << "Done!\n"; return 0; } void TestDeclar(){ //24 - array of 5 floats float xa[DIM3], xb[DIM3], xc[DIM3], xd[DIM3], xe[DIM3], xf[DIM3]; float xg[DIM3], xh[DIM3], xi[DIM3], xj[DIM3], xk[DIM3], xl[DIM3]; float xm[DIM3], xn[DIM3], xo[DIM3], xp[DIM3], xq[DIM3], xr[DIM3]; float xs[DIM3], xt[DIM3], xu[DIM3], xv[DIM3], xw[DIM3], xx[DIM3]; //6 - array of 4 pointers to floats float *ya[DIM2] = {xa, xb, xc, xd}, *yb[DIM2] = {xe, xf, xg, xh}; float *yc[DIM2] = {xi, xj, xk, xl}, *yd[DIM2] = {xm, xn, xo, xp}; float *ye[DIM2] = {xq, xr, xs, xt}, *yf[DIM2] = {xu, xv, xw, xx}; //2 - array of 3 pointers to pointers of floats float **za[DIM1] = {ya, yb, yc}; float **zb[DIM1] = {yd, ye, yf}; //array of 2 pointers to pointers to pointers of floats float ***ptr4D[DIM0] = {za, zb}; cout << &***ptr4D[DIM0] << '\n'; }

  Read the article

• Adding extra data to a Variable

  - by DogPooOnYourShoe

  Right now, my code plucks out only one value using Mysql. So I thought I might aswell add each found result to a variable, however I dont know how to do this. This must be a very basic question, but I cant find a answer for it echo '<table border="1">'; echo "<tr><td><b>Surname</b></td><td><b>Title/Name</b></td><td><b>Numbers</b></td><td><b>Telephone</b></td><td><b>Edit</b></td><td><b>Del</b></td></tr>\n"; while ($row= mysql_fetch_array($result)) { $Surname = $row["Surname"]; $Title = $row["TitleName"]; $Email = $row["Email"]; $Telephone = $row["Telephone"]; $id = $row["id"]; $MooringNumbers = $row['Number']; $Assignedto['AssignedTo']; } $MooringQuery = "select * FROM mooring WHERE AssignedTo='$id'"; $MooringResult = mysql_query($MooringQuery) or die("Couldn't execute query"); while ($row1= mysql_fetch_array($MooringResult)) { $AssignedTo = $row1["AssignedTo"]; $MooringNumbers = $row1["Number"]; echo '<tr><td>' .$Surname.'</td><td>'.$Title.'</td><td>'.$MooringNumbers . '</td><td>'.$Telephone.'</td><td>' . '<a href="rlayCustomerUpdtForm.php?id='.$id.'">[EDIT]</a></td>'.'<td>'. '<a href="deleteCustomer.php?id='.$id.'">[x]</a></td>'. '</tr>'; }

  Read the article

• jQuery ajax return value

  - by Jordan Pagaduan

  How can I return the value "pinNumber" from jquery ajax so I can append it outside of the ajax. Here is my code var x = pinLast + 1; for(i=x;i<=pinMany;i++) { var i = x++; var cardNumber = i.toPrecision(8).split('.').reverse().join(''); var pinNumber = ''; jQuery.ajax({ type: "POST", url: "data.php", data: "request_type=generator", async: false, success: function(msg){ var pinNumber = msg; return pinNumber; //pin number should return } }); jQuery('.pin_generated_table').append(cardNumber+' = '+pinNumber+''); // the variable pinNumber should be able to go here } Please ask me if you don't understand.. ^^ thanks

  Read the article

• PHP contact form, am I doing it wrong?

  - by decimal

  I'm learning PHP and I'm trying to write a simple email script. I have a function (checkEmpty) to check if all the forms are filled in and if the email adress is valid (isEmailValid). I'm not sure how to return true checkEmpty funciton. Here's my code: When the submit button is clicked: if (isset($_POST['submit'])) { //INSERT FORM VALUES INTO AN ARRAY $field = array ('name' => $_POST['name'], 'email' => $_POST['email'], 'message' => $_POST['message']); //CONVERT ARRAY KEYS TO VARIABLE NAMES extract ($field); checkEmpty($name, $email, $message); function checkEmpty($name, $email, $message) { global $name_error; global $mail_error; global $message_error; //CHECK IF NAME FIELD IS EMPTY if (isset($name) === true && empty($name) === true) { $name_error = "<span class='error_text'>* Please enter your name</span>"; } //CHECK IF EMAIL IS EMPTY if (isset($email) === true && empty($email) === true) { $mail_error = "<span class='error_text'>* Please enter your email address</span>"; //AND IF IT ISN'T EMPTY CHECK IF IT IS A VALID ONE } elseif (!isValidEmail($email)) { $mail_error = "<span class='error_text'> * Please enter a valid email</span>"; } //CHECK IF MESSAGE IS EMPTY if (isset($message) === true && empty($message) === true) { $message_error = "<span class='error_text'>* Please enter your message</span>"; } } // This function tests whether the email address is valid function isValidEmail($email){ $pattern = "^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$"; if (eregi($pattern, $email)) { return true; } else { return false; } } I know I shouldn't be using globals in the function, I don't know an alternative. The error messages are display beside each form element.

  Read the article

• Why is $b "b" in this logic when echoing out ${$b}

  - by user275074

  I'd have expected ${$b} to be 'a' but it is 'b', why is this the case? $a = "b"; $b = "a"; Sorry again I forgot to put ${$b} produces "b"

  Read the article

• Python: Best practice for including a version number in an app?

  - by Ben

  I have a PyQt application that reads and writes data files. I am including a 'version number' in each file written. This is a simple number similar to: 1.2 or something (major and minor versions). I am doing this so that I can change the format of these data files in future versions and then still correctly parse them simply by checking to see what the version is inside the file. My question is what is the best practice for keeping this number stored inside the app itself. I.e. do I just hard-code the app version number into the class that is responsible for reading and writing files? Or should I have some sort of object/variable stored at the top-level of the app and somehow access it from the class responsible for reading and writing these files. If the latter, how do I store it and how do I access it? Thanks.

  Read the article

• store in a variable only the first or only the second class of an element

  - by shecky

  I'm using this bit of jQ to add a class to two different elements based on the class of another (parent/grandparent, etc) element: $(document).ready(function(){ var containerClass = $('#main-content').attr('class'); $('#nav-primary li#'+containerClass).addClass('active'); $('#aux-left div[id$='+containerClass+']').addClass('active'); }); Brilliant, but I have two problems with it: First, when there's no class at all in <div id="main-content">, the 'active' class is added to all the #nav-primary LIs, and also to all the #aux-left DIVs; how can I modify this so that in the absence of any class on #main-content, do nothing? Second, how can I target only the first or second of multiple classes to store in the 'containerClass' variable, e.g., <div id="main-content" class="apples bananas">? Very much appreciated! svs

  Read the article

• Static variable for optimization

  - by keithjgrant

  I'm wondering if I can use a static variable for optimization: public function Bar() { static $i = moderatelyExpensiveFunctionCall(); if ($i) { return something(); } else { return somethingElse(); } } I know that once $i is initialized, it won't be changed by by that line of code on successive calls to Bar(). I assume this means that moderatelyExpensiveFunctionCall() won't be evaluated every time I call, but I'd like to know for certain. Once PHP sees a static variable that has been initialized, does it skip over that line of code? In other words, is this going to optimize my execution time if I make a lot of calls to Bar(), or am I wasting my time?

  Read the article

• jQuery global variable problem

  - by Emanuel

  var id = $(this).children().html(); // id is 5 $.ajax({ url: 'ajax.php?id=' + id, success: function(data) { id = data; // id is 1 } }); if(id == 1){ // id is again 5 ... } Why in the following example I can't reinitialize the id variable? What is wrong? Thanks.

  Read the article

• converting a form from text to textarea

  - by David Cook

  I have a form created to pull PHP values into my database. I created the form with all type="text" constructions. What follows is the code that used to set up the input of data and confirmed that it is functional. <label>About Me: <input type="text" name="BIO_info"/></label> I converted the input to a textarea and adjusted some parameters for proper display. Unfortunately, it has broken the ability for the script to function. What follows is the code I wrote to convert and store from a text area input. <label for="BIO_info" style=" margin-bottom: 500px; margin-top: 2000px; ">About Me: <textarea name="BIO_info" rows="20" cols="60" style="resize: none; overflow-y: hidden;vertical-align:middle;"></textarea> <p> I would appreciate any suggestions.

  Read the article

• PHP - How to determine if request is coming from a specific file.

  - by John

  I have fileA.php on SERVER_A and fileB.php on SERVER_B fileB.php makes a curl request to fileA.php for it's contents How can fileA.php determine that the request is coming specifically from fileB.php? -- I was thinking about sending the $_SERVER['SCRIPT_NAME'] in fileB.php to fileA.php but since someone can go into fileB.php or any file in general and just do $_SERVER['SCRIPT_NAME'] = 'fileB.php'; it's not really that secure. So how can I determine, for security reasons, that the request is coming from a specific file on a different server?

  Read the article

• How to give new life into a five years old, simple but reliable PHP form?

  - by Sam

  Hi all. I have a script in php 5.2. I want to use a simple form. I found something a programmer made for me about 5 years ago. When I use it, PHP outputs an error now unless I set register_long_arrays = On, then it works fine. On the PHP website, however, it says: Warning This feature has been DEPRECATED as of PHP 5.3.0. Relying on this feature is highly discouraged. It's recommended to turn them off, for performance reasons. Instead, use the superglobal arrays, like $_GET. Should I listen to PHP's warning, or just enable the option and keep using my old form happily? If the former, then how/where do I change this simple form, so it does not rely on the deprecated setting? Your answer is much appreciated. form.htm <html><body> <form method="POST" action="form_sent.php"> ... </form> </body></html> form_sent.php <html><body> <?php $email = $HTTP_POST_VARS[email]; $mailto = "[email protected]"; $mailsubj = "A Form was Sent from Website!"; $mailhead = "From: $email\n"; reset ($HTTP_POST_VARS); $mailbody = "Values submitted from web site form:\n"; while (list($key, $val) = each ($HTTP_POST_VARS)){$mailbody .= "$key : $val\n";} if (!eregi("\n",$HTTP_POST_VARS[email])) { mail($mailto, $mailsubj, $mailbody, $mailhead); } ?> <b>Form Sent. Thank you.</b> </body></html>

  Read the article

• unique random id

  - by Piyush

  I am generating unique id for my small application but I am facing some variable scope problem. my code- function create_id() { global $myusername; $part1 = substr($myusername, 0, -4); $part2 = rand (99,99999); $part3 = date("s"); return $part1.$part2.$part3; } $id; $count=0; while($count == 1) { $id; $id=create_id(); $sqlcheck = "Select * FROM ruser WHERE userId='$id';"; $count =mysql_query($sqlcheck,$link)or die(mysql_error()); } echo $id; I dont know which variable I have to declare as global

  Read the article

• C++ - 3 possible values in Variable?

  - by noryb009

  I need to store a 30 letter combination, but each letter can only be "0", "1" or "2". When I use sizeof(myString), it returns 32. I want to use this 30 letter combination to access a row of an array, so I'm wondering if it is possible to use a 3 value bool of some sort to store 1 of 3 values in.

  Read the article

• Bash Color Variable Output

  - by drewrockshard

  I've got a variable, let's say $x and it holds the value of website.com. I want to be able to call the variable and apply shell color to it like so: echo -e '\033[1;32m$x:\033[0m'; The problem is not the color, however, it's how the script it interpretting the output. So the output I'm getting is: $x: I need the output to obviously be the string in the variable, and not the variable name. Is there any way around this issue?

  Read the article

• Java: global values inside a class?

  - by HH

  I want less methods. I want a common global TestClass from which I could use any of its value inside the class. import java.util.*; import java.io.*; public class TestClass { TestClass(String hello){ String hallo = hello; String halloSecond = "Saluto!"; } public static void main(String[] args) { TestClass test = new TestClass("Tjena!"); System.out.println("I want "Tjena!": " + test.hallo); TestClass testSecond = new TestClass("1"); System.out.println("I want Saluto!:" + test.halloSecond); System.out.println("I want Saluto!:" + testSecond.halloSecond); } }

  Read the article

• Exporting an Environment Variable in Ruby

  - by wilhelmtell

  How do I export an environment variable from within a Ruby script to the parent shell? For example, implementing a naïve implementation of the /usr/bin/read utility: #!/usr/bin/ruby varname = ARGV[0] ENV[varname] = STDIN.gets # but have varname exported to the parent process

  Read the article

• Variable not accessible within and if statment

  - by Chris

  I have a variable which holds a score for a game. My variable is accessible and correct outside of an if statement but not inside as shown below cout << score << endl; //works if(!justFinished){ cout << score << endl; // doesn't work prints a large negative number endTime = time(NULL); ifstream highscoreFile; highscoreFile.open("highscores.txt"); if(highscoreFile.good()){ highscoreFile.close(); }else{ std::ofstream outfile ("highscores.txt"); cout << score << endl; outfile << score << std::endl; outfile.close(); } justFinished = true; } cout << score << endl;//works

  Read the article

• How do I add an object to a binary tree based on the value of a member variable?

  - by Max

  How can I get a specific value from an object? I'm trying to get a value of an instance for eg. ListOfPpl newListOfPpl = new ListOfPpl(id, name, age); Object item = newListOfPpl; How can I get a value of name from an Object item?? Even if it is easy or does not interest you can anyone help me?? Edited: I was trying to build a binary tree contains the node of ListOfPpl, and need to sort it in the lexicographic. Here's my code for insertion on the node. Any clue?? public void insert(Object item){ Node current = root; Node follow = null; if(!isEmpty()){ root = new Node(item, null, null); return; }boolean left = false, right = false; while(current != null){ follow = current; left = false; right = false; //I need to compare and sort it if(item.compareTo(current.getFighter()) < 0){ current = current.getLeft(); left = true; }else { current = current.getRight(); right = true; } }if(left) follow.setLeft(new Node(item, null, null)); else follow.setRight(new Node(item, null, null)); }

  Read the article

• C++ reference variable again!!!

  - by kumar_m_kiran

  Hi All, I think most would be surprised about the topic again, However I am referring to a book "C++ Common Knowledge: Essential Intermediate Programming" written by "Stephen C. Dewhurst". In the book, he quotes a particular sentence (in section under Item 5. References Are Aliases, Not Pointers), which is as below A reference is an alias for an object that already exists prior to the initialization of the reference. Once a reference is initialized to refer to a particular object, it cannot later be made to refer to a different object; a reference is bound to its initializer for its whole lifetime Can anyone please explain the context of "cannot later be made to refer to a different object" Below code works for me, #include <iostream> using namespace std; int main(int argc, char *argv[]) { int i = 100; int& ref = i; cout<<ref<<endl; int k = 2000; ref = k; cout<<ref<<endl; return 0; } Here I am referring the variable ref to both i and j variable. And the code works perfectly fine. Am I missing something? I have used SUSE10 64bit linux for testing my sample program. Thanks for your input in advance.

  Read the article

• How can I use a value of JSP in Javascript code?

  - by novellino

  Hello, I have a list of elements, each of them appeared in my page through jsp. So I have this: <div id="title"><%= list.get(ind).getTitle() %></div> When I display the elements, as this tag is in for loop, I get everything right. Now I what to place a button for deleting each of this elements. What I have done is: <input type="submit" name="submit" onclick="deleteNewsFunction();" id="submit_btn"/> In the deleteNewsFunction() I just want to print the data. <script> function deleteNewsFunction(){ var item = $('#title').val(); alert(item); } </script> The problem is that the title var gets always the first item even if I am clicking on the button of the second item. I was thinking that maybe a solution is to add the "list.get(ind).getTitle()" as a parameter in the function like deleteNewsFunction(<%=list.get(ind).getTitle()%) but then it did not work at all. Does anyone know how to help me? Thanks a lot!

  Read the article

• Perl ENV variable contains newline and tab

  - by Michael

  Say I have an environment variable myvar myvar=\tapple\n when the following command will print out this variable perl -e 'print "$ENV{myvar}"' I will literally have \tapple\n, however, I want those control chars to be evaluated and not escaped. How would I achieve it? In the real world $ENV residing in substitution, but I hope the answer will cover that.

  Read the article

• Symfony: Pass an object from another module to a form

  - by djcloud23

  I have a symfony project and I have one model, which for this example I will name Boat. From the Boat's showSuccess page, I would like to make a link to another model's form page. For this example we will call it Ticket. When they click on the link, I would like for the Boat object to be passed to the Ticket form because I have to display some of that specific Boat's fields (title, price, etc) on the Ticket form page (newSuccess.php). I guess my question is, how do I pass an object (as a variable) to another model's "new" form page. I have looked everywhere and I can't seem to find an answer that works for me. Thank you!

  Read the article

< Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >