Search Results

Search found 5330 results on 214 pages for 'django auth'.

Page 79/214 | < Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >

  • Django IN query as a string result - invalid literal for int() with base 10

    - by bmelton
    Trying to query a 'Favorites' model to get a list of items a user has favorited, and then querying against a different model to get the objects back from that query to present to the template, but I'm getting an error: "invalid literal for int() with base 10" Looking over all of the other instances of that error, I couldn't find any in which the asker actually wanted to work with a comma separated list of integers, so I'm kind of at a loss. Model class Favorite(models.Model): # key should be the model name, id is the model.id, and user is the User object. key = models.CharField(max_length=255, unique=True) val = models.IntegerField(default=0) user = models.ForeignKey(User) class Admin: list_display = ('key', 'id', 'user') View def index(request): favorites = Favorite.objects.filter(key='blog', user=request.user.pk) values = "" for favorite in favorites: values += "%s," % favorite.val #values = "[%s]" % values blogs = Blog.objects.filter(pk__in=values) return render_to_response('favorite/index.html', { "favorites" : favorites, "blogs" : blogs, "values" : values, }, context_instance=RequestContext(request) ) enter code here

    Read the article

  • Multi choice form field in Django

    - by Dingo
    Hi! I'am developing application on app-engine-path. I would like to make form with multichoice (acceptably languages for user). Code look like this: Language settings: settings.LANGUAGES = ((u"cs", u"Ceština"), (u"en", u"English")) Form model: class UserForm(forms.ModelForm): first_name = forms.CharField(max_length=100) last_name = forms.CharField(max_length=100) languages = forms.MultipleChoiceField(widget=forms.CheckboxSelectMultiple, choices=settings.LANGUAGES) The form is rendered o.k. (all languages have checkbox. IDs, NAMEs is ok.) But if I save some languages for user, those languages don't check checkboxes. User model look like this class User(User): #... languages = db.StringListProperty() #... and view: def edit_profile(request): user = request.user if request.method == 'POST': form = UserForm(request.POST) if form.is_valid(): # ... else: form = UserForm(instance=user) data = {"user":user, "form": form} return render_to_response(request, 'user_profile/user_profile.html', data)

    Read the article

  • django: grouping in an order_by query?

    - by AP257
    Hi all, I want to allocate rankings to users, based on a points field. Easy enough you'd think with an order_by query. But how do I deal with the situation where two users have the same number of points and need to share the same ranking? Should I use annotate to find users with the same number of points? My current code, and a pseudocode description of what I'd like to do, are below. top_users = User.objects.filter(problem_user=False).order_by('-points_total') # Wrong - in pseudocode, this should be # Get the highest points_total, find all the users with that points_total, # if there is more than one user, set status to 'Joint first prize', # otherwise set status to 'First prize' top_users[0].status = "First prize" if (top_users[1]): top_users[1].status = "Second prize" if (top_users[2]): top_users[2].status = "Third prize" if (top_users[3]): top_users[3:].status = "Highly commended" The code above doesn't deal with the situation where two users have the same number of points and need to share second prize. I guess I need to create a query that looks for unique values of points_total, and does some kind of nested ranking? It also doesn't cope with the fact that sometimes there are fewer than 4 users - does anyone know how I can do (in pseudocode) 'if top_users[1] is not null...' in Python?

    Read the article

  • Django TestCase testing order

    - by ziang
    If there are several methods in the test class, I found that the order to execute is alphabetical. But I want to customize the order of execution. How to define the execution order? For example: testTestA will be loaded first than testTestB. class Test(TestCase): def setUp(self): ... def testTestB(self): #test code def testTestA(self): #test code

    Read the article

  • Django select max id

    - by pistacchio
    Hi, given a standard model (called Image) with an autoset 'id', how do I get the max id? So far I've tried: max_id = Image.objects.all().aggregate(Max('id')) but I get a 'id__max' Key error. Trying max_id = Image.objects.order_by('id')[0].id gives a 'argument 2 to map() must support iteration' exception Any help?

    Read the article

  • Django Cannot set values on a ManyToManyField which specifies an intermediary model

    - by dana
    i am using a m2m and a through table, and when i was trying to save, my error was: Cannot set values on a ManyToManyField which specifies an intermediary model so, i've modified my code, so that when i save the form, to insert data into the 'through' table too.But now, i'm having another error. (i've bolded the lines where i think i am wrong) i have in models.py: class Classroom(models.Model): user = models.ForeignKey(User, related_name = 'classroom_creator') classname = models.CharField(max_length=140, unique = True) date = models.DateTimeField(auto_now=True) open_class = models.BooleanField(default=True) members = models.ManyToManyField(User,related_name="list of invited members", through = 'Membership') class Membership(models.Model): accept = models.BooleanField(User) date = models.DateTimeField(auto_now = True) classroom = models.ForeignKey(Classroom, related_name = 'classroom_membership') member = models.ForeignKey(User, related_name = 'user_membership') and in def save_classroom(request): if request.method == 'POST': form = ClassroomForm(request.POST, request.FILES, user = request.user) **classroom_instance = Classroom member_instance = Membership** if form.is_valid(): new_obj = form.save(commit=False) new_obj.user = request.user r = Relations.objects.filter(initiated_by = request.user) membership = Membership.objects.create(**classroom = classroom_instance, member = member_instance,date=datetime.datetime.now())** new_obj.save() form.save_m2m() return HttpResponseRedirect('/classroom/classroom_view/{{user}}/') else: form = ClassroomForm(user = request.user) return render_to_response('classroom/classroom_form.html', { 'form': form, }, context_instance=RequestContext(request)) but i don't seem to initialise okay the classroom_instance and menber_instance.My error os: Cannot assign "": "Membership.classroom" must be a "Classroom" instance. Thanks!

    Read the article

  • Trying to Nullify Django model fields with method where model and fields are parameters

    - by Johnny4000
    I'm trying to write a method like the below where a list of fields (a subset of all the fields) is passed in as a parameter and has their column values set to null. I would be happy of I could get a method with just the fields as a parameter like below, but having the model as a parameter would be even better. from my_project.my_app.models import MyModel def nullify_columns (self, null_fields): field_names = MyModel._meta.get_all_field_names() for field in field_names: if field in null_fields: # The below line does not work because I'm not sure how to # dynamically assign the field name. MyModel.objects.all().update( (MyModel.get_field(field).column) = None) Right now I have something like if 'column1' in list_of_fields: MyModel.objects.all().update(column1 = None) if 'column2' in list_of_fields: MyModel.objects.all().update(column2 = None) etc. which is horrible, but works.

    Read the article

  • Modify Django settings variables in a middleware

    - by jack
    I set a variable MAX_REQUEST = 100 in settings.py I write a middleware which may lower this value for request origining from a proxy ip address by the following code: settings.MAX_REQUEST = 10 However, looks like the above modification affects all legitimate users. Is it normal?

    Read the article

  • django manual login and redirect

    - by Zayatzz
    Hello I have such view that handles user registration. After creating new user i want to manually authenticate it and log it in.: def register(request): ... ... if form.is_valid(): username = form.cleaned_data['username'] password = form.cleaned_data['password1'] email = '' newuser = User.objects.create_user(username, email, password) user = authenticate(username=username, password=password) login (request, user) I have set LOGIN_REDIRECT_URL to '/profile/', but after authenticating and logging user in, it redirects me back to the same view not to /profile/, why? And how can i specify where to redirect after logging in? If i add HttpResponseRedirect('/profile/') After login line - nothing happens. The script never ends up there. Alan.

    Read the article

  • how to write re-usable views in django?

    - by rz
    These are the techniques that I use regularly to make my views reusable: take the template_name as an argument with a default take an optional extra_context which defaults to empty {} right before the template is rendered the context is updated with the extra_context for further re-usability, call any callable in extra_context.values() whenever the view deals with a queryset, there is a queryset argument with a default whenever the view needs a particular object from the ORM, it attempts to fetch it using any "id" parameter in several ways (e.g. as a slug, as a database id) (this may be a bad practice...) First, Should I add anything to my list? Should I remove anything from my list? The items accommodates a large number of cases. However, whenever an app extends a model of another in some way (e.g. adding a field or changing the behavior in some way) I end up writing my own views and only reusing the model. Is this normal?

    Read the article

  • django media url is not resolved in 500 internal server error template

    - by Tom Tom
    Hi, I'm using a 500.html template for my app, which is an identical copy of the 404.html with some minor text changes. Interestingly the {{ media_url }} context variable will not be resolved by the server if the 500.html is presented (e.g. when I force an internal server error), resulting in a page without any css loaded. An easy way to circumvent this would be to hardcode the links to the css, but I m just curious why the media_url is not resolved. Probably it is because the server encounters a internal server error and that leads to context variables not any more available!?

    Read the article

  • Django equivalent for latest entry for each user

    - by paul-ogrady
    Hi, I'm surprised this question hasn't come up. Couldn't find much on the web. Using Entry.objects.latest('created_at') I can recover the latest entry for all Entry objects, but say if I want the latest entry for each user? This is something similar to an SQL latest record query. But how do I achieve this using the ORM? Here is my approach I'm wondering if it is the most efficient way to do what I want. First I perform a sub query: Objects are grouped by user and the Max (latest) created_by field is returned for each user (created_at__max) I then filter Entry objects based on the results in the subquery and get the required objects. Entry.objects.filter(created_at__in=Entry.objects.values('user').annotate(Max('created_at')).values_list('created_at__max')) or using a manager: class UsersLatest(models.Manager): def get_query_set(self): return Super(UsersLatest,self).get_query_set().filter(created_at__in=self.model.objects.values('user').annotate(Max('created_at')).values_list('created_at__max')) Is there a more efficient way? possibly without sub query? Thanks, Paul

    Read the article

  • Django: Named URLs / Same Template, Different Named URL

    - by TheLizardKing
    I have a webapp that lists all of my artists, albums and songs when the appropriate link is clicked. I make extensive use of generic views (object_list/detail) and named urls but I am coming across an annoyance. I have three templates that pretty much output the exact same html that look just like this: {% extends "base.html" %} {% block content %} <div id="content"> <ul id="starts-with"> {% for starts_with in starts_with_list %} <li><a href="{% url song_list_x starts_with %}">{{ starts_with|upper }}</a></li> {% endfor %} </ul> <ul> {% for song in songs_list %} <li>{{ song.title }}</li> {% endfor %} </ul> </div> {% endblock content %} My artist and album template look pretty much the same and I'd like to combine the three template's into one. The fact that my variables start with song can easily be changed to the default obj. It's my <ul id="starts-with"> named url I don't know how to correct. Obviously I want it to link to a specific album/artist/song using the named urls in my urls.py but I don't know how to make it context aware. Any suggestions? urlpatterns = patterns('tlkmusic.apps.tlkmusic_base.views', # (r'^$', index), url(r'^artists/$', artist_list, name='artist_list'), url(r'^artists/(?P<starts_with>\w)/$', artist_list, name='artist_list_x'), url(r'^artist/(?P<artist_id>\d+)/$', artist_detail, name='artist_detail'), url(r'^albums/$', album_list, name='album_list'), url(r'^albums/(?P<starts_with>\w)/$', album_list, name='album_list_x'), url(r'^songs/$', song_list, name='song_list'), url(r'^songs/(?P<starts_with>\w)/$', song_list, name='song_list_x'), )

    Read the article

  • Django: test failing on a view with @login_required

    - by Esteban Feldman
    Hi all, I'm trying to build a test for a view that's decorated with @login_required, since I failed to make it work, I did a simple test and still can't make it pass. Here is the code for the simple test and the view: def test_login(self): user = self._create_new_user() self.assertTrue(user.is_active) login = self.client.login(username=user.username, password=self.data['password1']) self.failUnless(login, 'Could not log in') response = self.client.get('/accounts/testlogin/') self.assertEqual(response.status_code, 200) @login_required def testlogin(request): print 'testlogin !! ' return HttpResponse('OK') _create_new_user() is saving the user and there is a test inside that method to see that is working. The test fails in the response.status_code, returning 302 and the response instance is of a HttpResponseRedirect, is redirecting it as if not logged in. Any clue? I'm missing something? Regards Esteban

    Read the article

  • Django blog reply system

    - by dana
    hello, i'm trying to build a mini reply system, based on the user's posts on a mini blog. Every post has a link named reply. if one presses reply, the reply form appears, and one edits the reply, and submits the form.The problem is that i don't know how to take the id of the post i want to reply to. In the view, if i use as a parameter one number (as an id of the blog post),it inserts the reply to the database. But how can i do it by not hardcoding? The view is: def save_reply(request): if request.method == 'POST': form = ReplyForm(request.POST) if form.is_valid(): new_obj = form.save(commit=False) new_obj.creator = request.user new_post = New(1) #it works only hardcoded new_obj.reply_to = new_post new_obj.save() return HttpResponseRedirect('.') else: form = ReplyForm() return render_to_response('replies/replies.html', { 'form': form, }, context_instance=RequestContext(request)) i have in forms.py: class ReplyForm(ModelForm): class Meta: model = Reply fields = ['reply'] and in models: class Reply(models.Model): reply_to = models.ForeignKey(New) creator = models.ForeignKey(User) reply = models.CharField(max_length=140,blank=False) objects = NewManager() mentioning that New is the micro blog class thanks

    Read the article

  • Django LFS - custom views

    - by owca
    For all those ligthning fast shop users. I'm trying to implement my own first page view that will list all products from shop ( under '/' address). So I have a template : {% extends "lfs/shop/shop_base.html" %} {% block content %} <div id="najnowsze_produkty"> <ul> {% for obj in objects %} <li> {{ obj.name }} </li> {% endfor %} </ul> </div> {% endblock %} and then I've edited main shop view : from lfs.catalog.models import Category from lfs.catalog.models import Product def shop_view(request, template_name="lfs/shop/shop.html"): products = Product.objects.all() shop = lfs_get_object_or_404(Shop, pk=1) return render_to_response(template_name, RequestContext(request, { "shop" : shop, "products" : products })) but it just shows nothing. When I do Product.objects.all() query in shell I get results. Any ideas what could cause the problem ? Maybe I should filter products with 'active' status only ? But I'm not sure if it can influence all objects in any way.

    Read the article

  • Django openid authentication with google

    - by Zayatzz
    Hello I am looking into authenticating via google. I dont understand how it works:http://code.google.com/apis/accounts/docs/OpenID.html#Samples If i do that 2nd request by entering the data as one url with params into browser i get back XML file. Should i not get back sample response nr3? Can somebody explain this to me? The problem is, that im trying to sort through some third party app that uses google openid authentication and its not recieving authenticated users e-mail back, like in sample response 3. Alan PS i have read through similar questions and their responses and gone through pages like: http://stackoverflow.com/questions/353880/how-does-openid-authentication-works http://www.windley.com/archives/2006/04/how_does_openid.shtml http://tinisles.blogspot.com/2008/02/how-does-openid-work.html http://openid.net/pres/protocolflow-1.1.png etc..

    Read the article

  • Django template not loading properly

    - by fmsf
    Hey, When this one runs everything goes fine: (r"^newobject$", "views.myobjects.newobject"), All the CSS + JS files are properly fetched from: static/css/... static/js/... When this one runs: (r"^mybjects/(([a-z]|[A-Z]|[0-9])+)$","views.myobjects.loadobject"), All the css and JS files that are being fetched, are run trough the urlpatterns and are returning my defailt page: (r"", 'views.main.index'), This makes all my CSS and JS code to actualy be HTML. My guess is that i'm giving some noob mistake. Is there any common reason why this should happen? And how to fix it?

    Read the article

  • Django/Python best practice template_dict

    - by fredrik
    Hi, After just been coding for about 6-9 months. I probably changed my coding style a number of times after reading some code or read best practices. But one thing I haven't yet come a cross is a good why to populate the template_dict. As of now I pass the template_dict across a number of methods (that changes/modifies it) and returns is. The result is that every methods takes template_dict as first argument and the returns it and this in my eyes doesn't seems to be the best solution. An idea is to have a method that handles all the changes. But I'm curios if there's a best practice for this? Or is it "do what you feel like"-type of thing? The 2 things I think is pretty ugly is to send as an argument and return it in all methods. And the just the var name is written xxx number of times in the code :) ..fredrik

    Read the article

  • add text to the choice_label of ChoiceField in Django

    - by pablo
    The ChoiceField creates a select html element and the options show the choice_label which is the _unicode_ of each model object. How can I change the text of the choice_label without modifying _unicode_ ? I have a Product model and I want to show in the options text the product name + price + link to edit. I've searched in fields.py and widgets.py but couldn't find what needed to be changed. Thanks

    Read the article

  • ForeignKey django 1.1.1 model

    - by Spikie
    i have class staff_name(models.Model): firstname = models.CharField(max_length=150) surname = models.CharField(max_length=150) class inventory_transaction(models.Model): staffs = models.ForeignKey(staff_name) i want to get or create staff surname and first name through inventory_transaction i used these code below inventory_transaction.objects.get_or_create(staffs_surname_contains=sname,staffs_firstname_contains=fname) i got this error "staffs_surname_contains can not be defined" what have i done wrong ? thanks

    Read the article

< Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >