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  • Migration for creating and deleting model in South

    - by Almad
    I've created a model and created initial migration for it: db.create_table('tvguide_tvguide', ( ('id', models.AutoField(primary_key=True)), ('date', models.DateField(_('Date'), auto_now=True, db_index=True)), )) db.send_create_signal('tvguide', ['TVGuide']) models = { 'tvguide.tvguide': { 'channels': ('models.ManyToManyField', ["orm['tvguide.Channel']"], {'through': "'ChannelInTVGuide'"}), 'date': ('models.DateField', ["_('Date')"], {'auto_now': 'True', 'db_index': 'True'}), 'id': ('models.AutoField', [], {'primary_key': 'True'}) } } complete_apps = ['tvguide'] Now, I'd like to drop it: db.drop_table('tvguide_tvguide') However, I have also deleted corresponding model. South (at least 0.6.2) is however trying to access it: (venv)[almad@eva-03 project]$ ./manage.py migrate tvguide Running migrations for tvguide: - Migrating forwards to 0002_removemodels. > tvguide: 0001_initial Traceback (most recent call last): File "./manage.py", line 27, in <module> execute_from_command_line() File "/usr/lib/python2.6/site-packages/django/core/management/__init__.py", line 353, in execute_from_command_line utility.execute() File "/usr/lib/python2.6/site-packages/django/core/management/__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/usr/lib/python2.6/site-packages/django/core/management/base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/usr/lib/python2.6/site-packages/django/core/management/base.py", line 222, in execute output = self.handle(*args, **options) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/management/commands/migrate.py", line 91, in handle skip = skip, File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 581, in migrate_app result = run_forwards(mapp, [mname], fake=fake, db_dry_run=db_dry_run, verbosity=verbosity) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 388, in run_forwards verbosity = verbosity, File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 287, in run_migrations orm = klass.orm File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 62, in __get__ self.orm = FakeORM(*self._args) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 45, in FakeORM _orm_cache[args] = _FakeORM(*args) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 106, in __init__ self.models[name] = self.make_model(app_name, model_name, data) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 307, in make_model tuple(map(ask_for_it_by_name, bases)), File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/utils.py", line 23, in ask_for_it_by_name ask_for_it_by_name.cache[name] = _ask_for_it_by_name(name) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/utils.py", line 17, in _ask_for_it_by_name return getattr(module, bits[-1]) AttributeError: 'module' object has no attribute 'TVGuide' Is there a way around?

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  • Azure Full trust permissions

    - by kaleidoscope
    Under Windows Azure full trust, your role has access to a variety of system resources that are not available under partial trust File System Resources A role running in Windows Azure has permissions to read and write to certain file, directory, and volume resources on the server. These permissions are outlined in the following table.  File system resource Permission System root directory No access Subdirectories of the system root directory No access Windows directory Read access only Machine configuration files No access Service configuration file Read access only Local storage resource Full access Registry Resources The following table outlines permissions available to the role when accessing the registry while running in Windows Azure. HKEY_CLASSES_ROOT Read access HKEY_CURRENT_USER No access HKEY_LOCAL_MACHINE Read access HKEY_USERS Read access HKEY_CURRENT_CONFIG Read access More details can be found at: http://msdn.microsoft.com/en-us/library/dd573363.aspx   Amit, S

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  • How to Restrict Android App Permissions

    - by Chris Hoffman
    Android forces you to agree to every permission an app wants, assuming you want to use the app. After rooting your device, you can manage permissions on a per-app basis. Restricting permissions allows you to protect your contacts and other private data from apps that demand access you’d rather not allow. Many apps will continue working properly after you revoke the permissions. HTG Explains: What Is RSS and How Can I Benefit From Using It? HTG Explains: Why You Only Have to Wipe a Disk Once to Erase It HTG Explains: Learn How Websites Are Tracking You Online

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  • installed openstack using devstack install shell script but getting 500 error when i try opening dashboard

    - by Arvind
    I followed the instructions at http://devstack.org/guides/single-machine.html to install OpenStack. I first installed Ubuntu on my Windows 7 PC using the officially supported Windows installer for Ubuntu 12.04 LTS. And after that I followed the instructions at above page to install OpenStack. As per instructions, I should be able to access the dashboard aka Horizon, at http://192.168.1.4/ (thats the IP of the PC on which I installed Ubuntu-OpenStack). However I am getting a 500 error web page when I open that. How do I resolve this error? I want to set up a dev environment for OpenStack. For your ref, the whole error message is given now-- FilterError at / /usr/bin/env: node: No such file or directory Request Method: GET Request URL: http://192.168.1.4/ Django Version: 1.4.2 Exception Type: FilterError Exception Value: /usr/bin/env: node: No such file or directory Exception Location: /usr/local/lib/python2.7/dist-packages/compressor/filters/base.py in input, line 133 Python Executable: /usr/bin/python Python Version: 2.7.3 Python Path: ['/opt/stack/horizon/openstack_dashboard/wsgi/../..', '/opt/stack/python-keystoneclient', '/opt/stack/python-novaclient', '/opt/stack/python-openstackclient', '/opt/stack/keystone', '/opt/stack/glance', '/opt/stack/python-glanceclient/setuptools_git-0.4.2-py2.7.egg', '/opt/stack/python-glanceclient', '/opt/stack/nova', '/opt/stack/horizon', '/opt/stack/cinder', '/opt/stack/python-cinderclient', '/usr/local/lib/python2.7/dist-packages', '/usr/lib/python2.7', '/usr/lib/python2.7/plat-linux2', '/usr/lib/python2.7/lib-tk', '/usr/lib/python2.7/lib-old', '/usr/lib/python2.7/lib-dynload', '/usr/lib/python2.7/dist-packages', '/usr/lib/python2.7/dist-packages/PIL', '/usr/lib/python2.7/dist-packages/gst-0.10', '/usr/lib/python2.7/dist-packages/gtk-2.0', '/usr/lib/pymodules/python2.7', '/usr/lib/python2.7/dist-packages/ubuntu-sso-client', '/usr/lib/python2.7/dist-packages/ubuntuone-client', '/usr/lib/python2.7/dist-packages/ubuntuone-control-panel', '/usr/lib/python2.7/dist-packages/ubuntuone-couch', '/usr/lib/python2.7/dist-packages/ubuntuone-storage-protocol', '/opt/stack/horizon/openstack_dashboard'] Server time: Sat, 27 Oct 2012 08:43:29 +0000 Error during template rendering In template /opt/stack/horizon/openstack_dashboard/templates/_stylesheets.html, error at line 3 /usr/bin/env: node: No such file or directory 1 {% load compress %} 2 3 {% compress css %} 4 <link href='{{ STATIC_URL }}dashboard/less/horizon.less' type='text/less' media='screen' rel='stylesheet' /> 5 {% endcompress %} 6 7 <link rel="shortcut icon" href="{{ STATIC_URL }}dashboard/img/favicon.ico"/> 8 Also, the traceback is now given below-- Environment: Request Method: GET Request URL: http://192.168.1.4/ Django Version: 1.4.2 Python Version: 2.7.3 Installed Applications: ('openstack_dashboard', 'django.contrib.contenttypes', 'django.contrib.auth', 'django.contrib.sessions', 'django.contrib.messages', 'django.contrib.staticfiles', 'django.contrib.humanize', 'compressor', 'horizon', 'openstack_dashboard.dashboards.project', 'openstack_dashboard.dashboards.admin', 'openstack_dashboard.dashboards.settings', 'openstack_auth') Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.middleware.csrf.CsrfViewMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', 'horizon.middleware.HorizonMiddleware', 'django.middleware.doc.XViewMiddleware', 'django.middleware.locale.LocaleMiddleware') Template error: In template /opt/stack/horizon/openstack_dashboard/templates/_stylesheets.html, error at line 3 /usr/bin/env: node: No such file or directory 1 : {% load compress %} 2 : 3 : {% compress css %} 4 : <link href='{{ STATIC_URL }}dashboard/less/horizon.less' type='text/less' media='screen' rel='stylesheet' /> 5 : {% endcompress %} 6 : 7 : <link rel="shortcut icon" href="{{ STATIC_URL }}dashboard/img/favicon.ico"/> 8 : Traceback: File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py" in get_response 111. response = callback(request, *callback_args, **callback_kwargs) File "/usr/local/lib/python2.7/dist-packages/django/views/decorators/vary.py" in inner_func 36. response = func(*args, **kwargs) File "/opt/stack/horizon/openstack_dashboard/wsgi/../../openstack_dashboard/views.py" in splash 38. return shortcuts.render(request, 'splash.html', {'form': form}) File "/usr/local/lib/python2.7/dist-packages/django/shortcuts/__init__.py" in render 44. return HttpResponse(loader.render_to_string(*args, **kwargs), File "/usr/local/lib/python2.7/dist-packages/django/template/loader.py" in render_to_string 176. return t.render(context_instance) File "/usr/local/lib/python2.7/dist-packages/django/template/base.py" in render 140. return self._render(context) File "/usr/local/lib/python2.7/dist-packages/django/template/base.py" in _render 134. return self.nodelist.render(context) File "/usr/local/lib/python2.7/dist-packages/django/template/base.py" in render 823. bit = self.render_node(node, context) File "/usr/local/lib/python2.7/dist-packages/django/template/debug.py" in render_node 74. return node.render(context) File "/usr/local/lib/python2.7/dist-packages/django/template/loader_tags.py" in render 155. return self.render_template(self.template, context) File "/usr/local/lib/python2.7/dist-packages/django/template/loader_tags.py" in render_template 137. output = template.render(context) File "/usr/local/lib/python2.7/dist-packages/django/template/base.py" in render 140. return self._render(context) File "/usr/local/lib/python2.7/dist-packages/django/template/base.py" in _render 134. return self.nodelist.render(context) File "/usr/local/lib/python2.7/dist-packages/django/template/base.py" in render 823. bit = self.render_node(node, context) File "/usr/local/lib/python2.7/dist-packages/django/template/debug.py" in render_node 74. return node.render(context) File "/usr/local/lib/python2.7/dist-packages/compressor/templatetags/compress.py" in render 147. return self.render_compressed(context, self.kind, self.mode, forced=forced) File "/usr/local/lib/python2.7/dist-packages/compressor/templatetags/compress.py" in render_compressed 107. rendered_output = self.render_output(compressor, mode, forced=forced) File "/usr/local/lib/python2.7/dist-packages/compressor/templatetags/compress.py" in render_output 119. return compressor.output(mode, forced=forced) File "/usr/local/lib/python2.7/dist-packages/compressor/css.py" in output 51. ret.append(subnode.output(*args, **kwargs)) File "/usr/local/lib/python2.7/dist-packages/compressor/css.py" in output 53. return super(CssCompressor, self).output(*args, **kwargs) File "/usr/local/lib/python2.7/dist-packages/compressor/base.py" in output 230. content = self.filter_input(forced) File "/usr/local/lib/python2.7/dist-packages/compressor/base.py" in filter_input 192. for hunk in self.hunks(forced): File "/usr/local/lib/python2.7/dist-packages/compressor/base.py" in hunks 167. precompiled, value = self.precompile(value, **options) File "/usr/local/lib/python2.7/dist-packages/compressor/base.py" in precompile 210. command=command, filename=filename).input(**kwargs) File "/usr/local/lib/python2.7/dist-packages/compressor/filters/base.py" in input 133. raise FilterError(err) Exception Type: FilterError at / Exception Value: /usr/bin/env: node: No such file or directory

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  • ASP.NET Where can I write to without modifying permissions?

    - by LeeW
    Where can I write to without modifying site permissions? I need to store a value on the server that will remain when all sessions have closed and can be re-read when a new session is started. I need to make sure that no site permissions need to be changed so the location can be written to by anonymous users and any authenticated user. Does such a place exist? Thanks Lee

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  • Can you set SQL Server permissions from a Silverlight app?

    - by Paul Smith
    Is it possible to create a Silverlight application which can be used to provide a nice user interface for managing SQL Server permissions? We want to create a simple admin app to allow certain users to create new users, disable old users, and manage specific permissions for those users, but we feel that SQL Server Management Studio is perhaps too complex.

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  • [Django] Change state of obiects

    - by gameboy
    hi I have following problem. I have model: class Towar(models.Model): nrSeryjny=models.CharField(max_length=100) opis=models.CharField(max_length=255) naStanie=models.NullBooleanField(null=True) def __unicode__(self): return "%s" % self.opis def lowerName(self): return self.__class__.__name__.lower() def checkState(self): return self.naStanie def changeState(self,state): self.naStanie=state class Meta: ordering=['nrSeryjny'] app_label = 'baza' permissions=(("view_towar","mozna miec podglad dla towar"),) and model : class Wypozyczenie(models.Model): dataPobrania=models.DateField() pracownik=models.ForeignKey(User,null=True) kontrahent=models.ForeignKey(Kontrahenci,null=True) towar=models.ForeignKey(Towar,null=True) objects=WypozyczenieManager() default_objects=models.Manager() ZwrotyObjects=WypozyczenieZwrotyManager() def lowerName(self): return self.__class__.__name__.lower() def __unicode__(self): if self.towar == None: return "Dla:%s -- Kto:%s -- Kiedy:%s -- Co:%s" % (self.kontrahent,self.pracownik,self.dataPobrania,"Brak") else: return "Dla:%s -- Kto:%s -- Kiedy:%s -- Co:%s" % (self.kontrahent,self.pracownik,self.dataPobrania,self.towar) class Meta: ordering=['dataPobrania'] app_label = 'baza' permissions=(("view_wypozyczenie","mozna miec podglad dla wypozyczenie"),) and view to adding models: def modelAdd(request,model,modelForm): mod=model() if request.user.has_perm('baza.add_%s' % mod.lowerName()): if request.method=='POST': form=modelForm(request.POST) if form.is_valid(): form.save() return HttpResponseRedirect('/'+ mod.lowerName() + '/') else: form=modelForm() v=RequestContext(request,{'form':form}) return render_to_response('add_form.html',v) and i whant do that, when i add Wypozyczenie and save it then the Towar that is stored by Wypozyczenie change his na stanie from True to False Greets

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  • Good and easy way to share files on local machine

    - by jb
    I would like to have a directory that has following properties: Many users can copy files into it These files can be deleted/changed by these users (user A can delete/modify file that was copied into this directory) it cant be done using normal file permissions (because permissions are retained on copy). Here is what I found on the net: brainstorm idea blueprint Some use cases: Sharing music on local machine Simple git repository sharing (just make a bare repository writeable to many people) --- i know that there are solutions like gitosis Allow many developers to modify test instance of php app without giving them root (i guess they would copy files) --- I'm leading a team of nonprofit junior developers and I need to keep that one simple! EDIT AFAIK setting SGID bit is not enugh, it only affects newly created files --- and basic workflow for these use cases ivnolves copying and other operations (which cleave file's gid unchanged)

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  • Ubuntu sudo not working

    - by Ron Sebastian
    I wanted to move a file to a /usr/python2.7/ but i was unable to do so, so i changed the permissions of /usr to myuser: sudo chown -R ***** /usr it worked but i realised it was a blunder when sudo stopped working after that. It says: sudo: effective uid is not 0, is sudo installed setuid root? I have seen this post where the accepted solution was to use the policykit: pkexec chown root:root /usr/bin/sudo pkexec chmod 4755 /usr/bin/sudo however, even the policykit is saying that: pkexec must be setuid root please help, i've learned a lesson and will never change permissions for /usr again. Please help me this time!

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  • What is the default permission for /var/www?

    - by itsols
    After upgrading to 12.04, I had to reinstall the LAMP stack. Then I brought all my www project folders from a pen drive to the /var/www folder (using sudo nautilus, and dragging the files in there). Now I cannot make any changes to the files/directories within /var/www. Perhaps this changed with the backup copies I dragged in there. I'd like to know what the default permissions for the /var/www folder are. I don't want to just change the permissions and make my system abnormal and working. Rather I'd like to get it to the correct state that is meant to work.

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  • Unable to login following permission changes in device manager (11.10 + Gnome)

    - by Symanuk
    (Running Gnome 3 on Ubuntu 11.10) Everything working well (at least a couple of months), until recently when I changed the permissions through the device manager on the sda1 /2/ 3 drives, thinking it would save all the switching I seem to have to do between users in order to see / use files I previously copied across from an external drive. Now when I boot up the Ubuntu splash screen loads indefinitely, and if I go in through the GRUB / recover option, i'm getting a load of negative permission messages back (regardless of using the fsck or remount options) Either way = unusable machine (Laptop Dell Inspiron n5050), and no way through to login. I'm looking for: (1) a way back in so any help greatfully received (answers need to be pretty basic as i'm a novice), and (2) if i'm to learn anything, a decent thread on setting permissions within Ubuntu / Gnome 3. I'm new to both Ubuntu & Linux, so please be gentle!! Cheers

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  • New HDD formating on Ext4 root permission

    - by Carlos Salmeron
    OK people good evening, I have this new 80Gb HDD I want to use it as a backup storage for my actual system (14.04) not a server. I formatted it with Gpart but I just can't write in it, when I search for permissions it tells me that only root users can write/create in it, log on as root user and try to change permissions, and I can't do that either. Long have I searched for an answer, looking everywhere but not to find any, is there a way to format it and use it with my user permission? Don't want it on NTFS, is there a way?, I have searched in these forums but there’s only an answer to format it in NTFS, so please. Thank you in advance.

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  • how do i stop root from running a program

    - by joe Lovick
    I would like to prevent my root user from running certain applications that can change the permissions of files which in turn prevents normal users from running those applications again. for example, if i sudo to root, and then run thunderbird from the command prompt, it changes the permissions of files within my home dir / profile so i can no longer run it as a normal user; what i would like to do is prevent root from running thunderbird and hence stop this user error from repeating itself. any suggestions? to clarify, if i have a lot of administration to do i use "sudo -s" which gives me a root shell, its just once a year or so, i shoot myself in the foot.

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  • What should be the correct ownership of /tmp /var /usr and subdirectories?

    - by sbergeron
    For some reason I think the permissions of those were messed up from a small amount of disk corruption I had. This may be a dupe, I don't know but I googled it and didn't find any mention of it. I need to know how the permissions of them should be set up as currently my computer can't actually use the tmp directory and I can't download anything consequently. I have access to the recovery mode command line but while in sudo user prompts it doesn't seem to work correctly. Also something is wrong with package management and I get dpkg: error: unable to access dpkg status area: read-only file system. I know my system is really messed up but I don't want to have to reinstall AGAIN.

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  • Setting folder permission so it isn't deletable, but everything else is allowed

    - by user10324
    I want to set permissions to a folder such that, when I'm normally logged in (meaning not as root), this folder isn't deletable, but I can still change the name of this folder and move in around in my system ? IS this possible and if yes, how to set the permission ? I already tried different combinations for the permissions but couldn't figure out how to do it. Also (side question), if some folder hast some permission set and I copy this folder, along with its contents (assuming I am allowed to read it) to a memory, are these permission preserved ? I suppose not, since under Windows I could delete the folder on the stick, even if under Ubuntu it isn't allowed to delete it...

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  • how to import csv data into django models

    - by little_fish
    i have some csv data and i want to export into django models the example of csv data 1;"02-01-101101";"Worm Gear HRF 50";"Ratio 1 : 10";"input shaft, output shaft, direction A, color dark green"; 2;"02-01-101102";"Worm Gear HRF 50";"Ratio 1 : 20";"input shaft, output shaft, direction A, color dark green"; 3;"02-01-101103";"Worm Gear HRF 50";"Ratio 1 : 30";"input shaft, output shaft, direction A, color dark green"; 4;"02-01-101104";"Worm Gear HRF 50";"Ratio 1 : 40";"input shaft, output shaft, direction A, color dark green"; 5;"02-01-101105";"Worm Gear HRF 50";"Ratio 1 : 50";"input shaft, output shaft, direction A, color dark green"; and i have some django models name Product in Product there is some fields like name, description and price and i want to something like this product=Product() product.name = "Worm Gear HRF 70(02-01-101116)" product.description = "input shaft, output shaft, direction A, color dark green" product.price = 100

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  • nginx serving Django static media | 502 bad gateway

    - by MMRUser
    I'm trying to serve Django static media through nginx, Here's my nginx.conf server { listen 7777; listen localhost:7777; server_name example.com; location / { proxy_pass http://localhost:7777; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffer_size 4k; proxy_buffers 4 32k; proxy_busy_buffers_size 64k; proxy_temp_file_write_size 64k; } location /test-app-media/ { root /sites/mysite/staticmedia/; expires max; } } but give a 502 bad gateway error, the path to /sites/mysite/staticmedia/ is in the nginx root/ is that the problem.. Django running on Apache 2.2 + mod_wsgi nginx 0.7.65 Thanks..

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  • Django queryset not returning the same values as the generated sql

    - by HRCerqueira
    Hello guys, I have the following queryset: subscribers = User.objects.values('email', 'username').filter( Q(subscription_settings__new_question='i') | Q(subscription_settings__new_question_watched_tags='i', marked_tags__id__in=question.tags.values('id'), tag_selections__reason='good') ).exclude(id=question.author.id) The problem is that when I evaluate the query I get only the values that are filtered by the first Q object (even if I reverse the order of the objects). So lets say that I was expecting the user A, B, C and D, where A and B are filtered by the first Q object and C and D by the second. But the queryset only returns A and B. I used the django debug toolbar to see the query that was actually being executed (and then I used a direct print statement like "print subscriber.query.as_sql()" just to be sure) and then evaluated the query directly using psql (I'm using postgres by the way), and I get the results I expect. Here's the query btw: SELECT "auth_user"."email", "auth_user"."username" FROM "auth_user" LEFT OUTER JOIN "forum_markedtag" ON ("auth_user"."id" = "forum_markedtag"."user_id") INNER JOIN "forum_defaultsubscriptionsetting" ON ("auth_user"."id" = "forum_defaultsubscriptionsetting"."user_id") WHERE ((("forum_markedtag"."reason" = E'good' AND "forum_defaultsubscriptionsetting"."new_question_watched_tags" = E'i' AND "forum_markedtag"."tag_id" IN (SELECT U0."id" FROM "tag" U0 INNER JOIN "question_tags" U1 ON (U0."id" = U1."tag_id") WHERE U1."question_id" = 64 )) OR "forum_defaultsubscriptionsetting"."new_question" = E'i' ) AND NOT ("auth_user"."id" = 10 )) Thanks in advance EDIT: I tried to break the queryset into two, one that uses the first Q object as the filter and another one with the second Q object, and although the second queryset produces the correct sql that returns the correct values when evaluated directly, it still doesn't return nothing when evaluated as a django queryset. heres the alternative code: subscribers = User.objects.values('email', 'username').filter( subscription_settings__new_question='i').exclude(id=question.author.id) subscribers2 = User.objects.values('email', 'username').filter( subscription_settings__new_question_watched_tags='i', marked_tags__id__in=question.tags.values('id'), tag_selections__reason='good').exclude(id=question.author.id)

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  • File Uploading In Google Application Engine Using Django

    - by Ayush
    I am using gae with django. I have an project named MusicSite with following url mapping- urls.py from django.conf.urls.defaults import * from MusicSite.views import MainHandler from MusicSite.views import UploadHandler from MusicSite.views import ServeHandler urlpatterns = patterns('',(r'^start/', MainHandler), (r'^upload/', UploadHandler), (r'^/serve/([^/]+)?', ServeHandler), ) There is an application MusicSite inside MusicFun with the following codes- views.py import os import urllib from google.appengine.ext import blobstore from google.appengine.ext import webapp from google.appengine.ext.webapp import blobstore_handlers from google.appengine.ext.webapp import template from google.appengine.ext.webapp.util import run_wsgi_app def MainHandler(request): response=HttpResponse() upload_url = blobstore.create_upload_url('http://localhost: 8000/upload/') response.write('') response.write('' % upload_url) response.write("""Upload File: """) return HttpResponse(response) def UploadHandler(request): upload_files=request.FILES['file'] blob_info = upload_files[0] response.redirect('http://localhost:8000/serve/%s' % blob_info.key()) class ServeHandler(blobstore_handlers.BlobstoreDownloadHandler): def get(self, resource): resource = str(urllib.unquote(resource)) blob_info = blobstore.BlobInfo.get(resource) self.send_blob(blob_info) now whenever a upload a file using /start and click Submit i am taken to a blank page with the following url- localhost:8000/_ah/upload/ahhnb29nbGUtYXBwLWVuZ2luZS1kamFuZ29yGwsSFV9fQmxvYlVwbG9hZFNlc3Npb25fXxgHDA These random alphabets keep varying but the result is same. A blank page after every upload. Somebody please help. The server responses are as below- INFO:root:"GET /start/ HTTP/1.1" 200 - INFO:root:"GET /favicon.ico HTTP/1.1" 404 - INFO:root:Internal redirection to http://localhost:8000/upload/ INFO:root:Upload handler returned 500 ERROR:root:Invalid upload handler response. Only 301, 302 and 303 statuses are permitted and it may not have a content body. INFO:root:"POST /_ah/upload/ ahhnb29nbGUtYXBwLWVuZ2luZS1kamFuZ29yGwsSFV9fQmxvYlVwbG9hZFNlc3Npb25fXxgCDA HTTP/1.1" 500 - INFO:root:"GET /favicon.ico HTTP/1.1" 404 -

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  • Reversing Django URLs With Extra Options

    - by Justin Voss
    Suppose I have a URLconf like below, and 'foo' and 'bar' are valid values for page_slug. urlpatterns = patterns('', (r'^page/(?P<page_slug>.*)/', 'myapp.views.someview'), ) Then, I could reconstruct the URLs using the below, right? >>> from django.core.urlresolvers import reverse >>> reverse('myapp.views.someview', kwargs={'page_slug': 'foo'}) '/page/foo/' >>> reverse('myapp.views.someview', kwargs={'page_slug': 'bar'}) '/page/bar/' But what if I change my URLconf to this? urlpatterns = patterns('', (r'^foo-direct/', 'myapp.views.someview', {'page_slug': 'foo'}), (r'^my-bar-page/', 'myapp.views.someview', {'page_slug': 'bar'}), ) I expected this result: >>> from django.core.urlresolvers import reverse >>> reverse('myapp.views.someview', kwargs={'page_slug': 'foo'}) '/foo-direct/' >>> reverse('myapp.views.someview', kwargs={'page_slug': 'bar'}) '/my-bar-page/' However, this throws a NoReverseMatch exception. I suspect I'm trying to do something impossible. Any suggestions on a saner way to accomplish what I want? Named URLs aren't an option, since I don't want other apps that link to these to need to know about the specifics of the URL structure (encapsulation and all that).

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  • Treebeard admin in Django

    - by Sharath
    I've setup Treebeard in Django and everything seems to have gone well. I tried to setup the admin system and I can see my models being presented in the admin interface. However, when I try to add new data using the admin interface, I get the following error in my template. The code still works fine, and I did a check in my DB and the data seems to be inserted properly. However, the view doesn't seem to load properly. Any idea about what is causing this?? The exception am getting is.. Caught an exception while rendering: Failed lookup for key [request] in u'[{\'action_index\': 0, \'block\': , , , , , , ]}, {\'block\': , , , ], , , , , \n \', ], , ], , , , ], , , \n \', , , , , , , , , ], , ], \n \']}, {\'cl\': , \'root_path\': None, \'actions_on_bottom\': False, \'title\': u\'Select album to change\', \'has_add_permission\': True, \'media\': , \'is_popup\': False, \'action_form\': , \'actions_on_top\': True, \'app_label\': \'gallery\'}, {\'MEDIA_URL\': \'\'}, {\'LANGUAGES\': ((\'ar\', \'Arabic\'), (\'bn\', \'Bengali\'), (\'bg\', \'Bulgarian\'), (\'ca\', \'Catalan\'), (\'cs\', \'Czech\'), (\'cy\', \'Welsh\'), (\'da\', \'Danish\'), (\'de\', \'German\'), (\'el\', \'Greek\'), (\'en\', \'English\'), (\'es\', \'Spanish\'), (\'et\', \'Estonian\'), (\'es-ar\', \'Argentinean Spanish\'), (\'eu\', \'Basque\'), (\'fa\', \'Persian\'), (\'fi\', \'Finnish\'), (\'fr\', \'French\'), (\'ga\', \'Irish\'), (\'gl\', \'Galician\'), (\'hu\', \'Hungarian\'), (\'he\', \'Hebrew\'), (\'hi\', \'Hindi\'), (\'hr\', \'Croatian\'), (\'is\', \'Icelandic\'), (\'it\', \'Italian\'), (\'ja\', \'Japanese\'), (\'ka\', \'Georgian\'), (\'ko\', \'Korean\'), (\'km\', \'Khmer\'), (\'kn\', \'Kannada\'), (\'lv\', \'Latvian\'), (\'lt\', \'Lithuanian\'), (\'mk\', \'Macedonian\'), (\'nl\', \'Dutch\'), (\'no\', \'Norwegian\'), (\'pl\', \'Polish\'), (\'pt\', \'Portuguese\'), (\'pt-br\', \'Brazilian Portuguese\'), (\'ro\', \'Romanian\'), (\'ru\', \'Russian\'), (\'sk\', \'Slovak\'), (\'sl\', \'Slovenian\'), (\'sr\', \'Serbian\'), (\'sv\', \'Swedish\'), (\'ta\', \'Tamil\'), (\'te\', \'Telugu\'), (\'th\', \'Thai\'), (\'tr\', \'Turkish\'), (\'uk\', \'Ukrainian\'), (\'zh-cn\', \'Simplified Chinese\'), (\'zh-tw\', \'Traditional Chinese\')), \'LANGUAGE_BIDI\': False, \'LANGUAGE_CODE\': \'en-us\'}, {}, {\'perms\': , \'messages\': [], \'user\': }, {}]' This happens after I hit the save button in Django admin. This is my admin.py implementation.. class MP_Album_Admin(TreeAdmin): pass admin.site.register(Album,MP_Album_Admin)

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  • Django 404 page not showing up

    - by Matthew Doyle
    Hey all, I'm in the middle of putting up my first django application on shared hosting. This should be an easy thing, but I am just not seeing it. I tried to follow the directions of the django documentation, and created a 404.html page within my template folder. I just wrote "This is a 404 page." in the .html file. I also did the same thing for a 500.html page and wrote in it "This is a 500 page." However when I hit a 'bad page' I get a standard 404 page from the browser (Oops! This link appears to be broken. in Chrome) when I would expect "This is a 404 page." What's even more interesting is out of frustration I wrote {% asdfjasdf %} in the 404.html, and instead of getting the "Oops!..." error I get "This is a 500 page," so it definitely sees the 404.html template. Here's what I can confirm: Debug = False I am running apache on a shared hosting I have not done anything special with .htaccess and 404 errors. If I run with Debug = True, it says it's a 404 error. I am using FastCGI Anything else anyone think I could try? Thank you very much!

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  • Django server side AJAX validation

    - by MMRUser
    Hi, Recently I'm trying to implement a simple Django application that include one server side AJAX validation, it's a simple form input field (username). I have used a pre-built in line AJAX validation library which uses jQuery. So the code goes like this HTML snippet <form id="simpleform" method="post" action="/done/"> Username:<input value="" class="validate[required,custom[noSpecialCaracters],length[0,20],ajax[ajaxUser]]" type="text" name="user" id="user" /> <input class="submit" type="submit" value="Validate"/> </form> The server side code snippet (embedded in to a php script) /* RECEIVE VALUE */ $validateValue=$_POST['validateValue']; $validateId=$_POST['validateId']; $validateError=$_POST['validateError']; /* RETURN VALUE */ $arrayToJs = array(); $arrayToJs[0] = $validateId; $arrayToJs[1] = $validateError; if($validateValue =="testname"){ // validate?? $arrayToJs[2] = "true"; // RETURN TRUE echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; // RETURN ARRAY WITH success }else{ for($x=0;$x<1000000;$x++){ if($x == 990000){ $arrayToJs[2] = "false"; echo '{"jsonValidateReturn":'.json_encode($arrayToJs).'}'; // RETURN ARRAY WITH ERROR } } } So my question is that how do I get this in to Python code (in order to use in Django environment) how do I get the user name from the input field in to the back end,I think the server side script snippet already does it but I want to know how to use this in my Pyhon code,and this is my first time using jQuery and I do need to use this same exact validation library. Your valuable corporation is needed. Thanks.

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  • Mimic remote API or extend existing django model

    - by drozzy
    I am in a process of designing a client for a REST-ful web-service. What is the best way to go about representing the remote resource locally in my django application? For example if the API exposes resources such as: List of Cars Car Detail Car Search Dealership summary So far I have thought of two different approaches to take: Try to wrangle the django's models.Model to mimic the native feel of it. So I could try to get some class called Car to have methods like Car.objects.all() and such. This kind of breaks down on Car Search resources. Implement a Data Access Layer class, with custom methods like: Car.get_all() Car.get(id) CarSearch.search("blah") So I will be creating some custom looking classes. Has anyone encoutered a similar problem? Perhaps working with some external API's (i.e. twitter?) Any advice is welcome. PS: Please let me know if some part of question is confusing, as I had trouble putting it in precise terms.

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  • Is it approproate it use django signals withing the same app

    - by Alex Lebedev
    Trying to add email notification to my app in the cleanest way possible. When certain fields of a model change, app should send a notification to a user. Here's my old solution: from django.contrib.auth import User class MyModel(models.Model): user = models.ForeignKey(User) field_a = models.CharField() field_b = models.CharField() def save(self, *args, **kwargs): old = self.__class__.objects.get(pk=self.pk) if self.pk else None super(MyModel, self).save(*args, **kwargs) if old and old.field_b != self.field_b: self.notify("b-changed") # Sevelar more events here # ... def notify(self, event) subj, text = self._prepare_notification(event) send_mail(subj, body, settings.DEFAULT_FROM_EMAIL, [self.user.email], fail_silently=True) This worked fine while I had one or two notification types, but after that just felt wrong to have so much code in my save() method. So, I changed code to signal-based: from django.db.models import signals def remember_old(sender, instance, **kwargs): """pre_save hanlder to save clean copy of original record into `old` attribute """ instance.old = None if instance.pk: try: instance.old = sender.objects.get(pk=instance.pk) except ObjectDoesNotExist: pass def on_mymodel_save(sender, instance, created, **kwargs): old = instance.old if old and old.field_b != instance.field_b: self.notify("b-changed") # Sevelar more events here # ... signals.pre_save.connect(remember_old, sender=MyModel, dispatch_uid="mymodel-remember-old") signals.post_save.connect(on_mymodel_save, sender=MyModel, dispatch_uid="mymodel-on-save") The benefit is that I can separate event handlers into different module, reducing size of models.py and I can enable/disable them individually. The downside is that this solution is more code and signal handlers are separated from model itself and unknowing reader can miss them altogether. So, colleagues, do you think it's worth it?

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