Search Results

Search found 7576 results on 304 pages for 'drupal forms'.

Page 79/304 | < Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >

  • Problem with SQL syntax (probably simple)

    - by Bryan Folds
    I'm doing some custom database work for a module for Drupal and I get the following SQL error when trying to create my table: user warning: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'DEFAULT NULL, rooms INT DEFAULT NULL, adults INT DEFAULT NULL, children' at line 14 query: CREATE TABLE dr_enquiry ( eId INT unsigned NOT NULL auto_increment, eKey VARCHAR(16) NOT NULL, dateSent INT NOT NULL DEFAULT 0, status VARCHAR(30) NOT NULL DEFAULT 'Unanswered', custName VARCHAR(50) NOT NULL, custEmail VARCHAR(200) NOT NULL, custPhone VARCHAR(25) NOT NULL, custCountry VARCHAR(40) NOT NULL, custIP VARCHAR(11) DEFAULT NULL, offerName VARCHAR(100) NOT NULL, offerURL VARCHAR(200) NOT NULL, arrival DATETIME DEFAULT NULL, departure DEFAULT NULL, rooms INT DEFAULT NULL, adults INT DEFAULT NULL, children INT DEFAULT NULL, childAges VARCHAR(32) DEFAULT NULL, toddlers INT DEFAULT NULL, toddlerAges VARCHAR(32) DEFAULT NULL, catering VARCHAR(255) DEFAULT NULL, comments VARCHAR(255) DEFAULT NULL, agent VARCHAR(100) DEFAULT NULL, voucher VARCHAR(100) DEFAULT NULL, PRIMARY KEY (eId) ) /*!40100 DEFAULT CHARACTER SET UTF8 */ in /home/travelco/public_html/includes/database.inc on line 550.

    Read the article

  • Problems using MySQL instead of MySQLi

    - by vaibhav
    I have a blog, which is on Drupal v6.14. Recently I changed my web hosting provider. My new hosting provider does'nt support MySQLi. So I have to use MySQL instead of MySQLi. All things worked fine for some days. But on a very fine morning, I found my blog is down and the error message was Mysql: Too Many Connections to the server. And this problem occurs several times a day now. I contacted my web hosting provider, they said, its a problem in your database. I don't trust this. My blog was working fine at old web server. Can it be a problem because of I moved to MySQL from MYSQLi.

    Read the article

  • jquery cycle plugin using RSS feed images?

    - by Chris
    This could well be a terribly ignorant question, if so please forgive me: I'm using jquery cycle plugin to create an image rotator of recently posted images. Im using drupal 6.x and created an RSS feed of the recent images using the views module. I have no idea how to connect the two. Any suggestions? I have a feeling an RSS feed might not be the best way to go about this, but it's all I could come up with. Thanks for the help.

    Read the article

  • make javascript repeat for each row in a view

    - by Kathy Chavez
    I have created a view in Drupal. I"m using javascript to modify css in each row. The script runs on the first row, but does not make the changes on the rest of rows from the view. This is the script: <script language="javascript" type="text/javascript"> window.onload = floatbr; function floatbr() { var f = document.getElementById('firstright') // Get div element var s = document.getElementById('secondright') // Get div element var w = document.getElementById('catwrapper') // Get div element var sh = s.offsetHeight // secondright div height var wh = w.offsetHeight // catwrapper div height f.style.height = wh - sh + 'px'; } </script> I'm using it from this page: http://agsone.100webcustomers.com/floatbottom.php having the script in the page once does not do the trick. having the script in the view footer and repeating the script does not work. THanks! link to fiddle with html, css & js: http://jsfiddle.net/Vvjku/

    Read the article

  • How to display the rss version of a News Link

    - by cbrown16
    I'm trying to write a script that will show the rss version of a single url (title, author, image, source, etc..). This should behave much the way that facebook does when you copy paste a link to share and it generates this information automatically. I'm trying to do this with a php script but would also be open to opensource programs that can do this as well. also, if anyone knows of any Joomla/Drupal plugins that can do this that would be great. This may eventually end up on a site run on one of these frameworks. thanks!!

    Read the article

  • Word forms with too many ActiveX checkboxes load slowly.

    - by Luke
    Hi there, my company's software product has a feature that allows users to generate forms from Word templates. The program auto fills some fields from the SQL database and the user can fill in other data that they desire. So we have a .dotx template that holds the design of the form, and then the user gets the .docx file to fill out when they call it from our program. The problem we're having is that some of our users have been finding that the forms take an exceptionally long time to open up and then, once open, are so slow to respond (scroll around, etc) that they're unusable. So in my investigations so far, I've found out that the problem systems are one with lower powered CPUs (unfortunately it happens for systems above our system requirements) and the Word forms that cause the problems are ones with large amount of ActiveX style checkboxes on them. I verified that reducing the ActiveX checkboxes fixes the form loading problems. So I have the following questions about solutions (we're using Word 2007): 1) Is there any way to configure Word, or some other settings, so that there won't be such a strain opening a Word form with lots of ActiveX checkboxes? Any way of speeding up Word's opening? 2) Using Legacy style checkboxes instead of the ActiveX ones makes the forms load fine, but it looks like the user has to double-click the checkbox and change Default Value-Checked. Is there a way to configure it so that they can simply click on the checkbox to tick it? "Legacy Forms" checkbox as a name kind of worries me (Legacy…), does that mean a future version of word at some point wouldn't load the checkboxes because they're "legacy"? 3) Yes, it became clear to me after a little bit of research into solutions that Word is not the tool for the job for forms like I'm describing. InfoPath seems to be exactly what we should have been using all along but unfortunately I wasn't involved in the decision making or development of these forms, just tasked with coming up with a solution. I'd appreciate answers to any of these, or if anyone has any other ideas for solutions to this problem. Thanks

    Read the article

  • Edit and create nodes in a view?

    - by tputkonen
    We are storing people's class attendance information to Drupal. We would like to show this in a grid/chart, where the first column of each row shows person's name, and rest of the columns (ca. 20) either a checkbox or "X" if the user attended a class, or otherwise an non-checked box or empty column: (dates here) Jack X XXX X X Jill XX XXX XX It should also be possible to edit the attendance information on the grid. Each attendance information is a node of its own. This functionality can probably mostly be achieved using views and editablefields, but there is one problem: if a person has not attended a specific class he/she will not have at all an attendace node for that day. What would be the easiest way to create an attendace node in those cases, so that it would be possible for the end user to edit the grid by just clicking on the checkbox or typing an 'X'?

    Read the article

  • Automatic open Colorbox modal window

    - by user1631168
    I'm using the Colorbox module in Drupal 7. I'm opening an external website. I can make it work with a link. Click here, then click the "colorbox popup" link at the bottom, middle column. The client would like this to open automatically when the page opens. I've created a block and added the following code (from the colorbox site). <script type="text/javascript"> // Display a welcome message on first visit, and set a cookie that expires in 30 days: if (document.cookie.indexOf('visited=true') === -1) { var expires = new Date(); expires.setDate(expires.getDate()+30); document.cookie = "visited=true; expires="+expires.toUTCString(); jQuery.colorbox({html:"http://join.raretearepublic.com/popup/", width:887, height:638}); } </script> But it does not work. Any help would be greatly appreciated.

    Read the article

  • I had inserted a jQuery tab in my site. It was working fine till sometime ago. Suddenly it stopped w

    - by vr3690
    Hello, I had inserted two jQuery tabs on my site. One div container had the id - tabs and another had the id tabs-for-views. Both of them were working fine till sometime ago, until i made some changes. I don't remember what the exact changes were.. Right now, the first tab uses the jQuery UI theme I am using. As in, I can see the tab navigation and content panels - but on clicking the tabs nothing happens. But the second (tabs-for-views) is not even converted to proper tabs format. I am using the Drupal CMS for this site. the tabs can be found on this page: http://betterclassofleaders.co.cc/whackk/ this is the jquery ui css file i am using: (insert first link)sites/default/themes/whack_custom/jquery-ui-1.7.2.custom.css

    Read the article

  • Multiple sections on landing page only

    - by RDRAO
    Hi every one, I am very much new to Drupal but am loving it to start with. I got struck at a point with respect to theaming. I have a region called 'footer-teaser' just above footer. Its width is 800px. its been split into 3 equal size columns. Each column has the following. Image of size 120x120 Some teaser text Link to 'read more' The design requirement is all the above should be editable by the admin from the admin interface. If its static i would have hardcoded this but since the requirement is dynamic, i am not aware of how to achieve this. I have customised page.tpl for other sections of the page except this. I am sure someone else would have faced this issue before and was wondering if anyone can direct me in the right direction? Even better if an example is provided. Cheers RD

    Read the article

  • hook_form for multiple content types defined by the same module

    - by pao13gate
    A new module 'foo' implements foo_node_info() where one or more new content types can be defined. If foo_node_info() defines two content types, namely a content type 'footypea' and a content type 'footypeb', how does one go about implementing hook_form() (what should the name of the "hook" be?) to configure each node's editing form? In the drupal example, the name of the new content type is the same as the module name. What happens in the above described example where two new content types are defined by the module? Should the implemented hook_form() function be of the form: footypea_form() and footypeb_form() ? (this doesn't seem to work) Or should you implement a single foo_form() function and within this create and return an array $form with elements $form['footypea'] and $form['footypeb'] that are in turn arrays of the individual form field definitions?

    Read the article

  • How do Oracle Forms compare to Microsoft Access as a "front-end"?

    - by webworm
    I recently started a project where I was set to build an ADP based application in Access 2003. The font end GUI was going to be in Access while all the data resided in MS SQL Server. I say "was", because the powers that be have decided that Oracle Forms might be a better choice than Access and SQL Server. The place where I am doing this work is an Oracle shop where they use Oracle 10g. They also use Oracle Forms quite a bit internally. As for me I am always up for learning anything new. I have always been a rather "eclectic" developer (I work with .NET WinForms, ASP.NET, Java, C#, Python, and Access) so I would not mind moving to Oracle Forms as long as it could do the same things as MS Access (hopefully even more as VBA is rather limited). So my question is this. How does Oracle Forms (10g) compare to MS Access for developing a GUI application? Access uses VBA for it's language, what does Oracle Forms use? I know the Forms app is a Java applet. Does that means you can write Oracle Forms using Java?

    Read the article

  • Adding a javascript immediate after body tag

    - by prabdrup
    I am making a drupal module. My requirement in the module is that when the module is activated then it needs to add a javascript in page.tpl file just after the body tag. Can anyone help me how to do this. I have tried using drupal_add_js but it will not exactly put the script after body tag, rather puts inside the head or below in footer. I also tried using template variable and preprocess method but the problem is the preprocess method replaces the old value of that variable with the new one. Is there a way how i can implement this in.

    Read the article

  • druapal content image not showing

    - by tibin mathew
    hi, I'm doing a drupal site. i want show a facebook image in my page content in home page. i have edited content of that page. i have edited the body of that content through admin and put the text in body like this The BikeGlow™ Safety Light runs on 2-AA batteries. Light tube length is 10'. Complete unit weighs under 2 oz (without batteries). Light tube attaches to frame with included attachment strips. "It's like magic cycling protection from cars!" < img src='bikeglow_com/sites/default/files/5u84f48n.gif' alt="facebook" / but after saving image is not showing there even that alt tag is not coming. can any one help me, what will be reason for his

    Read the article

  • Theme the node-create and node-edit template

    - by Toxid
    I'm using drupal 6. I've managed to make a .tpl file for one content type, that is for images in my image gallery. I did that by adding this code in template.php: function artbasic_theme($existing, $type, $theme, $path) { return array( 'galleryimage_node_form' => array( 'arguments' => array('form' => NULL), 'template' => 'galleryimage_node_form' ) ); } And then I created galleryimage_node_form.tpl.php, and was good to go. Now it happens so that I want to have other template files for the forms of other content types, for example link_contrib_node_form.tpl.php. I've tried a couple of ways to change this function to include more content types, but I can't figure it out. Can anyone help?

    Read the article

  • access a property via string with array in php?

    - by sprugman
    (This is in drupal, but I don't really think that matters.) I have a big list of properties that I need to map between two objects, and in one, the value that I need to map is buried inside an array. I'm hoping to avoid hard-coding the property names in the code. If I have a class like this: class Product { public $colors, $sizes; } I can access the properties like this: $props = array('colors', 'sizes'); foreach ($props as $p) { $this->$p = $other_object->$p; } As far as I can tell, if each of the properties on the left are an array, I can't do this: foreach ($props as $p) { $this->$p[0]['value'] = $other_object->$p; } Is that correct, or am I missing some clever way around this?

    Read the article

  • Exception using SQLiteDataReader

    - by galford13x
    I'm making a Custom SQLite Wrapper. This is meant to allow a presistent connection to a database. However, I receive an exception when calling this function twice. public Boolean DatabaseConnected(string databasePath) { bool exists = false; if (ConnectionOpen()) { this.Command.CommandText = string.Format(DATABASE_QUERY); using (reader = this.Command.ExecuteReader()) { while (reader.Read()) { if (string.Compare(reader[FILE_NAME_COL_HEADER].ToString(), databasePath, true) == 0) { exists = true; break; } } reader.Close(); } } return exists; } I use the above function to check if the database is currently open before executing a command or trying to open a database. The first time I execute the function, it executes with no issue. After that the reader = this.Command.ExecuteReader() throws an exception Object reference not set to an instance of an object. StackTrace: at System.Data.SQLite.SQLiteStatement.Dispose() at System.Data.SQLite.SQLite3.Reset(SQLiteStatement stmt) at System.Data.SQLite.SQLite3.Step(SQLiteStatement stmt) at System.Data.SQLite.SQLiteDataReader.NextResult() at System.Data.SQLite.SQLiteDataReader..ctor(SQLiteCommand cmd, CommandBehavior behave) at System.Data.SQLite.SQLiteCommand.ExecuteReader(CommandBehavior behavior) at System.Data.SQLite.SQLiteCommand.ExecuteReader() at EveTraderApi.Database.SQLDatabase.DatabaseConnected(String databasePath) in C:\Documents and Settings\galford13x\My Documents\Visual Studio 2008\Projects\EveTrader\EveTraderApi\Database\Database.cs:line 579 at EveTraderApi.Database.SQLDatabase.OpenSQLiteDB(String filename) in C:\Documents and Settings\galford13x\My Documents\Visual Studio 2008\Projects\EveTrader\EveTraderApi\Database\Database.cs:line 119 at EveTraderApiExample.Form1.CreateTableDataTypes() in C:\Documents and Settings\galford13x\My Documents\Visual Studio 2008\Projects\EveTrader\EveTraderApiExample\Form1.cs:line 89 at EveTraderApiExample.Form1.Button1_ExecuteCommand(Object sender, EventArgs e) in C:\Documents and Settings\galford13x\My Documents\Visual Studio 2008\Projects\EveTrader\EveTraderApiExample\Form1.cs:line 35 at System.Windows.Forms.Control.OnClick(EventArgs e) at System.Windows.Forms.Button.OnClick(EventArgs e) at System.Windows.Forms.Button.OnMouseUp(MouseEventArgs mevent) at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks) at System.Windows.Forms.Control.WndProc(Message& m) at System.Windows.Forms.ButtonBase.WndProc(Message& m) at System.Windows.Forms.Button.WndProc(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m) at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam) at System.Windows.Forms.UnsafeNativeMethods.DispatchMessageW(MSG& msg) at System.Windows.Forms.Application.ComponentManager.System.Windows.Forms.UnsafeNativeMethods.IMsoComponentManager.FPushMessageLoop(Int32 dwComponentID, Int32 reason, Int32 pvLoopData) at System.Windows.Forms.Application.ThreadContext.RunMessageLoopInner(Int32 reason, ApplicationContext context) at System.Windows.Forms.Application.ThreadContext.RunMessageLoop(Int32 reason, ApplicationContext context) at System.Windows.Forms.Application.Run(Form mainForm) at EveTraderApiExample.Program.Main() in C:\Documents and Settings\galford13x\My Documents\Visual Studio 2008\Projects\EveTrader\EveTraderApiExample\Program.cs:line 18 at System.AppDomain._nExecuteAssembly(Assembly assembly, String[] args) at System.AppDomain.ExecuteAssembly(String assemblyFile, Evidence assemblySecurity, String[] args) at Microsoft.VisualStudio.HostingProcess.HostProc.RunUsersAssembly() at System.Threading.ThreadHelper.ThreadStart_Context(Object state) at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state) at System.Threading.ThreadHelper.ThreadStart()

    Read the article

  • No value given for one or more required parameters in connection initialisation

    - by DarkJaff
    Hi everyone, I have an C# form application that use an access database. This application works perfectly in debug and release. It works on all version of Windows. But it crash on one computer with Windows 7. The message I got is: System.Data.OleDb.OleDbException: No value given for one or more required parameters. The function that is supposely not working is this: public void InitConnection(string strFile) { string strConnection = String.Format("Provider=Microsoft.Jet.OLEDB.4.0;Data Source={0};User Id=admin;Password=;", strFile); m_conn = new OleDbConnection(strConnection); try { //On vérifie si la connexion n'est pas ouverte if (m_conn.State != ConnectionState.Open) { m_conn.Open(); m_VCoeffModele = GetModeleCoeff(); } } catch (Exception err) { throw err; } } I think it's something related to the connection string but why only on that computer. Thanks for your help! DarkJaff EDIT Here is the complete error message: See the end of this message for details on invoking just-in-time (JIT) debugging instead of this dialog box. ***** Exception Text ******* System.Data.OleDb.OleDbException: No value given for one or more required parameters. at System.Data.OleDb.OleDbCommand.ExecuteCommandTextErrorHandling(OleDbHResult hr) at System.Data.OleDb.OleDbCommand.ExecuteCommandTextForSingleResult(tagDBPARAMS dbParams, Object& executeResult) at System.Data.OleDb.OleDbCommand.ExecuteCommandText(Object& executeResult) at System.Data.OleDb.OleDbCommand.ExecuteCommand(CommandBehavior behavior, Object& executeResult) at System.Data.OleDb.OleDbCommand.ExecuteReaderInternal(CommandBehavior behavior, String method) at System.Data.OleDb.OleDbCommand.ExecuteReader(CommandBehavior behavior) at System.Data.OleDb.OleDbCommand.ExecuteReader() at DatabaseLayer.DatabaseFacade.GetModeleCoeff() at DatabaseLayer.DatabaseFacade.InitConnection(String strFile) at CalculatriceCHW.ListeMesure.OuvrirFichier(String strFichier) at CalculatriceCHW.ListeMesure.nouveauFichierMenu_Click(Object sender, EventArgs e) at System.Windows.Forms.ToolStripItem.RaiseEvent(Object key, EventArgs e) at System.Windows.Forms.ToolStripMenuItem.OnClick(EventArgs e) at System.Windows.Forms.ToolStripItem.HandleClick(EventArgs e) at System.Windows.Forms.ToolStripItem.HandleMouseUp(MouseEventArgs e) at System.Windows.Forms.ToolStripItem.FireEventInteractive(EventArgs e, ToolStripItemEventType met) at System.Windows.Forms.ToolStripItem.FireEvent(EventArgs e, ToolStripItemEventType met) at System.Windows.Forms.ToolStrip.OnMouseUp(MouseEventArgs mea) at System.Windows.Forms.ToolStripDropDown.OnMouseUp(MouseEventArgs mea) at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks) at System.Windows.Forms.Control.WndProc(Message& m) at System.Windows.Forms.ScrollableControl.WndProc(Message& m) at System.Windows.Forms.ToolStrip.WndProc(Message& m) at System.Windows.Forms.ToolStripDropDown.WndProc(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m) at System.Windows.Forms.NativeWindow.Callback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)

    Read the article

  • NHibernate Tutorial Run-Time Error: HibernateException

    - by Kashif
    I'm a newbie at NHibernate so please go easy on me if I have asked a stupid question... I am following the tutorial for NHibernate posted here and am getting a run-time error of type "HibernateException" The code in question looks like this: using System; using System.Collections.Generic; using System.Linq; using System.Text; using FirstSolution; using NHibernate.Cfg; using NHibernate.Tool.hbm2ddl; using NUnit.Framework; namespace FirstSolution.Tests { [TestFixture] public class GenerateSchema_Fixture { [Test] public void Can_generate_schema() { var cfg = new Configuration(); cfg.Configure(); cfg.AddAssembly(typeof(Product).Assembly); new SchemaExport(cfg).Execute(false, true, false); } } } The line I am getting the error at is: cfg.AddAssembly(typeof(Product).Assembly); The inner-most exception is: The IDbCommand and IDbConnection implementation in the assembly System.Data.SqlServerCe could not be found And here's my stack trace: at NHibernate.Connection.ConnectionProvider.ConfigureDriver(IDictionary`2 settings) at NHibernate.Connection.ConnectionProvider.Configure(IDictionary`2 settings) at NHibernate.Connection.ConnectionProviderFactory.NewConnectionProvider(IDictionary`2 settings) at NHibernate.Tool.hbm2ddl.SchemaExport.Execute(Action`1 scriptAction, Boolean export, Boolean justDrop) at NHibernate.Tool.hbm2ddl.SchemaExport.Execute(Boolean script, Boolean export, Boolean justDrop) at FirstSolution.Tests.GenerateSchema_Fixture.Can_generate_schema() in C:\Users\Kash\Documents\Visual Studio 2010\Projects\FirstSolution\FirstSolution\GenerateSchema_Fixture.cs:line 23 at HibernateUnitTest.Form1.button1_Click(Object sender, EventArgs e) in C:\Users\Kash\Documents\Visual Studio 2010\Projects\FirstSolution\HibernateUnitTest\Form1.cs:line 23 at System.Windows.Forms.Control.OnClick(EventArgs e) at System.Windows.Forms.Button.OnClick(EventArgs e) at System.Windows.Forms.Button.OnMouseUp(MouseEventArgs mevent) at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks) at System.Windows.Forms.Control.WndProc(Message& m) at System.Windows.Forms.ButtonBase.WndProc(Message& m) at System.Windows.Forms.Button.WndProc(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m) at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m) at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam) at System.Windows.Forms.UnsafeNativeMethods.DispatchMessageW(MSG& msg) at System.Windows.Forms.Application.ComponentManager.System.Windows.Forms.UnsafeNativeMethods.IMsoComponentManager.FPushMessageLoop(IntPtr dwComponentID, Int32 reason, Int32 pvLoopData) at System.Windows.Forms.Application.ThreadContext.RunMessageLoopInner(Int32 reason, ApplicationContext context) at System.Windows.Forms.Application.ThreadContext.RunMessageLoop(Int32 reason, ApplicationContext context) at System.Windows.Forms.Application.Run(Form mainForm) at HibernateUnitTest.Program.Main() in C:\Users\Kash\Documents\Visual Studio 2010\Projects\FirstSolution\HibernateUnitTest\Program.cs:line 18 at System.AppDomain._nExecuteAssembly(RuntimeAssembly assembly, String[] args) at System.AppDomain.ExecuteAssembly(String assemblyFile, Evidence assemblySecurity, String[] args) at Microsoft.VisualStudio.HostingProcess.HostProc.RunUsersAssembly() at System.Threading.ThreadHelper.ThreadStart_Context(Object state) at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state, Boolean ignoreSyncCtx) at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state) at System.Threading.ThreadHelper.ThreadStart() I've made sure that System.Data.SqlServerCe has been referenced and that its Copy Local property is set to True. The error persists, however. Your help would be appreciated. Thanks.

    Read the article

  • How to Create SharePoint List and Insert List Item programmatically from a Windows Forms Application.

    - by Michael M. Bangoy
    In this post I’m going to demonstrate how to create SharePoint List and also Insert Items on the List from a Windows Forms Application. 1. Open Visual Studio and create a new project. On the project template select Windows Form Application under C#. 2. In order to communicate with Sharepoint from a Windows Forms Application we need to add the 2 Sharepoint Client DLL located in c:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\14\ISAPI.  3. Select the Microsoft.Sharepoint.Client.dll and Microsoft.Sharepoint.Client.Runtime.dll. (Your solution should look like the one below) 4. Open the Form1 in design view and from the Toolbox menu add a button on the form surface. Your form should look like the one below. 5. Double click the button to open the code view. Add Using statement to reference the Sharepoint Client Library then create method for the Create List. Your code should like the codes below. using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Security; using System.Windows.Forms; using SP = Microsoft.SharePoint.Client; namespace ClientObjectModel {     public partial class Form1 : Form     {         // url of the Sharepoint site         const string _context = "urlofthesharepointsite";         public Form1()         {             InitializeComponent();         }         private void Form1_Load(object sender, EventArgs e)         {                    }         private void cmdcreate_Click(object sender, EventArgs e)         {             try             {                 // declare the ClientContext Object                 SP.ClientContext _clientcontext = new SP.ClientContext(_context);                 SP.Web _site = _clientcontext.Web;                 // declare a ListCreationInfo                 SP.ListCreationInformation _listcreationinfo = new SP.ListCreationInformation();                 // set the Title and the Template of the List to be created                 _listcreationinfo.Title = "NewListFromCOM";                 _listcreationinfo.TemplateType = (int)SP.ListTemplateType.GenericList;                 // Call the add method to the ListCreatedInfo                 SP.List _list = _site.Lists.Add(_listcreationinfo);                 // Add Description field to the List                 SP.Field _Description = _list.Fields.AddFieldAsXml(@"                                     <Field Type='Text'                                         DisplayName='Description'>                                     </Field>", true, SP.AddFieldOptions.AddToDefaultContentType);                 // declare the List item Creation object for creating List Item                 SP.ListItemCreationInformation _itemcreationinfo = new SP.ListItemCreationInformation();                 // call the additem method of the list to insert a new List Item                 SP.ListItem _item = _list.AddItem(_itemcreationinfo);                 _item["Title"] = "New Item from Client Object Model";                 _item["Description"] = "This item was added by a Windows Forms Application";                 // call the update method                 _item.Update();                 // execute the query of the clientcontext                 _clientcontext.ExecuteQuery();                 // dispose the clientcontext                 _clientcontext.Dispose();                 MessageBox.Show("List Creation Successfull");             }             catch(Exception ex)             {                 MessageBox.Show("Error creating list" + ex.ToString());             }          }     } } 6. Hit F5 to run the application. A message will be displayed on the screen if the operation is successful and also if it fails. 7. To make that the operation of our Windows Form Application has really created the List and Inserted an item on it. Let’s open our SharePoint site. Once the SharePoint is open click on the Site Actions then View All Site Content. 7. Click the List to open it and check if an Item is inserted. That’s it. Hope this helps.

    Read the article

  • How to retrieve Sharepoint data from a Windows Forms Application.

    - by Michael M. Bangoy
    In this demo I'm going to demonstrate how to retrieve Sharepoint data and display it on a Windows Forms Application. 1. Open Visual Studio 2010 and create a new Project. 2. In the project template select Windows Forms Application. 3. In order to communicate with Sharepoint from a Windows Forms Application we need to add the 2 Sharepoint Client DLL located in c:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\14\ISAPI. 4. Select the Microsoft.Sharepoint.Client.dll and Microsoft.Sharepoint.Client.Runtime.dll. That's it we're ready to write our codes. Note: In this example I've added to controls on the form, the controls are Button, TextBox, Label and DataGridView. using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Data.Objects; using System.Drawing; using System.Linq; using System.Text; using System.Security; using System.Windows.Forms; using SP = Microsoft.SharePoint.Client; namespace ClientObjectModel { public partial class Form1 : Form { // declare string url of the Sharepoint site string _context = "theurlofyoursharepointsite"; public Form1() { InitializeComponent(); } private void Form1_Load(object sender, EventArgs e) { } private void getsitetitle() {    SP.ClientContext context = new SP.ClientContext(_context);    SP.Web _site = context.Web;    context.Load(_site);    context.ExecuteQuery();    txttitle.Text = _site.Title;    context.Dispose(); } private void loadlist() { using (SP.ClientContext _clientcontext = new SP.ClientContext(_context)) {    SP.Web _web = _clientcontext.Web;    SP.ListCollection _lists = _clientcontext.Web.Lists;    _clientcontext.Load(_lists);    _clientcontext.ExecuteQuery();    DataTable dt = new DataTable();    DataColumn column;    DataRow row;    column = new DataColumn();    column.DataType = Type.GetType("System.String");    column.ColumnName = "List Title";    dt.Columns.Add(column);    foreach (SP.List listitem in _lists)    {       row = dt.NewRow();       row["List Title"] = listitem.Title;       dt.Rows.Add(row);    }       dataGridView1.DataSource = dt;    } private void cmdload_Click(object sender, EventArgs e) { getsitetitle(); loadlist(); } } That's it. Running the application and clicking the Load Button will retrieve the Title of the Sharepoint site and display it on the TextBox and also it will retrieve ALL of the Sharepoint List on that site and populate the DataGridView with the List Title. Hope this helps. Thank you.

    Read the article

  • ASP.NET MVC 2 Post AJAX from from JavaScript

    - by ANDyW
    Hi, I got control with strongly typed View, with Ajax.BeginForm(). Now I would like to change submit method from <input type="submit" id="testClick" value="Submit" /> To some javascript method DoSubmit(). What I tried is : Invoke click on that submit button Invoke submit on form ('form1').submit(), document.forms['form1'].submit() jQuery forms with ('form1').AjaxSubmit(); Create jQuery AJAX $.ajax({ type: "POST", url: $("#form1").attr("action"), data: $("#form1").serialize(), success: function() { alert("epic win!!!1!1!") }, error: function(XMLHttpRequest, textStatus, errorThrown) { alert("epic fail!") } }); All those method created normal request (not AJAX), or they didn't work. So anyone know how I can do AJAX submit "Form", from JavaScript and strongly typed mechanism (public AcrionResult MyFormAction(FormModel model); ) will work?

    Read the article

  • How to manually render a Django template for an inlineformset_factory with can_delete = True / False

    - by chefsmart
    I have an inlineformset with a custom Modelform. So it looks something like this: MyInlineFormSet = inlineformset_factory(MyMainModel, MyInlineModel, form=MyCustomInlineModelForm) I am rendering this inlineformset manually in a template so that I have more control over widgets and javascript. So I go in a loop like {% for form in myformset.forms %} and then manually render each field as described on this page http://docs.djangoproject.com/en/dev/topics/forms/#customizing-the-form-template The formset has can_delete = True or can_delete = False depending on whether the user is creating new objects or editing existing ones. Question is, how do I manually render the can_delete checkbox?

    Read the article

  • Create Django formset wihtout multiple queries

    - by Martin
    I need to display multiple forms (up to 10) of a model on a page. This is the code I use for to accomplish this. TheFormSet = formset_factory(SomeForm, extra=10) ... formset = TheFormSet(prefix='party') return render_to_response('template.html', { 'formset' : formset, }) The problem is, that it seems to me that Django queries the database for each of the forms in the formset, even though the data displayed in them is the same. Is this the way Formsets work or am I doing something wrong? Is there a way around it inside django or would I have to use JavaScript for a workaround?

    Read the article

< Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >