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  • How to get rid of "d»z" or "" characters

    - by Cassandra
    I have website based on Umbraco 5. I have installed contact form plugin (http://cultivjupitercontact.codeplex.com/). And on the web page at the end of this contact form there are always characters "d»z". It looks like that: ... <input type="submit" value="Send" /> </fieldset> <input name='uformpostroutevals' type='hidden' value='somevalue' /></form>d»z I suspect there is something wrong with encoding. I have tried to change it(to ANSI or UTF-8 without BOM but it didn't helped. Perhaps I have changed it in wrong file, cause I don't really know where exactly this 'd»z'is coming from. All I know it came with this plugin. On different server those extra characters are "". How can I get rid of those extra characters? Any help much appreciated!

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  • Adding to database. No repeat on refresh

    - by kevstarlive
    I have this code: Episode.php <?$feedback = new feedback; $articles = $feedback->fetch_all(); if (isset($_POST['name'], $_POST['post'])) { $cast = $_GET['id']; $name = $_POST['name']; $email = $_POST['email']; $post = nl2br ($_POST['post']); $ipaddress = $_SERVER['REMOTE_ADDR']; if (empty($name) or empty($post)) { $error = 'All Fields Are Required!'; }else{ $query = $pdo->prepare('INSERT INTO comments (cast, name, email, post, ipaddress) VALUES(?, ?, ?, ?, ?)'); $query->bindValue(1, $cast); $query->bindValue(2, $name); $query->bindValue(3, $email); $query->bindValue(4, $post); $query->bindValue(5, $ipaddress); $query->execute(); } }?> <div align="center"> <strong>Give us your feedback?</strong><br /><br /> <?php if (isset($error)) { ?> <small style="color:#aa0000;"><?php echo $error; ?></small><br /><br /> <?php } ?> <form action="episode.php?id=<?php echo $data['cast_id']; ?>" method="post" autocomplete="off" enctype="multipart/form-data"> <input type="text" name="name" placeholder="Name" /> / <input type="text" name="email" placeholder="Email" /><small style="color:#aa0000;">*</small><br /><br /> <textarea rows="10" cols="50" name="post" placeholder="Comment"></textarea><br /><br /> <input type="submit" onclick="myFunction()" value="Add Comment" /> <br /><br /> <small style="color:#aa0000;">* <b>Email will not be displayed publicly</b></small><br /> </form> </div> Include.php class feedback { public function fetch_all(){ global $pdo; $query = $pdo->prepare("SELECT * FROM comments"); $query->bindValue(1, $cast); $query->execute(); return $query->fetchAll(); } } This code updates to the database as it is suppose to. But after submission it reloads the current page as mentioned in the form action. But when I refresh the page to see the comment being added it asks to re submit. If I hit submit then the comment adds again. How can I stop this from happening? Maybe I could hide the comment box and display a thank you message but that would not stop a repeat entry. Please help. Thank you. Kev

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  • How do I toggle two images using jQuery and radio buttons?

    - by trench
    This isn't pretty, but I think you'll get what I'm trying to do. <label><input name="jpgSel" type="radio" value="0">jpg 1</label><br /> <label><input name="jpgSel" type="radio" value="1">jpg 2</label><br /> <div id="showjpg"></div> and $(document).ready(function() { $("select").change(function () { if ($("jpgSel:checked").val() == 1) { $('#showjpg').attr({ src: 'one.jpg', alt: 'one dot jpg' }); } else { $('#showjpg').attr({ src: 'two.jpg', alt: 'two dot jpg' }); } });

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  • Form submission and hyperlinks using GET and POST

    - by Jon
    I have a search resource, the user can perform searches by filling out a form and submitting it, the create action is called, the Search is saved, the show action is called, and the results are displayed. This all happens with the default POST, and all works fine. The user may want to save his search in the saved_search table (i don't use the Search table for this purpose as this table stores all searches for the purpose of compiling statistics, and gets cleared on a regular basis). Once the Search is saved, it can be re-run by clicking a hyperlink, this is where i start to get problems. I see no way of getting my hyperlink to run the create action of Search, with a POST request, and the necessary data. I then decided to try to get both form submission and the hyperlink to perform a search using a GET request, i was unable to get form_for to run my Search create action using a GET request, it always seems to get routed to my index action. Can someone suggest a good restful solution to this problem please. Many thanks

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  • Perform function on form submit

    - by flight643
    Hopefully this is a pretty simple question! I've got the code working in jQuery to listen for a specific form on a page to be submitted and perform an alert when it is.. I.e.: The form itself doesn't have a name so I am targetting the form within a specific form ID. $("#content form").submit(function() { alert("lorem ipsum dolor?"); }); What would be the syntax for performing this in javascript alone without using jquery? For example, I have this code (below) and just am unsure of how to listen for the form to be submitted to perform an action.. var submitform = document.getElementById("content").getElementsByTagName("form"); Thanks!

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  • Make form redirect users after posting

    - by Liso22
    I need to change a form so that instead of reloading the page after submitting it, it redirects the user to another page, this is the form: <form class="questionform" name="questionform-0" id="questionform-0"> <textarea class="question-box" cols="12" rows="5" id="question-box-' . $questionformid . '" name="title" type="text" maxlength="200" size="28"></textarea> <input type="text" class="ubicacion" value="" name="question"> <input type="button" name="ask" value="Publicar" onclick="askquestion('questionform-0'); window.location.reload(true);"> I want to remove the window.location.reload and change it for a redirect that sends users to the page their comment will appear. Which is: www.chusmix.com/s?= (the content of the second field) The problem is that the content of the second field is part of the url I want to redirect, it's not simply always the same URL. So I have no idea how to do it. How do I do it? Anyway thanks for any info or whatever that points me on the right direction. Thanks

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  • How do I pass the value of input fields on one html page to input fields on another html page using dojo

    - by Amen
    I am trying to pass the values of input fields on one html page to another html page that has a form with input fields. How do I write the dojo or JavaScript code to accomplish this? <form id="form1" method="post" action="form2.html"> First Name: <input id="tFName" name="tFName" type="text" tabindex="0" iclass="isCompleted" maxlength="50" /> <br/> <br/> Last Name: <input id="tLName" name="tFName" type="text" tabindex="0" iclass="isCompleted" maxlength="50" /> <br/> <input type='submit' value='Submit'/> </form> here is form 2: <form id="form"> First Name: <input id="tFName" name="tFName" type="text" tabindex="0" iclass="isCompleted" maxlength="50" /> <br/> <br/> Last Name: <input id="tLName" name="tFName" type="text" tabindex="0" iclass="isCompleted" maxlength="50" /> <br/> <input type='submit' value='Save Your Name'/> </form>

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  • Hit external url from code-behind

    - by Steven
    I have a form on my site. The user enters their e-mail and selects a location from a dropdown. I then need to post that data to an external site by hitting a url with the user's location and e-mail in the query string. I'm doing this like so: string url = "http://www.site.com/page.aspx?location=" + location.Text + "&email=" + email.Text; HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url); HttpWebResponse response = (HttpWebResponse)request.GetResponse(); My client says that I am not hitting their server, but when going through the debugger, I'm getting a response from their server. I also tried tracking what was happening by using Firebug, and I noticed that there was no POST made to that external site. What am I doing wrong here?

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  • Trouble with jQuery Form Validation

    - by Sennheiser
    I'm making a form that has the following validation rules: no fields are "required", but if you enter an email, it must be valid, and if you enter a password, it must be at least 6 characters and match the confirm password field value. The form works flawlessly with no validation so I know it's not a PHP or HTML problem. Here's the jQuery code handling the form: $('#success').hide(); $('#pwerror').hide(); $('#emailError').hide(); $('#subSet').live('click',function() { //if any of the fields have a value if($("#chfn").val() != "" || $("#chln").val() != "" || $("#chpw").val() != "" || $("#chpw2").val() != "" || $("#chem").val() != "") { $ev = 1; $pv = 1; //validates an email if there is one, trips the valid variable flag if($("#chem").val() != "") { $("#profSet").validate({ rules: { chem: { email: true }, chpw: { required: false, minlength: 6 }, chpw2: { required: false, minlength: 6, equalTo: $("#chpw").val() } }, messages:{ chpw2: { equalTo: "Passwords must be the same." }, chpw: { minlength: "Password must be at least 6 characters." } } }); if(!($("#profSet").valid())) { $ev = 0; } } //if either password field is filled, start trying to validate it if($("#chpw").val() != "" || $("#chpw2").val() != "") { if(!($("#profSet").valid())) { $pv = 0; } } //if those two were valid if($pv == 1 && $ev == 1) { $.post('php/profSet.php', $('#profSet').serialize(), function(){ $('#profSet').hide(); $('#success').show(); }); } //if either was invalid, the error was already tripped, and this code exits here } }); The problem I'm having now is that the "passwords must be the same" error keeps getting triggered even if both fields are blank, or if they actually are the same. Therefore, the form cannot submit. Any help?

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  • Set hidden form field values with JavaScript but request still empty

    - by tigerstyle
    HI volks, I try to set some hidden form field values with an onclick event. Ok, after I did something like this: document.getElementById('hidden_field').value = 123; I can output the value with the firebug console by entering this: alert(document.getElementById('hidden_field').value); So the values are definitely set. But now when I submit the form, the hidden field values are still empty. Do you have any idea whats going wrong? Thx for your answers.

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  • hide inputs value when input is hidden

    - by toingbou
    Hello, im using this function to hide some inputs from a form when a value selected in select tag. this is the function: function showEntry(obj,optionValue){ //hide all entry selections onchange document.getElementById("group1").style.display="none"; document.getElementById("group2").style.display="none"; if(obj.value=="group1") { document.getElementById('group1').style.display="inline"; } else if(obj.value=="group2") { document.getElementById('group2').style.display="inline"; } } and this is the form: <select class="textinput" name="function_title" onchange="showEntry(this,this.value);"> <option value=""> </option> <option value="group1" >group1</option> <option value="group2" >group2</option> </select> <span id="group1" style="display:none;"> <input class="textinput" type="text" id="input1" name="input1" value="100"/> <input class="textinput" type="text" id="input2" name="input2" value="50"/> </span> <span id="group2" style="display:none;"> <input class="textinput" type="text" id="input3" name="input3" value="60"/> <input class="textinput" type="text" id="input4" name="input4" value="45"/> </span> All i want is to hide the hidden inputs value when this group of inputs are hidden. Something like that: <input class="textinput" type="text" id="input3" name="input3" value="if(obj.value!="group2") { print(60); }"/> Is that right?

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  • Ruby on Rails: create records for multiple models with one form and one submit

    - by notblakeshelton
    I have a 3 models: quote, customer, and item. Each quote has one customer and one item. I would like to create a new quote, a new customer, and a new item in their respective tables when I press the submit button. I have looked at other questions and railscasts and either they don't work for my situation or I don't know how to implement them. I also want my index page to be the page where I can create everything. quote.rb class Quote < ActiveRecord::Base attr_accessible :quote_number has_one :customer has_one :item end customer.rb class Customer < ActiveRecord::Base #unsure of what to put here #a customer can have multiple quotes, so would i use: has_many :quotes #<----? end item.rb class Item < ActiveRecord::Base #also unsure about this #each item can also be in multiple quotes quotes_controller.rb class QuotesController < ApplicationController def index @quote = Quote.new @customer = Customer.new @item = item.new end def create @quote = Quote.new(params[:quote]) @quote.save @customer = Customer.new(params[:customer]) @customer.save @item = Item.new(params[:item]) @item.save end end items_controller.rb class ItemsController < ApplicationController def index end def new @item = Item.new end def create @item = Item.new(params[:item]) @item.save end end customers_controller.rb class CustomersController < ApplicationController def index end def new @customer = Customer.new end def create @customer = Customer.new(params[:customer]) @customer.save end end quotes/index.html.erb <%= form_for @quote do |f| %> <%= f.fields_for @customer do |builder| %> <%= label_tag :firstname %> <%= builder.text_field :firstname %> <%= label_tag :lastname %> <%= builder.text_field :lastname %> <% end %> <%= f.fields_for @item do |builder| %> <%= label_tag :name %> <%= builder.text_field :name %> <%= label_tag :description %> <%= builder.text_field :description %> <% end %> <%= label_tag :quote_number %> <%= f.text_field :quote_number %> <%= f.submit %> <% end %> When I try submitting that I get an error: Can't mass-assign protected attributes: item, customer So to try and fix it I updated the attr_accessible in quote.rb to include :item, :customer but then I get this error: Item(#) expected, got ActiveSupport::HashWithIndifferentAccess(#) Any help would be greatly appreciated.

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  • Does Spring MVC form submit data bind children objects automagically?

    - by predhme
    I have a data model that is something like this: public class Report { // report owner private User user; ... typical getter setter ... } public class User { ... omitted for clarity } What happens is when a report is created, the current user is set to the report user object. When the report is edited, the spring controller handling the POST request is receiving a report where the user object is null. Here is what my controller looks like: @Controller @RequestMapping("/report") public class ReportController { @RequestMapping(value = "/edit/{id}", method = RequestMethod.GET) public String editReport(@PathVariable Long id, Model model) { Report r = backend.getReport(id); // fully loads object model.addAttribute("report", report); return "report/edit"; } @RequestMapping(value = "/edit/{id}", method = RequestMethod.POST) public String process(@ModelAttribute("report") Report r) { backend.save(r); return "redirect:/report/show" + r.getId(); } } I ran things throw the debugger and it looks like in the editReport method the model object is storing the fully loaded report object (I can see the user inside the report). On the form jsp I can do the following: ${report.user.username} and the correct result is rendered. However, when I look at the debugger in the process method, the passed in Report r has a null user. I don't need to do any special data binding to ensure that information is retained do I?

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  • Instantiate a form, then find it later, without showing it initially

    - by awilson53
    I am having a problem that is strange to me but hopefully is not so strange to someone else. : ) Some background: I am working on a simple IM client that allows the user to broadcast messages to multiple recipients. The goal is to create a chat form for each of the recipients containing the text of the broadcast message, then show that form only if the recipient responds to the broadcast-er. However, when the application receives a response then attempts to locate the form for that particular chat session (using Application.OpenForms) it cannot find it UNLESS I .Show at the time it is created. I would like to avoid having to show this form when it is created because this means that the user will see a flash on the screen. The form doesn't seem to really be created until I show it, but it would seem there has to be a way to do this without showing first. Can anyone assist? I can provide code snippets if needed, I didn't in this post because this feels more like a conceptual misunderstanding on my part than a bug in the code. Thanks in advance!

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  • Customizing Django Form: Required and InputId?

    - by Mark
    I'm trying to customize how my form is displayed by using a form_snippet as suggested in the docs. Here's what I've come up with so far: {% for field in form %} <tr> <th><label for="{{ field.html_name }}">{{ field.label }}:</label></th> <td> {{ field }} {% if field.help_text %}<br/><small class="help_text">{{ field.help_text }}</small>{% endif %} {{ field.errors }} </td> </tr> {% endfor %} Of course, field.html_name is not what I'm looking for. I need the id of the input field. How can I get that? Also, is there a way I can determine if the field is required, so that I can display an asterisk beside the label?

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  • Form Search Onkeyup event

    - by Aryan
    I Have a Form In which the form should automatically search when i complete entering the 10th character in the text field but the below code is searching for each n every character i enter in the text field . . . I just want the result after completing the 10th character not for each n every character . . i have used onkeyup event and i set that value to 10 but still it is searching for each n every character... please do help me <body OnKeyPress="return disableKeyPress(event)"> <section id="content" class="container_12 clearfix" data-sort=true> <center><table class='dynamic styled with-prev-next' data-table-tools='{'display':true}' align=center> <script> function disableEnterKey(e) { var key; if(window.event) key = window.event.keyCode; //IE else key = e.which; //firefox return (key != 13); } function showUser(str) { if (str=="") { document.getElementById("txtHint").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("txtHint").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","resdb.php?id="+str,true); xmlhttp.send(); } </script> <script type='text/javascript'> //<![CDATA[ $(window).load(function(){ $('#id').keyup(function(){ if(this.value.length ==10) }); });//]]> </script> <form id="form" method="post" name="form" > <tr><td><p align="center"><font size="3"><b>JNTUH - B.Tech IV Year II Semester (R07) Advance Supplementary Results - July 2012</b></font></p></td></tr> <td><p align="center"><b>Last Date for RC/RV : 8th August 2012</b></p></td> <tr><td><p align="center"></b> <input type="text" onkeyup="showUser(this.value)" onKeyPress="return disableEnterKey(event)" data-type="autocomplete" data-source="extras/autocomplete1.php" name="id" id="id" maxlength="10" placeholder=" Hall-Ticket Number">&emsp;</p></td></tr> </table> </center> </form> <center> <div id="txtHint"><b>Results will be displayed here</b></div> </center> </body>

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  • Visual Basic: Newbie questions.

    - by Omega
    Hello there. I am starting to learn visual basic. So far, it is quite simple and easy to use. I am liking it! Anyway, I want to make applications a little bit more complex. So far I have done very silly things. I would appreciate if you could help me with these: How do I open a new window (form)? Maybe I click a button on my main form and another form pops up. How do I "deactivate" the main form while the new form is running? (if I try to click the main form, an error sound plays) So my second form has a text field and a "OK" button. If I click it, the second form closes activating the main form again. I want to "pass" the text in the text field from the second form to the first one. How do I do that? Thank you, I am enjoying this new programming environment (didn't use Visual Studio much before)

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  • $_POST Variable Detected in Chrome but not in Firefox

    - by user1707973
    I am using 2 images in a form to sort out query results from the database. The form is submitted using the POST method. When i click on the first image, the query results have to be sorted in ascending order, and when i click on the second, the results have to be sorted in the descending order. This is the code for the form: <form name="" action="" method="post"> <input type="hidden" name="typep" value="price" /> <input type="image" name="sort" value="asc" src="images/asc-ar.png" /> <input type="image" name="sort" value="desc" src="images/dsc-ar.png" /> </form> Now this is the code for checking if the $_REQUEST['sort'] variable is set and therefore whether sorting is required or not. if ($_REQUEST['sort'] != "") { $sort = $_REQUEST['sort']; $typep = $_REQUEST['typep']; //query to be executed depending on values of $sort and $typep } Firefox does detect the $_REQUEST['typep'] variable but not the $_REQUEST['sort'] one. This works perfectly in Chrome though. When i test the site in Firefox, it doesn't detect the $_REQUEST['sort'] variable and therefore the if condition evaluates to false and the search results don't get sorted.

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  • Pass PHP variables without being seen when working with a database generated list

    - by Wilcoholic
    Looking for any help regarding the problem. Here's the deal: I have a database that has a teams table and it contains team_id. On one of my pages, I generate a list of links that contain the team_id of the creator in their get URL. I need the team_id on the next page but can't figure out how to pass it through any other way. Using a form and POST isn't an option because this method would only pass through the last links data on the list. Storing in a session isn't an option either because there is no way to discretely pass the the variables I need to a function to set the session variables. I have tried and it can pretty easily be viewed from viewing the source code. So here's some sample code to see exactly what I'm dealing with. <? if(mysql_num_rows($result2)>0){ ?> <a class="fltrt btn btn-danger btn-small" onclick="test()" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=cancel">Cancel Match</a> <?}else{?> <a class="fltrt btn btn-success btn-small" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=accept">Accept Match</a> <?} ?> The code above is generated multiple times on a page via a while loop that was excluded. I want to pass the match_id and team_id variables without being seen anywhere. If I made this a form, it wouldn't pass the correct variables unless there is only one result at the time (not likely). I'm sure there has to be an easy method that is eluding me, so please share thoughts on how to solve this. I feel as though I am not explaining it well enough, but it's not really easy to explain. I basically want something that works like GET but acts like POST and can be hidden from people viewing source code or link locations. Thanks

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  • prevent form from automatically re-submitting on page load

    - by user323774
    I am using jQuery to point a form's target to an iframe on .submit(). This is to upload a file. It works fine, but when the page reloads, and the iframe is appended to the DOM, the iframe automatically resubmits the form, causing the same file to be sent to the server on each page load. If I do not include the iframe in the HTML markup, or do not append it to the DOM, this doesn't happen, but of course, I need the iFrame. So my question is, how can i prevent this? :) Andrew

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  • Persisting object changes from child form to parent form based on button press.

    - by Shyran
    I have created a form that is used for both adding and editing a custom object. Which mode the form takes is provided by an enum value passed from the calling code. I also pass in an object of the custom type. All of my controls at data bound to the specific properties of the custom object. When the form is in Add mode, this works great as when the controls are updated with data, the underlying object is as well. However, in Edit mode, I keep two variables of the custom object supplied by the calling code, the original, and a temporary one made through deep copying. The controls are then bound to the temporary copy, this makes it easy to discard the changes if the user clicks the Cancel button. What I want to know is how to persist those changes back to the original object if the user clicks the OK button, since there is now a disconnect because of the deep copying. I am trying to avoid implementing a internal property on the Add/Edit form if I can. Below is an example of my code: public AddEditCustomerDialog(Customer customer, DialogMode mode) { InitializeComponent(); InitializeCustomer(customer, mode); } private void InitializeCustomer(Customer customer, DialogMode mode) { this.customer = customer; if (mode == DialogMode.Edit) { this.Text = "Edit Customer"; this.tempCustomer = ObjectCopyHelper.DeepCopy(this.customer); this.customerListBindingSource.DataSource = this.tempCustomer; this.phoneListBindingSource.DataSource = this.tempCustomer.PhoneList; } else { this.customerListBindingSource.DataSource = this.customer; this.phoneListBindingSource.DataSource = this.customer.PhoneList; } }

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  • Form wont stay on top. How do I keep my excel form from hiding behind other windows after I browse

    - by ScottK
    I have a vb.net program that opens up an excel workbook and runs a macro ("Report") in that workbook when a button is clicked. //Workbook with macro and form xlWorkbook = xlApp.Workbooks.Open("W:Data\Excel Program.xls") //Macro: xlApp.Run("Report") //Macro opens form from workbook. I browse for my two .csv files //and then click a button to run code that creates my reports. //form closes, show the excel report after its created xlApp.Visible = True After I browse my first file and select it so that its location is displayed in my text box, the excel form then hides behind any open windows. I want this form to stay on top. It is after this code executes that the form will hide behind all other open windows: Private Sub btnBrowseFile1_Click() Dim fileName1 As String fileName1 = Application.GetOpenFilename("CSV file (*.csv), *.csv") If fileName1 <> "False" Then Me.txtFileName1.text = fileName1 End If End Sub EDIT: I still have no luck with this problem. When the excel macro is opened from a vb program I have this hiding issue...but only after browsing for a file. Why does the focus leave the form and go to Windows after browsing a file? Any one have any suggestions?

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  • How do I submit a form from another page?

    - by Tommy
    I have a two page site. Each page contains a header with "tabs" at the top, to navigate between page 1 and 2. When a tab is selected, I need the selected page to re-POST to the server, to quickly refresh before it is displayed. I have a form on each page that allows a manual refresh from that page but need to submit that form from the other page. For example, page 2 is displayed. The tab for page 1 is selected (which is on page 2) It should then submit the refresh form on page 1. Any help is appreciated. (Using jQuery, js, html and CSS)

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