Search Results

Search found 14302 results on 573 pages for 'saved password'.

Page 79/573 | < Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >

  • Exchange 2003: Accounts with only OWA access unable to change passwords when expired or forced

    - by radioactive21
    We have accounts whith only OWA access, because they are generic accounts and we do not want the accounts to be used as machine logins. We have a password policy that users must change their passwords every 6 months. The problem we are having is that since the accounts are not loging into the machines, when the password policy kicks in it is preventing users with OWA only access from changing their password. Also, when we select "User must change the password at next logon" it also causes the same issue. We have two exchange servers the main one and a front end one. what we have been doing with these generic account is in properties, under the "account" tab we restricted "log on to" to the front end server. Just to clarify, when we have no restrictions, users can change their passwords via the web without any issues. It is only when we force them to only login via OWA that they cant change passwords. I tried adding our domain controler and main exchange server to the "This user can log on to The following computers" in the account tab, but still it is not allowing them to change passwords. Currently I have to manually reset the passwords for OWA only accounts. Is there anyway to allow OWA acconts to change passwords? EDIT: Users restricted to only OWA can change their password via the web browser without any issues when there are no restrictions. In other words normally they can just log into outlook via the web and change their password, but when the password policy expires or we force them to change their password at next login, they are unable to.

    Read the article

  • Ruby - encrypted_strings

    - by Tom Andersen
    A bit of a Ruby newbie here - should be an easy question: I want to use the encrypted_strings gem to create a password encrypted string: (from http://rdoc.info/projects/pluginaweek/encrypted_strings) Question is: Everything works fine, but how come I don't need the password to decrypt the string? Say I want to store the string somewhere for a while,like the session. Is the password also stored with it? (which would seem very strange?). And no, I'm not planning on using 'secret-key' or any similar hack as a password. I am planning on dynamically generating a class variable @@password using a uuid, which I don't store other than in memory, and can change from one running of the program to the next. Symmetric: >> password = 'shhhh' => "shhhh" >> crypted_password = password.encrypt(:symmetric, :password => 'secret_key') => "qSg8vOo6QfU=\n" >> crypted_password.class => String >> crypted_password == 'shhhh' => true >> password = crypted_password.decrypt => "shhhh"

    Read the article

  • Using pam_python in a script running with mod_python

    - by markys
    Hi ! I would like to develop a web interface to allow users of a Linux system to do certain tasks related to their account. I decided to write the backend of the site using Python and mod_python on Apache. To authenticate the users, I thought I could use python_pam to query the PAM service. I adapted the example bundled with the module and got this: # out is the output stream used to print debug def auth(username, password, out): def pam_conv(aut, query_list, user_data): out.write("Query list: " + str(query_list) + "\n") # List to store the responses to the different queries resp = [] for item in query_list: query, qtype = item # If PAM asks for an input, give the password if qtype == PAM.PAM_PROMPT_ECHO_ON or qtype == PAM.PAM_PROMPT_ECHO_OFF: resp.append((str(password), 0)) elif qtype == PAM.PAM_PROMPT_ERROR_MSG or qtype == PAM.PAM_PROMPT_TEXT_INFO: resp.append(('', 0)) out.write("Our response: " + str(resp) + "\n") return resp # If username of password is undefined, fail if username is None or password is None: return False service = 'login' pam_ = PAM.pam() pam_.start(service) # Set the username pam_.set_item(PAM.PAM_USER, str(username)) # Set the conversation callback pam_.set_item(PAM.PAM_CONV, pam_conv) try: pam_.authenticate() pam_.acct_mgmt() except PAM.error, resp: out.write("Error: " + str(resp) + "\n") return False except: return False # If we get here, the authentication worked return True My problem is that this function does not behave the same wether I use it in a simple script or through mod_python. To illustrate this, I wrote these simple cases: my_username = "markys" my_good_password = "lalala" my_bad_password = "lololo" def handler(req): req.content_type = "text/plain" req.write("1- " + str(auth(my_username,my_good_password,req) + "\n")) req.write("2- " + str(auth(my_username,my_bad_password,req) + "\n")) return apache.OK if __name__ == "__main__": print "1- " + str(auth(my_username,my_good_password,sys.__stdout__)) print "2- " + str(auth(my_username,my_bad_password,sys.__stdout__)) The result from the script is : Query list: [('Password: ', 1)] Our response: [('lalala', 0)] 1- True Query list: [('Password: ', 1)] Our response: [('lololo', 0)] Error: ('Authentication failure', 7) 2- False but the result from mod_python is : Query list: [('Password: ', 1)] Our response: [('lalala', 0)] Error: ('Authentication failure', 7) 1- False Query list: [('Password: ', 1)] Our response: [('lololo', 0)] Error: ('Authentication failure', 7) 2- False I don't understand why the auth function does not return the same value given the same inputs. Any idea where I got this wrong ? Here is the original script, if that could help you. Thanks a lot !

    Read the article

  • BCrypt says long, similar passwords are equivalent - problem with me, the gem, or the field of crypt

    - by PreciousBodilyFluids
    I've been experimenting with BCrypt, and found the following. If it matters, I'm running ruby 1.9.2dev (2010-04-30 trunk 27557) [i686-linux] require 'bcrypt' # bcrypt-ruby gem, version 2.1.2 @long_string_1 = 'f287ed6548e91475d06688b481ae8612fa060b2d402fdde8f79b7d0181d6a27d8feede46b833ecd9633b10824259ebac13b077efb7c24563fce0000670834215' @long_string_2 = 'f6ebeea9b99bcae4340670360674482773a12fd5ef5e94c7db0a42800813d2587063b70660294736fded10217d80ce7d3b27c568a1237e2ca1fecbf40be5eab8' def salted(string) @long_string_1 + string + @long_string_2 end encrypted_password = BCrypt::Password.create(salted('password'), :cost => 10) puts encrypted_password #=> $2a$10$kNMF/ku6VEAfLFEZKJ.ZC.zcMYUzvOQ6Dzi6ZX1UIVPUh5zr53yEu password = BCrypt::Password.new(encrypted_password) puts password.is_password?(salted('password')) #=> true puts password.is_password?(salted('passward')) #=> true puts password.is_password?(salted('75747373')) #=> true puts password.is_password?(salted('passwor')) #=> false At first I thought that once the passwords got to a certain length, the dissimilarities would just be lost in all the hashing, and only if they were very dissimilar (i.e. a different length) would they be recognized as different. That didn't seem very plausible to me, from what I know of hash functions, but I didn't see a better explanation. Then, I tried shortening each of the long_strings to see where BCrypt would start being able to tell them apart, and I found that if I shortened each of the long strings to 100 characters or so, the final attempt ('passwor') would start returning true as well. So now I don't know what to think. What's the explanation for this?

    Read the article

  • Rails dealing with blank params at controller level

    - by stephenmurdoch
    I have a User model: class User < ActiveRecord::Base has_secure_password # validation lets users update accounts without entering password validates :password, presence: { on: :create }, allow_blank: { on: :update } validates :password_confirmation, presence: { if: :password_digest_changed? } end I also have a password_reset_controller: def update # this is emailed to the user by the create action - not shown @user=User.find_by_password_reset_token!(params[:id]) if @user.update_attributes(params[:user]) # user is signed in if password and confirmation pass validations sign_in @user redirect_to root_url, :notice => "Password has been reset." else flash.now[:error] = "Something went wrong, please try again." render :edit end end Can you see the problem here? A user can submit a blank a password/confirmation and rails will sign them in, because the User model allows blank on update. It's not a security concern, since an attacker would still need access to a user's email account before they could get anywhere near this action, but my problem is that a user submitting 6 blank chars would be signed in, and their password would not be changed for them, which could lead to confusion later on. So, I've come up with the following solution, and I'd like to check if there's a better way of doing it, before I push to production: def update @user=User.find_by_password_reset_token!(params[:id]) # if user submits blank password, add an error, and render edit action if params[:user][:password].blank? @user.errors.add(:password_digest, "can't be blank.") render :edit elsif @user.update_attributes(params[:user]) sign_in @user redirect_to root_url, :notice => "Password has been reset." else flash.now[:error] = "Something went wrong, please try again." render :edit end end Should I be checking for nil as well as blank? Are there any rails patterns or idiomatic ruby techniques for solving this? [Fwiw, I've got required: true on the html inputs, but want this handled server side too.]

    Read the article

  • Mpd as pppoe server with authorisation by freeradius2

    - by Korjavin Ivan
    I install freeradius2, add to raddb/users: test Cleartext-Password := "test1" Service-Type = Framed-User, Framed-Protocol = PPP, Framed-IP-Address = 10.36.0.2, Framed-IP-Netmask = 255.255.255.0, start radiusd, and check auth: radtest test test1 127.0.0.1 1002 testing123 Sending Access-Request of id 199 to 127.0.0.1 port 1812 User-Name = "test" User-Password = "test1" NAS-IP-Address = 127.0.0.1 NAS-Port = 1002 Message-Authenticator = 0x00000000000000000000000000000000 rad_recv: Access-Accept packet from host 127.0.0.1 port 1812, id=199, length=44 Service-Type = Framed-User Framed-Protocol = PPP Framed-IP-Address = 10.36.0.2 Framed-IP-Netmask = 255.255.255.0 Works fine. Next step. Add to mpd.conf: radius: set auth disable internal set auth max-logins 1 CI set auth enable radius-auth set radius timeout 90 set radius retries 2 set radius server 127.0.0.1 testing123 1812 1813 set radius me 127.0.0.1 create link template L pppoe set link action bundle B set link max-children 1000 set link no multilink set link no shortseq set link no pap chap-md5 chap-msv1 chap-msv2 set link enable chap set pppoe acname Internet load radius create link template em1 L set pppoe iface em1 set link enable incoming And trying to connect, auth failed, here is mpd log: mpd: [em1-2] LCP: auth: peer wants nothing, I want CHAP mpd: [em1-2] CHAP: sending CHALLENGE #1 len: 21 mpd: [em1-2] LCP: LayerUp mpd: [em1-2] CHAP: rec'd RESPONSE #1 len: 58 mpd: [em1-2] Name: "test" mpd: [em1-2] AUTH: Trying RADIUS mpd: [em1-2] RADIUS: Authenticating user 'test' mpd: [em1-2] RADIUS: Rec'd RAD_ACCESS_REJECT for user 'test' mpd: [em1-2] AUTH: RADIUS returned: failed mpd: [em1-2] AUTH: ran out of backends mpd: [em1-2] CHAP: Auth return status: failed mpd: [em1-2] CHAP: Reply message: ^AE=691 R=1 mpd: [em1-2] CHAP: sending FAILURE #1 len: 14 mpd: [em1-2] LCP: authorization failed Then i start freeradius as radiusd -fX, and get this log: rad_recv: Access-Request packet from host 127.0.0.1 port 46400, id=223, length=282 NAS-Identifier = "rubin.svyaz-nt.ru" NAS-IP-Address = 127.0.0.1 Message-Authenticator = 0x14d36639bed8074ec2988118125367ea Acct-Session-Id = "815965-em1-2" NAS-Port = 2 NAS-Port-Type = Ethernet Service-Type = Framed-User Framed-Protocol = PPP Calling-Station-Id = "00e05290b3e3 / 00:e0:52:90:b3:e3 / em1" NAS-Port-Id = "em1" Vendor-12341-Attr-12 = 0x656d312d32 Tunnel-Medium-Type:0 = IEEE-802 Tunnel-Client-Endpoint:0 = "00:e0:52:90:b3:e3" User-Name = "test" MS-CHAP-Challenge = 0xbb1e68d5bbc30f228725a133877de83e MS-CHAP2-Response = 0x010088746ae65b68e435e9d045ad6f9569b60000000000000000b56991b4f20704cb6c68e5982eec5e98a7f4b470c109c1b9 # Executing section authorize from file /usr/local/etc/raddb/sites-enabled/default +- entering group authorize {...} ++[preprocess] returns ok ++[chap] returns noop [mschap] Found MS-CHAP attributes. Setting 'Auth-Type = mschap' ++[mschap] returns ok [eap] No EAP-Message, not doing EAP ++[eap] returns noop [files] users: Matched entry DEFAULT at line 172 ++[files] returns ok Found Auth-Type = MSCHAP # Executing group from file /usr/local/etc/raddb/sites-enabled/default +- entering group MS-CHAP {...} [mschap] No Cleartext-Password configured. Cannot create LM-Password. [mschap] No Cleartext-Password configured. Cannot create NT-Password. [mschap] Creating challenge hash with username: test [mschap] Client is using MS-CHAPv2 for test, we need NT-Password [mschap] FAILED: No NT/LM-Password. Cannot perform authentication. [mschap] FAILED: MS-CHAP2-Response is incorrect ++[mschap] returns reject Failed to authenticate the user. Login incorrect: [test] (from client localhost port 2 cli 00e05290b3e3 / 00:e0:52:90:b3:e3 / em1) Using Post-Auth-Type REJECT # Executing group from file /usr/local/etc/raddb/sites-enabled/default +- entering group REJECT {...} [attr_filter.access_reject] expand: %{User-Name} -> test attr_filter: Matched entry DEFAULT at line 11 ++[attr_filter.access_reject] returns updated Delaying reject of request 2 for 1 seconds Going to the next request Waking up in 0.9 seconds. Sending delayed reject for request 2 Sending Access-Reject of id 223 to 127.0.0.1 port 46400 MS-CHAP-Error = "\001E=691 R=1" Why i have error "[mschap] No Cleartext-Password configured. Cannot create LM-Password." ? I define cleartext-password in users. I check raddb/sites-enabled/default authorize { chap mschap eap { ok = return } files } looks ok for me. Whats wrong with mpd/chap/radius ?

    Read the article

  • SSH error: Permission denied, please try again

    - by Kamal
    I am new to ubuntu. Hence please forgive me if the question is too simple. I have a ubuntu server setup using amazon ec2 instance. I need to connect my desktop (which is also a ubuntu machine) to the ubuntu server using SSH. I have installed open-ssh in ubuntu server. I need all systems of my network to connect the ubuntu server using SSH (no need to connect through pem or pub keys). Hence opened SSH port 22 for my static IP in security groups (AWS). My SSHD-CONFIG file is: # Package generated configuration file # See the sshd_config(5) manpage for details # What ports, IPs and protocols we listen for Port 22 # Use these options to restrict which interfaces/protocols sshd will bind to #ListenAddress :: #ListenAddress 0.0.0.0 Protocol 2 # HostKeys for protocol version 2 HostKey /etc/ssh/ssh_host_rsa_key HostKey /etc/ssh/ssh_host_dsa_key HostKey /etc/ssh/ssh_host_ecdsa_key #Privilege Separation is turned on for security UsePrivilegeSeparation yes # Lifetime and size of ephemeral version 1 server key KeyRegenerationInterval 3600 ServerKeyBits 768 # Logging SyslogFacility AUTH LogLevel INFO # Authentication: LoginGraceTime 120 PermitRootLogin yes StrictModes yes RSAAuthentication yes PubkeyAuthentication yes #AuthorizedKeysFile %h/.ssh/authorized_keys # Don't read the user's ~/.rhosts and ~/.shosts files IgnoreRhosts yes # For this to work you will also need host keys in /etc/ssh_known_hosts RhostsRSAAuthentication no # similar for protocol version 2 HostbasedAuthentication no # Uncomment if you don't trust ~/.ssh/known_hosts for RhostsRSAAuthentication #IgnoreUserKnownHosts yes # To enable empty passwords, change to yes (NOT RECOMMENDED) PermitEmptyPasswords no # Change to yes to enable challenge-response passwords (beware issues with # some PAM modules and threads) ChallengeResponseAuthentication no # Change to no to disable tunnelled clear text passwords #PasswordAuthentication yes # Kerberos options #KerberosAuthentication no #KerberosGetAFSToken no #KerberosOrLocalPasswd yes #KerberosTicketCleanup yes # GSSAPI options #GSSAPIAuthentication no #GSSAPICleanupCredentials yes X11Forwarding yes X11DisplayOffset 10 PrintMotd no PrintLastLog yes TCPKeepAlive yes #UseLogin no #MaxStartups 10:30:60 #Banner /etc/issue.net # Allow client to pass locale environment variables AcceptEnv LANG LC_* Subsystem sftp /usr/lib/openssh/sftp-server # Set this to 'yes' to enable PAM authentication, account processing, # and session processing. If this is enabled, PAM authentication will # be allowed through the ChallengeResponseAuthentication and # PasswordAuthentication. Depending on your PAM configuration, # PAM authentication via ChallengeResponseAuthentication may bypass # the setting of "PermitRootLogin without-password". # If you just want the PAM account and session checks to run without # PAM authentication, then enable this but set PasswordAuthentication # and ChallengeResponseAuthentication to 'no'. UsePAM yes Through webmin (Command shell), I have created a new user named 'senthil' and added this new user to 'sudo' group. sudo adduser -y senthil sudo adduser senthil sudo I tried to login using this new user 'senthil' in 'webmin'. I was able to login successfully. When I tried to connect ubuntu server from my terminal through SSH, ssh senthil@SERVER_IP It asked me to enter password. After the password entry, it displayed: Permission denied, please try again. On some research I realized that, I need to monitor my server's auth log for this. I got the following error in my auth log (/var/log/auth.log) Jul 2 09:38:07 ip-192-xx-xx-xxx sshd[3037]: pam_unix(sshd:auth): authentication failure; logname= uid=0 euid=0 tty=ssh ruser= rhost=MY_CLIENT_IP user=senthil Jul 2 09:38:09 ip-192-xx-xx-xxx sshd[3037]: Failed password for senthil from MY_CLIENT_IP port 39116 ssh2 When I tried to debug using: ssh -v senthil@SERVER_IP OpenSSH_5.9p1 Debian-5ubuntu1, OpenSSL 1.0.1 14 Mar 2012 debug1: Reading configuration data /etc/ssh/ssh_config debug1: /etc/ssh/ssh_config line 19: Applying options for * debug1: Connecting to SERVER_IP [SERVER_IP] port 22. debug1: Connection established. debug1: identity file {MY-WORKSPACE}/.ssh/id_rsa type 1 debug1: Checking blacklist file /usr/share/ssh/blacklist.RSA-2048 debug1: Checking blacklist file /etc/ssh/blacklist.RSA-2048 debug1: identity file {MY-WORKSPACE}/.ssh/id_rsa-cert type -1 debug1: identity file {MY-WORKSPACE}/.ssh/id_dsa type -1 debug1: identity file {MY-WORKSPACE}/.ssh/id_dsa-cert type -1 debug1: identity file {MY-WORKSPACE}/.ssh/id_ecdsa type -1 debug1: identity file {MY-WORKSPACE}/.ssh/id_ecdsa-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.8p1 Debian-7ubuntu1 debug1: match: OpenSSH_5.8p1 Debian-7ubuntu1 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.9p1 Debian-5ubuntu1 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: sending SSH2_MSG_KEX_ECDH_INIT debug1: expecting SSH2_MSG_KEX_ECDH_REPLY debug1: Server host key: ECDSA {SERVER_HOST_KEY} debug1: Host 'SERVER_IP' is known and matches the ECDSA host key. debug1: Found key in {MY-WORKSPACE}/.ssh/known_hosts:1 debug1: ssh_ecdsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: password debug1: Next authentication method: password senthil@SERVER_IP's password: debug1: Authentications that can continue: password Permission denied, please try again. senthil@SERVER_IP's password: For password, I have entered the same value which I normally use for 'ubuntu' user. Can anyone please guide me where the issue is and suggest some solution for this issue?

    Read the article

  • Creating a secure SQL server login - CHECK_EXPIRATION & CHECK_POLICY

    - by cabhilash
    In SQL Server you can create users using T-SQL or using the options provided by SQL Server Management Studio.   CREATE LOGIN sql_user WITH PASSWORD ='sql_user_password' MUST_CHANGE, DEFAULT_DATABASE = defDB, CHECK_EXPIRATION = ON, CHECK_POLICY = ONAs mentioned in the previous article (http://weblogs.asp.net/cabhilash/archive/2010/04/07/login-failed-for-user-sa-because-the-account-is-currently-locked-out-the-system-administrator-can-unlock-it.aspx) when CHECK_POLICY = ON user account follows the password rules provided in the system on which the SQL server is installed. When MUST_CHANGE keyword is used user is forced to change the password when he/she tries to login for the first time. CHECK_EXPIRATION and CHECK_POLICY are only enforced on Windows Server 2003 and later. If you want to turn off the password expiration enforcement or security policy enforcement, you can do by using the following statements. (But these wont work if you have created your login with MUST_CHANGE and user didn't change the default password) ALTER LOGIN sql_login WITH CHECK_EXPIRATION = OFF go ALTER LOGIN sql_login WITH CHECK_POLICY = OFF

    Read the article

  • Authentication failure!

    - by veera
    At the time of installation i gave login password and that was the login keyring password and authentication password.. then once in user accounts-login options in dat for password options i set as none and then i locked.. after that the passwd which i gave at the time of installation remained as login keyring passwd but wen i entered that passwd for authentication while installing some packages it's showing authentication failure.pls try again.. so i couldnt download any packages or updates.. is there any possibilities to change/reset the authentication password.. pls help me..

    Read the article

  • Would you consider using training/mentoring from LearnersParadise.com?

    - by HK1
    My initial question deserves some explanation. I signed up for an account at learnersparadise.com. After signing up I couldn't login so I opted to use their "send password" feature. Upon receiving my password in my email I confirmed two things A) They trimmed off 2 of the last digits of my 10-digit password without informing me and saved it that way in their database B) my password is not saved in their database using a one-way hash since they were able to email me my password. I'm quite certain that both of these are perfectly awful programming practices. I suspect that the mentors/trainers at learnersparadise are not necessarily affiliated with the website and it's design since they are basically people like you and me (hopefully more skill than me) who have signed up to become mentors. However, I'm still uncertain about signing up for training/mentoring at a site that uses such poor programming practices themselves? Would you let learnersparadise poor programming practices affect your opinion of their trainers/mentors?

    Read the article

  • tomcat6 manager

    - by Bary W Pollack
    I've just installed Ubuntu 10.04 LTS Server with LAMP support. Tomcat6 seems to run ok. But, I am unable to get into the manager-webapp... I've updated the tomcat-users.xml file: <?xml version='1.0' encoding='utf-8'?> <tomcat-users> <role rolename="tomcat"/> <role rolename="role1"/> <role rolename="manager"/> <role rolename="admin"/> <user username="tomcat" password="tomcat" roles="tomcat,manager,admin"/> <user username="both" password="tomcat" roles="tomcat,role1"/> <user username="role1" password="tomcat" roles="role1"/> <user username="admin" password="admin" roles="manager,admin"/> </tomcat-users> But, no matter what I try, it keeps rejecting my username/password combo. What might I be missing?

    Read the article

  • How to execute? [closed]

    - by Viswa
    Possible Duplicate: how to read the password from variable? I did the below code in my python script,but its not work. #! /usr/bin/python import os address = "rsync -avrz [email protected]:/opt/script/python/data/ /opt/script/python/data/" passwd ="my server password" os.system('%(address)s "echo %(passwd)s"' %locals()) it throws below error. If arg is a remote file/dir, prefix it with a colon (:). rsync error: syntax or usage error (code 1) at main.c(1236) [Receiver=3.0.7] If i run os.system('%(address)s' %locals()) means it work without any error but it ask password. I need that password should be read from my passwd variable. How to write python script to read server password from my variable.

    Read the article

  • "Save as webpage, complete" problem ?

    - by Adelave
    i have problem when i am trying to save web page from browser using "Save as Webpage, complete" some of CSS/Javascript/Image are not saved, thus when i reopen saved page offline webpage can't display properly. How do i solve this? How do i made webpage can be saved properly from browser ? i don't want to use MHT ext. Because what my situation here is i need to give URL for web designer to launch URL, saved webpage and modify CSS/HTML. Thanks

    Read the article

  • Problem while running the j2me application

    - by Paru
    I am not able to view any content in the emulator while running the application. The Build is not failed and i am able run the application successfully. While i am closing the emulator i am getting an error. i can provide both code and log here. import javax.microedition.lcdui.; import javax.microedition.midlet.; import java.io.; import java.lang.; import javax.microedition.io.; import javax.microedition.rms.; public class Login extends MIDlet implements CommandListener { TextField ItemName=null; TextField ItemNo=null; TextField UserName=null; TextField Password=null; Form authForm,mainscreen; TextBox t = null; StringBuffer b = new StringBuffer(); private Display myDisplay = null; private Command okCommand = new Command("Login", Command.OK, 1); private Command exitCommand = new Command("Exit", Command.EXIT, 2); private Command sendCommand = new Command("Send", Command.OK, 1); private Command backCommand = new Command("Back", Command.BACK, 2); private Alert alert = null; public Login() { ItemName=new TextField("Item Name","",10,TextField.ANY); ItemNo=new TextField("Item No","",10,TextField.ANY); myDisplay = Display.getDisplay(this); UserName=new TextField("Your Name","",10,TextField.ANY); Password=new TextField("Password","",10,TextField.PASSWORD); authForm=new Form("Identification"); mainscreen=new Form("Logging IN"); mainscreen.addCommand(sendCommand); mainscreen.addCommand(backCommand); authForm.append(UserName); authForm.append(Password); authForm.addCommand(okCommand); authForm.addCommand(exitCommand); authForm.setCommandListener(this); myDisplay.setCurrent(authForm); } public void startApp() throws MIDletStateChangeException { } public void pauseApp() { } protected void destroyApp(boolean unconditional) throws MIDletStateChangeException { } public void commandAction(Command c, Displayable d) { if ((c == okCommand) && (d == authForm)) { if (UserName.getString().equals("") || Password.getString().equals("")){ alert = new Alert("Error", "You should enter Username and Password", null, AlertType.ERROR); alert.setTimeout(Alert.FOREVER); myDisplay.setCurrent(alert); } else{ //myDisplay.setCurrent(mainscreen); login(UserName.getString(),Password.getString()); } } if ((c == backCommand) && (d == mainscreen)) { myDisplay.setCurrent(authForm); } if ((c == exitCommand) && (d == authForm)) { notifyDestroyed(); } if ((c == sendCommand) && (d == mainscreen)) { if(ItemName.getString().equals("") || ItemNo.getString().equals("")){ } else{ sendItem(ItemName.getString(),ItemNo.getString()); } } } public void login(String UserName,String PassWord) { HttpConnection connection=null; DataInputStream in=null; String url="http://olario.net/submitpost/submitpost/login.php"; OutputStream out=null; try { connection=(HttpConnection)Connector.open(url); connection.setRequestMethod(HttpConnection.POST); connection.setRequestProperty("IF-Modified-Since", "2 Oct 2002 15:10:15 GMT"); connection.setRequestProperty("User-Agent","Profile/MIDP-1.0 Configuration/CLDC-1.0"); connection.setRequestProperty("Content-Language", "en-CA"); connection.setRequestProperty("Content-Length",""+ (UserName.length()+PassWord.length())); connection.setRequestProperty("username",UserName); connection.setRequestProperty("password",PassWord); out = connection.openDataOutputStream(); out.flush(); in = connection.openDataInputStream(); int ch; while((ch = in.read()) != -1) { b.append((char) ch); //System.out.println((char)ch); } //t = new TextBox("Reply",b.toString(),1024,0); //mainscreen.append(b.toString()); String auth=b.toString(); if(in!=null) in.close(); if(out!=null) out.close(); if(connection!=null) connection.close(); if(auth.equals("ok")){ mainscreen.setCommandListener(this); myDisplay.setCurrent(mainscreen); } } catch(IOException x){ } } public void sendItem(String itemname,String itemno){ HttpConnection connection=null; DataInputStream in=null; String url="http://www.olario.net/submitpost/submitpost/submitPost.php"; OutputStream out=null; try { connection=(HttpConnection)Connector.open(url); connection.setRequestMethod(HttpConnection.POST); connection.setRequestProperty("IF-Modified-Since", "2 Oct 2002 15:10:15 GMT"); connection.setRequestProperty("User-Agent","Profile/MIDP-1.0 Configuration/CLDC-1.0"); connection.setRequestProperty("Content-Language", "en-CA"); connection.setRequestProperty("Content-Length",""+ (itemname.length()+itemno.length())); connection.setRequestProperty("itemCode",itemname); connection.setRequestProperty("qty",itemno); out = connection.openDataOutputStream(); out.flush(); in = connection.openDataInputStream(); int ch; while((ch = in.read()) != -1) { b.append((char) ch); //System.out.println((char)ch); } //t = new TextBox("Reply",b.toString(),1024,0); //mainscreen.append(b.toString()); String send=b.toString(); if(in!=null) in.close(); if(out!=null) out.close(); if(connection!=null) connection.close(); if(send.equals("added")){ alert = new Alert("Error", "Send Successfully", null, AlertType.INFO); alert.setTimeout(Alert.FOREVER); myDisplay.setCurrent(alert); } } catch(IOException x){ } } } and the log is pre-init: pre-load-properties: exists.config.active: exists.netbeans.user: exists.user.properties.file: load-properties: exists.platform.active: exists.platform.configuration: exists.platform.profile: basic-init: cldc-pre-init: cldc-init: cdc-init: ricoh-pre-init: ricoh-init: semc-pre-init: semc-init: savaje-pre-init: savaje-init: sjmc-pre-init: sjmc-init: ojec-pre-init: ojec-init: cdc-hi-pre-init: cdc-hi-init: nokiaS80-pre-init: nokiaS80-init: nsicom-pre-init: nsicom-init: post-init: init: conditional-clean-init: conditional-clean: deps-jar: pre-preprocess: do-preprocess: Pre-processing 0 file(s) into /home/sreekumar/NetBeansProjects/Login/build/preprocessed directory. post-preprocess: preprocess: pre-compile: extract-libs: do-compile: post-compile: compile: pre-obfuscate: proguard-init: skip-obfuscation: proguard: post-obfuscate: obfuscate: lwuit-build: pre-preverify: do-preverify: post-preverify: preverify: pre-jar: set-password-init: set-keystore-password: set-alias-password: set-password: create-jad: add-configuration: add-profile: do-extra-libs: nokiaS80-prepare-j9: nokiaS80-prepare-manifest: nokiaS80-prepare-manifest-no-icon: nokiaS80-create-manifest: jad-jsr211-properties.check: jad-jsr211-properties: semc-build-j9: do-jar: nsicom-create-manifest: do-jar-no-manifest: update-jad: Updating application descriptor: /home/sreekumar/NetBeansProjects/Login/dist/Login.jad Generated "/home/sreekumar/NetBeansProjects/Login/dist/Login.jar" is 3501 bytes. sign-jar: ricoh-init-dalp: ricoh-add-app-icon: ricoh-build-dalp-with-icon: ricoh-build-dalp-without-icon: ricoh-build-dalp: savaje-prepare-icon: savaje-build-jnlp: post-jar: jar: pre-run: netmon.check: open-netmon: cldc-run: Copying 1 file to /home/sreekumar/NetBeansProjects/Login/dist/nbrun4244989945642509378 Copying 1 file to /home/sreekumar/NetBeansProjects/Login/dist/nbrun4244989945642509378 Jad URL for OTA execution: http://localhost:8082/servlet/org.netbeans.modules.mobility.project.jam.JAMServlet//home/sreekumar/NetBeansProjects/Login/dist//Login.jad Starting emulator in execution mode Running with storage root /home/sreekumar/j2mewtk/2.5.2/appdb/temp.DefaultColorPhone1 /home/sreekumar/NetBeansProjects/Login/nbproject/build-impl.xml:915: Execution failed with error code 143. BUILD FAILED (total time: 35 seconds)

    Read the article

  • Using AES encryption in .NET - CryptographicException saying the padding is invalid and cannot be removed

    - by Jake Petroules
    I wrote some AES encryption code in C# and I am having trouble getting it to encrypt and decrypt properly. If I enter "test" as the passphrase and "This data must be kept secret from everyone!" I receive the following exception: System.Security.Cryptography.CryptographicException: Padding is invalid and cannot be removed. at System.Security.Cryptography.RijndaelManagedTransform.DecryptData(Byte[] inputBuffer, Int32 inputOffset, Int32 inputCount, Byte[]& outputBuffer, Int32 outputOffset, PaddingMode paddingMode, Boolean fLast) at System.Security.Cryptography.RijndaelManagedTransform.TransformFinalBlock(Byte[] inputBuffer, Int32 inputOffset, Int32 inputCount) at System.Security.Cryptography.CryptoStream.FlushFinalBlock() at System.Security.Cryptography.CryptoStream.Dispose(Boolean disposing) at System.IO.Stream.Close() at System.IO.Stream.Dispose() ... And if I enter something less than 16 characters I get no output. I believe I need some special handling in the encryption since AES is a block cipher, but I'm not sure exactly what that is, and I wasn't able to find any examples on the web showing how. Here is my code: using System; using System.IO; using System.Security.Cryptography; using System.Text; public static class DatabaseCrypto { public static EncryptedData Encrypt(string password, string data) { return DatabaseCrypto.Transform(true, password, data, null, null) as EncryptedData; } public static string Decrypt(string password, EncryptedData data) { return DatabaseCrypto.Transform(false, password, data.DataString, data.SaltString, data.MACString) as string; } private static object Transform(bool encrypt, string password, string data, string saltString, string macString) { using (AesManaged aes = new AesManaged()) { aes.Mode = CipherMode.CBC; aes.Padding = PaddingMode.PKCS7; int key_len = aes.KeySize / 8; int iv_len = aes.BlockSize / 8; const int salt_size = 8; const int iterations = 8192; byte[] salt = encrypt ? new Rfc2898DeriveBytes(string.Empty, salt_size).Salt : Convert.FromBase64String(saltString); byte[] bc_key = new Rfc2898DeriveBytes("BLK" + password, salt, iterations).GetBytes(key_len); byte[] iv = new Rfc2898DeriveBytes("IV" + password, salt, iterations).GetBytes(iv_len); byte[] mac_key = new Rfc2898DeriveBytes("MAC" + password, salt, iterations).GetBytes(16); aes.Key = bc_key; aes.IV = iv; byte[] rawData = encrypt ? Encoding.UTF8.GetBytes(data) : Convert.FromBase64String(data); using (ICryptoTransform transform = encrypt ? aes.CreateEncryptor() : aes.CreateDecryptor()) using (MemoryStream memoryStream = encrypt ? new MemoryStream() : new MemoryStream(rawData)) using (CryptoStream cryptoStream = new CryptoStream(memoryStream, transform, encrypt ? CryptoStreamMode.Write : CryptoStreamMode.Read)) { if (encrypt) { cryptoStream.Write(rawData, 0, rawData.Length); return new EncryptedData(salt, mac_key, memoryStream.ToArray()); } else { byte[] originalData = new byte[rawData.Length]; int count = cryptoStream.Read(originalData, 0, originalData.Length); return Encoding.UTF8.GetString(originalData, 0, count); } } } } } public class EncryptedData { public EncryptedData() { } public EncryptedData(byte[] salt, byte[] mac, byte[] data) { this.Salt = salt; this.MAC = mac; this.Data = data; } public EncryptedData(string salt, string mac, string data) { this.SaltString = salt; this.MACString = mac; this.DataString = data; } public byte[] Salt { get; set; } public string SaltString { get { return Convert.ToBase64String(this.Salt); } set { this.Salt = Convert.FromBase64String(value); } } public byte[] MAC { get; set; } public string MACString { get { return Convert.ToBase64String(this.MAC); } set { this.MAC = Convert.FromBase64String(value); } } public byte[] Data { get; set; } public string DataString { get { return Convert.ToBase64String(this.Data); } set { this.Data = Convert.FromBase64String(value); } } } static void ReadTest() { Console.WriteLine("Enter password: "); string password = Console.ReadLine(); using (StreamReader reader = new StreamReader("aes.cs.txt")) { EncryptedData enc = new EncryptedData(); enc.SaltString = reader.ReadLine(); enc.MACString = reader.ReadLine(); enc.DataString = reader.ReadLine(); Console.WriteLine("The decrypted data was: " + DatabaseCrypto.Decrypt(password, enc)); } } static void WriteTest() { Console.WriteLine("Enter data: "); string data = Console.ReadLine(); Console.WriteLine("Enter password: "); string password = Console.ReadLine(); EncryptedData enc = DatabaseCrypto.Encrypt(password, data); using (StreamWriter stream = new StreamWriter("aes.cs.txt")) { stream.WriteLine(enc.SaltString); stream.WriteLine(enc.MACString); stream.WriteLine(enc.DataString); Console.WriteLine("The encrypted data was: " + enc.DataString); } }

    Read the article

  • How to use the md5 hash?

    - by Ken
    Okay, so I'm learning php, html, and mysql to learn website development (for fun). One thing I still don't get is how to use md5 of sha1 hashes. I know how to hash the plain text, but say I want to make a login page. Since the password is hashed and can't be reversed, how would mysql know that the user-inserted password matches the hashed password in the database? Here is what I mean: $password = md5($_POST['password']); $query = ("INSERT INTO `users`.`data` (`password`) VALUES ('$password')"); I know that this snippet of script hashes the password, but how would I use this piece of code and make a login page? Any working examples would be great.

    Read the article

  • i am facing some problem while passing parameter to crystal report? it is asking for the password of

    - by Gaurav Sharma
    protected void Page_Load(object sender, EventArgs e) { ConnectionInfo myConnectionInfo = new ConnectionInfo(); myConnectionInfo.UserID = "sa"; myConnectionInfo.Password = "********"; setDBLOGONforREPORT(myConnectionInfo); //When i don't write this code it does not ask for the passowrd //but doesn't take Parameter as value int recpt_no = Convert.ToInt32(Request.QueryString["recpt_no"]); ReportDocument report1 = new ReportDocument(); //report1.SetDatabaseLogon("sa", "********"); report1.Load(Server.MapPath("purchase.rpt")); report1.FileName = Server.MapPath("purchase.rpt"); report1.SetParameterValue("recpt_no", recpt_no); CrystalReportViewer1.ReportSource = report1; } private void setDBLOGONforREPORT(ConnectionInfo myconnectioninfo) { TableLogOnInfos mytableloginfos = new TableLogOnInfos(); mytableloginfos = CrystalReportViewer1.LogOnInfo; foreach (TableLogOnInfo myTableLogOnInfo in mytableloginfos) { myTableLogOnInfo.ConnectionInfo = myconnectioninfo; } } kindly Help me as soon as possible respt_no is passed as querysting Gaurav Sharma

    Read the article

  • python-pam & pam_time module -- possible to check a user without password?

    - by medigeek
    I've looked at the example script of python-pam and linux pam pages, but it's a bit confusing, at least for a beginner in PAM (that I am): http://www.kernel.org/pub/linux/libs/pam/Linux-PAM-html/Linux-PAM_ADG.html http://packages.ubuntu.com/python-pam Is it possible to check if a user has or does not have access to login, without entering password? I would like to create a script that root can use to check if a user is allowed or not to login to the system. If so, can someone post an example that checks if the user is allowed against pam_time? Thanks in advance!

    Read the article

  • How do I fix JavaHL (JNI) Not available after I have changed the logon password on my Mac?

    - by INeedHelp
    I have installed Eclipse 3.5.2 and the plugin Subversion JavaHL Native Library Adapter 1.6.9.2 and this worked without any problems. However, this morning I was forced to change the password to logon to my Mac and since then I get the message that "Subversion native library not available" when I try to save any changes. Can anyone help? I have tried to add this line (-Djava.library.path=/usr/lib/jni) to the eclipse.ini file but this didn´t seem to make any difference. Can anyone help?

    Read the article

  • mercurial: less duplication in hgrc file

    - by zaharpopov
    Hi there. I have using Hg for some projects on my google code hosting. For each projects I set in [auth] section of .hgrc the username/password to push without every asking for password. But it is lots of duplication like: [auth] proj1.prefix = ... 111 proj1.username = google code username proj1.password = google code password proj2.prefix = ... 222 proj2.username = google code username proj2.password = google code password Can this somehow be doing with less duplications? Maybe set variable in hgrc and refer to it from all username/password lines? Thanks in advance for your help

    Read the article

  • Why Shouldn't I Programmatically Submit Username/Password to Facebook/Twitter/Amazon/etc?

    - by viatropos
    I wish there was a central, fully customizable, open source, universal login system that allowed you to login and manage all of your online accounts (maybe there is?)... I just found RPXNow today after starting to build a Sinatra app to login to Google, Facebook, Twitter, Amazon, OpenID, and EventBrite, and it looks like it might save some time. But I keep wondering, not being an authentication guru, why couldn't I just have a sleek login page saying "Enter username and password, and check your login service", and then in the background either scrape the login page from say EventBrite and programmatically submit the form with Mechanize, or use an API if there was one? It would be so much cleaner and such a better user experience if they didn't have to go through popups and redirects and they could use any previously existing accounts. My question is: What are the reasons why I shouldn't do something like that? I don't know much about the serious details of cookies/sessions/security, so if you could be descriptive or point me to some helpful links that would be awesome. Thanks!

    Read the article

  • How to version control config files pragmatically?

    - by erenon
    Suppose we have a config file with sensitive passwords. I'd like to version control the whole project, including the config file as well, but I don't want to share my passwords. That could be good, if this config file: password=secret foo=bar becomes password=* foo=bar and the other users of the vcs could also set up the password on they own. To ignoring the file isn't a good approach, the developers should be aware, if the config file changes. Example: Local version: password=own_secret foo=bar config file in vcs: password=* foo=bar Then suddenly, the config file changes: password=* foo=bar baz=foo And the local version would become for each developer: password=own_secret foo=bar baz=foo This is my solution. How could I achieve this behaviour? How do you store your config files? Is there a way to do that, or should I hack something?

    Read the article

  • What is the sense of permiting the user to use no passwords longer than xx chars?

    - by reox
    Its more like a usability question or maybe database, or even maybe security (consider injection attacks) but what is the sense of permiting the user's password to a be not longer than xx chars? It does not make any sense to me, because longer passwords are mostly considered better and even harder to crack, and some users use password safes, so the password length should not matter. I understand that passwords with more than 20 chars are hardly to remember, but if you use diceware or password safe you dont have any problem with that. I really cant understand why there are sites that say "your password need to be between 5 and 8 chars"... also should the password saved as hash, so the length of the field in the database is fixed, so where is the problem? i think that most of the sites where the password is has to be a fixed length are not even using any hashing method...

    Read the article

  • How to validate the following

    - by user281180
    I have the following code <% using(Ajax.BeginForm("UpdatePassword", new AjaxOptions{UpdateTargetId="Password"})) { %> <div id="Password"> <table> <tr> <td>New password</td><td><%=Html.Password("newPassword") %></td> </tr> <tr> <td>Confirm new password</td> <td><%=Html.Password("confirmPassword")%><%= Html.ValidationMessage("confirmPassword") %> </td> </tr> </table> <% } % Can someone help me how to proceed to validating that the confirmPassword is equal the new password, and if not the message is displayed in the html.validationMessage()...

    Read the article

< Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >