Search Results

Search found 18563 results on 743 pages for 'url'.

Page 79/743 | < Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >

  • Login with Google OAuth api and return url with variable

    - by user2833721
    I am using the Google API for login in my site and I appending my variable with URL and I want that variable in the return URL of OAuth API because of update purpose can I return back that variable For example: <a href="<?php echo($authUrl); ?>&kicker"> I append the kicker in $authUrl and when I return back from Oauth api print $me['displayName']; print $user['email']; print $me['gender']; print $me['id']; with this output I also want my variable "kicker" how can I get it

    Read the article

  • Django template CSS/IMG is "off" in the URL

    - by erimar77
    I have /path/to/my/theme/static/css/frontend.css which is called by base.html <link rel="stylesheet" type="text/css" href="{{ STATIC_URL }}css/frontend.css" media="all" /> In which I've got a background for the header: #header-wrapper min-width: 960px; height: 150px; background: transparent url(img/header-bg.png) repeat-x center bottom; } The file is /path/to/my/theme/static/img I've run manage.py collectstatic to gather the files and almost everything looks correct except the link generated looks like: http://example.com/static/css/img/header-bg.png In which the image does not show, because the correct URL is: http://example.com/static/img/header-bg.png Where am I going wrong??

    Read the article

  • Having trouble getting GET variables from url.

    - by mchl
    Hey everyone, I'm having trouble with this algorithm to extract the get variables from a url and print them each on a new line like: x=y z=hello etc. but instead it prints a seemingly random section of the url with no newlines to the file. There must be a logic error of some kind but i just can't spot it. for(i_m=0;i_m<len_m;i_m++) { if(var_m[i_m]=='&') { fwrite(var_m+offset_m, 1, amp_m, echo_out); fputc('\n',echo_out); offset_m+=amp_m; amp_m=0; } amp_m++; } any help appreciated.

    Read the article

  • can I change my open ID URL change?

    - by dhruvbird
    I wanted to know if I can change my open ID url from say: www.abc.com/username to www.pqr.com/username while the relying party still thinks I am the same user? or even say: www.abc.com/something/username to www.abc.com/somethingelse/username I intuitively think that this is not possible since if it were, then it is possible for anyone to spoof anyone else's identity. Also, does Open ID specify which fields the relying party should use to ensure secure determination of the user's identity? For example, I would expect it to club the URL provided with the username/email address sent back by the Open ID server.

    Read the article

  • Finding all the URL requests from a firefox extension

    - by user303052
    I am building a firefox extension. In this extension, I want to see the URLs of any new webpage that the user visits. The webpage can be in a different tab or window than the current tab that the user is viewing (this should also catch the URL of pop-ups). Is there a way to find when firefox makes a GET or POST request and grab the URL? An alternative that I am trying to avoid is going through all the tabs and manually check to see if they have loaded a new page. Thanks

    Read the article

  • [Javascript] Retrieve a URL of a frame

    - by Ricky
    Hi, guys: If I get a link <a href="/Users/ChangePassword.aspx" target="mainFrame"> in fraTopMenu, what (1) javascript can I add to get the current mainFrame's URL upon clicking the link and (2) append the URL to the querystrings? <frameset rows="60,*" cols="*" frameborder="no" border="0" framespacing="0"> <frame src="/Common/Manager/TopMenu.aspx" name="fraTopMenu" scrolling="no" noresize="noresize" id="fraTopMenu" title="" /> <frameset rows="*" cols="185,*" framespacing="0" frameborder="no" border="0"> <frame src="..." name="leftFrame" id="leftFrame" title="" /> <frame src="..." name="mainFrame" id="mainFrame" title="" /> </frameset> </frameset> Thank you.

    Read the article

  • Javascript - use to load xml data from URL

    - by spenf
    I have this url with some xml data in it: http://64.182.231.116/~spencerf/union_college/Upperclass_Sample_Menu.xml And I would like to load this xml data into my javascript script so I can parse it. I am using parse.com Javascript SDK, in there cloud code. Here is the code I have tried: Parse.Cloud.define("next", function(request, response) { response.success("Hello world!"); $.ajax({ url: 'http://64.182.231.116/~spencerf/union_college/Upperclass_Sample_Menu.xml', // name of file you want to parse dataType: "xml", // type of file you are trying to read success: parse, // name of the function to call upon success error: function(){alert("Error: Something went wrong");} }); }); But when I run this I get an error: $ is not defined at main.js:

    Read the article

  • CSS and JQuery: spaces inside image name break code of url()

    - by Shyam
    Hi, I have a page that is supposed to display a larger version of an image when hovered over a thumbnail. I have a 'div' with an ID and the JQuery code is as following: $(document).ready(function(){ $('img').hover(function() { var src = $("#im" + this.id).attr("src"); $('#viewlarge').css('backgroundImage','url(' + src +')'); return false; }); }); The images I use, are generated by a Ruby script that "generate" an image with a similar, yet different id. However, sometimes, photo's are uploaded that have "spaces" inside. My developer tools tell me that the background-image is not set correctly, yet the image path is correct and the browser don't have problems finding the image. My question is, can I somehow sanitize the url 'src', so spaces won't be a problem? I am aware of doing this server side, yet I would like to know how to do this with JQuery/JS too. Thanks!

    Read the article

  • Change URL of a saved HTML file

    - by Paul Camilleri
    I am new to HTML so this question might sound a bit lame. Anyways I have a saved webpage on my desktop that when i open it in google chrome i want it to show a specific URL instead of its current location. Any ideas how i might get this to work? I tried using the history.pushState but i have no idea why it is not working. I created a simple page for now to test it: <html> <head> <script> function setURL() { history.pushState("Test","page2", "www.test.com"); } </script> </head> <body> <button type="button" onclick="setURL()">Set Url</button> </body> </html> Any help would be greatly appreciated. Thank you

    Read the article

  • how to load image from server (url) to uitableview in Xcode

    - by Divya
    I need to load image from server(url) to UITableView. So i tired below code, but no use. UIImageView *img=[[UIImageView alloc]init]; img.frame=fr; img.image=[UIImage imageWithData:[NSData dataWithContentsOfURL:[NSURL URLWithString:countimg]]]; [cell.contentView addSubview:img]; Here countimg is NSMutableArray. countimg contains url of all images to load. But its not working, because its not a string variable. I don't know how to change NSMutuableArray to String. Anyone help me.

    Read the article

  • A HREF URL won't work

    - by user3586248
    I am trying to get the following link to work. <a href='#' onclick='window.open(" | &ESPP_Info_URL | ");return false;'>Employee Stock Purchase Plan Information</a> Basically the &ESPP_Info_URL variable takes in a url so that the code below looks like... <a onclick="window.open(https://...);return false;" href="#">Employee Stock Purchase Plan Information</a> But when I click the url it just refreshes the page. Does anyone know how to get this to access the link within the window.open function?

    Read the article

  • Nesting if else statements in PHP to validate a URL

    - by John
    I'm currently writing up a function in order to validate a URL by exploding it into different parts and matching those parts with strings I've defined. This is the function I'm using so far: function validTnet($tnet_url) { $tnet_2 = "defined2"; $tnet_3 = "defined3"; $tnet_5 = "defined5"; $tnet_7 = ""; if($exp_url[2] == $tnet_2) { #show true, proceed to next validation if($exp_url[3] == $tnet_3) { #true, and next if($exp_url[5] == $tnet_5) { #true, and last if($exp_url[7] == $tnet_7) { #true, valid } } } } else { echo "failed on tnet_2"; } } For some reason I'm unable to think of the way to code (or search for the proper term) of how to break out of the if statements that are nested. What I would like to do check each part of the URL, starting with $tnet_2, and if it fails one of the checks ($tnet_2, $tnet_3, $tnet_5 or $tnet_7), output that it fails, and break out of the if statement. Is there an easy way to accomplish this using some of the code I have already?

    Read the article

  • Different canonical URLs for Facebook and Google?

    - by Victor P
    The following URLs point to the same resource: http://www.domain.com/books/123 http://www.domain.com/books/123-Harry-Potter http://www.domain.com/books/123-Harry-Potter-And-The-Deathly-Hallows I would like to use (1) as the canonical URL for OpenGraph/Facebook, so if you "like" (2) and (3) then will count for (1). But I would like to use (3) as the canonical URL for Google, because of SEO. Is this recommended?

    Read the article

  • How to make CodeIgniter accept "query string" URLs?

    - by Peter
    According to CI's docs, CodeIgniter uses a segment-based approach, for example: example.com/my/group If I want to find a specific group (id=5), I can visit example.com/my/group/5 And in the controller, define function group($id='') { ... } Now I want to use the traditional approach, which CI calls "query string" URL. Example: example.com/my/group?id=5 If I go to this URL directly, I get a 404 page not found. So how can I enable this?

    Read the article

  • Rewrite query string "?x=y" style to "/x/y" style

    - by Ross
    I have a PHP MVC framework I've built from scratch which uses the traditional domain.com/controller/action URL routing. While I'm currently handling the below conversion in the router I'd like to replace them in the URL for cosmetic reasons. For example: controller/action?filter=bank Becomes: controller/action/filter/bank I've done a bit of experimentation with a regex but can't seem to find a match. I'm also not sure how to rewrite it using RewriteCond. Thanks in advance.

    Read the article

  • magento - webserver question

    - by WANNABE
    I've uploaded the Magento installation file to my hosting and I've been told to go to the URL you uploaded it to using you browser, then the installation wizard will run you through the processes. I uploaded to /home/domain/public_html/magneto What URL should I use to access it? Thanks in advance

    Read the article

  • Change post permalink structure on WordPress to use custom taxonomy

    - by TiuTalk
    Hi there! I want to change the post permalink schema on my WordPress 3.0-beta1 to use my new custom taxonomy. Today I can use /%category%/%postname%/ and the /my-category/my-post/ URL, that's nice but I need to use another taxonomy instead "category" one. I tried to use /%acervo%/%postname%/ but my URLs came with %acervo% on the URL instead the name of the "Acevo" (my taxonomy name) wich the post belongs to. I found something related to WP_Rewrite but without sucess...

    Read the article

  • How can I use wildcard urls with Code Igniter?

    - by tarnfeld
    I am building a system that has urls like app.com/login and app.com/dothing but it will also have app.com/xOldP. The web application is build using the latest version of Code Igniter and I was wondering if there was a way to add a check in, that if the url is a controller then do that and finish, but if not, do something else (which will check the url and if its not real 404, which I can do). I was wondering how annoying this would be :/ Some sample code or links would be great!

    Read the article

  • Rails / omitted from link_to?

    - by dannymcc
    Hi Everyone, I am using a Gem to communicate with FreeagentCentral via their API. I have the following code to display a link to the relevant freeagent project: <%= link_to "#{image_tag('/images/icons/Spinning Beach Ball.png')} Freeagent Project", "#{Freeagent::Base.site.to_s + Freeagent::Project.element_path(@kase.freeagent_id).gsub(/\A\//, '').gsub!(/.xml/,'')}" if @kase.freeagent_id %> The problem - There is a / omitted from the URL which makes the url like this: https://XXXXX.freeagentcentral.comprojects/12345 where it should be: https://XXXXX.freeagentcentral.com/projects/12345 This may be simple, but to me - it's driving me crazy! Thanks, Danny

    Read the article

  • iPhone SDK: Check validity of URLs with NSURL not working??

    - by Chris
    hi, I'm trying to check if a given URL is valid and i'm doing it like this: - (BOOL)urlIsValid:(NSString *)address { NSURL *testURL = [NSURL URLWithString:address]; if (testURL == nil) { return NO; } else { return YES; } } Since "URLWithString" is supposed to return "nil" if the URL is malformed I thought this would work but it doesn't for some reason. Could someone please tell me why? Thanks in advance!

    Read the article

< Previous Page | 75 76 77 78 79 80 81 82 83 84 85 86  | Next Page >