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  • Customizing Django Form: Required and InputId?

    - by Mark
    I'm trying to customize how my form is displayed by using a form_snippet as suggested in the docs. Here's what I've come up with so far: {% for field in form %} <tr> <th><label for="{{ field.html_name }}">{{ field.label }}:</label></th> <td> {{ field }} {% if field.help_text %}<br/><small class="help_text">{{ field.help_text }}</small>{% endif %} {{ field.errors }} </td> </tr> {% endfor %} Of course, field.html_name is not what I'm looking for. I need the id of the input field. How can I get that? Also, is there a way I can determine if the field is required, so that I can display an asterisk beside the label?

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  • form not showing for empty records

    - by Chris Hodges
    I have a relatively simple PHP page called editcustomers with 3 columns. The problem I'm having is that the form will show when there is a record in the database and the fields will be populated with that info. When no such records exists, the form is not even shown, eliminating the possibility to insert a record. My page layout is as follows: Column 1 shows a form containing customer information, allowing it to be edited. Column 2 allows ordering of products and showing how many products were ordered Column 3 shows the total paid so far, and the total owing. The code for the page I have at present: <html> <?php $id = $_GET['id']; require_once('connect.php'); $sth = $dbh->query("SELECT * FROM users where id = '$id';"); $sth->setFetchMode(PDO::FETCH_ASSOC); $eth = $dbh->query("SELECT * FROM purchases where id = '$id';"); $eth->setFetchMode(PDO::FETCH_ASSOC); ?> <div id="main"> <div id="left"> <form name="custInfo" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custInfo"/> <?php while($row = $sth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="firstName" size ="30" value=" <?php echo $row["firstName"]?>"/> <p><input type = "text" name ="lastName" size ="30" value="<?php echo $row["lastName"]?>"/> <p><input type = "text" name ="country" size ="30" value="<?php echo $row["country"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="mid"> <form name="custCosts" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custCosts"/> <?php while($row = $eth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="amountOwed" size ="30" value=" <?php echo $row["amountOwed"]?>"/> <p><input type = "text" name ="numAaa" size ="30" value="<?php echo $row["numAaa"]?>"/> <p><input type = "text" name ="numBbb" size ="30" value="<?php echo $row["numBbb"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="right"> <b>Total Balance</b> <p> Money owed: </p> <p> aaa total: </p> <p> bbb total: </p> <p> Total: </p> <input type = "text" name ="pay" size ="20" /></p> <input type="submit" value="Make Payment" /> </div> <?php $dbh =null; ?> </body> </html> And the code for all the database trickery: <?php require_once 'connect.php'; $formType = $_POST['formType']; $id = $_POST['id']; $firstName = $_POST['firstName']; $lastName = $_POST['lastName']; $country = $_POST['country']; $amountOwed = $_POST['amountOwed ']; $numAaa = $_POST['numAaa']; $numBbb = $_POST['numBbb']; if(empty($_POST['id'])) { $sth = $dbh->prepare("INSERT INTO customers (firstName, lastName, country) VALUES ('$firstName', '$lastName', '$country')"); $sth->execute(); } elseif(!empty($_POST['id']) && !isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("UPDATE customers SET firstName = '$firstName', lastName = '$lastName', country = '$country' WHERE id = '$id'"); $sth->execute(); }elseif(!empty($_POST['id']) && isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("INSERT INTO purchases (id, amountOwed, numAaa, numBbb) VALUES ('$id', '$amountOwed', '$numAaa', '$numBbb'"); $sth->execute(); }elseif(!empty($_POST['id']) && $_POST['formType'] == 'guestCosts'){ $sth = $dbh->prepare("UPDATE purchases SET amountOwed= '$amountOwed', numAaa = '$numAaa', numBbb= '$numBbb' WHERE id = '$id'"); $sth->execute(); } $dbh =null; ?> Why does the form not even display if there is no record? An error or something I might understand....but the form is still in the HTML and should still be being output, from what I can see. Why is this not the case?

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  • upload form only works in Firefox when uploading ASCII .stl 3D files

    - by NathanPDX
    uploadform.html and upload_file.php (below) works fine in Firefox but fails in Chrome, IE, and Safari when uploading ASCII .stl 3D files. Error message is "Invalid file" and problem occurs with multiple computers and multiple .stl files. When I modify the code to support other file types like JPG and PDF it allows those file types in all three web browsers. Also, Firefox only allows the .stl upload if I include application/octet-stream in the mime types section. Why doesn't this work outside of Firefox? uploadform.html: <!doctype html> <html> <body> <form action="upload_file.php" method="post" enctype="multipart/form-data"> <label for="file">Filename:</label> <input type="file" name="file" id="file" /> <br /> <input type="submit" name="submit" value="Submit" /> </form> </body> </html> upload_file.php: <!doctype html> <html> <body> <?php $allowedExts = array("stl"); $extension = end(explode(".", $_FILES["file"]["name"])); if ( ( ($_FILES["file"]["type"] == "application/sla") || ($_FILES["file"]["type"] == "application/octet-stream") || ($_FILES["file"]["type"] == "text/plain") || ($_FILES["file"]["type"] == "application/unknown") ) && ($_FILES["file"]["size"] < 2000000) && in_array($extension, $allowedExts) ) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] /1024) . " KB<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "successful upload"; } } } else { echo "Invalid file"; } ?> </body> </html>

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  • How best to make a link submit a form.

    - by nickf
    What's the best way to get a regular anchor (<a href="...">) to submit the form it is embedded in when clicked? <form> <ul> <li> <p> The link could be <span>embedded <a href="" onclick="?">at any level</a></span> in the form, so "this.parentNode.parentNode..." is no good. :( </p> </li> </ul> </form> I know that the easiest way using jQuery would be $('#myLink').click(function() { $(this).parents('form:first').submit(); }); ...but I'm trying to find a way to do this without using a library. Edit: I'm really trying to find a method which doesn't require knowledge of the form (eg: its name, id, etc). This would be similar to how you could put this on an input element: <input onclick="this.form.submit()" />

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  • prevent form from automatically re-submitting on page load

    - by user323774
    I am using jQuery to point a form's target to an iframe on .submit(). This is to upload a file. It works fine, but when the page reloads, and the iframe is appended to the DOM, the iframe automatically resubmits the form, causing the same file to be sent to the server on each page load. If I do not include the iframe in the HTML markup, or do not append it to the DOM, this doesn't happen, but of course, I need the iFrame. So my question is, how can i prevent this? :) Andrew

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  • Instantiate a form, then find it later, without showing it initially

    - by awilson53
    I am having a problem that is strange to me but hopefully is not so strange to someone else. : ) Some background: I am working on a simple IM client that allows the user to broadcast messages to multiple recipients. The goal is to create a chat form for each of the recipients containing the text of the broadcast message, then show that form only if the recipient responds to the broadcast-er. However, when the application receives a response then attempts to locate the form for that particular chat session (using Application.OpenForms) it cannot find it UNLESS I .Show at the time it is created. I would like to avoid having to show this form when it is created because this means that the user will see a flash on the screen. The form doesn't seem to really be created until I show it, but it would seem there has to be a way to do this without showing first. Can anyone assist? I can provide code snippets if needed, I didn't in this post because this feels more like a conceptual misunderstanding on my part than a bug in the code. Thanks in advance!

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  • In CakePHP, how do I create a form to list models withing a date range?

    - by anonymous coward
    I have a very simple model that includes the auto-filled field much like 'created'. (DateTime format). I'd like to use the Form helpers if possible, to validate the date fields and whatnot. I'd like a simple form with a "Begin Date" (YMD, 12 hours), and an "End Date" (same format). There is already a controller action set up as follows: function view_between($start_date = null, $end_date = null) { // ... stuff that works correctly when the URL is manually entered. } Have I defined the controller wrong, or how can I pass these values into that function? The reason I'm stuck is because I tried adding a $form->input('my_datetime_field' ...) twice, but obviously the name/id were the same on the respective elements. I have also tried using $form->dateTime(...) with similar results. I'm not sure how to uniquely identify a Begin and End date selection, when it should interact with a single field. Am I going about this wrong? A kind shove in the right direction should suffice.

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  • Inserting Row in Table inside Form tag autosubmitting in firefox/chrome

    - by user1861489
    I have a form that will have dynamic elements inserted with javascript and am experiencing some strange behavior. When I click the button to add another element to the table in the form, it adds the element but seems to to a form post immediately (without intending to submit the form yet) I have created a simplified example of the page that has the same behavior. the first table element is created on page load and subsequent elements are added when clicking on the button. this form works successfully in IE. does anyone have an idea of how to prevent this behavior? here is the code sample. <!DOCTYPE html> <html> <head> <title>Test Creating Form</title> <meta http-equiv="Content-type" content="text/html;charset=UTF-8"> <style type="text/css"> td{font-family:verdana;} </style> <script type="text/javascript"> var counter = 0; function makeTitle(title){ if(counter){ title += " " + counter; } counter++; var tbl = document.getElementById('tbl'); var tr = tbl.insertRow(-1) var td1 = tr.insertCell(-1); td1.innerHTML = title; } function load1(){ makeTitle('Primary Specimen'); } </script> </head> <body onload="load1();"> <form action="formtest.htm" method="post" name="testForm" id="testForm"> <table id="tbl" border="1"></table> <button onclick="makeTitle('Alternate Specimen')" id="clone" >Add Another Specimen</button> </form> </body> </html>

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  • JavaScript: Text "submit" link?

    - by Tedd
    I have the the following code and want to use a hyper link to submit my form. <form name="form_signup" id="form_signup" method="post" action="/" enctype="multipart/form-data"> ... <input type="submit" value="Go to Step 2" name="completed" /> or <a onclick="javascript:this.form.submit();">Proceed without uploading</a></span> </form> However, my hyperlink submit doesn't work. It just keeps me on the same page. Question: any idea why my link submit text doesn't work?

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  • ecommerce - use server side code for hidden values in an html form

    - by bsarmi
    I'm trying to learn how to implement a donation form on a website using virtual merchant. The html code from their developer manual goes like this: <form action="https://www.myvirtualmerchant.com/VirtualMerchant/process.do" method="POST"> Your Total: $5.00 <br/> <input type="hidden" name="ssl_amount" value="5.00"> <br/> <input type="hidden" name="ssl_merchant_id" value="my_virtualmerchant_ID"> <input type="hidden" name="ssl_pin" value="my_PIN"> <input type="hidden" name="ssl_transaction_type" value="ccsale"> <input type="hidden" name="ssl_show_form" value="false"> Credit Card Number: <input type="text" name="ssl_card_number"> <br/> Expiration Date (MMYY): <input type="text" name="ssl_exp_date" size="4"> <br/> <br/> <input type="submit" value="Continue"> </form> I have that in an html file and it works fine, but they suggest that the merchant data (the input type="hidden" values) should be in a Server Side Code. I was looking at cURL but it'a all very new to me and I spent a couple of hours trying to find some guide or some sample code on how to accomplish that. Any suggestions or help is greatly appreciated. Thanks!

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  • Set hidden form field values with JavaScript but request still empty

    - by tigerstyle
    HI volks, I try to set some hidden form field values with an onclick event. Ok, after I did something like this: document.getElementById('hidden_field').value = 123; I can output the value with the firebug console by entering this: alert(document.getElementById('hidden_field').value); So the values are definitely set. But now when I submit the form, the hidden field values are still empty. Do you have any idea whats going wrong? Thx for your answers.

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  • How do I toggle two images using jQuery and radio buttons?

    - by trench
    This isn't pretty, but I think you'll get what I'm trying to do. <label><input name="jpgSel" type="radio" value="0">jpg 1</label><br /> <label><input name="jpgSel" type="radio" value="1">jpg 2</label><br /> <div id="showjpg"></div> and $(document).ready(function() { $("select").change(function () { if ($("jpgSel:checked").val() == 1) { $('#showjpg').attr({ src: 'one.jpg', alt: 'one dot jpg' }); } else { $('#showjpg').attr({ src: 'two.jpg', alt: 'two dot jpg' }); } });

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  • cakephp - form for belongsTo Model

    - by user1511579
    I createt the following model to link 2 relational tables: class Ficha extends AppModel { //public $useTable = 'ficha_seg'; var $primaryKey = 'id_ficha'; var $name = 'Ficha'; var $belongsTo = array( 'Perigo' => array( 'className' => 'Perigo', 'foreignKey' => false, 'conditions' => 'Perigo.id_fichas = Ficha.id_ficha' ) ); } Now, i have a form that requires data from the class Ficha, and then is redirected to another ctp page where i will input the data for the table "Perigos". However, since i'm still a newbie in cakephp i'm having difficult building that second form to insert the data on the table "Perigos". Here goes the code i built at the moment related to the second form: FichasController.php (the method where is it supposed to save the data on the table "Perigos": public function preencher_ficha(){ if ($this->request->is('ficha')) { $this->Ficha->create(); if ($this->Ficha->Perigo->save($this->request->data)) { $last_id=$this->Ficha->getLastInsertID(); $this->Session->setFlash('Your post has been updated '.$last_id.'.'); //$this->redirect(array('action' => 'preencher_ficha')); } else { $this->Session->setFlash('Unable to qualquer coisa your post.'); } } } The preencher_ficha.ctp file with the form: echo $this->Form->create('Ficha->Perigo', array('action' => 'index')); echo $this->Form->input('class_subst', array('label' => 'Classificação:')); echo $this->Form->input('simbolos_perigo', array('label' => 'Símbolos:')); echo $this->Form->input('frases_r', array('label' => 'Frases:')); echo $this->Form->end('Finalizar Ficha'); Here i guess the create part is wrong, but i think i have errors too in the controller part.

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  • How to manipulate string to delete quotes?

    - by user1751581
    I am trying to manipulate a string so that any quotes (") within <a href> and <\a> get taken out... Sorry if its been asked before but I just can't get it to work! By the way, I am POSTing the data from a form and then manipulating the string. This is basically html but its in the form of a string, and I want to take out quotes on things like images and links... Another thing is, I do not want to escape the quotes because that would break the link... And the whole point is that the html can be used and work fine... But now, something is automatically creating a second set of quotes inside the normal quotes, like this: <a href="\"http://www.example.com/\""></a> Example input would be: <p><a href="http://www.example.com">example</a></p> Heres how it appears when I echo it however: <p><a href=\"http://www.example.com\">example</a></p> Heres how I want it to look: <p><a href="http://www.example.com">example</a></p> So I would actually be trying to get rid of the (/) my bad...

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  • Persisting object changes from child form to parent form based on button press.

    - by Shyran
    I have created a form that is used for both adding and editing a custom object. Which mode the form takes is provided by an enum value passed from the calling code. I also pass in an object of the custom type. All of my controls at data bound to the specific properties of the custom object. When the form is in Add mode, this works great as when the controls are updated with data, the underlying object is as well. However, in Edit mode, I keep two variables of the custom object supplied by the calling code, the original, and a temporary one made through deep copying. The controls are then bound to the temporary copy, this makes it easy to discard the changes if the user clicks the Cancel button. What I want to know is how to persist those changes back to the original object if the user clicks the OK button, since there is now a disconnect because of the deep copying. I am trying to avoid implementing a internal property on the Add/Edit form if I can. Below is an example of my code: public AddEditCustomerDialog(Customer customer, DialogMode mode) { InitializeComponent(); InitializeCustomer(customer, mode); } private void InitializeCustomer(Customer customer, DialogMode mode) { this.customer = customer; if (mode == DialogMode.Edit) { this.Text = "Edit Customer"; this.tempCustomer = ObjectCopyHelper.DeepCopy(this.customer); this.customerListBindingSource.DataSource = this.tempCustomer; this.phoneListBindingSource.DataSource = this.tempCustomer.PhoneList; } else { this.customerListBindingSource.DataSource = this.customer; this.phoneListBindingSource.DataSource = this.customer.PhoneList; } }

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  • Graphical Submit button doesn't 'post' in Firefox or IE

    - by Ken
    I've looked all over the net to try and solve this problem, but I can't find any solutions. So far, I've checked 3 different browsers. It does not work on IE or FireFox, but it works just fine in Safari. Here's the problem. When I click the button to submit my form, it forwards me to the 'post' URL page - INSTEAD of posting the data, and going to the thank you page like the script commands. Here's the code I'm working with: <form name="loginfrm" method="post" action="http://www.myaffiliatepowersite.com/members/quick_signup.php" style="margin:0; padding:0;"> " /

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  • Object synchronization with GUI Controls in C#

    - by Heka
    Hi, Every time when I change some values in form controls, I need to set a property of an object or vice versa. Instead of writing some methods for each control, I want a general solution for GUI elements. I do not use WPF but only C# 3.0. Any suggestions? Thanks.

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  • Changing a Select dropdown with a jquery ui slider

    - by Chris J. Lee
    Trying to set a select dropdown with a slider. You move the jquery ui slider and then it will change the selection of the other two dropdowns. is there a current method in jquery that would set these options? Current dropdown: <select id="alert-options-frequency-opts"> <option value=""></option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> </select>

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  • Hit external url from code-behind

    - by Steven
    I have a form on my site. The user enters their e-mail and selects a location from a dropdown. I then need to post that data to an external site by hitting a url with the user's location and e-mail in the query string. I'm doing this like so: string url = "http://www.site.com/page.aspx?location=" + location.Text + "&email=" + email.Text; HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url); HttpWebResponse response = (HttpWebResponse)request.GetResponse(); My client says that I am not hitting their server, but when going through the debugger, I'm getting a response from their server. I also tried tracking what was happening by using Firebug, and I noticed that there was no POST made to that external site. What am I doing wrong here?

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  • Login screen using user custom control

    - by Mocco
    Hi, I have followed some advices I got here today and would need a bit more help now: I have an user control with login logic. In mainForm I am using this: private void Form1_Load(object sender, EventArgs e) { LoginScreen login = new MainMenu(); login.Parent = this; login.Dock = DockStyle.Fill; login.Show(); } But I guess it is not modal and thus does not stop the original Form application. Sure I would need the main Form to do not continue until the login form is closed (and login sucessfull). Would using an event correct? Let login object to raise an event that login was successfull and let the MainForm handle it - run the app?

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  • hide inputs value when input is hidden

    - by toingbou
    Hello, im using this function to hide some inputs from a form when a value selected in select tag. this is the function: function showEntry(obj,optionValue){ //hide all entry selections onchange document.getElementById("group1").style.display="none"; document.getElementById("group2").style.display="none"; if(obj.value=="group1") { document.getElementById('group1').style.display="inline"; } else if(obj.value=="group2") { document.getElementById('group2').style.display="inline"; } } and this is the form: <select class="textinput" name="function_title" onchange="showEntry(this,this.value);"> <option value=""> </option> <option value="group1" >group1</option> <option value="group2" >group2</option> </select> <span id="group1" style="display:none;"> <input class="textinput" type="text" id="input1" name="input1" value="100"/> <input class="textinput" type="text" id="input2" name="input2" value="50"/> </span> <span id="group2" style="display:none;"> <input class="textinput" type="text" id="input3" name="input3" value="60"/> <input class="textinput" type="text" id="input4" name="input4" value="45"/> </span> All i want is to hide the hidden inputs value when this group of inputs are hidden. Something like that: <input class="textinput" type="text" id="input3" name="input3" value="if(obj.value!="group2") { print(60); }"/> Is that right?

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  • Form wont stay on top. How do I keep my excel form from hiding behind other windows after I browse

    - by ScottK
    I have a vb.net program that opens up an excel workbook and runs a macro ("Report") in that workbook when a button is clicked. //Workbook with macro and form xlWorkbook = xlApp.Workbooks.Open("W:Data\Excel Program.xls") //Macro: xlApp.Run("Report") //Macro opens form from workbook. I browse for my two .csv files //and then click a button to run code that creates my reports. //form closes, show the excel report after its created xlApp.Visible = True After I browse my first file and select it so that its location is displayed in my text box, the excel form then hides behind any open windows. I want this form to stay on top. It is after this code executes that the form will hide behind all other open windows: Private Sub btnBrowseFile1_Click() Dim fileName1 As String fileName1 = Application.GetOpenFilename("CSV file (*.csv), *.csv") If fileName1 <> "False" Then Me.txtFileName1.text = fileName1 End If End Sub EDIT: I still have no luck with this problem. When the excel macro is opened from a vb program I have this hiding issue...but only after browsing for a file. Why does the focus leave the form and go to Windows after browsing a file? Any one have any suggestions?

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