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  • Should I close sockets from both ends?

    - by Roman
    I have the following problem. My client program monitor for availability of server in the local network (using Bonjour, but it does not rally mater). As soon as a server is "noticed" by the client application, the client tries to create a socket: Socket(serverIP,serverPort);. At some point the client can loose the server (Bonjour says that server is not visible in the network anymore). So, the client decide to close the socket, because it is not valid anymore. At some moment the server appears again. So, the client tries to create a new socket associated with this server. But! The server can refuse to create this socket since it (server) has already a socket associated with the client IP and client port. It happens because the socket was closed by the client, not by the server. Can it happen? And if it is the case, how this problem can be solved? Well, I understand that it is unlikely that the client will try to connect to the server from the same port (client port), since client selects its ports randomly. But it still can happen (just by chance). Right?

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  • SQL server 2005 agent not working

    - by flaggers
    Sql server 2005 service pack 2 version: 9.00.3042.00 All maintenance plans fail with the same error. The details of the error are:- Execute Maintenance Plan Execute maintenance plan. test7 (Error) Messages Execution failed. See the maintenance plan and SQL Server Agent job history logs for details. The advanced information section shows the following; Job 'test7.Subplan_1' failed. (SqlManagerUI) Program Location: at Microsoft.SqlServer.Management.SqlManagerUI.MaintenancePlanMenu_Run.PerformActions() At this point the following appear in the windows event log: Event Type: Error Event Source: SQLISPackage Event Category: None Event ID: 12291 Date: 28/05/2009 Time: 16:09:08 User: 'DOMAINNAME\username' Computer: SQLSERVER4 Description: Package "test7" failed. and also this: Event Type: Warning Event Source: SQLSERVERAGENT Event Category: Job Engine Event ID: 208 Date: 28/05/2009 Time: 16:09:10 User: N/A Computer: SQLSERVER4 Description: SQL Server Scheduled Job 'test7.Subplan_1' (0x96AE7493BFF39F4FBBAE034AB6DA1C1F) - Status: Failed - Invoked on: 2009-05-28 16:09:02 - Message: The job failed. The Job was invoked by User 'DOMAINNAME\username'. The last step to run was step 1 (Subplan_1). There are no entries in the SQl Agent log at all.

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  • Design question for windows application, best approach?

    - by Jamie Keeling
    Hello, I am in the process of designing an application that will allow you to find pictures (screen shots) made from certain programs. I will provide the locations of a few of the program in the application itself to get the user started. I was wondering how I should go about adding new locations as the time goes on, my first thought was simply hard coding it into the application but this will mean the user has to reinstall it to make the changes take affect. My second idea was to use an XML file to contain all the locations as well as other data, such as the name of the application. This also means the user can add their own locations if they wish as well as sharing them over the internet. The second option seemed the best approach but then I had to think how would it be managed on the users computer. Ideally I'd like just a single .exe without the reliance on any external files such as the XML but this would bring me back to point one. Would it be best to simply use the ClickOnce deployment to create an entry in the start menu and create a folder containing the .exe and the file names? Thanks for the feedback, I don't want to start implementing the application until the design is nailed.

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  • Multiple HTTP requests using sockets in java

    - by codeomnitrix
    How could i send multiple http requests from my java program using sockets. actually i have tried as: import java.net.*; import java.io.*; class htmlPageFetch{ public static void main(String[] args){ try{ Socket s = new Socket("127.0.0.1", 80); DataInputStream dIn = new DataInputStream(s.getInputStream()); PrintWriter dOut = new PrintWriter(s.getOutputStream(), true); dOut.println("GET /mytesting/justCheck.html HTTP/1.1\r\nHost:localhost\r\n\r\n"); boolean more_data = true; String str; int i = 0; while(more_data){ str = dIn.readLine(); if(str==null){ //Now server has stopped sending data //So now write again the inputs dOut.println("GET /mytesting/justCheck1.html HTTP/1.1\r\nHost:localhost\r\n\r\n"); continue; } System.out.println(str); } }catch(IOException e){ } } } But when I send the request again it was not processed? Thank in advance.

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  • Getting an exception when trying to use extension method with SortedDictionary... why?

    - by Polaris878
    I'm trying to place custom objects into a sorted dictionary... I am then trying to use an extension method (Max()) on this sorted dictionary. However, I'm getting the exception: "At least one object must implement IComparable". I don't understand why I'm getting that, as my custom object obviously implements IComparable. Here is my code: public class MyDate : IComparable<MyDate> { int IComparable<MyDate>.CompareTo(MyDate obj) { if (obj != null) { if (this.Value.Ticks < obj.Value.Ticks) { return 1; } else if (this.Value.Ticks == obj.Value.Ticks) { return 0; } else { return -1; } } } public MyDate(DateTime date) { this.Value = date; } public DateTime Value; } class Program { static void Main(string[] args) { SortedDictionary<MyDate, int> sd = new SortedDictionary<MyDate,int>(); sd.Add(new MyDate(new DateTime(1)), 1); sd.Add(new MyDate(new DateTime(2)), 2); Console.WriteLine(sd.Max().Value); // Throws exception!! } } What on earth am I doing wrong???

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  • What is your personal approach/take on commenting?

    - by Trae
    Duplicate What are your hard rules about commenting? A Developer I work with had some things to say about commenting that were interesting to me (see below). What is your personal approach/take on commenting? "I don't add comments to code unless its a simple heading or there's a platform-bug or a necessary work-around that isn't obvious. Code can change and comments may become misleading. Code should be self-documenting in its use of descriptive names and its logical organization - and its solutions should be the cleanest/simplest way to perform a given task. If a programmer can't tell what a program does by only reading the code, then he's not ready to alter it. Commenting tends to be a crutch for writing something complex or non-obvious - my goal is to always write clean and simple code." "I think there a few camps when it comes to commenting, the enterprisey-type who think they're writing an API and some grand code-library that will be used for generations to come, the craftsman-like programmer that thinks code says what it does clearer than a comment could, and novices that write verbose/unclear code so as to need to leave notes to themselves as to why they did something."

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  • Ajax request (from .NET) give me unexpected results

    - by ironnailpiercethesky
    I wanted to learn a little more about web and .NET so i decided to write a program to download binaries, webpages and does a little ajax. The first download site i tried was too easy. So i went against uploading.com. It seemed good, no captcha, some ajax use required, you cant guess all the data, it was perfect. After 2hours of messing around i got frustrated. For the life of me i could not get the ajax response to give me what i was expecting. I decided to use tamper data clear my cookies, click on the entry for the ajax request. Copy the Referer, cookies and postdata and came up with this code. It does not work! I am shocked that copying those fields did not work. I even tried setting the user agent (not in code linked) and it still did not work. Why isnt this POST on the ajax request not giving me the correct file? I notice the JsHttpRequest=12719132559480-xml changes based on time so if you want to run the code you should grab a new snapshot with tamperdata (or at least update that url). I dont see any extra headers in tamper data so does anyone know why i might not be getting the response expected? I know disabling cookies or javascript will make the link 'expired' automatically. I dont think javascript will matter because i got the data from tamperdata at the moment of request so what gives? What am i forgetting or what data am i not submitting properly?

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  • Counting combinations in c or in python

    - by Dennis
    Hello I looked a bit on this topic here but I found nothing that could help me. I need a program in Python or in C that will give me all possible combinations of a and b that will meet the requirement n=2*a+b, for n from 0 to 10. a, b and n are integers. For example if n=0 both a and b must be 0. For n=1 a must be zero and b must be 1, for n=2 a can be 1 and b=0, or a=0 and b=2, etc. I'm not that good with programming. I made this: #include <stdio.h> int main(void){ int a,b,n; for(n = 0; n <= 10; n++){ for(a = 0; a <= 10; a++){ for(b = 0; b <= 10; b++) if(n == 2*a + b) printf("(%d, %d), ", (a,b)); } printf("\n"); } } But it keeps getting strange results like this: (0, -1079628000), (1, -1079628000), (2, -1079628000), (0, -1079628000), (3, -1079628000), (1, -1079628000), (4, -1079628000), (2, -1079628000), (0, -1079628000), (5, -1079628000), (3, -1079628000), (1, -1079628000), (6, -1079628000), (4, -1079628000), (2, -1079628000), (0, -1079628000), (7, -1079628000), (5, -1079628000), (3, -1079628000), (1, -1079628000), (8, -1079628000), (6, -1079628000), (4, -1079628000), (2, -1079628000), (0, -1079628000), (9, -1079628000), (7, -1079628000), (5, -1079628000), (3, -1079628000), (1, -1079628000), (10, -1079628000), (8, -1079628000), (6, -1079628000), (4, -1079628000), (2, -1079628000), (0, -1079628000), ideone Any idea what is wrong? Also if I could do this for Python it would be even cooler. :D

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  • How do you search a document for a string in c++?

    - by Jeff
    Here's my code so far: #include<iostream> #include<string> #include<fstream> using namespace std; int main() { int count = 0; string fileName; string keyWord; string word; cout << "Please make sure the document is in the same file as the program, thank you!" << endl << "Please input document name: " ; getline(cin, fileName); cout << endl; cout << "Please input the word you'd like to search for: " << endl; cin >> keyWord; cout << endl; ifstream infile(fileName.c_str()); while(infile.is_open()) { getline(cin,word); if(word == keyWord) { cout << word << endl; count++; } if(infile.eof()) { infile.close(); } } cout << count; } I'm not sure how to go to the next word, currently this infinite loops...any recommendation? Also...how do I tell it to print out the line that that word was on? Thanks in advance!

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  • -[UITableViewRowData isEqualToString:]: unrecognized selector sent to instance 0x391dce0

    - by tak
    I have a datatable which shows the list of contacts. when I start the application all the data is loaded correctly.But after selecting a contact, I am sometimes getting this exception :- Program received signal: “EXC_BAD_ACCESS”. and sometimes -[UITableViewRowData isEqualToString:]: unrecognized selector sent to instance 0x391dce0 most probably for this code:- - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; } ExpenseTrackerAppDelegate *appDelegate = (ExpenseTrackerAppDelegate *)[[UIApplication sharedApplication] delegate]; Person *person = (Person *)[appDelegate.expensivePersonsList objectAtIndex:indexPath.row]; NSString *name = (NSString *)[NSMutableString stringWithFormat:@"%@ %@" ,person.lastName , person.firstName]; cell.textLabel.text = name; //cell.detailTextLabel.text = person.lastName; // Configure the cell. return cell; } If I replace these lines of code NSString *name = (NSString *)[NSMutableString stringWithFormat:@"%@ %@" ,person.lastName , person.firstName]; cell.textLabel.text = name; with this code cell.textLabel.text = person.lastName; then everything works fine? I dont know what exactly happens?

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  • base destructor called twice after derived object?

    - by sil3nt
    hey there, why is the base destructor called twice at the end of this program? #include <iostream> using namespace std; class B{ public: B(){ cout << "BC" << endl; x = 0; } virtual ~B(){ cout << "BD" << endl; } void f(){ cout << "BF" << endl; } virtual void g(){ cout << "BG" << endl; } private: int x; }; class D: public B{ public: D(){ cout << "dc" << endl; y = 0; } virtual ~D(){ cout << "dd" << endl; } void f(){ cout << "df" << endl; } virtual void g(){ cout << "dg" << endl; } private: int y; }; int main(){ B b, * bp = &b; D d, * dp = &d; bp->f(); bp->g(); bp = dp; bp->f(); bp->g(); }

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  • How to visually reject user input in a table?

    - by FX
    In the programming of a table-based application module (i.e. the user mostly enters tabular data in an already laid-out table), how would you reject user input for a given cell? The scenario is: the user edits the cell, enters something (text, picture, ...) and you want them to notice when they finish editing (hitting enter, for example) that their entry is not valid for your given "format" (in the wider meaning: it can be that they entered a string instead of a number, that their entry is too long, too short, they include a picture while it's not acceptable, ...). I can see two different things happening: You can rather easily fit their entry into your format, and you do so, but you want them to notice it so they can change if your guess is not good enough (example: they entered "15.47" in a field that needs to be an integer, so your program makes it "15") You cannot guess what to do with their entry, and want to inform them that it's not valid. My question specifically is: what visual display can you offer to inform the user that his input is invalid? Is it preferable to refuse to leave the editing mode, or not? The two things I can imagine are: using colors (red background if invalid, yellow background for my case 1 above) when you reject an input, do something like Apple does for password entry of user accounts: you make the cell "shaking" (i.e. oscillating left and right) for one second, and keep the focus/editing in their so they don't loose what they've typed. Let's hear your suggestions. PS: This question is, at least in my thought process, somehow a continuation and a specialization of my previous question on getting users to read error messages. PPS: Made this community wiki, was that the right thing to do on this kind of question or not?

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  • How can I help fellow students struggling in programming classes?

    - by David Barry
    I'm a computer science student finishing up my second semester of programming classes. I've enjoyed them quite a bit, and learned a lot, but it seems other students are struggling with the concepts and assignments more than I am. When an assignment is due, the inevitable group email comes out the day or two before with people needing some help either with a specific part of the problem, or sometimes people just seem to have a hard time knowing where to start. I'd really like to be able to help out, but I have a hard time thinking of the right way to give them help without giving them the answer. When I'm having trouble understanding a concept, a code snippet can go along way to helping me, but at the same time if it makes a lot of sense, it can be difficult to think of another way to go about it. Plus the Academic Integrity section of each assignment is always looming overhead warning against sharing code with others. I've tried using pseudo code to help give others an idea on program flow, leaving them to figure out how to implement certain aspects of it, but I didn't get too much feedback and don't know how much it actually helped them out, or if it just confused them further. So I'm basically looking to see if anyone has experience with this, or good ways that I can help out other students to nudge them in the right direction or help them think about the problem in the right way.

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  • How big can I make an Android application's canvas in terms of pixels?

    - by user279112
    I've determined an estimate of the size of my Android emulator's screen in pixels, although I think its resolution can be changed to other numbers. Quite frankly though that doesn't eliminate the general problem of not knowing how many pixels on each axis I have to work with on my Android applications in general. The main problem I'm trying to solve is this: How do I make sure I don't use a faulty resolution on Android applications if I want to keep things' sizes constant (so that if the application screen shrinks, for instances, objects will still show up just as big - there just won't be as many of them being shown) if I wish to do this with a single universal resolution for each program? Failing that, how do I make sure everything's alright if I try to do everything the same way with maybe a few different pre-set resolutions? Mainly it seems like a relevant question that must be answered before I can come across a complete answer for the general problem is how big can I always make my application in pixels, NOT regarding if and when a user resizes the application's screen to something smaller than the maximum size permitted by the phone and its operating system. I really want to try to keep this simple. If I were doing this for a modern desktop, for instance, I know that if I design the application with a 800x600 canvas, the user can still shrink the application to the point they're not doing themselves any favors, but at least I can basically count on it working right and not being too big for the monitor or something. Is there such a magic resolution for Android, assuming that I'm designing for API levels 3+ (Android 1.5+)? Thanks

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  • ExecutorSerrvice memory leak on exception

    - by TofuBeer
    I am having a hard time tracking this down since the profiler keeps crashing (hotspot error). Before I go too deep into figuring it out I'd like to know if I really have a problem or not :-) I have a few thread pools created via: Executors.newFixedThreadPool(10); The threads connect to different web sites and, on occasion, I get connection refused and wind up throwing an exception. When I later on call Future.get() to get the result it will then catch the ExecutionException that wraps the exception that was thrown when the connection could not be made. The program uses a fairly constant amount of memory up until the point in time that the exceptions get thrown (they tend to happen in batches when a particular site is overloaded). After that point the memory again remains constant but at a higher level. So my question is along the lines of is the memory behaviour (reported by "top" on Unix) expected because the exceptions just triggered something or do I probably have an actual leak that I'll need to track down? Additionally when Future.get() throws an exception is there anything else I need to do besides catch the exception (such as call Future.cancel() on it)?

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  • Get more error information from unhandled error

    - by Andrew Simpson
    I am using C# in a desktop application. I am calling a DLL written in C that I do not have the source code for. Whenever I call this DLL I get an untrapped error which I trap in an UnhandledException event/delegate. The error is : object reference not set to an instance of an object But the stack trace is empty. When I Googled this the info back was that the error was being hanlded eleswhere and then rethrown. But this can only be in the DLL I do not have the source code for. So, is there anyway I can get more info about this error? This is my code... in program.cs... AppDomain.CurrentDomain.UnhandledException += new UnhandledExceptionEventHandler(CurrentDomain_UnhandledException); static void CurrentDomain_UnhandledException(object sender, UnhandledExceptionEventArgs e) { try { Exception _ex = (Exception)e.ExceptionObject; //the stact trace property is empty here.. } finally { Application.Exit(); } } My DLL... [DllImport("AutoSearchDevice.dll", EntryPoint = "Start", ExactSpelling = false, CallingConvention = CallingConvention.StdCall)] public static extern int Start(int ASD_HANDLE); An I call it like so: public static void AutoSearchStart() { try { Start(m_pASD); } catch (Exception ex) { } }

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  • What is the Pythonic way to implement a simple FSM?

    - by Vicky
    Yesterday I had to parse a very simple binary data file - the rule is, look for two bytes in a row that are both 0xAA, then the next byte will be a length byte, then skip 9 bytes and output the given amount of data from there. Repeat to the end of the file. My solution did work, and was very quick to put together (even though I am a C programmer at heart, I still think it was quicker for me to write this in Python than it would have been in C) - BUT, it is clearly not at all Pythonic and it reads like a C program (and not a very good one at that!) What would be a better / more Pythonic approach to this? Is a simple FSM like this even still the right choice in Python? My solution: #! /usr/bin/python import sys f = open(sys.argv[1], "rb") state = 0 if f: for byte in f.read(): a = ord(byte) if state == 0: if a == 0xAA: state = 1 elif state == 1: if a == 0xAA: state = 2 else: state = 0 elif state == 2: count = a; skip = 9 state = 3 elif state == 3: skip = skip -1 if skip == 0: state = 4 elif state == 4: print "%02x" %a count = count -1 if count == 0: state = 0 print "\r\n"

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  • What should go in each MVVM triad?

    - by Harry
    OK, let's say I am creating a program that will list users contacts in a ListBox on the left side of the screen. When a user clicks on the contact, a bunch of messages or whatever appears in the main part of the window. Now my question is: how should the MVVM triads look? I have two models: Contact, and Message. The Contact model contains a list of Message models. Each ViewModel object will contain a single corresponding Model, right? And what about the Views? I have a "MainView" that is the main window, that will have things like the menu, toolbar etc. Do I put the ListBox in the MainView? My confusion is with what to put where; for example, what should the ContactView contain? Just a single instance of a contact? So the DataTemplate, ControlTemplate, context menus, styles etc for that single contact, and then just have a ListBox of them in the MainView...? Thanks.

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  • How do I code and compile an Amiga application?

    - by nbolton
    I would like to program an application for the Amiga, just for fun! Please could someone post a step by step howto based on the following? Exactly what programming tools I should use, are there any already installed? Am I limited to plain text editors, or are there IDEs and debugging tools available? If no tools are already installed, how can this done? Are there free ones? I'd like to learn a traditional Amiga language, could you reccomend one? What should I use to compile the language you suggest? Please could you suggest tools I may use to debug the suggested language? Are there any libraries I should be aware of, such as GUI libraries? Some things to note... I'm running Workbench 3.1 from within the WinUAE emulator. From Workbench, I can access files from my Windows hard drive. I'd like to code and compile it from Workbench if possible. I'm running WinUAE in A1200 mode, not sure if that matters. There's an application already installed called MEmacs. I know C++ and C# very well, maybe there's a similar Amiga language. I'm aware that you can code with C and C++, but I want to learn a new language. Update: I have answered my own question, but please do contribute more answers as I intend on extending my answer. Thanks to all that have contributed so far, you've been very helpful!

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  • LoadError in Ruby

    - by wilhelmtell
    I'm having issues requiring 'digest/sha1'. ~$ ./configure --prefix=$HOME/usr --program-suffix=19 --enable-shared ~$ make ~$ make install ~$ irb19 irb(main):001:0> require 'digest/sha1' LoadError: dlopen(/Users/matan/usr/lib/ruby19/1.9.1/i386-darwin9.8.0/digest/sha1.bundle, 9): Symbol not found: _rb_Digest_SHA1_Finish Referenced from: /Users/matan/usr/lib/ruby19/1.9.1/i386-darwin9.8.0/digest/sha1.bundle Expected in: flat namespace - /Users/matan/usr/lib/ruby19/1.9.1/i386-darwin9.8.0/digest/sha1.bundle from (irb):1:in `require' from (irb):1 from /Users/matan/usr/bin/irb19:12:in `<main>' irb(main):002:0> I know some standard modules require fine, while others don't. If i'd say require 'yaml' or even require 'digest' then that works fine. I am using OS X 10.5.8, with Ruby 1.9.1-p378. The system-wide install of Ruby 1.8.6 works fine. Just last week I uninstalled Ruby and re-installed it. When I first installed Ruby I installed it in a similar manner, from source prefixed at my local $HOME/usr directory. I tried removing each and every file make install installs, then re-installing, but that didn't help. Do you have an idea what the issue is and how to resolve it?

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  • When an NSWindow object has a delegate that is a NSWindow subclass, who is responsible to act on received events?

    - by spade78
    So I'm building a program that features the use of the IKImageBrowserView component as a subview in an NSWindow. As a side note, I have a controller object called ImageBrowserController which subclasses NSWindow and is set as the delegate of the NSWindow object of my app. I have sent IKImageBrowserView the message setCanControlQuickLookPanel:YES to enable it to automatically use the QuickLook functionality to preview image files when the IKImageBrowserView is a first responder to receive key events. Then it took me a while to figure out how to make the IKImageBrowserView a first responder which I finally got working by overriding acceptsFirstResponder inside my ImageBrowserController. Now I understand that as the delegate to the NSWindow, ImageBrowserController has a place in the responder chain after the event gets triggered on NSWindow. And I understand that as a subview of NSWindow, IKImageBrowserView is in line to be passed events for event handling. What I don't get is where the connection is between the ImageBrowserController being a first responder and the event somehow making it to the IKImageBrowserView. I didn't set NSWindow or IKImageBrowserView as first responders explicitly. So why isn't it necessary for me to implement event handling inside my ImageBrowserController? EDIT: So after reading the accepted answer and going back to my code I tried removing the acceptsFirstResponder override in my ImageBrowserController and the QuickLook functionality still triggered just like the accepted answer said it would. Commenting out the setCanControlQuickLookPanel:YES made the app beep at me when I tried to invoke QuickLook functionality via the spacebar. I'm getting the feeling that my troubles were caused by user error of XCode in hitting the RUN button instead of the BUILD button after making changes to my code (sigh).

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  • Displaying modal view in Objective-C

    - by kpower
    I'm trying to display Modal View in my app. I have subclass of UIViewController that has only the "Done" button (UIButton created with IB and linked with XCode). .h @interface myModalVC : UIViewController { UIButton *bDone; } @property (nonatomic, retain) IBOutlet UIButton *bDone; - (IBAction)bDoneTouchDown:(id)sender; @end .m #import "myModalVC.h" @implementation myModalVC @synthesize bDone; - (void)dealloc { [bDone release]; [super dealloc]; } - (void)viewDidLoad { [super viewDidLoad]; } - (void)viewDidUnload { } - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { return (UIInterfaceOrientationLandscapeLeft == interfaceOrientation || UIInterfaceOrientationLandscapeRight == interfaceOrientation); } - (void)didReceiveMemoryWarning { [super didReceiveMemoryWarning]; } - (IBAction)bDoneTouchDown:(id)sender { [self.parentViewController dismissModalViewControllerAnimated:YES]; } @end I'm trying to display modal view with this code (from my main view): myModalVC *temp = [[[myModalVC alloc] initWithNibName:@"myModalVC" bundle:[NSBundle mainBundle]] autorelease]; [self presentModalViewController:temp animated:YES]; If this code is placed in some method, that responds to button touches - everything is fine. But when I place it to some other method (called during some processes in my app) - modal view is displayed without problems, but when I press (touch) "Done" button, application crashes with "Program received signal: “EXC_BAD_ACCESS”." What am I doing wrong?

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  • Why is calling close() after fopen() not closing?

    - by Richard Morgan
    I ran across the following code in one of our in-house dlls and I am trying to understand the behavior it was showing: long GetFD(long* fd, const char* fileName, const char* mode) { string fileMode; if (strlen(mode) == 0 || tolower(mode[0]) == 'w' || tolower(mode[0]) == 'o') fileMode = string("w"); else if (tolower(mode[0]) == 'a') fileMode = string("a"); else if (tolower(mode[0]) == 'r') fileMode = string("r"); else return -1; FILE* ofp; ofp = fopen(fileName, fileMode.c_str()); if (! ofp) return -1; *fd = (long)_fileno(ofp); if (*fd < 0) return -1; return 0; } long CloseFD(long fd) { close((int)fd); return 0; } After repeated calling of GetFD with the appropriate CloseFD, the whole dll would no longer be able to do any file IO. I wrote a tester program and found that I could GetFD 509 times, but the 510th time would error. Using Process Explorer, the number of Handles did not increase. So it seems that the dll is reaching the limit for the number of open files; setting _setmaxstdio(2048) does increase the amount of times we can call GetFD. Obviously, the close() is working quite right. After a bit of searching, I replaced the fopen() call with: long GetFD(long* fd, const char* fileName, const char* mode) { *fd = (long)open(fileName, 2); if (*fd < 0) return -1; return 0; } Now, repeatedly calling GetFD/CloseFD works. What is going on here?

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  • Using Loops for prompts with If/Else/Esif

    - by Dante
    I started with: puts "Hello there, and what's your favorite number?" favnum = gets.to_i puts "Your favorite number is #{favnum}?" " A better favorite number is #{favnum + 1}!" puts "Now, what's your favorite number greater than 10?" favnumOverTen = gets.to_i if favnumOverTen < 10 puts "Hey! I said GREATER than 10! Try again buddy." else puts "Your favorite number great than 10 is #{favnumOverTen}?" puts "A bigger and better number over 10 is #{favnumOverTen * 10}!" puts "It's literally 10 times better!" end That worked fine, but if the user entered a number less than 10 the program ended. I want the user to be prompted to try again until they enter a number greater than 10. Am I supposed to do that with a loop? Here's what I took a swing at, but clearly it's wrong: puts "Hello there, and what's your favorite number?" favnum = gets.to_i puts "Your favorite number is #{favnum}?" " A better favorite number is #{favnum + 1}!" puts "Now, what's your favorite number greater than 10?" favnumOverTen = gets.to_i if favnumOverTen < 10 loop.do puts "Hey! I said GREATER than 10! Try again buddy." favnumOverTen = gets.to_i until favnumOverTen > 10 else puts "Your favorite number great than 10 is #{favnumOverTen}?" puts "A bigger and better number over 10 is #{favnumOverTen * 10}!" puts "It's literally 10 times better!" end

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  • Python Interactive Interpreter always returns "Invalid syntax" on Windows

    - by user559217
    I've encountered an extremely confusing problem. Whatever I type into the Python interpreter returns "Invalid Syntax". See examples below. I've tried fooling around with the code page of the prompt I run the interpreter from, but it doesn't seem to help at all. Furthermore, I haven't been able to find this particular, weird bug elsewhere online. Any assistance anyone could provide would be lovely. I've already tried reinstalling Python, but I didn't have any luck - the problem is also there in both 3.13 and 2.7. Running: Python version 3.1.3, Windows XP SP3. Getting: C:\Program Files\Python31>.\python Python 3.1.3 (r313:86834, Nov 27 2010, 18:30:53) [MSC v.1500 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> 2+2 File "<stdin>", line 1 2+2 ^ SyntaxError: invalid syntax >>> x = "Oh, fiddlesticks." File "<stdin>", line 1 x = "Oh, fiddlesticks." ^ SyntaxError: invalid syntax

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