Search Results

Search found 27143 results on 1086 pages for 'include path'.

Page 795/1086 | < Previous Page | 791 792 793 794 795 796 797 798 799 800 801 802  | Next Page >

• Beginners PHP / mySQL question

  - by Reg H

  I'm brand new to PHP & MySQL, and one function I'm creating needs to access a large table or database. I've created the database and it's currently in a MySQL table, which I'm accessing with no problem. The table is 11,000 rows in length, with 8 columns (all text less than 8 characters long) - it's static, and will never change. Without getting too particular, my users will hit a button which will trigger scripts to access the data, say 500 times or more. So in general would it be better practice to include all of this data in a big 'switch' or 'if... then' conditional right in my scripts, rather than opening and accessing the database connection hundreds, or maybe even thousands of times? It just seems like that might be a bottleneck waiting to happen. Thanks!

  Read the article

• You have an error in your SQL syntax; check the manual that corresponds to your MySQL

  - by LuisEValencia

  I am trying to run a mysql query to find all occurences of a text. I have a syntax error but dont know where or how to fix it I am using sqlyog to execute this script DECLARE @url VARCHAR(255) SET @url = '1720' SELECT 'select * from ' + RTRIM(tbl.name) + ' where ' + RTRIM(col.name) + ' like %' + RTRIM(@url) + '%' FROM sysobjects tbl INNER JOIN syscolumns col ON tbl.id = col.id AND col.xtype IN (167, 175, 231, 239) -- (n)char and (n)varchar, there may be others to include AND col.length > 30 -- arbitrary min length into which you might store a URL WHERE tbl.type = 'U' -- user defined table 1 queries executed, 0 success, 1 errors, 0 warnings Query: declare @url varchar(255) set @url = '1720' select 'select * from ' + rtrim(tbl.name) + ' where ' + rtrim(col.name) + ' like %' ... Error Code: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'declare @url varchar(255)

  Read the article

• Is LocalDB supported by Visual Studio 2010 in Entity Framework 5?

  - by Mathias Lykkegaard Lorenzen

  Is LocalDB supported by Visual Studio 2010 in Entity Framework 5, on .NET 4.0? Or am I doing it wrong? I'm getting a "The network path can't be found" issue when instantiating my model container with a connection string for LocalDB. Here's the connection string: var connectionString = "metadata=res://*/Model.csdl|res://*/Model.ssdl|res://*/Model.msl;provider=System.Data.SqlClient;provider connection string=\"data source=(localdb)\v11.0;initial catalog=fablelane_com_db;integrated security=SSPI;multipleactiveresultsets=True;App=EntityFramework\""; Edit 1 I'm receiving the following error when connecting, more specifically: A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: Named Pipes Provider, error: 40 - Could not open a connection to SQL Server). Edit 2 I just figured out that changing to Visual Studio 11 beta doesn't work either. Still receiving the same error-message.

  Read the article

• AccessoryDisclosureIndicator and AccessoryCheckmark on the left side

  - by embedded

  Hi I'm adding support for right-to-left languages for the UITableView. now I need to move the AccessoryDisclosureIndicator and AccessoryCheckmark from the right corner to the left. I'm taking the UIImageView path and Now I'm looking for 2 png icons: one for the AccessoryDisclosureIndicator arrow to the left and the second for the AccessoryCheckmark. Does anyone know where I can get those 2 icons? Is it possible when the user clicks on some cell to switch to the other view to the left and not to the right? Thanks

  Read the article

• Throwing out of range exception in C++

  - by Shinka

  This code works; int at(int index) { if(index < 1 || index >= size) throw 0; return x[index]; } Yet this doesn't int at(int index) { if(index < 1 || index >= size) throw std::out_of_range; return x[index]; } I get the error "expected primary expression before ';'". Now... it surprises me because I know std::out_of_range exists and I have #include <stdexcept>

  Read the article

• Win32: Reading WS_VSCROLL style from a combo box (or list box)

  - by Adam Tegen

  I'm iterating through the controls in a dialog and I'm trying to determine if a combobox was created with the WS_VSCROLL style. The style, obtained from GetWindowLong(hwnd, GWL_STYLE), doesn't contain the WS_VSCROLL bit (0x200000), even when I know it was set on create. Clarification: I am looking to see if the ComboBox was created with the WS_VSCROLL style. Calling GetWindowLong() (or using spy++) to get the style of the combo's listbox will include WS_VSCROLL if a scrollbar is needed to based on the current contents of the list. I am trying to determine if the ComboBox was created with WS_VSCROLL, not if a scrollbar is currently visible.

  Read the article

• Hyperlinks in VS2008 Test Result Details

  - by Red XIII

  In case when resulting string in "Test Result Details" (TRD) is very long, the Visual Studio 2008 crashes. I fixed this by sending the result data into a file. There is a problem, however, because there isn't a simple way to open such file. Of course, I can manually open folder and then the file, but it isn't very efficient. Now, to the questions part. Is there a possibility to include in the "Error Message" part of TRD a hyperlink to a file? (something similar to what we can already find in the stack trace part) If not, is there any way to add such functionality (easy opening of a file) to TRD? If not, are there any ways to expand the default reporting of VS? Thanks for any help.

  Read the article

• hide XML element from appearing in browser

  - by ffsb

  HI, I have a website which I am setting up. However, I want the first page (Home) not to have any sub menu. When I change the value of true to false all the other pages where I want the drop down to appear also disappear. I want other pages to have sub menu but not the home page. I have tried to change the xml path etc, but nothing seems to work. Can somebody please advise on this. I am new to xml and finding this very challenging. I have uploaded the config.xml and the layout xml's. I have also placed the index.htm and js script there. http://www.mediafire.com/?sharekey=043102ffea137c3c67cd7f7bd65f7eef3662a86c6a842d54ea4ac78345cbe4ce Also could someone please help me understand from where it is reading the config.xml.

  Read the article

• Expanding a row in a div-based table

  - by magneticMonster

  I have a stack of <div> elements that show a name. I'd like to include a + link off to the side that, when clicked, expands the <div> and adds more detailed information (from a RoR controller). After poking around on the net, I found link_to_remote and related RoR stuff, but I can't seem to get the right combination to work together. Can someone point me to a tutorial or show what the controller and view interaction should look like? Thanks!

  Read the article

• what's wrong with my one-liner strncpy: while(*s++ = *t++ && n-- > 0);?

  - by pvd

  #include <stdio.h> #define STR_BUF 10000 #define STR_MATCH 7 void mystrncpy(char* s, char* t, int n) { while(*s++ = *t++ && n-- > 0); } int main() { int result; char str_s[STR_BUF] = "not so long test string"; char buf_1[STR_BUF]; mystrncpy(buf_1, str_s, STR_MATCH); printf ("buf_1 (mystrncpy, 7 chars): %s\n", buf_1); return 0; } When I run it, nothing happened ian@ubuntu:~/tmp$ gcc myncpy.c -o myn&&./myn buf_1 (mystrncpy, 7chars):

  Read the article

• C++ Declaring an uninitialized variable without a null constructor

  - by xbonez

  Consider the DUPoint class, whose declaration appears below. Assume this code appears in a file named DUPoint.h: #include <string> class DUPoint { public: DUPoint (int x, int y); int getX () const; int getY () const; void setX (int x); void setY (int y); void print(); private: int x_; int y_; }; Is it true that you cannot declare an uninitialized DUPoint variable with a statement such as DUPoint P; using this class as currently configured because it has no null constructor?

  Read the article

• Question about r-value in C++0x

  - by Goofy

  Rvalues IMHO are great improvement in C++, but at the beginning the're seems quite. Please look at code below: #include <string> std::string && foo (void) { std::string message ("Hello!"); return std::move (message); } void bar (const std::string &message2) { if (message == "Bye Bye!") return; } int main () { bar (foo ()); } Reference message2 is last owner of original message object returned by foo(), right?

  Read the article

• Is it possible to apply NOT(!) operator while DataBinding a property of a control ?

  - by Ashish Ashu

  I have Button control and I have to set the IsEanbled property based on the bool variable. bool IsBoolVariable I want if IsBoolVariable property is true then I want to set the IsEnabled property to false AND when IsBoolVariable property is false then I want to set the IsEnabled property to true. Is it possible to apply not(!) operator while defining the binding as given below <Button IsEnabled = "{Binding Path = **!**IsBoolVariable}" /> I can very well do that by applying convertors , but that is the only way to do that?

  Read the article

• How can I filter out the "My Computer"-option in a SWT DirectoryDialog?

  - by Superfisi

  Hello *, in our Eclipse RCP application running on Windows XP we use a DirectoryDialog, in which the user should... ahmm... choose a directory! :D The problem is: If the user selects the "My Computer"-option (in German Windows "Arbeitsplatz") the Dialog returns null. The DirectoryDialog provides a method setFilterPath(String path) in which I put the File.pathSeparatorChar (to remain OS-independant). My suggestion was that if there has to be a file separator in the directory the "My Computer"-option would be ignored cause it is null - for example the "OK"-button would be greyed out or sth. like that... but it is also valid to klick "OK". Any suggestions from your side? :D Thanks in advance! Alex

  Read the article

• Location inheritInChildApplications kill debugger?

  - by chobo2

  Hi I am wondering is this normal when you add this into your web.config <location path="." inheritInChildApplications="false"> </location> The debugger should stop working. Like when I add this to my site and try to run in debug mode it won't activate any of my debug points nor will it lock up Visual studios 2008. I can have it running and still make edits to my C# code. I take the line away and I get the debug mode back and it locks up VS2008.

  Read the article

• The best way to store username and password without a database

  - by Mokuchan

  Hello everyone, I want to build a simple single user login "library" in PHP, but I'm facing the following dilemma: how should I store username and password if I'm not using a database? A simple plain text file could be easily read and then the password could be easily decripted so that's not an option. If I create a php file with just <?php $Username= "username"; $Password= "password"; ?> then no one should be able to read it and I could simply include this file where I need it, but I'm not really sure you can't find a better way to do this! So what's, in your opinion, the best solution to this problem (and why)? Thanks

  Read the article

• Stopping users posting more than once

  - by user342391

  Before posting my form I am checking the database to see if there are any previous posts from the user. If there are previous posts then the script will kick back a message saying you have already posted. The problem is that what I am trying to achieve isn't working it all goes wrong after my else statement. It is also probable that there is an sql injection vulnerability too. Can you help??4 <?php include '../login/dbc.php'; page_protect(); $customerid = $_SESSION['user_id']; $checkid = "SELECT customerid FROM content WHERE customerid = $customerid"; if ($checkid = $customerid) {echo 'You cannot post any more entries, you have already created one';} else $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[customerid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

  Read the article

• Switching from php to python

  - by ts

  Hello I am trying to make a list of things which can be difficult/surprising to someone who is changing language from PHP to Python. so far i have rather short list: forget require / include, learn import (this was most difficult to me - to understand package - module - class - object hierarchy and its mapping to filesystem) you can't just upload file on server to have webpage (-mod_python, wsgi etc) learn the python way for use variable class names (new $class() vs import + getattr) / operator in python 2.x and all float-related horrors those were difficult to me, it takes few days before mind adapts a new paradigm after i found that there is few other areas which could be challenging for someone with (too) many years of php: everything is an object you have to live with exceptions array vs list, set, dictionary, tuple ... learn (effective) list comprehensions learn generators any other ideas / personal experiences ?

  Read the article

• Binding an Element to a Control Property (string)

  - by 108980470541437452574

  so, i've found a way to bind a label to a property on current Control i give it a name: <UserControl x:Class="WpfGridtest.GridControl" x:Name="GridControlControl1"> and than bind to property of this control: <Label Content="{Binding ElementName=GridControlControl1, Path=Filter}"></Label> I can see the default value i put in that property. I am guessing that this isn't working because i am binding to String property which doesn't implement INotifyPropertyChanged?? is there some other type i should be using for this property instead of String auto notify my label of changes, or am i going about this the wrong way?

  Read the article

• Getting input in system() function (Mac)

  - by Alex

  #include <iostream> using namespace std; int main() { short int enterVal; cout << "enter a number to say: " << endl; cin >> enterVal; system("say "%d"") << enterVal; return 0; } Is what I am currently trying. I want the user to enter a number and the system() function says it basically. The code above has an error which says " 'd' was not declared in this scope ". Thanks in advance.

  Read the article

• How can I login linux using C or C++

  - by jnblue

  I need to programmely switch the current user to another,then the followed code should be executed in the environment(such as path,authority..) of another user. I've find the 'chroot()','setuid()' may be associated with my case, but these functions need the root authority, I don't have root authority, but I have the password of the second user. what should I do? I have tried shell "su - " can switch current user, can this command help me in my C++ code? Don't laugh at me if my question is very stupid, I'm a true freshman on linux. :) Thanks!

  Read the article

• How can I get Ruby to treat the index of a string as a character (rather than the ASCII code)?

  - by user336777

  I am checking to see if the last character in a directory path is a '/'. How do you get ruby to treat the specific index of a string as a character rather than the associated ASCII code? For example the following always returns false: dir[dir.length - 1] == '/' This is because dir[dir.length - 1] returns the ASCII code 47 (rather than '/'). Any thoughts on how to interpret 47 as '/'? Or is there a completely different way to handle this in the first place? thanks.

  Read the article

• Strange iterator's behaviour;

  - by A-ha

  #include "stdafx.h" int _tmain(int argc, _TCHAR* argv[]) { string s = "Haven't got an idea why."; auto beg = s.begin(); auto end = s.end(); while (beg < end) { cout << *beg << '\n'; if (*beg == 'a') {//whithout if construct it works perfectly beg = s.erase(beg); } ++beg; } return 0; } Why if I erase one or more chars from this string this code breaks? I suppose it has something to do with returned iterator after erase operation being created at higher address than end iterator but I'm not sure and it surely isn't right behaviour. Or is it?

  Read the article

• No class def find error

  - by John Smith

  I have the following piece of code which helps me to read the paths of all the files in a directory and its subdirectories : File dir = new File("directory path"); try { System.out.println("Getting all files in " + dir.getCanonicalPath() + " including those in subdirectories"); } catch (IOException e1) { // TODO Auto-generated catch block e1.printStackTrace(); } List<File> files = (List<File>) FileUtils.listFiles(dir, TrueFileFilter.INSTANCE, TrueFileFilter.INSTANCE); for (File file : files) { try { System.out.println("file: " + file.getCanonicalPath()); } catch (IOException e1) { // TODO Auto-generated catch block e1.printStackTrace(); } } The problem is that I get a java.lang.NoClassDefFoundError: org/apache/commons/io/filefilter/TrueFileFilter error. I've imported the necessary libraries. I mention that I work on a plugin project. This code runs in a class with main function. I don't understand why it gave me this error. Thank you !

  Read the article

• How do stop form posting to mysql if database contains a specific ID?

  - by user342391

  I have a form that I am using to post data to mysql. Before submitting the form I want to check the database and see if there are any fields in the column 'customerid' that equal 'userid' and if so not to post the form. Basically, I am trying to limit my users from posting more than once. Users will be able to login to my system and make ONE post. They will be able to delete and modify their post but are only limited to one post. How would I do this??? Code so far: <?php include '../login/dbc.php'; page_protect(); $userid = $_SESSION['user_id']; $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[userid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

  Read the article

< Previous Page | 791 792 793 794 795 796 797 798 799 800 801 802  | Next Page >