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  • How should I solve this MySql problem (PHP) ? (Beginner)

    - by Camran
    I have several tables in a MySql database. I have a classifieds website, and at the bottom I display the users last visited classifieds. I do this by storing the ID:s of the ads to an array in the cookie. Now, my db is made up like this kindof: Main Table: // Stores global information, ie these fields have to be filled out in every record, never be blank ID Price category Seller Item Table: // Stores descriptive info about whats for sale ID AD_ID (FK) //This is the same as ID in the MAIN TABLE Color Size Mileage etc My problem is that I need to know what category the ad is in, in order to query mysql for the right information I think. So I need two variables, but the cookie only has one (ID) stored. Offcourse I could make two queries, first one just matching the ID to the main_table and fetch the category from the Main_table. Then make the second query and fetch all other info from the right table. Here is an example if the category was Vehicles: SELECT * FROM main_table, vehicles_table, WHERE main_table.id=$id_from_cookie AND main_table.ad_id=vehicles_table.ad_id As you can see above, I need the category to write in what table to check, right? But I think there must be a smarter way, like fetching them in one single query using only one variable (id from cookie)? How should I do this? Understand? Let me know if you need more input... Thanks

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  • IE showing hidden div under certain circumstances

    - by karola
    After googling around and finding a lot of ie bugs I still did not find a description of the problem I have. The initial situation is a standard one. We have a tooltip which is actually a hidden div that will be displayed on mouseover at a given location. The div is hidden with display:none and contains a table with the content. We tried different libraries for showing the div (scriptaculous and jQuery Cluetip) but the effect is the same. The problem: Everything is fine as long as the contents fits the width of my window. But when I resize it until the horizontal scrollbar is activated the content of the hidden div will be shown at the end of the page when the tooltip is activated. This is really strange as it happens only under these premises. When more than one tooltip is involved the browser might even crash (and under Vista takes the whole system with him duh). I know it's a bit complicated to explain but I hope that someone at least had heard of that bug and can point me into the right direction.

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  • include ::before pseudo class in javascript

    - by user1955837
    Why is this thing not working? If I remove ::before from javascript and css it works. But due to the design needs there has to be a ::before. How do I point to the class + ::before? $(function () { var sections = $("section"); var navigation_links = $("nav a"); sections.waypoint({ handler: function (event, direction) { var active_section; active_section = $(this); if (direction === "up") active_section = active_section.prev(); var active_link = $('nav a[href="#' + active_section.attr("id") + '"]'); navigation_links.removeClass("selected::before"); active_link.addClass("selected::before"); }, offset: '25%' }) }); css: .selected::before { display: block; content: ""; margin-top: 6px; width: 8px; height: 8px; background: url(../img/sprite.png) -126px -196px; background-size: 400px 480px; float: left; margin-left: 20px; margin-right: 20px; }

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  • Proper way to communicate between divs in jquery?

    - by folder
    This is probably a simple question, and i'm just being dense. I've looked through a few jquery books and nothing has jumped out at me, i'm probably missing something. I'm looking for the 'proper', best practices way to communicate between divs/dom items on a page? For example, I have a page with 5 panels that display when a link is chosen, they hide/show/run some code that changes other pieces on the page. Something like this snippet: <ul> <li><div id="unique_name_1_anchor">Unique div 1</div></li> <li><div id="unique_name_2_anchor">Unique div 2</div></li> <li><div id="unique_name_3_anchor">Unique div 3</div></li> <li><div id="unique_name_4_anchor">Unique div 4</div></li> </ul> ...Somewhere else on the page <div id="unique_name_1_panel">Some panel 1 stuff here</div> <div id="unique_name_2_panel">Some panel2 stuff here<div> <div id="unique_name_3_panel">Some panel3 here</div> <div id="unique_name_4_panel">Some panel4 here</div> The concept being when as user clicks on a unique_name_X_anchor div, some action is performed on the corresponding panel (ie show/hide etc...). What I have been doing now is parsing the id ie ($(this).replace("_anchor","_panel") to get the div id of the other dom element. This just seems clunky and there must be a better/more proper way of doing this. Suggestions? Thanks

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  • table in drupal with edit link

    - by user544079
    I have a table created in drupal with the edit link pointing to the input form. But the problem is, it only displays the last row values in the $email and $comment variables. Can anyone suggest how to modify the table display to have the edit link to the corresponding records? function _MYMODULE_sql_to_table($sql) { $html = ""; // execute sql $resource = db_query($sql); // fetch database results in an array $results = array(); while ($row = db_fetch_array($resource)) { $results[] = $row; $email = $row['email']; $comment = $row['comment']; drupal_set_message('Email: '.$email. ' comment: '.$comment); } // ensure results exist if (!count($results)) { $html .= "Sorry, no results could be found."; return $html; } // create an array to contain all table rows $rows = array(); // get a list of column headers $columnNames = array_keys($results[0]); // loop through results and create table rows foreach ($results as $key => $data) { // create row data $row = array( 'edit' => l(t('Edit'),"admin/content/test/$email/$comment/ContactUs", $options=array()),); // loop through column names foreach ($columnNames as $c) { $row[] = array( 'data' => $data[$c], 'class' => strtolower(str_replace(' ', '-', $c)), ); } // add row to rows array $rows[] = $row; } // loop through column names and create headers $header = array(); foreach ($columnNames as $c) { $header[] = array( 'data' = $c, 'class' = strtolower(str_replace(' ', '-', $c)), ); } // generate table html $html .= theme('table', $header, $rows); return $html; } // then you can call it in your code... function _MYMODULE_some_page_callback() { $html = ""; $sql = "select * from {contactus}"; $html .= _MYMODULE_sql_to_table($sql); return $html; }

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  • Query to bring count from comma seperated Value

    - by Mugil
    I have Two Tables One for Storing Products and Other for Storing Orders List. CREATE TABLE ProductsList(ProductId INT NOT NULL PRIMARY KEY, ProductName VARCHAR(50)) INSERT INTO ProductsList(ProductId, ProductName) VALUES(1,'Product A'), (2,'Product B'), (3,'Product C'), (4,'Product D'), (5,'Product E'), (6,'Product F'), (7,'Product G'), (8,'Product H'), (9,'Product I'), (10,'Product J'); CREATE TABLE OrderList(OrderId INT NOT NULL PRIMARY KEY AUTO_INCREMENT, EmailId VARCHAR(50), CSVProductIds VARCHAR(50)) SELECT * FROM OrderList INSERT INTO OrderList(EmailId, CSVProductIds) VALUES('[email protected]', '2,4,1,5,7'), ('[email protected]', '5,7,4'), ('[email protected]', '2'), ('[email protected]', '8,9'), ('[email protected]', '4,5,9'), ('[email protected]', '1,2,3'), ('[email protected]', '9,10'), ('[email protected]', '1,5'); Output ItemName NoOfOrders Product A 4 Product B 3 Product C 1 Product D 3 Product E 4 Product F 0 Product G 2 Product H 1 Product I 2 Product J 1 The Order List Stores the ItemsId as Comma separated value for every customer who places order.Like this i am having more than 40k Records in my dB table Now I am assigned with a task of creating report in which I should display Items and No of People ordered Items as Shown Below I Used Query as below in my PHP to bring the Orders One By One and storing in array. SELECT COUNT(PL.EmailId) FROM OrderList PL WHERE CSVProductIds LIKE '2' OR CSVProductIds LIKE '%,2,%' OR CSVProductIds LIKE '%,2' OR CSVProductIds LIKE '2,%'; 1.Is it possible to get the same out put by using Single Query 2.Does using a like in mysql query slows down the dB when the table has more no of records i.e 40k rows

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  • interface abstract in php real world scenario

    - by jason
    The goal is to learn whether to use abstract or interface or both... I'm designing a program which allows a user to de-duplicate all images but in the process rather then I just build classes I'd like to build a set of libraries that will allow me to re-use the code for other possible future purposes. In doing so I would like to learn interface vs abstract and was hoping someone could give me input into using either. Here is what the current program will do: recursive scan directory for all files determine file type is image type compare md5 checksum against all other files found and only keep the ones which are not duplicates Store total duplicates found at the end and display size taken up Copy files that are not duplicates into folder by date example Year, Month folder with filename is file creation date. While I could just create a bunch of classes I'd like to start learning more on interfaces and abstraction in php. So if I take the scan directory class as the first example I have several methods... ScanForFiles($path) FindMD5Checksum() FindAllImageTypes() getFileList() The scanForFiles could be public to allow anyone to access it and it stores in an object the entire directory list of files found and many details about them. example extension, size, filename, path, etc... The FindMD5Checksum runs against the fileList object created from scanForFiles and adds the md5 if needed. The FindAllImageTypes runs against the fileList object as well and adds if they are image types. The findmd5checksum and findallimagetypes are optionally run methods because the user might not intend to run these all the time or at all. The getFileList returns the fileList object itself. While I have a working copy I've revamped it a few times trying to figure out whether I need to go with an interface or abstract or both. I'd like to know how an expert OO developer would design it and why?

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  • NSTimer won't stop it only resets when invalidated & released

    - by J Fries
    When I press my stop button to stop the timer it just resets to the original time and begins counting down again. I have looked everywhere and all I have found is "invalidate" and it isn't working. I want the time to stop when I hit stop and the label to display the original time. I also turned off automatic counting so I could try releasing and it is giving me an error: 0x10e20a5: movl 16(%edx), %edx EXC_BAD_ACCESS (code=2, address=0x10) `NSTimer *rockettTimer; int rocketCount; @interface FirstViewController () @property (strong, nonatomic) IBOutlet UILabel *rocketTimer; - (IBAction)stopButton:(id)sender; - (IBAction)startButton:(id)sender; @end @implementation FirstViewController @synthesize rocketTimer; -(void) rocketTimerRun{ rocketCount = rocketCount - 1; int minuts = rocketCount / 60; int seconds = rocketCount - (minuts * 60); NSString *timerOutput = [NSString stringWithFormat:@"%d:%.2d", minuts, seconds]; rocketTimer.text = timerOutput; } - (IBAction)startButton:(id)sender { rocketCount = 180; rockettTimer = [NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(rocketTimerRun) userInfo:nil repeats:YES]; - (IBAction)stopButton:(id)sender { [rockettTimer invalidate]; //[rockettTimer release]; } - (void)viewDidLoad { [super viewDidLoad]; // Do any additional setup after loading the view, typically from a nib. } - (void)viewDidUnload { [self setRocketTimer:nil]; [super viewDidUnload]; // Release any retained subviews of the main view. } - (BOOL)shouldAutorotateToInterfaceOrientation: (UIInterfaceOrientation)interfaceOrientation { if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) { return (interfaceOrientation != UIInterfaceOrientationPortraitUpsideDown); } else { return YES; } } @end`

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  • JavaScript Fails to load content correctly on start

    - by Gaz_Edge
    I have inherited an image gallery constructed using javascript. I believe it uses a variation of JQuery, but it seems to have been heavily edited. The gallery loads the first image on page load. Each image has comments below them. There are forward and backward arrows that move between images. The problem I seem to have is that if there is a comment on image one, it is not loaded on page start, the only way to get it to display is to click forward to the next image, then click back to image one. The comment is then shown. All the comments are loaded into a script in the header under var sent_comments = [{COMMENTS}] The comment HTML code on loading is as follows; <div id="comments_container"> <div id="comments"> </div> </div> Once I have clicked to image two and then back to image one, the code is; <div id="comments_container"> <div id="comments"> SOME COMMENT </div> </div> Previous image button is: <a class="prev save_state" href="#"> <img src="/next.png?" alt="Next"> </a> Im new to javascript so not really sure what I will need to do to ensure the comment is loaded for the first image when the page loads. Code here: http://static.albumexposure.net/assets/presentation-9f47b054d96f9ec2459e89619a5fe9b4.js http://static.albumexposure.net/assets/presentations/book-699d82a2beb39df264e54c5d2578e0e4.js

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  • PHP: Trying to come up with a "prev" and "next" link

    - by fwaokda
    I'm displaying 10 records per page. The variables I have currently that I'm working with are.. $total = total number of records $page = whats the current page I'm displaying I placed this at the top of my page... if ( $_GET['page'] == '' ) { $page = 1; } //if no page is specified set it to `1` else { $page = ($_GET['page']); } // if page is specified set it Here are my two links... if ( $page != 1 ) { echo '<div style="float:left" ><a href="index.php?page='. ( $page - 1 ) .'" rev="prev" >Prev</a></div>'; } if ( !( ( $total / ( 10 * $page ) ) < $page ) ) { echo '<div style="float:right" ><a href="index.php?page='. ( $page + 1 ) .'" rev="next" >Next</a></div>'; } Now I guess (unless I'm not thinking of something) that I can display the "Prev" link every time except when the page is '1'. How can make it where the "Next" link doesn't show on the last page though?

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  • Car Class (first time with classes)

    - by user2967605
    For an assignment I needed to use a class named car and have it display the make and model, and also have the speed increase by 5 when you use accelerate and decrease by 5 when you brake. My teacher helped me along the way but when I got to the end I couldn't get it to run. Could someone correct me and tell my why it's wrong? Imp--------- #include <iostream> #include <string> using namespace std; void accelerate() { int speed; speed = speed + 5; } void brake() { int speed; speed = speed - 5; } Header #include <iostream> #include <string> using namespace std; class car { public: car(int getYear, string getMake); void accelerate(); void brake(); private: int year; string make; int speed; }; CarClass.cpp #include <string> #include "CarClass.h" using namespace std; int main() { car.(2013,"Kia") car.accelerate() car.brake() }

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  • NoInitialContextException: in ejb 3

    - by JavaDeveloper
    My client class code Hashtable hs = new Hashtable(); hs.put(Context.INITIAL_CONTEXT_FACTORY, "org.jnp.interfaces.NamingContextFactory"); hs.put(Context.PROVIDER_URL, "jnp://10.20.52.41:1200"); hs.put(Context.URL_PKG_PREFIXES, "org.jboss.naming:org.jnp.interfaces"); Context context = new InitialContext(hs); System.out.println("-----"); try { Example helloWorld = (Example) context .lookup("Example"); helloWorld.display("HelloWorld"); } catch (NamingException e) { System.out.println("naming exception occoured"); e.printStackTrace(); } My session bean code public class Example implements javax.ejb.SessionBean { //method here.. } getting following exception. how to resolve? Exception in thread "main" javax.naming.NoInitialContextException: Cannot instantiate class: org.jnp.interfaces.NamingContextFactory [Root exception is java.lang.ClassNotFoundException: org.jnp.interfaces.NamingContextFactory] at javax.naming.spi.NamingManager.getInitialContext(NamingManager.java:657) at javax.naming.InitialContext.getDefaultInitCtx(InitialContext.java:288) at javax.naming.InitialContext.init(InitialContext.java:223) at javax.naming.InitialContext.(InitialContext.java:197) at comtest.client.Example.main(Test.java:22) Caused by: java.lang.ClassNotFoundException: org.jnp.interfaces.NamingContextFactory at java.net.URLClassLoader$1.run(URLClassLoader.java:202) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:190) at java.lang.ClassLoader.loadClass(ClassLoader.java:306) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) at java.lang.ClassLoader.loadClass(ClassLoader.java:247) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:249) at com.sun.naming.internal.VersionHelper12.loadClass(VersionHelper12.java:46) at javax.naming.spi.NamingManager.getInitialContext(NamingManager.java:654) ... 4 more

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  • UIImageView not displaying image when property is set too early

    - by Undeadlegion
    I have an image I want to display inside a UIView. In Interface Builder, the UIView is the root and a UIImageView is its child. The view is connected to view controller's view outlet, and the image view is connected to the image view outlet: @property (nonatomic, retain) IBOutlet UIImageView *imageView; If I try to set the image property of UIImageView before it's visible, the image doesn't show up. TestView *testView = [[TestView alloc] initWithNibName:@"TestView" bundle:nil]; testview.imageView.image = [logos objectAtIndex:indexPath.row]; [self.navigationController pushViewController:testView animated:YES]; If, however, I pass the image to the controller and set the image property in view did load, the image becomes visible. TestView *testView = [[TestView alloc] initWithNibName:@"TestView" bundle:nil]; testview.image = [logos objectAtIndex:indexPath.row]; [self.navigationController pushViewController:testView animated:YES]; - (void)viewDidLoad { [super viewDidLoad]; imageView.image = image; } What is causing the image to not show up in the first scenario?

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  • Bind event to AJAX populated list items

    - by AnPel
    I have an unordered list with no list items. I get some information from the user, I run it through my database using AJAX and the servers sends back a JSON object response. Then I append each list item I want to display to the list using something like $('blabla').append('<li>information</li>') My question is, since the li elements were not there at the time the DOM was ready, how can I bind a click event to them? Here is my full code: $(function(){ var timer; $('#f').keyup(function(){ clearTimeout(timer); timer = setTimeout(getSuggestions, 400); }); }) function getSuggestions(){ var a = $('#f')[0].value.length; if( a < 3){ if(a == 0){ $('#ajaxerror').hide(300,function(){ $('#loading').hide(300,function(){ $('#suggest').hide(300) }) }) } return; } $('#loading').slideDown(200,function(){ $.ajax({ url: '/models/AJAX/suggest.php', dataType: 'json', data: {'data' : $('#f')[0].value }, success: function(response){ $('#ajaxerror').hide(0,function(){ $('#loading').hide(100,function(){ $('#suggest ul li').remove(); for(var b = 0; b < ( response.rows * 3); b = b + 3){ $('#suggest ul').append('<li>'+response[b]+' '+response[b+1]+' '+response[b+2]+'</li>') // MISSING SOME CODE HERE TO BIND CLICK EVENT TO NEWLY CREATED LI } $('#suggest').show(300) }) }) }, error: function(){ $('#suggest').hide(0,function(){ $('#loading').slideUp(100,function(){ $('#ajaxerror').show(300) }) }) } }) }) }

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  • listbox select count not work dont work

    - by sadpcd
    I recently trying to make a form with multiple select box. When someone select the options the number of selected options will be display on another text. I'm a beginner in JavaScript. The function is called, but it doesn't count the number of the selected options. <select name="element_17_1[ ]" size="7" multiple="multiple" class="element select medium" id="element_17_1[ ]" onfocus="selectCount(this.form);" onClick="selectCount(this.form);" > <option value="Opt1">Opt1</option> <option value="Opt2">Opt2</option> <option value="Opt3">Opt3</option> <option value="Opt4">Opt4</option> <option value="Opt5">Opt5</option> <option value="Opt6">Opt6</option> <option value="Opt7">Opt7</option> </select> and this is the function I tried in the <head> function selectCount(f) { var selObj = myForm.elements['element_17_1[]']; var totalChecked = 0; for (i = 0; i < selObj.options.length; i++) { if (selObj.options[i].selected) { totalChecked++; } } f.element_9.value = totalChecked; }

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  • One Common View In Every ViewController

    - by l3v
    I am having a hard time wording this when searching the internet so I am just going to ask the question. I have an options view in my app that slides into view when the user clicks a button. This options view will display app information like settings. I want this options view to be displayed on every view controller in my app. I do not want to copy and paste the code for the options view into every viewcontroller file. The options view has quite a few outlets and actions and also calls many delegates. How can I reuse this options view in all my view controllers without adding all the outlets, actions, and delegate methods each time? I was going to make a new file with public methods, but I would still have to copy the outlets. Would this public methods file have to include delegate methods as well then? Let me know if my question does not make sense. I am hoping there is a standard way of implementing something like this.

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  • Is there a Twitter Bootstrap class that means "initially hidden"?

    - by bgp
    Using Bootstrap 3, I have an element on a page I want to show later in response to the user clicking a button. Example: <div id="search_results"> ... gets populated from ajax data later ... </div> <button id="search_button" type="button" class="btn btn-primary pull-right">Search</button> <script> $('#search_button').click(function() { // ... do the call to search // and in the callback: $('#search_results').show(); }); </script> The search_results div should be initially hidden. Is there some normal/best practice way of doing this with bootstrap? Yes, I do realize I can just put style="display:none" on search_results, but is that the best way to do it? It would seem to be a bit better to have a style that semantically means "initially hidden". (NOTE: The hidden or hide classes don't do this as they are !important and show(), toggle(), etc. use an inline style which does not override them, i.e. setting "hidden" as the class makes it unshowable from jQuery.)

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  • Using Color.rgb() doesnt work for full 0...255 range

    - by superflyninja
    I'm writing an android game using opengl. I'm using: colour = Color.rgb(theR,theG,theB); (all ints) to store the color of a rectangle. Then I parse out the RGB to render the rectangle: colorR = Color.red(color); colorG = Color.green(color); colorB = Color.blue(color); For example for color 53,130,255 this should result in a blue but on my app it results in a white. If i use 1,1,1 i get white. If i use 0,0,0 i get black. If i use 0,1,0 I get green etc. So it looks like any value over one is treated as 1 and so i am not getting the full 0...255 range. I tried using Color.argb and color = Color.parseColor(theColor) where the Color is a string. I'm using this in an opengles app. I have a class to display a rectangle of color. This definitely works fine as the correct size rectangle is rendered, just not a color using values above 1. I also use textures and everything displays fine. any ideas? thanks a million

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  • submit in html on sql query

    - by user1644661
    i need to run this sql query , which give me a list of Id and Dates i want to click each result and take with me the Id value to the next form i wrote this query above but i see in the debager that the hidden ID get his value but not pass to the next form i think i have a problem with the submit() . where should i put him ? thanks anat function ShowAllCarts($user_email) { $connB = new ProductDAO(); $connB->Connect(); $pro_query = "SELECT * FROM Cart WHERE `Email`='$user_email';"; $db_result = $connB->ExecSQL($pro_query); $html_result = '<div data-role="content"> <ul data-role="listview" data-theme="b"> '; $html_result .= '<form action="PreviouscartProduct.php" method="POST"/>'; while($row_array = $db_result->fetch_array(MYSQLI_ASSOC)) { $Id= $row_array['Id']; $Date= $row_array['Date']; //$html_result // $html_result .="<li><a href='PreviouscartProduct.php'>Cart number: $Id from Date: $Date><input type='hidden' name='Id' value'<?=$Id?>'</input></a></li>'"; $html_result .= '<a onclick="this.form.submit();" </a>; } $html_result .= ' </ul> </div>'; $html_result .= '</form>'; $connB->Disconnect(); return $html_result; } //display all carts $func_result = ShowAllCarts($Email);

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  • Selecting records in SQL that have the minimum value for that record based on another field

    - by Ryan
    I have a set of data, and while the number of fields and tables it joins with is quite complex, I believe I can distill my problem down using the required fields/tables here for illustration regarding this particular problem. I have three tables: ClientData, Sources, Prices Here is what my current query looks like before selecting the minimum value: select c.RecordID, c.Description, s.Source, p.Price, p.Type, p.Weight from ClientData c inner join Sources s ON c.RecordID = s.RecordID inner join Prices p ON s.SourceID = p.SourceID This produces the following result: RecordID Description Source Price Type Weight ============================================================= 001002003 ABC Common Stock Vendor 1 104.5 Close 1 001002003 ABC Common Stock Vendor 1 103 Bid 2 001002003 ABC Common Stock Vendor 2 106 Close 1 001002003 ABC Common Stock Vendor 2 100 Unknwn 0 111222333 DEF Preferred Stk Vendor 3 80 Bid 2 111222333 DEF Preferred Stk Vendor 3 82 Mid 3 111222333 DEF Preferred Stk Vendor 2 81 Ask 4 What I am trying to do is display prices that belong to the same record which have the minimum non-zero weight for that record (so the weight must be greater than 0, but it has to be the minimum from amongst the remaining weights). So in the above example, for record 001002003 I would want to show the close prices from Vendor 1 and Vendor 2 because they both have a weight of 1 (the minimum weight for that record). But for 111222333 I would want to show just the bid price from Vendor 3 because its weight of 2 is the minimum, non-zero for that record. The result that I'm after would like like: RecordID Description Source Price Type Weight ============================================================= 001002003 ABC Common Stock Vendor 1 104.5 Close 1 001002003 ABC Common Stock Vendor 2 106 Close 1 111222333 DEF Preferred Stk Vendor 3 80 Bid 2 Any ideas on how to achieve this? EDIT: This is for SQL Compact Edition.

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  • Show image on hover with PHP

    - by Sorosh
    I have a small problem with my PHP code and It would be very nice if someone could help me. I want to display an image when hovering over a link. This is the link with the PHP code that I have now: <a href="<?php the_permalink(); ?>"><?php if ( has_post_thumbnail() ) {the_post_thumbnail();} else if ( has_post_video() ) {the_post_video_image();}?></a> This code shows a image, but I want to execute this code when hovering over the link with the image: <?php echo print_image_function(); ?> The code also shows a image that belongs to a category. I don't want the initial image to disappear I simply want to show the second image on top off the first image when hovering over the first image. I don't know if it is helpful but I use Wordpress and I am not a PHP expert. I even don't know if this is going to work. Thats why I am asking if somebody can help me with this. Thanks in advance

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  • Trying to login to site with PHP & cURL?

    - by motionman95
    I've never done something like this before...I'm trying to log into swagbucks.com and get retrieve some information, but it's not working. Can someone tell me what's wrong with my script? <?php $pages = array('home' => 'http://swagbucks.com/?cmd=home', 'login' => 'http://swagbucks.com/?cmd=sb-login&from=/?cmd=home', 'schedule' => 'http://swagbucks.com/?cmd=sb-acct-account&display=2'); $ch = curl_init(); //Set options for curl session $options = array(CURLOPT_USERAGENT => 'Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; `rv:1.9.2) Gecko/20100115 Firefox/3.6',` CURLOPT_HEADER => TRUE, //CURLOPT_RETURNTRANSFER => TRUE, CURLOPT_COOKIEFILE => 'cookie.txt', CURLOPT_COOKIEJAR => 'cookies.txt'); //Hit home page for session cookie $options[CURLOPT_URL] = $pages['home']; curl_setopt_array($ch, $options); curl_exec($ch); //Login $options[CURLOPT_URL] = $pages['login']; $options[CURLOPT_POST] = TRUE; $options[CURLOPT_POSTFIELDS] = '[email protected]&pswd=jblake&persist=on'; $options[CURLOPT_FOLLOWLOCATION] = FALSE; curl_setopt_array($ch, $options); curl_exec($ch); //Hit schedule page $options[CURLOPT_URL] = $pages['schedule']; curl_setopt_array($ch, $options); $schedule = curl_exec($ch); //Output schedule echo $schedule; //Close curl session curl_close($ch); ?> But it still doesn't log me in. What's wrong?

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  • How can I add dynamic text from a different table where primary key is a foreign key to adynamic table being shown?

    - by Jethro Tamares Doble
    I have here a dynamic table named tb_user with column region_id and institute_id and both ids are primary key of another table tb_region (with column region_name and region_id) and tb_institute (column institute_id and institute_name). I wanted to see region_name and institute_name instead of the ids. I've used this php script <?php echo $row_institute['institution_name']; ?> and query to collect data for tb_institute mysql_select_db($database_connection_ched, $connection_ched); $query_institution = "SELECT institute_id, institute_name FROM tb_institute"; $institution = mysql_query($query_institution, $connection_ched) or die(mysql_error()); $row_institution = mysql_fetch_assoc($institution); $totalRows_institution = mysql_num_rows($institution); but it seems not to display the correct name of id. query i used to collect data: mysql_select_db($database_connection_ched, $connection_ched); $query_notification = sprintf("SELECT * FROM tb_user WHERE status = 'inactive' ORDER BY date_register ASC", GetSQLValueString($colname_notification, "text")); $query_limit_notification = sprintf("%s LIMIT %d, %d", $query_notification, $startRow_notification, $maxRows_notification); $notification = mysql_query($query_limit_notification, $connection_ched) or die(mysql_error()); $row_notification = mysql_fetch_assoc($notification); if (isset($_GET['totalRows_notification'])) { $totalRows_notification = $_GET['totalRows_notification']; } else { $all_notification = mysql_query($query_notification); $totalRows_notification = mysql_num_rows($all_notification); } $totalPages_notification = ceil($totalRows_notification/$maxRows_notification)-1;

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  • jQuery: change a css value if a option is selected

    - by Ivan Castellanos
    I'm trying to make an option dropdown menu and I got stuck when I try to show a textbox if the option 'other' is selected. there's what I have: <span id="con-country"><label for="country">Country: </label> <select name="country" required="required"> <option value="usa">United States</option> <option value="uk">United Kingdom</option> <option id="other" value="other">Other</option> </select> </span> <span id="con-specify"> <label for="specify">Specify: </label> <input type="text" name="specify" id="c-specify" required="required"></input> </span> CSS: #con-specify{ margin-left: 50px; display: none; } Simple huh?, the problem is that I don't know how to do the code in jQuery So, if the user select other in the menu, then the textbox should appear, how can I do that?

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  • jquery $.ajax load in UI dialog() problem

    - by alex
    i have a working bing Image search api with jsonp datatype. It's working with no problems. When i load the image search script in a Jquery UI dialog, it display properly and i'm able to search and see the results in the dialog() box. But if i close the dialog() and open it again, now if i search no results show. Looking at console.log, i do confirm the jason data is recieved, but for some reason it's not appending to the result div, so i see no result on the screen. This onyl happens if i close the dialog and open it again. If i refresh refresh the page and open the dialog again then search results are displayed. This is what i'm using to append the results. $.each(data.SearchResponse.Image.Results, function(i, item) { console.log(item.Thumbnail.Url); $("#Results").append("<li><img style='width:100px; height:75px;' src='" + item.Thumbnail.Url + "'/></li>"); });

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