Search Results

Search found 17537 results on 702 pages for 'doctrine query'.

Page 8/702 | < Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >

  • strange doctrine update problem

    - by larryzhao
    Hi, guys, I have a simple table like following: class SnookerCurrentInfo extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('current_frame_id', 'integer', 4, array('notnull' => 'false')); $this->hasColumn('current_player_id', 'integer', 4, array('notnull' => 'false')); $this->hasColumn('current_score1', 'integer', 4, array('notnull' => 'false')); $this->hasColumn('current_score2', 'integer', 4, array('notnull' => 'false')); } public function setUp(){ $this->setTableName('snooker_current_info'); } } and I would like to keep only one entry in this table. So every time the value is changed I read the entry with id = 1 out and change the object and execute save. like the following: $info = Doctrine::getTable('SnookerCurrentInfo')->find(1); $info->current_frame_id = $jsonInfo['current_frame_id']; $info->current_player_id = $jsonInfo['current_player_id']; $info->current_score1 = $jsonInfo['current_score1']; $info->current_score2 = $jsonInfo['current_score2']; $info->save(); but the strange thing is, I try to make it clear. Let's say at first, the entry is (30, 1, 1, 0) and I switch player, so update the entry to (30, 2, 1, 0). and I switch the player back again, so the entry should be updated to (30, 1, 1, 0), but this is not affected to the database!! In the database, the entry still remains as (30, 2, 1, 0)!!!! But if after (30, 2, 1, 0), I update the score to (30, 2, 1, 1) and then switch the player back (30, 1, 1, 1) then this is ok. What's that? How should I deal with it? Thanks for a lot helping, really urgent!!

    Read the article

  • Query design in SQL - ORDER BY SUM() of field in rows which meet a certain condition

    - by Christian Mann
    OK, so I have two tables I'm working with - project and service, simplified thus: project ------- id PK name str service ------- project_id FK for project time_start int (timestamp) time_stop int (timestamp) One-to-Many relationship. Now, I want to return (preferably with one query) a list of an arbitrary number of projects, sorted by the total amount of time spent at them, which is found by SUM(time_stop) - SUM(time_start) WHERE project_id = something. So far, I have SELECT project.name FROM service LEFT JOIN project ON project.id = service.project_id LIMIT 100 but I cannot figure out how what to ORDER BY.

    Read the article

  • Help with MySQL query

    - by Michael S.
    I have a table that contains the next columns: ip(varchar 255), index(bigint 20), time(timestamp) each time something is inserted there, the time column gets current timestamp. I want to run a query that returns all the rows that have been added in the last 24 hours. This is what I try to execute: SELECT ip, index FROM users WHERE ip = 'some ip' AND TIMESTAMPDIFF(HOURS,time,NOW()) < 24 And it doesn't work. Can someone help me out? Thanks :)

    Read the article

  • Cardinality Estimation Bug with Lookups in SQL Server 2008 onward

    - by Paul White
    Cost-based optimization stands or falls on the quality of cardinality estimates (expected row counts).  If the optimizer has incorrect information to start with, it is quite unlikely to produce good quality execution plans except by chance.  There are many ways we can provide good starting information to the optimizer, and even more ways for cardinality estimation to go wrong.  Good database people know this, and work hard to write optimizer-friendly queries with a schema and metadata (e.g. statistics) that reduce the chances of poor cardinality estimation producing a sub-optimal plan.  Today, I am going to look at a case where poor cardinality estimation is Microsoft’s fault, and not yours. SQL Server 2005 SELECT th.ProductID, th.TransactionID, th.TransactionDate FROM Production.TransactionHistory AS th WHERE th.ProductID = 1 AND th.TransactionDate BETWEEN '20030901' AND '20031231'; The query plan on SQL Server 2005 is as follows (if you are using a more recent version of AdventureWorks, you will need to change the year on the date range from 2003 to 2007): There is an Index Seek on ProductID = 1, followed by a Key Lookup to find the Transaction Date for each row, and finally a Filter to restrict the results to only those rows where Transaction Date falls in the range specified.  The cardinality estimate of 45 rows at the Index Seek is exactly correct.  The table is not very large, there are up-to-date statistics associated with the index, so this is as expected. The estimate for the Key Lookup is also exactly right.  Each lookup into the Clustered Index to find the Transaction Date is guaranteed to return exactly one row.  The plan shows that the Key Lookup is expected to be executed 45 times.  The estimate for the Inner Join output is also correct – 45 rows from the seek joining to one row each time, gives 45 rows as output. The Filter estimate is also very good: the optimizer estimates 16.9951 rows will match the specified range of transaction dates.  Eleven rows are produced by this query, but that small difference is quite normal and certainly nothing to worry about here.  All good so far. SQL Server 2008 onward The same query executed against an identical copy of AdventureWorks on SQL Server 2008 produces a different execution plan: The optimizer has pushed the Filter conditions seen in the 2005 plan down to the Key Lookup.  This is a good optimization – it makes sense to filter rows out as early as possible.  Unfortunately, it has made a bit of a mess of the cardinality estimates. The post-Filter estimate of 16.9951 rows seen in the 2005 plan has moved with the predicate on Transaction Date.  Instead of estimating one row, the plan now suggests that 16.9951 rows will be produced by each clustered index lookup – clearly not right!  This misinformation also confuses SQL Sentry Plan Explorer: Plan Explorer shows 765 rows expected from the Key Lookup (it multiplies a rounded estimate of 17 rows by 45 expected executions to give 765 rows total). Workarounds One workaround is to provide a covering non-clustered index (avoiding the lookup avoids the problem of course): CREATE INDEX nc1 ON Production.TransactionHistory (ProductID) INCLUDE (TransactionDate); With the Transaction Date filter applied as a residual predicate in the same operator as the seek, the estimate is again as expected: We could also force the use of the ultimate covering index (the clustered one): SELECT th.ProductID, th.TransactionID, th.TransactionDate FROM Production.TransactionHistory AS th WITH (INDEX(1)) WHERE th.ProductID = 1 AND th.TransactionDate BETWEEN '20030901' AND '20031231'; Summary Providing a covering non-clustered index for all possible queries is not always practical, and scanning the clustered index will rarely be optimal.  Nevertheless, these are the best workarounds we have today. In the meantime, watch out for poor cardinality estimates when a predicate is applied as part of a lookup. The worst thing is that the estimate after the lookup join in the 2008+ plans is wrong.  It’s not hopelessly wrong in this particular case (45 versus 16.9951 is not the end of the world) but it easily can be much worse, and there’s not much you can do about it.  Any decisions made by the optimizer after such a lookup could be based on very wrong information – which can only be bad news. If you think this situation should be improved, please vote for this Connect item. © 2012 Paul White – All Rights Reserved twitter: @SQL_Kiwi email: [email protected]

    Read the article

  • count number of business that belongs to subcategory in doctrine

    - by Ibrahim Azhar Armar
    this is follow up of this question. count number of foreign keys i am using doctrine 1.2 and i want to count the number of business that belongs to subcategory. following are the mysql tables. 1.fi_category +----+-----------------+-----------------+ | id | name | slug | +----+-----------------+-----------------+ 2.fi_subcategory +----+-----------------+-----------------+-------------+ | id | name | slug | category_id | +----+-----------------+-----------------+-------------+ 3.fi_business_subcategory +----+-------------+----------------+ | id | business_id | subcategory_id | +----+-------------+----------------+ i am using this DQL. $q = Doctrine_Query::create() ->select('c.name, c.slug, sc.name, sc.slug') ->from('Model_Category c') ->leftJoin('c.Subcategory sc') ->leftJoin('sc.BusinessSubcategory bsc'); which gives me something like this. Array ( [0] => Array ( [id] => 1 [name] => Entertainment & Lifestyle [slug] => entertainment-lifestyle [Subcategory] => Array ( [0] => Array ( [id] => 1 [name] => Arts and Crafts [slug] => arts-and-crafts ) [1] => Array ( [id] => 2 [name] => Family [slug] => family ) [2] => Array ( [id] => 3 [name] => Fashion [slug] => fashion ) ) ) ) i am looking to fetch the number of business, i.e the returned result should be something like this depending on the business it belongs. Array ( [0] => Array ( [id] => 1 [name] => Entertainment & Lifestyle [slug] => entertainment-lifestyle [Subcategory] => Array ( [0] => Array ( [id] => 1 [name] => Arts and Crafts [slug] => arts-and-crafts [business_count] => 35 ) [1] => Array ( [id] => 2 [name] => Family [slug] => family [business_count] => 10 ) [2] => Array ( [id] => 3 [name] => Fashion [slug] => fashion [business_count] => 27 ) ) ) ) tried various ways using DQL, but nothing seems to work out. any idea how should i go with what i want?

    Read the article

  • Help with SQL query (add 5% to users with conditions)

    - by Mestika
    Hi everyone, I’m having some difficulties with a query which purpose is to give users with more than one thread (called CS) in current year a 5% point “raise”. My relational schema looks like this: Thread = (threadid, threadname, threadLocation) threadoffering = (threadid, season, year, user) user = (name, points) Then, what I need is to check: WHERE thread.threadid = threadoffering.threadid AND where threadoffering.year AND threadoffering.season = currentDate AND where threadoffering.User 1 GIVE 5 % raise TO user.points I hope it is explained thoroughly but otherwise here it is in short text: Give a 5 % “point raise” to all users who has more than 1 thread in threadLocation CS in the current year and season (always dynamic, so for example now is year = 2010 and season is = spring). I am looking forward to your answer Sincerely, Emil

    Read the article

  • MYSQL - Help with a more complicated Query

    - by Joe
    I have two tables: tbl_lists and tbl_houses Inside tbl_lists I have a field called HousesList - it contains the ID's for several houses in the following format: 1# 2# 4# 51# 3# I need to be able to select the mysql fields from tbl_houses WHERE ID = any of those ID's in the list. More specifically, I need to SELECT SUM(tbl_houses.HouseValue) WHERE tbl_houses.ID IN tbl_lists.HousesList -- and I want to do this select to return the SUM for several rows in tbl_lists. Anyone can help? I'm thinking of how I can do this in a SINGLE query since I don't want to do any mysql "loops" (within PHP).

    Read the article

  • Complicated conditional SQL query

    - by DevAno1
    I'm not even sure if it's possible but I need it for my Access database. So I have following db structure : Now I need to perform a query that takes category_id from my product and do the magic : - let's say product belongs to console (category_id is in table Console) - from console_types take type_id, where category_id == category_id - but if product belongs to console_game (category_id is in table console_game) - from console_game take game_cat_id, where category_id == category_id I'm not sure if mysql is capable of such thing. If not I'm really f&%ranked up. Maybe there is a way to split this into 2,3 separate queries ?

    Read the article

  • Why Doesn’t Partition Elimination Work?

    - by Paul White
    Given a partitioned table and a simple SELECT query that compares the partitioning column to a single literal value, why does SQL Server read all the partitions when it seems obvious that only one partition needs to be examined? Sample Data The following script creates a table, partitioned on the char(3) column ‘Div’, and populates it with 100,000 rows of data: USE Sandpit; GO CREATE PARTITION FUNCTION PF ( char (3)) AS RANGE RIGHT FOR VALUES ( '1' , '2' , '3' , '4' , '5' , '6' , '7' , '8' , '9'...(read more)

    Read the article

  • SQL SERVER – Get Latest SQL Query for Sessions – DMV

    - by pinaldave
    In recent SQL Training I was asked, how can one figure out what was the last SQL Statement executed in sessions. The query for this is very simple. It uses two DMVs and created following quick script for the same. SELECT session_id, TEXT FROM sys.dm_exec_connections CROSS APPLY sys.dm_exec_sql_text(most_recent_sql_handle) AS ST While working with DMVs if you ever find any DMV has column with name sql_handle you can right away join that DMV with another DMV sys.dm_exec_sql_text and can get the text of the SQL statement. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: DMV, SQL DMV

    Read the article

  • optimizing an sql query using inner join and order by

    - by Sergio B
    I'm trying to optimize the following query without success. Any idea where it could be indexed to prevent the temporary table and the filesort? EXPLAIN SELECT SQL_NO_CACHE `groups`.* FROM `groups` INNER JOIN `memberships` ON `groups`.id = `memberships`.group_id WHERE ((`memberships`.user_id = 1) AND (`memberships`.`status_code` = 1 AND `memberships`.`manager` = 0)) ORDER BY groups.created_at DESC LIMIT 5;` +----+-------------+-------------+--------+--------------------------+---------+---------+---------------------------------------------+------+----------------------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------------+--------+--------------------------+---------+---------+---------------------------------------------+------+----------------------------------------------+ | 1 | SIMPLE | memberships | ref | grp_usr,grp,usr,grp_mngr | usr | 5 | const | 5 | Using where; Using temporary; Using filesort | | 1 | SIMPLE | groups | eq_ref | PRIMARY | PRIMARY | 4 | sportspool_development.memberships.group_id | 1 | | +----+-------------+-------------+--------+--------------------------+---------+---------+---------------------------------------------+------+----------------------------------------------+ 2 rows in set (0.00 sec) +--------+------------+-----------------------------------+--------------+-----------------+-----------+-------------+----------+--------+------+------------+---------+ | Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | +--------+------------+-----------------------------------+--------------+-----------------+-----------+-------------+----------+--------+------+------------+---------+ | groups | 0 | PRIMARY | 1 | id | A | 6 | NULL | NULL | | BTREE | | | groups | 1 | index_groups_on_name | 1 | name | A | 6 | NULL | NULL | YES | BTREE | | | groups | 1 | index_groups_on_privacy_setting | 1 | privacy_setting | A | 6 | NULL | NULL | YES | BTREE | | | groups | 1 | index_groups_on_created_at | 1 | created_at | A | 6 | NULL | NULL | YES | BTREE | | | groups | 1 | index_groups_on_id_and_created_at | 1 | id | A | 6 | NULL | NULL | | BTREE | | | groups | 1 | index_groups_on_id_and_created_at | 2 | created_at | A | 6 | NULL | NULL | YES | BTREE | | +--------+------------+-----------------------------------+--------------+-----------------+-----------+-------------+----------+--------+------+------------+---------+ +-------------+------------+----------------------------------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+ | Table | Non_unique | Key_name | Seq_in_index | Column_name | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment | +-------------+------------+----------------------------------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+ | memberships | 0 | PRIMARY | 1 | id | A | 2 | NULL | NULL | | BTREE | | | memberships | 0 | grp_usr | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 0 | grp_usr | 2 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | grp | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | usr | 1 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | grp_mngr | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | grp_mngr | 2 | manager | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 1 | group_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 2 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 3 | status_code | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | complex_index | 4 | manager | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | index_memberships_on_user_id_and_status_code_and_manager | 1 | user_id | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | index_memberships_on_user_id_and_status_code_and_manager | 2 | status_code | A | 2 | NULL | NULL | YES | BTREE | | | memberships | 1 | index_memberships_on_user_id_and_status_code_and_manager | 3 | manager | A | 2 | NULL | NULL | YES | BTREE | | +-------------+------------+----------------------------------------------------------+--------------+-------------+-----------+-------------+----------+--------+------+------------+---------+

    Read the article

  • how to write this typical mysql query( ho to use subquery column into main query)

    - by I Like PHP
    I HAVE TWO TABLES shown below table_joining id join_id(PK) transfer_id(FK) unit_id transfer_date joining_date 1 j_1 t_1 u_1 2010-06-05 2010-03-05 2 j_2 t_2 u_3 2010-05-10 2010-03-10 3 j_3 t_3 u_6 2010-04-10 2010-01-01 4 j_5 NULL u_3 NULL 2010-06-05 5 j_6 NULL u_4 NULL 2010-05-05 table_transfer id transfer_id(PK) pastUnitId futureUnitId effective_transfer_date 1 t_1 u_3 u_1 2010-06-05 2 t_2 u_6 u_1 2010-05-10 3 t_3 u_5 u_3 2010-04-10 now i want to know total employee detalis( using join_id) which are currently working on unit u_3 . means i want only join_id j_1 (has transfered but effective_transfer_date is future date, right now in u_3) j_2 ( tansfered and right now in `u_3` bcoz effective_transfer_date has been passed) j_6 ( right now in `u_3` and never transfered) what i need to take care of below steps( as far as i know ) <1> first need to check from table_joining whether transfer_id is NULL or not <2> if transfer_id= is NULL then see unit_id=u_3 where joining_date <=CURDATE() ( means that person already joined u_3) <3> if transfer_id is NOT NULL then go to table_transfer using transfer_id (foreign key reference) <4> now see the effective_transfer_date regrading that transfer_id whether effective_transfer_date<=CURDATE() <5> if transfer date has been passed(means transfer has been done) then return futureUnitID otherwise return pastUnitID i used two separate query but don't know how to join those query?? for step <1 ans <2 SELECT unit_id FROM table_joining WHERE joining_date<=CURDATE() AND transfer_id IS NULL AND unit_id='u_3' for step<5 SELECT IF(effective_transfer_date <= CURDATE(),futureUnitId,pastUnitId) AS currentUnitID FROM table_transfer // here how do we select only those rows which have currentUnitID='u_3' ?? please guide me the process?? i m just confused with JOINS. i think using LEFT JOIN can return the data i need, but i m not getting how to implement ...please help me. Thanks for helping me alwayz

    Read the article

  • Designing complex query builders in java/jpa/hibernate

    - by Ramraj Edagutti
    I need to build complex sql queries programatically, based on large filter conditions. For example, below are few sample/hypothitical filter conditions, based on which i need to fetch users Country: india States: Andhra Pradesh(AP), Gujarat(GUJ), karnataka(KTK) Districts: All districts in AP except 3 district, 5 any districts from GUJ, all district from KTK except 1 district Cities: All cities in AP, all cities except few, include only 50 specific cities from KTK Villages: similar conditions like above with varies combinations... Currently, we have a query builder, which is very complex in nature, and not easy to modify/re-factory for improvements. So, thinking of complete re-design of it. Any suggesations on how to build this kind of complex query builders programmatically using some best practices/deisgn patterns?

    Read the article

  • Power Query in Modern Corporate BI–Copenhagen, June 3, 2014–#powerquery

    - by Marco Russo (SQLBI)
    I will be in Copenhagen to deliver the SSAS Tabular Workshop on June 2-4, 2014 (few seats still available, but hurry up!). In the same week I will be a speaker in an evening community event, MsBIP møde nr. 21, delivering the Power Query in Modern Corporate BI session that I also presented at TechEd North America 2014 last week. It’s not just a session about Power Query, there is a broader scope related to Corporate BI vs. Self-Service BI, which could be open to many consideration. I think that the two worlds can (and should) collaborate, instead of fighting against each other, especially when there is an existing investment in Corporate BI. I hope to meet many of you there!

    Read the article

  • How to programmatically construct textual query

    - by stibi
    Here is a query language, more specifically, it's JQL, you can use it in Jira, to search for issues, it's something like SQL, but quite simpler. My case is that, I need to construct such queries programmatically, in my application. Something like: JQLMachine jqlMachine = new JQLMachine() jqlMachine.setStatuses("Open", "In Progress") jqlMachine.setReporter("foouser", "baruser") jqlMachine.setDateRange(...) jqlMachine.getQuery() --> String with corresponding JQL query is returned You get my point I hope. I can imagine the code for this, but it's not nice, using my current knowledge how I'd do that. That's why I'm asking. What you'd advice to use to create such thing. I believe some patterns for creating something like this already exist and there is already best practices, how to do that in good way.

    Read the article

  • $query returns results but not the ones i want: $query looks good to me :S

    - by Toni Michel Caubet
    I'll start again, Lets say My data is: Table element (id,name,....) 1, name element 1, .... 2, name element 2, .... 3, name element 3, .... Table tags (id,name,id_element, ....) 1, happy , 1 2, result, 1 3, very , 1 4, element, 2 5, another, 3 6, element, 1 7, happy, 2 So if search is 'very, happy,element,result': Results i would like 1) element with id = 2 because it has all tags 2) element with id = 1 because it has the tag 'element' and the tag 'happy' (only 2 less taggs) 3) .... (only 3 less taggs) So if search is 'happy,element': Results i would like 1) element with id = 1 because it has all tags (and no more) 2) element with id = 2 because it has the tag 'element' and the tag 'happy' (and two more tags) 3) .... and 3 more tags This is an echo to my query: (it doesn't fit al requirements i wrote, but its first test to find with matched tags) SELECT element.id as id_deseada,tagg.* FROM element,tagg WHERE tagg.id_element = element.id AND tagg.nombre IN ('happy','tagg','result') GROUP BY tagg.id_element ORDER BY element.votos This returns 10 duplicated elements... :S and doen't even have all taggs (and on database there are taggs with 'happy' results) if it helps, thats how i get the elements of a tag (by name and with only one tagg) $query = "SELECT element.id FROM element,tagg WHERE tagg.nombre = '$nombre_tagg' AND tagg.id_element = element.id AND lan = '$lan' GROUP BY tagg.id_element"; I hope it's a bit easier to understand now, excuse my english.. :) Thanks a lot for you possible aportation!

    Read the article

  • PHP Doctrine: Filter Table?

    - by ropstah
    I'm still not convinced after my previous question and some experience. Requirements: I don't want to use an SQL query everytime a filterBy() function is called and still be able to call -filterBy() on the returned table. Please find the comment @ ObjectsTable class: "How to instantiate another table and add records which match the filter criteria?" Usage: $globaltable = new ObjectsTable(); //globally accessible variable $globaltable->findAll(); //this call is made once at the beginning of the request $globaltable->filterBy('somefield', $someValue); //this function is used all over the place ObjectsTable class: class ObjectsTable extends Doctrine_Table { function filterBy($field, $value) { //How to instantiate another table and add records which match the criteria? } }

    Read the article

  • Check if hydrated doctrine result is NULL

    - by iggnition
    Hi, I'm trying to check if a result in my DQL is NULL. I got the following DQL query: $q = self::createQuery("l") ->select('i.*, s.aantal, m.naam, c.cat_naam, a.app_id') ->from('InstalledBase i, i.Spare s, i.Apparaat a, a.Categorie c, a.Merk m') ->execute(); return $q; Now i want to check if the s.aantal is NULL so i do: if(is_null($installedbase->Spare->spare_id)) when the variable is NOT null everything works, but when it is actually NULL i get a E notice message: Notice: Trying to get property of non-object in \installedbase\templates\_index.php on line 29 It does see that it is null though because the if condition is executed. Weird thing is i'm doing the exact same thing on another page where it works no problem. But i must be doing something wrong or stupid since those messages generally don't show for nothing. So can anybody explain this to me? :)

    Read the article

  • Subquery Doctrine Couldn't find class

    - by yosesita
    I'm trying to create a query like this one : $q = Doctrine_Query::create() -select('p.nombre') -addSelect('(select count(*) from alojamiento a left join localidad l on a.localidad_id=l.id where p.id=l.provincia_id and a.activo=true)') -from('provincia p'); but it fails : error 500, couldn't find class a. And : $q = Doctrine_Query::create() -select('nombre') -addSelect('(select count(*) from alojamiento left join localidad on alojamiento.localidad_id=localidad.id where provincia.id=localidad.provincia_id and alojamiento.activo=true)') -from('provincia'); leads to : SQLSTATE[42S22]: Column not found: 1054 Unknown column 'a.localidad_id' in 'on clause'. Any help would be greatly appreciated !

    Read the article

  • How can I handle this kind of exceptions (in Doctrine)

    - by ppavlovic
    Can you tell me how can I handle this kind of exceptions: Fatal error: Uncaught exception 'Doctrine_Connection_Exception' with message 'PDO Connection Error: SQLSTATE[HY000] [2013] Lost connection to MySQL server at 'reading initial communication packet', system error: 110' in ... It happens when connection with MySQL is lost during query. I need to handle this exception so I can show 500 error page so the crawlers do not cache page, and to redirect user to appropriate "Try again" page. P.S. I have a lot's of code, so I can not go trough all code to put try/catch block. I need something simple and yet effective.

    Read the article

  • SQL SERVER – Example of Performance Tuning for Advanced Users with DB Optimizer

    - by Pinal Dave
    Performance tuning is such a subject that everyone wants to master it. In beginning everybody is at a novice level and spend lots of time learning how to master the art of performance tuning. However, as we progress further the tuning of the system keeps on getting very difficult. I have understood in my early career there should be no need of ego in the technology field. There are always better solutions and better ideas out there and we should not resist them. Instead of resisting the change and new wave I personally adopt it. Here is a similar example, as I personally progress to the master level of performance tuning, I face that it is getting harder to come up with optimal solutions. In such scenarios I rely on various tools to teach me how I can do things better. Once I learn about tools, I am often able to come up with better solutions when I face the similar situation next time. A few days ago I had received a query where the user wanted to tune it further to get the maximum out of the performance. I have re-written the similar query with the help of AdventureWorks sample database. SELECT * FROM HumanResources.Employee e INNER JOIN HumanResources.EmployeeDepartmentHistory edh ON e.BusinessEntityID = edh.BusinessEntityID INNER JOIN HumanResources.Shift s ON edh.ShiftID = s.ShiftID; User had similar query to above query was used in very critical report and wanted to get best out of the query. When I looked at the query – here were my initial thoughts Use only column in the select statements as much as you want in the application Let us look at the query pattern and data workload and find out the optimal index for it Before I give further solutions I was told by the user that they need all the columns from all the tables and creating index was not allowed in their system. He can only re-write queries or use hints to further tune this query. Now I was in the constraint box – I believe * was not a great idea but if they wanted all the columns, I believe we can’t do much besides using *. Additionally, if I cannot create a further index, I must come up with some creative way to write this query. I personally do not like to use hints in my application but there are cases when hints work out magically and gives optimal solutions. Finally, I decided to use Embarcadero’s DB Optimizer. It is a fantastic tool and very helpful when it is about performance tuning. I have previously explained how it works over here. First open DBOptimizer and open Tuning Job from File >> New >> Tuning Job. Once you open DBOptimizer Tuning Job follow the various steps indicates in the following diagram. Essentially we will take our original script and will paste that into Step 1: New SQL Text and right after that we will enable Step 2 for Generating Various cases, Step 3 for Detailed Analysis and Step 4 for Executing each generated case. Finally we will click on Analysis in Step 5 which will generate the report detailed analysis in the result pan. The detailed pan looks like. It generates various cases of T-SQL based on the original query. It applies various hints and available hints to the query and generate various execution plans of the query and displays them in the resultant. You can clearly notice that original query had a cost of 0.0841 and logical reads about 607 pages. Whereas various options which are just following it has different execution cost as well logical read. There are few cases where we have higher logical read and there are few cases where as we have very low logical read. If we pay attention the very next row to original query have Merge_Join_Query in description and have lowest execution cost value of 0.044 and have lowest Logical Reads of 29. This row contains the query which is the most optimal re-write of the original query. Let us double click over it. Here is the query: SELECT * FROM HumanResources.Employee e INNER JOIN HumanResources.EmployeeDepartmentHistory edh ON e.BusinessEntityID = edh.BusinessEntityID INNER JOIN HumanResources.Shift s ON edh.ShiftID = s.ShiftID OPTION (MERGE JOIN) If you notice above query have additional hint of Merge Join. With the help of this Merge Join query hint this query is now performing much better than before. The entire process takes less than 60 seconds. Please note that it the join hint Merge Join was optimal for this query but it is not necessary that the same hint will be helpful in all the queries. Additionally, if the workload or data pattern changes the query hint of merge join may be no more optimal join. In that case, we will have to redo the entire exercise once again. This is the reason I do not like to use hints in my queries and I discourage all of my users to use the same. However, if you look at this example, this is a great case where hints are optimizing the performance of the query. It is humanly not possible to test out various query hints and index options with the query to figure out which is the most optimal solution. Sometimes, we need to depend on the efficiency tools like DB Optimizer to guide us the way and select the best option from the suggestion provided. Let me know what you think of this article as well your experience with DB Optimizer. Please leave a comment. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Joins, SQL Optimization, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

    Read the article

  • SQL Intersection Conference, Las Vegas MGM Grand 10-13 November 2014

    - by Paul White
    I am very pleased to announce that I will be speaking at the SQL Intersection conference in Las Vegas again this year. This time around, I am giving a full-day workshop, "Mastering SQL Server Execution Plan Analysis" as well as a two-part session, "Parallel Query Execution" during the main conference. The workshop is a pre-conference event, held on Sunday 9 November (straight after this year's PASS Summit). Being on Sunday gives you the whole Monday off to recover and before the...(read more)

    Read the article

  • sort mysql query by filtered query

    - by kalpaitch
    I have two mysql queries: $sql = "SELECT * FROM content WHERE threadName LIKE '%$filter%' ORDER BY lastUpdated desc"; and $sql = "SELECT * FROM content ORDER BY lastUpdated desc"; The end result is to have all rows returned from a particular table 'content' but have those that match the variable $filter at the top. Is there either a single query that could combine these two or should I be using a JOIN?

    Read the article

  • How to apply GROUP_CONCAT in mysql Query

    - by Query Master
    How to apply GROUP_CONCAT in this Query if you guys have any idea or any alternate solution about this please share me. Helps are definitely appreciated also (see Query or result required) Query SELECT WEEK(cpd.added_date) AS week_no,COUNT(cpd.result) AS death_count FROM cron_players_data cpd WHERE cpd.player_id = 81 AND cpd.result = 2 AND cpd.status = 1 GROUP BY WEEK(cpd.added_date); Query output result screen Result Required 23,24,25 AS week_no 2,3,1 AS death_count

    Read the article

< Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >