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  • NHibernate mapping error SQL Server 2008 Express

    - by developer
    Hi All, I tried an example from NHibernate in Action book and when I try to run the app, it throws an exception saying "Could not compile the mapping document: HelloNHibernate.Employee.hbm.xml" Below is my code, Employee.hbm.xml <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" auto-import="true"> <class name="HelloNHibernate.Employee, HelloNHibernate" lazy="false" table="Employee"> <id name="id" access="field"> <generator class="native"/> </id> <property name="name" access="field" column="name"/> <many-to-one access="field" name="manager" column="manager" cascade="all"/> </class> Program.cs using System; using System.Collections.Generic; using System.Linq; using System.Text; using NHibernate; using System.Reflection; using NHibernate.Cfg; namespace HelloNHibernate { class Program { static void Main(string[] args) { CreateEmployeeAndSaveToDatabase(); UpdateTobinAndAssignPierreHenriAsManager(); LoadEmployeesFromDatabase(); Console.WriteLine("Press any key to exit..."); Console.ReadKey(); } static void CreateEmployeeAndSaveToDatabase() { Employee tobin = new Employee(); tobin.name = "Tobin Harris"; using (ISession session = OpenSession()) { using (ITransaction transaction = session.BeginTransaction()) { session.Save(tobin); transaction.Commit(); } Console.WriteLine("Saved Tobin to the database"); } } static ISession OpenSession() { if (factory == null) { Configuration c = new Configuration(); c.AddAssembly(Assembly.GetCallingAssembly()); factory = c.BuildSessionFactory(); } return factory.OpenSession(); } static void LoadEmployeesFromDatabase() { using (ISession session = OpenSession()) { IQuery query = session.CreateQuery("from Employee as emp order by emp.name asc"); IList<Employee> foundEmployees = query.List<Employee>(); Console.WriteLine("\n{0} employees found:", foundEmployees.Count); foreach (Employee employee in foundEmployees) Console.WriteLine(employee.SayHello()); } } static void UpdateTobinAndAssignPierreHenriAsManager() { using (ISession session = OpenSession()) { using (ITransaction transaction = session.BeginTransaction()) { IQuery q = session.CreateQuery("from Employee where name='Tobin Harris'"); Employee tobin = q.List<Employee>()[0]; tobin.name = "Tobin David Harris"; Employee pierreHenri = new Employee(); pierreHenri.name = "Pierre Henri Kuate"; tobin.manager = pierreHenri; transaction.Commit(); Console.WriteLine("Updated Tobin and added Pierre Henri"); } } } static ISessionFactory factory; } } Employee.cs using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace HelloNHibernate { class Employee { public int id; public string name; public Employee manager; public string SayHello() { return string.Format("'Hello World!', said {0}.", name); } } } App.config <?xml version="1.0" encoding="utf-8" ?> <configuration> <configSections> <section name="hibernate-configuration" type="NHibernate.Cfg.ConfigurationSectionHandler,NHibernate"/> </configSections> <hibernate-configuration xmlns="urn:nhibernate-configuration-2.2"> <session-factory> <property name="connection.provider">NHibernate.Connection.DriverConnectionProvider</property> <property name="connection.driver_class">NHibernate.Driver.SqlClientDriver</property> <property name="connection.connection_string"> Data Source=SQLEXPRESS2008;Integrated Security=True; User ID=SQL2008;Password=;initial catalog=HelloNHibernate </property> <property name="dialect">NHibernate.Dialect.MsSql2008Dialect</property> <property name="show_sql">false</property> </session-factory> </hibernate-configuration> </configuration>

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  • How to minimize the risk of employees spreading critical information?

    - by Industrial
    Hi everyone, What's common sense when it comes to minimising the risk of employees spreading critical information to rivalling companies? As of today, it's clear that not even the US government and military can be sure that their data stays safely within their doors. Thereby I understand that my question probably instead should be written as "What is common sense to make it harder for employees to spread business critical information?" If anyone would want to spread information, they will find a way. That's the way life work and always has. If we make the scenario a bit more realistic by narrowing our workforce by assuming we only have regular John Does onboard and not Linux-loving sysadmins , what should be good precautions to at least make it harder for the employees to send business-critical information to the competition? As far as I can tell, there's a few obvious solutions that clearly has both pros and cons: Block services such as Dropbox and similar, preventing anyone to send gigabytes of data through the wire. Ensure that only files below a set size can be sent as email (?) Setup VLANs between departments to make it harder for kleptomaniacs and curious people to snoop around. Plug all removable media units - CD/DVD, Floppy drives and USB Make sure that no configurations to hardware can be made (?) Monitor network traffic for non-linear events (how?) What is realistic to do in a real world? How does big companies handle this? Sure, we can take the former employer to court and sue, but by then the damage has already been caused... Thanks a lot

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  • How to minimize the risk of employees spreading critical information? [closed]

    - by Industrial
    What's common sense when it comes to minimising the risk of employees spreading critical information to rivalling companies? As of today, it's clear that not even the US government and military can be sure that their data stays safely within their doors. Thereby I understand that my question probably instead should be written as "What is common sense to make it harder for employees to spread business critical information?" If anyone would want to spread information, they will find a way. That's the way life work and always has. If we make the scenario a bit more realistic by narrowing our workforce by assuming we only have regular John Does onboard and not Linux-loving sysadmins , what should be good precautions to at least make it harder for the employees to send business-critical information to the competition? As far as I can tell, there's a few obvious solutions that clearly has both pros and cons: Block services such as Dropbox and similar, preventing anyone to send gigabytes of data through the wire. Ensure that only files below a set size can be sent as email (?) Setup VLANs between departments to make it harder for kleptomaniacs and curious people to snoop around. Plug all removable media units - CD/DVD, Floppy drives and USB Make sure that no configurations to hardware can be made (?) Monitor network traffic for non-linear events (how?) What is realistic to do in a real world? How does big companies handle this? Sure, we can take the former employer to court and sue, but by then the damage has already been caused... Thanks a lot

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  • Un blogueur dévoile un iPhone tournant sous Android, alors que les relations entre Google et Apple s

    Un blogueur dévoile un iPhone tournant sous Android, alors que les relations entre Google et Apple sont au plus mal Alors que la situation est des plus tendues entre Apple et Google, les deux concurrents se retrouvent réunis sur un même appareil. Un informaticien passionné a en effet trouvé le moyen de faire tourner son iPhone sous Android. Cela fait déjà un an qu'il essaie et expérimentent divers techniques pour arriver à cette cohabitation de systèmes, avec plus ou moins de succès. Il dit avoir perdu du temps en se laissant distraire par le jailbreak. Grâce au dual boot, ils peuvent passer le l'OS iPhone à celui de Google. Planetbeing, le blogueur derrière cette initiative, a publié aujourd'hui une v...

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  • Creating multiple relationships in rails with same datatypes

    - by Lowgain
    What I am trying to do is kind of like this: I have datatypes "user" and "article" for instance. I want to have relationships between these two, but in more than one way. So for instance, I'd like to let a user "like" or "bookmark" an article. So I need to have two relations in the database, one for users liking the article, and one for users bookmarking, so making a "user_article" table for instance won't be sufficient, correct? What is the best way of going about doing this?

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  • Am I personally liable for bugs in medical software I've developed as an employee? [closed]

    - by user466406
    Some background: I'm employed at a small, Australia-based web agency that is dipping it's toe into Mobile Application development (iOS). The project that I'm working on provides a way for users to save medication dosage information which is sync'd with a backend server. Users must agree to ToS, Disclaimer etc before using the application. This is my first iOS application, and the project is currently over budget. As a result, management is not devoting the resources to Q&A and is pushing instead for more features. I am an employee of the agency, that has been contracted by a non-for-profit. The application will probably be released under our agency's name, but we also have the option of releasing it as the not-for-profit. My question is, if there are bugs found in the application, and as a result a user takes an incorrect dosage of a medication, am I personally liable? Is there anything that I can or should do in order to protect myself personally?

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  • Ruby - calling constructor without arguments & removal of new line characters

    - by Raj
    I am a newbie at Ruby, I have written down a sample program. I dont understand the following: Why constructor without any arguments are not called in Ruby? How do we access the class variable outside the class' definition? Why does it always append newline characters at the end of the string? How do we strip it? Code: class Employee attr_reader :empid attr_writer :empid attr_writer :name def name return @name.upcase end attr_accessor :salary @@employeeCount = 0 def initiaze() @@employeeCount += 1 puts ("Initialize called!") end def getCount return @@employeeCount end end anEmp = Employee.new print ("Enter new employee name: ") anEmp.name = gets() print ("Enter #{anEmp.name}'s employee ID: ") anEmp.empid = gets() print ("Enter salary for #{anEmp.name}: ") anEmp.salary = gets() theEmpName = anEmp.name.split.join("\n") theEmpID = anEmp.empid.split.join("\n") theEmpSalary = anEmp.salary.split.join("\n") anEmp = Employee.new() anEmp = Employee.new() theCount = anEmp.getCount puts ("New employee #{theEmpName} with employee ID #{theEmpID} has been enrolled, welcome to hell! You have been paid as low as $ #{theEmpSalary}") puts ("Total number of employees created = #{theCount}") Output: Enter new employee name: Lionel Messi Enter LIONEL MESSI 's employee ID: 10 Enter salary for LIONEL MESSI : 10000000 New employee LIONEL MESSI with employee ID 10 has been enrolled, welcome to hell! You have been paid as low as $ 10000000 Total number of employees created = 0 Thanks

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  • GWT + JDO + ArrayList

    - by dvieira
    Hi, I'm getting a Null ArrayList in a program i'm developing. For testing purposes I created this really small example that still has the same problem. I already tried diferent Primary Keys, but the problem persists. Any ideas or suggestions? 1-Employee class @PersistenceCapable(identityType = IdentityType.APPLICATION) public class Employee { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) @Extension(vendorName="datanucleus", key="gae.encoded-pk", value="true") private String key; @Persistent private ArrayList<String> nicks; public Employee(ArrayList<String> nicks) { this.setNicks(nicks); } public String getKey() { return key; } public void setNicks(ArrayList<String> nicks) { this.nicks = nicks; } public ArrayList<String> getNicks() { return nicks; } } 2-EmployeeService public class BookServiceImpl extends RemoteServiceServlet implements EmployeeService { public void addEmployee(){ ArrayList<String> nicks = new ArrayList<String>(); nicks.add("name1"); nicks.add("name2"); Employee employee = new Employee(nicks); PersistenceManager pm = PMF.get().getPersistenceManager(); try { pm.makePersistent(employee); } finally { pm.close(); } } /** * @return * @throws NotLoggedInException * @gwt.typeArgs <Employee> */ public Collection<Employee> getEmployees() { PersistenceManager pm = getPersistenceManager(); try { Query q = pm.newQuery("SELECT FROM " + Employee.class.getName()); Collection<Employee> list = pm.detachCopyAll((Collection<Employee>)q.execute()); return list; } finally { pm.close(); } } }

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  • Passing models between controllers in MVC4

    - by wtfsven
    I'm in the middle of my first foray into web development with MVC4, and I've run into a problem that I just know is one of the core issues in web development in general, but can't seem to wrap my mind around it. So I have two models: Employee and Company. Employee has a Company, therefore /Employee/Create contains a field that is either a dropdown list for selecting an existing Company, or an ActionLink to /Company/Create if none exists. But here's the issue: If a user has to create a Company, I need to preserve the existing Employee model across both Views--over to /Company/Create, then back to /Employee/Create. So my first approach was to pass the Employee model to /Company/Create with a @Html.ActionLink("Add...", "Create", "Organization", Model , null), but then when I get to Company's Create(Employee emp), all of emp's values are null. The second problem is that if I try to come back to /Employee/Create, I'd be passing back an Employee, which would resolve to the POST Action. Basically, the whole idea is to save the state of the /Employee/Create page, jump over to /Company/Create to create a Company record, then back to /Employee/Create to finish creating the Employee. I know there is a well understood solution to this because , but I can't seem to phase it well enough to get a good Google result out of it. I've though about using Session, but it seems like doing so would be a bit of a kludge. I'd really like an elegant solution to this.

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  • Configuring JPA Primary key sequence generators

    - by pachunoori.vinay.kumar(at)oracle.com
    This article describes the JPA feature of generating and assigning the unique sequence numbers to JPA entity .This article provides information on jpa sequence generator annotations and its usage. UseCase Description Adding a new Employee to the organization using Employee form should assign unique employee Id. Following description provides the detailed steps to implement the generation of unique employee numbers using JPA generators feature Steps to configure JPA Generators 1.Generate Employee Entity using "Entities from Table Wizard". View image2.Create a Database Connection and select the table "Employee" for which entity will be generated and Finish the wizards with default selections. View image 3.Select the offline database sources-Schema-create a Sequence object or you can copy to offline db from online database connection. View image 4.Open the persistence.xml in application navigator and select the Entity "Employee" in structure view and select the tab "Generators" in flat editor. 5.In the Sequence Generator section,enter name of sequence "InvSeq" and select the sequence from drop down list created in step3. View image 6.Expand the Employees in structure view and select EmployeeId and select the "Primary Key Generation" tab.7.In the Generated value section,select the "Use Generated value" check box ,select the strategy as "Sequence" and select the Generator as "InvSeq" defined step 4. View image   Following annotations gets added for the JPA generator configured in JDeveloper for an entity To use a specific named sequence object (whether it is generated by schema generation or already exists in the database) you must define a sequence generator using a @SequenceGenerator annotation. Provide a unique label as the name for the sequence generator and refer the name in the @GeneratedValue annotation along with generation strategy  For  example,see the below Employee Entity sample code configured for sequence generation. EMPLOYEE_ID is the primary key and is configured for auto generation of sequence numbers. EMPLOYEE_SEQ is the sequence object exist in database.This sequence is configured for generating the sequence numbers and assign the value as primary key to Employee_id column in Employee table. @SequenceGenerator(name="InvSeq", sequenceName = "EMPLOYEE_SEQ")   @Entity public class Employee implements Serializable {    @Id    @Column(name="EMPLOYEE_ID", nullable = false)    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator="InvSeq")   private Long employeeId; }   @SequenceGenerator @GeneratedValue @SequenceGenerator - will define the sequence generator based on a  database sequence object Usage: @SequenceGenerator(name="SequenceGenerator", sequenceName = "EMPLOYEE_SEQ") @GeneratedValue - Will define the generation strategy and refers the sequence generator  Usage:     @GeneratedValue(strategy = GenerationType.SEQUENCE, generator="name of the Sequence generator defined in @SequenceGenerator")

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  • Using Include() with inherited entities problem

    - by Peter Stegnar
    In EF eager loading related entities is easy. But I'm having difficulties including inherited entities when loading data using table-per-type model. This is my model: Entities: ArticleBase (base article entity) ArticleSpecial (inherited from ArticleBase) UserBase (base user entity) UserSpecial (inherited from UserBase) Image Relations are as shown on the image (omitting many columns): In reality my users are always of type UserSpecial, since UserBase is used in another application, thus we can share credentials. That's the only reason I have two separate tables. UserBase table can't be changed in any way shape or form, because the other app would break. Question How am I suppose to load ArticleSpecial with both CreatedBy and EditedBy set, so that both are of type UserSpecial (that defines Image relation)? I've tried (unsuccessfully though) these options: 1. Using lambda expressions: context.ArticleBases .OfType<ArticleSpecial>() .Include("UserCreated.Image") .Include("UserEdited.Image"); In this case the problem is that both CreatedBy and EditedBy are related to UserBase, that doesn't define Image navigation. So I should somehow cast these two to UserSpecial type like: context.ArticleBases .OfType<ArticleSpecial>() .Include("UserCreated<UserSpecial>.Image") .Include("UserEdited<UserSpecial>.Image"); But of course using generics in Include("UserCreated<UserSpecial>.Image") don't work. 2. I have tried using LINQ query var results = from articleSpecial in ctx.ArticleBase.OfType<ArticleSpecial>() join created in ctx.UserBase.OfType<UserSpecial>().Include("Image") on articleSpecial.UserCreated.Id equals created.Id join edited in ctx.UserBase.OfType<UserSpecial>().Include("Image") on articleSpecial.UserEdited.Id equals edited.Id select articleSpecial; In this case I'm only getting ArticleSpecial object instances without related properties being set. I know I should select those somehow, but I don't know how? Select part in my LINQ could be changed to something like select new { articleSpecial, articleSpecial.UserCreated, articleSpecial.UserEdited }; but images are still not loaded into my context. My joins in this case are barely used to filter out articleSpecial results, but they don't load entities into context (I suppose). Can anybody provide any help regarding this problem? I think it's not so uncommon.

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  • Need help deciding if Joomla! experience as a good metric for hiring a particular prospective employee.

    - by Stephen
    My company has been looking to hire a PHP developer. Some of the requirements for the job include: an understanding of design patterns, particularly MVC. some knowledge of PHP 5.3's new features. experience working with a PHP framework (it doesn't matter which one). I interviewed a man today who's primary work experience involved working with Joomla!. As an employee, he will be required to work on existing and new web applications that use Zend Framework, CakePHP and/or CodeIgniter. It is my opinion that we shouldn't dismiss hiring a developer just because he has not used the same technologies that he'll be using on the job. So, I'd like to know about the kind of coding experience working with Joomla! can provide. I've never bothered to take more than a brief look (if that) at the Joomla! package, so I'm hoping to lean on the knowledge of my peers. Would you consider Joomla! to contain a professional code-base? Is the package well organized, and/or OO in general, or is it more like WordPress where logic and presentation are commingled? When working with Joomla!, is the developer encouraged to use best practices? In your opinion, would experience working with Joomla! garner the skills needed to get up to speed with Zend or CakePHP quickly, or will there be a steep learning curve ahead of the developer? I'm not saying that Joomla! is a bad technology, or even that it is lower on the totem pole when compared to the frameworks I've mentioned. Maybe it's awesome, I dunno. I simply have no idea!

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  • Json.Net Issues: StackOverflowException is thrown when serialising circular dependent ISerializable object with ReferenceLoopHandling.Ignore

    - by keyr
    I have a legacy application that used binary serialisation to persist the data. Now we wanted to use Json.net 4.5 to serialise the data without much changes to the existing classes. Things were working nice till we hit a circular dependent class. Is there any workaround to solve this problem? Sample code as shown below [Serializable] class Department : ISerializable { public Employee Manager { get; set; } public string Name { get; set; } public Department() { } public Department( SerializationInfo info, StreamingContext context ) { Manager = ( Employee )info.GetValue( "Manager", typeof( Employee ) ); Name = ( string )info.GetValue( "Name", typeof( string ) ); } public void GetObjectData( SerializationInfo info, StreamingContext context ) { info.AddValue( "Manager", Manager ); info.AddValue( "Name", Name ); } } [Serializable] class Employee : ISerializable { [NonSerialized] //This does not work [XmlIgnore]//This does not work private Department mDepartment; public Department Department { get { return mDepartment; } set { mDepartment = value; } } public string Name { get; set; } public Employee() { } public Employee( SerializationInfo info, StreamingContext context ) { Department = ( Department )info.GetValue( "Department", typeof( Department ) ); Name = ( string )info.GetValue( "Name", typeof( string ) ); } public void GetObjectData( SerializationInfo info, StreamingContext context ) { info.AddValue( "Department", Department ); info.AddValue( "Name", Name ); } } And the test code Department department = new Department(); department.Name = "Dept1"; Employee emp1 = new Employee { Name = "Emp1", Department = department }; department.Manager = emp1; Employee emp2 = new Employee() { Name = "Emp2", Department = department }; IList<Employee> employees = new List<Employee>(); employees.Add( emp1 ); employees.Add( emp2 ); var memoryStream = new MemoryStream(); var formatter = new BinaryFormatter(); formatter.Serialize( memoryStream, employees ); memoryStream.Seek( 0, SeekOrigin.Begin ); IList<Employee> deserialisedEmployees = formatter.Deserialize( memoryStream ) as IList<Employee>; //Works nicely JsonSerializerSettings jsonSS= new JsonSerializerSettings(); jsonSS.TypeNameHandling = TypeNameHandling.Objects; jsonSS.TypeNameAssemblyFormat = FormatterAssemblyStyle.Full; jsonSS.Formatting = Formatting.Indented; jsonSS.ReferenceLoopHandling = ReferenceLoopHandling.Ignore; //This is not working!! //jsonSS.ReferenceLoopHandling = ReferenceLoopHandling.Serialize; //This is also not working!! jsonSS.PreserveReferencesHandling = PreserveReferencesHandling.All; string jsonAll = JsonConvert.SerializeObject( employees, jsonSS ); //Throws stackoverflow exception Edit1: The issue has been reported to Json (http://json.codeplex.com/workitem/23668)

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  • DataContractSerializer and XSLT not Serializing Class Properties

    - by Russ Clark
    I've written a simple Employee class that I'm trying to serialize to an XDocument and then use XSLT to transform the document to a page that displays both the properties (Name and ID) from the Employee class, and an html form with 2 radio buttons (Approve and Reject) and a submit button. Here is the Employee class: [Serializable, DataContract(Namespace="XSLT_MVC.Controllers/")] public class Employee { [DataMember] public string Name { get; set; } [DataMember] public int ID { get; set; } public Employee() { } public Employee(string name, int id) { Name = name; ID = id; } public XDocument GetDoc() { XDocument doc = new XDocument(); var serializer = new DataContractSerializer(typeof(Employee)); using (var writer = doc.CreateWriter()) { serializer.WriteObject(writer, this); writer.Close(); } return doc; } } And here is the XSLT file: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <html> <body> <xsl:value-of select="Employee/Name"/> <br /> <xsl:value-of select="Employee/ID"/> <br /> <form method="post" action="/Home/ProcessRequest?id={Employee/ID}"> <input id="Action" name="Action" type="radio" value="Approved"></input> Approved <br /> <input id="Action" name="Action" type="radio" value="Rejected"></input> Rejected <br /> <input type="submit" value="Submit"></input> </form> </body> </html> </xsl:template> </xsl:stylesheet> When I run this, all I get is the html form with the 2 radio buttons and the submit button, but not the properties from the Employee class. I saw a separate StackOverflow post that said I need to change the <xsl:template match="/"> to match on the namespace of my Employee class like this: <xsl:template match="/XSLT_MVC.Controllers"> but when I do that, now all I get are the Employee properties, and not the html form with the 2 radio buttons and the submit button. Does anyone know what needs to be done so that my transform will select and display both the Employee properties and the html form?

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  • How to use second level cache for lazy loaded collections in Hibernate?

    - by Chandru
    Let's say I have two entities, Employee and Skill. Every employee has a set of skills. Now when I load the skills lazily through the Employee instances the cache is not used for skills in different instances of Employee. Let's Consider the following data set. Employee - 1 : Java, PHP Employee - 2 : Java, PHP When I load Employee - 2 after Employee - 1, I do not want hibernate to hit the database to get the skills and instead use the Skill instances already available in cache. Is this possible? If so how? Hibernate Configuration <session-factory> <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property> <property name="hibernate.connection.password">pass</property> <property name="hibernate.connection.url">jdbc:mysql://localhost/cache</property> <property name="hibernate.connection.username">root</property> <property name="hibernate.dialect">org.hibernate.dialect.MySQLInnoDBDialect</property> <property name="hibernate.cache.use_second_level_cache">true</property> <property name="hibernate.cache.use_query_cache">true</property> <property name="hibernate.cache.provider_class">net.sf.ehcache.hibernate.EhCacheProvider</property> <property name="hibernate.hbm2ddl.auto">update</property> <property name="hibernate.show_sql">true</property> <mapping class="org.cache.models.Employee" /> <mapping class="org.cache.models.Skill" /> </session-factory> The Entities with imports, getters and setters Removed @Entity @Table(name = "employee") @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public class Employee { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; public Employee() { } @ManyToMany @JoinTable(name = "employee_skills", joinColumns = @JoinColumn(name = "employee_id"), inverseJoinColumns = @JoinColumn(name = "skill_id")) @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) private List<Skill> skills; } @Entity @Table(name = "skill") @Cache(usage = CacheConcurrencyStrategy.READ_WRITE) public class Skill { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String name; } SQL for Loading the Second Employee and his Skills Hibernate: select employee0_.id as id0_0_, employee0_.name as name0_0_ from employee employee0_ where employee0_.id=? Hibernate: select skills0_.employee_id as employee1_1_, skills0_.skill_id as skill2_1_, skill1_.id as id1_0_, skill1_.name as name1_0_ from employee_skills skills0_ left outer join skill skill1_ on skills0_.skill_id=skill1_.id where skills0_.employee_id=? In that I specifically want to avoid the second query as the first one is unavoidable anyway.

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  • Normalization of database for timesheet tool and ensure data integrity

    - by fireeyedboy
    I'm creating a timesheet application. I have the following entities (amongst others): Company Employee = an employee associated with a company Client = a client associated with a company So far I have the following (abbreviated) database setup: Company - id - name Employee - id - companyId (FK to Company.id) - name Client - id - companyId (FK to Company.id) - name Now, I want an employee to be associated with a client, but only if that client is associated with the company the employee works for. How would you guarantee this data integrity on a database level? Or should I just depend on the application to guarantee this data integrity? I thought about creating a many to many table like this: EmployeeClient - employeeId (FK to Employee.id) - companyId \ (combined FK to Client.companyId, Client.id) - clientId / Thus, when I insert a client for an employee along with the employee's company id, the database should prevent this when the client is not associated with the employee's company id. Does this make sense? Because this still doesn't guarantee the employee is associated with the company. How do you deal with these things? UPDATE The scenario is as followed: A company has multiple employees. Employees will only be linked to one company. A company has multiple clients also. Clients will only be linked to one company. (Company is a sandbox, so to speak). An employee of a company can be linked to a client of it's company, but only if the client is part of the company's clientele. In other words: The application will allow a company to create/add employees and create/add clients (hence the companyId FK in the Employee and Client tables). Next, the company will be allowed to assign certain clients to certain of it's employees (EmployeeClient table). Imagine an employee working on projects for a few clients for which s/he can write billable hours, but the employee must not be allowed to write billable hours for clients they are not assigned to by their employer (the company). So, employees will not automatically have access to all their company's clients, but only to those that the company has selected for them. Hopefully this has shed some more light on the matter.

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  • DataContractSerializer and XSLT

    - by Russ Clark
    I've got a simple Employee class that I'm trying to serialize to an XDocument and then use XSLT to transform the document to a page that displays both the properties (Name and ID) from the Employee class, and an html form with 2 radio buttons (Approve and Reject) and a submit button. Here is the Employee class: [Serializable, DataContract(Namespace="XSLT_MVC.Controllers/")] public class Employee { [DataMember] public string Name { get; set; } [DataMember] public int ID { get; set; } public Employee() { } public Employee(string name, int id) { Name = name; ID = id; } public XDocument GetDoc() { XDocument doc = new XDocument(); var serializer = new DataContractSerializer(typeof(Employee)); using (var writer = doc.CreateWriter()) { serializer.WriteObject(writer, this); writer.Close(); } return doc; } } And here is the XSLT file: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <html> <body> <xsl:value-of select="Employee/Name"/> <br /> <xsl:value-of select="Employee/ID"/> <br /> <form method="post" action="/Home/ProcessRequest?id={Employee/ID}"> <input id="Action" name="Action" type="radio" value="Approved"></input> Approved <br /> <input id="Action" name="Action" type="radio" value="Rejected"></input> Rejected <br /> <input type="submit" value="Submit"></input> </form> </body> </html> </xsl:template> </xsl:stylesheet> When I run this, all I get is the html form with the 2 radio buttons and the submit button, but not the properties from the Employee class. I saw a separate StackOverflow post that said I need to change the <xsl:template match="/"> to match on the namespace of my Employee class like this: <xsl:template match="/XSLT_MVC.Controllers">, but when I do that, now all I get are the Employee properties, and not the html form with the 2 radio buttons and the submit button. Does anyone know what needs to be done so that my transform will select and display both the Employee properties and the html form?

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  • Inaccessible item using C++ inheritance

    - by shinjuo
    I am working on C++ project that uses inheritance. I seem to have an error in visual studio in the below file administrator.h. It says that salariedemploye:salary on line 17 is inaccessible and I am not sure why. Admin.cpp #include namespace SavitchEmployees { Administrator::Administrator( ):SalariedEmployee(), salary(0) { //deliberately empty } Administrator::Administrator(const string& theName, const string& theSsn, double theAnnualSalary) :SalariedEmployee(theName, theSsn),salary(theAnnualSalary) { //deliberately empty } void Administrator::inputAdminData() { cout << " Enter the details of the administrator " << getName() << endl; cout << " Enter the admin title" << endl; getline(cin, adminTitle); cout << " Enter the area of responsibility " << endl; getline(cin, workingArea); cout << " Enter the immediate supervisor's name " << endl; getline(cin, supervisorName); } void Administrator::outputAdminData() { cout << "Name: " << getName() << endl; cout << "Title: " << adminTitle << endl; cout << "Area of responsibility: " << workingArea << endl; cout << "Immediate supervisor: " << supervisorName << endl; } void Administrator::printCheck() { setNetPay(salary); cout << "\n___________________________________\n" << "Pay to the order of " << getName() << endl << "The sum of" << getNetPay() << "Dollars\n" << "______________________________________\n" << "Check Stub Not negotiable \n" << "Employee Number: " << getSsn() << endl << "Salaried Employee(Administrator). Regular Pay: " << salary << endl << "______________________________________\n"; } } admin.h #include <iostream> #include "salariedemployee.h" using std::endl; using std::string; namespace SavitchEmployees { class Administrator : public SalariedEmployee { public: Administrator(); Administrator(const string& theName, const string& theSsn, double salary); double getSalary() const; void inputAdminData(); void outputAdminData(); void printCheck(); private: string adminTitle;//administrator's title string workingArea;//area of responsibility string supervisorName;//immediate supervisor }; } #endif SalariedEmployee.cpp namespace SavitchEmployees { SalariedEmployee::SalariedEmployee():Employee(),salary(0) { //deliberately empty } SalariedEmployee::SalariedEmployee(const string& theName, const string& theNumber, double theWeeklyPay) :Employee(theName, theNumber), salary(theWeeklyPay) { //deliberately empty } double SalariedEmployee::getSalary() const { return salary; } void SalariedEmployee::setSalary(double newSalary) { salary = newSalary; } void SalariedEmployee::printCheck() { setNetPay(salary); cout << "\n___________________________________\n" << "Pay to the order of " << getName() << endl << "The sum of" << getNetPay() << "Dollars\n" << "______________________________________\n" << "Check Stub NOT NEGOTIABLE \n" << "Employee Number: " << getSsn() << endl << "Salaried Employee. Regular Pay: " << salary << endl << "______________________________________\n"; } } Salariedemplyee.h #ifndef SALARIEDEMPLOYEE_H #define SALARIEDEMPLOYEE_H #include <string> #include "employee.h" namespace SavitchEmployees{ class SalariedEmployee : public Employee{ public: SalariedEmployee(); SalariedEmployee(const string& theName, const string& theSsn, double theWeeklySalary); double getSalary() const; void setSalary(double newSalary); void printCheck(); private: double salary; }; } #endif employee.cpp namespace SavitchEmployees { Employee::Employee():name("No name yet"),ssn("No number yet"),netPay(0){} Employee::Employee(const string& theName, const string& theSsn):name(theName),ssn(theSsn),netPay(0){} string Employee::getName() const { return name; } string Employee::getSsn() const { return ssn; } double Employee::getNetPay() const { return netPay; } void Employee::setName(const string& newName) { name = newName; } void Employee::setSsn(const string& newSsn) { ssn = newSsn; } void Employee::setNetPay(double newNetPay) { netPay = newNetPay; } void Employee::printCheck() const { cout << "\nERROR: pringCheck function called for an \n" << "Undifferentiated employee. Aborting the program!\n" << "Check with the author of this program about thos bug. \n"; exit(1); } }

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  • [LINQ] Master&ndash;Detail Same Record (I)

    - by JTorrecilla
    PROBLEM Firstly, I am working on a project based on LINQ, EF, and C# with VS2010. The following Table shows what I have and what I want to show. Header C1 C2 C3 1 P1 01/01/2011 2 P2 01/02/2011 Details 1 1 D1 2 1 D2 3 1 D3 4 2 D1 5 2 D4 Expected Results 1 P1 01/01/2011 D1, D2, D3 2 P2 01/02/2011 D1,D4   IDEAS At the begin I got 3 possible ways: - Doing inside the DB:  It could be achieved from DB with a CURSOR in a Stored Procedure. - Doing from .NET with LOOPS. - Doing with LINQ (I love it!!) FIRST APROX Example with a simple CLASS with a LIST: With and Employee Class that acts as Header Table: 1: public class Employee 2: { 3: public Employee () { } 4: public Int32 ID { get; set; } 5: public String FirstName{ get; set; } 6: public String LastName{ get; set; } 7: public List<string> Numbers{ get; set; } // Acts as Details Table 8: } We can show all numbers contained by Employee: 1: List<Employee > listado = new List<Employee >(); 2: //Fill Listado 3: var query= from Employee em in listado 4: let Nums= string.Join(";", em.Numbers) 5: select new { 6: em.Name, 7: Nums 8: }; The “LET” operator allows us to host the results of “Join” of the Numbers List of the Employee Class. A little example. ASAP I will post the second part to achieve the same with Entity Framework. Best Regards

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  • Who owns the IP rights of the software without written employment contract? Employer or employee? [closed]

    - by P T
    I am a software engineer who got an idea, and developed alone an integrated ERP software solution over the past 2 years. I got the idea and coded much of the software in my personal time, utilizing my own resources, but also as intern/employee at small wholesale retailer (company A). I had a verbal agreement with the company that I could keep the IP rights to the code and the company would have the "shop rights" to use "a copy" of the software without restrictions. Part of this agreement was that I was heavily underpaid to keep the rights. Recently things started to take a down turn in the company A as the company grew fairly large and new head management was formed, also new partners were brought in. The original owners distanced themselves from the business, and the new "greedy" group indicated that they want to claim the IP rights to my software, offering me a contract that would split the IP ownership into 50% co-ownership, completely disregarding the initial verbal agreements. As of now there was no single written job description and agreement/contract/policy that I signed with the company A, I signed only I-9 and W-4 forms. I now have an opportunity to leave the company A and form a new business with 2 partners (Company B), obviously using the software as the primary tool. There would be no direct conflict of interest as the company A sells wholesale goods. My core question is: "Who owns the code without contract? Me or the company A? (in FL, US)" Detailed questions: I am familiar with the "shop rights", I don't have any problem leaving a copy of the code in the company for them to use/enhance to run their wholesale business. What worries me, Can the company A make any legal claims to the software/code/IP and potential derived profits/interests after I leave and form a company B? Can applying for a copyright of the code at http://www.copyright.gov in my name prevent any legal disputes in the future? Can I use it as evidence for legal defense? Could adding a note specifying the company A as exclusive license holder clarify the arrangements? If I leave and the company A sues me, what evidence would they use against me? On what basis would the sue since their business is in completely different industry than software (wholesale goods). Every single source file was created/stored on my personal computer with proper documentation including a copyright notice with my credentials (name/email/addres/phone). It's also worth noting that I develop significant part of the software prior to my involvement with the company A as student. If I am forced to sign a contract and the company A doesn't honor the verbal agreement, making claims towards the ownership, what can I do settle the matter legally? I like to avoid legal process altogether as my budget for court battles is extremely limited at the moment. Would altering the code beyond recognition and using it for the company B prevent the company A make any copyright claims? My common sense tells me that what I developed is by default mine in terms of IP, unless there is a signed legal agreement stating otherwise. But looking online it may be completely backwards, this really worries me. I understand that this is not legal advice, and I know to get the ultimate answer I need to hire a lawyer. I am only hoping to get some valuable input/experience/advice/opinion from those who were in similar situation or are familiar with the topic. Thank you, PT

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  • linq to sql update data

    - by pranay
    can i update my employee record as given in below function or i have to make query of employee collection first and than i update data public int updateEmployee(App3_EMPLOYEE employee) { DBContextDataContext db = new DBContextDataContext(); db.App3_EMPLOYEEs.Attach(employee); db.SubmitChanges(); return employee.PKEY; } or i have to do this public int updateEmployee(App3_EMPLOYEE employee) { DBContextDataContext db = new DBContextDataContext(); App3_EMPLOYEE emp = db.App3_EMPLOYEEs.Single(e => e.PKEY == employee.PKEY); db.App3_EMPLOYEEs.Attach(employee,emp); db.SubmitChanges(); return employee.PKEY; } But i dont want to use second option is there any efficient way to update data

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  • Build comma seperated string from the struct in C#

    - by acadia
    Hello, I have the following struct in C# class public struct Employee { public const string EMPID = "EMP_ID"; public const string FName = "FIRST_NAME"; public const string LNAME = "LAST_NAME"; public const string DEPTID = "DEPT_ID"; } Is there an easy way to build a string as follows const string mainquery="INSERT INTO EMP(EMP_ID,FIRST_NAME,LAST_NAME,DEPT_ID) VALUES(:EMP_ID,:FIRST_NAME,:LAST_NAME,:DEPT_ID)" Instead of doing as follows and then concatenating it. const string EMP_COLS= EMPLOYEE.EMPID + "," + EMPLOYEE.FNAME + "," + EMPLOYEE.LNAME + "," + EMPLOYEE.DEPTID; const string EMP_Values= EMPLOYEE.EMPID + ":" + EMPLOYEE.FNAME + ":" + EMPLOYEE.LNAME + ":" + EMPLOYEE.DEPTID;

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  • Most efficient way to Update with Linq2Sql

    - by pranay
    can I update my employee record as given in below function or i have to make query of employee collection first and than i update data public int updateEmployee(App3_EMPLOYEE employee) { DBContextDataContext db = new DBContextDataContext(); db.App3_EMPLOYEEs.Attach(employee); db.SubmitChanges(); return employee.PKEY; } or i have to do this public int updateEmployee(App3_EMPLOYEE employee) { DBContextDataContext db = new DBContextDataContext(); App3_EMPLOYEE emp = db.App3_EMPLOYEEs.Single(e => e.PKEY == employee.PKEY); db.App3_EMPLOYEEs.Attach(employee,emp); db.SubmitChanges(); return employee.PKEY; } But i dont want to use second option is there any efficient way to update data

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  • Extract 2 numbers preceded with two different strings in a paragrapf using TCL Regular Expression

    - by Madhu
    Hi, I need to extract two different numbers preceded by two different strings. Employee Id-- Employee16(I need 16) and Employee links-- Employee links:2 (I need 2). Source String looks like following: Employee16, Employee name is QueenRose Working for 46w0d Billing is Distributed 65537 assigned tasks, 0 reordered, 0 unassigned 0 discarded, 0 lost received, 5/255 load received sequence unavailable, 0xC2E7 sent sequence Employee links: 2 active, 0 inactive (max not set, min not set) Dt3/5/10:0, since 46w0d, no tasks pending Dt3/5/10:10, since 21w0d, no tasks rcvd Employee is currently working in Hardware section. Employee19, Employee name is Edward11 Working for 48w4d Billing is Distributed 206801498 assigned tasks, 0 reordered, 0 unassigned 655372 discarded, 0 lost received, 9/255 load received sequence unavailable, 0x23CA sent sequence Employee links: 7 active, 0 inactive (max not set, min not set) Dt3/5/10:0, since 47w2d, tasks pending Dt3/5/10:10, since 28w6d, no tasks pending Dt3/5/10:11, since 18w4d, no tasks pending Dt3/5/10:12, since 18w4d, no tasks pending Dt3/5/10:13, since 18w4d, no tasks pending Dt3/5/10:14, since 18w4d, no tasks pending Dt3/5/10:15, since 7w2d, no tasks pending Employee is currently working in Hardware sectione. Employee6 (inactive) Employee links: 2 Dt3/5/10:0 (inactive) Dt3/5/10:10 (inactive) Employee7 (inactive) Employee links: 2 Dt3/5/10:0 (inactive) Dt3/5/10:10 (inactive) Tried with the following: Multilink(\d+)[^\n\r]*[^M]*Member links:\s+(\d+) But is not listing all the Ids and links. Can anybody help me getting this? Thanks in advance, Madhu.

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  • Entity Framework: Auto-updating foreign key when setting a new object reference

    - by Adrian Grigore
    Hi, I am porting an existing application from Linq to SQL to Entity Framework 4 (default code generation). One difference I noticed between the two is that a foreign key property are not updated when resetting the object reference. Now I need to decide how to deal with this. For example supposing you have two entity types, Company and Employee. One Company has many Employees. In Linq To SQL, setting the company also sets the company id: var company=new Company(ID=1); var employee=new Employee(); Debug.Assert(employee.CompanyID==0); employee.Company=company; Debug.Assert(employee.CompanyID==1); //Works fine! In Entity Framework (and without using any code template customization) this does not work: var company=new Company(ID=1); var employee=new Employee(); Debug.Assert(employee.CompanyID==0); employee.Company=company; Debug.Assert(employee.CompanyID==1); //Throws, since CompanyID was not updated! How can I make EF behave the same way as LinqToSQL? I had a look at the default code generation T4 template, but I could not figure out how to make the necessary changes.

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