Search Results

Search found 386 results on 16 pages for 'fileupload'.

Page 8/16 | < Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >

  • How to store private pictures and videos in Ruby on Rails

    - by TK
    Here's a story: User A should be able to upload an image. User A should be able to set a privacy. ("Public" or "Private"). User B should not be able to access "Private" images of User A. I'm planning to user Paperclip for dealing with uploads. If I store the images under "RAILS_ROOT/public/images", anyone who could guess the name of the files might access the files. (e.g., accessing http://example.com/public/images/uploads/john/family.png ) I need to show the images using img tags, so I cannot place a file except public. How can I ensure that images of a user or group is not accessible by others?

    Read the article

  • Determine how many bytes of a request have been read/received?

    - by vdhant
    Hey guys Just wondering if anyone has any idea how you can determine how many bytes of a request have been read/received by the server... In other words how do I stream http request... In that, users are uploading files and I want to report on a perotic basis how many bytes have been read/received so far. Just wondering if anyone has any ideas on how I might do this... Cheers Anthony

    Read the article

  • where from does paperclip get the name of original file?

    - by Pavel K.
    i started using nginx upload module (which creates upload files like /tmp/000121545) but i need paperclip to use original filename while saving files (like /public/avatars/LuckyLuke.jpg) previously in the parameters Rails were passing just "avatar"=>#<File:/tmp/RackMultipart20100413-6151-t3ecq0-0> no original filename as well, so i am wondering where from does it come in paperclip? i tried looking through plugin code but it's currently a bit too complex for me.

    Read the article

  • File upload using HTML file type.

    - by vaibhav
    I want to upload a file on my aspx page. I am using <form id="frmId" method="post" enctype="Multipart/form-data"> <input type="file" id="file1"/> <input type="submit" id="btnsubmit"/> </form> and in code behind I am trying to get this file. Its not letting me to get the file until I use server side input file control. I don't want to use runat="server" attribute with my file control. Do anyone know how to do this.

    Read the article

  • How to upload a directory via Grails or Java ?

    - by fabien-barbier
    What is the best way to upload a directory in grails ? I try this code : def upload = { if(request.method == 'POST') { Iterator itr = request.getFileNames(); while(itr.hasNext()) { MultipartFile file = request.getFile(itr.next()); File destination = new File(file.getOriginalFilename()) if (!file.isEmpty()) { file.transferTo(destination) // success } else { // failure } } response.sendError(200,'Done'); } } Unfortunately, I can only upload file by file. I would like to define my directory, and upload all files directly. Any ideas ?

    Read the article

  • Upload file and parse in classic asp

    - by Allen
    Any ideas how this can be done thru pure asp? I have various upload scripts, but they all either save a file to a folder or in a database. I can't seem to modify these examples correctly to put the file in an array. Here's the 2 I'm currently using: http://www.asp101.com/articles/jacob/scriptupload.asp|http://www.pscode.com/vb/scripts/ShowCode.asp?txtCodeId=7361&lngWId=4

    Read the article

  • Agile Uploader error code 2101?

    - by adamwstl
    I'm trying to install Agile Uploader, but keep running into an error code 2101 (no other message besides that.) Any idea what error code "2101" means? Whenever I try to submit/upload (when I call agileUploaderSubmit()), nothing seems to happen and with Firebug mode on, all the log prints out is that code. I can't find anything that tells me what it means. Thanks

    Read the article

  • Curl (*nix) upload file to ASP.NET

    - by WedTM
    I have an old redhat 8 box that I need to pragmatically send files to my webserver from. Disregarding the security issues with this, I've come up with the following way. curl -F file=@<filename> http://webhost/reciever.aspx The problem is, no matter what I try, the ASP.NET page is not accepting the file. What am I doing wrong?

    Read the article

  • JSP Upload File Java.lang.NullPointer

    - by newbie123
    I want to develope upload and download file from server. Upload.html <form action="/UploadFile/UploadFile" method="POST" enctype="multipart/form-data">Select a file: <input type="submit" name="button" /> <input type="file" name="first"></form> UploadFile.servlet protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String temp = request.getParameter("first"); System.out.println(temp); File origFile = new File(temp); FileOutputStream out = new FileOutputStream(request.getContextPath() + "pdtImages/" + "FirstFile"); InputStream ins = new FileInputStream(origFile); try { System.out.println(request.getContextPath()); byte[] buf = new byte[1024]; int len; while ((len = ins.read(buf)) > 0) { out.write(buf, 0, len); } out.close(); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } When I submitted the file I got null pointer error message. I not very familiar with jsp can anybody help me? I want to store the file to the server directory.

    Read the article

  • How do I upload a file from a Java servlet to a location on a web server within Tomcat/webapps

    - by Ankur
    How do I upload a file from a Java servlet to a location on a web server within Tomcat/webapps. I am using Commons upload. I have a location such as myserver:8080/myapp/mylocation where I want to put the files that are uploaded. I tried using getServletContext().getRealPath("/"); to find where I am and then appended that with mylocation but I get a nullpointer exception. I know I sound vague, it's because I am confused about the big picture, what are the generals steps I need to perform to make this work. Any code or links to code would be much appreciated.

    Read the article

  • PHP file upload issue

    - by Varun
    I am working on a PHP based, ticket management system. While creating a ticket, one can upload an attachment. I want to put a limit (say 10 MB) per file upload. To implement this I plan the following- 1. In php.ini set post_max_size = 10M 2.In PHP script which receives the POST- Since the file is larger than post_max_size, $_FILES[] will be empty. But I can still check the content-length header and discard the upload, if size more than 10M. While testing this I tried uploading a file of 1 GB and analysed the http traffic and this is what I found. - the entire 1 GB data is first uploaded to a to the server temporarily and discarded once the http request completes. Though I couldn't exactly find out where the file was getting saved(as it was not there in the temporary directory in the server.), but my http traffic analyzer showed that the browser did send 1 GB data to the server. - the PHP script execution started only after completion of the http request(i.e after uploading the entire 1 GB) Now I have 2 concerns: a) People may exploit my server bandwidth by trying to upload large file, which I will have to discard anyways. b) Even worse, if someone starts uploading a huge file (say 100 GB), entire 100 GB data is first uploaded to the server temporarily, that means for that period, it will consume that much of memory on my server. What's the common solution for this. Am I missing something here?

    Read the article

  • Python timed file upload

    - by Ali
    I have a python script that accepts a file from the user and saves it. Is it possible to not upload the file immediately but to que it up and when the server has less load to upload it then. Can this be done by transferring the file to the browsers storage area or taking the file from the Harddrive and transferring to the User's RAM?

    Read the article

  • question on regular servlets within GWT (working in dev mode ,not working in deployment in tomcat)

    - by molleman
    Hello guys, i am having trouble with my web application developed in GWT. the application allows users to upload and download using an upload servlet and a download servlet, the upload servlet was created using the gwtUpload library. the download servlet is using regular HTTPServlet. when i run the application within eclipse the download servlet works fine, when i deploy it to tomcat, when a user selects to upload a file, the file does not download, when a user selects a link to download a file, this error is returned type Status report message /testhibernategilead/downloadServlet description The requested resource (/testhibernategilead/downloadServlet) is not available. can anyone explain why this is

    Read the article

  • Using delayed_job to process file uploads across multiple servers

    - by Steve Klabnik
    Does anyone have any good resources on how to do this? Basically, I'm working on a project (in Rails) where people can upload files. They might be big. I'd like to process them using delayed_job before sending them to S3. I'd also like to do this processing on a separate job queue server, rather than on the webserver itself. I'd rather not have to upload the files to the webserver, then transfer them to the job queue server, and then upload them to S3 if I don't have to. Thanks.

    Read the article

  • ASP.Net/C# File Upload Progress Display

    - by Ioxp
    I am having a hard time figuring out how to do a "Please wait while file is uploading" message when the user submits the following form. So far the application works to specification with regards to checking files and uploading to the server. You will see some java script below, this is there to allow me to fake out the style of the file up load buttons so that it matches the rest of the site. I have tried to use the ASP.Net Ajax controls to do this however the updateprogress panel would not show up. In further reading it was explained that this has something to do with the Asynchronous transfer that the file upload control uses when you issue a PostedFile.SaveAs("filename") command. I also found a site that refereed to using an iframe to do the job. I'm not really sure if that's the best way to go about doing this or not so I'm asking you the professionals of stackoverflow for help to try and resolve this issue. I will be more than happy to post any spinets you need from my code to help me expedite a solution for this. <table border="0"> <tr> <td>File 1:&nbsp;</td> <td><div class="fileinputs"><input type="file" class="file" size="37" id="f1" runat="server" /></div></td> </tr> <tr> <td>File 2:&nbsp;</td> <td><div class="fileinputs"><input type="file" class="file" size="37" id="f2" runat="server" /></div></td> </tr> <tr> <td colspan="2" style="text-align:right;"><asp:ImageButton ID="ImageButton1" runat="server" ImageUrl="~/Images/Buttons/Upload_Files.gif" OnClick="Submit_Form" /></td> </tr> </table> <asp:Label ID="lblError" runat="server" Text=""></asp:Label> <script type="text/javascript"> var fakeFileUpload = document.createElement('div'); fakeFileUpload.className = 'fakefile'; var fakeInput = document.createElement('input'); fakeInput.style.width = '200px'; fakeFileUpload.appendChild(fakeInput); var image = document.createElement('img'); image.src='../Images/Buttons/Browse.gif'; fakeFileUpload.appendChild(image); var x = document.getElementsByTagName('input'); for (var i=0;i<x.length;i++) { if (x[i].type != 'file') continue; if (x[i].parentNode.className != 'fileinputs') continue; x[i].className = 'file hidden'; var clone = fakeFileUpload.cloneNode(true); x[i].parentNode.appendChild(clone); x[i].relatedElement = clone.getElementsByTagName('input')[0]; x[i].onchange = x[i].onmouseout = function () { this.relatedElement.value = this.value; } } </script>

    Read the article

  • Checking contents of Uploaded file

    - by kapil
    Hi all, I am using ASP.NEt MVC . I want to upload .zip files for which I am using html input file upload control on my view. I want only .zip files to be uploaded. I want to check that my .zip contains only two files - both having extensions .txt and one of them having name "start". Can anyone please suggest me about how to check this? How can we assure that the uploaded .zip is really a zipped folder and not any other file having just .zip extension. can we use HttpPostedFileBase.ContentType? thanks in advance, kaps

    Read the article

  • Automatic upload of 10KB file to web service?

    - by Joseph Turian
    I am writing an application, similar to Seti@Home, that allows users to run processing on their home machine, and then upload the result to the central server. However, the final result is maybe a 10K binary file. (Processing to achieve this output is several hours.) What is the simplest reliable automatic method to upload this file to the central server? What do I need to do server-side to prevent blocking? Perhaps having the client send mail is simple and reliable? NB the client program is currently written in Python, if that matters.

    Read the article

  • Flex 3 multiple upload progress monitoring

    - by Darko Z
    I have a Flex3 application which has to be capable of uploading multiple files and monitoring each files individual progress using a label NOT a progress bar. My problem is that a generic progress handler for the uploads has no way (that I know of) of indicating WHICH upload it is that is progressing. I know that a file name is available to check but in the case of this app the file name might be the same for multiple uploads. My question: With a generic progress handler how does one differentiate between 2 multiple uploads with the same file name? EDIT: answerers may assume that I am a total newb to Flex... because I am.

    Read the article

  • mysql: can't set max_allowed_package to anything grater than 16MB

    - by sas
    I'm not sure if this is the right place to post these kind of questions, if it's not so, please (politely) let me know... :-) I need to save files greater than 16MB on a mysql database from a php site... I've already changed the c:\xampp\mysql\bin\my.cnf and set max_allowed_packet to 16 MB, and everything worked fine then I set it to 32 MB but there´s no way I can handle a file bigger than 16 MB I get the following error: 'MySQL server has gone away' (the same error I had when max_allowed_packet was set to 1MB) there must be some other setting that doesn´t allow me to handle files bigger than 16MB maybe the php client, I guess, but I don't know where to edit it this is the code I'm running when file.txt is smaller than 16.776.192 bytes long, it works fine, but if file.txt has 16.777.216 bytes i get the aforementioned error oh, and the field download.content is a longblob... $file = 'file.txt'; $file_handle = fopen( $file, 'r' ); $content = fread( $file_handle, filesize( $file ) ); fclose( $file_handle ); db_execute( 'truncate table download', true ); $sql = "insert into download( code, title, name, description, original_name, mime_type, size, content, user_insert_id, date_insert, user_update_id, date_update ) values ( 'new file', 'new file', 'sas.jpg', 'new file', '$file', 'mime', " . filesize( $file ) . ", '" . addslashes( $content ) . "', 0, " . db_char_to_sql( now_char(), 'datetime' ) . ", 0, " . db_char_to_sql( now_char(), 'datetime' ) . " )"; db_execute( $sql, true ); (the db_execute funcion just opens the connections and executes the sql stuff) running on windows XP sp2 server version: 5.0.67-community PHP Version 4.4.9 mysql client API version: 3.23.49 using: ApacheFriends XAMPP (Basispaket) version 1.6.8 that comes with + Apache 2.2.9 + MySQL 5.0.67 (Community Server) + PHP 5.2.6 + PHP 4.4.9 + PEAR + phpMyAdmin 2.11.9.2 ... this is part of the content of c:\xampp\mysql\bin\my.cnf # The MySQL server [mysqld] port= 3306 socket= "C:/xampp/mysql/mysql.sock" basedir="C:/xampp/mysql" tmpdir="C:/xampp/tmp" datadir="C:/xampp/mysql/data" skip-locking key_buffer = 16M # max_allowed_packet = 1M max_allowed_packet = 32M table_cache = 128 sort_buffer_size = 512K net_buffer_length = 8K read_buffer_size = 256K read_rnd_buffer_size = 512K myisam_sort_buffer_size = 8M

    Read the article

  • Need to get the uploaded file to my local PC

    - by Suhail
    Hi, I have created a test form which will ask users to enter a name and upload the image file: <html lang="en"> <head> <title>Testing image upload</title> </head> <body> <form action="/services/upload" method="POST" enctype="multipart/form-data"> File Description: <input name='fdesc' type='text'><br> File name: <input type="file" name="fname"><br> <div><input type="submit"></div> </form> </body> </html> i need to get the file uploaded by the user and store it on my local PC. can this be done in python ? please let me know.

    Read the article

  • Which location to save uploaded files

    - by chupinette
    hello! I am using php and i have written codes to allow a user upload a file. For testing purposes, i have saved the file to D:/final/temp/test.xls. Then i generate another file and save it to the same location. This file can be downloaded by the user. But if an actual user would be using my application, where should the location point to? Thanks!

    Read the article

< Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >