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  • .NET WF4: Should it be in the middle of everything?

    - by stimpy77
    I am aware that WF4 (Windows Workflow 4.0, part of .NET 4.0) is a significant rework and redesign of WF3, where much of what made WF3 a poor technology choice has been cleaned up in WF4. For example, as far as I can tell, WF4 (Windows Workflow 4.0) activities are more or less testable with [TestMethod] and mocking. This among other things, like improved performance, has grabbed my attention about the technology again, whereas I had previously pooh-poohed WF3. I'm working on a new architecture for essentially an n-tier collaborative application (not enterprise-class, just a smallish project with potential to grow significantly) where I'm already trying to discipline myself to use IoC and, to some extent, TDD, and I'm wondering, in general terms, whether it is wiser to just hand-code workflow logic or if I should delve into learning and integrating WF4 so that WF becomes literally the controller of the entire application, i.e. the practical C in "MVC" (not ASP.NET MVC but rather the pattern). So should workflow activities in WF4 be the primary controller for a highly expandable/growable web-based collaborative application? Or am I asking entirely the wrong question? This is a vague question, I'm sure, so abstract answers are as welcome as specific ones.

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  • How to add rows in middle of a table with jQuery?

    - by understack
    I've a table which has customers names along with the products they purchased with their prices. So there are multiple records for each customer. This table is simple 3 column table : name, product and price. What I wanna do is: Put all records belonging to one customer together (I've done it) and just after these rows add one new extra row which would just show total price of all the products each customer has purchased. This row would have empty cell in name and product column. And would have total in price column.

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  • How do you align text so it is in the middle of a button in Silverlight?

    - by Roy
    Here is the current code I am using: <UserControl xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" x:Class="ButtonPrototype.MainPage" Width="640" Height="480"> <UserControl.Resources> <ControlTemplate x:Key="CellTemplate" TargetType="Button"> <Grid> <Border x:Name="CellBorderBrush" BorderBrush="Black" BorderThickness="1"> <ContentPresenter Content="{TemplateBinding Content}" HorizontalAlignment="Center" VerticalAlignment="Center"/> </Border> </Grid> </ControlTemplate> <Style x:Key="CellStyle" TargetType="Button"> <Setter Property="Template" Value="{StaticResource CellTemplate}"></Setter> <Setter Property="Foreground" Value="Black"></Setter> <Setter Property="FontSize" Value="80"></Setter> <Setter Property="Width" Value="100"></Setter> <Setter Property="Height" Value="100"></Setter> </Style> </UserControl.Resources> <Grid x:Name="LayoutRoot" Background="White"> <Button Content="A" Style="{StaticResource CellStyle}"></Button> </Grid> </UserControl> The Horizontal aligning works but the verticalalignment doesn't do anything. Thanks for your help.

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  • Sort/Enumerate an NSArray from somewhere in the middle?

    - by Kenny Winker
    I have an NSArray, with objects ordered like so: a b c d e f I would like to enumerate through this array in this order: c d e f a b i.e. starting at some point that is not the beginning, but hitting all the items. I imagine this is a matter of sorting first and then enumerating the array, but I'm not sure if that's the best technique... or, frankly, how to sort the array like this. Edit Adding details: These will be relatively small arrays, varying from 3 to 10 objects. No concurrent access. I'd like to permanently alter the sort order of the array each time I do this operation.

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  • Sliding panel in the middle of the page. Z-index given not working

    - by Nehal Rupani
    Hi all, I am implementing sliding panel element but problem is when i slide out other div element is floating down. I guess and tried to give z-index to element which i am sliding but it doesn't seems to work. Let me put code for both div. <div class="vrcontrol"> <div class="slide-out-div"> <a class="handle" href="http://link-for-non-js-users.html">Content</a> <h3>Contact me</h3> <p>Thanks for checking out my jQuery plugin, I hope you find this useful. </p> <p>This can be a form to submit feedback, or contact info</p> </div> This is div which i am sliding in and out and beneath is code of effective div. <div class="askform"> <p class="titletext">Ask an Expert Trade Forum</p> <p class="detailtext">WD-40’s leading source for DIY tips and tricks.</p> <span> <form id="askform" name="askform" action="" method="post"> <span class="left"><input name="input" type="text" class="askinputbox"/></span><span class="marginleft"><input type="image" src="images/search_icon.gif" /></span> </form> </span> <div class="followus"> <span class="followtext">Follow us on</span><span class="right"><img src="images/bookmark.jpg" width="121" height="45" alt="Bookmark" /></span> </div> </div> Sliding div is in left portion of the page and effective div is in right portion of the page. I guess something with z-index, positioning element and overflow properties will do something.

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  • Putting $$s in the middle of an `equation` environment: why doesn't Latex complain?

    - by Charles Stewart
    I was surprised that the Latex code from a recent question didn't throw up any errors, and even more surprised on further investigation, that Crowley's explanation seems to be true. My intuition about the \begin{equation} ... \end{equation} code is clearly off, what's really going on? Consider this, slightly adapted code: \begin{equation} 1: e^{i\pi}+1=0 $$ 2: B\"ob $$ 3: e=mc^2 \end{equation} This seems to prove that Crowley's explanation of such code, namely that "What that code says to LaTeX is begin equation, end it, begin it again, typeset definition of tangens and end the equation" is right: lines 1&3 can only be typeset in maths mode, line 2 only in text mode. Shouldn't Latex see that the \end{equation} is ending a display math that wasn't started by the \begin{equation}?

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  • Quality Design for Asynchronous WCF Services Calls in a Middle-Tier and Returning Data to UI Tier

    - by Perplexed
    I have a WPF application with a group of asynchronous WCF service calls all mashed into the code behind, complete with event handlers and everything, that I have to refactor to productionize and maintain. I want to separate concerns here for maintainability and all the other good reasons to do this, but I'm not sure exactly how to achieve this. Anybody have any good ideas on how to do this, or at least some links to put me in the right direction? My thinking: Create an "infrastructure" layer and reference the services there. Move the asynchronous event handlers into this layer. When an update is called, I will bubble up my own event with my own derivation of the EventArgs class that contains the data the UI will need. I'll have a fairly coupled hooking of the UI to the infrastructure layer as it will consume events I fire off upon completion of an asynchronous data call.

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  • Authentication Failed exception - In the middle of bulk mail sending code.

    - by Ezhil
    We have a thread program that sends bulk mail. The information like 1. To 2. Subject Etc., are fetched from database, mail is composed and pushed to SMTP server. One of our customer sent a bulk mail with 2390 email. After sending 40 emails, suddenly the following exception occurred EXCEPTION javax.mail.AuthenticationFailedException STACKTRACE javax.mail.Service.connect(Service.java:306) javax.mail.Service.connect(Service.java:156) javax.mail.Service.connect(Service.java:105) ............... java.lang.Thread.run(Thread.java:619) and the rest 2350 emails failed. Why does this occur? Thanks for the Suggestions and Help Ezhil

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  • Why do I get an extra newline in the middle of a UTF-8 character with XML::Parser?

    - by René Nyffenegger
    I encountered a problem dealing with UTF-8, XML and Perl. The following is the smallest piece of code and data in order to reproduce the problem. Here's an XML file that needs to be parsed: <?xml version="1.0" encoding="utf-8"?> <test> <words>???????????? ??????? ????????? ???? ???????????? ??????</words> <words>???????????? ??????? ????????? ???? ???????????? ??????</words> <words>???????????? ??????? ????????? ???? ???????????? ??????</words> [<words> .... </words> 148 times repeated] <words>???????????? ??????? ????????? ???? ???????????? ??????</words> <words>???????????? ??????? ????????? ???? ???????????? ??????</words> </test> The parsing is done with this perl script: use warnings; use strict; use XML::Parser; use Data::Dump; my $in_words = 0; my $xml_parser=new XML::Parser(Style=>'Stream'); $xml_parser->setHandlers ( Start => \&start_element, End => \&end_element, Char => \&character_data, Default => \&default); open OUT, '>out.txt'; binmode (OUT, ":utf8"); open XML, 'xml_test.xml' or die; $xml_parser->parse(*XML); close XML; close OUT; sub start_element { my($parseinst, $element, %attributes) = @_; if ($element eq 'words') { $in_words = 1; } else { $in_words = 0; } } sub end_element { my($parseinst, $element, %attributes) = @_; if ($element eq 'words') { $in_words = 0; } } sub default { # nothing to see here; } sub character_data { my($parseinst, $data) = @_; if ($in_words) { if ($in_words) { print OUT "$data\n"; } } } When the script is run, it produces the out.txt file. The problem is in this file on line 147. The 22th character (which in utf-8 consists of \xd6 \xb8) is split between the d6 and b8 with a new line. This should not happen. Now, I am interested if someone else has this problem or can reproduce it. And why I am getting this problem. I am running this script on Windows: C:\temp>perl -v This is perl, v5.10.0 built for MSWin32-x86-multi-thread (with 5 registered patches, see perl -V for more detail) Copyright 1987-2007, Larry Wall Binary build 1003 [285500] provided by ActiveState http://www.ActiveState.com Built May 13 2008 16:52:49

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  • How to add an array value to the middle of an associative array?

    - by Citizen
    Lets say I have this array: $array = array('a'=>1,'z'=>2,'d'=>4); Later in the script, I want to add the value 'c'=>3 before 'z'. How can I do this? EDIT: Yes, the order is important. When I run a foreach() through the array, I do NOT want this newly added value added to the end of the array. I am getting this array from a mysql_fetch_assoc() EDIT 2: The keys I used above are placeholders. Using ksort() will not achieve what I want. EDIT 3: http://www.php.net/manual/en/function.array-splice.php#88896 accomplishes what I'm looking for but I'm looking for something simpler. EDIT 4: Thanks for the downvotes. I gave feedback to your answers and you couldn't help, so you downvoted and requested to close the question because you didn't know the answer. Thanks. EDIT 5: Take a sample db table with about 30 columns. I get this data using mysql_fetch_assoc(). In this new array, after column 'pizza' and 'drink', I want to add a new column 'full_dinner' that combines the values of 'pizza' and 'drink' so that when I run a foreach() on the said array, 'full_dinner' comes directly after 'drink'

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  • How can I copy files in the middle of a build in Team System?

    - by Dana
    I have two solutions that I want to include in a build. Solution two requires the dll's from solution one to successfully build. Solution two has a Binaries folder where the dll's from solution one need to be copied before building Solution two. I've been trying an AfterBuild Target, hoping that it would copy the items after the first SolutionToBuild, but it doesn't fire then. I'm guessing that it would probably fire after both solutions have compiled, but that's not what I want. <SolutionToBuild Include="$(BuildProjectFolderPath)/../../Main/Framework.sln"> <Targets>AfterCompileFramework</Targets> <Properties></Properties> </SolutionToBuild> <SolutionToBuild Include="$(BuildProjectFolderPath)/../../../Dashboard/Main/Dashboard.sln"> <Targets></Targets> <Properties></Properties> </SolutionToBuild> <ItemGroup> <FrameworkBinaries Include="$(DropLocation)\$(BuildNumber)\Release\Framework.*.dll"/> </ItemGroup> <Message Text="FrameworkBinaries: @(FrameworkBinaries)" Importance="high"/> <Copy SourceFiles="@(FrameworkBinaries)" DestinationFolder="$(BuildProjectFolderPath)/../../../Dashboard/Main/Binaries"/>

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  • How can I prevent page-break in CFDocument from occuring in middle of content?

    - by Dan Roberts
    I am generating a PDF file dynamically from html/css using the cfdocument tag. There are blocks of content that I don't want to span multiple pages. After some searching I found that the style "page-break-inside" is supported according to the docs. However in my testing the declaration "page-break-inside: avoid" does no good. Any suggestions on getting this style declaration to work, or have alternative suggestions? Here is an example. I would expect the content in the div tag not to span a page break but it does. The style "page-break-inside: avoid" is not being honored. <cfdocument format="flashpaper"> <cfloop from="1" to="10" index="i"> <div style="page-break-inside: avoid"> <h1>Table Label</h1> <table> <tr><td>label</td><td>data</td></tr> <tr><td>label</td><td>data</td></tr> <tr><td>label</td><td>data</td></tr> <tr><td>label</td><td>data</td></tr> <tr><td>label</td><td>data</td></tr> <tr><td>label</td><td>data</td></tr> <tr><td>label</td><td>data</td></tr> <tr><td>label</td><td>data</td></tr> <tr><td>label</td><td>data</td></tr> </table> </div> </cfloop> </cfdocument>

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  • Java: Is there a way to efficiently insert or remove many elements from the middle of a LinkedList?

    - by allyourcode
    I was expecting to find this in Java's LinkedList, since the point of linked lists is to be able to efficiently insert (and remove) anywhere (assuming you have some kind of pointer to the location where you want to insert or remove). I'm not finding anything in the API though. Am I overlooking something? The closest thing I can find to this are the add and remove method in ListIterator. This has some limitations though. In particular, other iterators become invalid as soon as the underlying LinkedList is modified via remove, according to the API. This is born out in my tests as well; the following program results in a IllegalStateException: import java.util.*; public class RemoveFromLinkedList { public static void main(String[] args) { LinkedList<Integer> myList= new LinkedList<Integer>(); for (int i = 0; i < 10; ++i) { myList.add(i); } ListIterator<Integer> i1 = myList.listIterator(); ListIterator<Integer> i2 = myList.listIterator(); for (int i = 0; i < 3; ++i) { i1.next(); i2.next(); } System.out.println("i1.next() should be 3: " + i1.next()); i1.remove(); i1.remove(); // Exception! System.out.println("i2.next() should be 5: " + i2.next()); } } Ideally, what I'm expecting is something like this: // In my imagination only. This is the way Java actually works, afaict. // Construct two insertion/deletion points in LinkedList myLinkedList. myIterator = myLinkedList.iterator(); for (...) { myIterator.next(); } start = myIterator.clone(); for (...) { myIterator.next(); } // Later... after = myLinkedList.spliceAfter(myIterator, someOtherLinkedList); // start, myIterator, and after are still all valid; thus, I can do this: // Removes everything I just spliced in, as well as some other stuff before that. myLinkedList.remove(start, after); // Now, myIterator is invalid, but not start, nor after. C++ has something like this for its list class (template). Only iterators pointing to moved elements become invalidated, not ALL iterators.

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  • Ignoring a xml Tag in the middle of the file in Regex (with non capturing group ?)

    - by schmirrwurst
    I have an xml with an embeded tag, and I would like to capture everthing but the FType Tags... in python regex. <xml> <EType> <E></E> <F></F> <FType><E1></E1><E2></E2></FType> <FType><E1></E1><E2></E2></FType> <FType><E1></E1><E2></E2></FType> <G></G> </EType> </xml> I tried : (?P<xml>.*(?=<FType>.*<FType>).*) But it give me everything ;-( I Expect : <xml> <EType> <E></E> <F></F> <G></G> </EType> </xml>

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  • OptimisticLockException in inner transaction ruins outer transaction

    - by Pace
    I have the following code (OLE = OptimisticLockException)... public void outer() { try { middle() } catch (OLE) { updateEntities(); outer(); } } @Transactional public void middle() { try { inner() } catch (OLE) { updateEntities(); middle(); } @Transactional public void inner() { //Do DB operation } inner() is called by other non-transactional methods which is why both middle() and inner() are transactional. As you can see, I deal with OLEs by updating the entities and retrying the operation. The problem I'm having is that when I designed things this way I was assuming that the only time one could get an OLE was when a transaction closed. This is apparently not the case as the call to inner() is throwing an OLE even when the stack is outer()->middle()->inner(). Now, middle() is properly handling the OLE and the retry succeeds but when it comes time to close the transaction it has been marked rollbackOnly by Spring. When the middle() method call finally returns the closing aspect throws an exception because it can't commit a transaction marked rollbackOnly. I'm uncertain what to do here. I can't clear the rollbackOnly state. I don't want to force create a transaction on every call to inner because that kills my performance. Am I missing something or can anyone see a way I can structure this differently? EDIT: To clarify what I'm asking, let me explain my main question. Is it possible to catch and handle OLE if you are inside of an @Transactional method? FYI: The transaction manager is a JpaTransactionManager and the JPA provider is Hibernate.

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  • best way to reference business objects from presentation layer..?

    - by Vytas999
    I want to develop an enterprise app that includes a WindowsForms presentation layer, middle-tier components for business logic and data access, and a MsSQL Server database. Middle-tier components should contain some business objects and will be called from presentation layer using .NET Remoting. Whitch is the best way (and why) to reference these business objects from presentation layer? a) Create class library project, implementing business objects. Reference this project from presentation layer and middle-tier layer. b) Create interface library project defining business objects. Create class library project implementing interfaces. Reference class library project from middle-tier layer. Reference interface library project from presentation layer. c) Create separate class library projects for middle-tier and presentation layer. Reference corresponding project from presentation layer.

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  • How can I change mouse keymapping

    - by zuberuber
    I have Razer DeathAdder(left handed edition) and A4Tech wireless mouse. My problem is I don't know how to change wireless mouse keymapping(swaping left/right click). Can somebody guide me how to do such thing? List of my devices: ? Virtual core pointer id=2 [master pointer (3)] ? ? Virtual core XTEST pointer id=4 [slave pointer (2)] ? ? Logitech Unifying Device. Wireless PID:4004 id=8 [slave pointer (2)] ? ? Razer Razer DeathAdder id=11 [slave pointer (2)] ? ? A4TECH USB Device id=12 [slave pointer (2)] ? ? A4TECH USB Device id=13 [slave pointer (2)] ? Virtual core keyboard id=3 [master keyboard (2)] ? Virtual core XTEST keyboard id=5 [slave keyboard (3)] ? Power Button id=6 [slave keyboard (3)] ? Power Button id=7 [slave keyboard (3)] ? Logitech USB Keyboard id=9 [slave keyboard (3)] ? Logitech USB Keyboard id=10 [slave keyboard (3)] This is my Razer xinput: Device 'Razer Razer DeathAdder': Device Enabled (121): 1 Coordinate Transformation Matrix (123): 1.000000, 0.000000, 0.000000, 0.000000, 1.000000, 0.000000, 0.000000, 0.000000, 1.000000 Device Accel Profile (246): 0 Device Accel Constant Deceleration (247): 5.000000 Device Accel Adaptive Deceleration (248): 1.000000 Device Accel Velocity Scaling (249): 10.000000 Device Product ID (240): 5426, 22 Device Node (241): "/dev/input/event4" Evdev Axis Inversion (250): 0, 0 Evdev Axes Swap (252): 0 Axis Labels (253): "Rel X" (131), "Rel Y" (132), "Rel Vert Wheel" (274) Button Labels (254): "Button Left" (124), "Button Middle" (125), "Button Right" (126), "Button Wheel Up" (127), "Button Wheel Down" (128), "Button Horiz Wheel Left" (129), "Button Horiz Wheel Right" (130), "Button Side" (269), "Button Extra" (270), "Button Forward" (271), "Button Back" (272), "Button Task" (273), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243) Evdev Middle Button Emulation (255): 0 Evdev Middle Button Timeout (256): 50 Evdev Third Button Emulation (257): 0 Evdev Third Button Emulation Timeout (258): 1000 Evdev Third Button Emulation Button (259): 3 Evdev Third Button Emulation Threshold (260): 20 Evdev Wheel Emulation (261): 0 Evdev Wheel Emulation Axes (262): 0, 0, 4, 5 Evdev Wheel Emulation Inertia (263): 10 Evdev Wheel Emulation Timeout (264): 200 Evdev Wheel Emulation Button (265): 4 Evdev Drag Lock Buttons (266): 0 And this is my wireless mouse xinput: Device 'A4TECH USB Device': Device Enabled (121): 1 Coordinate Transformation Matrix (123): 1.000000, 0.000000, 0.000000, 0.000000, 1.000000, 0.000000, 0.000000, 0.000000, 1.000000 Device Accel Profile (246): 0 Device Accel Constant Deceleration (247): 1.000000 Device Accel Adaptive Deceleration (248): 1.000000 Device Accel Velocity Scaling (249): 10.000000 Device Product ID (240): 2522, 1359 Device Node (241): "/dev/input/event16" Evdev Axis Inversion (250): 0, 0 Evdev Axes Swap (252): 0 Axis Labels (253): "Rel X" (131), "Rel Y" (132), "Rel Horiz Wheel" (245), "Rel Vert Wheel" (274) Button Labels (254): "Button Left" (124), "Button Middle" (125), "Button Right" (126), "Button Wheel Up" (127), "Button Wheel Down" (128), "Button Horiz Wheel Left" (129), "Button Horiz Wheel Right" (130), "Button Side" (269), "Button Extra" (270), "Button Forward" (271), "Button Back" (272), "Button Task" (273), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243), "Button Unknown" (243) Evdev Middle Button Emulation (255): 0 Evdev Middle Button Timeout (256): 50 Evdev Third Button Emulation (257): 0 Evdev Third Button Emulation Timeout (258): 1000 Evdev Third Button Emulation Button (259): 3 Evdev Third Button Emulation Threshold (260): 20 Evdev Wheel Emulation (261): 0 Evdev Wheel Emulation Axes (262): 0, 0, 4, 5 Evdev Wheel Emulation Inertia (263): 10 Evdev Wheel Emulation Timeout (264): 200 Evdev Wheel Emulation Button (265): 4 Evdev Drag Lock Buttons (266): 0

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  • Reading three words and sorting them in lexicographic order

    - by Derrick
    I am trying to create a program that asks the User to type three words and sort them in lexicographic order. EXAMPLE; Enter three words separated by spaces: Pear Orange Apple Apple Orange Pear The program is working fine (if I attempt the above example) except for one type of combination example that I will show below. EXAMPLE; Enter three words separated by spaces: Orange Apple Pear Apple Pear Pear The program is skipping the first word (Orange) if it is supposed to appear in the middle of the three words. I believe that this line of code is affecting the program because it says that "this assigned value is never used" but I'm not sure how to fix it since I'm still an entry Java learner. middle = firstWord; Because of that line being unused, it's why Pear appeared twice. import java.util.*; public static void main(String[] args) { Scanner wordInput = new Scanner(System.in); String firstWord; String secondWord; String thirdWord; System.out.println("Enter three words separated by spaces: "); firstWord = wordInput.next(); secondWord = wordInput.next(); thirdWord = wordInput.next(); String top = firstWord; String bottom = firstWord; if( top.compareTo(secondWord) > 0) { top = secondWord; } if( top.compareTo(thirdWord) > 0) { top = thirdWord; } if( bottom.compareTo(secondWord) < 0) { bottom = secondWord; } if( bottom.compareTo(thirdWord) < 0) { bottom = thirdWord; } String middle; if( !firstWord.equals(bottom) && !firstWord.equals(top) ) { middle = firstWord; } if( !secondWord.equals(bottom) && !secondWord.equals(top) ) { middle = secondWord; } else { middle = thirdWord; } System.out.println( top ); System.out.println( middle ); System.out.println( bottom ); } } Does anyone what I am missing or doing wrong? :( Please and thank you for any help!

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  • gvim Cannot make changes, 'modifiable' is off issues with file explorer.

    - by nos
    In gvim using netrw(the file explorer), I usually middle click a file to open it in the last active window. This just leads to an error stating "Cannot make changes, 'modifiable' is off". Another middle click, and the file opens fine where I expect it to. All buffers are saved, there's no uncommuted changes anywhere. What causes this, and what can I do about it ? Here's a pic when I middle click a file:

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