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  • For each level of factor aggregate values over all levels except the current one (in R)

    - by Andrey Chetverikov
    For each level of factor I need to extract values aggregated over all subsets of data.frame except the current one. For example, there is a several subjects doing a reaction time task during several days, and I need to compute mean reaction time for all subjects and all days, but not including the subject for whom the mean is computed. Currently, I do it like this: library(lme4) ddply(sleepstudy, .(Subject, Days), summarise , avg_rt=mean(sleepstudy[sleepstudy$Subject!=Subject&sleepstudy$Days==Days,"Reaction"]), .progress="text") It works fine for small data sets, but for large ones it can be very slow. Is there a way to do it faster?

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  • The largest prime factor with php

    - by Tom
    So, I wrote php program to find the largest prime factor with php and I think it is quite optimal, because it loads quite fast. But there is a problem, it doesn't count very big numbers's prime factors. Here is a program: function is_even($s) { $sk_sum = 0; for($i = 1; $i <= $s; $i++) { if($s % $i == 0) { $sk_sum++; } } if($sk_sum == 2) { return true; } } $x = 600851475143; $i = 2; //x is number while($i <= $x) { if($x % $i == 0) { if(is_even($i)) { $sk = $i; $x = $x / $i; } } $i++; } echo $sk;

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  • Correct way to model recursive relationship in Django

    - by Yuval A
    My application has two node types: a parent node which can hold recursive child nodes. Think of it like the post-comment system in SO, but comments can be recursive: parent_1 child_11 child_12 child_121 child_3 parent_2 child_21 child_211 child_2111 Important to note that the parent nodes have different attributes and behavior than the child nodes. What is the correct (and presumably most efficient) way of modeling this relationship in Django?

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  • Recognizing Tail-recursive functions with Flex+Bison and convert code to an Iterative form

    - by Viet
    I'm writing a calculator with an ability to accept new function definitions. Being aware of the need of newbies to try recursive functions such as Fibonacci, I would like my calculator to be able to recognize Tail-recursive functions with Flex + Bison and convert code to an Iterative form. I'm using Flex & Bison to do the job. If you have any hints or ideas, I welcome them warmly. Thanks!

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  • Recursive insert-method for a linked list

    - by user3726477
    I'm learning C# and I've made a recursive insert-method for a linked list: public static int recursiveInsert(ref int value, ref MyLinkedList list) { if (list == null) return new MyLinkedList(value, null); else { list.next = recursiveInsert(ref int value, ref list.next); return list; } } How would you modify this method to make the recursive call look like this: recursiveInsert(value, ref list.next) instead of: list.next = recursiveInsert(ref int value, ref list.next);

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  • Scala: recursive search avoiding cycles

    - by user1826663
    How can I write a recursive search that I avoid cycles. My class is this: class Component(var name: String, var number: Int, var subComponent: Set[Component]) Now I need a way to check whether a component is contained within its subcomponent or between subcomponent of its subcomponent and so on.Avoiding possible cycles caused by other Component. My method of recursive search must have the following signature, where subC is the Set [component] of comp. def content (comp: Component, subC: Set[Component]) : Boolean = { } Thanks for the help.

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  • Which are the fundamental stack manipulation operations?

    - by Aadit M Shah
    I'm creating a stack oriented virtual machine, and so I started learning Forth for a general understanding about how it would work. Then I shortlisted the essential stack manipulation operations I would need to implement in my virtual machine: drop ( a -- ) dup ( a -- a a ) swap ( a b -- b a ) rot ( a b c -- b c a ) I believe that the following four stack manipulation operations can be used to simulate any other stack manipulation operation. For example: nip ( a b -- b ) swap drop -rot ( a b c -- c a b ) rot rot tuck ( a b -- b a b ) dup -rot over ( a b -- a b a ) swap tuck That being said however I wanted to know whether I have listed all the fundamental stack manipulation operations necessary to manipulate the stack in any possible way. Are there any more fundamental stack manipulation operations I would need to implement, without which my virtual machine wouldn't be Turing complete?

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  • Simple recursive DNS resolver for debugging (app or VM)

    - by notpeter
    I have an issue which I believe is caused by incorrect DNS queries (doubled subdomains like _record.host.subdomain.tld.subdomain.tld) when querying for SRV records. So I need to an alternate DNS server with heavy logging so I can see every query (especially stupid ones), acting as a recursive resolver with the ability create records which override real DNS records so I can not only find the records it's (wrongly) looking for, but populate those records as well. I know I could install a DNS server on yet another linux box, but I feel like this is the sort of thing that someone may already setup a simple python script or single use vm just for this purpose.

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  • Subquery using derived table in Hibernate HQL

    - by Vladimir
    I have a Hibernate HQL question. I'd like to write a subquery as a derived table (for performance reasons). Is it possible to do that in HQL? Example: FROM Customer WHERE country.id in (SELECT id FROM (SELECT id FROM Country where type='GREEN') derivedTable) (btw, this is just a sample query so don't give advices on rewriting it, is just the derived table concept I'm interested in) Thanks.

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  • sql query without subquery

    - by user1285737
    I need to rewrite this query and I'm not allowed to use a subquery. I need to select the name and color of the parts that are heavier than the wheel. SELECT name, color FROM parts WHERE weight > (SELECT weight FROM parts WHERE name="wheel"); This is the table: PARTS ID NAME COLOR WEIGHT 1 wheel black 100 2 tire black 50 3 gear red 20 Thanks in advance

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  • postgres subquery w/ derived column

    - by Wells
    The following query won't work, but it should be clear what I'm trying to do: split the value of 't' on space and use the last element in that array in the subquery (as it will match tl). Any ideas how to do this? Thanks! SELECT t, y, "type", regexp_split_to_array(t, ' ') as t_array, sum(dr), ( select uz from f.tfa where tl = t_array[-1] ) as uz, sc FROM padres.yd_fld WHERE y = 2010 AND pos <> 0 GROUP BY t, y, "type", sc;

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  • MYSQL Query using subquery

    - by Michael Quiles
    Cant get this to work can any one help. List the part number, part description, and on_hand value of each part whose number of units on hand is more than the average number of units onhand for all parts use a subquery? SELECT PART_NUM, DESCRIPTION, SUM(ON_HAND * PRICE) ON_HAND_VALUE FROM PART; WHERE MAX(ON_HAND); (AVG(ON_HAND) > ON_HAND);

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  • 'Subquery returned more than 1 value' problem in EntityFramework

    - by plotnick
    I have one 'Transaction' entity object with 'Operations' navproperty with multiplicity of 'Many'. When I'm adding only one operation per transaction nothing happens, but when I'm trying to add more than one operation, db.SaveChanges() throws an exception like 'Subquery returned more than 1 value blah, blah, blah' How can I solve that? Help me guys please... BTW... Could you tell me how can I see the exact query string that EF passes to Sql Server on db.SaveChanges() method?

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  • Tail-recursive merge sort in OCaml

    - by CFP
    Hello world! I’m trying to implement a tail-recursive list-sorting function in OCaml, and I’ve come up with the following code: let tailrec_merge_sort l = let split l = let rec _split source left right = match source with | [] -> (left, right) | head :: tail -> _split tail right (head :: left) in _split l [] [] in let merge l1 l2 = let rec _merge l1 l2 result = match l1, l2 with | [], [] -> result | [], h :: t | h :: t, [] -> _merge [] t (h :: result) | h1 :: t1, h2 :: t2 -> if h1 < h2 then _merge t1 l2 (h1 :: result) else _merge l1 t2 (h2 :: result) in List.rev (_merge l1 l2 []) in let rec sort = function | [] -> [] | [a] -> [a] | list -> let left, right = split list in merge (sort left) (sort right) in sort l ;; Yet it seems that it is not actually tail-recursive, since I encounter a "Stack overflow during evaluation (looping recursion?)" error. Could you please help me spot the non tail-recursive call in this code? I've searched quite a lot, without finding it. Cout it be the let binding in the sort function? Thanks a lot, CFP.

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  • A F# tail-recursive question

    - by ksharp
    Recently, I'm learning F#. I try to solve problem in different ways. Like this: (* [0;1;2;3;4;5;6;7;8] -> [(0,1,2);(3,4,5);(6,7,8)] *) //head-recursive let rec toTriplet_v1 list= match list with | a::b::c::t -> (a,b,c)::(toTriplet_v1 t) | _ -> [] //tail-recursive let toTriplet_v2 list= let rec loop lst acc= match lst with | a::b::c::t -> loop t ((a,b,c)::acc) | _ -> acc loop list [] //tail-recursive(???) let toTriplet_v3 list= let rec loop lst accfun= match lst with | a::b::c::t -> loop t (fun ls -> accfun ((a,b,c)::ls)) | _ -> accfun [] loop list (fun x -> x) let funs = [toTriplet_v1; toTriplet_v2; toTriplet_v3]; funs |> List.map (fun x -> x [0..8]) |> List.iteri (fun i x -> printfn "V%d : %A" (i+1) x) I thought the results of V2 and V3 should be the same. But, I get the result below: V1 : [(0, 1, 2); (3, 4, 5); (6, 7, 8)] V2 : [(6, 7, 8); (3, 4, 5); (0, 1, 2)] V3 : [(0, 1, 2); (3, 4, 5); (6, 7, 8)] Why the results of V2 and V3 are different?

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  • recursive grep started at / hangs

    - by Martin
    I have used following grep search pattern on multiple platforms: grep -r -I -D skip 'string_to_match' / For example on FreeBSD 8.0, FreeBSD 6.4 and Debian 6.0(squeeze). Command does a recursive search starting from root directory, assumes that binary files do not have the 'string_to_match' and skips devices, sockets and named pipes. FreeBSD 8.0 and FreeBSD 6.4 use GNU grep version 2.5.1 and Debian 6.0 uses GNU grep version 2.6.3. On FreeBSD 6.4, last information printed to stderr was "grep: /dev/cuad0: Device busy". After this grep just idles as according to "top -m io -o total" the I/O usage of grep is nonexistent. Same behavior is true under FreeBSD 8.0, but last information sent to stderr is "grep: /tmp/.wine-0: Permission denied" on my installation. In case of Debian, last output to stderr is "grep: /proc/sysrq-trigger: Input/output error". If I check the I/O usage of grep process under Debian, it is following: root@Debian:~# iotop -bp 22439 Total DISK READ: 0.00 B/s | Total DISK WRITE: 0.00 B/s TID PRIO USER DISK READ DISK WRITE SWAPIN IO COMMAND 22439 be/4 root 0.00 B/s 0.00 B/s 0.00 % 0.00 % grep -r -I -D skip 10.10.10.99 / Total DISK READ: 0.00 B/s | Total DISK WRITE: 0.00 B/s TID PRIO USER DISK READ DISK WRITE SWAPIN IO COMMAND 22439 be/4 root 0.00 B/s 0.00 B/s 0.00 % 0.00 % grep -r -I -D skip 10.10.10.99 / Total DISK READ: 0.00 B/s | Total DISK WRITE: 0.00 B/s TID PRIO USER DISK READ DISK WRITE SWAPIN IO COMMAND 22439 be/4 root 0.00 B/s 0.00 B/s 0.00 % 0.00 % grep -r -I -D skip 10.10.10.99 / ^Croot@Debian:~# What might cause this? Is there a way to view which file grep is currently processing in case lsof is not present? I'm able to use lsof under Debian and looks like the problematic file name there is "0xc6b2c230 file struct, ty=0, op=0xc0d34120". I'm not sure what this is.. I'm not able to use lsof or fstat under FreeBSD. PS: I know I could use find utility, but this is not the question.

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  • named responding recursive on norecurse queries

    - by Keks
    I have a server on which named is running. It is intercepted with another named server which it is not aware of. Querying the first named server results in timeouts. The server tries to resolve the query recursively. During that the firewall redirects the DNS Request from the first named server to the second one (the query from the first one is addressed to a e.g. a root server and has its "Recursion desired" bit set to 0). Despite that the second named responds to this request with a entirely or at least 1 level more resolved response than the first named server expects. So it ends up with a timeout even though it got a correct name server or even the full IP for the queried domain. In the first case the first name server tries to follow the authority domain ignoring the coresponding glue record and ends up in a loop it aborts: queried: google.com -> got from named#2: ns1.google.com -> ignore glue record and query: ns1.google.com -> got authority from named#2: google.com In the second case it ignores the answer section with the correct IP and instead tries to follow the name servers from the authority section, which ends up in the same dead end as case 1. So how can it be that the second named responds with recursive results even though the bit was explicitly set to 0 in the request from the first named?

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  • Cannot make bind9 forward DNS query to subdomain unless recursive enabled

    - by PP.
    I am trying to develop my own dynamic DNS. I'm running my own custom DNS for the subdomain on port 5353. ASCII diagram: INET --->:53 Bind 9 --->:5353 node.js | V zone_files I have example.com. The node.js DNS is for dyn.example.com. In my /etc/bind/named.conf.local I have: zone "example.com" { type master; file "/etc/bind/db.com.example"; allow-transfer { zonetxfrsafe; }; }; zone "dyn.example.com" IN { # DYNAMIC type forward; forwarders { 127.0.0.1 port 5353; }; forward only; }; I've even gone so far as to add a NS in my example.com zone file: $TTL 86400 @ IN SOA ns.example.com. hostmaster.example.com. ( 2013070104 ; Serial 7200 ; Refresh 1200 ; Retry 2419200 ; Expire 86400 ) ; Negative Cache TTL ; NS ns ; inet of our nameserver ns A 1.2.3.4 ; NS record for subdomain dyn NS ns When I attempt to get a record from the subdomain server it doesn't get forwarded: dig @127.0.0.1 test.dyn.example.com However if I turn recursive on in /etc/bind/named.conf.options: options { recursion yes; } .. then I CAN see the request going to the subdomain server. But I don't want recursion yes; in my Bind configuration as it is poor security practice (and allows all-and-sundry requests that are not related to my managed zones). How does one forward (proxy) zone queries for just one zone? Or do I give up on Bind altogether and find a DNS server that can actually forward specific queries?

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  • Why so much stack space used for each recursion?

    - by Harvey
    I have a simple recursive function RCompare() that calls a more complex function Compare() which returns before the recursive call. Each recursion level uses 248 bytes of stack space which seems like way more than it should. Here is the recursive function: void CMList::RCompare(MP n1) // RECURSIVE and Looping compare function { auto MP ne=n1->mf; while(StkAvl() && Compare(n1=ne->mb)) RCompare(n1); // Recursive call ! } StkAvl() is a simple stack space check function that compares the address of an auto variable to the value of an address near the end of the stack stored in a static variable. It seems to me that the only things added to the stack in each recursion are two pointer variables (MP is a pointer to a structure) and the stuff that one function call stores, a few saved registers, base pointer, return address, etc., all 32-bit (4 byte) values. There's no way that is 248 bytes is it? I don't no how to actually look at the stack in a meaningful way in Visual Studio 2008. Thanks

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  • stats::reorder vs Hmisc::reorder

    - by learnr
    I am trying to get around the strange overlap of stats::reorder vs Hmisc::reorder. Without Hmisc loaded I get the result I want, i.e. an unordered factor: > with(InsectSprays, reorder(spray, count, median)) [1] A A A A A A A A A A A A B B B B B B B B B B B B C C C C C C C C C C C C D D [39] D D D D D D D D D D E E E E E E E E E E E E F F F F F F F F F F F F attr(,"scores") A B C D E F 14.0 16.5 1.5 5.0 3.0 15.0 Levels: C E D A F B Now after loading Hmisc the result is an ordered factor: > library(Hmisc) Loading required package: survival Loading required package: splines Attaching package: 'Hmisc' The following object(s) are masked from 'package:survival': untangle.specials The following object(s) are masked from 'package:base': format.pval, round.POSIXt, trunc.POSIXt, units > with(InsectSprays, reorder(spray, count, median)) [1] A A A A A A A A A A A A B B B B B B B B B B B B C C C C C C C C C C C C D D [39] D D D D D D D D D D E E E E E E E E E E E E F F F F F F F F F F F F Levels: C < E < D < A < F < B In calling stats::reorder directly, I now for some reason get an ordered factor. > with(InsectSprays, stats::reorder(spray, count, median)) [1] A A A A A A A A A A A A B B B B B B B B B B B B C C C C C C C C C C C C D D [39] D D D D D D D D D D E E E E E E E E E E E E F F F F F F F F F F F F Levels: C < E < D < A < F < B Specifying, that I would need an unordered factor results in an error suggesting that stats::reorder is not used? > with(InsectSprays, stats::reorder(spray, count, median, order = FALSE)) Error in FUN(X[[1L]], ...) : unused argument(s) (order = FALSE) So the question really is how do I get an unordered factor with Hmisc loaded?

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  • Subquery works in 9i but not in 11g

    - by Zsuetam
    Statement below is working on Oracle 9i but not on Oracle 11g SELECT * FROM ( SELECT 0 scrnfail_rate, '9' zz, 7 hh FROM DUAL UNION ALL SELECT 0 scrnfail_rate, '9' zz, 7 hh FROM DUAL ) WHERE zz IS NOT NULL AND TO_CHAR (hh) NOT IN ( SELECT DECODE ( scrnfail_rate, 0, -1, ROUND (LEVEL * 1 / (scrnfail_rate / 100)) - ROUND (1 / (2 * (scrnfail_rate / 100))) ) AS nno FROM DUAL WHERE NVL (scrnfail_rate, 0) > 0 CONNECT BY LEVEL <= ROUND(9 * scrnfail_rate / 100) ) It looks like Oracle 11g is ignoring where decode or even where clause in the subquery. This query should return two rows as it does on Oracle 9i, but results ORA-01476: divisor is equal to zero on Oracle 11g EE 11.2.0.1.0 - 64bit. Can anyone help? Thanks!

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  • Exclude records matching subquery

    - by Skudd
    There is probably an obvious answer to this question, but I am having one heck of a time getting anywhere with it. Consider the query: SELECT * FROM reports AS r JOIN reportvalues AS rv ON rv.report_id = r.report_id JOIN metrics AS m ON m.metric_id = rv.metric_id WHERE r.report_id NOT IN( SELECT DISTINCT report_id FROM exclude_report ) In this query, exclude_report is a view constructed in a similar manner. Now what happens is the query takes an EXTREMELY long time to execute, presumably because the subquery is being executed over each and every row in the parent query. However, I am finding no feasible means of doing this any other way. Oh great SQL wizards, please advise. I really need a way of doing this all in SQL, which I will be using in SSRS.

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  • Referencing outer query's tables in a subquery

    - by soulmerge
    Is it possible to reference an outer query in a subquery with MySQL? I know there are some cases where this is possible: SELECT * FROM table t1 WHERE t1.date = ( SELECT MAX(date) FROM table t2 WHERE t2.id = t1.id)` ); But I'm wondering if something like this could work: SELECT u.username, c._postCount FROM User u INNER JOIN ( SELECT p.user, COUNT(*) AS _postCount FROM Posting p --# This is the reference I would need: WHERE p.user = u.id ) c ON c.user = u.id WHERE u.joinDate < '2009-10-10'; I know I could achieve the same using a GROUP BY or by pulling the outer WHERE clause into the sub-query, but I need this for automatic SQL generation and cannot use either alternative for various other reasons.

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