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  • How do I write a custom validator for a zend form element with customized error messages?

    - by Mallika Iyer
    I have a question field with a list of allowed characters : A-Z,0-9,colon (:), question mark (?), comma(,), hyphen(-), apostrophe ('). I have the regex which works fine, in the fashion : $question->addValidator('regex', true, array(<regular expresstion>)) The default error message is something like ''' does not match against pattern '' I want to write a custom error message that says ' is not allowed in this field' Is there a simple way to do it using the existing zend components that I'm missing? Is writing a custom validator the only way to achieve what I'm trying to achieve? If yes, how do I write a custom validator (I looked at the documentation and didn't quite understand how I can customize the error messages) If there is any other way, I'd most appreciate that input too. Thanks for taking the time to answer this!

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  • python coockie,request another page

    - by polovinamozga
    #!/usr/bin/python # -*- coding: utf-8 -*- import urllib2 import urllib import httplib import Cookie import cookielib Login = 'user' Password = 'password' Domain = 'inbox.ru' Auth = 'https://auth.mail.ru/cgi-bin/auth' cj = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj)) login_data = urllib.urlencode({'Login' : Login, 'Domain' :Domain, 'Password' : Password }) opener.open('https://auth.mail.ru/cgi-bin/auth', login_data) resp = opener.open('https://auth.mail.ru/cgi-bin/auth').read() print resp.decode('cp1251') #output page in cp1251 When script sucessfully executed i see in print resp.decode('cp1251') my page with auth. But when a try to request another page for example http://my.mail.ru i see autorization request. How i can use cookie with another page?

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  • Javascript onunload form submit isn't submitting data

    - by Kevin
    I currently have form that checks if a user has unsubmitted changes when they leave the page with a function called through the onunload event. Here's the function: function saveOnExit() { var answer = confirm("You are about to leave the page. All unsaved work will be lost. Would you like to save now?"); if (answer) { document.main_form.submit(); } } And here's the form: <body onunload="saveOnExit()"> <form name="main_form" id="main_form" method="post" action="submit.php" onsubmit="saveScroll()"> <textarea name="comments"></textarea> <input type="submit" name="submit2" value="Submit!"/> </form> I'm not sure what I'm doing wrong here. The data gets submitted and saved in my database if I just press the submit button for the form. However, trying to submit the form through the onunload event doesn't result in anything being stored, from what I can tell. I've tried adding onclick alerts to the submitt button and onsubmit alerts to the form elements and I can verify that the submit button is being triggered and that the form does get submitted. However, nothing gets passed stored in the database. Any ideas as to what I'm doing wrong? Thanks.

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  • How can Request Validation be disabled for HttpHandlers?

    - by Mun
    Is it possible to disable request validation for HttpHandlers? A bit of background - I've got an ASP.NET web application using an HttpHandler to receive the payment response from WorldPay. The IIS logs show that the handler is being called correctly from WorldPay, but the code inside the handler is never called. If I create a physical ASPX page and set ValidateRequest=false in the header, and put the same code in the Page_Load method, the code is called without any problems. This solves the problem, though I'd prefer to stick with using an HttpHandler for this as it's better suited for this type of functionality, rather than having an empty ASPX page, though this is dependent on being able to disable request validation. The web application is using ASP.NET 2.0 and the server is IIS6.

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  • Java HTTP Request Occasionally Hangs

    - by behrk2
    Hello Everyone, For the majority of the time, my HTTP Requests work with no problem. However, occasionally they will hang. The code that I am using is set up so that if the request succeeds (with a response code of 200 or 201), then call screen.requestSucceeded(). If the request fails, then call screen.requestFailed(). When the request hangs, however, it does so before one of the above methods are called. Is there something wrong with my code? Should I be using some sort of best practice to prevent any hanging? The following is my code. I would appreciate any help. Thanks! HttpConnection connection = (HttpConnection) Connector.open(url + connectionParameters); connection.setRequestMethod(method); connection.setRequestProperty("WWW-Authenticate", "OAuth realm=api.netflix.com"); if (method.equals("POST")) { connection.setRequestProperty("Content-type", "application/x-www-form-urlencoded"); } int responseCode = connection.getResponseCode(); System.out.println("RESPONSE CODE: " + responseCode); if (connection instanceof HttpsConnection) { HttpsConnection secureConnection = (HttpsConnection) connection; String issuer = secureConnection.getSecurityInfo() .getServerCertificate().getIssuer(); UiApplication.getUiApplication().invokeLater( new DialogRunner( "Secure Connection! Certificate issued by: " + issuer)); } if (responseCode != 200 && responseCode != 201) { screen.requestFailed("Unexpected response code: " + responseCode); connection.close(); return; } String contentType = connection.getHeaderField("Content-type"); ByteArrayOutputStream baos = new ByteArrayOutputStream(); InputStream responseData = connection.openInputStream(); byte[] buffer = new byte[20000]; int bytesRead = 0; while ((bytesRead = responseData.read(buffer)) > 0) { baos.write(buffer, 0, bytesRead); } baos.close(); connection.close(); screen.requestSucceeded(baos.toByteArray(), contentType); } catch (IOException ex) { screen.requestFailed(ex.toString()); }

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  • Track each request to the website using HttpModule

    - by stacker
    I want to save each request to the website. In general I want to include the following information: User IP, The web site url, user-if-exist, date-time. Response time, response success-failed status. Is it reasonable to collect the 1 and 2 in the same action? (like same HttpModule)? Do you know about any existing structure that I can follow that track every request/response-status to the website? The data need to be logged to sql server.

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  • transfer parameter to next request

    - by user234194
    I have a situation where clicking a link in one column on the datatable opens A update FORM in the same page. The problem is when I hit the submit button for update, the render is set to false again of that update panel which was previously set true by parameter passed clicking the link. I tried htmlhiddenInput and did setValue and getvalue but the value is lost. Is there any way I can save that parameter send from link, when clicked, even after submitting the form. I achieved it doing session but I dont wanna use session. Any help is appreciated, thanks.

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  • What can cause a double page request?

    - by johnnietheblack
    I am currently investigating a double request problem on my site. Not all the time, but sometimes, a requested page will in fact load twice...which is not a problem really until it is on a page with PHP that inserts stuff into my db on request (my tracking script). I have read that an empty src in an image tag, and an empty url() in a css background could potentially cause the page to be requested twice. However, I can't find any problems with those. Is there anything else that could be causing something like this?

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  • Strange issue with fixed form border styles in Vista

    - by Nazgulled
    My previous post about this issue didn't got too many answers and it was kinda specific and hard to understand. I think I've managed to understand the problem better and I now believe it to be a Vista issue... The problem lies on all types of fixed border styles like FixedDialog, Fixed3D, FixedSingle and FixedToolWindow. It does not happen on the sizable ones. This problem, like I said, it also happens only on Vista. Let's say you have a form with any of the fixed border styles and set the starting location to 0,0. What you want here is for the form to be snapped to the top left corner of the screen. This works just fine if the form border style is one of the sizable options, if it's fixed, well, the form will be a little bit outside of the screen working area both to the left and top. What's more strange about this is that the form location does not change, it sill is 0,0, but a few pixels of the form are still drawn outside of the working screen area. I tested this on XP and it didn't happen, the problem is Vista specific. On XP, the only difference was the border size that change a bit between any of the styles. But the form was always perfectly snapped to position 0,0. If possible, without finding how many pixels are being drawn outside of the working area and then add that to the form location, is there a possible way to fix or workaround this?

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  • handle json request in PHP

    - by wo_shi_ni_ba_ba
    When making an ajax call, when contentType is set to application/json instead of the default x-www-form-urlencoded, server side (in PHP) can't get the post parameters. in the following working example, if I set the contentType to "application/json" in the ajax request, PHP $_POST would be empty. why does this happen? How can I handle a request where contentType is application/json properly in PHP? $.ajax({ cache: false, type: "POST", url: "xxx.php", //contentType: "application/json", processData: true, data: {my_params:123}, success: function(res){ }, complete: function(XMLHttpRequest, text_status) { } });

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  • Refresh page in browser without resubmitting form

    - by Michael
    I'm an ASP.NET developer, and I usually find myself leaving the webpage that I'm working on open in my browser (Chrome is my browser of choice, but this question is relevant for any browser). My workflow typically goes like this: I write code, I rebuild my project in Visual Studio, and then I flip back to my browser with Alt-Tab and hit F5 to refresh the page. This is fine and dandy if a form hasn't been submitted since the page was opened. But if I've been clicking around on ASP.NET form controls, the page has posted form data a number of times, so hitting F5 causes the browser to (sensibly) pop up a confirmation message, e.g., "Confirm Form Resubmission: The page that you're looking for used information that you entered...". Sometimes I do want to resubmit the form, but more often than not, I just want to start over with the page (rather than resubmit form data). The way I usually get around this is to simply add some query string data to the URL so that the browser sees it as a fresh page request, e.g.: page.aspx becomes page.aspx? (or vice-versa). My question is: Is there a better way to quickly request a fresh version of a webpage (and not submit form data) in any of the major browsers? It seems like a no-brainer to me for web development, but maybe I'm missing something. What I'd love to see is something like the last item in this list: F5: refresh page Ctrl-F5: refresh page (and force cache refresh) Alt-F5: request fresh copy of the page without resubmitting the form

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  • FireFox: strange behavior on submiting a form

    - by ilnur777
    Can anyone help with this strange form submiting in FireFox? So this form should be submitted after pushing "go to submit" button. There is an onclick event on the button that should submit form through JavaScript. In the form there is another button "test" without any onclick event. Following the script, the form should be submitted only after pushing the "go to submit" button, but it submits even pushing at "test" button. In the Internet Explorer it works well! But this stupid FireFox browser behaves different. Here is example of HTML page: <script> function func(){ document.form1.submit(); } </script> <form name="form1" method="post" action="somewhere.php"> <button>test</button> <input type="button" value="go to submit" onclick="func();"> </form> I have several buttons with <button onclick="...">option 1</button> options. I want to fix strange submiting a form in FireFox. Help please!

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  • problem with get http request from IPhone

    - by user317192
    Hi, I am writing a sample PHP Web Service that is sending GET Http request from the iphone to the web server. The server side code is returning JSON Data to iphone, the server side code looks like: function getUsers(){ $con=mysql_connect("localhost","root","123456") or die(mysql_error()); if(!mysql_select_db("eventsfast",$con)) { echo "Unable to connect to DB"; exit; } $sql="SELECT * from users"; $result=mysql_query($sql); if(!$result) { die('Could not successfully run query Error:'.mysql_error()); } $data = array(); while($row = mysql_fetch_assoc($result)){ $data['username'][] = $row['username']; $data['password'][]= $row['password']; } mysql_close($con); //print_r(json_encode($data)); //return (json_encode($data)); return json_encode('success'); } getUsers(); ? Its a simple code that Fetches all the data from the user table and send it to the iphone application. *****************************************************IPHONE APPLICATION (void)viewDidLoad { [super viewDidLoad]; responseData = [[NSMutableData data] retain]; NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://localhost:8888/GetData.php"]]; [[NSURLConnection alloc] initWithRequest:request delegate:self]; } (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response { [responseData setLength:0]; } (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data { [responseData appendData:data]; } (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error { label.text = [NSString stringWithFormat:@"Connection failed: %@", [error description]]; } (void)connectionDidFinishLoading:(NSURLConnection *)connection { [connection release]; NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding]; [responseData release]; NSError *error; SBJSON *json = [[SBJSON new] autorelease]; NSArray *luckyNumbers = [json objectWithString:responseString error:&error]; [responseString release]; if (luckyNumbers == nil) label.text = [NSString stringWithFormat:@"JSON parsing failed: %@", [error localizedDescription]]; else { NSMutableString *text = [NSMutableString stringWithString:@"Lucky numbers:\n"]; for (int i = 0; i < [luckyNumbers count]; i++) [text appendFormat:@"%@\n", [luckyNumbers objectAtIndex:i]]; NSLog(text); label.text = text; } } ********************PROBLEM**************** The problem is that nothing is coming on iphone side of the application........... the response doesn't contains anything.............. Please help..............

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  • Disable redirect in fb:request-form Send/Cancel button

    - by Colossal Paul
    How do I disable the redirect in Facebook's invite form? <fb:serverfbml style="width: 600px; height: 650px;"> <script type="text/fbml"> <fb:request-form action="index.php" method="POST" invite="true" type="MyApp" content="Please have a look. <fb:req-choice url='http://apps.facebook.com/myapp/' label='View Now!' />"> <div class="clearfix" style="padding-bottom: 10px;"> <fb:multi-friend-selector condensed="true" style="width: 600px;" /> </div> <fb:request-form-submit /> </fb:request-form> After selecting friends, you will see the final Send Invite dialog with your template. After you click send or cancel, how do i disable the redirect by just closing the the dialog? Thanks.

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  • PDF form (not) saving

    - by gregseth
    Hi, I've created a form in a PDF with Adobe Acrobat Pro. When empy, I want to use it as a template which the user opens, fills in, and saves as a copy to preserve the blank state of the template. Here's the trick : I found both ways to make the document read only - the user can't save the form value, only print them make the document writeable, but in this case the document acting as a template can be modified too. Any ideas? Thanks.

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  • Using a checkbox input on a form to send the form data to different email addresses

    - by Cody Thomas
    I am building a form for a client. Here is the rundown. The form will be used as a request to have a staff member contact the person filling out the form. However, there is a list of staff members that will contact them depending on what the subject matter is. So, I want to create a checkbox input section on the form with each staff person's email address attached to a corresponding checkbox. So, the person filling out the form can check only the staff people necessary for their needs. Finally, when the person clicks "submit", the form will be emailed to only the staff members who were checked in the form. I'm at a loss of how to set this up.

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  • How to pass email from one form to another page's form with javascript

    - by zac
    I am trying to have an email signup form on one page populate the email block on another page by passing it through the url and pulling it out with document.write. The first form is something like: <form action="/sign-up"> <input type="text" name="passEmail"><input type="submit"></form> And the recieving form is like : <form name="theForm"> <input type='text' name='email'></form> And I am trying a script like this <SCRIPT LANGUAGE="javascript"> var locate = window.location document.theForm.email.value = locate var text = document.theForm.email.value function delineate(str) { theEmail = str.indexOf("=") + 1; return(str.substring(theEmail)); } document.write(delineate(text)); </SCRIPT> Instead of pulling the email after the = in the url it is pulling the entire url. Can someone help me accomplish this?

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  • Apache HttpClient making multipart form post

    - by Russ
    I'm pretty green to HttpClient and I'm finding the lack of (and or blatantly incorrect) documentation extremely frustrating. I'm trying to implement the following post (listed below) with Apache Http Client, but have no idea how to actually do it. I'm going to bury myself in documentation for the next week, but perhaps more experienced HttpClient coders could get me an answer sooner. Post: Content-Type: multipart/form-data; boundary=---------------------------1294919323195 Content-Length: 502 -----------------------------1294919323195 Content-Disposition: form-data; name="number" 5555555555 -----------------------------1294919323195 Content-Disposition: form-data; name="clip" rickroll -----------------------------1294919323195 Content-Disposition: form-data; name="upload_file"; filename="" Content-Type: application/octet-stream -----------------------------1294919323195 Content-Disposition: form-data; name="tos" agree -----------------------------1294919323195--

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  • How to pass an input value from a small form into a big form? (PHP, Javascript, URLs)

    - by sarahdopp
    I have a Wordpress website that needs to display a 3rd party newsletter signup form. This sign-up form has lots of fields and takes up its own full page. I want to display a simple "enter email address, hit submit" form at the top of every page. When the user hits submit, it should take them to the full form, where their email address is already pre-populated in the appropriate field. What's a good way to pass the input value from the short form to the long form? I'm inclined to use the URL somehow, but I've never approached it before. (My skills: expert XHTML/CSS. competent with WP theme hacking. comfortable enough with PHP and Javascript to move things around, but not enough to write them from scratch.) Thanks!

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  • Retrieve value from form

    - by vetri
    My form is like <form action="javascript:;" method="post" id="reportForm"> <input type="text" name="as" maxlength="3" /> --CODE-- <html:hidden property="reportid" value="${Scope.reportId}" /> --code-- </form> I can retrieve values from the form in javascript like this.form = dojo.byId('reportForm'); this.as1 = this.form.as; How can i retrieve the value of the html:hidden tag property.

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  • how to do server side form validation for dynamic inputs with Django

    - by Satoru.Logic
    Hi, all. I am using django.forms.Form to validate form data in a survey applications. In a survey-creating form, a user can submit multiple questions that belong to the survey being created. Names for the question inputs are in the form of 'question_seq' , where seq is maintained using Javascript. Back in the server side, my code doesn't know before hand how many such questions will be submitted. Is there any way to do this with Django form so that the form can automatically recognizes the questions and validate them?

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  • iphone uiwebview / form

    - by user290031
    Hey All, Okay, so I have an iphone app that presents the user with a UIWebview of an html page with a form I created. The form has standard stuff like a message box and dropdown boxes. Once the user fills out the form and clicks submit, it saves the information as nsstrings in my program. Okay, no problem there. That all works fine. However, I also wanna be able to edit this form as well. Once I save all this information the user selected in the form (as strings), is there a way to put it back into an html form using an uiwebview so a user of the app can edit the info later on?? I apologize in advance if I didn't give enough info.

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  • Perl: Value of response code in HTTP::Request

    - by lola
    Hi all, So, I am writing a code to get a document from the internet. The document size is around 200 KB. This is the code: !/usr/local/bin/perl -w use strict; use LWP::UserAgent; my $ua = LWP::UserAgent->new; my $url = "SOME URL"; my $req = HTTP::Request->new(GET => $url); my $res = $ua->request($req); if($res->is_success){ print $res->content ."\n"; } else{ print "Error: " . $res->status_line; } Now, the only problem is I can't mention what the URL is. However, the output is: "Error: 500 read timeout". When I checked the link externally, the data is being downloaded in under 5 seconds. I even changed the timeout to 1000s, but it still didn't work. How should I go about finding more information related to the response. The size of the file (around 200KB) is also not too great to warrant a read timeout. The server is also not a busy one, didn't give a problem whenever I checked the link on the browser. Thanks.

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  • Delphi - form within form

    - by mawg
    For aesthetic reasons, I want to show a form on top of another form, just as if it were a component, say like a TPanel. It should resize with the parent, move around as th eparent is drageed by its title bar, etc. ----------------------------- | main form component 1 | ----------------------------- | main | the 'embedded' | | form | form goes here | |comp 2| | ----------------------------- can I do that? If so how?

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