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  • When should assertions stay in production code?

    - by Carl Seleborg
    Hi all, There's a discussion going on over at comp.lang.c++.moderated about whether or not assertions, which in C++ only exist in debug builds by default, should be kept in production code or not. Obviously, each project is unique, so my question here is not so much whether assertions should be kept, but in which cases this is recommendable/not a good idea. By assertion, I mean: A run-time check that tests a condition which, when false, reveals a bug in the software. A mechanism by which the program is halted (maybe after really minimal clean-up work). I'm not necessarily talking about C or C++. My own opinion is that if you're the programmer, but don't own the data (which is the case with most commercial desktop applications), you should keep them on, because a failing asssertion shows a bug, and you should not go on with a bug, with the risk of corrupting the user's data. This forces you to test strongly before you ship, and makes bugs more visible, thus easier to spot and fix. What's your opinion/experience? Cheers, Carl See related question here

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  • Speech Recognition Server Does Not Stay Open

    - by Waffle
    I am trying to create a simple program that loops for user speech input using com.apple.speech.recognitionserver. My code thus far is as follows: set user_response to "start" repeat while user_response is not equal to "Exit" tell application id "com.apple.speech.recognitionserver" set user_response to listen for {"Time", "Weather", "Exit"} with prompt "Good Morning" end tell if user_response = "Time" then set curr_time to time string of (the current date) set curr_day to weekday of (the current date) say "It is" say curr_time say "on" say curr_day say "day" else if user_response = "Weather" then say "It is hot outside. What do you expect?" end if end repeat say "Have a good day" If the above is run on my system it says good morning and it then pops up with the speech input system and waits for either Time, Weather, or Exit. They all do what they say they are going to do, but instead of looping if I say Time and Weather and asking again until I say exit the speechserver times out and never pops up again. Is there a way of either keeping that application open until the program ends or is applescript not capable of looping for user speech input?

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  • Why do my buttons stay pressed?

    - by Timmmm
    In my activity I respond to an onClick() by replacing the current view with a new one (setContentView()). For some reason when I do this and then go back to the original view later the button I originally pressed still looks like it is pressed. If you 'refresh' it somehow (e.g. scroll over it with the trackball) then it reverts to the unpressed state. It's as if the button doesn't get the 'touch-up' event. The weird thing is: This only happens on my T-Mobile Pulse (android 1.5). It doesn't happen on the emulator. I've tried calling invalidate()/postInvalidate() on the view when I show it but it doesn't have any effect.

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  • Making a sqlite file stay existent between runs of the program

    - by Cocorico
    Hi! I'm having a problem with some sqlite code for an iPhone program in Xcode. I was opening my database like this: int result = sqlite3_open("stealtown.db", &database); Which is how they had it in a book I was looking at while I type the program. But then, that way of opening a database it only works when you run in simulator, not on device. So I finally figure out I need to do this: NSString *file = [[NSBundle mainBundle] pathForResource:@"stealtown" ofType:@"db"]; int result = sqlite3_open([file UTF8String], &database); And that works on device, EXCEPT one thing: Each time you launch the program, it starts as if you had never created the database, and when you stick an entry in the table, it's the ONLY entry in that table. When I used the first code on the simulator, I could open my program 6 times, each time adding 1 entry to a table, and at the end, I had 6 entries in that table. With the second code, I do exact same thing but each time there is only 1 entry in that table. Am I explaining this okay, I hope so, it's hard sometimes for me. Anyone maybe know why this would be?

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  • How to stay DRY when using both Javascript and ERB templates (Rails)

    - by user94154
    I'm building a Rails app that uses Pusher to use web sockets to push updates to directly to the client. In javascript: channel.bind('tweet-create', function(tweet){ //when a tweet is created, execute the following code: $('#timeline').append("<div class='tweet'><div class='tweeter'>"+tweet.username+"</div>"+tweet.status+"</div>"); }); This is nasty mixing of code and presentation. So the natural solution would be to use a javascript template. Perhaps eco or mustache: //store this somewhere convenient, perhaps in the view folder: tweet_view = "<div class='tweet'><div class='tweeter'>{{tweet.username}}</div>{{tweet.status}}</div>" channel.bind('tweet-create', function(tweet){ //when a tweet is created, execute the following code: $('#timeline').append(Mustache.to_html(tweet_view, tweet)); //much cleaner }); This is good and all, except, I'm repeating myself. The mustache template is 99% identical to the ERB templates I already have written to render HTML from the server. The intended output/purpose of the mustache and ERB templates are 100% the same: to turn a tweet object into tweet html. What is the best way to eliminate this repetition? UPDATE: Even though I answered my own question, I really want to see other ideas/solutions from other people--hence the bounty!

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  • Tomcat does save logged users during restart

    - by mabuzer
    How to force Tomcat to save logged users, so that the they kept logged in even after Tomcat has restarted? Right now the user has to login again everytime. Added the following lines into web-app context.xml: <Manager className="org.apache.catalina.session.PersistentManager"> <Store className="org.apache.catalina.session.FileStore"/> </Manager> but still I see login page after Tomcat restart, I use Tomcat 6.0.26 Update I managed to solve it like this: 1) Make my own extended version of FormAuthentication class: package com.alz.tomcat; import java.io.IOException; import java.security.Principal; import org.apache.catalina.Session; import org.apache.catalina.deploy.LoginConfig; import org.apache.catalina.connector.Request; import org.apache.catalina.connector.Response; import org.apache.catalina.authenticator.Constants; import org.apache.catalina.authenticator.FormAuthenticator; /** * * @author mabuzer */ public class Authenticator extends FormAuthenticator { @Override public boolean authenticate(Request request, Response response, LoginConfig config) throws IOException { String username = (String) request.getSession().getAttribute("USERNAME"); String password = (String) request.getSession().getAttribute("PASSWORD"); Principal principal = request.getUserPrincipal(); Session session = request.getSessionInternal(true); if (request.getUserPrincipal() == null && !isNull(username) && !isNull(password)) { principal = context.getRealm().authenticate(username, password); if (principal != null) { session.setNote(Constants.FORM_PRINCIPAL_NOTE, principal); if (!matchRequest(request)) { register(request, response, principal, Constants.FORM_METHOD, username, password); return (true); } } return super.authenticate(request, response, config); } else { return super.authenticate(request, response, config); } } private boolean isNull(String str) { if (str == null || "".equals(str)) { return true; } else { return false; } } } 2) Have your own ContextConfig class: package com.alz.tomcat; import java.util.HashMap; import org.apache.catalina.Valve; /** * * @author [email protected] */ public class ContextConfig extends org.apache.catalina.startup.ContextConfig { public ContextConfig() { super(); // we need to append our authenticator setCustomAuthenticators(customAuthenticators); customAuthenticators = new HashMap(); customAuthenticators.put("Authenticator" , new Authenticator()); } } 3) Have a class extends LifeCycleListener to set replace default ContextConfig the one you made: package com.alz.tomcat; import org.apache.catalina.Lifecycle; import org.apache.catalina.LifecycleEvent; import org.apache.catalina.core.StandardHost; /** * * @author [email protected] */ public class LifeCycleListener implements org.apache.catalina.LifecycleListener { public void lifecycleEvent(LifecycleEvent lifeCycleEvent) { if (Lifecycle.BEFORE_START_EVENT.equals(lifeCycleEvent.getType())) { StandardHost aStandardHost = (StandardHost) lifeCycleEvent.getLifecycle(); aStandardHost.setConfigClass("com.alz.tomcat.ContextConfig"); } } } 4) Final step which is to add your LifeCycleListener to server.xml in Host tag like this: <Host appBase="webapps" autoDeploy="true" name="localhost" unpackWARs="true" xmlNamespaceAware="false" xmlValidation="false"> <Listener className="com.alz.tomcat.LifeCycleListener"/> </Host>

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  • How to make Edittext size stay put? Android

    - by Sephy
    Hi everybody, I know the attribute which makes the text "disapear" on the left part of the Edittext to maintain a single line, (singleLine="true"). Btu my issue is when I fill the edittext before the view is displayed... in this case, my edittexts are all going out of the screen... any ideas? thx

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  • Paperclip: Stay put on edit

    - by EricR
    When a user edits something in my application, they're forced to re-upload their image via paperclip even if they aren't changing it. Failing to do so will cause an error, since I validate_presence_of :image. This is quite annoying. How can I make it so Paperclip won't update its attributes if a user simply doesn't supply a new image on an edit? The photo controller is fresh out of Rails' scaffold generator. The rest of the source code is provided below. models/accommodation.rb class Accommodation < ActiveRecord::Base attr_accessible :photo validates_presence_of :photo has_one :photo has_many :notifications belongs_to :user accepts_nested_attributes_for :photo, :allow_destroy => true end controllers/accommodation_controller.rb class AccommodationsController < ApplicationController def index @accommodations = Accommodation.all end def show @accommodation = Accommodation.find(params[:id]) rescue ActiveRecord::RecordNotFound flash[:error] = "Accommodation not found." redirect_to :home end def new @accommodation = current_user.accommodations.build @accommodation.build_photo end def create @accommodation = current_user.accommodations.build(params[:accommodation]) if @accommodation.save flash[:notice] = "Successfully created your accommodation." redirect_to @accommodation else @accommodation.build_photo render :new end end def edit @accommodation = Accommodation.find(params[:id]) @accommodation.build_photo rescue ActiveRecord::RecordNotFound flash[:error] = "Accommodation not found." redirect_to :home end def update @accommodation = Accommodation.find(params[:id]) if @accommodation.update_attributes(params[:accommodation]) flash[:notice] = "Successfully updated accommodation." redirect_to @accommodation else @accommodation.build_photo render :edit end end def destroy @accommodation = Accommodation.find(params[:id]) @accommodation.destroy flash[:notice] = "Successfully destroyed accommodation." redirect_to :inkeep end end models/photo.rb class Photo < ActiveRecord::Base attr_accessible :image, :primary belongs_to :accommodation has_attached_file :image, :styles => { :thumb=> "100x100#", :small => "150x150>" } end

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  • How do I implement Hibernate Pagination using a cursor (so the results stay consistent, despite new

    - by hunterae
    Hey all, Is there any way to maintain a database cursor using Hibernate between web requests? Basically, I'm trying to implement pagination, but the data that is being paged is consistently changing (i.e. new records are added into the database). We are trying to set it up such that when you do your initial search (returning a maximum of 5000 results), and you page through the results, those same records always appear on the same page (i.e. we're not continuously running the query each time next and previous page buttons are clicked). The way we're currently implementing this is by merely selecting 5000 (at most) primary keys from the table we're paging, storing those keys in memory, and then just using 20 primary keys at a time to fetch their details from the database. However, we want to get away from having to store these keys in memory and would much prefer a database cursor that we just keep going back to and moving backwards and forwards over the cursor to generate pages. I tried doing this with Hibernate's ScrollableResults but found that I could not call methods like next() and previous() would cause an exception if you within a different web request / Hibernate session (no surprise there). Is there any way to reattach a ScrollableResults object to a Session, much the same way you would reattach a detached database object to make it persistent? Are there any other approaches to implement this data paging with consistent paging results without caching the primary keys?

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  • Java MessageDigest result does not stay constant

    - by user344146
    I've got this function for encrypting passwords in Java, but somehow when I call MessageDigest, it returns a different result every time even though I call it with the same password. I wonder if I am initializing it wrong somehow. public String encrypt (String password) { MessageDigest md = MessageDigest.getInstance("SHA-1"); md.reset(); md.update(password.getBytes(Charset.forName("utf-8")),0,password.length()); String res = md.digest().toString(); }

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  • Stay on current page after POST

    - by DogPooOnYourShoe
    I have a form which once the Submit button is pressed, it goes to a blank page and returns any error messages on that blank page. However I have a website template and I wish that my script is run, and returns the the page which did the action POST and puts any error messages on that page. Example of what is happening: PAGE REQUESTS POST ---- SCRIPT RUNS --- RETURNS ERROR MESSAGE What I want it to do is: PAGE REQUESTS POST --- SCRIPT RUNS ---- GOES TO THE PAGE WHICH REQUESTED POST ---- SHOWS ANY ERROR MESSAGES WHICH THE SCRIPT PICKED OUT.

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  • My cookies won't stay (PHP).

    - by RemiX
    I'm building an autologin system using cookies, but one fundamental part of the functionality of the cookies fails: they are non-persistent over different sessions - or even pages! In my login script, I set the cookies like this: setcookie('userID', $userID, time()+86400); // (edited after replies) $userID has a value. Then I print the $_COOKIE variable and it says array(['base_usid'] = 1); So that's good, but when I click the home page and print the $_COOKIE variable there, it says NULL. Does anyone see the problem?

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  • Dynamic URL to Stay the Same on all Pages

    - by JCBiggar
    so when my url looks like this: http://mywebsitehere.com/?kw=1 I am using this code below to do stuff with it: <?php if( isset($_GET['kw'] )){ //my div here } ?> It works great, and I am getting exactly what I want on the page. However, any link I click on that page will change the url structure and remove the ?kw=1 . Is there anyway to add the ?kw=1 to every link for that session? I have no clue how to do this? Any ideas or answers would be great! Thanks! Let me know if I need to give more to my question.

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  • How do I run my C# application in scheduled tasks when I am not logged in

    - by Peggy A
    I have a C# console application that just processes data. The problem is that when I log off, the console application ends. If I schedule the application to run at a set time and I am not logged in, the application does not run at all. I can run it interactively by double clicking the exe and I can open scheduled tasks and run it by right clicking and selecting run. As soon as I log out, the application ends. Any help will be greatly appreciated.

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  • Get UPN or email for logged in user in a .NET web application

    - by DrStalker
    I'm not a .NET developer, and I have a feeling this would be trivial for someone who is: I have a C# web application that makes user of the user credentials of the logged in user. Currently it uses the SID which comes from System.Security.Principal.WindowsIdentity.GetCurrent().User.Value I need to get either the users UPN login or email address (as defined in active directory) instead of the SID. GetCurrent() returns an object of type WindowsIdentity; looking in the details for WindowsIdentity Members: MSDN: WindowsIdentity Members I can't see anything that looks like it would give me either the UPN or email in there. How can I pull up that information to use, either by feeding the SID into some other function or calling something different in the first place.

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  • Flex Inheriting Logged in User

    - by Nick
    I am trying to secure my Flex application within my Java web application. Currently my Java web application, handles logging and managing user accounts and the like. I was wondering if there is a way to essentially share that user credentials with the Flash movie in a secure mechanism? For instance, if you log in, we want you to be able to save items in the Flex application for that user, only if that user is logged in of course. Any ideas? Any help is greatly appreciated.

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  • node_load in drupal gets incorrect node when you are NOT logged in

    - by Alaa
    Hi All, i have a module and i am using node_load(array('nid' = arg(1))); now the problem is that this function keep getting its data for node_load from DB cache. how can i force this function to not use DB cache or static value? Example my link is http://mydomain.com/node/344983 now: $node=node_load(array('nid'=arg(1)),null,true); echo $node-nid; output: 435632 which is a randomly node id (available in the database) and everytime i ctrl+F5 my browser, i get new nid!! Note: if i am logged in, it gives the result correctly, but this problem happens only when i am browsing the website as an anonymous user i really appreciate any idea!! Thanks

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  • ASP MVC: Keeping track of logged in users.

    - by user323395
    I'm creating a ASP MVC application. And because of the complex authorization i'm trying to build my own login system. (So i'm not using asp membership providers, and related classes). Now i'm able to create new accounts in the database with hashed passwords. But how do i keep track that a user is logged in. Is generating a long random number and putting this with the userID in the database and cookie enough? Sorry for my rather bad english! Ty in advance :)

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  • Displaying objects based on if a user is logged in or not

    - by MaxMackie
    I'm learning about PHP sessions for user authentication on my website. I know how to restrict the viewing of a complete page using sessions (simply check if the 'uid' session variable is set and if it is, show content, if not redirect to an error). However I'm trying to figure out the best way to selectively show and hide different objects (div, text, images) based on if a user is logged in or not. Is it as simple as checking for the 'uid' session variable and displaying based on if it set or not? Is there a more efficient way of doing this id there are a lot of conditional elements on a page?

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  • MVC Pages that require the user to be logged in

    - by keithjgrant
    I'm working on a little MVC framework and I'm wondering what the "best way" is to structure things so secure pages/controllers always ensure the user is logged in (and thus automatically redirects to a login page--or elsewhere--if not). Obviously, there are a lot of ways to do it, but I'm wondering what solution(s) are the most common or are considered the best practice. Some ideas I had: Explicitly call user->isLoggedIn() at the beginning of your controller action method? (Seems far too easy to forget and leave an important page unsecure on accident) Make your controller extend a secureController that always checks for login in the constructor? Do this check in the model when secure information is requested? (Seems like redundant calls would be made) Something else entirely? Note: I'm working in PHP, though the question is not language-dependent.

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  • Display username to logged in user only?

    - by RodeoRamsey
    I have a Wordpress blog set up to display comments as "Anonymous User" by hard coding it into the comments.php file. I would like to have it say the user's Username next to their comment and ONLY display that Username to THEM. In other words, if they're a guest, they'll see "Anonymous User" and if they're a registered/logged in DIFFERENT user, they'll still see "Anonymous User", but if it's THEIR comment it'll say "Your Comment" or their own username. Any clue on a snippet of code? Here's what I have so far: Anonymous User: <div class="post-txt" id="<?php comment_ID() ?>"><?php comment_text() ?></div> Thanks!

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  • Getting Data Specific to Logged in user

    - by user1770470
    I need to list logged in users active leads,and allow paging and selectable sorting, I cant use the grid because of the layout requirement. I have been searching the web for the last 2 days and cant find any viable solution Any help or direction would be greatly appreciated. var query = db.Query("SELECT a.listingId, a.datetime, c.details, c.buycommercial, c.buyindustrial, c.buyretail, c.buyland, c.tencommercial, c.tenindustrial, c.tenretail, c.tenland, c.investor, c.developer, d.companyname, d.firstname, d.lastname, d.tel, d.cell, d.email FROM dbo.tblactivebroker a JOIN dbo.tblActiveListing b ON a.ListingId = b.ListingId JOIN dbo.tblListings c ON b.ListingId = c.ListingId JOIN dbo.tblContact d ON c.crmid = d.id WHERE b.active = 'True' AND a.ActiveBrokerID = @0",brokerid);

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  • How to change the elements in the page base on user who is logged in

    - by user225269
    Please give me an idea on how to display elements in a page depending on who is logged in. For example, a user or an administrator. I'm thinking of something like this but I get a parse error, what do I lack in this code?: <?php session_start(); if (!(isset($_SESSION['loginAdmin']) && $_SESSION['loginAdmin'] != '')) { header ("Location: loginam.php"); } if else (!(isset($_SESSION[['loginAdmin']) && $_SESSION['loginAdmin'] =='')) { ?> <?php include('head2.php'); ?> } <?php if (!(isset($_SESSION['login']) && $_SESSION['login'] != '')) { header ("Location: login.php"); } if else (!(isset($_SESSION[['login']) && $_SESSION['login'] =='')) { ?> <?php include('head3.php'); } ?> Please help

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  • How should I determine if a user is logged in graphically while lightdm is running?

    - by Jack
    I want to know if someone is logged into a local X-session. In the past I looked at the output of ck-list-sessions. The output looked something like this: Session12: unix-user = '[redacted]' realname = '[redacted]' seat = 'Seat1' session-type = '' active = TRUE x11-display = ':0' x11-display-device = '/dev/tty8' display-device = '' remote-host-name = '' is-local = TRUE on-since = '2012-10-22T18:17:55.553236Z' login-session-id = '4294967295' If no one was logged in, there was no output. I checked if someone was logged in with ck_result" string => execresult("/usr/bin/ck-list-sessions | /bin/grep x11 | /usr/bin/cut --delimiter=\\' -f 2 | /usr/bin/wc -w This no longer works, because lightdm greeter looks like a logged in user Session12: unix-user = '[redacted]' realname = 'Light Display Manager' seat = 'Seat1' session-type = 'LoginWindow' active = TRUE x11-display = ':0' x11-display-device = '/dev/tty8' display-device = '' remote-host-name = '' is-local = TRUE on-since = '2012-10-22T22:17:55.553236Z' login-session-id = '4294967295' I guess I could check session-type, but I don't know how to do that and check x11-display in one-liner. I then need to write my own script, but at that point I thought I would check if anyone else has already done the work or if there is a way to get ConsoleKit to tell me what I want (or if I should be using a different tool)?

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