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  • An XML file or Database?

    - by webnoob
    I am re-writing a section of my site and am trying to decide how much of a rewrite this will be. At the moment I have a web service feed that generates an xml once per day. I then use this xml file on my website to generate the general structure. I am trying to decide if this information should be located in the database or stay in the xml file. The file can range from 4mb - 12mb. The files depth can go on and on so I have to recurse to find the data I want. I use the .NET serializer classes and store the serialized file in a global variable to avoid re-serializing it each time the page is loaded. My reasons for thinking a database would be better are: I would know exactly where I am in the file by using an internal ID so I wouldn't have to recurse the file to get information. I wouldn't have to load / serialize the XML and could just use my already open database connections. Searching for the data in the file would be quicker(?) as I would just perform an SQL query rather than re-cursing the file. Has anyone got any ideas which is better and which option uses more resources on the server or be quicker? EDIT: The file is read every time the web page is loaded (although only serialized once). It isn't written to by standard users (only by an admin task that runs in the middle of the night). This is my initial investigation before mocking up.

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  • Stairway to XML: Level 8 - Deleting Data from an XML Instance

    in order to use the modify() method to delete data from typed and untyped XML instances, you must pass an XML DML expression as an argument to the method. That expression must include the delete keyword, along with an XQuery expression that defines the XML component to be deleted. Robert makes it seem simple, as usual. The best way to version control T-SQLSSMS plug-in SQL Source Control connects SVN, TFS, Git, Hg and all others to SQL Server. Learn more.

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  • Design for XML mapping scenarios between two different systems [on hold]

    - by deepak_prn
    Mapping XML fields between two systems is a mundane routine in integration scenarios. I am trying to make the design documents look better and provide clear understanding to the developers especially when we do not use XSLT or any other IDE such as jDeveloper or eclipse plugins. I want it to be a high level design but at the same time talk in developer's language. So that there is no requirements that slip under the crack. For example, one of the scenarios goes: the store cashier sells an item, the transaction data is sent to Data management system. Now, I am writing a functional design for the scenario which deals with mapping XML fields between our system and the data management system. Question : I was wondering if some one had to deal with mapping XML fields between two systems? (without XSLT being involved) and if you used a table to represent the fields mapping (example is below) or any other visualization tool which does not break the bank ? I am trying to find out if there is a better way to represent XML mapping in your design documents. The widely accepted and used method seems to be using a simple table such as in the picture to illustrate the mapping. I am wondering if there are alternate ways/ tools to represent such as in Altova:

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  • Stairway to XML: Level 7 - Updating Data in an XML Instance

    You need to provide the necessary keywords and define the XQuery and value expressions in your XML DML expression in order to use the modify() method to update element and attribute values in either typed or untyped XML instances in an XML column. Robert Sheldon explains how. "It really helped us isolate where we were experiencing a bottleneck"- John Q Martin, SQL Server DBA. Get started with SQL Monitor today to solve tricky performance problems - download a free trial

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  • Convience of mySQL over xml

    - by Bonechilla
    Currently I use XML to store specific information to correctly load a few things such as a list of specfied characters, scenes and music, Once more I use JAXB in combination with standard compression/decompression(ZIP) functionality to store a list of extrenous data. This data is called to add functionality to the character, somewhat like Skills in an RPG. Each skill is seperated into its own XML file with a grandlist which contains the names of each file with their extensions omitted and zipped in folder that gets encrypted. At first using xml was working fine however as the skill list grow i worry about its stability. I was wondering if I should begin storing the data in mySQL. Originally I planned to simply convert everything to JSON over xml but i think possibly mySQL would be a better move. Can anyone inform me of the key difference and pros and cons of each I guess i'm looking for the best way to store the data more conviently and would be easier to operate on. The data is mostly primatives and strings and the only arraylist of values i have i can just concat into a single field and parse later

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  • Stairway to XML: Level 5 - The XML exist() and nodes() Methods

    The XML exist() method is used, often in a WHERE clause, to check the existence of an element within an XML document or fragment. The nodes() method lets you shred an XML instance and return the information as relational data. 12 essential tools for database professionalsThe SQL Developer Bundle contains 12 tools designed with the SQL Server developer and DBA in mind. Try it now.

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  • Redirect output logs of javax.xml.ws and com.sun.xml.ws

    - by chrisnfoneur
    I am working on a SOAP based web service, with Sun's Metro. I am facing an annoying bug, each time I send a malformed SOAP object to my web service, sun's api spam the System.out with logs like this: javax.xml.ws.WebServiceException: com.sun.istack.XMLStreamException2: org.xml.sax.SAXParseException: cvc-complex-type.4: Attribute 'type' must appear on element 'object'. at com.sun.xml.ws.util.pipe.AbstractSchemaValidationTube.doProcess(AbstractSchemaValidationTube.java:206) at com.sun.xml.ws.util.pipe.AbstractSchemaValidationTube.processRequest(AbstractSchemaValidationTube.java:175) at com.sun.xml.ws.api.pipe.Fiber.__doRun(Fiber.java:595) at com.sun.xml.ws.api.pipe.Fiber._doRun(Fiber.java:554) at com.sun.xml.ws.api.pipe.Fiber.doRun(Fiber.java:539) at com.sun.xml.ws.api.pipe.Fiber.runSync(Fiber.java:436) at com.sun.xml.ws.server.WSEndpointImpl$2.process(WSEndpointImpl.java:243) at com.sun.xml.ws.transport.http.HttpAdapter$HttpToolkit.handle(HttpAdapter.java:444) at com.sun.xml.ws.transport.http.HttpAdapter.handle(HttpAdapter.java:244) at com.sun.xml.ws.transport.http.server.WSHttpHandler.handleExchange(WSHttpHandler.java:106) at com.sun.xml.ws.transport.http.server.WSHttpHandler.handle(WSHttpHandler.java:91) at com.sun.net.httpserver.Filter$Chain.doFilter(Filter.java:65) at sun.net.httpserver.AuthFilter.doFilter(AuthFilter.java:54) at com.sun.net.httpserver.Filter$Chain.doFilter(Filter.java:68) at sun.net.httpserver.ServerImpl$Exchange$LinkHandler.handle(ServerImpl.java:555) at com.sun.net.httpserver.Filter$Chain.doFilter(Filter.java:65) at sun.net.httpserver.ServerImpl$Exchange.run(ServerImpl.java:527) at sun.net.httpserver.ServerImpl$DefaultExecutor.execute(ServerImpl.java:119) at sun.net.httpserver.ServerImpl$Dispatcher.handle(ServerImpl.java:349) at sun.net.httpserver.ServerImpl$Dispatcher.run(ServerImpl.java:321) at java.lang.Thread.run(Thread.java:619) Caused by: com.sun.istack.XMLStreamException2: org.xml.sax.SAXParseException: cvc-complex-type.4: Attribute 'type' must appear on element 'object'. at com.sun.xml.ws.util.xml.StAXSource$1.parse(StAXSource.java:185) at com.sun.xml.ws.util.xml.StAXSource$1.parse(StAXSource.java:170) at org.apache.xerces.jaxp.validation.ValidatorHandlerImpl.validate(Unknown Source) at org.apache.xerces.jaxp.validation.ValidatorImpl.validate(Unknown Source) at javax.xml.validation.Validator.validate(Validator.java:127) at com.sun.xml.ws.util.pipe.AbstractSchemaValidationTube.doProcess(AbstractSchemaValidationTube.java:204) ... 20 more I would like to switch off this log or redirect it to my error/warn/debug.log files used by log4j. I tried to add a rule in my log4j.xml file : <category name="javax.xml.ws"> <priority value="error" /> </category> It didn't worked. So I tried the following trick: java.util.logging.Logger.getLogger("javax.xml.ws.WebServiceException").setLevel( java.util.logging.Level.OFF); it didn't worked neither. Any ideas ? It is not a big issue but it makes my catalina.log getting bigger & bigger and it's not the appropriate place for this kind of log. Chris

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  • How to include multiple XML files in a single XML file for deserialization by XmlSerializer in .NET

    - by harrydev
    Hi, is it possible to use the XmlSerializer in .NET to load an XML file which includes other XML files? And how? This, in order to share XML state easily in two "parent" XML files, e.g. AB and BC in below. Example: using System; using System.IO; using System.Xml.Serialization; namespace XmlSerializerMultipleFilesTest { [Serializable] public class A { public int Value { get; set; } } [Serializable] public class B { public double Value { get; set; } } [Serializable] public class C { public string Value { get; set; } } [Serializable] public class AB { public A A { get; set; } public B B { get; set; } } [Serializable] public class BC { public B B { get; set; } public C C { get; set; } } class Program { public static void Serialize<T>(T data, string filePath) { using (var writer = new StreamWriter(filePath)) { var xmlSerializer = new XmlSerializer(typeof(T)); xmlSerializer.Serialize(writer, data); } } public static T Deserialize<T>(string filePath) { using (var reader = new StreamReader(filePath)) { var xmlSerializer = new XmlSerializer(typeof(T)); return (T)xmlSerializer.Deserialize(reader); } } static void Main(string[] args) { const string fileNameA = @"A.xml"; const string fileNameB = @"B.xml"; const string fileNameC = @"C.xml"; const string fileNameAB = @"AB.xml"; const string fileNameBC = @"BC.xml"; var a = new A(){ Value = 42 }; var b = new B(){ Value = Math.PI }; var c = new C(){ Value = "Something rotten" }; Serialize(a, fileNameA); Serialize(b, fileNameB); Serialize(c, fileNameC); // How can AB and BC be deserialized from single // files which include two of the A, B or C files. // Using ideally something like: var ab = Deserialize<AB>(fileNameAB); var bc = Deserialize<BC>(fileNameBC); // That is, so that A, B, C xml file // contents are shared across these two } } } Thus, the A, B, C files contain the following: A.xml: <?xml version="1.0" encoding="utf-8"?> <A xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Value>42</Value> </A> B.xml: <?xml version="1.0" encoding="utf-8"?> <B xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Value>3.1415926535897931</Value> </B> C.xml: <?xml version="1.0" encoding="utf-8"?> <C xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Value>Something rotten</Value> </C> And then the "parent" XML files would contain a XML include file of some sort (I have not been able to find anything like this), such as: AB.xml: <?xml version="1.0" encoding="utf-8"?> <AB xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <A include="A.xml"/> <B include="B.xml"/> </AB> BC.xml: <?xml version="1.0" encoding="utf-8"?> <BC xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <B include="B.xml"/> <C include="C.xml"/> </BC> Of course, I guess this can be solved by implementing IXmlSerializer for AB and BC, but I was hoping there was an easier solution or a generic solution with which classes themselves only need the [Serializable] attribute and nothing else. That is, the split into multiple files is XML only and handled by XmlSerializer itself or a custom generic serializer on top of this. I know this should be somewhat possible with app.config (as in http://stackoverflow.com/questions/480538/use-xml-includes-or-config-references-in-app-config-to-include-other-config-files), but I would prefer a solution based on XmlSerializer. Thanks.

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  • XML serialization query

    - by David Neale
    I have the following XML which needs deserializing/serializing: <instance> <dog> <items> <item> <label>Spaniel</label> </item> </items> </dog> <cat> <items> <item> <label>Tabby</label> </item> </items> </cat> </instance> I cannot change the XML structure. I need to map this to the following class: [Serializable, XmlRoot("instance")] public class AnimalInstance { public string Dog { get; set; } public string Cat { get; set; } } I'm not really sure where to start on this one without manually parsing the XML. I'd like to keep the code as brief as possible. Any ideas? (and no, my project doesn't actually involve cats and dogs).

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  • XML to Type - Quick way?

    - by MRFerocius
    Team; How are you doing? Im breaking my head trying to do this that seems simple but I can't figure it out... Suppose I have this XML as a string: <calles> <calle> <nombre>CALLAO AV.</nombre> <altura>1500</altura> <longitud>-58.3918617027</longitud> <latitud>-34.5916734896</latitud> <barrio>Recoleta</barrio> </calle> </calles> And and have this Type I created to map that XML: public class Ubicacion { public string Latitud { get; set; } public string Longitud { get; set; } public string Nombre { get; set; } public string Altura { get; set; } public string Barrio { get; set; } public Ubicacion() { } } I need to take that XML file and create an object with those values... Does somebody know a quick way to do it? with C#? I have been trying this but is not working at all... XElement dir = XElement.Parse(text); Ubicacion informacion = from d in dir.Elements("calle"). select new Ubicacion { Longitud = d.Element("longitud").Value, Latitud = d.Element("latitud").Value, Altura = d.Element("altura").Value, Nombre = d.Element("nombre").Value, Barrio = d.Element("barrio").Value, }; return informacion.Cast<Ubicacion>(); } Any ideas? Thanks!!!

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  • How to retain XML string as a string field during XML deserialization

    - by detale
    I got an XML input string and want to deserialize it to an object which partially retain the raw XML. <SetProfile> <sessionId>A81D83BC-09A0-4E32-B440-0000033D7AAD</sessionId> <profileDataXml> <ArrayOfProfileItem> <ProfileItem> <Name>Pulse</Name> <Value>80</Value> </ProfileItem> <ProfileItem> <Name>BloodPresure</Name> <Value>120</Value> </ProfileItem> </ArrayOfProfileItem> </profileDataXml> </SetProfile> The class definition: public class SetProfile { public Guid sessionId; public string profileDataXml; } I hope the deserialization syntax looks like string inputXML = "..."; // the above XML XmlSerializer xs = new XmlSerializer(typeof(SetProfile)); using (TextReader reader = new StringReader(inputXML)) { SetProfile obj = (SetProfile)xs.Deserialize(reader); // use obj .... } but XMLSerializer will throw an exception and won't output < profileDataXml 's descendants to "profileDataXml" field in raw XML string. Is there any way to implement the deserialization like that?

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  • C# LINQ to XML missing space character.

    - by Fossaw
    I write an XML file "by hand", (i.e. not with LINQ to XML), which sometimes includes an open/close tag containing a single space character. Upon viewing the resulting file, all appears correct, example below... <Item> <ItemNumber>3</ItemNumber> <English> </English> <Translation>Ignore this one. Do not remove.</Translation> </Item> ... the reasons for doing this are various and irrelevent, it is done. Later, I use a C# program with LINQ to XML to read the file back and extract the record... XElement X_EnglishE = null; // This is CRAZY foreach (XElement i in Records) { X_EnglishE = i.Element("English"); // There is only one damned record! } string X_English = X_EnglishE.ToString(); ... and test to make sure it is unchanged from the database record. I detect a change, when processing Items where the field had the single space character... +E+ Text[3] English source has been altered: Was: >>> <<< Now: >>><<< ... the and <<< parts I added to see what was happening, (hard to see space characters). I have fiddled around with this but can't see why this is so. It is not absolutely critical, as the field is not used, (yet), but I cannot trust C# or LINQ or whatever is doing this, if I do not understand why it is so. So what is doing that and why?

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  • XML Schema and element with type string

    - by svick
    I'm trying to create an XML Schema and I'm stuck. It seems I can't define an element with string content. What am I doing wrong? Schema: <?xml version="1.0"?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://ponderka.wz.cz/MusicLibrary0" targetNamespace="http://ponderka.wz.cz/MusicLibrary0"> <xs:element name="music-library"> <xs:complexType> <xs:sequence> <xs:element name="artist" type="xs:string"/> </xs:sequence> </xs:complexType> </xs:element> </xs:schema> Document: <?xml version="1.0"?> <music-library xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://ponderka.wz.cz/MusicLibrary0 data0.xsd" xmlns="http://ponderka.wz.cz/MusicLibrary0"> <artist>a</artist> </music-library> The validator says: Element <artist> is not allowed under element <music-library>. Reason: The following elements are expected at this location (see below) <artist> Error location: music-library / artist Details cvc-model-group: Element <artist> unexpected by type '{anonymous}' of element <music-library>. cvc-elt.5.2.1: The element <music-library> is not valid with respect to the actual type definition '{anonymous}'.

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  • HELP with XML to XML transformation using XSLT.

    - by kaniths
    Am a rookie trying XSLT and XML tranformations for the first time. To start off, i tried a simple sample programs. I expected the Output in Tree format (maintaining the hierarchy) instead i just get " KING" in single line... What could be the problem? PS: I use XMLSpy. Any guideline would be great full. Thanks :) Input XML: <ROWSET> <ROW> <EMPNO>7839</EMPNO> <ENAME>KING</ENAME> </ROW> </ROWSET> XSL used for transformation: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" encoding="UTF-8" indent="yes" omit-xml-declaration="no"/> <xsl:template match="/"> <Invitation> <To> <xsl:value-of select="ROWSET/ROW/ENAME"/> </To> </Invitation> </xsl:template>

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  • how to compare the two xml files and update the one xml file in java?

    - by prasad.gai
    I have created two xml files from those xml file i would like to compare one xml file with another xml file and update the xml file. I have created an xml file as follows: main.xml <?xml version="1.0" encoding="utf-8"?> <ScrollView xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="#00BFFF"> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical"> <LinearLayout android:id="@+id/linearLayout1" android:layout_width="fill_parent" android:layout_height="wrap_content" android:gravity="center" android:visibility="visible"> </LinearLayout> <LinearLayout android:id="@+id/linearLayout2" android:layout_width="fill_parent" android:layout_height="wrap_content" android:gravity="center" android:visibility="visible"> </LinearLayout> </LinearLayout> </ScrollView> properties.xml <?xml version='1.0' encoding='utf-8' standalone='yes' ?> <map> <int name="linearLayout1" value="8" /> <int name="linearLayout2" value="0" /> </map> from the above two xml files i would like to compare with LinearLayout android:id ="@id/LinearLayout1" from main.xml with int name ="linearLayout1" from properties.xml. from the above properties.xml file where name ="linearLayout1" and value ="8" then i would like to update the main.xml file where as LinearLayout android:id="@id/linearLayout1" propertie value as android:visibility="gone" From the above xml file how can i update main.xml file by comparing properties.xml? please any body help me.....

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  • How to parse a custom XML-style error code response from a website

    - by user1870127
    I'm developing a program that queries and prints out open data from the local transit authority, which is returned in the form of an XML response. Normally, when there are buses scheduled to run in the next few hours (and in other typical situations), the XML response generated by the page is handled correctly by the java.net.URLConnection.getInputStream() function, and I am able to print the individual results afterwards. The problem is when the buses are NOT running, or when some other problem with my queries develops after it is sent to the transit authority's web server. When the authority developed their service, they came up with their own unique error response codes, which are also sent as XMLs. For example, one of these error messages might look like this: <Error xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> <Code>3005</Code> <Message>Sorry, no stop estimates found for given values.</Message> </Error> (This code and similar is all that I receive from the transit authority in such situations.) However, it appears that URLConnection.getInputStream() and some of its siblings are unable to interpret this custom code as a "valid" response that I can handle and print out as an error message. Instead, they give me a more generic HTTP/1.1 404 Not Found error. This problem cascades into my program which then prints out a java.io.FileNotFoundException error pointing to the offending input stream. My question is therefore two-fold: 1. Is there a way to retrieve, parse, and print a custom XML-formatted error code sent by a web service using the plugins that are available in Java? 2. If the above is not possible, what other tools should I use or develop to handle such custom codes as described?

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  • Exporting to XML, including embedded classes

    - by Andy
    I have an object config which has some properties. I can export this ok, however, it also has an ArrayList which relates to embedded classes which I can't get to appear when I export to XML. Any pointers would be helpful. Export Method public String exportXML(config conf, String path) { String success = ""; try { FileOutputStream fstream = new FileOutputStream(path); try { XMLEncoder ostream = new XMLEncoder(fstream); try { ostream.writeObject(conf); ostream.flush(); } finally { ostream.close(); } } finally { fstream.close(); } } catch (Exception ex) { success = ex.getLocalizedMessage(); } return success; } Config Class (some detail stripped to keep size down) public class config { protected String author = ""; protected String website = ""; private ArrayList questions = new ArrayList(); public config(){ } public void addQuestion(String name) { questions.add(new question(questions.size(), name)); } public void removeQuestion(int id) { questions.remove(id); for (int c = 0; c <= questions.size(); c++) { question q = (question) (questions.get(id)); q.setId(c); } questions.trimToSize(); } public config.question getQuestion(int id){ return (question)questions.get(id); } /** * There can be multiple questions per config. * Questions store all the information regarding what questions are * asked of the user, including images, descriptions, and answers. */ public class question { protected int id; protected String title; protected ArrayList answers; public question(int id, String title) { this.id = id; this.title = title; } public int getId() { return id; } public void setId(int id) { this.id = id; } public void addAnswer(String name) { answers.add(new answer(answers.size(), name)); } public void removeAnswer(int id) { answers.remove(id); for (int c = 0; c <= answers.size(); c++) { answer a = (answer) (answers.get(id)); a.setId(c); } answers.trimToSize(); } public config.question.answer getAnswer(int id){ return (answer)answers.get(id); } public class answer { protected int id; protected String title; public answer(int id, String title) { this.id = id; this.title = title; } public int getId() { return id; } public void setId(int id) { this.id = id; } } } } Resultant XML File <?xml version="1.0" encoding="UTF-8"?> <java version="1.6.0_18" class="java.beans.XMLDecoder"> <object class="libConfig.config"> <void property="appName"> <string>xxx</string> </void> <void property="author"> <string>Andy</string> </void> <void property="website"> <string>www.example.com/dsx.xml</string> </void> </object> </java>

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  • c++ write own xml parser vs using tinyxml

    - by AdityaGameProgrammer
    Hi , I am currently in a task to generate an XML file for an srt text file containing timestamps and corresponding text. To generate an exe file which accepts file name input and outputs the relevant XML file to be used as part of an automated script. Is it Advisable to use Tinyxml for this? Is this a very simple task that can be done with minimal programming? Is this one of those things which are very basic to c++ programmers? reason i am asking this is I have recently made a shift into c++ programming after over 3 years of action script development. Edit: your comments regarding this are very much appreciated what's the easiest way to generate xml in c++?

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  • Do dconf use EXI binary XML?

    - by Hibou57
    A question came to my mind reading an answer to the question What are the differences between gconf and dconf?. In an reply to the above question, Oli said: Binary read access is far faster than parsing XML. However, there exist a W3C recommendation for binary XML, since 2010: Efficient XML Interchange (EXI) Format 1.0. Is this what dconf uses? If Yes, where is it confirmed? If No, was there some investigations toward it at some time, and what was the conclusions? Thanks for any tracks, I'm curious to know.

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  • How to Send Custom data in ADF/XML format

    - by Kaidul Islam Sazal
    I have built a lead generator form Here which will send email in ADF/XML format.But all I found in internet about ADF that there are limited tags like contact, customer, vendors, vehicle and their corresponding sub tags.I have to send these information via ADF/XML : Your Company Name App Name Description for iTunes and Google Keywords Image or logo for icon First splash page image Second splash page image About Company work schedule List up to 10 services your company provide Company Email Company Phone Company Website Company Facebook Company Youtube Company Twitter Company Google Comments My question is that, how I can send all this data in ADF/XML ? what will be tags for these ? What will be format? I didn't find any specific answers on it in internet.

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  • XML ou JSON? (pt-BR)

    - by srecosta
    Depende.Alguns de nós sentem a necessidade de escolher uma nova técnica / tecnologia em detrimento da que estava antes, como uma negação de identidade ou como se tudo que é novo viesse para substituir o que já existe. Chega a parecer, como foi dito num dos episódios de “This Developer’s Life”, que temos de esquecer algo para termos espaço para novos conteúdos. Que temos de abrir mão.Não é bem assim que as coisas funcionam. Eu vejo os colegas abraçando o ASP.NET MVC e condenando o ASP.NET WebForms como o anticristo. E tenho observado a mesma tendência com o uso do JSON para APIs ao invés de XML, como se o XML não servisse mais para nada. Já vi, inclusive, módulos sendo reescritos para trabalhar com JSON, só porque “JSON é melhor” ™.O post continua no meu blog: http://www.srecosta.com/2012/11/22/xml-ou-json/Grande abraço,Eduardo Costa

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  • Is there a very simple XML Editor/Viewer?

    - by Paul Spangle
    Part of our support job is to look at XML documents sent to our systems by our clients that have failed to load correctly. I do this by pasting the file in to Visual Studio as an XML file and VS colours it and adds line-breaks, indenting, etc. and it's then usually quite simple to spot the error and manually fix it and resubmit the document. Do I really have to use Visual Studio to do this? OK, it does the job quite well, but I'd have thought that something like Notepad++ would do the job just as well with a fraction of the machine resource usage. Is there are plugin for Notepad++ or another bit of freeware that can make XML look pretty and let me make simple edits?

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  • Tool to convert from XML to CSV and back to XML without losing information?

    - by Lanaru
    I would like to convert an XML file into CSV, and then be able to convert that CSV back into the original XML file. Is there a tool out there that makes this possible? The reason I want to do this is that I want to generate a ton of data to be stored in an xml file that my program will parse. I can easily generate a lot of data with a CSV file through the use of Excel macros, so that's why I'm looking for a tool to convert between these two formats. Any alternative suggestions are greatly appreciated.

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  • Writing use cases for XML mapping scenarios between two different systems

    - by deepak_prn
    I am having some trouble writing use cases for XML mapping after a certain trigger invoked by the system. For example, one of the scenarios goes: the store cashier sells an item, the transaction data is sent to Data management system. Now, I am writing a functional design for the scenario which deals with mapping XML fields between our system and the data management system. Question : I was wondering if some one had to deal with writing use cases or extension use cases for mapping XML fields between two systems? (There is no XSLT involved) and if you used a table to represent the fields mapping (example is below) or any other visualization tool which does not break the bank ? I searched many questions on SO and here but nothing came close to my requirement.

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  • Passing XML markers to Google Map

    - by djmadscribbler
    I've been creating a V3 Google map based on this example from Mike Williams http://www.geocodezip.com/v3_MW_example_map3.html I've run into a bit of a problem though. If I have no parameters in my URL then I get the error "id is undefined idmarkers [id.toLowerCase()] = marker;" in Firebug and only one marker will show up. If I have a parameter (?id=105 for example) then all the sidebar links say 105 (or whatever the parameter in the URL was) instead of their respective label as listed in the XML file and a random infowindow will be opened instead of the window for the id in the URL. Here is my javascript: var map = null; var lastmarker = null; // ========== Read paramaters that have been passed in ========== // Before we go looking for the passed parameters, set some defaults // in case there are no parameters var id; var index = -1; // these set the initial center, zoom and maptype for the map // if it is not specified in the query string var lat = 42.194741; var lng = -121.700301; var zoom = 18; var maptype = google.maps.MapTypeId.HYBRID; function MapTypeId2UrlValue(maptype) { var urlValue = 'm'; switch (maptype) { case google.maps.MapTypeId.HYBRID: urlValue = 'h'; break; case google.maps.MapTypeId.SATELLITE: urlValue = 'k'; break; case google.maps.MapTypeId.TERRAIN: urlValue = 't'; break; default: case google.maps.MapTypeId.ROADMAP: urlValue = 'm'; break; } return urlValue; } // If there are any parameters at eh end of the URL, they will be in location.search // looking something like "?marker=3" // skip the first character, we are not interested in the "?" var query = location.search.substring(1); // split the rest at each "&" character to give a list of "argname=value" pairs var pairs = query.split("&"); for (var i = 0; i < pairs.length; i++) { // break each pair at the first "=" to obtain the argname and value var pos = pairs[i].indexOf("="); var argname = pairs[i].substring(0, pos).toLowerCase(); var value = pairs[i].substring(pos + 1).toLowerCase(); // process each possible argname - use unescape() if theres any chance of spaces if (argname == "id") { id = unescape(value); } if (argname == "marker") { index = parseFloat(value); } if (argname == "lat") { lat = parseFloat(value); } if (argname == "lng") { lng = parseFloat(value); } if (argname == "zoom") { zoom = parseInt(value); } if (argname == "type") { // from the v3 documentation 8/24/2010 // HYBRID This map type displays a transparent layer of major streets on satellite images. // ROADMAP This map type displays a normal street map. // SATELLITE This map type displays satellite images. // TERRAIN This map type displays maps with physical features such as terrain and vegetation. if (value == "m") { maptype = google.maps.MapTypeId.ROADMAP; } if (value == "k") { maptype = google.maps.MapTypeId.SATELLITE; } if (value == "h") { maptype = google.maps.MapTypeId.HYBRID; } if (value == "t") { maptype = google.maps.MapTypeId.TERRAIN; } } } // this variable will collect the html which will eventually be placed in the side_bar var side_bar_html = ""; // arrays to hold copies of the markers and html used by the side_bar // because the function closure trick doesnt work there var gmarkers = []; var idmarkers = []; // global "map" variable var map = null; // A function to create the marker and set up the event window function function createMarker(point, icon, label, html) { var contentString = html; var marker = new google.maps.Marker({ position: point, map: map, title: label, icon: icon, zIndex: Math.round(point.lat() * -100000) << 5 }); marker.id = id; marker.index = gmarkers.length; google.maps.event.addListener(marker, 'click', function () { lastmarker = new Object; lastmarker.id = marker.id; lastmarker.index = marker.index; infowindow.setContent(contentString); infowindow.open(map, marker); }); // save the info we need to use later for the side_bar gmarkers.push(marker); idmarkers[id.toLowerCase()] = marker; // add a line to the side_bar html side_bar_html += '<a href="javascript:myclick(' + (gmarkers.length - 1) + ')">' + id + '<\/a><br>'; } // This function picks up the click and opens the corresponding info window function myclick(i) { google.maps.event.trigger(gmarkers[i], "click"); } function makeLink() { var mapinfo = "lat=" + map.getCenter().lat().toFixed(6) + "&lng=" + map.getCenter().lng().toFixed(6) + "&zoom=" + map.getZoom() + "&type=" + MapTypeId2UrlValue(map.getMapTypeId()); if (lastmarker) { var a = "/about/map/default.aspx?id=" + lastmarker.id + "&" + mapinfo; var b = "/about/map/default.aspx?marker=" + lastmarker.index + "&" + mapinfo; } else { var a = "/about/map/default.aspx?" + mapinfo; var b = a; } document.getElementById("idlink").innerHTML = '<a href="' + a + '" id=url target=_new>- Link directly to this page by id</a> (id in xml file also entry &quot;name&quot; in sidebar menu)'; document.getElementById("indexlink").innerHTML = '<a href="' + b + '" id=url target=_new>- Link directly to this page by index</a> (position in gmarkers array)'; } function initialize() { // create the map var myOptions = { zoom: zoom, center: new google.maps.LatLng(lat, lng), mapTypeId: maptype, mapTypeControlOptions: { style: google.maps.MapTypeControlStyle.DROPDOWN_MENU }, navigationControl: true, mapTypeId: google.maps.MapTypeId.HYBRID }; map = new google.maps.Map(document.getElementById("map_canvas"), myOptions); var stylesarray = [ { featureType: "poi", elementType: "labels", stylers: [ { visibility: "off" } ] }, { featureType: "landscape.man_made", elementType: "labels", stylers: [ { visibility: "off" } ] } ]; var options = map.setOptions({ styles: stylesarray }); // Make the link the first time when the page opens makeLink(); // Make the link again whenever the map changes google.maps.event.addListener(map, 'maptypeid_changed', makeLink); google.maps.event.addListener(map, 'center_changed', makeLink); google.maps.event.addListener(map, 'bounds_changed', makeLink); google.maps.event.addListener(map, 'zoom_changed', makeLink); google.maps.event.addListener(map, 'click', function () { lastmarker = null; makeLink(); infowindow.close(); }); // Read the data from example.xml downloadUrl("example.xml", function (doc) { var xmlDoc = xmlParse(doc); var markers = xmlDoc.documentElement.getElementsByTagName("marker"); for (var i = 0; i < markers.length; i++) { // obtain the attribues of each marker var lat = parseFloat(markers[i].getAttribute("lat")); var lng = parseFloat(markers[i].getAttribute("lng")); var point = new google.maps.LatLng(lat, lng); var html = markers[i].getAttribute("html"); var label = markers[i].getAttribute("label"); var icon = markers[i].getAttribute("icon"); // create the marker var marker = createMarker(point, icon, label, html); } // put the assembled side_bar_html contents into the side_bar div document.getElementById("side_bar").innerHTML = side_bar_html; // ========= If a parameter was passed, open the info window ========== if (id) { if (idmarkers[id]) { google.maps.event.trigger(idmarkers[id], "click"); } else { alert("id " + id + " does not match any marker"); } } if (index > -1) { if (index < gmarkers.length) { google.maps.event.trigger(gmarkers[index], "click"); } else { alert("marker " + index + " does not exist"); } } }); } var infowindow = new google.maps.InfoWindow( { size: new google.maps.Size(150, 50) }); google.maps.event.addDomListener(window, "load", initialize); And here is an example of my XML formatting <marker lat="42.196175" lng="-121.699224" html="This is the information about 104" iconimage="/about/map/images/104.png" label="104" />

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