Search Results

Search found 21427 results on 858 pages for 'enterprise search'.

Page 80/858 | < Previous Page | 76 77 78 79 80 81 82 83 84 85 86 87  | Next Page >

  • Why won't title attributes get indexed in Google?

    - by Sam
    When I search for Ride On + my site's name, I see that it's indexed. But when I search for Green Horse + my site's name, I don't see my site appearing in the results anywhere! Here's my code: <td><a href="#" title="Green Horse Ride">Ride On</a></td> Does this mean that title attributes are not indexed/shown by Google at all? What is better to use, alt? What are the other alternatives except title and alt?

    Read the article

  • Why my site not linking with google.com?

    - by nishant
    i am very tired about my website ranking in google. i am dong hard work about it but not getting anywhere my site in google. actually i am web master of a www.panbeli.in matrimony website INDIA. i am trying to improve its visibility in google last 5 month but not getting any positive result. but other search engine giving good result like yahoo and bing but google showing no any result in top 20 page result. my website is www.panbeli.in and my keyword are- bari samaj bari matrimony bari community bari shadi panbeli please help me if you can, b'coz i am very frustrated about it. my domain age is 4 years when i type link:panbeli.in in google search does not appear any pages from my site in google. whats the meaning is that?my site does not indexed in google?

    Read the article

  • Why google is not crawling my website

    - by Aman Virk
    I am running a design and development blog http://www.thetutlage.com/ . From last couple of days my search traffic have been reduced from 70% to 10%. I myself is against black hat seo and all it do is write my own unique content almost everyday. Last week my search traffic was really good but now is dropping like heck. I have checked my webmasters dashboard and no message there from google. When i checked server logs i came to know last time google crawled my website was on 27 september 2012. Really i have no idea what i am doing wrong. I follow all google guidelines like bible, please help me

    Read the article

  • How can I search an XML file without a dynamic language?

    - by jeph perro
    Let me try to explain my situation: We are using a CMS which 'bakes' a website, and you publish it to a webserver. The published site contains only static HTML ( or XML ) pages ( generated from the content in the CMS database ). I imported an XML file with the names and phone numbers from the company phone directory. Using only XSLT, can I create a way to search that directory? For example, if my XML file, directory.xml looks like this: <directory> <person> <fname>Ryan</fname> <lname>Purple</lname> <phone>887 778 5544</phone> </person> <person> <fname>Tanya</fname> <lname>Orange</lname> <phone>887 998 5541</phone> </person> <directory> Can I create a way to search for a person with the last name starting with "Pur" ? Can I pass a parameter to the XSLT? Can I search the XML tree to match the string in the parameter?

    Read the article

  • Is there a command-line utility app which can locate a specific block of lines in a text file?

    - by fred.bear
    The text "search and replace" utility programs I've seen, seem to only search on a line-by-line basis... Is there a command-line tool which can locate one block of lines (in a text file), and replace it with another block of lines.? For example: Does the test file file contain this exact group of lines: 'Twas brillig, and the slithy toves Did gyre and gimble in the wabe: All mimsy were the borogoves, And the mome raths outgrabe. 'Beware the Jabberwock, my son! The jaws that bite, the claws that catch! Beware the Jubjub bird, and shun The frumious Bandersnatch!' I want this, so that I can replace multiple lines of text in a file and know I'm not overwriting the wrong lines. I would never replace "The Jabberwocky" (Lewis Carroll), but it makes a novel example :)

    Read the article

  • How long does it take for Google Webmasters to index site after submitting sitemap? [closed]

    - by Venkatesh Hodavdekar
    Possible Duplicate: Why isn't my website in Google search results? I have submitted my website today into Google search using Google Webmasters using sitemaps. The status on the sitemap says OK and it shows that 12 urls have been recognized. I was wondering how long does it take for the link to get indexed, as the indexed url option says "No data available. Please check back soon." I am not sure if it is showing this message due to some error, or everything is fine.

    Read the article

  • Directing crawlers to content in language per language sub-domain

    - by Noam
    I have a site with multilingual website with many pages (40M). The site has UGC, and each translation is actually for the titles. Each sub-domain points to the same content with different titles per language. As far as I understand, each sub-domain should be indexed by search engines, meaning they will actually need to crawl 40M x supported-languages. So I thought it might be best to direct each subdomain crawler, to pages that are fully in that language (titles + UGC). Is there a way to do this? Should search engines understand this on their own?

    Read the article

  • SQLSaturday #60 - Cleveland Rocks!

    - by Mike C
    Looking forward to seeing all the DBAs, programmers and BI folks in Cleveland at SQLSaturday #60 tomorrow! I'll be presenting on (1) Intro to Spatial Data and (2) Build Your Own Search Engine in SQL. I've reworked the Spatial Data presentation based on feedback from previous SQLSaturday events and added more sample code. I also expanded the Build Your Own Search Engine code samples to demonstrate additional FILESTREAM functionality. See you all tomorrow! A little road music, please! http://www.youtube.com/watch?v=vU0JpyH1gC...(read more)

    Read the article

  • Can I make query strings produce separate pages?

    - by John Smith
    I have a profile page with a URL like so: localhost/profile.php/?username=Bob I was wondering, if I had a separate <title> which changed according to the username, would they produce separate pages in the google search results? How do I tell Google to only use the username string or does it search within the title? On a similar note, how would I create a separate page with the username like so: localhost/bob instead of a query string like facebook does. Do that make a new file for each user?

    Read the article

  • How does one implement storage/retrieval of smart-search/mailbox features?

    - by humble_coder
    Hi All, I have a question regarding implementation of smart-search features. For example, consider something like "smart mailboxes" in various email applications. Let's assume you have your data (emails) stored in a database and, depending on the field for which the query will be created, you present different options to the end user. At the moment let's assume the Subject, Verb, Object approach… For instance, say you have the following: SUBJECTs: message, to_address, from_address, subject, date_received VERBs: contains, does_not_contain, is_equal_to, greater_than, less_than OBJECTs: ??????? Now, in case it isn't clear, I want a table structure (although I'm not opposed to an external XMLesque file of some sort) to store (and later retrieve/present) my criteria for smart searches/mailboxes for later use. As an example, using SVO I could easily store then reconstruct a query for "date between two dates" -- simply use "date greater than" AND "date less than". However, what if, in the same smart search, I wanted a "between" OR'ed with another criterion? You can see that it might get out of hand -- not necessarily in the query creation (as that is rather simplistic), but in the option presentation and storage mechanism. Perhaps I need to think more on a more granular level. Perhaps I need to simply allow the user to select AND or OR for each entry independently instead of making it an ALL OR NOTHING type smart search (i.e. instead of MATCH ALL or MATCH ANY, I need to simply allow them to select -- I just don't want it to turn into a Hydra). Any input would be most appreciated. My apologies if the question is a bit incoherent. It is late, and I my brain is toast. Best.

    Read the article

  • PG::Error: ERROR: operator does not exist: integer ~~ unknown

    - by rsvmrk
    I'm making a search-function in a Rails project with Postgres as db. Here's my code def self.search(search) if search find(:all, :conditions => ["LOWER(name) LIKE LOWER(?) OR LOWER(city) LIKE LOWER(?) OR LOWER(address) LIKE LOWER(?) OR (venue_type) LIKE (?)", "%#{search}%", "%#{search}%", "%#{search}%", "%#{search}%"]) else find(:all) end end But my problem is that "venue_type" is an integer. I've made a case switch for venue_type def venue_type_check case self.venue_type when 1 "Pub" when 2 "Nattklubb" end end Now to my question: How can I find something in my query when venue_type is an int?

    Read the article

  • SQLSaturday #60 - Cleveland Rocks!

    - by Mike C
    Looking forward to seeing all the DBAs, programmers and BI folks in Cleveland at SQLSaturday #60 tomorrow! I'll be presenting on (1) Intro to Spatial Data and (2) Build Your Own Search Engine in SQL. I've reworked the Spatial Data presentation based on feedback from previous SQLSaturday events and added more sample code. I also expanded the Build Your Own Search Engine code samples to demonstrate additional FILESTREAM functionality. See you all tomorrow! A little road music, please! http://www.youtube.com/watch?v=vU0JpyH1gC...(read more)

    Read the article

  • Is there a word or description for this type of query?

    - by Nick
    We have the requirement to find a result in a collection of records based on a prioritised set of search criteria against a relational db (I'm talking indexed field matching here rather than text search). The way we are thinking about designing the query is to begin with a highly refined and specific set of criteria. If there are no results for this initial query we want to progressively reduce the criteria one by one in order of reducing priority, querying each time such a less specific set of criteria until we find a result we can accept. Alternatively, we have considered starting with a smaller set of criteria and increasing until we have reduced number of results down to the last set. What I would like to know is if an existing term to describe this type of query exists? So that we can look to model our own on existing patterns and use best practice.

    Read the article

  • MySQL searching using many 'like' operators: is there a better way?

    - by DrAgonmoray
    I have a page that gets all rows from a table in a database, then displays the rows in an HTML table. That works great, but now I want to implement a 'search' feature. There is a searchbox, and search-terms are separated by a space. I am going to make it search three fields for the search terms, 'make' 'model' and 'type.' These three fields are VARCHAR(30). Currently if I wanted to search using 3 terms (say 'cool' 'abc' and '123') my query would look something like this. SELECT * FROM table WHERE make LIKE '%cool%' OR make LIKE '%abc%' OR make LIKE '%123%' OR model LIKE '%cool%' OR model LIKE '%abc%' OR model LIKE '%123%' OR type LIKE '%cool%' OR type LIKE '%abc%' OR type LIKE '%123%' That looks really bad, and it will get even worse if there are more search terms or more fields to search. My question to you: is there a better way to search? If so, what?

    Read the article

  • Address Book Authentication

    - by Gus E
    I just upgraded to Ubuntu 14.04.1 and run Gnome Shell. I am consistently getting a pop up window prompting me for my Gmail address book authentication. The window pops up the moment I type something into gnome shell after hitting the super key. I'm assuming that Ubuntu wants to search my address book for people to include in the search. I have opened up the settings and deleted my account from the online accounts section and rebooted, nothing seems to stop the popup. Where is it getting my email address from? Most importantly, how to I stop this super annoying popup from appearing?

    Read the article

  • Writing a spell checker similar to "did you mean"

    - by user888734
    I'm hoping to write a spellchecker for search queries in a web application - not unlike Google's "Did you mean?" The algorithm will be loosely based on this: http://catalog.ldc.upenn.edu/LDC2006T13 In short, it generates correction candidates and scores them on how often they appear (along with adjacent words in the search query) in an enormous dataset of known n-grams - Google Web 1T - which contains well over 1 billion 5-grams. I'm not using the Web 1T dataset, but building my n-gram sets from my own documents - about 200k docs, and I'm estimating tens or hundreds of millions of n-grams will be generated. This kind of process is pushing the limits of my understanding of basic computing performance - can I simply load my n-grams into memory in a hashtable or dictionary when the app starts? Is the only limiting factor the amount of memory on the machine? Or am I barking up the wrong tree? Perhaps putting all my n-grams in a graph database with some sort of tree query optimisation? Could that ever be fast enough?

    Read the article

  • What factors help in getting a site indexed by Google fast?

    - by ekaj
    What should I do to get a site indexed on Google, fast? Taking example of Super User I just did a quick Google for a question that was 20 minutes old, to look for an answer, and it was already on Google Search - how is this possible? I glanced over this article which seems to suggest that SU has added RSS feeds (which SU has, but when I opened the feed the article says last posted 6 minutes ago, but when Googled it is 11 hours old) - which leads me to think (Based on that article, I don't know much about search indexing but I am reading at the moment) that most of this indexing is done thanks to the sitemap. is there anything else I am unaware of that helps SU questions get on Google so fast?

    Read the article

  • How can I make my Google Maps api v3 address search bar work by hitting the enter button on the keyboard?

    - by Gavin
    I'm developing a webpage and I would just like to make something more user friendly. I have a functional Google Maps api v3 and an address search bar. Currently, I have to use the mouse to select search to initialize the geocoding function. How can I make the map return a placemark by hitting the enter button on my keyboard? I just want to make it as user-friendly as possible. Here is the javascript and div, respectively, I created for the address bar: var geocoder; function initialize() { geocoder = new google.maps.Geocoder (); function codeAddress () { var address = document.getElementById ("address").value; geocoder.geocode ( { 'address': address}, function(results, status) { if (status == google.maps.GeocoderStatus.OK) { map.setCenter(results [0].geometry.location); marker.setPosition(results [0].geometry.location); map.setZoom(14); } else { alert("Geocode was not successful for the following reason: " + status); } }); } <div id="geocoder"> <input id="address" type="textbox" value=""> <input type="button" value="Search" onclick="codeAddress()"> </div> Thank you in advance for your help

    Read the article

  • How to find the insertion point in an array using binary search?

    - by ????
    The basic idea of binary search in an array is simple, but it might return an "approximate" index if the search fails to find the exact item. (we might sometimes get back an index for which the value is larger or smaller than the searched value). For looking for the exact insertion point, it seems that after we got the approximate location, we might need to "scan" to left or right for the exact insertion location, so that, say, in Ruby, we can do arr.insert(exact_index, value) I have the following solution, but the handling for the part when begin_index >= end_index is a bit messy. I wonder if a more elegant solution can be used? (this solution doesn't care to scan for multiple matches if an exact match is found, so the index returned for an exact match may point to any index that correspond to the value... but I think if they are all integers, we can always search for a - 1 after we know an exact match is found, to find the left boundary, or search for a + 1 for the right boundary.) My solution: DEBUGGING = true def binary_search_helper(arr, a, begin_index, end_index) middle_index = (begin_index + end_index) / 2 puts "a = #{a}, arr[middle_index] = #{arr[middle_index]}, " + "begin_index = #{begin_index}, end_index = #{end_index}, " + "middle_index = #{middle_index}" if DEBUGGING if arr[middle_index] == a return middle_index elsif begin_index >= end_index index = [begin_index, end_index].min return index if a < arr[index] && index >= 0 #careful because -1 means end of array index = [begin_index, end_index].max return index if a < arr[index] && index >= 0 return index + 1 elsif a > arr[middle_index] return binary_search_helper(arr, a, middle_index + 1, end_index) else return binary_search_helper(arr, a, begin_index, middle_index - 1) end end # for [1,3,5,7,9], searching for 6 will return index for 7 for insertion # if exact match is found, then return that index def binary_search(arr, a) puts "\nSearching for #{a} in #{arr}" if DEBUGGING return 0 if arr.empty? result = binary_search_helper(arr, a, 0, arr.length - 1) puts "the result is #{result}, the index for value #{arr[result].inspect}" if DEBUGGING return result end arr = [1,3,5,7,9] b = 6 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = 6 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [] b = 60 arr.insert(binary_search(arr, b), b) p arr and result: Searching for 6 in [1, 3, 5, 7, 9] a = 6, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = 6, arr[middle_index] = 7, begin_index = 3, end_index = 4, middle_index = 3 a = 6, arr[middle_index] = 5, begin_index = 3, end_index = 2, middle_index = 2 the result is 3, the index for value 7 [1, 3, 5, 6, 7, 9] Searching for 6 in [1, 3, 5, 7, 9, 11] a = 6, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = 6, arr[middle_index] = 9, begin_index = 3, end_index = 5, middle_index = 4 a = 6, arr[middle_index] = 7, begin_index = 3, end_index = 3, middle_index = 3 the result is 3, the index for value 7 [1, 3, 5, 6, 7, 9, 11] Searching for 60 in [1, 3, 5, 7, 9] a = 60, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = 60, arr[middle_index] = 7, begin_index = 3, end_index = 4, middle_index = 3 a = 60, arr[middle_index] = 9, begin_index = 4, end_index = 4, middle_index = 4 the result is 5, the index for value nil [1, 3, 5, 7, 9, 60] Searching for 60 in [1, 3, 5, 7, 9, 11] a = 60, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = 60, arr[middle_index] = 9, begin_index = 3, end_index = 5, middle_index = 4 a = 60, arr[middle_index] = 11, begin_index = 5, end_index = 5, middle_index = 5 the result is 6, the index for value nil [1, 3, 5, 7, 9, 11, 60] Searching for -60 in [1, 3, 5, 7, 9] a = -60, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 1, middle_index = 0 a = -60, arr[middle_index] = 9, begin_index = 0, end_index = -1, middle_index = -1 the result is 0, the index for value 1 [-60, 1, 3, 5, 7, 9] Searching for -60 in [1, 3, 5, 7, 9, 11] a = -60, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 1, middle_index = 0 a = -60, arr[middle_index] = 11, begin_index = 0, end_index = -1, middle_index = -1 the result is 0, the index for value 1 [-60, 1, 3, 5, 7, 9, 11] Searching for -60 in [1] a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 0, middle_index = 0 the result is 0, the index for value 1 [-60, 1] Searching for 60 in [1] a = 60, arr[middle_index] = 1, begin_index = 0, end_index = 0, middle_index = 0 the result is 1, the index for value nil [1, 60] Searching for 60 in [] [60]

    Read the article

  • Mysql optimization question - How to apply AND logic in search and limit on results in one query?

    - by sandeepan-nath
    This is a little long but I have provided all the database structures and queries so that you can run it immediately and help me. Run the following queries:- CREATE TABLE IF NOT EXISTS `Tutor_Details` ( `id_tutor` int(10) NOT NULL auto_increment, `firstname` varchar(100) NOT NULL default '', `surname` varchar(155) NOT NULL default '', PRIMARY KEY (`id_tutor`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=41 ; INSERT INTO `Tutor_Details` (`id_tutor`,`firstname`, `surname`) VALUES (1, 'Sandeepan', 'Nath'), (2, 'Bob', 'Cratchit'); CREATE TABLE IF NOT EXISTS `Classes` ( `id_class` int(10) unsigned NOT NULL auto_increment, `id_tutor` int(10) unsigned NOT NULL default '0', `class_name` varchar(255) default NULL, PRIMARY KEY (`id_class`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=229 ; INSERT INTO `Classes` (`id_class`,`class_name`, `id_tutor`) VALUES (1, 'My Class', 1), (2, 'Sandeepan Class', 2); CREATE TABLE IF NOT EXISTS `Tags` ( `id_tag` int(10) unsigned NOT NULL auto_increment, `tag` varchar(255) default NULL, PRIMARY KEY (`id_tag`), UNIQUE KEY `tag` (`tag`), KEY `id_tag` (`id_tag`), KEY `tag_2` (`tag`), KEY `tag_3` (`tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=18 ; INSERT INTO `Tags` (`id_tag`, `tag`) VALUES (1, 'Bob'), (6, 'Class'), (2, 'Cratchit'), (4, 'Nath'), (3, 'Sandeepan'), (5, 'My'); CREATE TABLE IF NOT EXISTS `Tutors_Tag_Relations` ( `id_tag` int(10) unsigned NOT NULL default '0', `id_tutor` int(10) default NULL, KEY `Tutors_Tag_Relations` (`id_tag`), KEY `id_tutor` (`id_tutor`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `Tutors_Tag_Relations` (`id_tag`, `id_tutor`) VALUES (3, 1), (4, 1), (1, 2), (2, 2); CREATE TABLE IF NOT EXISTS `Class_Tag_Relations` ( `id_tag` int(10) unsigned NOT NULL default '0', `id_class` int(10) default NULL, `id_tutor` int(10) NOT NULL, KEY `Class_Tag_Relations` (`id_tag`), KEY `id_class` (`id_class`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `Class_Tag_Relations` (`id_tag`, `id_class`, `id_tutor`) VALUES (5, 1, 1), (6, 1, 1), (3, 2, 2), (6, 2, 2); Following is about the tables:- There are tutors who create classes. Tutor_Details - Stores tutors Classes - Stores classes created by tutors And for searching we are using a tags based approach. All the keywords are stored in tags table (while classes/tutors are created) and tag relations are entered in Tutor_Tag_Relations and Class_Tag_Relations tables (for tutors and classes respectively)like this:- Tags - id_tag tag (this is a a unique field) Tutors_Tag_Relations - Stores tag relations while the tutors are created. Class_Tag_Relations - Stores tag relations while any tutor creates a class In the present data in database, tutor "Sandeepan Nath" has has created class "My Class" and "Bob Cratchit" has created "Sandeepan Class". 3.Requirement The requirement is to return tutor records from Tutor_Details table such that all the search terms (AND logic) are present in the union of these two sets - 1. Tutor_Details table 2. classes created by a tutor in Classes table) Example search and expected results:- Search Term Result "Sandeepan Class" Tutor Sandeepan Nath's record from Tutor Details table "Class" Both the tutors from ... Most importantly, there should be only one mysql query and a LIMIT applicable on the number of results. Following is a working query which I have so far written (It just applies OR logic of search key words instead of the desired AND logic). SELECT td . * FROM Tutor_Details AS td LEFT JOIN Tutors_Tag_Relations AS ttagrels ON td.id_tutor = ttagrels.id_tutor LEFT JOIN Classes AS wc ON td.id_tutor = wc.id_tutor INNER JOIN Class_Tag_Relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN Tags AS t ON t.id_tag = ttagrels.id_tag OR t.id_tag = wtagrels.id_tag WHERE t.tag LIKE '%Sandeepan%' OR t.tag LIKE '%Nath%' GROUP BY td.id_tutor LIMIT 20 Please help me with anything you can. Thanks

    Read the article

  • Search files blazing fast

    If you know there is a file somewhere on your machine, but you cannot find it with the default Windows Search Tools (that why they tend to call it Windows Search and not Windows Find ) then switch to a tool that really works. Go to http://www.voidtools.com/ to download your copy of Everything. The download is only small (350KB), it indexes fast (within 5 mins) and searches my complete computer even faster then I can type. I only blame David Carpenter for not spreading the word more aggressively and for not developing this earlier.

    Read the article

< Previous Page | 76 77 78 79 80 81 82 83 84 85 86 87  | Next Page >