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  • Apache rewrite URL replace characters

    - by Tim Cooper
    It's been a while since I've done anything with mod_write, so I was hoping I could help some help on this. I would like a URL like this: http://example.com/qwerty/xyz/ to be directed to querty.xyz.php, where the number of slashes and alpha characters between the slashes is not explicitly set.

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  • Apache Rewrite - put parts of query string in replacement string

    - by Rangi Robinson
    Hello, I'd like to rewrite: www.example.com/file.html?username=john&number=1234 To: www.example.com/users/john But I can't figure out how to extract the "username" value from the query string. I've been Googling this all morning and reading the official docs but no luck. I need to solve this problem with a rewrite, rather than changing the application. Any help much appreciated! Rangi

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  • Clean URLs mod_rewrite & wildcard subdomains

    - by Søren Zet
    I got this url http://domain.com/blogs/directory-param with this rule RewriteBase /blogs/directory/ RewriteRule ^/blogs/directory-([A-Za-z0-9-]+)$ /blogs/directory/index.php?cat=$1 [L] so I get /blogs/directory/index.php?cat=param now my problem is the following: I use wildcards subdomains so every *.domain.com is mapped to domain.com/blogs/ for example soeren.domain.com is mapped to domain.com/blogs and so on... My problem now is I want a rule for soeren.domain.com/directory-param which points to domain.com/blogs/directory?index.php?cat=param Do you have any ideas?

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  • Rewrite only external requests to a certain URL

    - by Cyclone
    I want to rewrite from http://example.com/blah/<something>/<somethingelse> to http://<something>.example.com/<somethingelse>, but only if the request is not an internal redirect. How can I achieve this effect? I know I can use %{THE_REQUEST}, but I can't seem to find any good examples. Thanks for the help!

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  • url rewriting index.php

    - by bean
    i have urls like http://mysite.com/index.php?p=resources http://mysite.com/index.php?p=resources&s=view&id=938 but i want urls like http://mysite.com/resources http://mysite.com/resources/view/938 instead of making hundreds of rewrite rules i wonder if it would be possible to just have one? Ive head this is possible by "getting the uri and splitting it into parts" and then just add a rewrite rule for index.php but how? could someone give an example or link a tutorial

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  • Mod_rewrite shortening url .htaccess

    - by Peter
    is there any way to hide redirected url, here is what I think: RewriteEngine On RewriteCond %{REQUEST_FILENAME} -f RewriteRule ^(.*)$ http://minteddomain.com/mint/pepper/tillkruess/downloads/tracker.php?url=http://%{HTTP_HOST}%{REQUEST_URI}&force So the long redirected url http://minteddomain.com/mint/pepper/tillkruess/downloads/tracker.php?url=http://%{HTTP_HOST}%{REQUEST_URI} to something shorter like /mintedomain.com/track/ It is possible? Adrian edit: Andrew: This is a stats software Mint (haveamint.com) with File Download tracker plugin. The File Download tracker works in this way: in .htaccess every file (zip, rar, txt,...) is redirected to the tracker.php file (because the stats): http://mydomain.com/mint/pepper/tillkruess/downloads/tracker.php?url=http://%{HTTP_HOST}%{REQUEST_URI} So the redirected url look like this for a zip file: http://minteddomain.com/mint/pepper/tillkruess/downloads/tracker.php?url=http://mydomain/downloads/apple.zip This redirected URL is very long and ugly. The best for me would be to redirect this redirected URL to something shorter URL: example: http://mydomain.com/track/downloads/apple.zip.. So the http://mydomain.com/track would be the http://minteddomain.com/mint/pepper/tillkruess/downloads/tracker.php

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  • django+mod_wsgi on virtualenv not working

    - by jwesonga
    I've just finished setting up a django app on virtualenv, deployment went smoothly using a fabric script, but now the .wsgi is not working, I've tried every variation on the internet but no luck. My .wsgi file is: import os import sys import django.core.handlers.wsgi # put the Django project on sys.path root_path = os.path.abspath(os.path.dirname(__file__) + '../') sys.path.insert(0, os.path.join(root_path, 'kcdf')) sys.path.insert(0, root_path) os.environ['DJANGO_SETTINGS_MODULE'] = 'kcdf.settings' application = django.core.handlers.wsgi.WSGIHandler() I keep getting the same error: [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] mod_wsgi (pid=16938): Exception occurred processing WSGI script '/home/kcdfweb/webapps/kcdf.web/releases/current/kcdf/apache/kcdf.wsgi'. [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] Traceback (most recent call last): [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/wsgi.py", line 230, in __call__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self.load_middleware() [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py", line 33, in load_middleware [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] for middleware_path in settings.MIDDLEWARE_CLASSES: [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/utils/functional.py", line 269, in __getattr__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self._setup() [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 40, in _setup [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] self._wrapped = Settings(settings_module) [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 75, in __init__ [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] raise ImportError, "Could not import settings '%s' (Is it on sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE, e) [Sun Apr 18 12:44:30 2010] [error] [client 41.215.123.159] ImportError: Could not import settings 'kcdf.settings' (Is it on sys.path? Does it have syntax errors?): No module named kcdf.settings my virtual environment is on /home/user/webapps/kcdfweb my app is /home/user/webapps/kcdf.web/releases/current/project_name my wsgi file home/user/webapps/kcdf.web/releases/current/project_name/apache/project_name.wsgi

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  • Rewrite Query String

    - by Virgil
    Hello, I am trying to write some mod_rewrite rules to generate thumbnails on the fly. So when this url example.com/media/myphoto.jpg?width=100&height=100 the script should rewrite it to example.com/media/myphoto-100x100.jpg and if the file exists on the disk it gets served by Apache and if it doesn't exist it is called a script to generate the file. I wrote this RewriteCond %{QUERY_STRING} ^width=(\d+)&height=(\d+) RewriteRule ^media/([a-zA-Z0-9_\-]+)\.([a-zA-Z0-9]+)$ media/$1-%1x%2.$2 [L] RewriteCond %{QUERY_STRING} ^(.+)? RewriteRule ^media/([a-zA-Z0-9_\-\._]+)$ media/index.php?file=$1&%1 [L] and I get infinite internal redirects. The first condition is matched and the rule is executed and right after that I get an internal redirect. I need advice to finish this script. Thank you.

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  • Apache rewrite with many slash not working?

    - by Daok
    I have modified a website with a redirection to a single page: RewriteCond %{REQUEST_FILENAME} -s [OR] RewriteCond %{REQUEST_FILENAME} -l [OR] RewriteCond %{REQUEST_FILENAME} -d RewriteRule ^.*$ - [NC,L] RewriteRule ^.*$ index.php [NC,L] It works as it suppose to be. Everything is redirected to index.php. Here is a working example that display index.php with all images and css: http://.....com/section1 The problem occur when I try : http://....com/section1/subsection The page is redirected to index.php, BUT no images, no css, no javascript. Inside the PHP script everything is like this directly linked to the images or css or javascript like: <img src="images/images1.png> ... <img src="images2.png"> Why does url with many slash like .com../123/123/whatever does not work with images, css or javascript when .com/no_slash_url works?

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  • django setup with Apache, mod_wsgi and cx_Oracle

    - by pablo
    Hi, I need to setup the same django project on several identical servers. Details: - os - free edition of oracle enterprise linux 5 - Apache / mod_wsgi - python - custom python2.6 installation - oracle db with cx_Oracle What is the simplest way to set it up? Would you recommend creating a system user for the django project and use daemon mode? What type of user and what privileges does it need? Can I set ORACLE_HOME, LD_LIBRARY_PATH, PATH=$ORACLE_HOME/bin:$PATH for this user? Would you use a virtualenv for cx_Oracle? Can I somehow put the python2.6 inside the virtualenv so it will portable to other servers? Thanks

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  • Django: TypeError: 'str' object is not callable, referer: http://xxx

    - by user705415
    I've been wondering why when I set the settings.py of my django project 'arvindemo' debug = Flase and deploy it on Apache with mod_wsgi, I got the 500 Internal Server Error. Env: Django 1.4.0 Python 2.7.2 mod_wsgi 2.8 OS centOS Here is the recap: Visit the homepage, go to sub page A/B/C/D, and fill some forms, then submit it to the Apache server. Once click 'submit' button, I will get the '500 Internal Server Error', and the error_log listed below(Traceback): [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] Traceback (most recent call last): [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/handlers/wsgi.py", line 241, in __call__ [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] response = self.get_response(request) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/handlers/base.py", line 179, in get_response [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] response = self.handle_uncaught_exception(request, resolver, sys.exc_info()) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/handlers/base.py", line 224, in handle_uncaught_exception [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] if resolver.urlconf_module is None: [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/urlresolvers.py", line 323, in urlconf_module [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] self._urlconf_module = import_module(self.urlconf_name) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] __import__(name) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/web/django/arvindemo/arvindemo/../arvindemo/urls.py", line 23, in <module> [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] url(r'^submitPage$', name=submitPage), [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] TypeError: url() takes at least 2 arguments (2 given) When using django runserver, I set arvindemo.settings debug = True, everything is OK. But things changed once I set debug = Flase. Here is my views.py from django.http import HttpResponseRedirect from django.http import HttpResponse, HttpResponseServerError from django.shortcuts import render_to_response import datetime, string from user_info.models import * from django.template import Context, loader, RequestContext import settings def hello(request): return HttpResponse("hello girl") def helpPage(request): return render_to_response('kktHelp.html') def server_error(request, template_name='500.html'): return render_to_response(template_name, context_instance = RequestContext(request) ) def page404(request): return render_to_response('404.html') def submitPage(request): post = request.POST Mall = 'goodsName' Contest = 'ojs' Presentation = 'addr' WeatherReport = 'city' Habit = 'task' if Mall in post: return submitMall(request) elif Contest in post: return submitContest(request) elif Presentation in post: return submitPresentation(request) elif Habit in post: return submitHabit(request) elif WeatherReport in post: return submitWeather(request) else: return HttpResponse(request.POST) return HttpResponseRedirect('404') def submitXXX(): ..... def xxxx(): .... Here comes the urls.py from django.conf.urls import patterns, include, url from views import * from django.conf import settings handler500 = 'server_error' urlpatterns = patterns('', url(r'^hello/$', hello), # hello world url(r'^$', homePage), url(r'^time/$', getTime), url(r'^time/plus/(\d{1,2})/$', hoursAhead), url(r'^Ttime/$', templateGetTime), url(r'^Mall$', templateMall), url(r'^Contest$', templateContest), url(r'^Presentation$', templatePresentation), url(r'^Habit$', templateHabit), url(r'^Weather$', templateWeather), url(r'^Help$', helpPage), url(r'^404$', page404), url(r'^500$', server_error), url(r'^submitPage$', submitPage), url(r'^submitMall$', submitMall), url(r'^submitContest$', submitContest), url(r'^submitPresentation$', submitPresentation), url(r'^submitHabit$', submitHabit), url(r'^submitWeather$', submitWeather), url(r'^terms$', terms), url(r'^privacy$', privacy), url(r'^thanks$', thanks), url(r'^about$', about), url(r'^static/(?P<path>.*)$','django.views.static.serve',{'document_root':settings.STATICFILES_DIRS}), ) I'm sure there is no syntax error in my django project,cause when I use django runserver, everything is fine. Anyone can help ? Best regards

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  • mod_rewrite infinite loop problem

    - by ninuhadida
    Hi guys, I've been trying to do the following with mod_rewrite on the server there is a file about.htm (which is found in the root directory of the domain) I need to redirect about.htm to about/ On the server still keep about.htm, hence when about/ is called, it actually loads up about.htm I tried something like this: RewriteRule ^about/$ about.htm [L] RewriteRule ^about\.htm$ about/ [R=302] I also tried changing it a bit and see what happends, but I always end up with an infinite loop of redirection or a 500 server error. Any idea why it's not working as intended? Thanks in advance!

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  • Apache - "dynamic" rewrite rule

    - by Christian A. Rasmussen
    Hi there. I'm working on a Zend Framework project where I've stumbled across a bit of a problem. The problem originates from the fact that modules are 2nd class citizens in Zend Framework. In my project, I'd like for each module to have a folder containing files which are to be accessed from the outside - files such as stylesheets, javascripts and images. Now, how is this to be done. With a Zend Framework project I have a folder structure which looks like this: application/ modules/ moduleOne/ public/ stylesheet.css moduleTwo/ moduleThree/ public/ index.php The standard .htaccess file located in the public/ folder holds this: SetEnv APPLICATION_ENV development RewriteEngine On RewriteCond %{REQUEST_FILENAME} -s [OR] RewriteCond %{REQUEST_FILENAME} -l [OR] RewriteCond %{REQUEST_FILENAME} -d RewriteRule ^.*$ - [NC,L] RewriteRule ^.*$ index.php [NC,L] The way it works, is that the project's apache DocumentRoot is the public/ folder. All requests gets redirected through the index.php file where Zend Framework's router component takes over. Now, I'm by no means an expert with Apache nor mod_rewrite so pardon me if this is just silly. I imagine that I implement an extra step in the existing rewrite rule so that if I request http://project/public/moduleOne/stylesheet.css it will for instance resolve to /var/www/project/application/modules/moduleOne/public/stylesheet.css. So the steps which need to be done is to check if the first element in the URI is public/ if it is, we take the next segment as the modules name and use that in the path we're trying to resolve to and attempt to serve the file. Is this at all possible or does anyone have a better suggestion? Thank you for your time Christian Rasmussen

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  • How to disable mod_security2 rule (false positive) for one domain on centos 5

    - by nicholas.alipaz
    Hi I have mod_security enabled on a centos5 server and one of the rules is keeping a user from posting some text on a form. The text is legitimate but it has the words 'create' and an html <table> tag later in it so it is causing a false positive. The error I am receiving is below: [Sun Apr 25 20:36:53 2010] [error] [client 76.171.171.xxx] ModSecurity: Access denied with code 500 (phase 2). Pattern match "((alter|create|drop)[[:space:]]+(column|database|procedure|table)|delete[[:space:]]+from|update.+set.+=)" at ARGS:body. [file "/usr/local/apache/conf/modsec2.user.conf"] [line "352"] [id "300015"] [rev "1"] [msg "Generic SQL injection protection"] [severity "CRITICAL"] [hostname "www.mysite.com"] [uri "/node/181/edit"] [unique_id "@TaVDEWnlusAABQv9@oAAAAD"] and here is /usr/local/apache/conf/modsec2.user.conf (line 352) #Generic SQL sigs SecRule ARGS "((alter|create|drop)[[:space:]]+(column|database|procedure|table)|delete[[:space:]]+from|update.+set.+=)" "id:1,rev:1,severity:2,msg:'Generic SQL injection protection'" The questions I have are: What should I do to "whitelist" or allow this rule to get through? What file do I create and where? How should I alter this rule? Can I set it to only be allowed for the one domain, since it is the only one having the issue on this dedicated server or is there a better way to exclude table tags perhaps? Thanks guys

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  • CodeIgniter - How to hide index.php from the URL

    - by kapil.israni
    This is what my .htaccess looks like. The .htaccess is sitting in /www/scripts directory which is the parent of codeigniter's "system" directory and which also contains index.php. I have enabled mod_rewrite in my Apache 2.2.x. This is on Ubuntu 9.10 server. I followed this link, but it does not work. Is there anything i need to do in apache2, any specific configuration so that this works?? RewriteEngine on RewriteBase / RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php/$1 [QSA,L]

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  • stumped by WSGI module import errors

    - by rguha
    Hi, I'm writing a bare bones Python wsgi application and am getting stumped by module import errors. I have a .py file in the current directory which initially failed to import. By adding sys.path.insert(0, '/Users/guhar/Sites/acom') the import of the module worked. But I now try and import a module that I had installed via easy_install and it fails to import. I tried setting sys.path.insert(0, '/Library/Python/2.5/site-packages/') which contains the egg file, but to no avail. I would've thought that all packages under "/Library/Python/2.5/site-packages/" would be available to a WSGI application. Does anybody have any pointers?

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  • Checking if file exist with RewriteCond in a chained RewriteRule

    - by gelilloabad
    Hello, I hope you could help me here. I have a RewriteRule which gives you a crossdomain.xml file depending on the domain name. I have it in a way that ignores the ".dev." string in the middle, example: Request: http://site1.dev.mydomain.com/crossdomain.xml Returns file: /etc/httpd/conf/crossdomain/site.mydomain.com.xml RewriteCond %{HTTP_HOST} "^(.*)\.dev\.(.*)" RewriteCond %{REQUEST_URI} "/crossdomain.xml" enter code hereRewriteRule ^(.+) %{HTTP_HOST}$1 [C] RewriteRule ^(.*)\.dev\.([^/]*)/crossdomain.xml /etc/httpd/conf/crossdomain/$1.$2.xml [L] Question: How do I check if the file exists? I tried adding this on top but it doesn't work: RewriteCond /etc/httpd/conf/crossdomain/$1.$2.xml -f I guess because it is a chained rule, no idea. Please help.

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  • mod_rewrite regex help

    - by Bathan
    HI guys. Im using mod_rewrite to do some redirects on a web site. I want to be able to do the following mySite.com/ - Goto Home mySite.com/foo - Goto redirect.php and redirect acordingly. My redirect rule was RewriteRule (^\w*$) redirect.php?url=$1 [NC] But im oviously missing something because when I go tomySite.com/ I get sent to redirect.php I need a regex that allow lower and upper case letters, as well as underscores but it has to ignore "empty" strings so when I go to mySite.com/ the index file is displayed. Any help? Thanks!

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  • Simple mod_rewrite rule.....?

    - by eberswine
    Hello. I have a edit page that looks at record_id's in the url.. I don't want the user to see any record id, that way they can't replace it with another and edit another record.... Anyways, my url is like: http://www.mywebsite.com/folder/folder_detail_edit.php?recordID=3980 I would like it to just display: http://www.mywebsite.com/folder/folder_detail_edit.php Is this possible regardless of the recordID???

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  • URL rewrite with ?lang= parameter

    - by agorom7
    my developer is saying that it is not possible to rewrite url form example.com/name/name/?lang=english to example.com/en/name/name/ is it possible to do or not? if yes, how should it be done? if not, what could be the reasons? we have windows based hosting from maddogdomains (godaddy)

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  • Apache rewrite to add a directory to REQUEST_URI not working on localhost running wamp.

    - by Brett Pontarelli
    I'm running wamp on Vista (Apache v2.2.11) and have projects setup such that http://localhost/projectx is the base directory for projectx. Now, I want that requests for http://localhost/projectx/somepage/extra will rewrite to http://localhost/projectx/PUBLIC/somepage/extra To that end I have a file in C:\wamp\www\projectx\.htacces that is this simple: RewriteEngine On RewriteBase /projectx RewriteCond %{REQUEST_URI} !^/PUBLIC RewriteRule ^(.*)$ /PUBLIC$1 [L] I can't for the life of me figure out why this doesn't work. The error I'm getting is "The requested URL /PUBLIC was not found on this server". Thanks.

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  • rewrite rule to switch to subfolder

    - by Midday
    I'm deploying a Wordpress blog, but I don't want to overwrite the current site yet. public_html/. <-- the current site public_html/wp/. <-- the new site How must my .htaccess look like so I can seamlessly switch from the current site to the new one so that http://domain.tld shows the new site like it would be directly in the public_html folder

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  • How can I do a clean Mod_Rewrite that hides the variable numbers passed in the query string but just

    - by Jay Bee
    Hi, I have been developing web applications for a while now. My applications have been fairing poorly in search engine results because of the dynamic links that my websites generate. I admire the way some developers do their mod_rewrite to produce something like: http://www.mycompany.com/accommodation/europe/ to run a substitute of "index.php?category_id=2&country=23" How can I achieve that in my urls? Warm regards, JB

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  • Wildcard redirect for subdomains and URI

    - by user1807680
    I have a problem with create pernament (301) redirect in apache: I have 2 domains: olddomain.com with many subdomains newdomain.com and I want to do redirect like: if user enter on http://anysubdomain.olddomain.com should be redirected to http://anysubdomain.newdomain.com if user enter on http://olddomain.com/something should be redirected to http://newdomain.com/something if user enter on http://olddomain.com/different/index.html should be redirected to http://newdomain.com/different/index.html if user enter on http://example.olddomain.com/ex/index.html should be redirected to http://example.newdomain.com/ex/index.html I don't know how I should set this: <VirtualHost *:80> ServerName olddomain.com </VirtualHost> Regards

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