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  • Correct way to initialize dynamic Array in C++

    - by mef
    Hey guys, I'm currently working on a C++ project, where dynamic arrays often appear. I was wondering, what could be the correct way to initialize a dynamic array using the new-operator? A colleague of mine told me that it's a no-no to use new within the constructor, since a constructor is a construct that shouldn't be prone to errors or shouldn't fail at all, respectively. Now let's consider the following example: We have two classes, a more or less complex class State and a class StateContainer, which should be self-explained. class State { private: unsigned smth; public: State(); State( unsigned s ); }; class StateContainer { private: unsigned long nStates; State *states; public: StateContainer(); StateContainer( unsigned long n ); virtual ~StateContainer(); }; StateContainer::StateContainer() { nStates = SOME_DEFINE_N_STATES; states = new State[nStates]; if ( !states ) { // Error handling } } StateContainer::StateContainer( unsigned long n ) { nStates = n; try { states = new State[nStates] } catch ( std::bad_alloc &e ) { // Error handling } } StateContainer::~StateContainer() { if ( states ) { delete[] states; states = 0; } } Now actually, I have two questions: 1.) Is it ok, to call new within a constructor, or is it better to create an extra init()-Method for the State-Array and why? 2.) Whats the best way to check if new succeeded: if (!ptr) std::cerr << "new failed." or try { /*new*/ } catch (std::bad_alloc) { /*handling*/ } 3.) Ok its three questions ;o) Under the hood, new does some sort of ptr = (Struct *)malloc(N*sizeof(Struct)); And then call the constructor, right?

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  • New Big Data Appliance Security Features

    - by mgubar
    The Oracle Big Data Appliance (BDA) is an engineered system for big data processing.  It greatly simplifies the deployment of an optimized Hadoop Cluster – whether that cluster is used for batch or real-time processing.  The vast majority of BDA customers are integrating the appliance with their Oracle Databases and they have certain expectations – especially around security.  Oracle Database customers have benefited from a rich set of security features:  encryption, redaction, data masking, database firewall, label based access control – and much, much more.  They want similar capabilities with their Hadoop cluster.    Unfortunately, Hadoop wasn’t developed with security in mind.  By default, a Hadoop cluster is insecure – the antithesis of an Oracle Database.  Some critical security features have been implemented – but even those capabilities are arduous to setup and configure.  Oracle believes that a key element of an optimized appliance is that its data should be secure.  Therefore, by default the BDA delivers the “AAA of security”: authentication, authorization and auditing. Security Starts at Authentication A successful security strategy is predicated on strong authentication – for both users and software services.  Consider the default configuration for a newly installed Oracle Database; it’s been a long time since you had a legitimate chance at accessing the database using the credentials “system/manager” or “scott/tiger”.  The default Oracle Database policy is to lock accounts thereby restricting access; administrators must consciously grant access to users. Default Authentication in Hadoop By default, a Hadoop cluster fails the authentication test. For example, it is easy for a malicious user to masquerade as any other user on the system.  Consider the following scenario that illustrates how a user can access any data on a Hadoop cluster by masquerading as a more privileged user.  In our scenario, the Hadoop cluster contains sensitive salary information in the file /user/hrdata/salaries.txt.  When logged in as the hr user, you can see the following files.  Notice, we’re using the Hadoop command line utilities for accessing the data: $ hadoop fs -ls /user/hrdataFound 1 items-rw-r--r--   1 oracle supergroup         70 2013-10-31 10:38 /user/hrdata/salaries.txt$ hadoop fs -cat /user/hrdata/salaries.txtTom Brady,11000000Tom Hanks,5000000Bob Smith,250000Oprah,300000000 User DrEvil has access to the cluster – and can see that there is an interesting folder called “hrdata”.  $ hadoop fs -ls /user Found 1 items drwx------   - hr supergroup          0 2013-10-31 10:38 /user/hrdata However, DrEvil cannot view the contents of the folder due to lack of access privileges: $ hadoop fs -ls /user/hrdata ls: Permission denied: user=drevil, access=READ_EXECUTE, inode="/user/hrdata":oracle:supergroup:drwx------ Accessing this data will not be a problem for DrEvil. He knows that the hr user owns the data by looking at the folder’s ACLs. To overcome this challenge, he will simply masquerade as the hr user. On his local machine, he adds the hr user, assigns that user a password, and then accesses the data on the Hadoop cluster: $ sudo useradd hr $ sudo passwd $ su hr $ hadoop fs -cat /user/hrdata/salaries.txt Tom Brady,11000000 Tom Hanks,5000000 Bob Smith,250000 Oprah,300000000 Hadoop has not authenticated the user; it trusts that the identity that has been presented is indeed the hr user. Therefore, sensitive data has been easily compromised. Clearly, the default security policy is inappropriate and dangerous to many organizations storing critical data in HDFS. Big Data Appliance Provides Secure Authentication The BDA provides secure authentication to the Hadoop cluster by default – preventing the type of masquerading described above. It accomplishes this thru Kerberos integration. Figure 1: Kerberos Integration The Key Distribution Center (KDC) is a server that has two components: an authentication server and a ticket granting service. The authentication server validates the identity of the user and service. Once authenticated, a client must request a ticket from the ticket granting service – allowing it to access the BDA’s NameNode, JobTracker, etc. At installation, you simply point the BDA to an external KDC or automatically install a highly available KDC on the BDA itself. Kerberos will then provide strong authentication for not just the end user – but also for important Hadoop services running on the appliance. You can now guarantee that users are who they claim to be – and rogue services (like fake data nodes) are not added to the system. It is common for organizations to want to leverage existing LDAP servers for common user and group management. Kerberos integrates with LDAP servers – allowing the principals and encryption keys to be stored in the common repository. This simplifies the deployment and administration of the secure environment. Authorize Access to Sensitive Data Kerberos-based authentication ensures secure access to the system and the establishment of a trusted identity – a prerequisite for any authorization scheme. Once this identity is established, you need to authorize access to the data. HDFS will authorize access to files using ACLs with the authorization specification applied using classic Linux-style commands like chmod and chown (e.g. hadoop fs -chown oracle:oracle /user/hrdata changes the ownership of the /user/hrdata folder to oracle). Authorization is applied at the user or group level – utilizing group membership found in the Linux environment (i.e. /etc/group) or in the LDAP server. For SQL-based data stores – like Hive and Impala – finer grained access control is required. Access to databases, tables, columns, etc. must be controlled. And, you want to leverage roles to facilitate administration. Apache Sentry is a new project that delivers fine grained access control; both Cloudera and Oracle are the project’s founding members. Sentry satisfies the following three authorization requirements: Secure Authorization:  the ability to control access to data and/or privileges on data for authenticated users. Fine-Grained Authorization:  the ability to give users access to a subset of the data (e.g. column) in a database Role-Based Authorization:  the ability to create/apply template-based privileges based on functional roles. With Sentry, “all”, “select” or “insert” privileges are granted to an object. The descendants of that object automatically inherit that privilege. A collection of privileges across many objects may be aggregated into a role – and users/groups are then assigned that role. This leads to simplified administration of security across the system. Figure 2: Object Hierarchy – granting a privilege on the database object will be inherited by its tables and views. Sentry is currently used by both Hive and Impala – but it is a framework that other data sources can leverage when offering fine-grained authorization. For example, one can expect Sentry to deliver authorization capabilities to Cloudera Search in the near future. Audit Hadoop Cluster Activity Auditing is a critical component to a secure system and is oftentimes required for SOX, PCI and other regulations. The BDA integrates with Oracle Audit Vault and Database Firewall – tracking different types of activity taking place on the cluster: Figure 3: Monitored Hadoop services. At the lowest level, every operation that accesses data in HDFS is captured. The HDFS audit log identifies the user who accessed the file, the time that file was accessed, the type of access (read, write, delete, list, etc.) and whether or not that file access was successful. The other auditing features include: MapReduce:  correlate the MapReduce job that accessed the file Oozie:  describes who ran what as part of a workflow Hive:  captures changes were made to the Hive metadata The audit data is captured in the Audit Vault Server – which integrates audit activity from a variety of sources, adding databases (Oracle, DB2, SQL Server) and operating systems to activity from the BDA. Figure 4: Consolidated audit data across the enterprise.  Once the data is in the Audit Vault server, you can leverage a rich set of prebuilt and custom reports to monitor all the activity in the enterprise. In addition, alerts may be defined to trigger violations of audit policies. Conclusion Security cannot be considered an afterthought in big data deployments. Across most organizations, Hadoop is managing sensitive data that must be protected; it is not simply crunching publicly available information used for search applications. The BDA provides a strong security foundation – ensuring users are only allowed to view authorized data and that data access is audited in a consolidated framework.

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  • Returning new object, overwrite the existing one in Java

    - by lupin
    Note: This is an assignment. Hi, Ok I have this method that will create a supposedly union of 2 sets. i mport java.io.*; class Set { public int numberOfElements; public String[] setElements; public int maxNumberOfElements; // constructor for our Set class public Set(int numberOfE, int setE, int maxNumberOfE) { this.numberOfElements = numberOfE; this.setElements = new String[setE]; this.maxNumberOfElements = maxNumberOfE; } // Helper method to shorten/remove element of array since we're using basic array instead of ArrayList or HashSet from collection interface :( static String[] removeAt(int k, String[] arr) { final int L = arr.length; String[] ret = new String[L - 1]; System.arraycopy(arr, 0, ret, 0, k); System.arraycopy(arr, k + 1, ret, k, L - k - 1); return ret; } int findElement(String element) { int retval = 0; for ( int i = 0; i < setElements.length; i++) { if ( setElements[i] != null && setElements[i].equals(element) ) { return retval = i; } retval = -1; } return retval; } void add(String newValue) { int elem = findElement(newValue); if( numberOfElements < maxNumberOfElements && elem == -1 ) { setElements[numberOfElements] = newValue; numberOfElements++; } } int getLength() { if ( setElements != null ) { return setElements.length; } else { return 0; } } String[] emptySet() { setElements = new String[0]; return setElements; } Boolean isFull() { Boolean True = new Boolean(true); Boolean False = new Boolean(false); if ( setElements.length == maxNumberOfElements ){ return True; } else { return False; } } Boolean isEmpty() { Boolean True = new Boolean(true); Boolean False = new Boolean(false); if ( setElements.length == 0 ) { return True; } else { return False; } } void remove(String newValue) { for ( int i = 0; i < setElements.length; i++) { if ( setElements[i] != null && setElements[i].equals(newValue) ) { setElements = removeAt(i,setElements); } } } int isAMember(String element) { int retval = -1; for ( int i = 0; i < setElements.length; i++ ) { if (setElements[i] != null && setElements[i].equals(element)) { return retval = i; } } return retval; } void printSet() { for ( int i = 0; i < setElements.length; i++) { if (setElements[i] != null) { System.out.println("Member elements on index: "+ i +" " + setElements[i]); } } } String[] getMember() { String[] tempArray = new String[setElements.length]; for ( int i = 0; i < setElements.length; i++) { if(setElements[i] != null) { tempArray[i] = setElements[i]; } } return tempArray; } Set union(Set x, Set y) { String[] newXtemparray = new String[x.getLength()]; String[] newYtemparray = new String[y.getLength()]; int len = newYtemparray.length + newXtemparray.length; Set temp = new Set(0,len,len); newXtemparray = x.getMember(); newYtemparray = x.getMember(); for(int i = 0; i < newYtemparray.length; i++) { temp.add(newYtemparray[i]); } for(int j = 0; j < newXtemparray.length; j++) { temp.add(newXtemparray[j]); } return temp; } Set difference(Set x, Set y) { String[] newXtemparray = new String[x.getLength()]; String[] newYtemparray = new String[y.getLength()]; int len = newYtemparray.length + newXtemparray.length; Set temp = new Set(0,len,len); newXtemparray = x.getMember(); newYtemparray = x.getMember(); for(int i = 0; i < newXtemparray.length; i++) { temp.add(newYtemparray[i]); } for(int j = 0; j < newYtemparray.length; j++) { int retval = temp.findElement(newYtemparray[j]); if( retval != -1 ) { temp.remove(newYtemparray[j]); } } return temp; } } // This is the SetDemo class that will make use of our Set class class SetDemo { public static void main(String[] args) { //get input from keyboard BufferedReader keyboard; InputStreamReader reader; String temp = ""; reader = new InputStreamReader(System.in); keyboard = new BufferedReader(reader); try { System.out.println("Enter string element to be added" ); temp = keyboard.readLine( ); System.out.println("You entered " + temp ); } catch (IOException IOerr) { System.out.println("There was an error during input"); } /* ************************************************************************** * Test cases for our new created Set class. * ************************************************************************** */ Set setA = new Set(0,10,10); setA.add(temp); setA.add("b"); setA.add("b"); setA.add("hello"); setA.add("world"); setA.add("six"); setA.add("seven"); setA.add("b"); int size = setA.getLength(); System.out.println("Set size is: " + size ); Boolean isempty = setA.isEmpty(); System.out.println("Set is empty? " + isempty ); int ismember = setA.isAMember("sixb"); System.out.println("Element sixb is member of setA? " + ismember ); Boolean output = setA.isFull(); System.out.println("Set is full? " + output ); //setA.printSet(); int index = setA.findElement("world"); System.out.println("Element b located on index: " + index ); setA.remove("b"); //setA.emptySet(); int resize = setA.getLength(); System.out.println("Set size is: " + resize ); //setA.printSet(); Set setB = new Set(0,10,10); setB.add("b"); setB.add("z"); setB.add("x"); setB.add("y"); Set setC = setA.union(setB,setA); System.out.println("Elements of setA"); setA.printSet(); System.out.println("Union of setA and setB"); setC.printSet(); } } The union method works a sense that somehow I can call another method on it but it doesn't do the job, i supposedly would create and union of all elements of setA and setB but it only return element of setB. Sample output follows: java SetDemo Enter string element to be added hello You entered hello Set size is: 10 Set is empty? false Element sixb is member of setA? -1 Set is full? true Element b located on index: 2 Set size is: 9 Elements of setA Member elements on index: 0 hello Member elements on index: 1 world Member elements on index: 2 six Member elements on index: 3 seven Union of setA and setB Member elements on index: 0 b Member elements on index: 1 z Member elements on index: 2 x Member elements on index: 3 y thanks, lupin

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  • Windows performance monitor new instances

    - by fborozan
    Hi all, I am trying to configure performance monitor on 2003/2008R1&R2 to capture new instances of the counters without any luck. For example if I select counter Process\%Processor time (to monitor processor time per any instances of the process) everything works fine until I open or close any application. If in the meanwhile new application is open it will not be included in the monitoring processor, and old application instance will display zero for % processor time. The problem is performance monitor is not refreshing instances of the new applications/users/new terminal session/ or any other metrics that changes instances in the meanwhile. The solution is to stop/start log file, but I don't want to do that every sec and the logging will be split into two files. Anybody knows how do I accomplish to add all new instances? Any help greatly appreciated

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  • New Windows 7 Libraries created keep disappearing

    - by Sean
    I've just got a new laptop that came pre-installed with Windows 7 Professional edition. One of the new features of Windows 7 is Libraries. I'm familiar with how this works and am trying to create my own library called 'Work' to include all my work folders on my computer. However every time I create a new custom Library, after I rename it, it disappears from my Library menu. Each time I click Libraries in the Explorer, I keep seeing the same 4 default libraries, I.e. Documents, Pictures, Music, and Video. So when I try to create a new Library called 'Work' again, I get a pop up message "Do you want to rename New library to Work (2).Library-Microsoft?" Which means that my original work library still exists but for some reason I can't see it. Can someone please help me figure out why this is happening?

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  • Config file (App.config) does not update on new installation

    - by Muhammad Kashif Nadeem
    I am creating setup of my project using Visula Studio 2008. I am facing problem in setup installation. If I uninstall old setup (application) and install the new one then config file (App.config) updates the attributes (surely it is new file) of config file but if I install new setup without uninstalling the old one then config file does not update. from config file I mean MyProject.exe.config Why is this behavior of config file. Should it not be updated on installation of the new setup Is this possible to delete and copy the config file of new setup? Is there a way to update only config file forcefully during installation. Thanks for your help!

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  • How to redirect domain to new server?

    - by hfidgen
    I've got a domain registered with a hosting company who I no longer wish to use. I'm happy for them to keep managing my domain, but I want my domain to point to my new (better) server which i've just bought and set up. I know my new server's IP address and Nameservers, What do I need to do in my domain management control panel to make it point to my new server? Change the "A" record to the new IP? Change the nameservers to my new hosts nameservers? Is that it? Are there no other record on either server which need changing? I always get confused by who needs to do what when it comes to domains... Thanks, Hugh

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  • Dhcp clients fail after successful import of server to new machine

    - by Tathagata
    I transfered the configs of a dhcp server from one server to another both running Windows Server 2003 R2 following http [://] support.microsoft.com/kb/325473. The new server has a statically configured ip(outside the scope) like the old one. Stopped the server on the old, and started up in the new server (authorized too) - but when I ipconfig /renew from a client its network interface fails with all 0.0.0.0 (or 169...*). I read somewhere I need to reconcile the scope to sync the new registry values ('ll try this tomorrow). What other troubleshooting steps can I take other than these (which didn't help)? Things work fine when the old server resurrects and the new one is taken down. The new server showed there was no requests for offer.

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  • Dhcp server change fail after successful importing to new machine

    - by Tathagata
    I transfered the configs of a dhcp server from one server to another both running Windows Server 2003 R2 following http [://] support.microsoft.com/kb/325473. The new server has a statically configured ip(outside the scope) like the old one. Stopped the server on the old, and started up in the new server (authorized too) - but when I ipconfig /renew from a client its network interface fails with all 0.0.0.0 (or 169...*). I read somewhere I need to reconcile the scope to sync the new registry values ('ll try this tomorrow). What other troubleshooting steps can I take other than these (which didn't help)? Things work fine when the old server resurrects and the new one is taken down. The new server showed there was no requests for offer.

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  • Dhcp clients fail after successful import of server to new machine (win2k3)

    - by Tathagata
    I transfered the configs of a dhcp server from one server to another both running Windows Server 2003 R2 following http [://] support.microsoft.com/kb/325473. The new server has a statically configured ip(outside the scope) like the old one. Stopped the server on the old, and started up in the new server (authorized too) - but when I ipconfig /renew from a client its network interface fails with all 0.0.0.0 (or 169...*). I read somewhere I need to reconcile the scope to sync the new registry values ('ll try this tomorrow). What other troubleshooting steps can I take other than these (which didn't help)? Things work fine when the old server resurrects and the new one is taken down. The new server showed there was no requests for offer.

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  • Robocopy to copy only new folders and files

    - by Valery Shampal
    A task: To find all new files and subfolders under some root folder (let us say Documents) and to copy them to other disk (j: in this case) Command line used: robocopy c:\users\valery\documents j:\robocopy /XO /E /MAXAGE:20131030 /XD Result: A full folders tree created. Only new files copyed, as supposed. It's good A point is, that I do not want to create all subfolders on a target disk, if there are no new files in them. Results are exeptable, but there is a lot of work to go through all folders and to find new files, as well, as to understand, what subfolders are a new ones Regards, Valery

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  • How to follow up new technologies and software releases as they come out

    - by Developer
    I don't know if this is right place to ask question, if not please move it to right area please. Is there a website/app/forum/newsletter where I can followup different softwares or technology and feature soon after their new releases. i.e. ipad iphone ios 7 release as soon as it will release with its feature. andriod next version soon after it release with its feature. coreldraw x7 whenever it will rlease zend framework new version when ever it will release. mac php new version photoshop new version ....... there are lot more list than that which goes on and on and Its difficult to follow up new technology as they come out. Any better and less time consuming way to follow up.

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  • Perl : Reading messages in gmail account

    - by kiruthika
    Hi all, I have used the module Mail::Webmail::Gmail to read the new messages in my gmail account. I have written the following code for this purpose. use strict; use warnings; use Data::Dumper; use Mail::Webmail::Gmail; my $gmail = Mail::Webmail::Gmail->new( username => 'username', password => 'password', ); my $messages = $gmail->get_messages( label => $Mail::Webmail::Gmail::FOLDERS{ 'INBOX' } ); foreach ( @{ $messages } ) { if ( $_->{ 'new' } ) { print "Subject: " . $_->{ 'subject' } . " / Blurb: " . $_->{ 'blurb' } . "\n"; } } But it didn't print anything. Can anyone help me in this or suggest any other module for this. Thanks in advance.

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  • How to add a new entry to a multiple has_many association?

    - by siulamvictor
    I am not sure am I doing these correct. I have 3 models, Account, User, and Event. Account contains a group of Users. Each User have its own username and password for login, but they can access the same Account data under the same Account. Events is create by a User, which other Users in the same Account can also read or edit it. I created the following migrations and models. User migration class CreateUsers < ActiveRecord::Migration def self.up create_table :users do |t| t.integer :account_id t.string :username t.string :password t.timestamps end end def self.down drop_table :users end end Account migration class CreateAccounts < ActiveRecord::Migration def self.up create_table :accounts do |t| t.string :name t.timestamps end end def self.down drop_table :accounts end end Event migration class CreateEvents < ActiveRecord::Migration def self.up create_table :events do |t| t.integer :account_id t.integer :user_id t.string :name t.string :location t.timestamps end end def self.down drop_table :events end end Account model class Account < ActiveRecord::Base has_many :users has_many :events end User model class User < ActiveRecord::Base belongs_to :account end Event model class Event < ActiveRecord::Base belongs_to :account belongs_to :user end so.... Is this setting correct? Every time when a user create a new account, the system will ask for the user information, e.g. username and password. How can I add them into correct tables? How can I add a new event? I am sorry for such a long question. I am not very understand the rails way in handling such data structure. Thank you guys for answering me. :)

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  • [Ruby on Rails] how to add a new entry with a multiple has_many association?

    - by siulamvictor
    I am not sure am I doing these correct. I have 3 models, Account, User, and Event. Account contains a group of Users. Each User have its own username and password for login, but they can access the same Account data under the same Account. Events is create by a User, which other Users in the same Account can also read or edit it. I created the following migrations and models. User migration class CreateUsers < ActiveRecord::Migration def self.up create_table :users do |t| t.integer :account_id t.string :username t.string :password t.timestamps end end def self.down drop_table :users end end Account migration class CreateAccounts < ActiveRecord::Migration def self.up create_table :accounts do |t| t.string :name t.timestamps end end def self.down drop_table :accounts end end Event migration class CreateEvents < ActiveRecord::Migration def self.up create_table :events do |t| t.integer :account_id t.integer :user_id t.string :name t.string :location t.timestamps end end def self.down drop_table :events end end Account model class Account < ActiveRecord::Base has_many :users has_many :events end User model class User < ActiveRecord::Base belongs_to :account end Event model class Event < ActiveRecord::Base belongs_to :account belongs_to :user end so.... Is this setting correct? Every time when a user create a new account, the system will ask for the user information, e.g. username and password. How can I add them into correct tables? How can I add a new event? I am sorry for such a long question. I am not very understand the rails way in handling such data structure. Thank you guys for answering me. :)

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  • Invalid format for New Relic licence when installing on Elastic Beanstalk

    - by BenFreke
    We've created an app that is running on an Elastic Beanstalk instance, 64 bit PHP version 5.4 (so not legacy). I've used the New Relic installation instructions to install New Relic, and viewing phpinfo shows that New Relic is installed. However, I'm not getting any data in New Relic and that is because it is saying that the licence is ***invalid format*** under newrelic.licence I'm getting the licence from my New Relic account, and it is a 40 character hexadecimal string. Here is the current newrelic.config file in the .ebextensions folder I'm using, with most of the licence key commented out. packages: yum: newrelic-php5: [] rpm: newrelic: http://yum.newrelic.com/pub/newrelic/el5/x86_64/newrelic-repo-5-3.noarch.rpm commands: configure_new_relic: command: newrelic-install install env: NR_INSTALL_SILENT: true NR_INSTALL_KEY: ec9a4... Skitch of relevant phpinfo Can anyone shed some light on what's going on here? I've tried two different New Relic licence keys with the same error, I've also surrounded it with a single quote mark and tried uppercase only. And at this point I'm out of ideas on what to try. We're not AWS gurus so it could very easily be something simple like not opening a port to allow the licence to be validated?

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  • New user profile creation error - Windows cannot open *.exe

    - by Jake
    I have a windows 7 laptop with the user "mydomain\boy" that cannot log in to the laptop. the error message is something like "User profile service cannot log in the user boy". I then logged in with the domain admin account "mydomain\admin" and then went to delete the "mydomain\boy" from my computer system properties advance system settings user profiles settings. I also ensure that the user is deleted from control panel user accounts. I then also deleted the user folder c:\users\boy I also checked that the registry at this location HKLM\software\microsoft\windows nt\currentversion\profilelist\ and ensure that there is no entry for boy. I followed http://support.microsoft.com/kb/947215 using the method 3 "fix it for me" but does not seem to do anything. (or i don't know how to use it). AFTER EVERYTHING DONE ABOVE... Everytime i log in with a new user, be it boy, girl or anything other domain account (other than the admin account already created when I first logged in to begin the fix/break), it takes a long time, and when the "preparing desktop" goes away, it starts to exe cannot open error e.g. regsvr.exe etc.. file association problem with exe QUESTION (phew finally..): Please tell me how to fix it? Thanks!

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  • I can't connect new Windows 7 PC to Mac iBook with OS 10.3.9

    - by Jeff Humm
    Help ! I have an old iBook wired to a router and a new PC linking wirelessly to same router. On the Mac I have 'seen' the PC but not been able to connect to it. On the PC, the Network and Sharing Centre lists 'IBOOK'. When I click on this, 'Windows Security' asks me to 'Enter Network Password', asking for User name and password. I have tried: 1) The user name and password of my admin account on the iBook. This returns a 'logon failure' message but lists the user name as [NAME_OF_PC\User Name], suggesting it was looking for the user name of the PC, not the Mac. 2) The user name and password of my account on the PC. This also returns a 'logon failure' message. 3) The user name of my account on the PC and the 'homegroup password' given to me by Windows when setting up the PC. This also returns a 'logon failure' message. Today I've tried connecting the two machines via a patch cable - still no joy. Can anyone help? It is 20 years since I wrestled with any OS other than Mac, and 10 years since I've done mich wrangling with the Macs, so please assume no knowledge! Thanks in advance,

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  • How to add "create a new python file" to the registry

    - by Anthony
    I have Python 3.2 on a windows 7 operating system. The other day I thought that it would be convenient to add a link to create a new .py file in the right hand click "new" menu. I had worked with the registry before and looked up how to add an item to the "new" menu, but when I got to the registry under HKEY_CLASSES_ROOT the .py extension key was not there. I only know how to add something to the "new" menu using the extension key. I searched the web, but could not come up with any other ways. Python works perfectly fine, and I don't want to mess anything up by adding the extension key. So here are my questions: Will I mess up python or something else by adding a .py key?( I know it is dangerous to work with the registry, that is why I am looking for a safe solution) If not how can I go about doing this? OR Is there a different way to add "create a new python file" to the "new" menu? If so how can I do it? OR If the only way is very complicated should I forget about it? Thank you in advance. P.S I originally posted on Stack Overflow that they told me to move it over here.

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  • Configure New Server for .htaccess

    - by Phil T
    I have a new LAMP CENTOS 5 server I am setting up and trying to copy the configuration from another web server I have. I am stuck with what I think is a mod_rewrite problem. If I go to http://old-server.com/any_page_name.php it correctly routes through some handling code in index.php and shows me a graceful "Page Cannot Be Displayed" message. But if I go to http://new-server.com/any_page_name.php I get an ugly Apache 404 Not Found error message. I looked in both httpd.conf files and they both have only one reference to mod_rewrite. LoadModule rewrite_module modules/mod_rewrite.so So it seems like that should be fine. At the bottom of httpd.conf I have the code: <VirtualHost *:80> ServerAdmin [email protected] DocumentRoot /var/www/html ServerName new-server.com ErrorLog logs/new-server.com-error_log CustomLog logs/new-server.com-access_log common </VirtualHost> Then in the root of /var/www/html I have the exact same .htaccess file that looks like this: RewriteEngine on Options +FollowSymlinks RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule . index.php [L] ErrorDocument 404 /page-unavailable/ <files ~ "\.tpl$"> order deny,allow allow from none deny from all </files> So I don't see why the page load at old-server.com works fine while new-server.com doesn't route through index.php like I want it to do. Thanks.

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  • Wipe 12.04/Windows 7 dual boot setup and start fresh new 12.04

    - by dswhite85
    I have an Asus u56e laptop running dual boot setup, Windows 7 and 12.04. I had Windows 7 first. I was wondering what's the easiest way possible to erase/format my drive (500GB) so that it deletes Ubuntu and Windows 7 so I can reinstall 12.04 onto my whole drive? Does the Ubuntu Live CD help make this a possibility or is there something with gparted I have to tinker with? I've already got everything I need backed up. Any help would be much appreciated.

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  • New Style of Post

    - by Lee Brandt
    I’ve been absent from blogging for awhile. Part of it is due to the ultimate inertia of my life. Most of it is due to my inability to post my thoughts without turning it into an ‘According to Hoyle’ blog post. I have an idea, and I try to flesh it into an interesting article. Something that you might see posted in a magazine or something. It never lives up to my standards and I end up dropping it. How did I get to this? I started this blog for the intended purpose of archiving my ideas and solutions so that I could find them again. Me. I realize that maybe some people read this blog, but I am NOT a celebrity or God’s gift to programming. So why am I worried about making my posts ‘worthy of public consumption’? Well, no more. If you are a reader of this blog, I thank you. But my content may change dramatically over the coming months, so be prepared. Hopefully you will still find my thoughts, ideas and solutions worth reading. Thanks again, Lee

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  • Soluto’s New Quick Question Button Makes Family Tech Support Simple

    - by Jason Fitzpatrick
    Soluto, a computer and boot management tool, now features a Quick Question button that allows the people you help out to easily click a button and send you both a short message and a screenshot of the problem. Any time your friend or family member presses F8, Soluto will take a screenshot of the screen, the Task Manager history, and a note from the user highlighting what issue they’re experiencing, and then email it all to you. After reviewing the email you can easily login to Soluto to remotely manage your friend’s computer and help with the problem. For more information about Soluto you can check out our previous reviews of the service here and here, or just hit up the link below to read more and take Soluto for a test drive. Soluto is a free service (for the first 5 computers), Windows only. Introducing Quick Question [The Soluto Blog] Java is Insecure and Awful, It’s Time to Disable It, and Here’s How What Are the Windows A: and B: Drives Used For? HTG Explains: What is DNS?

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  • New Rules of Retail

    - by David Dorf
    I've been on vacation and preparing for Crosstalk, so its been a while since I've posted. I've seen the agenda, and I can assure you Crosstalk will be lots of fun. In addition to hearing from lots of retailers, we'll also be doing a little bowling and racing on the track. I'll be around for the sessions, the ORUG meetings, and our Customer Advisory Board so please be sure to say hello. I also just completed a white paper based on a previous blog posting which in turn was based on learnings from reading What Would Google Do? For each of Jarvis' ten rules, I discuss the concept in the context of retail and provide real-world examples. No mention of products or sales pitches at all. You can download the paper here. It will put you in the right frame of mind for hearing Jeff Jarvis speak at Crosstalk. For those that can't make it, I'll post some highlights afterwards.

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  • New Whitepaper: Advanced Compression 11gR1 Benchmarks with EBS 12

    - by Steven Chan
    In my opinion, if there's any reason to upgrade an E-Business Suite environment to the 11gR1 or 11gR2 database, it's the Advanced Compression database option.  Oracle Advanced Compression was introduced in Oracle Database 11g, and allows you to compress structured data (numbers, characters) as well as unstructured data (documents, spreadsheets, XML and other files).  It provides enhanced compression for database backups and also includes network compression for faster synchronization with standby databases.In other words, the promise of Advanced Compression is that it can make your E-Business Suite database smaller and faster.  But how well does it actually deliver on that promise?Apps 12 + Advanced Compression Benchmarks now availableThree of my colleagues, Uday Moogala, Lester Gutierrez, and Andy Tremayne, have been benchmarking Oracle E-Business Suite Release 12 with Advanced Compression 11gR1.  They've just released a detailed whitepaper with their benchmarking results and recommendations.This whitepaper is available in two locations:Oracle E-Business Suite Release 12.1 with Oracle Database 11g Advanced Compression (Note 1110648.1) (requires My Oracle Support access)Oracle E-Business Suite Release 12.1 with Oracle Database 11g Advanced Compression (Applications Benchmark website, PDF, 500K)

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