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  • How to avoid printing nearly blank pages?

    - by joelarson
    How many times have you printed an email just to have the last page be 2 or 3 lines of a person's signature (or worse, the "This is confidential" copy inserted by corporate mailservers)? How many times has the last page contained just the footer of the website? Does anyone know of a utility or print driver that can help avoid printing blank or nearly-blank pages? I am not looking for techniques for avoiding this in specific programs -- if I take the effort of doing print preview and then adjusting the pages to be printed, then of course I can avoid it. What I want something I can install that, whenever I push "Print" to any of the various printers I print to with my laptop, it automatically says "hmmm... I bet he doesn't really want that page which is 95% empty" and possibly prompts me to say "do you really want to waste paper on this?"

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  • Okular (on Ubuntu 9.10) prints multiple pages per sheet (n-up) very small

    - by dgleich
    I'm trying to print a set of beamer slides with multiple slides per page (4-up or 6-up). When I select 4 pages or 6 pages per sheet in the Okular print dialog, the pages print quite small (perhaps even tiny -- about 1.75" by 1.25") and leave significant white-space on the page. I can get around this behavior by using the pdfnup utility (in the pdfjam package); which will correctly generate a 4- or 6-up pdf file but it's annoying to generate a second pdf file when I should be able to accomplish this task from the print dialog. Details: Ubuntu 9.10 (Karmic), 64-bit, Color Postscript printer.

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  • Directly printing to remote CUPS/IPP server on Snow Leopard

    - by Martin v. Löwis
    I need to use Kerberos authentication when printing from my OSX machine, however, the machine itself does not have a service account in active directory, so the KDC will not issue a delegation ticket for the local CUPS installation. I think printing could work if the printing framework would directly print to the network CUPS server (or even to the Windows print server), bypassing the local CUPS. Is it possible to setup printing so that it directly accesses the remote print server? (asking for a service ticket for that server would succeed)

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  • linux/solaris kill many proccess with one command

    - by yael
    Is it possible to kill all find process with one command? I do not want to kill each process as kill -9 25295 , kill -9 11994 , etc.. Rather, what I want is a simple way or command that kill all find process (my target is to perfrom this action on linux and solaris machines). $ ps -ef | grep find root 25295 25290 0 08:59:59 pts/1 0:01 find /etc -type f -exec grep -l 100.106.23.152 {} ; -print root 11994 26144 0 09:04:18 pts/1 0:00 find /etc -type f -exec grep -l 100.106.23.153 {} ; -print root 25366 25356 0 08:59:59 pts/1 0:01 find /etc -type f -exec grep -l 100.106.23.154 {} ; -print root 26703 26658 0 09:00:05 pts/1 0:01 find /etc -type f -exec grep -l 100.106.23.155 {} ; -print

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  • Windows 2008 Server Firewall blocks from printing in other subnet

    - by xenolf
    Greetings, i have a windows 2008 server with activated firewall in the 192.168.0.xx subnet. From there i want to print on an printer which is located in the 192.168.10.xx subnet. Now when i try to print with the firewall on, nothing happens... when i turn the firewall off it prints flawlessly. Now i messed around with the windows firewall for about 4 hours straight and i cant seem to find a rule which lets me print. Even when i set the firewall to let everything through im unable to print. Has anyone encountered the same or a similar problem and has a solution for this issue? Thanks in advance xenolf

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  • Converting DOCX files to PDF via SSH without losing formatting

    - by Reado
    I'm struggling to find a solution that will allow me to convert a DOCX file to a PDF without losing or malforming the formatting of the document on CentOS 5.7. I have tried CUPS-PDF but it doesn't work; spool files appear in the /var/spool folder but nothing happens after that. OpenOffice and LibreOffice converted a DOCX to PDF but the formatting was all wrong. However if I print the DOCX to a Windows PDF printer from my Windows 7 workstation, it outputs to PDF absolutely fine. So why can't Linux do the same? I tried to print via CUPS to the Windows PDF printer (shared) but the document appears in the queue as "Remote Downlevel Document" and doesn't print. This only happens when I print from Linux.

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  • Directly printing to remote CUPS/IPP server on Snow Leopard

    - by Martin v. Löwis
    I need to use Kerberos authentication when printing from my OSX machine, however, the machine itself does not have a service account in active directory, so the KDC will not issue a delegation ticket for the local CUPS installation. I think printing could work if the printing framework would directly print to the network CUPS server (or even to the Windows print server), bypassing the local CUPS. Is it possible to setup printing so that it directly accesses the remote print server? (asking for a service ticket for that server would succeed)

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  • Printer offline until spooler service is restarted multiple times

    - by Zian Choy
    When I try to print from my ThinkPad to a printer shared through a Windows 7 Homegroup hosted by a desktop computer, I often have to restart the Print Spooler service several times before the job will go through. In particular, this problem occurs when the desktop is in sleep mode when the print job is started and then brought out of sleep mode after the print job has been kicked off. Both computers are running Windows 7 32-bit edition with the latest patches. I have tried the following with no improvement: SNMP registry hack (see MS KB for details) Following the instructions in a blog post entitled "Sharing Printers on Vista 64-bit" Looking at Printer offline until spooler service is restarted

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  • Nginx location to match query parameters

    - by Dave
    Is it possible in nginx to have a location {} block that matches query parameters. For example I want to pick up that "preview=true" in this url and then instruct it to do several different things, all possible in a location block. http://192.158.0.1/web/test.php?hello=test&preview=true&another=var The problem I'm having is that my test stuff doesn't seem to match, it seems like I can only match the URL itself? E.g. location ~ ^(.*)(preview)(.*)$ Or something aloong those lines?

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  • The plugin of munin is always timed out

    - by haoX
    I want to use munin to make a graph of ttyACM0 in Linux, but munin can not create the graph. I found some information in "munin-node.log". it shows that "Service 'temperature' timed out". So I changed timeout to 60 or 120 in /munin/plugin-conf.d/munin-node, but it does not work. It's also timed out. Here is part of my code: if [ "$1" = "config" ]; then echo 'graph_title Temperature of board' echo 'graph_args --base 1000 -l 0' echo 'graph_vlabel temperature(°C)' echo 'graph_category temperature' echo 'graph_scale no' echo 'graph_info This graph shows the temperature of board' for i in 1 2 3 4 5; do case $i in 1) TYPE="Under PCB" ;; 2) TYPE="HDD" ;; 3) TYPE="PHY" ;; 4) TYPE="CPU" ;; 5) TYPE="Ambience" ;; esac name=$(clean_name $TYPE) if [ "$TYPE" != "NA" ]; then echo "temp_$name.label $TYPE"; fi done exit 0 fi for i in 1 2 3 4 5; do case $i in 1) TYPE="Under PCB" VALUE=$(head -1 /dev/ttyACM0 | awk '{print $1}') ;; 2) TYPE="HDD" VALUE=$(head -1 /dev/ttyACM0 | awk '{print $2}') ;; 3) TYPE="PHY" VALUE=$(head -1 /dev/ttyACM0 | awk '{print $3}') ;; 4) TYPE="CPU" VALUE=$(head -1 /dev/ttyACM0 | awk '{print $4}') ;; 5) TYPE="Ambience" VALUE=$(head -1 /dev/ttyACM0 | awk '{print $5}') ;; esac name=$(clean_name $TYPE) if [ "$TYPE" != "NA" ]; then echo "temp_$name.value $VALUE" fi

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  • Prevent Chrome from automatically opening downloaded PDF and Image files

    - by Phoenix
    When I download a PDF or image in Google Chrome on my Mac, is it possible to prevent Chrome from automatically opening it in my default application for that file type (e.g., Preview)? I notice that Chrome does not do this for other downloaded files such as audio and ZIP archives. I still want to be able to preview files in Chrome; I just want to prevent it from automatically launching my image/PDF viewer application after I download them. For example: I click on a link in an email to a PDF document or an image file. Chrome displays the contents in the browser. I press Cmd-S and save the file to my computer. When the download finishes, the file opens automatically in Preview.app. It's that last step that I would like to bypass.

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  • Problem installing CanonMF5880dn

    - by Paul
    Just got a CanonMF5880dn and cannot print to it from Suse 11.1 MacBook prints w/o issue ping 192.168.1.103 no problem cups sees it as Canon MF5880/MF5840 PCL at URI socket://192.168.1.103:9100 cups test print appears to submit and complete job but no action from printer Yast also seems to install printer correctly CQue2 also seems to install printer correctly all attempts to print yield same results: Suse indicates job processed correctly and completely but no printing happens. firewall is off http://192.168.1.103 in FF gives me the printer config menus correctly What have I failed to do?

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  • Tool or website or process to display previews of website templates residing in archive files?

    - by Tony_Henrich
    I have hundreds of website templates in rar or zip files. To view any of them I have to extract the archive to a temporary folder and then view the template in there. It's a time consuming manual process to do this for each template Is there a tool which enables me to quickly preview the templates in the files? OR (if I extract each template into a separate folder off a master folder) A web app which can enable previewing of each template by automatically creating a link or a preview image (similar to template sites) of the home page for? OR any method to preview the templates in the fastest convenient way possible?

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  • Pictures Are Printed Extremely Dark

    - by Sam
    Problem I printed a picture using Windows Photo Viewer, and the resulting print was significantly darker than the original image. It was almost completely black. I'm using a Brother HL-2270DW printer. Troubleshooting Checked Windows's Colour Profile for printer: not set Checked available installed colour profiles: didn't see specific to this printer What doesn't work Printing it from Windows Photo Viewer Printing it from Paint.NET What works The printer's built-in self-test print page Windows's test print page Printing text from Notepad++ So the problem might be specific to: How Windows prints photos/pictures The picture How the printer prints photos/pictures

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  • Okular (on Ubuntu 9.10) prints multiple pages per sheet (n-up) very small

    - by user23884
    I'm trying to print a set of beamer slides with multiple slides per page (4-up or 6-up). When I select 4 pages or 6 pages per sheet in the Okular print dialog, the pages print quite small (perhaps even tiny -- about 1.75" by 1.25") and leave significant white-space on the page. I can get around this behavior by using the pdfnup utility (in the pdfjam package); which will correctly generate a 4- or 6-up pdf file but it's annoying to generate a second pdf file when I should be able to accomplish this task from the print dialog. Details: Ubuntu 9.10 (Karmic), 64-bit, Color Postscript printer.

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  • Only show changed files while syncing from ext4 to NTFS

    - by qox
    I would like rsync to print modified and deleted files. The verbose option (-v) does print modified files but also the list of subdirectories, maybe because touched directories are considered modified. Since I sync a lot of files from a lot of subdirectories, it's impossible to see the actual changes. So, is there a way to not print directories using rsync ? Im not looking for grep -v "*/$" kind of answers since it would also exclude new directories. Command I am using: rsync -avh --delete /media/data/src /media/data/bkp And everytime it prints the list of all directories: src/dir1/ src/dir1/sdir1/ src/dir1/sdir2/ src/dir2/ ..... Thanks for your help. EDIT: Ok, after some intensive tests .. It doesn't print all directories when syncing from an ext4 partition to an ext4 and from NTFS to NTFS. It only does when syncing from ext4 to NTFS .. And options '-c' or '--omit-dir-times' don't change that.

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  • how to change the existing printed line in AWK

    - by manimaran
    Hi, when i execute the following line, its prints the words in newline. awk 'BEGIN { print "line one\nline two\nline three" }' like line one line two line three How can i print the info in the same line with flush the existing line. For example, while executing the loop, it should print 'one' then wipe out the line and prints 'two' then wipe out the line and prints 'three' etc. can you please assist me?

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  • WMD editor freezes IE7 for 3 seconds on load

    - by dhruvbird
    Hello all, I am using the WMD editor's original code(not the stackoverflow version) since I need multiple of 'em on the same page and stackoverflow's version makes heavy use of element IDs internally since they aren't going to be having more than one editor instance per page. The code runs fin in FF 3.5, etc.. However, when I run it in IE8 (in IE7 compatibility mode), it freezes the whole browser for about 3 sec. before a new instance shows up. I tried profiling it with IE's dev. tools, and it seems that the getWidth() function on line 520 of the minified version of the code is taking up all the time. However, when I tried to hard-code the return (since it was always returning the same thing), the bottleneck shifted to the getHeight() function. I am attaching the code I am using to convert it to a jQuery plugin. jQuery.fn.wmd = function(params) { function createInstance(container, params) { /* Make sure WMD has finished loading */ if (!Attacklab || !Attacklab.wmd) { alert("WMD hasn't finished loading!"); return; } var defaultParams = { width : "600px", rows : 6, autogrow : false, preview : false, previewDivClassName: "wmd-preview-div" }; if (typeof(params) == "undefined") { var params = defaultParams; } else { var params = jQuery.extend({}, defaultParams, params); } /* Build the DOM elements */ var textarea = document.createElement("textarea"); textarea.style.width = params.width; textarea.rows = params.rows; jQuery(container).append(textarea); var previewDiv = document.createElement("div"); if (params.preview) { jQuery(previewDiv).addClass(params.previewDivClassName); jQuery(container).append(previewDiv); } /* Build the preview manager */ var panes = {input:textarea, preview:previewDiv, output:null}; var previewManager = new Attacklab.wmd.previewManager(panes); /* Build the editor and tell it to refresh the preview after commands */ var editor = new Attacklab.wmd.editor(textarea,previewManager.refresh); /* Save everything so we can destroy it all later */ var wmdInstance = {ta:textarea, div:previewDiv, ed:editor, pm:previewManager}; var wmdInstanceId = $(container).attr('postID'); wmdInstanceProcs.add(wmdInstanceId, wmdInstance); if (params.autogrow) { // $(textarea).autogrow(); } }; if (jQuery(this).html().length > 0) { var wmdInstanceId = jQuery(this).attr('postID'); var inst = wmdInstanceProcs.get(wmdInstanceId); jQuery(inst.ta).show(); } else { createInstance(this, params); } } jQuery.fn.unwmd = function(params) { var wmdInstanceId = $(this).attr('postID'); var inst = wmdInstanceProcs.get(wmdInstanceId); if (inst != null) { jQuery(inst.ta).hide(); } } wmdInstanceProcs = function() { var wmdInstances = { }; var getProc = function(wmdInstanceId) { var inst = wmdInstances[wmdInstanceId]; if (typeof(inst) != "undefined") { return inst; } else { return null; } }; var addProc = function(wmdInstanceId, wmdInstance) { wmdInstances[wmdInstanceId] = wmdInstance; }; return { add: addProc, get: getProc }; }(); Any help would be much appreciated.

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  • Maze not being random.

    - by Matt Habel
    Hey there, I am building a program that generates a maze so I can later translate the path to my graphical part. I have most of it working, however, every time you can just take the east and south routes, and you'll get to the end. Even if I set the width as high as 64, so the maze is 64*64, I'm able to choose those 2 options and get to the end every time. I really don't understand why it is doing that. The code is below, it's fairly easy to understand. import random width = 8 def check(x,y): """Figures out the directions that Gen can move while""" if x-1 == -1: maze[x][y][3] = 0 if x+1 == width + 1: maze[x][y][1] = 0 if y+1 == width + 1: maze[x][y][2] = 0 if y-1 == -1: maze[x][y][0] = 0 if x + 1 in range(0,width) and visited[x+1][y] == False: maze[x][y][1] = 2 if x - 1 in range(0,width) and visited[x-1][y] == False: maze[x][y][3] = 2 if y + 1 in range(0,width) and visited[x][y+1] == False: maze[x][y][2] = 2 if y - 1 in range(0,width) and visited[x][y-1] == False: maze[x][y][0] = 2 def possibleDirs(x,y): """Figures out the ways that the person can move in each square""" dirs = [] walls = maze[x][y] if walls[0] == 1: dirs.append('n') if walls[1] == 1: dirs.append('e') if walls[2] == 1: dirs.append('s') if walls[3] == 1: dirs.append('w') return dirs def Gen(x,y): """Generates the maze using a depth-first search and recursive backtracking.""" visited[x][y] = True dirs = [] check(x,y) if maze[x][y][0] == 2: dirs.append(0) if maze[x][y][1] == 2: dirs.append(1) if maze[x][y][2] == 2: dirs.append(2) if maze[x][y][3] == 2: dirs.append(3) print dirs if len(dirs): #Randonly selects a derection for the current square to move past.append(current[:]) pos = random.choice(dirs) maze[x][y][pos] = 1 if pos == 0: current[1] -= 1 maze[x][y-1][2] = 1 if pos == 1: current[0] += 1 maze[x+1][y][3] = 1 if pos == 2: current[1] += 1 maze[x][y+1][0] = 1 if pos == 3: current[0] -= 1 maze[x-1][y][1] = 1 else: #If there's nowhere to go, go back one square lastPlace = past.pop() current[0] = lastPlace[0] current[1] = lastPlace[1] #Build the initial values for the maze to be replaced later maze = [] visited = [] past = [] #Generate empty 2d list with a value for each of the xy coordinates for i in range(0,width): maze.append([]) for q in range(0, width): maze[i].append([]) for n in range(0, 4): maze[i][q].append(4) #Makes a list of falses for all the non visited places for x in range(0, width): visited.append([]) for y in range(0, width): visited[x].append(False) dirs = [] print dirs current = [0,0] #Generates the maze so every single square has been filled. I'm not sure how this works, as it is possible to only go south and east to get to the final position. while current != [width-1, width-1]: Gen(current[0], current[1]) #Getting the ways the person can move in each square for i in range(0,width): dirs.append([]) for n in range(0,width): dirs[i].append([]) dirs[i][n] = possibleDirs(i,n) print dirs print visited pos = [0,0] #The user input part of the maze while pos != [width - 1, width - 1]: dirs = [] print pos if maze[pos[0]][pos[1]][0] == 1: dirs.append('n') if maze[pos[0]][pos[1]][1] == 1: dirs.append('e') if maze[pos[0]][pos[1]][2] == 1: dirs.append('s') if maze[pos[0]][pos[1]][3] == 1: dirs.append('w') print dirs path = raw_input("What direction do you want to go: ") if path not in dirs: print "You can't go that way!" continue elif path.lower() == 'n': pos[1] -= 1 elif path.lower() == 'e': pos[0] += 1 elif path.lower() == 's': pos[1] += 1 elif path.lower() == 'w': pos[0] -= 1 print"Good job!" As you can see, I think the problem is at the point where I generate the maze, however, when I just have it go until the current point is at the end, it doesn't fill every maze and is usually just one straight path. Thanks for helping. Update: I have changed the for loop that generates the maze to a simple while loop and it seems to work much better. It seems that when the for loop ran, it didn't go recursively, however, in the while loop it's perfectly fine. However, now all the squares do not fill out.

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  • Best style for Python programs: what do you suggest?

    - by Noctis Skytower
    A friend of mine wanted help learning to program, so he gave me all the programs that he wrote for his previous classes. The last program that he wrote was an encryption program, and after rewriting all his programs in Python, this is how his encryption program turned out (after adding my own requirements). #! /usr/bin/env python ################################################################################ """\ CLASS INFORMATION ----------------- Program Name: Program 11 Programmer: Stephen Chappell Instructor: Stephen Chappell for CS 999-0, Python Due Date: 17 May 2010 DOCUMENTATION ------------- This is a simple encryption program that can encode and decode messages.""" ################################################################################ import sys KEY_FILE = 'Key.txt' BACKUP = '''\ !"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNO\ PQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~ _@/6-UC'GzaV0%5Mo9g+yNh8b">Bi=<Lx [sQn#^R.D2Xc(\ Jm!4e${lAEWud&t7]H\`}pvPw)FY,Z~?qK|3SOfk*:1;jTrI''' ################################################################################ def main(): "Run the program: loads key, runs processing loop, and saves key." encode_map, decode_map = load_key(KEY_FILE) try: run_interface_loop(encode_map, decode_map) except SystemExit: pass save_key(KEY_FILE, encode_map) def run_interface_loop(encode_map, decode_map): "Shows the menu and runs the appropriate command." print('This program handles encryption via a customizable key.') while True: print('''\ MENU ==== (1) Encode (2) Decode (3) Custom (4) Finish''') switch = get_character('Select: ', tuple('1234')) FUNC[switch](encode_map, decode_map) def get_character(prompt, choices): "Gets a valid menu option and returns it." while True: sys.stdout.write(prompt) sys.stdout.flush() line = sys.stdin.readline()[:-1] if not line: sys.exit() if line in choices: return line print(repr(line), 'is not a valid choice.') ################################################################################ def load_key(filename): "Gets the key file data and returns encoding/decoding dictionaries." plain, cypher = open_file(filename) return dict(zip(plain, cypher)), dict(zip(cypher, plain)) def open_file(filename): "Load the keys and tries to create it when not available." while True: try: with open(filename) as file: plain, cypher = file.read().split('\n') return plain, cypher except: with open(filename, 'w') as file: file.write(BACKUP) def save_key(filename, encode_map): "Dumps the map into two buffers and saves them to the key file." plain = cypher = str() for p, c in encode_map.items(): plain += p cypher += c with open(filename, 'w') as file: file.write(plain + '\n' + cypher) ################################################################################ def encode(encode_map, decode_map): "Encodes message for the user." print('Enter your message to encode (EOF when finished).') message = get_message() for char in message: sys.stdout.write(encode_map[char] if char in encode_map else char) def decode(encode_map, decode_map): "Decodes message for the user." print('Enter your message to decode (EOF when finished).') message = get_message() for char in message: sys.stdout.write(decode_map[char] if char in decode_map else char) def custom(encode_map, decode_map): "Allows user to edit the encoding/decoding dictionaries." plain, cypher = get_new_mapping() for p, c in zip(plain, cypher): encode_map[p] = c decode_map[c] = p ################################################################################ def get_message(): "Gets and returns text entered by the user (until EOF)." buffer = [] while True: line = sys.stdin.readline() if line: buffer.append(line) else: return ''.join(buffer) def get_new_mapping(): "Prompts for strings to edit encoding/decoding maps." while True: plain = get_unique_chars('What do you want to encode from?') cypher = get_unique_chars('What do you want to encode to?') if len(plain) == len(cypher): return plain, cypher print('Both lines should have the same length.') def get_unique_chars(prompt): "Gets strings that only contain unique characters." print(prompt) while True: line = input() if len(line) == len(set(line)): return line print('There were duplicate characters: please try again.') ################################################################################ # This map is used for dispatching commands in the interface loop. FUNC = {'1': encode, '2': decode, '3': custom, '4': lambda a, b: sys.exit()} ################################################################################ if __name__ == '__main__': main() For all those Python programmers out there, your help is being requested. How should the formatting (not necessarily the coding by altered to fit Python's style guide? My friend does not need to be learning things that are not correct. If you have suggestions on the code, feel free to post them to this wiki as well.

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  • Differing styles in Python program: what do you suggest?

    - by Noctis Skytower
    A friend of mine wanted help learning to program, so he gave me all the programs that he wrote for his previous classes. The last program that he wrote was an encryption program, and after rewriting all his programs in Python, this is how his encryption program turned out (after adding my own requirements). #! /usr/bin/env python ################################################################################ """\ CLASS INFORMATION ----------------- Program Name: Program 11 Programmer: Stephen Chappell Instructor: Stephen Chappell for CS 999-0, Python Due Date: 17 May 2010 DOCUMENTATION ------------- This is a simple encryption program that can encode and decode messages.""" ################################################################################ import sys KEY_FILE = 'Key.txt' BACKUP = '''\ !"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNO\ PQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuvwxyz{|}~ _@/6-UC'GzaV0%5Mo9g+yNh8b">Bi=<Lx [sQn#^R.D2Xc(\ Jm!4e${lAEWud&t7]H\`}pvPw)FY,Z~?qK|3SOfk*:1;jTrI''' ################################################################################ def main(): "Run the program: loads key, runs processing loop, and saves key." encode_map, decode_map = load_key(KEY_FILE) try: run_interface_loop(encode_map, decode_map) except SystemExit: pass save_key(KEY_FILE, encode_map) def run_interface_loop(encode_map, decode_map): "Shows the menu and runs the appropriate command." print('This program handles encryption via a customizable key.') while True: print('''\ MENU ==== (1) Encode (2) Decode (3) Custom (4) Finish''') switch = get_character('Select: ', tuple('1234')) FUNC[switch](encode_map, decode_map) def get_character(prompt, choices): "Gets a valid menu option and returns it." while True: sys.stdout.write(prompt) sys.stdout.flush() line = sys.stdin.readline()[:-1] if not line: sys.exit() if line in choices: return line print(repr(line), 'is not a valid choice.') ################################################################################ def load_key(filename): "Gets the key file data and returns encoding/decoding dictionaries." plain, cypher = open_file(filename) return dict(zip(plain, cypher)), dict(zip(cypher, plain)) def open_file(filename): "Load the keys and tries to create it when not available." while True: try: with open(filename) as file: plain, cypher = file.read().split('\n') return plain, cypher except: with open(filename, 'w') as file: file.write(BACKUP) def save_key(filename, encode_map): "Dumps the map into two buffers and saves them to the key file." plain = cypher = str() for p, c in encode_map.items(): plain += p cypher += c with open(filename, 'w') as file: file.write(plain + '\n' + cypher) ################################################################################ def encode(encode_map, decode_map): "Encodes message for the user." print('Enter your message to encode (EOF when finished).') message = get_message() for char in message: sys.stdout.write(encode_map[char] if char in encode_map else char) def decode(encode_map, decode_map): "Decodes message for the user." print('Enter your message to decode (EOF when finished).') message = get_message() for char in message: sys.stdout.write(decode_map[char] if char in decode_map else char) def custom(encode_map, decode_map): "Allows user to edit the encoding/decoding dictionaries." plain, cypher = get_new_mapping() for p, c in zip(plain, cypher): encode_map[p] = c decode_map[c] = p ################################################################################ def get_message(): "Gets and returns text entered by the user (until EOF)." buffer = [] while True: line = sys.stdin.readline() if line: buffer.append(line) else: return ''.join(buffer) def get_new_mapping(): "Prompts for strings to edit encoding/decoding maps." while True: plain = get_unique_chars('What do you want to encode from?') cypher = get_unique_chars('What do you want to encode to?') if len(plain) == len(cypher): return plain, cypher print('Both lines should have the same length.') def get_unique_chars(prompt): "Gets strings that only contain unique characters." print(prompt) while True: line = input() if len(line) == len(set(line)): return line print('There were duplicate characters: please try again.') ################################################################################ # This map is used for dispatching commands in the interface loop. FUNC = {'1': encode, '2': decode, '3': custom, '4': lambda a, b: sys.exit()} ################################################################################ if __name__ == '__main__': main() For all those Python programmers out there, your help is being requested. How should the formatting (not necessarily the coding by altered to fit Python's style guide? My friend does not need to be learning things that are not correct. If you have suggestions on the code, feel free to post them to this wiki as well.

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  • [BEGINNER] Javascript Pop Ups

    - by user566312
    Hey All, My boss has asked for a page that will not change to have two timed pop ups load. I have found code and edited it to what I had thought it should do, but it is only loading the last onLoad event. I am a designer and I have helped with making webpages, but Javascript is so far outside of what I can understand. I have already learned how to use the single pop up and spent a whiiile learning the timeouts, but I cannot seem to get it to work with multiple popup functions. If you have a moment, would you take a look? Thank you :) h <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>H's Page 1</title> <SCRIPT LANGUAGE="JavaScript"> <!-- Original: Ronnie T. Moore, Editor --> <!-- Web Site: The JavaScript Source --> <!-- This script and many more are available free online at --> <!-- The JavaScript Source!! http://javascript.internet.com --> <!-- Begin closetime = 3; // Close window after __ number of seconds? // 0 = do not close, anything else = number of seconds function Start1(URL, WIDTH, HEIGHT) { windowprops = "left=50,top=50,width=" + WIDTH + ",height=" + HEIGHT; preview = window.open(URL, "preview", windowprops); if (closetime) setTimeout("preview.close();", closetime*1000); } function doPopup1() { url = "http://www.google.com"; width = 1680; // width of window in pixels height = 1050; // height of window in pixels delay = 10; // time in seconds before popup opens timer = setTimeout("Start1(url, width, height)", delay*1000); } closetime = 3; // Close window after __ number of seconds? function Start2(URL, WIDTH, HEIGHT) { windowprops = "left=50,top=50,width=" + WIDTH + ",height=" + HEIGHT; preview = window.open(URL, "preview", windowprops); if (closetime) setTimeout("preview.close();", closetime*1000); } function doPopup2() { url = "http://www.yahoo.com"; width = 1680; // width of window in pixels height = 1050; // height of window in pixels delay = 5; // time in seconds before popup opens timer = setTimeout("Start2(url, width, height)", delay*1000); } // End --> </script> <!-- STEP TWO: Insert the onLoad event handler into your BODY tag --> <!-- Script Size: 1.27 KB --> </head> <body OnLoad="doPopup1(); doPopup2();"> <p>My page text.</p> <p>My page text.</p> <p>My page text.</p> <p>My page text.</p> </body> </html>

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  • Reading a user input (character or string of letters) into ggplot command inside a switch statement or a nested ifelse (with functions in it)

    - by statisticalbeginner
    I have code like AA <- as.integer(readline("Select any number")) switch(AA, 1={ num <-as.integer(readline("Select any one of the options \n")) print('You have selected option 1') #reading user data var <- readline("enter the variable name \n") #aggregating the data based on required condition gg1 <- aggregate(cbind(get(var))~Mi+hours,a, FUN=mean) #Ploting ggplot(gg1, aes(x = hours, y = get(var), group = Mi, fill = Mi, color = Mi)) + geom_point() + geom_smooth(stat="smooth", alpha = I(0.01)) }, 2={ print('bar') }, { print('default') } ) The dataset is [dataset][1] I have loaded the dataset into object list a <- read.table(file.choose(), header=FALSE,col.names= c("Ei","Mi","hours","Nphy","Cphy","CHLphy","Nhet","Chet","Ndet","Cdet","DON","DOC","DIN","DIC","AT","dCCHO","TEPC","Ncocco","Ccocco","CHLcocco","PICcocco","par","Temp","Sal","co2atm","u10","dicfl","co2ppm","co2mol","pH")) I am getting error like source ("switch_statement_check.R") Select any one of the options 1 [1] "You have selected option 1" enter the variable name Nphy Error in eval(expr, envir, enclos) : (list) object cannot be coerced to type 'double' > gg1 is getting data that is fine. I dont know what to do to make the variable entered by user to work in that ggplot command. Please suggest any solution for this. The dput output structure(list(Ei = c(1L, 1L, 1L, 1L, 1L, 1L), Mi = c(1L, 1L, 1L, 1L, 1L, 1L), hours = 1:6, Nphy = c(0.1023488, 0.104524, 0.1064772, 0.1081702, 0.1095905, 0.110759), Cphy = c(0.6534707, 0.6448216, 0.6369597, 0.6299084, 0.6239005, 0.6191941), CHLphy = c(0.1053458, 0.110325, 0.1148174, 0.1187672, 0.122146, 0.1249877), Nhet = c(0.04994161, 0.04988347, 0.04982555, 0.04976784, 0.04971029, 0.04965285), Chet = c(0.3308593, 0.3304699, 0.3300819, 0.3296952, 0.3293089, 0.3289243), Ndet = c(0.04991916, 0.04984045, 0.04976363, 0.0496884, 0.04961446, 0.04954156), Cdet = c(0.3307085, 0.3301691, 0.3296314, 0.3290949, 0.3285598, 0.3280252), DON = c(0.05042275, 0.05085697, 0.05130091, 0.05175249, 0.05220978, 0.05267118 ), DOC = c(49.76304, 49.52745, 49.29323, 49.06034, 48.82878, 48.59851), DIN = c(14.9933, 14.98729, 14.98221, 14.9781, 14.97485, 14.97225), DIC = c(2050.132, 2050.264, 2050.396, 2050.524, 2050.641, 2050.758), AT = c(2150.007, 2150.007, 2150.007, 2150.007, 2150.007, 2150.007), dCCHO = c(0.964222, 0.930869, 0.8997098, 0.870544, 0.843196, 0.8175117), TEPC = c(0.1339044, 0.1652179, 0.1941872, 0.2210289, 0.2459341, 0.2690721), Ncocco = c(0.1040715, 0.1076058, 0.1104229, 0.1125141, 0.1140222, 0.1151228), Ccocco = c(0.6500288, 0.6386706, 0.6291149, 0.6213265, 0.6152447, 0.6108502), CHLcocco = c(0.1087667, 0.1164099, 0.1225822, 0.1273103, 0.1308843, 0.1336465), PICcocco = c(0.1000664, 0.1001396, 0.1007908, 0.101836, 0.1034179, 0.1055634), par = c(0, 0, 0.8695131, 1.551317, 2.777707, 4.814341), Temp = c(9.9, 9.9, 9.9, 9.9, 9.9, 9.9), Sal = c(31.31, 31.31, 31.31, 31.31, 31.31, 31.31), co2atm = c(370, 370, 370, 370, 370, 370), u10 = c(0.01, 0.01, 0.01, 0.01, 0.01, 0.01), dicfl = c(-2.963256, -2.971632, -2.980446, -2.989259, -2.997877, -3.005702), co2ppm = c(565.1855, 565.7373, 566.3179, 566.8983, 567.466, 567.9814), co2mol = c(0.02562326, 0.02564828, 0.0256746, 0.02570091, 0.02572665, 0.02575002 ), pH = c(7.879427, 7.879042, 7.878636, 7.878231, 7.877835, 7.877475)), .Names = c("Ei", "Mi", "hours", "Nphy", "Cphy", "CHLphy", "Nhet", "Chet", "Ndet", "Cdet", "DON", "DOC", "DIN", "DIC", "AT", "dCCHO", "TEPC", "Ncocco", "Ccocco", "CHLcocco", "PICcocco", "par", "Temp", "Sal", "co2atm", "u10", "dicfl", "co2ppm", "co2mol", "pH"), row.names = c(NA, 6L), class = "data.frame") As per the below suggestions I have tried a lot but it is not working. Summarizing I will say: var <- readline("enter a variable name") I cant use get(var) inside any command but not inside ggplot, it wont work. gg1$var it also doesnt work, even after changing the column names. Does it have a solution or should I just choose to import from an excel sheet, thats better? Tried with if else and functions fun1 <- function() { print('You have selected option 1') my <- as.character((readline("enter the variable name \n"))) gg1 <- aggregate(cbind(get(my))~Mi+hours,a, FUN=mean) names(gg1)[3] <- my #print(names(gg1)) ggplot (gg1,aes_string(x="hours",y=(my),group="Mi",color="Mi")) + geom_point() } my <- as.integer(readline("enter a number")) ifelse(my == 1,fun1(),"") ifelse(my == 2,print ("its 2"),"") ifelse(my == 3,print ("its 3"),"") ifelse(my != (1 || 2|| 3) ,print("wrong number"),"") Not working either...:(

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  • How can I share Perl data structures through a socket?

    - by pavun_cool
    In sockets I have written the client server program. First I tried to send the normal string among them it sends fine. After that I tried to send the hash and array values from client to server and server to client. When I print the values using Dumper, it gives me only the reference value. What should I do to get the actual values in client server? Server Program: use IO::Socket; use strict; use warnings; my %hash = ( "name" => "pavunkumar " , "age" => 20 ) ; my $new = \%hash ; #Turn on System variable for Buffering output $| = 1; # Creating a a new socket my $socket= IO::Socket::INET->new(LocalPort=>5000,Proto=>'tcp',Localhost => 'localhost','Listen' => 5 , 'Reuse' => 1 ); die "could not create $! \n" unless ( $socket ); print "\nUDPServer Waiting port 5000\n"; my $new_sock = $socket->accept(); my $host = $new_sock->peerhost(); while(<$new_sock>) { #my $line = <$new_sock>; print Dumper "$host $_"; print $new_sock $new . "\n"; } print "$host is closed \n" ; Client Program use IO::Socket; use Data::Dumper ; use warnings ; use strict ; my %hash = ( "file" =>"log.txt" , size => "1000kb") ; my $ref = \%hash ; # This client for connecting the specified below address and port # INET function will create the socket file and establish the connection with # server my $port = shift || 5000 ; my $host = shift || 'localhost'; my $recv_data ; my $send_data; my $socket = new IO::Socket::INET ( PeerAddr => $host , PeerPort => $port , Proto => 'tcp', ) or die "Couldn't connect to Server\n"; while (1) { my $line = <stdin> ; print $socket $ref."\n"; if ( $line = <$socket> ) { print Dumper $line ; } else { print "Server is closed \n"; last ; } } I have given my sample program about what I am doing. Can any one tell me what I am doing wrong in this code? And what I need to do for accessing the hash values?

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  • (This is for a project, so yes it is homework) How would I finish this java code?

    - by user2924318
    The task is to create arrays using user input (which I was able to do), then for the second part, use a separate method to sort the array in ascending order then output it. I have gotten it to do everything I need except I don't know how I would get it to sort. The directions say to use a while loop from 0 to the length to find the minimum value then swap that with the 1st, but I don't know how to do this. This is what I have so far: public static void main(String[] args) { Scanner in = new Scanner(System.in); int storage = getNumDigits(in); if(storage == 0){ System.out.print("No digits to store? OK, goodbye!"); System.exit(0); } int []a = new int [storage]; a = getDigits(a, in); displayDigits(a); selectionSort(a); } private static int getNumDigits(Scanner inScanner) { System.out.print("Please enter the number of digits to be stored: "); int stored = inScanner.nextInt(); while(stored < 0){ System.out.println("ERROR! You must enter a non-negative number of digits!"); System.out.println(); System.out.print("Please enter the number of digits to be stored: "); stored = inScanner.nextInt(); } return stored; } private static int[] getDigits(int[] digits, Scanner inScanner) { int length = digits.length; int count = 0; int toBeStored = 0; while(count < length){ System.out.print("Enter integer " +count +": "); toBeStored = inScanner.nextInt(); digits[count] = toBeStored; count++; } return digits; } private static void displayDigits(int[] digits) { int len = digits.length; System.out.println(); System.out.println("Array before sorting:"); System.out.println("Number of digits in array: " +len); System.out.print("Digits in array: "); for(int cnt = 0; cnt < len-1; cnt++){ System.out.print(digits[cnt] + ", "); } System.out.println(digits[len-1]); } private static void selectionSort(int[] digits) { int l = digits.length; System.out.println(); System.out.println("Array after sorting:"); System.out.println("Number of digits in array: " +l); System.out.print("Digits in array: "); int index = 0; int value = digits[0]; int indVal = digits[index]; while(index < l){ indVal = digits[index]; if(indVal <= value){ indVal = value; digits[index] = value; index++; } else if(value < indVal){ index++; } System.out.print(value); //This is where I don't know what to do. } }

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