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  • globals and locals in python exec()

    - by hawkettc
    Hi, I'm trying to run a piece of python code using exec. my_code = """ class A(object): pass print 'locals: %s' % locals() print 'A: %s' % A class B(object): a_ref = A """ global_env = {} local_env = {} my_code_AST = compile(my_code, "My Code", "exec") exec(my_code_AST, global_env, local_env) print local_env which results in the following output locals: {'A': <class 'A'>} A: <class 'A'> Traceback (most recent call last): File "python_test.py", line 16, in <module> exec(my_code_AST, global_env, local_env) File "My Code", line 8, in <module> File "My Code", line 9, in B NameError: name 'A' is not defined However, if I change the code to this - my_code = """ class A(object): pass print 'locals: %s' % locals() print 'A: %s' % A class B(A): pass """ global_env = {} local_env = {} my_code_AST = compile(my_code, "My Code", "exec") exec(my_code_AST, global_env, local_env) print local_env then it works fine - giving the following output - locals: {'A': <class 'A'>} A: <class 'A'> {'A': <class 'A'>, 'B': <class 'B'>} Clearly A is present and accessible - what's going wrong in the first piece of code? I'm using 2.6.5, cheers, Colin * UPDATE 1 * If I check the locals() inside the class - my_code = """ class A(object): pass print 'locals: %s' % locals() print 'A: %s' % A class B(object): print locals() a_ref = A """ global_env = {} local_env = {} my_code_AST = compile(my_code, "My Code", "exec") exec(my_code_AST, global_env, local_env) print local_env Then it becomes clear that locals() is not the same in both places - locals: {'A': <class 'A'>} A: <class 'A'> {'__module__': '__builtin__'} Traceback (most recent call last): File "python_test.py", line 16, in <module> exec(my_code_AST, global_env, local_env) File "My Code", line 8, in <module> File "My Code", line 10, in B NameError: name 'A' is not defined However, if I do this, there is no problem - def f(): class A(object): pass class B(object): a_ref = A f() print 'Finished OK' * UPDATE 2 * ok, so the docs here - http://docs.python.org/reference/executionmodel.html 'A class definition is an executable statement that may use and define names. These references follow the normal rules for name resolution. The namespace of the class definition becomes the attribute dictionary of the class. Names defined at the class scope are not visible in methods.' It seems to me that 'A' should be made available as a free variable within the executable statement that is the definition of B, and this happens when we call f(), but not when we use exec(). This can be more easily shown with the following - my_code = """ class A(object): pass print 'locals in body: %s' % locals() print 'A: %s' % A def f(): print 'A in f: %s' % A f() class B(object): a_ref = A """ which outputs locals in body: {'A': <class 'A'>} A: <class 'A'> Traceback (most recent call last): File "python_test.py", line 20, in <module> exec(my_code_AST, global_env, local_env) File "My Code", line 11, in <module> File "My Code", line 9, in f NameError: global name 'A' is not defined So I guess the new question is - why aren't those locals being exposed as free variables in functions and class definitions - it seems like a pretty standard closure scenario.

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  • Why does my Perl CGI script cause a 500 internal server error?

    - by Nitish
    I get a 500 internal server error when I try to run the code below in a web server which supports perl: #! /usr/bin/perl use LWP; my $ua = LWP::UserAgent->new; $ua->agent("TestApp/0.1 "); $ua->env_proxy(); my $req = HTTP::Request->new(POST => 'http://www.google.com/loc/json'); $req->content_type('application/jsonrequest'); $req->content('{ "cell_towers": [{"location_area_code": "55000", "mobile_network_code": "95", "cell_id": "20491", "mobile_country_code": "404"}], "version": "1.1.0", "request_address": "true"}'); my $res = $ua->request($req); if ($res->is_success) { print $res->content,"\n"; } else { print $res->status_line, "\n"; return undef; } But there is no error when I run the code below: #! /usr/bin/perl use CGI::Carp qw(fatalsToBrowser); print "Content-type: text/html\n\n"; print "<HTML>\n"; print "<HEAD><TITLE>Hello World!</TITLE></HEAD>\n"; print "<BODY>\n"; print "<H2>Hello World!</H2> <br /> \n"; foreach $key (sort keys(%ENV)) { print "$key = $ENV{$key}<p>" ; } print "</BODY>\n"; print "</HTML>\n"; So I think there is some problem with my code. When I run the first perl script in my local machine with the -wc command, it says that the syntax is OK. Help me please.

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  • Why wont numpy matrix let me print its rows?

    - by uberjumper
    Okay this is probably a really dumb question, however its really starting to hurt. I have a numpy matrix, and basically i print it out row by row. However i want to make each row be formatted and separated properly. >>> arr = numpy.matrix([[x for x in range(5)] for y in range(5)]) >>> arr matrix([[0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4]]) Lets say i want to print the first row, and add a '|' between each element: >>> '|'.join(map(str, arr[0,])) '[[0 1 2 3 4]]' Err... >>> '|'.join(map(lambda x: str(x[0]), arr[0])) '[[0 1 2 3 4]]' I am really confused by this behavior why does it do this?

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  • Perl MiniWebserver

    - by snikolov
    hey guys i have config this miniwebserver, however i require the server to download a file in the local directory i am getting a problem can you please fix my issue thanks !/usr/bin/perl use strict; use Socket; use IO::Socket; my $buffer; my $file; my $length; my $output; Simple web server in Perl Serves out .html files, echos form data sub parse_form { my $data = $_[0]; my %data; foreach (split /&/, $data) { my ($key, $val) = split /=/; $val =~ s/+/ /g; $val =~ s/%(..)/chr(hex($1))/eg; $data{$key} = $val;} return %data; } Setup and create socket my $port = shift; defined($port) or die "Usage: $0 portno\n"; my $DOCUMENT_ROOT = $ENV{'HOME'} . "public"; my $server = new IO::Socket::INET(Proto = 'tcp', LocalPort = $port, Listen = SOMAXCONN, Reuse = 1); $server or die "Unable to create server socket: $!" ; Await requests and handle them as they arrive while (my $client = $server-accept()) { $client-autoflush(1); my %request = (); my %data; { -------- Read Request --------------- local $/ = Socket::CRLF; while (<$client>) { chomp; # Main http request if (/\s*(\w+)\s*([^\s]+)\s*HTTP\/(\d.\d)/) { $request{METHOD} = uc $1; $request{URL} = $2; $request{HTTP_VERSION} = $3; } # Standard headers elsif (/:/) { (my $type, my $val) = split /:/, $_, 2; $type =~ s/^\s+//; foreach ($type, $val) { s/^\s+//; s/\s+$//; } $request{lc $type} = $val; } # POST data elsif (/^$/) { read($client, $request{CONTENT}, $request{'content-length'}) if defined $request{'content-length'}; last; } } } -------- SORT OUT METHOD --------------- if ($request{METHOD} eq 'GET') { if ($request{URL} =~ /(.*)\?(.*)/) { $request{URL} = $1; $request{CONTENT} = $2; %data = parse_form($request{CONTENT}); } else { %data = (); } $data{"_method"} = "GET"; } elsif ($request{METHOD} eq 'POST') { %data = parse_form($request{CONTENT}); $data{"_method"} = "POST"; } else { $data{"_method"} = "ERROR"; } ------- Serve file ---------------------- my $localfile = $DOCUMENT_ROOT.$request{URL}; Send Response if (open(FILE, "<$localfile")) { print $client "HTTP/1.0 200 OK", Socket::CRLF; print $client "Content-type: text/html", Socket::CRLF; print $client Socket::CRLF; my $buffer; while (read(FILE, $buffer, 4096)) { print $client $buffer; } $data{"_status"} = "200"; } else { $file = 'a.pl'; open(INFILE, $file); while (<INFILE>) { $output .= $_; ##output of the file } $length = length($output); print $client "'HTTP/1.0 200 OK", Socket::CRLF; print $client "Content-type: application/octet-stream", Socket::CRLF; print $client "Content-Length:".$length, Socket::CRLF; print $client "Accept-Ranges: bytes", Socket::CRLF; print $client 'Content-Disposition: attachment; filename="test.zip"', Socket::CRLF; print $client $output, Socket::CRLF; print $client 'Content-Transfer-Encoding: binary"', Socket::CRLF; print $client "Connection: Keep-Alive", Socket::CRLF; # #$data{"_status"} = "404"; # } close(FILE); Log Request print ($DOCUMENT_ROOT.$request{URL},"\n"); foreach (keys(%data)) { print (" $_ = $data{$_}\n"); } ----------- Close Connection and loop ------------------ close $client; } END

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  • how to load files in python

    - by Alvaro
    I'm fairly new to python and would like some help on properly loading separate files. My codes purpose is to open a given file, search for customers of that file by the state or state abbreviation. However, i have a separate function to open a separate file where i have (name of state):(state abbreviation) Thanks. def file_state_search(fileid, state): z=0 indx = 0 while z<25: line=fileid.readline() data_list = ("Name:", "Address:", "City:", "State:", "Zipcode:") line_split = line.split(":") if state in line: while indx<5: print data_list[indx], line_split[indx] indx = indx + 1 elif state not in line: z = z + 1 def state_convert(fileid, state): line2=in_file2.readline() while state in line2: print line2 x=1 while x==1: print "Choose an option:" print print "Option '1': Search Record By State" print option = raw_input("Enter an option:") print if option == "1": state = raw_input("Enter A State:") in_file = open("AdrData.txt", 'r') line=in_file.readline() print in_file2 = open("States.txt", 'r') line2=in_file2.readline() converted_state = state_convert(in_file2, state) print converted_state state_find = file_state_search(in_file, state) print state_find x=raw_input("Enter '1' to continue, Enter '2' to stop: ") x=int(x) By the way, my first import statement works, for whatever reason my second one doesn't. Edit: My question is, what am i doing wrong in my state_convert function.

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  • Connection hangs after time of inactivity

    - by Sinuhe
    In my application, Spring manages connection pool for database access. Hibernate uses these connections for its queries. At first glance, I have no problems with the pool: it works correctly with concurrent clients and a pool with only one connection. I can execute a lot of queries, so I think that I (or Spring) don't leave open connections. My problem appears after some time of inactivity (sometimes 30 minutes, sometimes more than 2 hours). Then, when Hibernate does some search, it lasts too much. Setting log4j level to TRACE, I get this logs: ... 18:27:01 DEBUG nsactionSynchronizationManager - Retrieved value [org.springframework.orm.hibernate3.SessionHolder@99abd7] for key [org.hibernate.impl.SessionFactoryImpl@7d2897] bound to thread [http-8080-Processor24] 18:27:01 DEBUG HibernateTransactionManager - Found thread-bound Session [org.hibernate.impl.SessionImpl@8878cd] for Hibernate transaction 18:27:01 DEBUG HibernateTransactionManager - Using transaction object [org.springframework.orm.hibernate3.HibernateTransactionManager$HibernateTransactionObject@1b2ffee] 18:27:01 DEBUG HibernateTransactionManager - Creating new transaction with name [com.acjoventut.service.GenericManager.findByExample]: PROPAGATION_REQUIRED,ISOLATION_DEFAULT 18:27:01 DEBUG HibernateTransactionManager - Preparing JDBC Connection of Hibernate Session [org.hibernate.impl.SessionImpl@8878cd] 18:27:01 TRACE SessionImpl - setting flush mode to: AUTO 18:27:01 DEBUG JDBCTransaction - begin 18:27:01 DEBUG ConnectionManager - opening JDBC connection Here it gets frozen for about 2 - 10 minutes. But then continues: 18:30:11 DEBUG JDBCTransaction - current autocommit status: true 18:30:11 DEBUG JDBCTransaction - disabling autocommit 18:30:11 TRACE JDBCContext - after transaction begin 18:30:11 DEBUG HibernateTransactionManager - Exposing Hibernate transaction as JDBC transaction [jdbc:oracle:thin:@212.31.39.50:30998:orcl, UserName=DEVELOP, Oracle JDBC driver] 18:30:11 DEBUG nsactionSynchronizationManager - Bound value [org.springframework.jdbc.datasource.ConnectionHolder@843a9d] for key [org.apache.commons.dbcp.BasicDataSource@7745fd] to thread [http-8080-Processor24] 18:30:11 DEBUG nsactionSynchronizationManager - Initializing transaction synchronization ... After that, it works with no problems, until another period of inactivity. IMHO, it seems like connection pool returns an invalid/closed connection, and when Hibernate realizes that, ask another connection to the pool. I don't know how can I solve this problem or things I can do for delimiting it. Any help achieving this will be appreciate. Thanks. EDIT: Well, it finally was due a firewall rule. Database detects the connection is lost, but pool (dbcp or c3p0) not. So, it tries to query the database with no success. What is still strange for me is that timeout period is very variable. Maybe the rule is specially strange or firewall doesn't work correctly. Anyway, I have no access to that machine and I can only wait for an explanation. :(

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  • Pymedia video encoding failed

    - by user1474837
    I am using Python 2.5 with Windows XP. I am trying to make a list of pygame images into a video file using this function. I found the function on the internet and edited it. It worked at first, than it stopped working. This is what it printed out: Making video... Formating 114 Frames... starting loop making encoder Frame 1 process 1 Frame 1 process 2 Frame 1 process 2.5 This is the error: Traceback (most recent call last): File "ScreenCapture.py", line 202, in <module> makeVideoUpdated(record_files, video_file) File "ScreenCapture.py", line 151, in makeVideoUpdated d = enc.encode(da) pymedia.video.vcodec.VCodecError: Failed to encode frame( error code is 0 ) This is my code: def makeVideoUpdated(files, outFile, outCodec='mpeg1video', info1=0.1): fw = open(outFile, 'wb') if (fw == None) : print "Cannot open file " + outFile return if outCodec == 'mpeg1video' : bitrate= 2700000 else: bitrate= 9800000 start = time.time() enc = None frame = 1 print "Formating "+str(len(files))+" Frames..." print "starting loop" for img in files: if enc == None: print "making encoder" params= {'type': 0, 'gop_size': 12, 'frame_rate_base': 125, 'max_b_frames': 90, 'height': img.get_height(), 'width': img.get_width(), 'frame_rate': 90, 'deinterlace': 0, 'bitrate': bitrate, 'id': vcodec.getCodecID(outCodec) } enc = vcodec.Encoder(params) # Create VFrame print "Frame "+str(frame)+" process 1" bmpFrame= vcodec.VFrame(vcodec.formats.PIX_FMT_RGB24, img.get_size(), # Covert image to 24bit RGB (pygame.image.tostring(img, "RGB"), None, None) ) print "Frame "+str(frame)+" process 2" # Convert to YUV, then codec da = bmpFrame.convert(vcodec.formats.PIX_FMT_YUV420P) print "Frame "+str(frame)+" process 2.5" d = enc.encode(da) #THIS IS WHERE IT STOPS print "Frame "+str(frame)+" process 3" fw.write(d.data) print "Frame "+str(frame)+" process 4" frame += 1 print "savng file" fw.close() Could somebody tell me why I have this error and possibly how to fix it? The files argument is a list of pygame images, outFile is a path, outCodec is default, and info1 is not used anymore. UPDATE 1 This is the code I used to make that list of pygame images. from PIL import ImageGrab import time, pygame pygame.init() f = [] #This is the list that contains the images fps = 1 for n in range(1, 100): info = ImageGrab.grab() size = info.size mode = info.mode data = info.tostring() info = pygame.image.fromstring(data, size, mode) f.append(info) time.sleep(fps)

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  • Looking for a Regex to get SccTeamFoundationServer value from .sln file

    - by Arthur
    I am looking tor a Regex for C# to get SccTeamFoundationServer value from .sln file. Maybe someone has come across such need and found a solution. Could you help? File: Microsoft Visual Studio Solution File, Format Version 10.00 # Visual Studio 2008 Project("{FAE04EC0-301F-11D3-BF4B-00C04F79EFBC}") = "WebApplication", "WebApplication\WebApplication.csproj", "{AE0F6C02-1C8D-426D-AFA0-C07A52E6112F}" EndProject Project("{FAE04EC0-301F-11D3-BF4B-00C04F79EFBC}") = "ConsoleApplication", "ConsoleApplication\ConsoleApplication.csproj", "{2BD82C34-CF50-4559-A3CD-F85ACD657292}" EndProject Global GlobalSection(TeamFoundationVersionControl) = preSolution SccNumberOfProjects = 3 SccEnterpriseProvider = {4CA58AB2-18FA-4F8D-95D4-32DDF27D184C} SccTeamFoundationServer = http://ServerName:8080/ SccLocalPath0 = . SccProjectUniqueName1 = ConsoleApplication\\ConsoleApplication.csproj SccProjectName1 = ConsoleApplication SccLocalPath1 = ConsoleApplication SccProjectUniqueName2 = WebApplication\\WebApplication.csproj SccProjectName2 = WebApplication SccLocalPath2 = WebApplication EndGlobalSection GlobalSection(SolutionConfigurationPlatforms) = preSolution Debug|Any CPU = Debug|Any CPU Release|Any CPU = Release|Any CPU EndGlobalSection GlobalSection(ProjectConfigurationPlatforms) = postSolution {AE0F6C02-1C8D-426D-AFA0-C07A52E6112F}.Debug|Any CPU.ActiveCfg = Debug|Any CPU {AE0F6C02-1C8D-426D-AFA0-C07A52E6112F}.Debug|Any CPU.Build.0 = Debug|Any CPU {AE0F6C02-1C8D-426D-AFA0-C07A52E6112F}.Release|Any CPU.ActiveCfg = Release|Any CPU {AE0F6C02-1C8D-426D-AFA0-C07A52E6112F}.Release|Any CPU.Build.0 = Release|Any CPU {2BD82C34-CF50-4559-A3CD-F85ACD657292}.Debug|Any CPU.ActiveCfg = Debug|Any CPU {2BD82C34-CF50-4559-A3CD-F85ACD657292}.Debug|Any CPU.Build.0 = Debug|Any CPU {2BD82C34-CF50-4559-A3CD-F85ACD657292}.Release|Any CPU.ActiveCfg = Release|Any CPU {2BD82C34-CF50-4559-A3CD-F85ACD657292}.Release|Any CPU.Build.0 = Release|Any CPU EndGlobalSection GlobalSection(SolutionProperties) = preSolution HideSolutionNode = FALSE EndGlobalSection EndGlobal

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  • Perl 500 internal server error. Something wrong with my code.

    - by Nitish
    I get a 500 internal server error when I try to run the code below in a web server which supports perl: #! /usr/bin/perl use LWP; my $ua = LWP::UserAgent->new; $ua->agent("TestApp/0.1 "); $ua->env_proxy(); my $req = HTTP::Request->new(POST => 'http://www.google.com/loc/json'); $req->content_type('application/jsonrequest'); $req->content('{ "cell_towers": [{"location_area_code": "55000", "mobile_network_code": "95", "cell_id": "20491", "mobile_country_code": "404"}], "version": "1.1.0", "request_address": "true"}'); my $res = $ua->request($req); if ($res->is_success) { print $res->content,"\n"; } else { print $res->status_line, "\n"; return undef; } But there is no error when I run the code below: #! /usr/bin/perl use CGI::Carp qw(fatalsToBrowser); print "Content-type: text/html\n\n"; print "<HTML>\n"; print "<HEAD><TITLE>Hello World!</TITLE></HEAD>\n"; print "<BODY>\n"; print "<H2>Hello World!</H2> <br /> \n"; foreach $key (sort keys(%ENV)) { print "$key = $ENV{$key}<p>" ; } print "</BODY>\n"; print "</HTML>\n"; So I think there is some problem with my code. When I run the first perl script in my local machine with the -wc command, it says that the syntax is OK. Help me please.

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  • Java: Switch statements with methods involving arrays

    - by Shane
    Hi guys I'm currently creating a program that allows the user to create an array, search an array and delete an element from an array. Looking at the LibraryMenu Method, the first case where you create an array in the switch statement works fine, however the other ones create a "cannot find symbol error" when I try to compile. My question is I want the search and delete functions to refer to the first switch case - the create Library array. Any help is appreciated, even if its likely from a simple mistake. import java.util.*; public class EnterLibrary { public static void LibraryMenu() { java.util.Scanner scannerObject =new java.util.Scanner(System.in); LibraryMenu Menu = new LibraryMenu(); Menu.displayMenu(); switch (scannerObject.nextInt() ) { case '1': { System.out.println ("1 - Add Videos"); Library[] newLibrary; newLibrary = createLibrary(); } break; case '2': System.out.println ("2 - Search Videos"); searchLibrary(newLibrary); break; case '3': { System.out.println ("3 - Change Videos"); //Change video method TBA } break; case '4': System.out.println ("4 - Delete Videos"); deleteVideo(newLibrary); break; default: System.out.println ("Unrecognized option - please select options 1-3 "); break; } } public static Library[] createLibrary() { Library[] videos = new Library[4]; java.util.Scanner scannerObject =new java.util.Scanner(System.in); for (int i = 0; i < videos.length; i++) { //User enters values into set methods in Library class System.out.print("Enter video number: " + (i+1) + "\n"); String number = scannerObject.nextLine(); System.out.print("Enter video title: " + (i+1) + "\n"); String title = scannerObject.nextLine(); System.out.print("Enter video publisher: " + (i+1) + "\n"); String publisher = scannerObject.nextLine(); System.out.print("Enter video duration: " + (i+1) + "\n"); String duration = scannerObject.nextLine(); System.out.print("Enter video date: " + (i+1) + "\n"); String date= scannerObject.nextLine(); System.out.print("VIDEO " + (i+1) + " ENTRY ADDED " + "\n \n"); //Initialize arrays videos[i] = new Library (); videos[i].setVideo( number, title, publisher, duration, date ); } return videos; } public static void printVidLibrary( Library[] videos) { //Get methods to print results System.out.print("\n======VIDEO CATALOGUE====== \n"); for (int i = 0; i < videos.length; i++) { System.out.print("Video number " + (i+1) + ": \n" + videos[i].getNumber() + "\n "); System.out.print("Video title " + (i+1) + ": \n" + videos[i].getTitle() + "\n "); System.out.print("Video publisher " + (i+1) + ": \n" + videos[i].getPublisher() + "\n "); System.out.print("Video duration " + (i+1) + ": \n" + videos[i].getDuration() + "\n "); System.out.print("Video date " + (i+1) + ": \n" + videos[i].getDate() + "\n "); } } public static Library searchLibrary( Library[] videos) { //User enters values to setSearch Library titleResult = new Library(); java.util.Scanner scannerObject =new java.util.Scanner(System.in); for (int n = 0; n < videos.length; n++) { System.out.println("Search for video number:\n"); String newSearch = scannerObject.nextLine(); titleResult.getSearch( videos, newSearch); if (!titleResult.equals(-1)) { System.out.print("Match found!\n" + newSearch + "\n"); } else if (titleResult.equals(-1)) { System.out.print("Sorry, no matches found!\n"); } } return titleResult; } public static void deleteVideo( Library[] videos) { Library titleResult = new Library(); java.util.Scanner scannerObject =new java.util.Scanner(System.in); for (int n = 0; n < videos.length; n++) { System.out.println("Search for video number:\n"); String deleteSearch = scannerObject.nextLine(); titleResult.deleteVideo(videos, deleteSearch); System.out.print("Video deleted\n"); } } public static void main(String[] args) { Library[] newLibrary; new LibraryMenu(); } }

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  • How to automatically print the contents of a folder in OS X?

    - by MDRoz
    I would like to be able to set up a folder on my Mac, where I could dump files and have them be automatically sent to the default printer. This way I would be able to print files at home when I'm not physically at home, using something like Dropbox. It wouldn't have to be real-time; i.e., a scheduled job that checks the folder every so often would be acceptable. What's the easiest approach? Automator? Applescript? Cron job?

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  • How to read back and print text with newlines from a Python (Django) string with HTML?

    - by user1801486
    If someone types in a phrase, such as: I see you driving round town with the girl I love, and I’m like: haiku. (no blank lines between each line, but the text is written on three separate lines) into a text box on a web page, and then presses a button which is then stored in a database via Django, and that string is read back and printed on a page, how can I get it to print on an HTML page with the newlines still in the text? So instead of it being printed back as: I see you driving round town with the girl I love, and I’m like: haiku. It would print as: I see you driving round town with the girl I love, and I’m like: haiku. I know that if I use: (textarea)soAndSo.body(/textarea), this preserves the newlines that were in the file when the user typed it up originally. How can I get this same effect, but without having to use textarea boxes?

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  • Generating a python file

    - by fema
    Hi! I'm havin issues with python (imo python itself is an issue). I have a txt file, it contains a custom language and I have to translate it to a working python code. The input: import sys n = int(sys.argv[1]) ;;print "Beginning of the program!" LOOP i in range(1,n) {print "The number:";;print i} BRANCH n < 5 {print n ;;print "less than 5"} The wanted output looks exactly like this: import sys n = int(sys.argv[1]) print "Beginning of the program!" for i in range(1,n) : print "The number:" print i if n < 5 : print n print "less than 5" The name of the input file is read from parameter. The out file is out.py. In case of a wrong parameter, it gives an error message. The ;; means a new line. When I tried to do it, I made an array, I read all the lines into it, split by " ". Then I wanted to strip it from the marks I don't need. I made 2 loops, one for the lines, one for the words. So then I started to replace the things. Everything went fine until it came to the } mark. It finds it, but it can not replace or strip it. I have no more idea what to do. Could someone help me, please? Thanks in advance!

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  • Filtering string in Python

    - by Ecce_Homo
    I am making algorithm for checking the string (e-mail) - like "E-mail addres is valid" but their are rules. First part of e-mail has to be string that has 1-8 characters (can contain alphabet, numbers, underscore [ _ ]...all the parts that e-mail contains) and after @ the second part of e-mail has to have string that has 1-12 characters (also containing all legal expressions) and it has to end with top level domain .com EDIT email = raw_input ("Enter the e-mail address:") length = len (email) if length > 20 print "Address is too long" elif lenght < 5: print "Address is too short" if not email.endswith (".com"): print "Address doesn't contain correct domain ending" first_part = len (splitting[0]) second_part = len(splitting[1]) account = splitting[0] domain = splitting[1] for c in account: if c not in "abcdefghijklmopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789_.": print "Invalid char", "->", c,"<-", "in account name of e-mail" for c in domain: if c not in "abcdefghijklmopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789_.": print "Invalid char", "->", c,"<-", "in domain of e-mail" if first_part == 0: print "You need at least 1 character before the @" elif first_part> 8: print "The first part is too long" if second_part == 4: print "You need at least 1 character after the @" elif second_part> 16: print "The second part is too long" else: # if everything is fine return this print "E-mail addres is valid" EDIT: After reproting what is wrong with our input, now I need to make Python recognize valid address and return ("E-mail adress is valid") This is the best i can do with my knowledge....and we cant use regular expressions, teacher said we are going to learn them later.

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