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  • How to get search results in XML format

    - by Shibin Moideen
    Hi, I am planning to make an iPhone search app. the user types in the search string. the string will be searched by some search engines like Google, Live, Yahoo ... I need to get the search result in the XML format. Is there any way to do this. Help needed. Please. Thanks and regards, Shibin

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  • programming language xml reader

    - by matt
    Indentify a suitable programming language that will read the XML document and insert its contents into the database. i need help with this question i am getting really confused can some one show me and guide me thorught how to do this

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  • WP7 Return the last 7 days of data from an xml web service

    - by cvandal
    Hello, I'm trying to return the last 7 days of data from an xml web service but with no luck. Could someone please explain me to how I would accomplish this? The XML is as follows: <node> <api> <usagelist> <usage day="2011-01-01"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-02"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-03"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-04"> <traffic name="total" unit="bytes">23579797</traffic> </usage> </usagelist> </api> </node> EDIT The data I want to retrieve will be used to populate a line graph. Specificly I require the day attribute value and the traffic element value for the past 7 days. At the moment, I have the code below in place, howevewr it's only showing the first day 7 times and traffic for the first day 7 times. XDocument xDocument = XDocument.Parse(e.Result); var values = from query in xDocument.Descendants("usagelist") select new History { day = query.Element("usage").Attribute("day").Value, traffic = query.Element("usage").Element("traffic").Value }; foreach (History history in values) { ObservableCollection<LineGraphItem> Data = new ObservableCollection<LineGraphItem>() { new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, }; lineGraph1.DataSource = Data; }

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  • Passing input value thru XML loop and return value

    - by Mike Dyer
    "X" is reading the form value, but it is still passing and older "var thisMarket" value. The objective is to take a zip code via HTML form: <form id="market" name="market" onSubmit="return validateZIP(this.zip.value);" method="get" action=""> <input type="text" name="zip" id="zip" value="zipcode" onfocus="if(!this._haschanged){this.value=''};this._haschanged=true;" style="float:left; width:100px; margin-top:5px;"> <input type="image" style="float:left; margin-top:5px; border: 0pt none ; width: 22px; height:17px;" src="images/nav/bottom/linkbar/btn_search_btn.gif" onClick="findLda();"> </form> The script being passed thru is: function findLda(x){ marketName = new Array(); marketURL = new Array(); zip = new Array(); zip_temp = new Array(); zipMatch = false; var shareZip = "Shared Zips"; var thisMarket = "Market value"; xmlDoc=loadXML("/_includes/market.xml"); var Offer,node; document.getElementById('market').innerHTML=''; for(var j=0; j<xmlDoc.getElementsByTagName('market').length; j++){ node = xmlDoc.getElementsByTagName('market')[j]; marketName.push(node.childNodes[3].textContent); marketURL.push(node.childNodes[5].textContent); for(var k=0; k<node.getElementsByTagName('zip').length; k++){ if(node.getElementsByTagName('zip')[k].textContent!=null){ zip_temp.push(node.getElementsByTagName('zip')[k].textContent); } } zip.push(zip_temp); zip_temp = new Array(); } //loop the zip Array to find a match for the query Zip. for(k=0; k<zip.length; k++){ for(m=0; m<zip[k].length; m++){ if(x == zip[k][m].toString()){ zipMatch=true; thisMarket=marketName[k].toString(); } } } alert(thisMarket); } The objective naturally is to take field input (A), pass it thru market.xml - initialize a loop and match a zip (B), alert the result (C). Looking for any direction with what is existing or a completely new direction. Thanks!

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  • Help with XML path views

    - by xmlpath
    Hi all, is there any tool that will give me a view for XML fields like so. I want something that will show me the a view like so, if i select element1 Service/Body/element1 Is there any tool for eclipse for doing the above. Thanks.

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  • c# update xml file

    - by Pila
    I want to replace a xml node that is not a child of the root element. how can I do it - not in .Net 3.5? I don't know the exact path to the node I want to replace, I get the node by XPath query like : XmlElement root = doc.DocumentElement; oldItem = root.SelectSingleNode("//Node1[@name='aaa']//Node2[Item='bbb']/Value"); how can I replace this olditem?

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  • AS3 XML problem

    - by dd
    My Flash project is made of several .swf files, one of them loads XML gallery. everything works fine on my machine, but when I upload it to the testing server gallery content doesn't load. All my paths are relative to Main swf file. I can't make them absolute URLs, b/c I have to deliver zip package. What could be wrong?

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  • xml schema construction

    - by amanrahahla
    in xml can any concept inhert the attribute of the main concept as an example: book( -author -title -isbn -price) and textbook as a subconcept from book can textbook take the same attribute of book and how?

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  • update XML file

    - by Pila
    I want to replace an XML node that is not a child of the root element. How can I do it - not in .NET 3.5? I don't know the exact path to the node I want to replace, I get the node by XPath query like: XmlElement root = doc.DocumentElement; oldItem = root.SelectSingleNode("//Node1[@name='aaa']//Node2[Item='bbb']/Value"); How can I replace this old item?

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  • One log4j.xml - many scripts

    - by psed
    One of my utility jar files is used by different nix scripts, located in different categories. Problem: unable to initialize log4j framework (unable to find log4j.xml). Solution, that allows to configure logger correctly while launching jar classes by different scripts - usage of env vars and force configuring using DOMConfigurtor.configure(pathToConfXml) method. is it possible to avoid path hardcoding and configure logger inside of a script? Appreciate all your help. Thanks.

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  • php DOM, get values from xml document, php xml

    - by Michael
    I'm trying to get some information (itemID, title, price and mileage) for multiple listings from ebay website using their api . So far I got this link up http://open.api.ebay.com/shopping?callname=GetMultipleItems&responseencoding=XML&appid=Morcovar-c74b-47c0-954f-463afb69a4b3&siteid=0&version=525&IncludeSelector=ItemSpecifics&ItemID=220617293997,250645537939,230485306218 I've saved the document as .xml file using php curl and now I need to get/extract the values(itemID, title, price and mileage) into arrays and store them in database. Unfortunately I never worked with php dom and I can't figure it out how to extract the values . I tried to follow the tutorial found on IBM website http://www.ibm.com/developerworks/library/os-xmldomphp/ but I had no success. Some help would be highly appreciated.

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  • Trying to send XML via EMail and the XML includes a byte[]

    - by barbary
    Hello All, I want to send an email that has a machine readable part you cut and paste into an asp.net page and you get the information. I have stored all the information in an object and then used an XMLSerizer to create some xml. It all worked fine until I added some Images as byte[] to the object. If I dump the resulting string to disk then I can recreate the object fine but after it appears in the email client and I try to cut and paste it it never works. Clearly there are non standard characters coming out that email clients don't like. Is there some encoding I could apply to my XML that would make it display correctly in an email client? Then I could cut, paste, decode and deserilize to get my object back. Please an example of how to encode the string in c# would be great.

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  • Oracle Primavera Partner Programs

    - by mark.kromer
    Here is the slide presentation with only the slides that can be shared at this time, for our Oracle Primavera partner programs focusing on expanding P6's workflows and reporting capabilities. By leveraging Oracle's BPM & BI Publisher products, you can build exciting new workflow & enhanced reports to expand the capabilities of Primavera applications.

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  • XML Parsing Error: junk after document element

    - by Jake
    I am using the following script to generate a RSS feed for my site: <?php class RSS { public function RSS() { $root = $_SERVER['DOCUMENT_ROOT']; require_once ("../connect.php"); } public function GetFeed() { return $this->getDetails() . $this->getItems(); } private function dbConnect() { DEFINE ('LINK', mysql_connect (DB_HOST, DB_USER, DB_PASSWORD)); } private function getDetails() { $detailsTable = "rss_feed_details"; $this->dbConnect($detailsTable); $query = "SELECT * FROM ". $detailsTable ." WHERE feed_category = ''"; $result = mysql_db_query (DB_NAME, $query, LINK); while($row = mysql_fetch_array($result)) { $details = '<?xml version="1.0" encoding="ISO-8859-1" ?> <rss version="2.0"> <channel> <title>'. $row['title'] .'</title> <link>'. $row['link'] .'</link> <description>'. $row['description'] .'</description> <language>'. $row['language'] .'</language> <image> <title>'. $row['image_title'] .'</title> <url>'. $row['image_url'] .'</url> <link>'. $row['image_link'] .'</link> <width>'. $row['image_width'] .'</width> <height>'. $row['image_height'] .'</height> </image>'; } return $details; } private function getItems() { $itemsTable = "rss_posts"; $this->dbConnect($itemsTable); $query = "SELECT * FROM ". $itemsTable ." ORDER BY id DESC"; $result = mysql_db_query (DB_NAME, $query, LINK); $items = ''; while($row = mysql_fetch_array($result)) { $items .= '<item> <title>'. $row["title"] .'</title> <link>'. $row["link"] .'</link> <description><![CDATA['.$row["readable_date"]."<br /><br />".$row["description"]."<br /><br />".']]></description> </item>'; } $items .= '</channel> </rss>'; return $items; } } ?> The baffling thing is, the script works perfectly fine on my localhost but gives the following error on my remote server: XML Parsing Error: junk after document element Location: http://mysite.com/rss/main/ Line Number 2, Column 1:<b>Parse error</b>: syntax error, unexpected T_STRING in <b>/home/studentw/public_html/rss/global-reach/rssClass.php</b> on line <b>1</b><br /> ^ Can someone please tell me what's wrong?

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  • What is this XML Parse Error?

    - by Jake
    I am using the following script to generate a RSS feed for my site: <?php class RSS { public function RSS() { $root = $_SERVER['DOCUMENT_ROOT']; require_once ("../connect.php"); } public function GetFeed() { return $this->getDetails() . $this->getItems(); } private function dbConnect() { DEFINE ('LINK', mysql_connect (DB_HOST, DB_USER, DB_PASSWORD)); } private function getDetails() { $detailsTable = "rss_feed_details"; $this->dbConnect($detailsTable); $query = "SELECT * FROM ". $detailsTable ." WHERE feed_category = ''"; $result = mysql_db_query (DB_NAME, $query, LINK); while($row = mysql_fetch_array($result)) { $details = '<?xml version="1.0" encoding="ISO-8859-1" ?> <rss version="2.0"> <channel> <title>'. $row['title'] .'</title> <link>'. $row['link'] .'</link> <description>'. $row['description'] .'</description> <language>'. $row['language'] .'</language> <image> <title>'. $row['image_title'] .'</title> <url>'. $row['image_url'] .'</url> <link>'. $row['image_link'] .'</link> <width>'. $row['image_width'] .'</width> <height>'. $row['image_height'] .'</height> </image>'; } return $details; } private function getItems() { $itemsTable = "rss_posts"; $this->dbConnect($itemsTable); $query = "SELECT * FROM ". $itemsTable ." ORDER BY id DESC"; $result = mysql_db_query (DB_NAME, $query, LINK); $items = ''; while($row = mysql_fetch_array($result)) { $items .= '<item> <title>'. $row["title"] .'</title> <link>'. $row["link"] .'</link> <description><![CDATA['.$row["readable_date"]."<br /><br />".$row["description"]."<br /><br />".']]></description> </item>'; } $items .= '</channel> </rss>'; return $items; } } ?> The baffling thing is, the script works perfectly fine on my localhost but gives the following error on my remote server: XML Parsing Error: junk after document element Location: http://mysite.com/rss/main/ Line Number 2, Column 1:<b>Parse error</b>: syntax error, unexpected T_STRING in <b>/home/studentw/public_html/rss/global-reach/rssClass.php</b> on line <b>1</b><br /> ^

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  • How to convert XML to a HTML table using XSL for-each

    - by Meeeee
    I am trying to convert some XML with XSL, to make the output look better and more readable for other users. I have some XML along the lines of: <G> <OE> <example1>Sample 1</example1> <example2>Sample 2</example2> <var name="name1"> <integer>1</integer> </var> </OE> </G> I want to get all the details from it and display it in a table so I use the following XSL code: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:template match="/"> <html> <body> <h2>Heading</h2> <table border="1"> <tr bgcolor="#3399FF"> <th>Example 1</th> <th>Example 2</th> <th>Var name</th> <th>Int</th> </tr> <xsl:for-each select="G/OE"> <xsl:for-each select="var"> <tr> <td> <xsl:value-of select="Example 1" /> </td> <td> <xsl:value-of select="Example 2" /> </td> <td> <xsl:value-of select="@name" /> </td> <td> <xsl:value-of select="integer" /> </td> </tr> </xsl:for-each> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> I know that the following XSL won't work properly. I want the output to be: Sample 1, Sample 2, name1, 1 - in a table format. My problem is I don't know how to do this. In the above XSL code it will only retrieve var and integer. If I only use the top <xsl:for-each>, then only the first two are retrieved. I have tried moving the 2nd <xsl:for-each> after the first to have been selected, so between: <td><xsl:value-of select="Example 2"/></td> and <td><xsl:value-of select="@name"/></td> I get an error. Is there any way to solve this problem? Thanks for the help.

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  • How to find specific value of the node in xml file

    - by user2735149
    I am making windows phone 8 app based the webservices. This is my xml code: - <response> <timestamp>2013-10-31T08:30:56Z</timestamp> <resultsOffset>0</resultsOffset> <status>success</status> <resultsLimit>8</resultsLimit> <resultsCount>38</resultsCount> - <headlines> - <headlinesItem> <headline>City edge past Toon</headline> <keywords /> <lastModified>2013-10-30T23:45:22Z</lastModified> <audio /> <premium>false</premium> + <links> - <api> - <news> <href>http://api.espn.com/v1/sports/news/1600444?region=GB</href> </news> </api> - <web> <href>http://espnfc.com/uk/en/report/381799/city-edge-toon?ex_cid=espnapi_public</href> </web> - <mobile> <href>http://m.espn.go.com/soccer/gamecast?gameId=381799&lang=EN&ex_cid=espnapi_public</href> </mobile> </links> <type>snReport</type> <related /> <id>1600444</id> <story>Alvardo Negredo and Edin Dzeko struck in extra-time to book Manchester City's place in the last eight of the Capital One Cup, while Costel Pantilimon kept a clean sheet in the 2-0 win to keep the pressure on Joe Hart. </story> <linkText>Newcastle 0-2 Man City</linkText> - <images> - <imagesItem> <height>360</height> <alt>Man City celebrate after Edin Dzeko scored their second extra-time goal at Newcastle.</alt> <width>640</width> <name>Man City celeb Edin Dzeko goal v nufc 20131030 [640x360]</name> <caption>Man City celebrate after Edin Dzeko scored their second extra-time goal at Newcastle.</caption> <type>inline</type> <url>http://espnfc.com/design05/images/2013/1030/mancitycelebedindzekogoalvnufc20131030_640x360.jpg</url> </imagesItem> </images> Code behind: myData = XDocument.Parse(e.Result, LoadOptions.None); var data = myData.Descendants("headlines").FirstOrDefault(); var data1 = from query in myData.Descendants("headlinesItem") select new UpdataNews { News = (string)query.Element("headline").Value, Desc = (string)query.Element("description"), Newsurl = (string)query.Element("links").Element("mobile").Element("href"), Imageurl=(string)query.Element("images").Element("imagesItem").Element("url").Value, }; lstShow.ItemsSource = data1; I am trying to get value from xml tags and assign them to News,Desc, etc. Everything works fine except Imageurl, it shows NullException. I tried same method for Imageurl, i dont know whats going wrong. Help..

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  • Binding Combobox to XML (wpf)

    - by mortor
    <EssenceList> <Essence GUID="464"> <Properties> <Property Name="Name"> <value>mt-1232-1. (1-1-3)</value> </Property> </Properties> <Characteristics> <Characteristic GUID="78"> <value>gadget</value> </Characteristic> <Characteristic GUID="79"> <value>measures</value> </Characteristic> </Characteristics> <LinkedEssences> <LinkType Type="ObjGroup"> <LinkedEssence GUID="369" /> </LinkType> <LinkType Type="ObjGroupProp" /> <LinkType Type="RoleObject"> <LinkedEssence GUID="5747"/> </LinkType> </LinkedEssences> </Essence> ... <Essence GUID="5747" Type="Role"> <Properties> <Property Name="Name"> <value>????-22</value> </Property> <Property Name="ShortName"> <value>UKPG-22</value> </Property> <Property Name="TagPrefix"> <value>UKPG22</value> </Property> <Property Name="useParentTagPrefix"> <value>0</value> </Property> </Properties> </Essence> ... <Essence GUID="5748" Type="Role"> </Essence> ... in example is a xml file with data from database. now i need to bind it to some fields... i use the XMLDataProvider here <Grid.DataContext> <XmlDataProvider x:Name="dataxml" XPath="EssenceList/Essence" Source="464.xml"/> </Grid.DataContext> and mostof simple texboxes i bind like <TextBox Text="{Binding XPath=/EssenceList/Essence/LinkedEssences/LinkType[1]/LinkedEssence/@GUID}" /> but now i need to bind a combobox this way: - the first Essence in the document contains LinkedEssences, that contains and - in document below there is a full description for it that contains the NAME property i need ????-22 UKPG22 0 and many other available Essences for this combobox i managed to bind the list of thems to combobox <ComboBox ItemTemplate="{StaticResource rolelistTemplate}" ItemsSource="{Binding XPath=/EssenceList/Essence[@Type]}" /> so it displays it well, but i can't bind it to my LinkedEssences.

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