Search Results

Search found 16491 results on 660 pages for 'root node'.

Page 81/660 | < Previous Page | 77 78 79 80 81 82 83 84 85 86 87 88  | Next Page >

  • XSLT: Get node where one certain value is present

    - by Kim Andersen
    Hi there I have the following XML: <data> <page id="1118"> <itms> <values> <value>1104</value> </values> </itms> </page> <page id="1177"> <itms> <values> <value>1273</value> <value>1215</value> </values> </itms> </page> </data> I need to get the @id from the < page , where a certain value is present in one of the < value -tags. The id that need to be in the < value is kept in this: $itm/@id. This means that if my $itm/@id is equal to 1273, I need to get 1177 returned. I'm not quite sure how to achieve this. Actually I could have XML that looks like this as well: <data> <page id="1118"> <itms> <values> <value>1104</value> </values> </itms> </page> <page id="1177"> <itms> <values> <value>1273</value> <value>1215</value> </values> </itms> </page> <page id="1352"> <itms> <values> <value>1242</value> <value>1273</value> </values> </itms> </page> </data> If that's the case, I need the latest id, so this means that if the $itm/@id matches values in more < page 's, then I need to grab the value from the latest page. I the above case that would be 1352. Hope this makes sense to you guys. And by the way, I work with Umbraco CMS if that does any difference. Best Regards, Kim

    Read the article

  • XSL: How to print an iterated node in for-each

    - by Shoaib
    xml: <skills> <skill>PHP</skill> <skill>CSS</skill> <skill>HTML</skill> <skill>XML</skill> </skills> XSL: <ul> <xsl:for-each select="skills/skill"> <li><xsl:value-of select="[what should be xpath here]" /></li </xsl:for-each> </ul> Here what should be the xpath to print each skill?

    Read the article

  • install barnyard2 ubuntu 12.04

    - by Muhammad Ardiansyah
    I trying to install barnyard2 in ubuntu 12.04 32-bit I'm configure using syntax: ./configure --with-mysql-libraries=/usr/lib/x86_64-linux-gnu and when I trying to compile daq-1.1.1 using a makefile, I encountered the following errors: make[3]: Leaving directory /root/snortinstall/barnyard2/src' make[2]: Leaving directory/root/snortinstall/barnyard2/src' Making all in etc make[2]: Entering directory /root/snortinstall/barnyard2/etc' make[2]: Nothing to be done forall'. make[2]: Leaving directory /root/snortinstall/barnyard2/etc' Making all in doc make[2]: Entering directory/root/snortinstall/barnyard2/doc' make[2]: Nothing to be done for all'. make[2]: Leaving directory /root/snortinstall/barnyard2/doc' Making all in rpm make[2]: Entering directory /root/snortinstall/barnyard2/rpm' make[2]: Nothing to be done forall'. make[2]: Leaving directory /root/snortinstall/barnyard2/rpm' Making all in schemas make[2]: Entering directory/root/snortinstall/barnyard2/schemas' make[2]: Nothing to be done for all'. make[2]: Leaving directory /root/snortinstall/barnyard2/schemas' Making all in m4 make[2]: Entering directory /root/snortinstall/barnyard2/m4' make[2]: Nothing to be done forall'. make[2]: Leaving directory /root/snortinstall/barnyard2/m4' make[2]: Entering directory /root/snortinstall/barnyard2' make[2]: Nothing to be done for all-am'. make[2]: Leaving directory/root/snortinstall/barnyard2' make[1]: Leaving directory `/root/snortinstall/barnyard2'

    Read the article

  • finding an adjacent node in xml through xpath

    - by kolosy
    i have a deeply nested structure (actually parsing out xhtml, so lots of nasty), like so: <tr> <td> <font id="blah"> stuff </font> </td> </tr> <tr> <td> more stuff </td> </tr> and this repeats in a long table. i need an xpath expression that will select the second font tag (or rather it's text()). i was looking at the preceding-sibling axis, but something isn't quite working right. something along the lines of (and pardon me if this is ridiculous, my xpath is rusty) //tr[preceding-sibling::tr/td/font/b]/td/text()

    Read the article

  • AJAX XML reply node value iteration

    - by XpiritO
    Hi there, guys. I would really appreciate to get your help on this, as I can't seem to detect and solve the problem I'm having with an AJAX functionality on a site that I'm currently developing. I have a webform that makes an asynchronous call to a handler (.ashx) that delivers a XML response that is later processed by a Javascript client-side function that places it's contents into the user-interface. I'm attaching an example of the response generated by my handler, and what I would like to know is how can I get all the <body> element innerHTML (with the text and child nodes) contents to append it to a <span> element on the user-interface. Can anyone help me out with this? XML Response returned by the handler (checked via Firebug): <message> <content> <messageId>2</messageId> <from>Barack Obama</from> <fromMail>[email protected]</fromMail> <subject>Yes, we can... get World Peace</subject> <body>Hello, dear citizen. I'm sending you this message to invite you to join us! <a href="http://www.whitehouse.gov">Test link</a> Thank you for your time.</body> </content> </message> Client-side Javascript function to affect the user-interface innerHTML property with the data returned via AJAX: function GetMessageContentsCallback(args, resp) { //XML Parser try { //Internet Explorer xmlDoc = new ActiveXObject("Microsoft.XMLDOM"); xmlDoc.async = "false"; xmlDoc.loadXML(resp); } catch (e) { parser = new DOMParser(); xmlDoc = parser.parseFromString(resp, "text/xml"); } var msgReply = xmlDoc.getElementsByTagName('message')[0]; var ajaxRespondeBodyInnerHTML = msgReply.getElementsByTagName(body)[0].firstChild.nodeValue; //this currently only delivers inner text content, without the <a href... bit and subsequent text document.getElementById("bodySpan").innerHTML = ajaxRespondeBodyInnerHTML; }

    Read the article

  • Redirect question using mod_rewrite (no extensions - root of site)

    - by alex
    Hi, I'm having a small problem with mod_rewrite I have the following in my .htacces: Options +FollowSymlinks RewriteEngine on RewriteRule ^(.+)\.htm$ index.php?name=$1 [NC] This is my index.php file: <?php echo $_GET['name]; ?> This works great for the following url: www.mySite.com/this is an example.htm this would display "this is an example" What i'm trying to do however, is get it to do the same, without the .htm extension: for example: www.mySite.com/this is an example Any ideas? (dont think it's relevant but i'm using xampp to test this)

    Read the article

  • writing a Simplest XML DeSerialization class for the simplest xml file. How to avoid the nesting? de

    - by Enggr
    Hi, I want to deserialize an xml file which has to be just in this form <Basket> <Fruit>Apple</Fruit> <Fruit>Orange</Fruit> <Fruit>Grapes</Fruit> </Basket> Out of the examples I read on internet the least possible format I could find was the following <Basket> <FruitArray> <Fruit>Apple</Fruit> </FruitArray> <FruitArray> <Fruit>Orange</Fruit> </FruitArray> <FruitArray> <Fruit>Grapes</Fruit> </FruitArray> </Basket> and that has the following deserialization class for converting it into a class object. using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace XMLSerialization_Basket { [System.Xml.Serialization.XmlRootAttribute("Basket", Namespace = "BasketNamespace", IsNullable = false)] public class Basket { /// <remarks/> [System.Xml.Serialization.XmlElementAttribute("FruitArray")] public FruitArray[] objFruitArray; } /// <remarks/> [System.Xml.Serialization.XmlTypeAttribute(Namespace = "BasketNamespace")] public class FruitArray { /// <remarks/> private string _Fruit; public string Fruit { get { return _Fruit; } set { _Fruit = value; } } } } Can I add something like the following directly under top class private string _Fruit; public string Fruit { get { return _Fruit; } set { _Fruit = value; } } and avoid the array nesting? my goal is to deserialize an xml of following format <Basket> <Fruit>Apple</Fruit> <Fruit>Orange</Fruit> <Fruit>Grapes</Fruit> </Basket>

    Read the article

  • Wrong root on image_tag, include_tags, etc

    - by Newy
    On my dev setup, generated routes are mysteriously pointing to my public www server. <%= javascript_include_tag :defaults % [yields] <script src="http://www.mysite.com//javascripts/prototype.js?1265304231" type="text/javascript"></script> <script src="http://www.mysite.com//javascripts/effects.js?1265304231" type="text/javascript"></script> <script src="http://www.mysite.com//javascripts/dragdrop.js?1265304231" type="text/javascript"></script> <script src="http://www.mysite.com//javascripts/controls.js?1273647885" type="text/javascript"></script> <script src="http://mysite.opzi.com//javascripts/application.js?1273611341" type="text/javascript"></script> Where is this option set? Can't find it for the life of me.

    Read the article

  • doesn't parse xml when it's a single node

    - by tag
    my script.php returns this XML <all> <item> <field1>value1</field1> <field2>value2</field2> </item> <item> <field1>value1</field1> <field2>value2</field2> </item> </all> The HTTPService uses the default resultFormat="object" but I don't declare it since it's the default. Then I bind it to a List dataProvider="{getDataHTTP.lastResult.all.item}" I get no problems when the number of item returned is more than 1. But when it's only 1 item I get an error cannot convert XMLList to mx.collections.IList. I tried different solutions including trying to cast it as XMLListCollection but it still gives an error for single items. Does anyone know of a way to possibly solve this?

    Read the article

  • Assembly-wide / root-level styles in WPF class library

    - by WarpedBoard
    I have a C# (2008/.NET 3.5) class library assembly that supports WPF (based on http://dotupdate.wordpress.com/2007/12/05/how-to-add-a-wpf-control-library-template-to-visual-c-express-2008/). I've created several windows, and am now attempting to create a common style set for them. However, as it's a class library (instead of a WPF app), I don't have an app.xaml (and its contained Application & corresponding Application.Resources) in which to store these styles for global access. So: How can I create a top-level set of style definitions that'll be seen by all xaml files in the assembly, given that I do not have app.xaml (see above)? And/or is it possible to add a working app.xaml to a class library? FYI, I did try creating a ResourceDictionary in a ResourceDictionary.xaml file, and include it in each window within a "Window.Resources" block. That turned out to solve the styling of Buttons, etc... but not for the enclosing Window. I can put 'Style="{StaticResource MyWindowStyle}"' in the Window's opening block, and it compiles and shows up in the VS Design window fine, but during actual runtime I get a parse exception (MyWindowStyle could not be found; I'm guessing Visual Studio sees the dictionary included after the line in question, but the CRL does things more sequentially and therefore hasn't loaded the ResourceDictionary yet).

    Read the article

  • How to find specific value of the node in xml file

    - by user2735149
    I am making windows phone 8 app based the webservices. This is my xml code: - <response> <timestamp>2013-10-31T08:30:56Z</timestamp> <resultsOffset>0</resultsOffset> <status>success</status> <resultsLimit>8</resultsLimit> <resultsCount>38</resultsCount> - <headlines> - <headlinesItem> <headline>City edge past Toon</headline> <keywords /> <lastModified>2013-10-30T23:45:22Z</lastModified> <audio /> <premium>false</premium> + <links> - <api> - <news> <href>http://api.espn.com/v1/sports/news/1600444?region=GB</href> </news> </api> - <web> <href>http://espnfc.com/uk/en/report/381799/city-edge-toon?ex_cid=espnapi_public</href> </web> - <mobile> <href>http://m.espn.go.com/soccer/gamecast?gameId=381799&lang=EN&ex_cid=espnapi_public</href> </mobile> </links> <type>snReport</type> <related /> <id>1600444</id> <story>Alvardo Negredo and Edin Dzeko struck in extra-time to book Manchester City's place in the last eight of the Capital One Cup, while Costel Pantilimon kept a clean sheet in the 2-0 win to keep the pressure on Joe Hart. </story> <linkText>Newcastle 0-2 Man City</linkText> - <images> - <imagesItem> <height>360</height> <alt>Man City celebrate after Edin Dzeko scored their second extra-time goal at Newcastle.</alt> <width>640</width> <name>Man City celeb Edin Dzeko goal v nufc 20131030 [640x360]</name> <caption>Man City celebrate after Edin Dzeko scored their second extra-time goal at Newcastle.</caption> <type>inline</type> <url>http://espnfc.com/design05/images/2013/1030/mancitycelebedindzekogoalvnufc20131030_640x360.jpg</url> </imagesItem> </images> Code behind: myData = XDocument.Parse(e.Result, LoadOptions.None); var data = myData.Descendants("headlines").FirstOrDefault(); var data1 = from query in myData.Descendants("headlinesItem") select new UpdataNews { News = (string)query.Element("headline").Value, Desc = (string)query.Element("description"), Newsurl = (string)query.Element("links").Element("mobile").Element("href"), Imageurl=(string)query.Element("images").Element("imagesItem").Element("url").Value, }; lstShow.ItemsSource = data1; I am trying to get value from xml tags and assign them to News,Desc, etc. Everything works fine except Imageurl, it shows NullException. I tried same method for Imageurl, i dont know whats going wrong. Help..

    Read the article

  • Wrong root on image_tag

    - by Euwyn
    On my dev setup, the image_tag is mysteriously pointing to my public www server (i.e. computing the image path as http://www.domain.com/images/blah.jpg). Where is this option set?

    Read the article

  • change a value xml in php but false with a node name id-7

    - by Nataly Nguyen
    I want to change a xml, but fails with this code. I think mistake with name of variable (ID-1) in php. chang.php <?php include 'example.php'; $xml = new SimpleXMLElement($xmlstr); $xml->ID-1 = '8'; $xml->name = 'Big Cliff'; $xml->asXML('test2.xml'); echo $xml->asXML(); ?> example.php <?php $xmlstr = <<<XML <?xml version="1.0" encoding="utf-8"?> <film> <ID-1>29</ID-1> <name>adf</name> </film> XML; ?>

    Read the article

  • Getting the correct node

    - by YsoL8
    Hello I have this structure in my dom: <label>London<input type="checkbox" name="London"></label><br> <div class="innerpost"> <label>N1 2AB<input type="checkbox" name="N1 2AB"></label><br> <label>E1 1AB<input type="checkbox" name="E1 1AB"></label><br> </div> I need a way to select the div from the first checkbox. Something like parentNode.parentNode.getElementsByTagName("div"); But I'm not getting it right - that particular line selects all the divs one parent above the one I need.

    Read the article

  • Installing CodeIgniter on root and WordPress in sub-directory

    - by maSnun
    Hello, I want to create a website where the main pages will be served from CodeIgniter. I will use Wordpress in the /blog/ sub-directory to host the blog. Thats it! I want nothing else. Just to make sure that: example.com/somepage/ calls a CI controller where as example.com/blog/some-post/ is handled by Wordpress. I don't need any kind of integration or interaction between CI and WP. Is it possible to install in that way? If not, any workarounds so that I can achieve the objectives? Thanks and Regards, Masnun

    Read the article

  • asp.net and Visual studio root directory question

    - by Mark Kadlec
    I am seeing something very odd and thought I would ask the Stackoverflow community if they knew the answer. I have an asp.net project that runs fine in one environment, but couldn't figure out what happened to the styles in another environment. In the first environment (Windows 2008 Server), the following link worked fine: <link href="/Styles/09/style.css" rel="stylesheet" type="text/css" /> but in the other environment (it's a Windows 7), I had to change it to work: <link href="../Styles/09/style.css" rel="stylesheet" type="text/css" /> Notice that the directories seemed to shift ahead one directory in the Win7, what's going on? It's like the "running" directory seems now be the \bin directory instead of the home! Which environment is configured correctly? How do I determine execution directory level? My concern going forward is pushing to a prod environment and guessing which configuration is correct. Any insight would be appreciated!

    Read the article

  • angular-ui-router : breadcrumps ok but view ko

    - by anakin59490
    this is my app.router.js : agentRouter.config([ '$stateProvider', '$urlRouterProvider', function($stateProvider, $urlRouterProvider) { var root = { name: 'root', abstract: true, url: '', title: 'home', views: { 'header': { templateUrl: 'views/headers/header.app.html', controller: 'HeaderCtrl' }, 'body': { templateUrl: "views/root.html" }, 'footer': { templateUrl: 'views/footers/footer.app.html' } } }; var agent = { name: 'root.agent', url: '/agent', title: 'agent', views: { 'root.sidebar': { templateUrl: "views/main.sidebar.html" }, 'root.container': { templateUrl: "views/partials/agent/list.container.html" } } }; var detail = { name: 'root.agent.detail', url: '/detail/:id', title: 'agentDetail', // use for breadcrumb views: { 'root.sidebar': { templateUrl: "views/main.sidebar.html" }, 'root.container': { templateUrl: "views/partials/agent/list.chantier.html" } } }; /.../ $stateProvider.state(root); $stateProvider.state(agent); $stateProvider.state(detail); } ]); and this is my root.html : <!--Breadcrumb content--> <ul class="row breadcrumb"> <i class="glyphicon glyphicon-home" style=""></i> <li ng-repeat="state in $state.$current.path"> <a ng-href="#{{state.url.format($stateParams)}}"><span ng-bind="state.title"></span></a> <span ng-hide="$last" class=""></span> </li> </ul> <!--Sidebar content--> <div ui-view="root.sidebar">default root.sidebar</div> <!--Container content--> <div style="background-color: #f9f9f9" ui-view="root.container">default root.container</div> I can access to my "agent" page (a list of person) and my breadcrumb is right : home / agent but when i click on an item of the list i got always the same page but my breadcrumb is right : home / agent / agentDetail but in app.router.js if change detail like this : var detail = { name: 'root.detail', // référence initiale + detail (fils) url: '/agent/detail/:id', // réference utilisée dans les fichiers HTML, attention c'est la suite de l'url précédente!!! title: 'agentDetail', // référence utilisée pour le breadcump views: { 'root.sidebar': { templateUrl: "views/main.sidebar.html" }, 'root.container': { templateUrl: "views/partials/agent/list.chantier.html" } } }; i got the right page (list.chantier.xml) but the breadcrumb is false : home / agentDetail instead of home / agent / agentDetail I would like to got the right breadcrumb (home / agent / agentDetail) with the right page (list.chantier.html) when i click on an item of the agent list page (list.container.html) Thank you in advance for your help

    Read the article

  • delete XML node, keep original

    - by marzsman
    I need to delete some nodes from an XML variable and I want to keep the original intact. So I pass the XML to a new variable and delete the nodes from that one but the original changes with it. Is there a way to protect the XML from the original variable?

    Read the article

  • Verify p2p node

    - by mazzzzz
    Hey guys, I have been working on a p2p namespace for some of my programs. I created a system to encrypt/decrypt the packets send/received with the class. I was using the basic public private key system: 1) encrypt the data with Symmetric encryption 2) encrypt the symmetric key with RSA. Then do the opposite when you decrypted.. I was wondering though, how would you verify if the packet was coming from where it said it was. I was going to use a basic certificate system (where you encrypt with your private RSA key, then they decrypt it with your public key), but I don't know how to do this with C#. I am using the RSACryptoServiceProvider class. Does anyone know how do this? Thanks, Max

    Read the article

  • How to display node name in Action script 3 xml

    - by Mirage
    My xml is like below <rat> <to>tt</to> <from>ggg</from> <heading>hhhhh</heading> <body>jjj</body> </rat> My AS3 code is var example:XML = new XML(event.target.data); _label.text = example[0].rat[0][nodeName]; addChild(_label); I want to display the data like to = tt from = ggg how can i do that

    Read the article

  • Select records from XML column (SQL Server 2005) based on node order

    - by jdoe
    I have a column in a SQL Server 2005 table defined as an XML column. Is there a way to select records from this table based on the order of two nodes in that column? For example, we have the following structure in our XML: <item> <latitude/> <longitude/> </item> I want to see if there are any records that have latitude/longitude in the opposite order i.e. <longitude/> then <latitude/>. I've tried some XPath expressions but with no luck.

    Read the article

  • Updating the url of a navigation node in moss programatically

    - by 78lro
    Can anyone see why this should not work: SPSite topNavigationSite = new SPSite("http://moss"); SPWeb topNavigationWeb = topNavigationSite.OpenWeb(); SPNavigationNodeCollection topNavigationBarNodes = topNavigationWeb.Navigation.TopNavigationBar; SPNavigationNode updateNode = topNavigationBarNodes.Navigation.GetNodeByUrl("/about"); updateNode.Url = ""; topNavigationWeb.Update(); I can see debugging that the url get's set to "" but when the page renders, the navigation still shows the url as /about/default.aspx I'm running this in page_load and expected it to update the moss database with the new url value.

    Read the article

< Previous Page | 77 78 79 80 81 82 83 84 85 86 87 88  | Next Page >