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  • Need some tips on my SQL script?

    - by Nano HE
    Hi I plan to create a tale to store the race result like this, Place RaceNumber Gender Name Result 12 0112 Male Mike Lee 1:32:40 16 0117 Female Rose Marry 2:20:40 I confused at the items type definiation. Q1.I am not sure the result can be set to varchar(32) or other type? Q2. and for racenumber, between int(11) and varchar(11), which one is better? Q3. Can I use `UNIQUE KEY` like my way? Q4. Do I need split name to firstName and lastName in my DB table? DROP TABLE IF EXISTS `race_result`; CREATE TABLE IF NOT EXISTS `race_result` ( `id` int(11) NOT NULL auto_increment, `racenumber` int(11) NOT NULL, `gender` enum('male','female') NOT NULL, `name` varchar(16) NOT NULL, `result` varchar(32) NOT NULL, PRIMARY KEY (`id`), UNIQUE KEY `racenumber` (`racenumber`,`id`) ) ENGINE=MyISAM AUTO_INCREMENT=3 DEFAULT CHARSET=utf8 AUTO_INCREMENT=3;

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  • How to tell endianness from this output?

    - by Nick Rosencrantz
    I'm running this example program and I'm suppossed to be able to tell from the output what machine type it is. I'm certain it's from inspecting one or two values but how should I perform this inspection? /* pointers.c - Test pointers * Written 2012 by F Lundevall * Copyright abandoned. This file is in the public domain. * * To make this program work on as many systems as possible, * addresses are converted to unsigned long when printed. * The 'l' in formatting-codes %ld and %lx means a long operand. */ #include <stdio.h> #include <stdlib.h> int * ip; /* Declare a pointer to int, a.k.a. int pointer. */ char * cp; /* Pointer to char, a.k.a. char pointer. */ /* Declare fp as a pointer to function, where that function * has one parameter of type int and returns an int. * Use cdecl to get the syntax right, http://cdecl.org/ */ int ( *fp )( int ); int val1 = 111111; int val2 = 222222; int ia[ 17 ]; /* Declare an array of 17 ints, numbered 0 through 16. */ char ca[ 17 ]; /* Declare an array of 17 chars. */ int fun( int parm ) { printf( "Function fun called with parameter %d\n", parm ); return( parm + 1 ); } /* Main function. */ int main() { printf( "Message PT.01 from pointers.c: Hello, pointy World!\n" ); /* Do some assignments. */ ip = &val1; cp = &val2; /* The compiler should warn you about this. */ fp = fun; ia[ 0 ] = 11; /* First element. */ ia[ 1 ] = 17; ia[ 2 ] = 3; ia[ 16 ] = 58; /* Last element. */ ca[ 0 ] = 11; /* First element. */ ca[ 1 ] = 17; ca[ 2 ] = 3; ca[ 16 ] = 58; /* Last element. */ printf( "PT.02: val1: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val1, val1, val1 ); printf( "PT.03: val2: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val2, val2, val2 ); printf( "PT.04: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.05: Dereference pointer ip and we find: %d \n", *ip ); printf( "PT.06: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.07: Dereference pointer cp and we find: %d \n", *cp ); *ip = 1234; printf( "\nPT.08: Executed *ip = 1234; \n" ); printf( "PT.09: val1: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val1, val1, val1 ); printf( "PT.10: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.11: Dereference pointer ip and we find: %d \n", *ip ); printf( "PT.12: val1: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val1, val1, val1 ); *cp = 1234; /* The compiler should warn you about this. */ printf( "\nPT.13: Executed *cp = 1234; \n" ); printf( "PT.14: val2: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val2, val2, val2 ); printf( "PT.15: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.16: Dereference pointer cp and we find: %d \n", *cp ); printf( "PT.17: val2: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val2, val2, val2 ); ip = ia; printf( "\nPT.18: Executed ip = ia; \n" ); printf( "PT.19: ia[0]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ia[0], ia[0], ia[0] ); printf( "PT.20: ia[1]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ia[1], ia[1], ia[1] ); printf( "PT.21: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.22: Dereference pointer ip and we find: %d \n", *ip ); ip = ip + 1; /* add 1 to pointer */ printf( "\nPT.23: Executed ip = ip + 1; \n" ); printf( "PT.24: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.25: Dereference pointer ip and we find: %d \n", *ip ); cp = ca; printf( "\nPT.26: Executed cp = ca; \n" ); printf( "PT.27: ca[0]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ca[0], ca[0], ca[0] ); printf( "PT.28: ca[1]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ca[1], ca[1], ca[1] ); printf( "PT.29: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.30: Dereference pointer cp and we find: %d \n", *cp ); cp = cp + 1; /* add 1 to pointer */ printf( "\nPT.31: Executed cp = cp + 1; \n" ); printf( "PT.32: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.33: Dereference pointer cp and we find: %d \n", *cp ); ip = ca; /* The compiler should warn you about this. */ printf( "\nPT.34: Executed ip = ca; \n" ); printf( "PT.35: ca[0]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ca[0], ca[0], ca[0] ); printf( "PT.36: ca[1]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ca[1], ca[1], ca[1] ); printf( "PT.37: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.38: Dereference pointer ip and we find: %d \n", *ip ); cp = ia; /* The compiler should warn you about this. */ printf( "\nPT.39: Executed cp = ia; \n" ); printf( "PT.40: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.41: Dereference pointer cp and we find: %d \n", *cp ); printf( "\nPT.42: fp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &fp, (long) fp, (long) fp ); printf( "PT.43: Dereference fp and see what happens.\n" ); val1 = (*fp)(42); printf( "PT.44: Executed val1 = (*fp)(42); \n" ); printf( "PT.45: val1: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val1, val1, val1 ); return( 0 ); } Output Message PT.01 from pointers.c: Hello, pointy World! PT.02: val1: stored at 21e50 (hex); value is 111111 (dec), 1b207 (hex) PT.03: val2: stored at 21e54 (hex); value is 222222 (dec), 3640e (hex) PT.04: ip: stored at 21eb8 (hex); value is 138832 (dec), 21e50 (hex) PT.05: Dereference pointer ip and we find: 111111 PT.06: cp: stored at 21e6c (hex); value is 138836 (dec), 21e54 (hex) PT.07: Dereference pointer cp and we find: 0 PT.08: Executed *ip = 1234; PT.09: val1: stored at 21e50 (hex); value is 1234 (dec), 4d2 (hex) PT.10: ip: stored at 21eb8 (hex); value is 138832 (dec), 21e50 (hex) PT.11: Dereference pointer ip and we find: 1234 PT.12: val1: stored at 21e50 (hex); value is 1234 (dec), 4d2 (hex) PT.13: Executed *cp = 1234; PT.14: val2: stored at 21e54 (hex); value is -771529714 (dec), d203640e (hex) PT.15: cp: stored at 21e6c (hex); value is 138836 (dec), 21e54 (hex) PT.16: Dereference pointer cp and we find: -46 PT.17: val2: stored at 21e54 (hex); value is -771529714 (dec), d203640e (hex) PT.18: Executed ip = ia; PT.19: ia[0]: stored at 21e74 (hex); value is 11 (dec), b (hex) PT.20: ia[1]: stored at 21e78 (hex); value is 17 (dec), 11 (hex) PT.21: ip: stored at 21eb8 (hex); value is 138868 (dec), 21e74 (hex) PT.22: Dereference pointer ip and we find: 11 PT.23: Executed ip = ip + 1; PT.24: ip: stored at 21eb8 (hex); value is 138872 (dec), 21e78 (hex) PT.25: Dereference pointer ip and we find: 17 PT.26: Executed cp = ca; PT.27: ca[0]: stored at 21e58 (hex); value is 11 (dec), b (hex) PT.28: ca[1]: stored at 21e59 (hex); value is 17 (dec), 11 (hex) PT.29: cp: stored at 21e6c (hex); value is 138840 (dec), 21e58 (hex) PT.30: Dereference pointer cp and we find: 11 PT.31: Executed cp = cp + 1; PT.32: cp: stored at 21e6c (hex); value is 138841 (dec), 21e59 (hex) PT.33: Dereference pointer cp and we find: 17 PT.34: Executed ip = ca; PT.35: ca[0]: stored at 21e58 (hex); value is 11 (dec), b (hex) PT.36: ca[1]: stored at 21e59 (hex); value is 17 (dec), 11 (hex) PT.37: ip: stored at 21eb8 (hex); value is 138840 (dec), 21e58 (hex) PT.38: Dereference pointer ip and we find: 185664256 PT.39: Executed cp = ia; PT.40: cp: stored at 21e6c (hex); value is 138868 (dec), 21e74 (hex) PT.41: Dereference pointer cp and we find: 0 PT.42: fp: stored at 21e70 (hex); value is 69288 (dec), 10ea8 (hex) PT.43: Dereference fp and see what happens. Function fun called with parameter 42 PT.44: Executed val1 = (*fp)(42); PT.45: val1: stored at 21e50 (hex); value is 43 (dec), 2b (hex)

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  • How can * be a safe hashed password?

    - by Exception e
    phpass is a widely used hashing 'framework'. While evaluating phpass' HashPassword I came across this odd method fragment. function HashPassword($password) { // <snip> trying to generate a hash… # Returning '*' on error is safe here, but would _not_ be safe # in a crypt(3)-like function used _both_ for generating new # hashes and for validating passwords against existing hashes. return '*'; } This is the complete phpsalt class: # Portable PHP password hashing framework. # # Version 0.2 / genuine. # # Written by Solar Designer <solar at openwall.com> in 2004-2006 and placed in # the public domain. # # # class PasswordHash { var $itoa64; var $iteration_count_log2; var $portable_hashes; var $random_state; function PasswordHash($iteration_count_log2, $portable_hashes) { $this->itoa64 = './0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz'; if ($iteration_count_log2 < 4 || $iteration_count_log2 > 31) $iteration_count_log2 = 8; $this->iteration_count_log2 = $iteration_count_log2; $this->portable_hashes = $portable_hashes; $this->random_state = microtime() . getmypid(); } function get_random_bytes($count) { $output = ''; if (is_readable('/dev/urandom') && ($fh = @fopen('/dev/urandom', 'rb'))) { $output = fread($fh, $count); fclose($fh); } if (strlen($output) < $count) { $output = ''; for ($i = 0; $i < $count; $i += 16) { $this->random_state = md5(microtime() . $this->random_state); $output .= pack('H*', md5($this->random_state)); } $output = substr($output, 0, $count); } return $output; } function encode64($input, $count) { $output = ''; $i = 0; do { $value = ord($input[$i++]); $output .= $this->itoa64[$value & 0x3f]; if ($i < $count) $value |= ord($input[$i]) << 8; $output .= $this->itoa64[($value >> 6) & 0x3f]; if ($i++ >= $count) break; if ($i < $count) $value |= ord($input[$i]) << 16; $output .= $this->itoa64[($value >> 12) & 0x3f]; if ($i++ >= $count) break; $output .= $this->itoa64[($value >> 18) & 0x3f]; } while ($i < $count); return $output; } function gensalt_private($input) { $output = '$P$'; $output .= $this->itoa64[min($this->iteration_count_log2 + ((PHP_VERSION >= '5') ? 5 : 3), 30)]; $output .= $this->encode64($input, 6); return $output; } function crypt_private($password, $setting) { $output = '*0'; if (substr($setting, 0, 2) == $output) $output = '*1'; if (substr($setting, 0, 3) != '$P$') return $output; $count_log2 = strpos($this->itoa64, $setting[3]); if ($count_log2 < 7 || $count_log2 > 30) return $output; $count = 1 << $count_log2; $salt = substr($setting, 4, 8); if (strlen($salt) != 8) return $output; # We're kind of forced to use MD5 here since it's the only # cryptographic primitive available in all versions of PHP # currently in use. To implement our own low-level crypto # in PHP would result in much worse performance and # consequently in lower iteration counts and hashes that are # quicker to crack (by non-PHP code). if (PHP_VERSION >= '5') { $hash = md5($salt . $password, TRUE); do { $hash = md5($hash . $password, TRUE); } while (--$count); } else { $hash = pack('H*', md5($salt . $password)); do { $hash = pack('H*', md5($hash . $password)); } while (--$count); } $output = substr($setting, 0, 12); $output .= $this->encode64($hash, 16); return $output; } function gensalt_extended($input) { $count_log2 = min($this->iteration_count_log2 + 8, 24); # This should be odd to not reveal weak DES keys, and the # maximum valid value is (2**24 - 1) which is odd anyway. $count = (1 << $count_log2) - 1; $output = '_'; $output .= $this->itoa64[$count & 0x3f]; $output .= $this->itoa64[($count >> 6) & 0x3f]; $output .= $this->itoa64[($count >> 12) & 0x3f]; $output .= $this->itoa64[($count >> 18) & 0x3f]; $output .= $this->encode64($input, 3); return $output; } function gensalt_blowfish($input) { # This one needs to use a different order of characters and a # different encoding scheme from the one in encode64() above. # We care because the last character in our encoded string will # only represent 2 bits. While two known implementations of # bcrypt will happily accept and correct a salt string which # has the 4 unused bits set to non-zero, we do not want to take # chances and we also do not want to waste an additional byte # of entropy. $itoa64 = './ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789'; $output = '$2a$'; $output .= chr(ord('0') + $this->iteration_count_log2 / 10); $output .= chr(ord('0') + $this->iteration_count_log2 % 10); $output .= '$'; $i = 0; do { $c1 = ord($input[$i++]); $output .= $itoa64[$c1 >> 2]; $c1 = ($c1 & 0x03) << 4; if ($i >= 16) { $output .= $itoa64[$c1]; break; } $c2 = ord($input[$i++]); $c1 |= $c2 >> 4; $output .= $itoa64[$c1]; $c1 = ($c2 & 0x0f) << 2; $c2 = ord($input[$i++]); $c1 |= $c2 >> 6; $output .= $itoa64[$c1]; $output .= $itoa64[$c2 & 0x3f]; } while (1); return $output; } function HashPassword($password) { $random = ''; if (CRYPT_BLOWFISH == 1 && !$this->portable_hashes) { $random = $this->get_random_bytes(16); $hash = crypt($password, $this->gensalt_blowfish($random)); if (strlen($hash) == 60) return $hash; } if (CRYPT_EXT_DES == 1 && !$this->portable_hashes) { if (strlen($random) < 3) $random = $this->get_random_bytes(3); $hash = crypt($password, $this->gensalt_extended($random)); if (strlen($hash) == 20) return $hash; } if (strlen($random) < 6) $random = $this->get_random_bytes(6); $hash = $this->crypt_private($password, $this->gensalt_private($random)); if (strlen($hash) == 34) return $hash; # Returning '*' on error is safe here, but would _not_ be safe # in a crypt(3)-like function used _both_ for generating new # hashes and for validating passwords against existing hashes. return '*'; } function CheckPassword($password, $stored_hash) { $hash = $this->crypt_private($password, $stored_hash); if ($hash[0] == '*') $hash = crypt($password, $stored_hash); return $hash == $stored_hash; } }

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  • MacRuby - CLLocation Properties Not Accessible

    - by Craig Williams
    Anyone know why this works in Objective-C but not in MacRuby? Objective-C Version: CLLocation *loc = [[CLLocation alloc] initWithLatitude:38.0 longitude:-122.0]; NSLog(@"Lat: %.2f", loc.coordinate.latitude); NSLog(@"Long: %.2f", loc.coordinate.longitude); [loc release]; // Results: // 2010-04-30 16:48:55.568 OCCoreLocationTest[70030:a0f] Lat: 38.00 // 2010-04-30 16:48:55.570 OCCoreLocationTest[70030:a0f] Long: -122.00 Here is the MacRuby version with results: loc = CLLocation.alloc.initWithLatitude(38.0, longitude:-122.0) puts loc.class # => CLLocation puts loc.description # => <+38.00000000, -122.00000000> +/- 0.00m (speed -1.00 mps / course -1.00) @ 2010-04-30 16:37:47 -0600 puts loc.respond_to?(:coordinate) # => true puts loc.coordinate.latitude # => Error: unrecognized runtime type `{?=dd}' (TypeError)

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  • How to create Query syntax for multiple DataTable for implementing IN operator of Sql Server

    - by Shantanu Gupta
    I have fetched 3-4 tables by executing my stored procedure. Now they resides on my dataset. I have to maintain this dataset for multiple forms and I am not doing any DML operation on this dataset. Now this dataset contains 4 tables out of which i have to fetch some records to display data. Data stored in tables are in form of one to many relationship. i.e. In case of transactions. N records per record. Then these N records are further mapped to M records of 3rd table. Table 1 MAP_ID GUEST_ID DEPARTMENT_ID PARENT_ID PREFERENCE_ID -------------------- -------------------- -------------------- -------------------- -------------------- 19 61 1 1 5 14 61 1 5 15 15 61 2 4 10 18 61 2 13 23 17 61 2 20 26 16 61 40 40 41 20 62 1 5 14 21 62 1 5 15 22 62 1 6 16 24 62 2 3 4 23 62 2 4 9 27 62 2 13 23 25 62 2 20 24 26 62 2 20 25 28 63 1 1 5 29 63 1 1 8 34 63 1 5 15 30 63 2 4 10 33 63 2 4 11 31 63 2 13 23 32 63 40 40 41 35 65 1 NULL 1 36 65 1 NULL 1 38 68 2 13 22 37 68 2 20 25 39 68 2 23 27 40 92 1 NULL 1 Table 2 Department_ID Department_Name Parent_Id Parent_Name -------------------- ----------------------- --------------- ---------------------------------------------------------------------------------- 1 Food 1, 5, 6 Food, North Indian, South Indian 2 Lodging 3, 4, 13, 20, 23 Room, Floor, Non Air Conditioned, With Balcony, Without Balcony 40 New 40 SubNew TABLE 3 Parent_Id Parent_Name Preference_ID Preference_Name -------------------- ----------------------------------------------- ----------------------- ------------------- NULL NULL NULL NULL 1 Food 5, 8 North Indian, Italian 3 Room 4 Floor 4 Floor 9, 10, 11 First, Second, Third 5 North Indian 14, 15 X, Y 6 South Indian 16 Dosa 13 Non Air Conditioned 22, 23 With Balcony, Without Balcony 20 With Balcony 24, 25, 26 Mountain View, Ocean View, Garden View 23 Without Balcony 27 Mountain View 40 New 41 SubNew I have these 3 tables that are related in some fashion like this. Table 1 will be the master for these 2 tables i.e. table 2 and table 3. I need to query on them as SELECT Department_Id, Department_Name, Parent_Name FROM Table2 WHERE Department_Id in ( SELECT Department_Id FROM Table1 WHERE guest_id=65 ) SELECT Parent_Id, Parent_Name, Preference_Name FROM Table3 WHERE PARENT_ID in ( SELECT parent_id FROM Table1 WHERE guest_id=65 ) Now I need to use these queries on DataTables. So I am using Query Syntax for this and reached up to this point. var dept_list= from dept in DtMapGuestDepartment.AsEnumerable() where dept.Field<long>("PK_GUEST_ID")==long.Parse(63) select dept; This should give me the list of all departments that has guest id =63 Now I want to select all departments_name and parent_name from Table 2 where guest_id=63 i.e. departments that i fetched above. This same case will be followed for Table3. Please suggest how to do this. Thanks for keeping up patience for reading my question.

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  • Setting WPF image source in code

    - by Torbjørn
    I'm trying to set a WPF image's source in code. The image is embedded as a resource in the project. By looking at examples I've come up with the below code. For some reason it doesn't work - the image does not show up. By debugging I can see that the stream contains the image data. So what's wrong? Assembly asm = Assembly.GetExecutingAssembly(); Stream iconStream = asm.GetManifestResourceStream("SomeImage.png"); PngBitmapDecoder iconDecoder = new PngBitmapDecoder(iconStream, BitmapCreateOptions.PreservePixelFormat, BitmapCacheOption.Default); ImageSource iconSource = iconDecoder.Frames[0]; _icon.Source = iconSource; The icon is defined something like this: <Image x:Name="_icon" Width="16" Height="16" />

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  • How do I add artwork to an iTunes track with obj-c AppleScript?

    - by demonslayer319
    aTrack is an ITReference* object, value is an NSImage* object, initialized via a URL to a jpeg. [[[[[aTrack artworks] data_] set] to:value] send]; I get the following message in GDB: 2010-03-09 16:59:42.860 Sandbox[2260:a0f] Can't pack object of class NSImage (unsupported type): <NSImage 0x10054a440 Size={0, 0} Reps=( I then tried the following code: NSData *imageData = [[NSData alloc] initWithData:[value TIFFRepresentation]]; [[[[[aTrack artworks] data_] set] to:imageData] send]; and get this message instead 2010-03-09 16:46:09.341 Sandbox[2193:a0f] Can't pack object of class NSConcreteData (unsupported type): <4d4d002a 00000000> In the AppleScript documentation, it says that the "data" property of the "artwork" item is a PICTPicture image. How do I convert an NSImage to a PICT? Am I using the AppleScript all wrong?

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  • Stack trace method names redacted

    - by c.cam108
    I have users email me stack traces when my app crashes on their device. Prior to iOS 6 they looked like this: CRASH: NSInvalidArgumentException (*** -[__NSArrayM insertObject:atIndex:]: object cannot be nil) TRACE: ( 0 CoreFoundation 0x355e58a7 __exceptionPreprocess + 186 1 libobjc.A.dylib 0x3798c259 objc_exception_throw + 32 2 CoreFoundation 0x3553a1d7 -[__NSArrayM insertObject:atIndex:] + 186 3 MYAPP 0x0006c0f7 MYAPP + 188663 4 MYAPP 0x000652a3 MYAPP + 160419 5 Foundation 0x3512ac29 __65-[NSURLConnectionInternal _withConnectionAndDelegate:onlyActive:]_block_invoke_0 + 16 6 Foundation 0x350826d9 -[NSURLConnectionInternalConnection invokeForDelegate:] + 28 7 Foundation 0x350826a3 -[NSURLConnectionInternal _withConnectionAndDelegate:onlyActive:] + 198 8 Foundation 0x350825c5 -[NSURLConnectionInternal _withActiveConnectionAndDelegate:] + 60 9 CFNetwork 0x34de77f5 _ZN19URLConnectionClient23_clientDidFinishLoadingEPNS_26ClientConnectionEventQueueE + 192 10 CFNetwork 0x34ddc4a5 _ZN19URLConnectionClient26ClientConnectionEventQueue33processAllEventsAndConsumePayloadEP20XConnectionEventInfoI12XClientEvent18XClientEventParamsEl + 424 11 CFNetwork 0x34ddc1a3 _ZN19URLConnectionClient13processEventsEv + 106 12 CFNetwork 0x34ddc0d9 _ZN17MultiplexerSource7performEv + 156 13 CoreFoundation 0x355b9ad3 __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION__ + 14 14 CoreFoundation 0x355b929f __CFRunLoopDoSources0 + 214 15 CoreFoundation 0x355b8045 __CFRunLoopRun + 652 16 CoreFoundation 0x3553b4a5 CFRunLoopRunSpecific + 300 17 CoreFoundation 0x3553b36d CFRunLoopRunInMode + 104 18 GraphicsServices 0x371d7439 GSEventRunModal + 136 19 UIKit 0x33047cd5 UIApplicationMain + 1080 20 MYAPP 0x0003fbcf MYAPP + 7119 21 MYAPP 0x0003fb84 MYAPP + 7044 ) From the CoreFoundation etc method names and asking the user what happened, I can get a pretty good idea of where the crash happened. However, since iOS 6 was released, my crash reports all look like this: CRASH: NSRangeException (*** -[__NSArrayI objectAtIndex:]: index 2147483670 beyond bounds [0 .. 11]) TRACE: ( 0 CoreFoundation 0x3a3872bb <redacted> + 186 1 libobjc.A.dylib 0x32ca697f objc_exception_throw + 30 2 CoreFoundation 0x3a2d1e8d <redacted> + 164 3 MYAPP 0x000ff721 MYAPP + 214817 4 MYAPP 0x000e8999 MYAPP + 121241 5 UIKit 0x372f60ad <redacted> + 72 6 UIKit 0x372f605f <redacted> + 30 7 UIKit 0x372f603d <redacted> + 44 8 UIKit 0x372f58f3 <redacted> + 502 9 UIKit 0x372e1287 <redacted> + 526 10 UIKit 0x37373f3d <redacted> + 748 11 UIKit 0x3721e52b <redacted> + 318 12 UIKit 0x3720b809 <redacted> + 380 13 UIKit 0x3720b123 <redacted> + 6154 14 GraphicsServices 0x362085a3 <redacted> + 590 15 GraphicsServices 0x362081d3 <redacted> + 34 16 CoreFoundation 0x3a35c173 <redacted> + 34 17 CoreFoundation 0x3a35c117 <redacted> + 138 18 CoreFoundation 0x3a35af99 <redacted> + 1384 19 CoreFoundation 0x3a2cdebd CFRunLoopRunSpecific + 356 20 CoreFoundation 0x3a2cdd49 CFRunLoopRunInMode + 104 21 GraphicsServices 0x362072eb GSEventRunModal + 74 22 UIKit 0x3725f301 UIApplicationMain + 1120 23 MYAPP 0x000ccbd3 MYAPP + 7123 24 MYAPP 0x000ccb88 MYAPP + 7048 ) I get the stack trace from here, which the user is prompted to email when the app is re-opened: void uncaughtExceptionHandler(NSException *exception) { //make a file name to write the data to using the documents directory: NSString *fileName = [NSString stringWithFormat:@"%@/crashlog.txt", documentsDirectory]; //create content - four lines of text NSString *content = [NSString stringWithFormat:@"CRASH: %@ (%@)\n\nTRACE: %@", [exception name], [exception reason], [exception callStackSymbols]]; //save content to the documents directory [content writeToFile:fileName atomically:NO encoding:NSStringEncodingConversionAllowLossy error:nil]; } Without the method names, this is worse than useless. Is there any way of getting these method names back into my stack traces? This is a release configuration, not debug.

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  • R glm standard error estimate differences to SAS PROC GENMOD

    - by Michelle
    I am converting a SAS PROC GENMOD example into R, using glm in R. The SAS code was: proc genmod data=data0 namelen=30; model boxcoxy=boxcoxxy ~ AGEGRP4 + AGEGRP5 + AGEGRP6 + AGEGRP7 + AGEGRP8 + RACE1 + RACE3 + WEEKEND + SEQ/dist=normal; FREQ REPLICATE_VAR; run; My R code is: parmsg2 <- glm(boxcoxxy ~ AGEGRP4 + AGEGRP5 + AGEGRP6 + AGEGRP7 + AGEGRP8 + RACE1 + RACE3 + WEEKEND + SEQ , data=data0, family=gaussian, weights = REPLICATE_VAR) When I use summary(parmsg2) I get the same coefficient estimates as in SAS, but my standard errors are wildly different. The summary output from SAS is: Name df Estimate StdErr LowerWaldCL UpperWaldCL ChiSq ProbChiSq Intercept 1 6.5007436 .00078884 6.4991975 6.5022897 67911982 0 agegrp4 1 .64607262 .00105425 .64400633 .64813891 375556.79 0 agegrp5 1 .4191395 .00089722 .41738099 .42089802 218233.76 0 agegrp6 1 -.22518765 .00083118 -.22681672 -.22355857 73401.113 0 agegrp7 1 -1.7445189 .00087569 -1.7462352 -1.7428026 3968762.2 0 agegrp8 1 -2.2908855 .00109766 -2.2930369 -2.2887342 4355849.4 0 race1 1 -.13454883 .00080672 -.13612997 -.13296769 27817.29 0 race3 1 -.20607036 .00070966 -.20746127 -.20467944 84319.131 0 weekend 1 .0327884 .00044731 .0319117 .03366511 5373.1931 0 seq2 1 -.47509583 .00047337 -.47602363 -.47416804 1007291.3 0 Scale 1 2.9328613 .00015586 2.9325559 2.9331668 -127 The summary output from R is: Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 6.50074 0.10354 62.785 < 2e-16 AGEGRP4 0.64607 0.13838 4.669 3.07e-06 AGEGRP5 0.41914 0.11776 3.559 0.000374 AGEGRP6 -0.22519 0.10910 -2.064 0.039031 AGEGRP7 -1.74452 0.11494 -15.178 < 2e-16 AGEGRP8 -2.29089 0.14407 -15.901 < 2e-16 RACE1 -0.13455 0.10589 -1.271 0.203865 RACE3 -0.20607 0.09315 -2.212 0.026967 WEEKEND 0.03279 0.05871 0.558 0.576535 SEQ -0.47510 0.06213 -7.646 2.25e-14 The importance of the difference in the standard errors is that the SAS coefficients are all statistically significant, but the RACE1 and WEEKEND coefficients in the R output are not. I have found a formula to calculate the Wald confidence intervals in R, but this is pointless given the difference in the standard errors, as I will not get the same results. Apparently SAS uses a ridge-stabilized Newton-Raphson algorithm for its estimates, which are ML. The information I read about the glm function in R is that the results should be equivalent to ML. What can I do to change my estimation procedure in R so that I get the equivalent coefficents and standard error estimates that were produced in SAS? To update, thanks to Spacedman's answer, I used weights because the data are from individuals in a dietary survey, and REPLICATE_VAR is a balanced repeated replication weight, that is an integer (and quite large, in the order of 1000s or 10000s). The website that describes the weight is here. I don't know why the FREQ rather than the WEIGHT command was used in SAS. I will now test by expanding the number of observations using REPLICATE_VAR and rerunning the analysis.

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  • Sample the deltas between values using boost::accumulators

    - by Checkers
    I have a data set with N integers (say, 13, 16, 17, 20) where each next sample is incremented by some value (3, 1, 3 in this case) and I want to use boost::accumulators::accumulator_set to find various statistics of the second sequence. I want to be able to do something like this: accumulator_set< double, features< tag::mean > > acc; ... acc(13); acc(16); acc(17); acc(20); ...BUT sampling the differences instead of the actual values. How can I do that with accumulator_set without keeping track of the last value manually?

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  • PHP array ordering

    - by Melonheadjr44
    Hi, I was wondering how I could sort this array, when I use asort right now it does 14 17 16 15. How would I go to have 14 15 16 17 array(4) { [15]=> array(9) { [2025]=> string(80) "20:25 à 21:15 Spectacle / L'histoire d'un coeur / Auditorium, É.S.P. De La Salle" [2135]=> string(71) "21:35 à 22:25 Spectacle / Transfugue 2 / Auditorium, É.S.P. De La Salle" [1430]=> string(64) "14:30 à 15:30 Mise en lecture/Théâtre la Catapulte / De La Salle" [110]=> string(44) "11:00 à 13:00 Inscription / Pavillon Tabaret" [1330]=> string(49) "13:30 à 14:30 CÉRÉMONIE D'OUVERTURE / De La Salle" [1550]=> string(61) "15:50 à 16:40 Spectacle/Université Laurentienne / De La Salle" [170]=> string(57) "17:00 à 17:50 Spectacle/Université d'Ottawa / De La Salle" [1750]=> string(45) "17:50 à 19:00 REPAS DE L'AMITIÉ / De La Salle" [1915]=> string(76) "19:15 à 20:05 Spectacle / Attendre la pluie / Auditorium, É.S.P. De La Salle" } [16]=> array(8) { [1845]=> string(81) "18:45 à 19:35 Spectacle / Mimes d'horreur / Salle Académique, Université d'Ottawa" [1955]=> string(73) "19:55 à 20:45 Spectacle / Déroute / Salle Académique, Université d'Ottawa" [8]=> string(45) "08:30 à 11:30 Atelier / ABC du jeu dramatique" [13]=> string(41) "13:00 à 16:00 Atelier / Théâtre physique" [1130]=> string(28) "11:30 à 13:00 DÎNER LIBRE / " [1620]=> string(29) "16:20 à 18:20 SOUPER LIBRE / " [220]=> string(58) "22:00 à 23:30 BAL MASQUÉ / l'Agora du centre universitaire" [210]=> string(47) "21:00 à 22:00 Rétroaction / Université d'Ottawa" } [17]=> array(4) { [950]=> string(79) "09:50 à 10:40 Spectacle / Raison d'être / Salle Académique, Université d'Ottawa" [110]=> string(76) "11:00 à 11:50 Spectacle / Potionnée / Salle Académique, Université d'Ottawa" [120]=> string(28) "12:00 à 13:00 DÎNER LIBRE / " [1330]=> string(48) "13:30 à 14:30 CÉRÉMONIE DE CLÔTURE / De La Salle" } [14]=> array(1) { [150]=> string(49) "15:00 à 16:30 Préparation technique / De La Salle" } }

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  • How do I add artwork to an iTunes track with obj-c AppScript?

    - by demonslayer319
    aTrack is an ITReference* object, value is an NSImage* object, initialized via a URL to a jpeg. [[[[[aTrack artworks] data_] set] to:value] send]; I get the following message in GDB: 2010-03-09 16:59:42.860 Sandbox[2260:a0f] Can't pack object of class NSImage (unsupported type): <NSImage 0x10054a440 Size={0, 0} Reps=( I then tried the following code: NSData *imageData = [[NSData alloc] initWithData:[value TIFFRepresentation]]; [[[[[aTrack artworks] data_] set] to:imageData] send]; and get this message instead 2010-03-09 16:46:09.341 Sandbox[2193:a0f] Can't pack object of class NSConcreteData (unsupported type): <4d4d002a 00000000> In the AppScript documentation, it says that the "data" property of the "artwork" item is a PICTPicture image. How do I convert an NSImage to a PICT? Am I using the AppScript all wrong?

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  • How to make awkward pivot of sql table in MS SQL Server 2005?

    - by Oliver
    I have to rotate a given table from an sql server but a normal pivot just doesn't work (as far as i tried). So has anybody an idea how to rotate the table into the desired format? Just to make the problem more complicated, the list of given labels can vary and it is possible that a new label name can come into at any given time. Given Data ID | Label | Numerator | Denominator | Ratio ---+-----------------+-------------+---------------+-------- 1 | LabelNameOne | 41 | 10 | 4,1 1 | LabelNameTwo | 0 | 0 | 0 1 | LabelNameThree | 21 | 10 | 2,1 1 | LabelNameFour | 15 | 10 | 1,5 2 | LabelNameOne | 19 | 19 | 1 2 | LabelNameTwo | 0 | 0 | 0 2 | LabelNameThree | 15 | 16 | 0,9375 2 | LabelNameFive | 19 | 19 | 1 2 | LabelNameSix | 17 | 17 | 1 3 | LabelNameOne | 12 | 12 | 1 3 | LabelNameTwo | 0 | 0 | 0 3 | LabelNameThree | 11 | 12 | 0,9167 3 | LabelNameFour | 12 | 12 | 1 3 | LabelNameSix | 0 | 1 | 0 Wanted result ID | ValueType | LabelNameOne | LabelNameTwo | LabelNameThree | LabelNameFour | LabelNameFive | LabelNameSix ---+-------------+--------------+--------------+----------------+---------------+---------------+-------------- 1 | Numerator | 41 | 0 | 21 | 15 | | 1 | Denominator | 10 | 0 | 10 | 10 | | 1 | Ratio | 4,1 | 0 | 2,1 | 1,5 | | 2 | Numerator | 19 | 0 | 15 | | 19 | 17 2 | Denominator | 19 | 0 | 16 | | 19 | 17 2 | Ratio | 1 | 0 | 0,9375 | | 1 | 1 3 | Numerator | 12 | 0 | 11 | 12 | | 0 3 | Denominator | 12 | 0 | 12 | 12 | | 1 3 | Ratio | 1 | 0 | 0,9167 | 1 | | 0

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  • Confusion testing fftw3 - poisson equation 2d test

    - by user3699736
    I am having trouble explaining/understanding the following phenomenon: To test fftw3 i am using the 2d poisson test case: laplacian(f(x,y)) = - g(x,y) with periodic boundary conditions. After applying the fourier transform to the equation we obtain : F(kx,ky) = G(kx,ky) /(kx² + ky²) (1) if i take g(x,y) = sin (x) + sin(y) , (x,y) \in [0,2 \pi] i have immediately f(x,y) = g(x,y) which is what i am trying to obtain with the fft : i compute G from g with a forward Fourier transform From this i can compute the Fourier transform of f with (1). Finally, i compute f with the backward Fourier transform (without forgetting to normalize by 1/(nx*ny)). In practice, the results are pretty bad? (For instance, the amplitude for N = 256 is twice the amplitude obtained with N = 512) Even worse, if i try g(x,y) = sin(x)*sin(y) , the curve has not even the same form of the solution. (note that i must change the equation; i divide by two the laplacian in this case : (1) becomes F(kx,ky) = 2*G(kx,ky)/(kx²+ky²) Here is the code: /* * fftw test -- double precision */ #include <iostream> #include <stdio.h> #include <stdlib.h> #include <math.h> #include <fftw3.h> using namespace std; int main() { int N = 128; int i, j ; double pi = 3.14159265359; double *X, *Y ; X = (double*) malloc(N*sizeof(double)); Y = (double*) malloc(N*sizeof(double)); fftw_complex *out1, *in2, *out2, *in1; fftw_plan p1, p2; double L = 2.*pi; double dx = L/((N - 1)*1.0); in1 = (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*(N*N) ); out2 = (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*(N*N) ); out1 = (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*(N*N) ); in2 = (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*(N*N) ); p1 = fftw_plan_dft_2d(N, N, in1, out1, FFTW_FORWARD,FFTW_MEASURE ); p2 = fftw_plan_dft_2d(N, N, in2, out2, FFTW_BACKWARD,FFTW_MEASURE); for(i = 0; i < N; i++){ X[i] = -pi + (i*1.0)*2.*pi/((N - 1)*1.0) ; for(j = 0; j < N; j++){ Y[j] = -pi + (j*1.0)*2.*pi/((N - 1)*1.0) ; in1[i*N + j][0] = sin(X[i]) + sin(Y[j]) ; // row major ordering //in1[i*N + j][0] = sin(X[i]) * sin(Y[j]) ; // 2nd test case in1[i*N + j][1] = 0 ; } } fftw_execute(p1); // FFT forward for ( i = 0; i < N; i++){ // f = g / ( kx² + ky² ) for( j = 0; j < N; j++){ in2[i*N + j][0] = out1[i*N + j][0]/ (i*i+j*j+1e-16); in2[i*N + j][1] = out1[i*N + j][1]/ (i*i+j*j+1e-16); //in2[i*N + j][0] = 2*out1[i*N + j][0]/ (i*i+j*j+1e-16); // 2nd test case //in2[i*N + j][1] = 2*out1[i*N + j][1]/ (i*i+j*j+1e-16); } } fftw_execute(p2); //FFT backward // checking the results computed double erl1 = 0.; for ( i = 0; i < N; i++) { for( j = 0; j < N; j++){ erl1 += fabs( in1[i*N + j][0] - out2[i*N + j][0]/N/N )*dx*dx; cout<< i <<" "<< j<<" "<< sin(X[i])+sin(Y[j])<<" "<< out2[i*N+j][0]/N/N <<" "<< endl; // > output } } cout<< erl1 << endl ; // L1 error fftw_destroy_plan(p1); fftw_destroy_plan(p2); fftw_free(out1); fftw_free(out2); fftw_free(in1); fftw_free(in2); return 0; } I can't find any (more) mistakes in my code (i installed the fftw3 library last week) and i don't see a problem with the maths either but i don't think it's the fft's fault. Hence my predicament. I am all out of ideas and all out of google as well. Any help solving this puzzle would be greatly appreciated. note : compiling : g++ test.cpp -lfftw3 -lm executing : ./a.out output and i use gnuplot in order to plot the curves : (in gnuplot ) splot "output" u 1:2:4 ( for the computed solution )

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  • How does this method give me a -61 Error?

    - by prestonmarshall
    This is in an application I am using called Mirth, but it appears to be coming from inside an Apache Commons library from a method that checks if something is indeed Base64 encoded or not. All of the docs say the only return is true or false, so how am I getting -61? -61 org.apache.commons.codec.binary.Base64.isBase64(Base64.java:137) org.apache.commons.codec.binary.Base64.discardNonBase64(Base64.java:478) org.apache.commons.codec.binary.Base64.decodeBase64(Base64.java:374) org.apache.commons.codec.binary.Base64.decode(Base64.java:220) com.webreach.mirth.plugins.pdfviewer.PDFViewer.viewAttachments(PDFViewer.java:51) com.webreach.mirth.client.ui.browsers.message.MessageBrowser$16.doInBackground(MessageBrowser.java:1429) com.webreach.mirth.client.ui.browsers.message.MessageBrowser$16.doInBackground(MessageBrowser.java:1426) org.jdesktop.swingworker.SwingWorker$1.call(SwingWorker.java:276) java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:303) java.util.concurrent.FutureTask.run(FutureTask.java:138) org.jdesktop.swingworker.SwingWorker.run(SwingWorker.java:315) java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886) java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908) java.lang.Thread.run(Thread.java:637)

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  • iPhone current user location coordinates showing as (0,0)

    - by ennuikiller
    I'm trying to get the users current latitude and longitude with this viewDidLoad method. The resulting map is correctly indicating the current location however the NSLog consistently shows: 2009-09-19 16:45:29.765 Mapper[671:207] user latitude = 0.000000 2009-09-19 16:45:29.772 Mapper[671:207] user longitude = 0.000000 Anyone know what I am missing here? Thanks in advance for your help! - (void)viewDidLoad { [super viewDidLoad]; [mapView setMapType:MKMapTypeStandard]; [mapView setZoomEnabled:YES]; [mapView setScrollEnabled:YES]; [mapView setShowsUserLocation:YES]; CLLocation *userLoc = mapView.userLocation.location; CLLocationCoordinate2D userCoordinate = userLoc.coordinate; NSLog(@"user latitude = %f",userCoordinate.latitude); NSLog(@"user longitude = %f",userCoordinate.longitude); }

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  • Get the number of calendar weeks between 2 dates in C#

    - by Phil Scholtes
    For the purposes of this question, let's assume the user will be from the US and will use the standard Gregorian calendar. So, a calendar week starts on Sunday and ends on Saturday. What I'm trying to do is determine the number of calendar weeks that exist between two dates. A perfect example of my problem exists in October 2010. Between 10/16 and 10/31 there are 4 calendar weeks. View a picture of October 2010 October 10 - October 16 October 17 - October 23 October 24 - October 30 October 31 - November 6 I'd prefer to stay away from any hardcoded logic like: if (Day == DayOfWeek.Saturday && LastDayOfMonth == 31) { ... } Can anyone think of a logical way to do this?

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  • How to see a branch created in master

    - by richard
    Hi, I create a branch in my master repository (192.168.1.2). And in my other computer, I did '$ git pull --rebase ', I see Unpacking objects: 100% (16/16), done. From git+ssh://[email protected]/media/LINUXDATA/mozilla-1.9.1 62d004e..b291703 master -> origin/master * [new branch] improv -> origin/improv But when I do a 'git branch' in my local repository, I see only 1 branch and I did '$ git checkout improv ' $ git branch * master $ git checkout improv error: pathspec 'improv' did not match any file(s) known to git. Did you forget to 'git add'?

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  • How to set that compiler flag?

    - by mystify
    Shark told me this: This instruction is the start of a loop that is not aligned to a 16-byte address boundary. For optimal performance, you should align the start of a hot loop using a compiler directive. With gcc 3.3 or later, use the -falign-loops=16 compiler flag. for (int i=0; i < 4; i++) { // line with the info //...code } How would I set that flag, and does it really improve performance?

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  • mysql alter to table

    - by user485783
    Hi, I drop the mysql alter code below to database via phpmyadmin one by one, it it work fine, is there anyone could help me how to drop it all together at once? or do you know the the samples of php code that may execute it? just let me know please. thanks in advace ALTER TABLE user ADD title varchar(16) COLLATE utf8_bin NOT NULL DEFAULT '' AFTER user_id ALTER TABLE customer ADD title varchar(16) COLLATE utf8_bin NOT NULL DEFAULT '' AFTER customer_id ALTER TABLE customer ADD date_birtdate datetime NOT NULL DEFAULT '0000-00-00 00:00:00' AFTER lastname ALTER TABLE customer ADD security_question varchar(96) COLLATE utf8_bin NOT NULL DEFAULT '' AFTER fax ALTER TABLE customer ADD security_answer varchar(96) COLLATE utf8_bin NOT NULL DEFAULT '' AFTER fax ALTER TABLE customer ADD pin_number text COLLATE utf8_bin AFTER password ALTER TABLE customer ADD notes text COLLATE utf8_bin AFTER bank_number ALTER TABLE customer ADD last_active datetime NOT NULL DEFAULT '0000-00-00 00:00:00' AFTER date_added

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  • CakeDC Users Plugin - I Can't Send Emails

    - by JimBadger
    I apologise for the rambling nature of this question, please bear with me and I'll provide all the extra info needed for you to stop me going mad from failing at something that looks inherently very straightforward... I've just installed CakePHP 2.2, and the first thing I've done is add the cakeDC Users plugin. It's all working, apart from sending an email verification when a user registers. I've tried so many combinations of different things in email.php, that I have now utterly got my knickers in a twist. Whatever I do, when the verification email should be sent, all I get is: No connection could be made because the target machine actively refused it. My email.php currently looks like this: class EmailConfig { public $default = array( 'transport' => 'Smtp', 'from' => '[email protected]', //'charset' => 'utf-8', //'headerCharset' => 'utf-8', ); public $smtp = array( 'transport' => 'Smtp', 'from' => array('Blah <[email protected]>' => 'Chimp'), 'host' => 'ssl://smtp.gmail.com', 'port' => 465, 'timeout' => 30, 'username' => '[email protected]', 'password' => 'secret', 'client' => null, 'log' => false, //'charset' => 'utf-8', //'headerCharset' => 'utf-8', ); public $fast = array( 'from' => '[email protected]', 'sender' => null, 'to' => null, 'cc' => null, 'bcc' => null, 'replyTo' => null, 'readReceipt' => null, 'returnPath' => null, 'messageId' => true, 'subject' => null, 'message' => null, 'headers' => null, 'viewRender' => null, 'template' => false, 'layout' => false, 'viewVars' => null, 'attachments' => null, 'emailFormat' => null, 'transport' => 'Smtp', 'host' => 'blah.net', 'port' => 25, 'timeout' => 30, 'username' => 'user', 'password' => 'secret', 'client' => null, 'log' => true, //'charset' => 'utf-8', //'headerCharset' => 'utf-8', ); } How do I get cakeDC Users plugin to just send a non-SMTP email? Or do I have to use, for example, my Gmail details? But, if I do have to go down the SMTP route, what is wrong with the above? Other info: I'm using the latest version of XAMPP and my PHP install is ssl enabled.

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  • How do I check the validity of the Canadian Social Insurance Number in C#?

    - by user518307
    I've been given the assignment to write an algorithm in C# that checks the validity of a Canadian Social Insurance Number (SIN). Here are the steps to validate a SIN. Given an example Number: 123 456 782 Remove the check digit (the last digit): 123456782 Extract the even digits (2,4,6,8th digith): 12345678 Double them: 2 4 6 8 | | | | v v v v 4 8 12 16 Add the digits together: 4+8+1+2+1+6 = 22 Add the Odd placed digits: 1+3+5+7 = 16 Total : 38 Validity Algorithm If the total is a multiple of 10, the check digit should be zero. Otherwise, Subtract the Total from the next highest multiple of 10 (40 in this case) The check digit for this SIN must be equal to the difference of the number and the totals from earlier (in this case, 40-38 = 2; check digit is 2, so the number is valid) I'm lost on how to actually implement this in C#, how do I do this?

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  • Calculate hours difference in datetime

    - by ScG
    I have a series of datetime values. I want to select records with a difference of 2 or more hours between them. 2010-02-11 08:55:00.000 2010-02-11 10:45:00.000 2010-02-11 10:55:00.000 2010-02-11 12:55:00.000 2010-02-11 14:52:00.000 2010-02-11 16:55:00.000 2010-02-11 17:55:00.000 2010-02-11 23:55:00.000 2010-02-12 00:55:00.000 2010-02-12 02:55:00.000 Expected (The next date compared is with the last date that qualified for the 2 hr difference): 2010-02-11 08:55:00.000 2010-02-11 10:55:00.000 2010-02-11 12:55:00.000 2010-02-11 16:55:00.000 2010-02-11 23:55:00.000 2010-02-12 02:55:00.000 I am using SQL 2005 or 2008

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  • How to find the Mac address of a 'shutdown' system on local lan (is it possible?)

    - by pirates-iiita
    hello everyone, Can anyone please tell the way to find out the mac address of a system which is: Shutdown Power plugged in Connected to Lan Nic card ON. Kindly post the solution as i urgently need it in my project... thank you Update I am asking how to find out the mac address of some other system which is already shutdown.... and which is on lan.. I want to find out its mac from my system.... and to be clear... i want to tell that.. arp table can be populated by using ping .. i.e. if 172.16.3.12 is not in arp table then it can be added by just ping 172.16.3.12 but a system can be pinged only if its on ... a shutdown system can't be pinged...

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