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  • Getting error that the database is locked when refreshing the page

    - by acidzombie24
    The title is a joke. However it is serious as far as my app is concerned. I am running apache with mod mono and my asp.net app is using mono sqlite as its db. When i refresh the page twice i get the DB is locked error. The folder it is in is chmod 777. The webapp is creating sqlite.db and sqlite.db-journal but it doesnt seem to be able to delete the journal. i'm confused. What permissions do i need to set these? i tried precreating the files using 777 and had no luck.

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  • Codeigniter: Controller URI with Library

    - by Kevin Brown
    I have a working controller and library function, but I now need to pass a URI segment to the library for decision making, and I'm stuck. Controller: function survey($method) { $id = $this->session->userdata('id'); $data['member'] = $this->home_model->getUser($id); //Convert the db Object to a row array $data['manager'] = $data['member']->row(); $manager_id = $data['manager']->manager_id; $data['manager'] = $this->home_model->getUser($manager_id); $data['manager'] = $data['manager']->row(); if ($data['manager']->credits == '0') { flashMsg('warning',"You can't complete the assessment until your manager has purchased credit."); redirect('home','location'); } elseif ($data['manager']->test_complete == '3'){ flashMsg('warning',"You already completed the Assessment."); redirect('home','location'); } else{ $data['header'] = "Home"; $this->survey_form_processing->survey_form($this->_container,$data); } } Library: function survey_form($container) { if($method ==1){ $id = $this->CI->session->userdata('id'); // Setup fields for($i=1;$i<18;$i++){ $fields["a_".$i] = 'Question '.$i; } for($i=1;$i<17;$i++){ $fields["b_".$i] = 'Question '.$i; } $fields["company_name"] = "Company Name"; $fields['company_address'] = "company_address"; $fields['company_phone'] = "company_phone"; $fields['company_state'] = "company_state"; $fields['company_city'] = "company_city"; $fields['company_zip'] = "company_zip"; $fields['job_title'] = "job_title"; $fields['job_type'] = "job_type"; $fields['job_time'] = "job_time"; $fields['department'] = "department"; $fields['supervisor'] = "supervisor"; $fields['vision'] = "vision"; $fields['height'] = "height"; $fields['weight'] = "weight"; $fields['hand_dominance'] = "hand_dominance"; $fields['areas_of_fatigue'] = "areas_of_fatigue"; $fields['injury_review'] = "injury_review"; $fields['job_positive'] = "job_positive"; $fields['risk_factors'] = "risk_factors"; $fields['job_improvement_short'] = "job_improvement_short"; $fields['job_improvement_long'] = "job_improvement_long"; $fields["c_1"] = "Near Lift"; $fields["c_2"] = "Middle Lift"; $fields["c_3"] = "Far Lift"; $this->CI->validation->set_fields($fields); // Set Rules for($i=1;$i<18;$i++){ $rules["a_".$i]= 'hour|integer|max_length[2]'; } for($i=1;$i<17;$i++){ $rules["b_".$i]= 'hour|integer|max_length[2]'; } // Setup form default values $this->CI->validation->set_rules($rules); if ( $this->CI->validation->run() === FALSE ) { // Output any errors $this->CI->validation->output_errors(); } else { // Submit form $this->_submit(); } // Modify form, first load $this->CI->db->from('be_user_profiles'); $this->CI->db->where('user_id' , $id); $user = $this->CI->db->get(); $this->CI->db->from('be_survey'); $this->CI->db->where('user_id' , $id); $survey = $this->CI->db->get(); $user = array_merge($user->row_array(),$survey->row_array()); $this->CI->validation->set_default_value($user); // Display page $data['user'] = $user; $data['header'] = 'Risk Assessment Survey'; $data['page'] = $this->CI->config->item('backendpro_template_public') . 'form_survey'; $this->CI->load->view($container,$data); } else{ redirect('home','location'); } } My library function doesn't know what to do with Method...and I'm confused. Does it have something to do with instances in my library?

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  • How to check if an entityset is populated

    - by TheQ
    How can i check if an entityset of a linq-object is populated or not? Example code below. My model have two methods, one joins data, and the other does not: public static Member GetMemberWithSettings(Guid memberId) { using (DataContext db = new DataContext()) { DataLoadOptions dataLoadOptions = new DataLoadOptions(); dataLoadOptions.LoadWith<Member>(x => x.Settings); db.LoadOptions = dataLoadOptions; var query = from x in db.Members where x.MemberId == memberId select x; return query.FirstOrDefault(); } } public static Member GetMember(Guid memberId) { using (DataContext db = new DataContext()) { var query = from x in db.Members where x.MemberId == memberId select x; return query.FirstOrDefault(); } } Then my control have the following code: Member member1 = Member.GetMemberWithSettings(memberId); Member member2 = Member.GetMember(memberId); Debug.WriteLine(member1.Settings.Count); Debug.WriteLine(member2.Settings.Count); The last line will generate a "Cannot access a disposed object" exception. I know that i can get rid of that exception just by not disposing the datacontext, but then the last line will generate a new query to the database, and i don't want that. What i would like is something like: Debug.WriteLine((member1.Settings.IsPopulated()) ? member1.Settings.Count : -1); Debug.WriteLine((member2.Settings.IsPopulated()) ? member2.Settings.Count : -1); Is it possible?

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  • how to make objects globally accessible?

    - by fayer
    i have this code: class IC_Core { /** * Database * @var IC_Database */ public static $db = NULL; /** * Core * @var IC_Core */ protected static $_instance = NULL; private function __construct() { } public static function getInstance() { if ( ! is_object(self::$_instance)) { self::$_instance = new self(); self::initialize(self::$_instance); } return self::$_instance; } private static function initialize(IC_Core $IC_Core) { self::$db = new IC_Database($IC_Core); } } but when i wanna access IC_Database with: $IC = IC_Core::getInstance(); $IC->db->add() // it says that its not an object. i think the problem lies in self::$db = new IC_Database($IC_Core); but i dont know how to make it work. could someone give me a hand=) thanks!

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  • Utilizing 5 physical servers in 1 cluster

    - by Vijay Gharge
    Hi all, I have 5 physical servers with low end memory & cpu resources. I want to create 1 cluster using all these servers and want to run mysql db on the same such that mysql db would utilize 5 server's CPU power to execute db queries & same for memory. Could you please help me understanding how to achieve this? Regards,

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  • How to Merge two databases in one in SQL Server 2008?

    - by SzamDev
    Hi I have 2 PCs, each one of them has SQL Server 2008 installed on it and there is a database with data in it. I need a way that I can move data in my DB from this SQL Server to another one (another PC which has the same DB) move data from one PC to another one - There is one problem, the ID column, because each DB in my 2 PCs has data in it so this column counts from 1,2,3,....... ( data will be conflict with other data in my DB ) Is there any way to solve my problem and move data successfully?

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  • Pre loaded database on iPhone?

    - by Julian
    Hi, I have recently developed an app using core data as the storage db. The app allowed the user to read and write to the db. I am now developing a new app which the user doesnt need to write anything to the db, instead the app just needs to read the data. The data has relationships etc so cannot just use a plist or something similar. My question is should I use core data for such a requirement and if so how would i go about entering the data and then releasing the app. Would I have to code the data entry which would populate the db then remove all this code (as I dont want the database to repopulate every time the user opens the app)?? Is there a way to create a core data model using sql commands as with sqlite ie insert into..... etc? Any ideas/thoughts would be very helpful. Many thanks Jules

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  • How to do a back-reference on Google Webapp?

    - by jCuga
    I'm trying to access an object that is linked to by a db.ReferenceProperty in Google app engine. here's the model's code: class InquiryQuestion(db.Model): inquiry_ref = db.ReferenceProperty(reference_class=GiftInquiry, required=True, collection_name="inquiry_ref") And I am trying to access it in the following way: linkedObject = question.inquiry_ref and then linkedKey = linkedObject.key but it's not working. Can anyone please help?

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  • How to deal with unknown entity references?

    - by Chris
    I'm parsing (a lot of) XML files that contain entity references which i dont know in advance (can't change that fact). For example: xml = "<tag>I'm content with &funny; &entity; &references;.</tag>" when i try to parse this using the following code: final DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); final DocumentBuilder db = dbf.newDocumentBuilder(); final InputSource is = new InputSource(new StringReader(xml)); final Document d = db.parse(is); i get the following exception: org.xml.sax.SAXParseException: The entity "funny" was referenced, but not declared. but, what i do want to achieve is, that the parser replaces every entity that is not declared (unknown to the parser) with an empty String ''. Or even better, is there a way to pass a map to the parser like: Map<String,String> entityMapping = ... entityMapping.put("funny","very"); entityMapping.put("entity","important"); entityMapping.put("references","stuff"); so that i could do the following: final DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); final DocumentBuilder db = dbf.newDocumentBuilder(); final InputSource is = new InputSource(new StringReader(xml)); db.setEntityResolver(entityMapping); final Document d = db.parse(is); if i would obtain the text from the document using this example code i should receive: I'm content with very important stuff. Any suggestions? Of course, i already would be happy to just replace the unknown entity's with empty strings. Thanks,

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  • Error in django using Apache & mod_wsgi

    - by Ignacio
    Hey, I've been doing some changes to my django develpment env, as some of you suggested. So far I've managed to configure and run it successfully with postgres. Now I'm trying to run the app using apache2 and mod_wsgi, but I ran into this little problem after I followed the guidelines from the django docs. When I access localhost/myapp/tasks this error raises: Request Method: GET Request URL: http://localhost/myapp/tasks/ Exception Type: TemplateSyntaxError Exception Value: Caught an exception while rendering: argument 1 must be a string or unicode object Original Traceback (most recent call last): File "/usr/local/lib/python2.6/dist-packages/django/template/debug.py", line 71, in render_node result = node.render(context) File "/usr/local/lib/python2.6/dist-packages/django/template/defaulttags.py", line 126, in render len_values = len(values) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 81, in __len__ self._result_cache = list(self.iterator()) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 238, in iterator for row in self.query.results_iter(): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/query.py", line 287, in results_iter for rows in self.execute_sql(MULTI): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/query.py", line 2369, in execute_sql cursor.execute(sql, params) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/util.py", line 19, in execute return self.cursor.execute(sql, params) TypeError: argument 1 must be a string or unicode object ... ... ... And then it highlights a {% for t in tasks %} template tag, like the source of the problem is there, but it worked fine on the built-in server. The view associated with that page is really simple, just fetch all Task objects. And the template just displays them on a table. Also, some pages get rendered ok. Don't want to fill this Question with code, so if you need some more info I'd be glad to provide it. Thanks

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  • error in running recursion

    - by GOsha
    if running function returns server misconfiguration error function build_path($cid) { $result = array(); $DB = new MySQLTable; $DB->TblName = 'shop_categories'; $where['cat_id']['='] = $DB->CleanQuest($cid); $res = $DB->Select('cat_id,cat_name,cat_parent', $where); if($res !== 'false') { $pid = mysql_fetch_array($res); if($pid['cat_parent'] !== 0) { Echo $pid['cat_parent']; build_path($pid['cat_parent']); } else { Echo $pid['cat_id']; return true; } } return false; } I can't find an error here. Please help. Sorry for disturbing you all. The trouble was in comparison 'if($pid['cat_parent'] !== 0)': $pid['cat_parent'] was a string with int(0) Can i build this function to store full path without using GLOBALS and SESSION vars?

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  • Passing arguments and conditions to model in codeigniter

    - by stormdrain
    I'm adding some models to a project, and was wondering if there is a "best practice" kind of approach to creating models: Does it make sense to create a function for each specific query? I was starting to do this, then had the idea of creating a generic function that I could pass parameters to. e.g: Instead of function getClients(){ return $this->db->query('SELECT client_id,last FROM Names ORDER BY id DESC'); } function getClientNames($clid){ return $this->db->query('SELECT * FROM Names WHERE client_id = '.$clid); } function getClientName($nameID){ return $this->db->query('SELECT * FROM Names WHERE id ='.$nameID); } } Something like function getNameData($args,$cond){ if($cond==''){ $q=$this->db->query('SELECT '.$args.' FROM Names'); return $q; }else{ $q=$this->db->query('SELECT '.$args.' FROM Names WHERE '.$cond); return $q; } } where I can pass the fields and conditions (if applicable) to the model. Is there a reason the latter example would be a bad idea? Thanks!

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  • Codeigniter setting multiple where conditions, how to unset one

    - by Dustin
    I've got a script that is a notify_url from paypal that is supposed to update multiple tables in my database using the following code: //update first table $this-db-where('someid', $somid); $this-db-update('table', $data); ///update second table $this-db-where('somesecondid', $somesecondid) $this-db-update('anothertable', $data2); Then I get the following error: Unknown column 'somesecondid' in 'where clause' UPDATE anothertable SET avail = 0 WHERE someid = '13' AND somesecondid = '199' So codeigniter is combining those where clauses into a single query. Is there a way to unset the first one so it only has "UPDATE anothertable SET avail=0 WHERE somesecondid = 199" ? Thanks!

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  • Help with PHP MySQL join

    - by kester martinez
    Please help me to understand proper join syntax. I have table named inventory which has: trans_id trans_items items -> item_id trans_user employees -> person_id trans_date trans_comment trans_inventory As you can see above, trans_items is a foreign key in items table, and trans_user is a foreign key in employees table. Now what I want to do is to display in HTML the inventory table, but instead of displaying the item id, I want the ITEM NAME to be displayed. Here is what I have done. Please note I'm using CodeIgniter. public function getData(array $inputs) { $this->db->select('trans_items, trans_user, trans_date, trans_inventory, trans_comment'); $this->db->from('inventory'); $this->db->order_by('trans_date desc'); return $this->db->get()->result_array(); }

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  • EGODatabase does not retain inserted record

    - by user135775
    Hi Guy! I'm using EGODatabase to process my data. When I tried to insert data into the database which I created with Base and attached to the project, the data that was inserted programmatically will not show up when I restart my app.However the data inserted manually using Base will show up just fine. Following is the code for inserting data into the database: NSString *path = [[NSBundle mainBundle] pathForResource:@"Database" ofType:@"db"]; db = [EGODatabase databaseWithPath:path]; if ([db open]) { NSLog(@"Database is opened successfully!"); } else { NSLog(@"Database is failed to open!"); } NSArray *params = [NSArray arrayWithObjects:[aFeed feedID], [aFeed title], nil]; [db executeUpdate:@"Insert INTO Feed (FeedID, Title) VALUES (?, ?)" parameters:params]; EGODatabaseResult *results = [db executeQuery:@"SELECT * FROM Feed"]; for ( EGODatabaseRow * row in results) { NSLog(@"ID: %@ Title: %@", [row stringForColumn:@"FeedID"], [row stringForColumn:@"Title"]); } I appreciate if anyone can share me a working sample code for EGODatabase. I'm using EGODatabase because I might have multi-threading code that write to the database. Thank in advance.

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  • How can i clear a SQLite database each time i start my app

    - by AndroidUser99
    Hi, i want that each time i start my app my SQLite database get's cleaned for this, i need to make a method on my class MyDBAdapter.java code examples are welcome, i have no idea how to do it this is the dbadapter/helper i'm using: public class MyDbAdapter { private static final String TAG = "NotesDbAdapter"; private DatabaseHelper mDbHelper; private SQLiteDatabase mDb; private static final String DATABASE_NAME = "gpslocdb"; private static final String PERMISSION_TABLE_CREATE = "CREATE TABLE permission ( fk_email1 varchar, fk_email2 varchar, validated tinyint, hour1 time default '08:00:00', hour2 time default '20:00:00', date1 date, date2 date, weekend tinyint default '0', fk_type varchar, PRIMARY KEY (fk_email1,fk_email2))"; private static final String USER_TABLE_CREATE = "CREATE TABLE user ( email varchar, password varchar, fullName varchar, mobilePhone varchar, mobileOperatingSystem varchar, PRIMARY KEY (email))"; private static final int DATABASE_VERSION = 2; private final Context mCtx; private static class DatabaseHelper extends SQLiteOpenHelper { DatabaseHelper(Context context) { super(context, DATABASE_NAME, null, DATABASE_VERSION); } @Override public void onCreate(SQLiteDatabase db) { db.execSQL(PERMISSION_TABLE_CREATE); db.execSQL(USER_TABLE_CREATE); } @Override public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) { db.execSQL("DROP TABLE IF EXISTS user"); db.execSQL("DROP TABLE IF EXISTS permission"); onCreate(db); } } /** * Constructor - takes the context to allow the database to be * opened/created * * @param ctx the Context within which to work */ public MyDbAdapter(Context ctx) { this.mCtx = ctx; } /** * Open the database. If it cannot be opened, try to create a new * instance of the database. If it cannot be created, throw an exception to * signal the failure * * @return this (self reference, allowing this to be chained in an * initialization call) * @throws SQLException if the database could be neither opened or created */ public MyDbAdapter open() throws SQLException { mDbHelper = new DatabaseHelper(mCtx); mDb = mDbHelper.getWritableDatabase(); return this; } public void close() { mDbHelper.close(); } public long createUser(String email, String password, String fullName, String mobilePhone, String mobileOperatingSystem) { ContentValues initialValues = new ContentValues(); initialValues.put("email",email); initialValues.put("password",password); initialValues.put("fullName",fullName); initialValues.put("mobilePhone",mobilePhone); initialValues.put("mobileOperatingSystem",mobileOperatingSystem); return mDb.insert("user", null, initialValues); } public Cursor fetchAllUsers() { return mDb.query("user", new String[] {"email", "password", "fullName", "mobilePhone", "mobileOperatingSystem"}, null, null, null, null, null); } public Cursor fetchUser(String email) throws SQLException { Cursor mCursor = mDb.query(true, "user", new String[] {"email", "password", "fullName", "mobilePhone", "mobileOperatingSystem"} , "email" + "=" + email, null, null, null, null, null); if (mCursor != null) { mCursor.moveToFirst(); } return mCursor; } public List<Friend> retrieveAllUsers() { List <Friend> friends=new ArrayList<Friend>(); Cursor result=fetchAllUsers(); if( result.moveToFirst() ){ do{ //note.getString(note.getColumnIndexOrThrow(NotesDbAdapter.KEY_TITLE))); friends.add(new Friend(result.getString(result.getColumnIndexOrThrow("email")), "","","","")); }while( result.moveToNext() ); } return friends; } }

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  • Linq2SQL or EntityFramework and databinding

    - by rene marxis
    is there some way to do databinding with linq2SQL or EntityFramework using "typed links" to the bound property? Public Class Form1 Dim db As New MESDBEntities 'datacontext/ObjectContext Dim bs As New BindingSource Private Sub Form1_Load(sender As System.Object, e As System.EventArgs) Handles MyBase.Load bs.DataSource = (From m In db.PROB_GROUP Select m) grid.DataSource = bs TextBox1.DataBindings.Add("Text", bs, "PGR_NAME") TextBox1.DataBindings.Add("Text", bs, db.PROB_GROUP) '**<--- Somthing like this** End Sub End Class I'd like to have type checking when compiling and the model changed.

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  • How to check if a child-object is populated

    - by TheQ
    How can i check if a child-object of a linq-object is populated or not? Example code below. My model have two methods, one joins data, and the other does not: public static Member GetMemberWithPhoto(Guid memberId) { using (DataContext db = new DataContext()) { DataLoadOptions dataLoadOptions = new DataLoadOptions(); dataLoadOptions.LoadWith<Member>(x => x.UserPhoto); db.LoadOptions = dataLoadOptions; var query = from x in db.Members where x.MemberId == memberId select x; return query.FirstOrDefault(); } } public static Member GetMember(Guid memberId) { using (DataContext db = new DataContext()) { var query = from x in db.Members where x.MemberId == memberId select x; return query.FirstOrDefault(); } } Then my control have the following code: Member member1 = Member.GetMemberWithPhoto(memberId); Member member2 = Member.GetMember(memberId); Debug.WriteLine(member1.UserPhoto.ToString()); Debug.WriteLine(member2.UserPhoto.ToString()); The last line will generate a "Cannot access a disposed object" exception. I know that i can get rid of that exception just by not disposing the datacontext, but then the last line will generate a new query to the database, and i don't want that. What i would like is something like: Debug.WriteLine((member1.UserPhoto.IsPopulated()) ? member1.UserPhoto.ToString() : "none"); Debug.WriteLine((member2.UserPhoto.IsPopulated()) ? member2.UserPhoto.ToString() : "none"); Is it possible?

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  • Create sqlite3 database at prompt

    - by user15432
    I tried using the following commands to create a database file at prompt, but none of them would work. $ sqlite3 test.db sqlite3 test.db test.db does it require a semi-colon at the end or is it that hard to create a database file using sqlite3 prompt?

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  • PDFBox Pagebreak strange Nullpointer exception

    - by schneiti
    I currently try printing out text on multiple pages. For this, I count the number of rows and when they reach a fixed amount a method called pagebreakis executed. After the first pagebreak, when I try setting a font using contentstream.setFont(PDType1Font.HELVETICA, 12); it yields the following errormessage occuring at the described setFont-row. java.lang.NullPointerException at org.apache.pdfbox.pdmodel.edit.PDPageContentStream.setFont(PDPageContentStream.java:321) at com.xy.deu.xy.abc.db.schemavergleich.PDFDocumenter.drawBGCS(PDFDocumenter.java:781) at com.xy.deu.xy.abc.db.schemavergleich.PDFDocumenter.createPDFDocumentation(PDFDocumenter.java:205) at com.xy.deu.xy.abc.db.schemavergleich.MainClass.createPDFandOutput(MainClass.java:361) at com.xy.deu.xy.abc.db.schemavergleich.MainClass.start(MainClass.java:231) at com.xy.deu.xy.abc.db.schemavergleich.MainClass.main(MainClass.java:180) Below is the code that gets executed as the error occurs. ... // If Table gets to long for a page -> pagebreak: if(currentLines > 37) { pageBreak(currentLinePos); // TODO Currently causing app to crash } ... private void pageBreak(int currentLine) throws Exception { contentStream.endText(); contentStream.close(); // Create new page page = new PDPage(PDPage.PAGE_SIZE_A4); doc.addPage( page ); // Create a new font object selecting one of the PDF base fonts font = PDType1Font.HELVETICA; // Start a new content stream which will "hold" the to be created content contentStream = new PDPageContentStream(doc, page); currentLines = 0; mediabox = page.findMediaBox(); contentStream.beginText(); contentStream.moveTextPositionByAmount(startX, startY); contentStream.setFont(PDType1Font.HELVETICA, 12); } Now comes the strange thing: Debugging yields into nothing that is not set. I'll attach a screenshot for you right at the position where the error occurs:

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  • Drupal 6: Creating "ON/OFF News Links" functionality for a block created with View Module.

    - by artmania
    Hi friends, I'm a drupal newbie who needs some advice... I have a news list block at homepage, created with View Module. It is listing all added news' title and link. Everything is cool so far. Now I need to add an ON/OFF option at admin side for homepage news block. When the setting is ON, it will work as it is. When it is OFF, only the titles will be listed with no linking to news detail page. So, now where should I add this ON/OFF option? I have only add/edit/delete pages for each news, there is no common news page to add such option. Should I create an admin page with such ON/OFF option in? Also I think I need to create a db table to keep this ON/OFF status. and controlling this value at homepage block, if it is 1 or 0, and displaying links according to db value :/ it looks too long way Create db table Create an page with ON/OFF option in add php codes to update db for admin's choice get the db value in homepage block to display links, etc. is there any shorter, better way to do what I need? Appreciate helps so much!!! Thanks a lot!!

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  • What data actually gets cached in InnoDB/MySQL?

    - by ming yeow
    Hi folks, i am trying to optimize performance for my database. My question is - what get cached in the db memory? For example: (table with 2 columns: key (indexed), data (not indexed) updated (not indexed) Select * where updated=20100202 (the db will do a scan - will the scanned rows be kept in memory?) Select * where key = 20 (the db will refer to the index - will the identified rows be kept in memory?)

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