Search Results

Search found 31693 results on 1268 pages for 'ssi php'.

Page 82/1268 | < Previous Page | 78 79 80 81 82 83 84 85 86 87 88 89  | Next Page >

• please suggest good variable names that represent theirself ( php)

  - by I Like PHP

  Hi all, it may be wrong place to ask this question, but i hope u all programmer must have the interesting naming convention of variables. i have seen many places that some variable names are very good n effective like common variable names $link $db $connect $query $stmt $sql $qry $output $result $list so please suggest me some good names for variable , bcoz all time i have to write $x, $y etc.. if i want to save something instantly on page...that are even not relevant, so please suggest me good variable names

  Read the article

• (php) regexto remove comments but ignore occurances within strings

  - by David

  Hi there, I am writing a comment-stripper and trying to accommodate for all needs here. I have the below stack of code which removes pretty much all comments, but it actually goes too far. A lot of time was spent trying and testing and researching the regex patterns to match, but I don't claim that they are the best at each. My problem is that I also have situation where I have 'PHP comments' (that aren't really comments' in standard code, or even in PHP strings, that I don't actually want to have removed. Example: <?php $Var = "Blah blah //this must not comment"; // this must comment. ?> What ends up happening is that it strips out religiously, which is fine, but it leaves certain problems: <?php $Var = "Blah blah ?> Also: will also cause problems, as the comment removes the rest of the line, including the ending ? See the problem? So this is what I need... Comment characters within '' or "" need to be ignored PHP Comments on the same line, that use double-slashes, should remove perhaps only the comment itself, or should remove the entire php codeblock. Here's the patterns I use at the moment, feel free to tell me if there's improvement I can make in my existing patterns? :) $CompressedData = $OriginalData; $CompressedData = preg_replace('!/\*.*?\*/!s', '', $CompressedData); // removes /* comments */ $CompressedData = preg_replace('!//.*?\n!', '', $CompressedData); // removes //comments $CompressedData = preg_replace('!#.*?\n!', '', $CompressedData); // removes # comments $CompressedData = preg_replace('/<!--(.*?)-->/', '', $CompressedData); // removes HTML comments Any help that you can give me would be greatly appreciated! :)

  Read the article

• How can I secure my $_GETs in PHP?

  - by ggfan

  My profile.php displays all the user's postings,comments,pictures. If the user wants to delete, it sends the posting's id to the remove.php so it's like remove.php?action=removeposting&posting_id=2. If they want to remove a picture, it's remove.php?action=removepicture&picture_id=1. Using the get data, I do a query to the database to display the info they want to delete and if they want to delete it, they click "yes". So the data is deleted via $POST NOT $GET to prevent cross-site request forgery. My question is how do I make sure the GETs are not some javascript code, sql injection that will mess me up. here is my remove.php //how do I make $action safe? //should I use mysqli_real_escape_string? //use strip_tags()? $action=trim($_GET['action']); if (($action != 'removeposting') && ($action != 'removefriend') && ($action != 'removecomment')) { echo "please don't change the action. go back and refresh"; header("Location: index.php"); exit(); } if ($action == 'removeposting') { //get the info and display it in a form. if user clicks "yes", deletes } if ($action =='removepicture') { //remove pic } I know I can't be 100% safe, but what are some common defenses I can use. EDIT Do this to prevent xss $action=trim($_GET['action']); htmlspecialchars(strip_tags($action)); Then when I am 'recalling' the data back via POST, I would use $posting_id = mysqli_real_escape_string($dbc, trim($_POST['posting_id']));

  Read the article

• JavaScript two-dimensional Array to PHP

  - by vi

  Hi I have to send a two-dimensional JavaScript Array to a PHP page. Indeed, I'm working on a form-builder, in which the user can add or remove fields. These fields are added (or removed) using JavaScript (jQuery). When the user is done and hit a 'publish' button, I have to get all the fields concerned and send them to a PHP page which would build a real form with it. I found a way to do it but I'm pretty sure it's not very clean : addedFields = new Array(); $("#add-info .field").each(function() { addedFields.push(new Array($(this).find('.name').val(), $(this).find('.type').val(), $(this).find('.size').val())); }); Basically, the ".field" class objects are <tr> and the ".name", ".type" and ".size" objects are inputs. So I get an array of [name, type, size], then I convert it into a string using addedFields = addedFields.join(";"); Finally, I go to the PHP form that way ; document.location.href = "create.php?addedfields=" + addedFields; Concerning the PHP code, I create a PHP array using the explode() function: $addedFields = explode(";", $_GET['addedfields']); and then I use it again for each element in the array: foreach ($addedFields as $field) { $field = explode(",", $field); echo "<li>Field with name : '$field[0]', of '$field[1]' type and with a size of $field[2]"; }

  Read the article

• passing a variable by value using php

  - by PHP-Prabhu

  can any one please tell me how to pass a variable as/by value? what i did a mistake on the below code, its shows an parse error $a = &$$b

  Read the article

• Show image on hover with PHP

  - by Sorosh

  I have a small problem with my PHP code and It would be very nice if someone could help me. I want to display an image when hovering over a link. This is the link with the PHP code that I have now: <a href="<?php the_permalink(); ?>"><?php if ( has_post_thumbnail() ) {the_post_thumbnail();} else if ( has_post_video() ) {the_post_video_image();}?></a> This code shows a image, but I want to execute this code when hovering over the link with the image: <?php echo print_image_function(); ?> The code also shows a image that belongs to a category. I don't want the initial image to disappear I simply want to show the second image on top off the first image when hovering over the first image. I don't know if it is helpful but I use Wordpress and I am not a PHP expert. I even don't know if this is going to work. Thats why I am asking if somebody can help me with this. Thanks in advance

  Read the article

• Textbox auto generate by php and html

  - by user2892997

  i have few field of data such as product , amount and barcode.The system just show 1 row of data insert form that contain the 3 field.when i completed insert the first row, then second row of textbox will auto generate, i can do it by microsoft access, can i do so for php ? <?php $i=0; ?> <form method="post" action=""> <input type="text" name="<?php echo $i; ?>" /> </form> <?php if(isset($_POST[$i])){ $i++; ?> <form method="post" action=""> <input type="text" name="<?php echo $i; ?>" /> </form> <?php }?> it work for the first and second textbox, but how can i continue to create more textbox accordingly?

  Read the article

• php mysql_fetch_array() error

  - by user1877823

  I am getting this error while i am trying to delete a record the query is working but this line remains on the page. i want to echo "Deleted" written in the while should show up but the while loop is not working, i have tried and searched alot nothing helps! mysql_fetch_array() expects parameter 1 to be resource, boolean given in delete.php on line 27 delete.php <html> <body> <form method="post"> Id : <input type="text" name="id"> Name : <input type="text" name="name"> Description : <input type="text" name="des"> <input type="submit" value="delete" name="delete"> </form> <?php include("connect.php"); $id = $_POST['id']; $name = $_POST['name']; $des = $_POST['des']; $result = mysql_query("DELETE FROM fact WHERE id='$id'") or die(mysql_error()); while($row = mysql_fetch_array($result)) { echo "Deleted"; } mysql_close($con); ?> </body> </html> connect.php <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Dataentry", $con); ?> How should i make the while loop work..

  Read the article

• PHP, Apache and curl: Differences between Windows and Linux?

  - by beginner_

  I'm trying to run my php App on Ubuntu Server 11.10. This App works fine under Apache + PHP in windows. I have other applications that I can simply copy&paste between the 2 OS and they work on both. (These don't use cURL). However this one uses the php library tonic (RESTful webservices) and makes us of php cURL module. The issue is I'm not getting an error message which makes it impossible to find the issue. I (must) use NTLM authentication and this is done with AuthenNTLM Apache Module: Order allow,deny Allow from all PerlAuthenHandler Apache2::AuthenNTLM AuthType ntlm AuthName "Protected Access" require valid-user PerlAddVar ntdomain "domainName server" PerlSetVar defaultdomain domainName PerlSetVar ntlmsemtimeout 2 PerlSetVar ntlmdebug 1 PerlSetVar splitdomainprefix 0 All files that cURL needs to fetch override AuthenNTLM authentication: order deny,allow deny from all allow from 127.0.0.1 Satisfy any Since these files are only fectehd by cURL from same server, access can be limited to localhost. Possible issues are: NTLM auth isn't overridden for files requested through cURL (even though AllowOverride All is set) curl works differently on linux $ch = curl_init(); curl_setopt($ch, CURLOPT_COOKIE, $strCookie); curl_setopt($ch, CURLOPT_URL, $baseUrl . $queryString); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $html = curl_exec($ch); curl_close($ch); other? Apache log says: [error] Bad/Missing NTLM/Basic Authorization Header for /myApp/webservice/local/viewList.php But this directory should override NTLM authentication using curl command line from windows to access same resource i get: <!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN"> <html> <head> <title>406 Not Acceptable</title> </head> <body> <h1>Not Acceptable</h1> <p>An appropriate representation of the requested resource /myApp/webservice/myResource could not be found on this server.</p> Available variants: <ul> <li><a href="myResource.php">myResource.php</a> , type application/x-httpd-php</li> </ul> <hr> <address>Apache/2.2.20 (Ubuntu) Server at localhost Port 80</address> </body> </html> Note: This is duplicate from http://stackoverflow.com/questions/9821979/php-curl-on-linux-what-is-the-difference-to-curl-on-windows Is it was suggested I post it here. EDIT: Please see Ubuntu Server: Apache2 seems to attach .php to URI as I discovered why it does not work but need help so the issue does not occur anymore. ANSWER: The issue is the default Apache configuration on Ubuntu: Options Indexes FollowSymLinks MultiViews MultiViews is changing request_uri from myResource to myResource.php. Solutions: disable MultiViews in .htaccess: Options -MultiViews remove MultiViews from default config rename the file as example to myResourceClass I chose last option because that should work regardless of configuration and I only have 3 such files so the change took about 30 secs...

  Read the article

• I am getting a 400 Bad Request error when using Nginx and PHP-FPM, why?

  - by Bob

  I am trying to run a website (that requires PHP - it technically doesn't require MySQL at this time, but it may sometime in the near future as I continue developing it, so I went ahead and installed that as well) using nginx 1.2.4 and PHP-FPM 5.3.3 on Ubuntu 12.04.1 LTS. As far as I know, I haven't done anything wrong, but clearly something is not quite right - I seem to be getting a 400 Bad Request error whenever I try to browse to my website. I've been mostly following one guide, and I've done more or less everything it recommends, except for not setting up PHP-FPM to use a Unix Socket and I used service as opposed to /etc/init.d/ when starting/stopping nginx, PHP, and MySQL. Anyways, here are my relevant configuration files (I have only censored personal/sensitive details, like my domain name - which contains my real name): /etc/nginx/nginx.conf user www-data; worker_processes 4; pid /var/run/nginx.pid; events { worker_connections 768; # multi_accept on; } http { ## # Basic Settings ## sendfile on; tcp_nopush on; tcp_nodelay on; keepalive_timeout 15; types_hash_max_size 2048; # server_tokens off; # server_names_hash_bucket_size 64; # server_name_in_redirect off; include /etc/nginx/mime.types; default_type application/octet-stream; ## # Logging Settings ## access_log /var/log/nginx/access.log; error_log /var/log/nginx/error.log; ## # Gzip Settings ## gzip on; gzip_disable "msie6"; # gzip_vary on; # gzip_proxied any; # gzip_comp_level 6; # gzip_buffers 16 8k; # gzip_http_version 1.1; # gzip_types text/plain text/css application/json application/x-javascript text/xml application/xml application/xml+rss text/javascript; ## # nginx-naxsi config ## # Uncomment it if you installed nginx-naxsi ## #include /etc/nginx/naxsi_core.rules; ## # nginx-passenger config ## # Uncomment it if you installed nginx-passenger ## #passenger_root /usr; #passenger_ruby /usr/bin/ruby; ## # Virtual Host Configs ## include /etc/nginx/conf.d/*.conf; include /etc/nginx/sites-enabled/*; } /etc/nginx/sites-enabled/subdomain.mydomain.net server { listen 80; # listen for IPv4 listen [::]:80; # listen for IPv6 server_name www.subdomain.mydomain.net subdomain.mydomain.net; access_log /srv/www/subdomain.mydomain.net/logs/access.log; error_log /srv/www/subdomain.mydomain.net/logs/error.log; location / { root /srv/www/subdomain.mydomain.net/public; index index.php; } location ~ \.php$ { try_files $uri =400; include fastcgi_params; fastcgi_split_path_info ^(.+\.php)(/.+)$; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME /srv/www/subdomain.mydomain.net/public$fastcgi_script_name; } } All the directories listed in the configuration files above are correct on my server (to the extent of my knowledge). I have not included /etc/php5/fpm/pool.d/www.conf or /etc/php5/fpm/php.ini in this post as they're rather long, but I have posted them on Pastebin: http://pastebin.com/ensErJD8 and http://pastebin.com/T23dt7vM, respectively. Although, the only thing I've changed in either of the two files was in php.ini, where I set expose_php to off so as to hide the .php file extension from users. What can I do to resolve my issue? Please let me know if I need to supply any additional details.

  Read the article

• Am I correctly handling duplicate URLs for my homepage?

  - by Rob Goldstein

  I own a Job Search site named www.conservationjobboard.com and have a concern about how the domain is viewed by search engines. The issue is that when the site was first designed, the default page was left as default.php, but the homepage was actually JobBoard.php. To handle this, the default.php page performed a redirect to the JobBoard.php file when www.conservationjobboard.com/ was requested. The main problem resulted because the redirect was a temporary redirect causing search engines to index conservationjobboard.com/ and conservationjobboard.com/JobBoard.php as 2 separate pages. This has since been corrected to use the .htaccess file so that JobBoard.php is now the default file for the root directory eliminating the need for the redirect. Problem is that search engines still show both URL's in search results (one including JobBoard.php and one that ends with /). Another potential problem is that some of my early backlinks are to conservationjobboard.com/JobBoard.php while the rest are to conservationjobboard.com The 2 outstanding questions are as follows: 1. Is my domain still being penalized by search engines like Google for having duplicate homepage URL's? 2. Are all of the back links to my homepage being considered as the same now or is the total number of back links being split between the 2 different URL's? If you think there are still issues with how we have this set-up, I was wondering if you could give me advice on what we should do differently. Thanks.

  Read the article

• OpenJs mysql not reading database [migrated]

  - by Benedikt Wutzi

  I try to access a mysql table using OpenJs Grid. I already doublechecked if the database "partsdb" and the table "parts" exists and it can be accessed from the commandline. Currently I'm using the must basic example: members.php: <!DOCTYPE html> <html lang="en"> <head> <meta charset="utf-8"> <title>Members Page</title> <script> $(function() { $(".parts").grid(); }); </script> </head> <body> <div id="container"> <h1>Members Page</h1> <table action="ajax.php"> <tr> <th col="id">Id</th> <th col="name">Name</th> </tr> </table> <a href='<?php echo base_url()."main/logout" ?>'>Logout</a> </div> and ajax.php <?php mysql_connect("localhost","****","*****"); mysql_select_db("partsdb"); require_once("grid.php"); $grid = new Grid("parts"); ?> When I run php directly on ajax.php I get an error telling me: " Unknown column 'parts.' in 'field list' " and the table shows only the headers. What am I doing wrong?

  Read the article

• How to enabled pdo mysql in Centos 5.8

  - by nacho3d

  I have a VPS with Centos 5.8 In phpinfo displays: './configure' '--disable-fileinfo' '--disable-pdo' '--enable-bcmath' '--enable-calendar' '--enable-ftp' '--enable-libxml' '--enable-magic-quotes' '--enable-sockets' '--prefix=/usr/local' '--with-apxs2=/usr/local/apache/bin/apxs' '--with-curl=/opt/curlssl/' '--with-imap=/opt/php_with_imap_client/' '--with-imap-ssl=/usr' '--with-kerberos' '--with-libdir=lib64' '--with-libxml-dir=/opt/xml2/' '--with-mysql=/usr' '--with-mysql-sock=/var/lib/mysql/mysql.sock' '--with-openssl=/usr' '--with-openssl-dir=/usr' '--with-pcre-regex=/opt/pcre' '--with-pic' '--with-zlib' '--with-zlib-dir=/usr' I've tried this: http://www.host1free.com/forum/vps-technical-support/7248-tutoria-centos-apache-webserver-mysql-php-eaccelerator-apc.html And aparently it installed php-pdo # rpm -qa |grep php php-5.3.13-1.el5.remi php-xml-5.3.13-1.el5.remi php-common-5.3.13-1.el5.remi php-cli-5.3.13-1.el5.remi php-pdo-5.3.13-1.el5.remi php-xmlrpc-5.3.13-1.el5.remi php-mcrypt-5.3.13-1.el5.remi But I've restarted apache and it still says in my phpinfo: '--disable-pdo' Should I rebuild php? Do I need to do some other step?

  Read the article

• Entry / JR Php Programmer - What do I learn next?

  - by dtj

  I got very interested in programming toward the end of college. Took a few classes, but learned most everything on my own via books and such. Its mostly been Php and MySQL. Right out of school, I got a job working at a company for 2 years (web media) and ended up learning a lot of stuff and programming some things for them. I am no longer at that company but I am looking for my next steps as a programmer. I really enjoy Web Development and Php and MySQL seems to be my thing. Basically, I know how to do CRUD operations, i am mediocre at OOP and still have more to learn, I know HTML and CSS quite well, I know my way around a Unix terminal and can access MySQL through it and set up cron jobs and such. I know some basic Javascript. Whats a good next step? I don't anything about 3rd party services, PDO, APIs (twitter, facebook, etc), Drupal / Joomla, Unit Testing, E-Commerce, PECL, PEAR ....in other words A LOT I get easily overwhelmed by the amount of stuff there is to learn, so I'm sort of trying to find a path. Right now, I'm digging into OOP more, as that seems like a good conceptual first-step. Any suggestions?

  Read the article

• Is Movable Type among the most secure PHP blogs? How secure are the various PHP blog applications?

  - by user6025

  Basically I'm trying to find a blog for a website, and security is the highest priority in our case. We don't need any features that I would imagine are special. Wordpress was our first idea, but its reputation precedes it, and though it may have cleaned up its act lately, I'm not seeing much solid evidence. I get the impression that Movable Type (at least the Perl version) has a much better reputation for security than Wordpress (historically at least). I'm not sure I want to take a chance with Wordpress at this point, but is there some objective source I can got to to back up (or counter) the notion that MT is at least among the best? Secunia doesn't recommend using their stats for comparisons, and securityfocus.com doesn't have stats at all that I can see. Searching here http://web.nvd.nist.gov makes MT look way better than WP (at least in 2007), but this site was referenced by MT's own page boasting about their security, so I don't know how relevant it is or how seriously people take it. Any suggestions on sites where I could/should make a somewhat objective comparison?

  Read the article

• How to develop Online Shopping Portal Application using PHP ?

  - by Sarang

  I do not know PHP & I have to develop a Shopping Portal with following Definition : Scenario: Online Shopping Portal XYZ.com wants to create an online shopping portal for managing its registered customers and their shopping. The customers need to register themselves first before they do shopping using the shopping portal. However, everyone, whether registered or not, can view the various products along with the prices listed in the portal. The registered customers, after logging in, are allowed to place order for one or more products from the products listed in the portal. Once the order is placed, the customer gets a reference order number and the order status should be “order in process”. The customers can track their order using the given reference number. The management of XYZ.com should be able to modify the order status of a particular reference order number to “shipped” once the products are shipped to the shipping address entered by the customer at the time of placing the order. The Functionalities required are : Create the interface for the XYZ.com shopping portal using HTML/XHTML and CSS. Implement the client side validations using JavaScript. Create the tables using MySQL. Implement the functionality using the server side scripting language, PHP. Integrate all the above tasks and make the XYZ.com shopping portal functional. How do I develop this application with following proper steps of development ?

  Read the article

• I'm confused about encryption and SSL

  - by ChowKiko

  while my friends and I planning to run our own website, we're confused about the encryption where hackers can TAPPING or in social engineering it's WIRE TAPPING, but I don't know how do they call it in Computers today... Well guys, I just want to know how encryption works with websites if we are using PHP+MYSQL? Is it ok to use user login ---- (PHP) encrypt inputted value then (PHP) will decrypt and validate it going to (MySQL) user login ---- (PHP) encrypt inputted value and decrypt the (MySQL) data if they are similar... Is it similar if we use $_SESSION without encryption inside PHP going to MySQL?or PHP encryption also helps the manipulation of binaries?..I'm so confused T_T... In regards to what I stated above, can a hacker hook the data if the server uses $_SESSION? Is $_SESSION safe?... IF THE HACKER CAN HOOK it? is it necessary to use SSL on our website? and why do some Merchandise websites use SSL and likewise facebook also uses SSL? what is the best suit for you if there is no SSL? encrypting the DATA using PHP going to MySQL or even without encryption while the PHP server uses $_SESSION?...

  Read the article

• How do I get away from PHP in the web industry?

  - by Kurtis

  I'm just looking for some tips on getting away from using PHP for web development. I'm self-employed but it seems like all of the work I find deals with PHP. I'm not complaining about the work -- just the poor choice of a language that is incredibly popular. I'd love to do my web development in Python, Perl, C#, or even a fun and fancy functional language. There's the old saying that you don't tell a carpenter what kind of a hammer to use. At the same time, you do tell them what kind of material to build your house out of and how much you're willing to spend. The problem I am running in to is that I don't know how to get out of this spiral. I can't just turn down work because then I wouldn't have any. I really don't want to go work for another company -- and even if I did, I'd probably still be stuck using something I don't enjoy. I'm hoping someone has "been there" before and might have some good ideas on how to get out of this situation. Thanks!

  Read the article

• PHP FPDF PDF Page Break Question

  - by Michael

  I am using PHP and FPDF to generate a PDF with a list of items. My problem is if the item list goes on to a second or third page, I want to keep the Item Name, Quantity and Description together. Right now, it will go to a second page, but it may split up all of the details for a particular item. PLEASE HELP! <?php require_once('auth.php'); require_once('config.php'); require_once('connect.php'); $sqlitems="SELECT * FROM $tbl_items WHERE username = '" . $_SESSION['SESS_LOGIN'] . "'"; $resultitems=mysql_query($sqlitems); require_once('pdf/fpdf.php'); require_once('pdf/fpdi.php'); $pdf =& new FPDI(); $pdf->AddPage('P', 'Letter'); $pdf->setSourceFile('pdf/files/healthform/meds.pdf'); $tplIdx = $pdf->importPage(1); $pdf->useTemplate($tplIdx); $pdf->SetAutoPageBreak(on, 30); $pdf->SetTextColor(0,0,0); $pdf->Ln(10); while($rowsitems=mysql_fetch_array($resultitems)){ $pdf->SetFont('Arial','B',10); $pdf->Cell(50,4,'Item Name:',0,0,'L'); $pdf->SetFont(''); $pdf->Cell(100,4,$rowsitems['itemname'],0,0,'L'); $pdf->SetFont('Arial','B',10); $pdf->Cell(50,4,'Quantity:',0,0,'L'); $pdf->SetFont(''); $pdf->Cell(140,4,$rowsitems['itemqty'],0,1,'L'); $pdf->SetFont('Arial','B'); $pdf->Cell(50,4,'Description:',0,0,'L'); $pdf->SetFont(''); $pdf->Cell(140,4,$rowsitems['itemdesc'],0,1,'L'); } $pdf->Output('Items.pdf', 'I'); ?>

  Read the article

• [solved] PHP-called hyperlink stopped showing when CSS table implemented

  - by Luke

  EDIT: Solved - was not flutter's tag stripping, should work as advertised. I'm using Flutter (which creates custom fields) in Wordpress to display profile information entered as a Post. Before I implemented the CSS tables the link showed up and was clickable. Now I get nothing returned, even when I try to call the link outside the table. If you know anything about this, here's my code in the index.php file and I remain available for any questions. <?php if (in_category('Profile')) { ?> <table id="mytable" cellspacing="0"> -snip- <tr> <th class="row1" valign="top">Website </td> <td>Link: <a href="<?php echo get_post_meta($post->ID, 'FrWebsite', $single=true) ?>"> <?php echo get_post_meta($post->ID, 'FrWebsite', $single=true) ?></a></td> </tr> -snip- </table> Thanks, L Edit: @Josh - there is a foreach looping construct in the table and it is reading and displaying the code correctly, I see what you're getting at now: <tr> <th class="row2" valign="top">Specialities </td> <td class="alt" valign="top"><?php $my_array = get('Expertise'); $output = ""; foreach($my_array as $check) { $output .= "<span>$check</span><br/> "; } echo $output; ?></td> </tr> Edit - @Josh - here's the old code as far as I can remember it, there was no major difference just a <td> tag where there now stands a <th>, there wasn't the class="" and there was no "Link:" and FrWebsite was called Website, but it still didn't work when called Website so I changed to see if that was the error. <tr> <td width="200" valign="top">Website </td> <td><a href="<?php echo get_post_meta($post->ID, 'Website', $single=true) ?>"><?php echo get_post_meta($post->ID, 'Website', $single=true) ?></a></td> </tr>

  Read the article

• I have a php form dropdown menu that needs to send information

  - by shinjuo

  I have a dropdown menu that is filled by a mysql database. I need to select one and have it send the information for use on the next page after clicking submit. It does populate the drop down menu like it is supposed to it just does not seem to catch the data on the next page. Here is what I have: removeMain.php <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <form action="remove.php" method="post"> <?php $link = mysql_connect('********', '********', '*********'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("********", $link); $res = mysql_query("SELECT * FROM cardLists order by cardID") or die(mysql_error()); echo "<select name = CardID>"; while($row=mysql_fetch_assoc($res)) { echo "<option value=$row[ID]>$row[cardID]</a></option>"; } echo "</select>"; ?> Amount to Remove: <input type="text" name="Remove" /> <input type="submit" /> </form> <body> </body> </html> remove.php <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <body> <?php $link = mysql_connect('*********', '*********', '*********'); if (!$link){ die('Could not connect: ' . mysql_error()); } mysql_select_db("***********y", $link); $query = sprintf("UPDATE cardLists SET AmountLeft = AmountLeft - %s WHERE cardID = '%s'", mysql_real_escape_string($_POST["Remove"]), mysql_real_escape_string($_POST["CardID"])); mysql_query($query); mysql_close($link); ?> <br /> <a href="removeMain.php"> <input type="submit" name="return" id="return" value="Update More" /></a> <a href="index.php"> <input type="submit" name="main" id="main" value="Return To Main" /></a> </body> </html>

  Read the article

• Newbie's problems with MySQL and php

  - by Mirage81

  I'm a real newbie with php and MySQL. Now I'm working on the following code which should search the database for eg. all the Lennons living in Liverpool. 1) How should I modify "get.php" to get the text "no results" to appear if there are no search results. 2) How should I modify "index.php" to get the option values (city and lastname) straight from the database instead of having to type them one by one? 3) Am I using mysql_real_escape_string the right way? 4) Any other mistakes in the code? index.php: <form action="get.php" method="post"> <p> <select name="city"> <option value="Birmingham">Birmingham</option> <option value="Liverpool">Liverpool</option> <option value="London">London</option> </select> </p> <p> <select name="lastname"> <option value="Lennon">Lennon</option> <option value="McCartney">McCartney</option> <option value="Osbourne">Osbourne</option> </select> </p> <p> <input value="Search" type="submit"> </p> </form> get.php: <?php $city = $_POST['city']; $lastname = $_POST['lastname']; $conn = mysql_connect('localhost', 'user', 'password'); mysql_select_db("database", $conn) or die("connection failed"); $query = "SELECT * FROM users WHERE city = '$city' AND lastname = '$lastname'"; $result = mysql_query($query, $conn); $city = mysql_real_escape_string($_POST['city']); $lastname = mysql_real_escape_string($_POST['lastname']); echo $rowcount; while ($row = mysql_fetch_row($result)) { if ($rowcount == '0') echo 'no results'; else { echo '<b>City: </b>'.htmlspecialchars($row[0]).'<br />'; echo '<b>Last name: </b>'.htmlspecialchars($row[1]).'<br />'; echo '<b>Information: </b>'.htmlspecialchars($row[2]); } } mysql_close($conn);

  Read the article

• php array code with regular expressions

  - by user551068

  there are few mistakes which it is showing as Warning: preg_match() [function.preg-match]: Delimiter must not be alphanumeric or backslash in array 4,9,10,11,12... can anyone resolve them <?PHP $hosts = array( array("ronmexico.kainalopallo.com/","beforename=$F_firstname%20$F_lastname&gender=$F_gender","Your Ron Mexico Name is ","/the ultimate disguise, is <u><b>([^<]+)<\/b><\/u>/s"), array("www.fjordstone.com/cgi-bin/png.pl","gender=$F_gender&submit=Name%20Me","Your Pagan name is ","/COLOR=#000000 SIZE=6> *([^<]*)<\/FONT>/"), array("rumandmonkey.com/widgets/toys/mormon/index.php","gender=$F_gender&firstname=$F_firstname&surname=$F_lastname","Your Mormon Name is ","/<p>My Mormon name is <b>([^<]+)<\/b>!<br \/>/s"), array("cyborg.namedecoder.com/index.php","acronym=$F_firstname&design=edox&design_click-edox.x=0&design_click-edox.y=0&design_click-edox=edo","","Your Cyborg Name is ","/<p>([^<]+)<\/p>/"), array("rumandmonkey.com/widgets/toys/namegen/10/","nametype=$brit&page=2&id=10&submit=God%20save%20the%20Queen!&name=$F_firstname%20$F_lastname","Your Very British Name is ","/My very British name is \&lt\;b\&gt;([^&]+)\&lt;\/b\&gt;\.\&lt;br/"), array("blazonry.com/name_generator/usname.php","realname=$F_firstname+$F_lastname&gender=$F_gender","Your U.S. Name is ","/also be known as <font size=\'\+1\'><b>([^<]+)<\/b>/s"), array("www.spacepirate.org/rogues.php","realname=$F_firstname%20$F_lastname&formentered=Yes&submit=Arrrgh","Your Space Pirate name is ","/Your pirate name is <font size=\'\+1\'><b>([^<]+)<\/b><\/font>/s"), array("rumandmonkey.com/widgets/toys/ghetto/","firstname=$F_firstname&lastname=$F_lastname","Your Ghetto Name is ","/<p align=\"center\" style=\"font-size: 36px\">\s*<br \/>\s*([^<]*)<br \/>/"), array("www.emmadavies.net/vampire/default.aspx","mf=$emgender&firstname=$F_firstname&lastname=$F_lastname&submit=Find+My+Vampire+Name","","Your Vampire Name is ","/<i class=\"vampirecontrol vampire name\">([^<]*)<\/i>/"), array("www.emmadavies.net/fairy/default.aspx","mf=$emgender&firstname=$F_firstname&lastname=$F_lastname&submit=Seek+Fairy","","Your Fairy Name is ","/<i class=\'ng fairy name\'>([^<]*)<\/i>/"), array("www.irielion.com/israel/reggaename.html","phase=3&oldname=$F_firstname%20$F_lastname&gndr=$reggender","","Your Rasta Name is ","/Yes I, your irie new name is ([^\n]*)\n/"), array("www.ninjaburger.com/fun/games/ninjaname/ninjaname.php","realname=$F_firstname+$F_lastname","Your Ninja Burger Name is ","/<BR>Ninja Burger ninja name will be<BR><BR><FONT SIZE=\'\+1\'>([^<]*)<\/FONT>/"), array("gangstaname.com/pirate_name.php","sex=$F_gender&name=$F_firstname+$F_lastname","Your Pirate Name is ","/<p><strong>We\'ll now call ye:<\/strong><\/p> *<h2 class=\"newName\">([^<]*)<\/h2>/"), array("www.xach.com/nerd-name/","name=$F_firstname+$F_lastname&gender=$F_gender","Your Nerd Name is ","/<p><div align=center class=\"nerdname\">([^<]*)<\/div>/"), array("rumandmonkey.com/widgets/toys/namegen/5941/","page=2&id=5941&nametype=$dj&name=$F_firstname+$F_lastname","Your DJ Name is ","/My disk spinnin nu name is &lt\;b&gt\;([^<]*)&lt\;\/b&gt\;\./"), array("pizza.sandwich.net/poke/pokecgi.cgi","name=$F_firstname%20$F_lastname&color=black&submit=%20send%20","Your Pokename is ","/Your Pok&eacute;name is: <h1>([^<]*)<\/h1>/") ); return $hosts; ?>

  Read the article

• Display all images from outside web root folder using PHP

  - by micmola

  Hello, I want to display all images that are stored outside my web root folder. Please help me. I am only able to display one image repeatedly. For example, if I have 5 images in my folder, only one image is displayed on my browser 5 times. Please help me on this. I've been working on this problem for over a month now. I'm a newbie. Help. Thank you. Here is the code I'm using. images.php <?php // Get our database connector require("includes/copta.php"); // Grab the data from our people table $sql = "select * from people"; $result = mysql_query($sql) or die ("Could not access DB: " . mysql_error()); $imgLocation = " /uploadfile/"; while ($row = mysql_fetch_array($result)) { $imgName = $row["filename"]; $imgPath = $imgLocation . $imgName; echo "<img src=\"call_images.php?imgPath=" . $imgName . "\" alt=\"\"><br/>"; echo $row['id'] . " " . $imgName. "<br />"; } ?> call_images.php <?php // Get our database connector require("includes/copta.php"); $imgLocation = '/ uploadz/'; $sql = "select * from people"; $result = mysql_query($sql) or die ("Could not access DB: " . mysql_error()); while ($row = mysql_fetch_array($result)) { $imgName = $row["filename"]; $imgPath = $imgLocation . $imgName; // Make sure the file exists if(!file_exists($imgPath) || !is_file($imgPath)) { header('HTTP/1.0 404 Not Found'); die('The file does not exist'); } // Make sure the file is an image $imgData = getimagesize($imgPath); if(!$imgData) { header('HTTP/1.0 403 Forbidden'); die('The file you requested is not an image.'); } // Set the appropriate content-type // and provide the content-length. header("Pragma: public"); header("Expires: 0"); header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Type: image/jpg"); header("Content-length: " . filesize($imgPath)); // Print the image data readfile($imgPath); exit(); } ?>

  Read the article

• Included php file calling Javascript function

  - by Illes Peter

  Hi there! Here's the deal. I've got index.php which links to an internal JS file in it's header. index.php then includes another .php file, which outputs this: + add file. addFile() is a Javascript function defined in the external JS file. By doing this nothing happens, the included php does not "see" the JS function. Encapsulating the JS in the included PHP makes it all work. But I don't want to do it that way. Any ideas? EDIT: here's the source <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Archie</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"/> <link rel="stylesheet" href="/screen.css" type="text/css" media="screen"/> <script src="/lib/js/archie.js" type="text/javascript"></script> </head> <body> ... ... //included php starts here <form action="/lib/course.php" method="post"> <fieldset> <div id="addFileLocation"></div> <a href="#" onClick="addFile()">+ add file</a> <input type="hidden" id="addFileCount" value="0"/> </fieldset> </form> //ends here ... ... </body> </html> and the js: <script type="text/javascript"> //Dynamically add form fields //add file browser function addFile() { var location = document.getElementById('addFileLocation'); var num = document.getElementById('addFileCount'); var newnum = (document.getElementById('addFileCount').value -1)+ 2; num.value = newnum; var newname = 'addFile_'+newnum; var newelement = document.createElement('input'); newelement.setAttribute('name',newname); newelement.setAttribute('type','file'); location.appendChild(newelement); } </script>

  Read the article

< Previous Page | 78 79 80 81 82 83 84 85 86 87 88 89  | Next Page >