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  • A System Monitoring Tool Primer

    <b>CertCities:</b> "Linux comes with a number of utilities that can be used to monitor one or more of these performance parameters. The following sections introduce a few of these utilities and show how to understand the information presented by them"

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  • Developing a php system that tracks other websites analytics

    - by CodeCrack
    I want to develop a PHP website feature where users sign up, get a javascript snippet code that display an image on their site, and let's me track the number of visitors, unique hits, clicks and average visitor duration on their page. Is that something that should be done with some open source analytic software such as http://piwik.org/ or it's pretty doable on your own? If I had to do it myself from scratch, I would use image/pixel as a way to track the visit, drop a cookie with javascript snippet to track uniques, track clicks based on image click and redirect, and not sure about the bounce rate. Any thoughts or opinions are welcome.

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  • Cannot boot into system after deleting partition

    - by Clayton
    Okay...so this was kind of a stupid thing for me to do now that I think back on it. I was experiencing a ton of lag and not as much memory that I could use after installing Ubuntu 12.04. So after remembering I had installed multiple server versions of Ubuntu 12.04 by mistake, I went into Disk Management and proceeded to delete each and every one. Everything went fine. Up until this week, I have not experienced any problems. But starting yesterday I began to get lag just as I had before, and nothing fixed the problem. I decided to remove the Ubuntu partition, since I was also experiencing a visual error when given the option to select one to boot(the screen doesn't come up at all, and I recieved a monitor resolution error instead, but could still access both Windows and Ubuntu via arrow keys). After deleting the Ubuntu partition, so that I could see if running just Windows would fix the problem, I proceeded with what I was doing, installing a few programs that were not tied to my prediciment in any way. Upon rebooting my desktop, however, I recieved the following error: error: unknown filesystem. grub rescue> Hoping I could boot into Ubuntu via a pendrive and possibly backup my important files and wipe the hard drive to start fresh, I installed Ubuntu 13.04, but even that does not boot. Instead, I get this message on a terminal screen: SYSLINUX 4.06. EDD 4.06-pre1 Copyright (C) 1994-2011 H. Peter Anvin et al ERROR: No configuration file found No DEFAULT or UI configuration directive found! boot: So more or less, my desktop is screwed. I need to be able to get to the files inside because of my job as an artist, as well as retrieve my documents for my stories stored on Windows. Once I can succeed in solving this once and for all, I know for a fact I will stick to Ubuntu only, and install what is required to be able to run any Windows applications I used to use or need to use. I would rather not reformat the hard drive, and if I need to, it is a last resort. And I doubt I can use a Windows Recovery Disk to get my files back, as my mom has thrown out a lot of the installation disks and paperwork I would need to even follow through with that. :\ Keep in mind that I am a novice/newbie when it comes to Linux, but am hoping ot become better at it as time goes by. I appreciate any help you guys can give me. This will probably be the last time I attempt to do anything that could risk the well-being of my PC. (I've also looked through various questions on the site and tested a lot of the solutions. None seem to have worked.)

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  • Roll Your Own Passive 3D Movie System with Dual Projectors

    - by Jason Fitzpatrick
    If you’d like to enjoy 3D movies with passive polarized glasses for less than $50,000 (the average price of a passive 3D projector), this DIY setup brings the price down to a more accessible level. Courtesy of 3D movie and theater enthusiast Jahun, this guide details how you can achieve passive 3D projection using two radically less expensive projectors, cheap polarized filters, and some software. The project won’t be free-as-in-beer but with some careful shopping the bill will ring up at the thousands instead of tens-of-thousands of dollars. Hit up the link below to see how he pulled off miming a $50,000 projector for less than a tenth the cost. Passive Projection [via Hack A Day] How to Get Pro Features in Windows Home Versions with Third Party Tools HTG Explains: Is ReadyBoost Worth Using? HTG Explains: What The Windows Event Viewer Is and How You Can Use It

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  • Printing out this week's dates in perl

    - by ABach
    Hi folks, I have the following loop to calculate the dates of the current week and print them out. It works, but I am swimming in the amount of date/time possibilities in perl and want to get your opinion on whether there is a better way. Here's the code I've written: #!/usr/bin/env perl use warnings; use strict; use DateTime; # Calculate numeric value of today and the # target day (Monday = 1, Sunday = 7); the # target, in this case, is Monday, since that's # when I want the week to start my $today_dt = DateTime->now; my $today = $today_dt->day_of_week; my $target = 1; # Create DateTime copies to act as the "bookends" # for the date range my ($start, $end) = ($today_dt->clone(), $today_dt->clone()); if ($today == $target) { # If today is the target, "start" is already set; # we simply need to set the end date $end->add( days => 6 ); } else { # Otherwise, we calculate the Monday preceeding today # and the Sunday following today my $delta = ($target - $today + 7) % 7; $start->add( days => $delta - 7 ); $end->add( days => $delta - 1 ); } # I clone the DateTime object again because, for some reason, # I'm wary of using $start directly... my $cur_date = $start->clone(); while ($cur_date <= $end) { my $date_ymd = $cur_date->ymd; print "$date_ymd\n"; $cur_date->add( days => 1 ); } As mentioned, this works - but is it the quickest/most efficient/etc.? I'm guessing that quickness and efficiency may not necessarily go together, but your feedback is very appreciated.

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  • System hang when using SSHFS

    - by Borivoje Petrovic
    This is just a quick note that I want to share with others. It is about the problem that I encountered with my office machine. It was hanging continuously when ssh mount was used. The main problem is, as I assumed, the termination of ssh session, which caused the sshfs not to respond. The solution for this issue is the ServerAliveInterval 60 directive in /etc/ssh/ssh_config file. Hope this someone help!

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  • Printing HTML blocks

    - by Lem0n
    I have a page with a few tables that I want to be printable. I want the following behaviour: 1) Add a page break if the next table fits in a single page, but won't fit in the current page (because of other stuff already printed on this page) 2) Print the "table header" again in case it's needed to break a table (I guess it's the default behaviour) Any ideas specially on the first issue? Maybe some CSS can help? I'll give on example. I have a page with 4 tables. All of them with 10 lines, except the third one, with 50 lines. The first and second goes on the first page. Since the third one won't fit in the same page, but will fit in a page alone, it's printed on a page alone... and then the forth table is printed on the third page (in case it doesn't fit together in the second page). But, if the third page had 300 lines and would be broke anyway, it could have started to be print in the first page.

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  • Programmatically printing git revision and checking for uncommitted changes

    - by Andrew Grimm
    To ensure that my scientific analysis is reproducible, I'd like to programmatically check if there are any modifications to the code base that aren't checked in, and if not, print out what commit is being used. For example, if there are uncommitted changes, it should output Warning: uncommitted changes made. This output may not be reproducible. Else, produce Current commit: d27ec73cf2f1df89cbccd41494f579e066bad6fe Ideally, it should use "plumbing", not "porcelain".

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  • What is the default file system of /var/run, /var/lock

    - by Casey
    Trying to figure out if my /var/run is using disk or not. See the command output: $ df -h Filesystem Size Used Avail Use% Mounted on /dev/mapper/vg0-root 40G 15G 26G 36% / none 3.9G 340K 3.9G 1% /dev none 3.9G 1.1M 3.9G 1% /dev/shm tmpfs 3.9G 600K 3.9G 1% /tmp none 3.9G 452K 3.9G 1% /var/run none 3.9G 0 3.9G 0% /var/lock none 3.9G 0 3.9G 0% /lib/init/rw /dev/md0 236M 59M 165M 27% /boot /dev/mapper/vg0-home 60G 58G 2.3G 97% /home

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  • Printing Instance ID to NSLog?

    - by fuzzygoat
    In the dealloc method for a class how would I print out the ID (or some other unique identifier) for the instance being deallocated? - (void)dealloc { NSLog(@"_deallocing: ??"); [super dealloc]; } Is this possible? I am just trying to get a little more feedback in the console as an aid to learning. many thanks -gary-

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  • HTG Explains: What AppArmor Is and How It Secures Your Ubuntu System

    - by Chris Hoffman
    AppArmor is an important security feature that’s been included by default with Ubuntu since Ubuntu 7.10. However, it runs silently in the background, so you may not be aware of what it is and what it’s doing. AppArmor locks down vulnerable processes, restricting the damage security vulnerabilities in these processes can cause. AppArmor can also be used to lock down Mozilla Firefox for increased security, but it doesn’t do this by default. How to Use an Xbox 360 Controller On Your Windows PC Download the Official How-To Geek Trivia App for Windows 8 How to Banish Duplicate Photos with VisiPic

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  • How to Back Up Your Linux System With Back In Time

    - by Chris Hoffman
    Ubuntu includes Déjà Dup, an integrated backup tool, but some people prefer Back In Time instead. Back In Time has several advantages over Déjà Dup, including a less-opaque backup format, integrated backup file browser, and more configurability. Déjà Dup still has a few advantages, notably its optional encryption and simpler interface, but Back In Time gives Déjà Dup a run for its money. How to Sync Your Media Across Your Entire House with XBMC How to Own Your Own Website (Even If You Can’t Build One) Pt 2 How to Own Your Own Website (Even If You Can’t Build One) Pt 1

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  • How to enable ajax when deriving from System.Web.UI.WebControls.WebControl on controls that are crea

    - by Dave
    I've built a class that derives from System.Web.UI.WebControl. It basically renders pagination links (same as what you see on top of GridView when enabled) for use above a repeater. I'm creating some anchor tags explicitly inside my nav control obviously, but they don't perform ajax postbacks. My understanding is that ajax requires POSTS to work right? Well, these would be GETs which I think is the problem. Is there a way to achieve what I'm trying to do? Thanks!

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  • c printing string syntax

    - by user535256
    Hello guys, Just stuck on c syntax regarding strings. Say I have a string like (name[5]="peter";) in c say if I just wanted to print the last character of string or check the last character of the string, which in this case would be 'r' how can I do this? The way I was thinking does not seem to work name[5]="peter"; if(name[5]=="r") printf("last character of name is r"); Question: is there some sort of function to do this that can check one character of array, is a certain value, like name[5] is 'r' in string peter or likewise name[1] is 'n' Also how do I use printf to print that certain char, having problems using printf("last character of name is %s",name[5]) ??? Thanks

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  • printing reverse in singly link list using pointers

    - by theoneabhinav
    i have been trying this code. i think the logic is ok but the program terminates abruptly when the display_rev function is called here is code of display_rev void display_rev(emp_node *head) { emp_node *p=head, *q; while(p->next != NULL) p=p->next; while(p!=head || p==head){ q=head; display_rec(p); while(q->next != p) q=q->next; p=q; } } here is my whole code #include<stdio.h> #include<stdlib.h> #include<ctype.h> #include<string.h> //Declarations=============================================================== typedef struct //employee record { int emp_id; char name[150]; char mob_no[11]; float salary; int proj[5]; struct emp_node *next; } emp_node; emp_node* add_rec(emp_node*); emp_node* create_db(emp_node*); emp_node* search_db(emp_node*, int); emp_node* delete_rec(emp_node*, int); void read_name(emp_node*); void read_mob(emp_node*); void display_db(emp_node*); void display_rec(emp_node*); void display_rev(emp_node*); void modify_rec(emp_node*); void swtch(emp_node*); //=========================================================================== int main() { char ans; emp_node *head = NULL; head = create_db(head); display_db(head); do { swtch(head); printf("\n\n\tDo you want to continue (y/n) : "); getchar(); scanf("%c", &ans); } while (ans == 'y' || ans == 'Y'); return 0; } //Definitions================================================================ emp_node* create_db(emp_node *head) //database creation { int i = 1, no; emp_node *p; printf("Enter number of employees:"); scanf("%d", &no); printf("\n\n"); head = (emp_node *) malloc(sizeof(emp_node)); head = add_rec(head); head->next = NULL; p = head; while (i < no) { p->next = (emp_node *) malloc(sizeof(emp_node)); p = p->next; p = add_rec(p); p->next = NULL; i++; } return head; } emp_node* add_rec(emp_node *p) //new record { int j; printf("\n\tEmployee ID : "); scanf("%d", &(p->emp_id)); printf("\n\tFirst Name:"); read_name(p); printf("\n\tMobile No.:"); read_mob(p); printf("\n\tSalary :"); scanf("%f", &(p->salary)); printf( "\n\tEnter \"1\" for the projects employee is working on, otherwise enter \"0\": \n"); for (j = 0; j < 5; j++) { printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); while (p->proj[j] != 1 && p->proj[j] != 0) { printf("\n\nInvalid entry!! Please re-enter."); printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); } } printf("\n\n\n"); return p; } void read_name(emp_node *p) //validation for name { int j, len; scanf("%s", p->name); len = strlen(p->name); for (j = 0; j < len; j++) { if (!isalpha(p->name[j])) { printf( "\n\n\tInvalid name!!Can contain only characters. Please Re-enter.\n"); printf("\n\tName : "); read_name(p); } } } void read_mob(emp_node *p) //validation for mobile no. { int j; scanf("%s", p->mob_no); while (strlen(p->mob_no) != 10) { printf("\n\nInvalid Mobile No!!Please Re-enter"); printf("\n\n\tMobile No.:"); read_mob(p); } for (j = 0; j < 10; j++) { if (!(48 <= p->mob_no[j] && p->mob_no[j] <= 57)) { printf( "\n\nInvalid Mobile No!!Can contain only digits. Please Re-enter."); printf("\n\n\tMobile No.:"); read_mob(p); } } } void display_db(emp_node *head) //displaying whole database { emp_node *p; p = head; printf("\n\n\t\t****** EMPLOYEE DATABASE ******\n"); printf( "\n=============================================================================="); printf("\n Id.\t Name\t\t Mobile No\t Salary\t Projects\n"); while (p != NULL) { display_rec(p); p = p->next; printf("\n\n\n"); } printf( "\n=============================================================================="); } void swtch(emp_node *head) //function for menu and switch case { int cho, x; emp_node *p; printf("\n\n\t\t****** MENU ******"); printf( "\n\n\t1. insert Record\n\t2. Search Record\n\t3. Modify Record\n\t4. Delete Record\n\t5. Display Reverse\n\t6. Exit"); printf("\n\tWhich operation do you want to perform? "); scanf("%d", &cho); switch (cho) { case 1: p=head; while(p->next != NULL) p=p->next; p->next = (emp_node *) malloc(sizeof(emp_node)); p=p->next; p = add_rec(p); p->next = NULL; display_db(head); break; case 2: printf("\n\n\tEnter employee ID whose record is to be Searched :"); scanf("%d", &x); p = search_db(head, x); if (p == NULL) printf("\n\nRecord not found."); else display_rec(p); break; case 3: printf("\n\n\tEnter employee ID whose record is to be modified :"); scanf("%d", &x); p = search_db(head, x); if (p == NULL) printf("\n\nRecord not found."); else modify_rec(p); display_db(head); break; case 4: printf("\n\n\tEnter employee ID whose record is to be deleted :"); scanf("%d", &x); head = delete_rec(head, x); display_db(head); break; case 5: display_rev(head); case 6: exit(0); default: printf("Invalid Choice!! Please try again."); } } emp_node* search_db(emp_node *head, int id) //search database { emp_node *p = head; while (p != NULL) { if (p->emp_id == id) return p; p = p->next; } return NULL; } void display_rec(emp_node *p) //display a single record { int j; printf("\n %d", p->emp_id); printf("\t %10s", p->name); printf("\t %10s", p->mob_no); printf("\t %05.2f", p->salary); printf("\t "); for (j = 0; j < 5; j++) { if (p->proj[j] == 1) printf(" %d,", j + 1); } } void modify_rec(emp_node *p) //modifying a record { int j, cho; char ch1, edt; do { printf( "\n\t1. Name\n\t2. Email Address\n\t3. Mobile No.\n\t4. Salary\n\t5. Date of birth\n\t6. Projects\n"); printf("Enter your choice : "); scanf("%d", &cho); switch (cho) { case 1: printf("\n\tPrevious name:%s", p->name); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New Name:"); read_name(p); } break; case 2: printf("\n\tPrevious Mobile No. : %s", p->mob_no); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New Mobile No. :"); read_mob(p); } break; case 3: printf("\n\tPrevious salary is : %f", p->salary); printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf("\n\tEnter New salary:"); scanf("%f", &(p->salary)); } break; case 4: printf("the employee is currently working on project no. "); for (j = 0; j < 5; j++) { if (p->proj[j] == 1) printf(" %d,", j + 1); } printf("\n\tDo you want to edit ? (y/n)"); getchar(); scanf("%c", &ch1); if (ch1 == 'y' || ch1 == 'Y') { printf( "\n\tEnter \"1\" for the projects employee is working on : \n"); for (j = 0; j < 5; j++) { printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); while (p->proj[j] != 1) { printf("\n\nInvalid entry!! Please re-enter."); printf("\n\t\tProject No. %d : ", j + 1); scanf("%d", &(p->proj[j])); } } } break; default: printf("\n\nInvalid Choice!! Please Try again."); } printf("\n\nDo you want to edit any other fields ?(y/n)"); getchar(); scanf("%c", &edt); } while (edt == 'y' || edt == 'Y'); } emp_node* delete_rec(emp_node *head, int id) //physical deletion of record { emp_node *p = head, *q; if (head->emp_id == id) { head = head->next; free(p); return head; } else { q = p->next; while (q->emp_id != id) { p = p->next; q = q->next; } if (q->next == NULL) p->next = NULL; else p->next = q->next; free(q); return head; } } void display_rev(emp_node *head) { emp_node *p=head, *q; while(p->next != NULL) p=p->next; while(p!=head || p==head){ q=head; display_rec(p); while(q->next != p) q=q->next; p=q; } }

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  • Recommended total system backup solution

    - by bioShark
    I hope this question won't get closed immediately since it has a generic title. I already searched a bit around the answers here, but nothing satisfied me. I want a back-up solution that makes a total back-up, so that I can restore my Ubuntu in case of major failures, like HDD failing. As far as I can see, I have 2 choices: 1) Backing up with Deja Dup to an external disk. This is fine and I am already doing, but in case my HDD fails, and I make a new Ubuntu install on a new disk, will Deja Dup be able to restore all my setting and stuff from the backed up files? If it can, then what other files/folders should I add in Deja Dup to back-up (currently I have set only the recommended /home folder)? Is there a point in telling Deja Dup to back-up everything under "/" ? 2) A disk/partition cloning software. This would be something similar to Noton ghost. Is there such a software with nice GUI that you could recommend for Ubuntu? And even better, it would be nice if Ubuntu's liveCD could recognize such a clone at install step. I am using 11.10

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  • Windows no longer boots on dual-boot system

    - by N Alex
    While trying to delete an Ubuntu partition from my hdd I accidentally rebooted my computer. (Note: the partition was originally made from an existing partition using paragon.) After that when I tried to start the computer I got the GRUB rescue terminal prompt. I wasn't able to do much from that, but I did manage to boot Ubuntu from a USB drive and to run boot-repair. But now when I try to select Windows 7 from the boot selection menu I get the error 0xc0000225. Here is the link to the BootInfo summary created by boot-repair: http://paste.ubuntu.com/1032584/ I have a lot of very important data on my hdd and I would really appreciate your help.

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  • Ubuntu 12.10 automatic logout

    - by anthony
    I just had a new desktop constructed and installed ubuntu 12.10 which was successful for the most part but every time I open up some applications like thunderbird I get automatically logged out and all my windows are closed. System error messages also come up from time to time. Also I'm not sure if this helps but if I select the "Use system title bar and borders" in chromium I will also get logged out and from that point won't be able to use it without getting logged out in the future. If I click on particular links as well. If anyone has any tips on how I can isolate and fix the problem I would greatly appreciate it.

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  • sprite animation system height recalculating has some issues

    - by Nicolas Martel
    Basically, the way it works is that it update the frame to show every let's say 24 ticks and every time the frame update, it recalculates the height and width of the new sprite to render so that my gravity logics and stuff works well. But the problem i am having now is a bit hard to explain in words only, therefore i will use this picture to assist me The picture So what i need basically is that if let's say i froze the sprite at the first frame, then unfreeze it and freeze it at the second frame, have the second frame's sprite (let's say it's a prone move) simply stand on the foothold without starting the gravity and when switching back, have the first sprite go back on the foothold like normal without being under the foothold. I had 2 ideas on doing this but I'm not sure it's the most efficient ways to do it so i wanna hear your inputs.

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  • commons-exec: Executing a program on the system PATH?

    - by Stefan Kendall
    I'm trying to execute a program (convert from ImageMagick, to be specific) whose parent folder exists on the path. Ergo, when I run convert from the command line, it runs the command. The following, however, fails: String command = "convert" CommandLine commandLine = CommandLine.parse(command); commandLine.addArgument(...) ... int exitValue = executor.execute(commandLine); If I specify the full path of the convert executable (C:\Program files\...) then this code works. If I don't do this, I get an exception thrown with exit value 4. How do I get commons-exec to recognize the system path?

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  • Printing array with delimiters in Perl

    - by Mark B
    I have an array in Perl I want to print with space delimiters between each element, except every 10th element which should be newline delimited. There aren't any spaces in the elements if that matters. I've written a function to do it with for and a counter, but I wondered if there's a better/shorter/canonical Perl way, perhaps a special join syntax or similar. My function to illustrate: sub PrintArrayWithNewlines { my $counter = 0; my $newlineIndex = shift @_; foreach my $item (@_) { ++$counter; print "$item"; if($counter == $newlineIndex) { $counter = 0; print "\n"; } else { print " "; } } }

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  • Printing contents of a div

    - by Hulk
    The contents of the following div re derived dynamically. i.e, A table is added dynamically to this div with some button .My question is how to print the content of this div(window.print) and not other things in the page <div id="newdiv" name="newdiv"></div> Thanks..............

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