Search Results

Search found 17510 results on 701 pages for 'xml dom'.

Page 82/701 | < Previous Page | 78 79 80 81 82 83 84 85 86 87 88 89  | Next Page >

  • How to decode ASN.1 to XML with erlang

    - by shian
    Hi I use asn1 module in erlang to decode. The output is like {'UL-CCCH-Message',asn1_NOVALUE, {rrcConnectionRequest, {'RRCConnectionRequest', {'tmsi-and-LAI', {'TMSI-and-LAI-GSM-MAP', [1,0,0,0,0,1,1,1,1,1,1,0,1,0,0,0,0,1,1,0,1,1,0,1,0,1,1, 1,1,0,1,0], {'LAI', {'PLMN-Identity',[2,2,6],[0,1]}, [0,1,1,1,1,0,0,1,1,0,0,0,1,1,0,1]}}}, terminatingBackgroundCall,noError, {'MeasuredResultsOnRACH', {'MeasuredResultsOnRACH_currentCell', {fdd, {'MeasuredResultsOnRACH_currentCell_modeSpecificInfo_fdd', {'cpich-Ec-N0',39}}}}, asn1_NOVALUE}, asn1_NOVALUE}}} How can I output XML instead of erlang term?

    Read the article

  • Python modify an xml file

    - by michele
    I have this xml model. link text So I have to add some node (see the text commented) to this file. How I can do it? I have writed this partial code but it doesn't work: xmldoc=minidom.parse(directory) child = xmldoc.createElement("map") for node in xmldoc.getElementsByTagName("Environment"): node.appendChild(child) Thanks in advance.

    Read the article

  • Does an XPathDocument load the whole xml document?

    - by Wires
    If I do XPathDocument doc = new XPathDocument("filename.xml"); Does that load the entire document into memory? I'm writing a mobile phone app and the document might store lots of data that doesn't ever need to all be loaded at the same time. Mobile phones don't usually have too much ram!

    Read the article

  • Convert text to xml

    - by Nave
    I want to convert a tab delimited text file to a XML file. I was able to do it with a single character delimiter. But how do i extend it to tabs? I am coding in C# and using Visual Studio 2010.

    Read the article

  • Merging XML records into one

    - by BhanuPratap Tarigopula
    I am new to XSLT. I have requirement of merging and adding. XML: <OrderDetails> <OrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <OrderDetail action="add"> <OrderedUnits>12</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <IOrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295762</PONumber> </OrderDetail> <OrderDetails> If the LocationCode, Date, and PONumber fields match, I need to add the OrderedUnits and make it only one entry. Expected output XML: <OrderDetails> <OrderDetail action="add"> <OrderedUnits>30</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <IOrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295762</PONumber> </OrderDetail> <OrderDetails> How can I write this XSLT?

    Read the article

  • xml appending issue - in ie, chrome browsers

    - by 3gwebtrain
    Hi, i am using this coding for my xml information to append in to html. As well it works fine. but in the ie7,ie8 as well chrome browser it's not propelry. This code work9ing well with firefox,opera, safari.. i unable to find, what is the mistake i made this.. any one help me please? $(function(){ var thisPage; var parentPage; $('ul.left-navi li a').each(function(){ $('ul.left-navi li a').removeClass('current'); var pathname = (window.location.pathname.match(/[^\/]+$/)[0]); var currentPage = $(this).attr('href'); var pathArr = new Array(); pathArr = pathname.split("."); var file = pathArr[pathArr.length - 2]; thisPage = file; if(currentPage==pathname){ $(this).addClass("active"); } }) $.get('career-utility.xml',function(myData){ var receivedData = myData; var myXml = $(myData).find(thisPage); parentPage = thisPage; var overviewTitle = myXml.find('overview').attr('title'); var description = myXml.find('discription').text(); var mainsublinkTitle = myXml.find('mainsublink').attr('title'); var thisTitle = myXml.find("intro").attr('title'); var thisIntro = myXml.find("introinfo").text(); $('<h3>'+overviewTitle+'</h3>').appendTo('.overViewInfo'); $('<p>'+description+'</p>').appendTo('.overViewInfo'); var sublinks = myXml.find('mainsublink').children('sublink'); $('#intro h3').append(thisTitle); $('#intro').append(thisIntro); sublinks.each(function(numsub){ var newSubLink = $(this); var sublinkPage = $(this).attr('pageto'); var linkInfo = $(this).text(); $('ul.career-link').append('<li><a href="'+sublinkPage+'">'+linkInfo+'</a></li>'); }) // alert('thisTitle : '+thisTitle+'thisIntro :'+thisIntro); $(myXml).find('listgroup').each(function(index){ var count = index; var listGroup = $(this); var listGroupTitle = $(this).attr('title'); var shortNote = $(this).attr('shortnote'); var subLink = $(this).find('sublist'); var firstList = $(this).find('list'); $('.grouplist').append('<div class="list-group"><h3>'+listGroupTitle+'</h3><ul class="level-one level' + count + '"></ul></div>'); firstList.each(function(listnum) { $(this).wrapInner('<li>') .find('sublistgroup').wrapInner('<ul>').children().unwrap() .find('sublist').wrapInner('<li>').children().unwrap(); // Append content of 'list' node $('ul.level'+count).append($(this).children()); }); }); }); })

    Read the article

  • Saving an XML that has invalid characters

    - by BDotA
    there are code snippets that strip the invalid characters inside a string before we save it as an XML ... but I have one more problem: Let's say my user wants to have a column name like "[MyColumnOne] ...so now I do not want to strip these "[","] well because these are the ones that user has defined and wants to see them so if I use some codes that are stripping the invalid characters they are also removing "[" and "[" but in this case I still need them to be saved... what can I do?

    Read the article

  • Write xml file with lxml

    - by systempuntoout
    Having a code like this: from lxml import etree root = etree.Element("root") root.set("interesting", "somewhat") child1 = etree.SubElement(root, "test") How do i write root Element object to an xml file using write() method of ElementTree class?

    Read the article

  • 'How decode my encode xml data?

    - by Alex
    Hi <% 'Stage 1 datas=Server.URLencode("<PaginationData currentPage=""1"" totalPages=""9""/>") response.write "Encode = " datas &"</br></br>" 'Stage 2 response.write "Decode = " 'How i again decode my encode data? %> In the "Stage 1" , i encode my xml data In the "Stage 2", How i decode the "Stage 1" Encode data? hoping your support

    Read the article

  • TouchCode XML parsing error

    - by itsaboutcode
    Hi, I have a xml document which has only one element in the document, which is <error>error string<error> But when i try to parse it, it says this document has no element at all. In other words when i try to access the rootElement it says "null" CXMLDocument *rssParser = [[[CXMLDocument alloc] initWithContentsOfURL:url options:0 error:nil] autorelease]; NSLog(@"Root: %@",[[rssParser rootElement] name]); Please tell me what is wroing with this. Thanks

    Read the article

  • Programatically upload XML file to SSRS server

    - by xt_20
    Hi all, How do I programatically upload an XSLT file to an SSRS server database? I would like exactly the same functionality as the 'Upload File', preferably using the 'rs' command. I have tried rs.CreateResource, but it doesn't seem to work for XML/XSLT files (though it works for Excel and image files) I understand that manipulating the SSRS db is not supported. Thanks

    Read the article

  • Actionscript 3 E4X working with MMS values in XML

    - by user150946
    I am building an application using Action script 3 I am retrieving some XML from the web however the node names are mms:Image mms:Results etc my action script compiler is throwing an error becuase it is not expecting to see the semi colon in the node name. How to I access the nodes? thanks

    Read the article

  • Replace XML Bullet Points Found in Feed in Classic ASP

    - by StevieB
    Hey I am currently reading in a XML file which contains bullet list in the following container i.e. ? the average pension contribution rate for executive directors . I am having a problem with symbol directly before the text of each bullet point I want to remove it i.e Replace(text,"old","new") but i cant seem to find what value that bullet point actually is to replace of that makes sense. Thanks

    Read the article

  • Is there any way to get the combine two xml into one xml in Linux.

    - by Tattat
    XML one is something like that: <dict> <key>2</key> <array> <string>A</string> <string>B</string> </array> <key>3</key> <array> <string>C</string> <string>D</string> <string>E</string> </array> </dict> XML Two is something like that: <dict> <key>A</key> <array> <string>A1</string> <false/> <false/> <array> <string>Apple</string> <string>This is an apple</string> </array> <array> <string>Apple Pie</string> <string>I love Apple Pie.</string> </array> </array> <key>B</key> <array> <string>B7</string> <false/> <false/> <array> <string>Boy</string> <string>I am a boy.</string> </array> </array> </dict> I want to convert to this: <dict> <key>2</key> <array> <string>A, Apple, Apple Pie</string> <string>B, Boy</string> </array> ... </dict>

    Read the article

< Previous Page | 78 79 80 81 82 83 84 85 86 87 88 89  | Next Page >