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  • Passing input value thru XML loop and return value

    - by Mike Dyer
    "X" is reading the form value, but it is still passing and older "var thisMarket" value. The objective is to take a zip code via HTML form: <form id="market" name="market" onSubmit="return validateZIP(this.zip.value);" method="get" action=""> <input type="text" name="zip" id="zip" value="zipcode" onfocus="if(!this._haschanged){this.value=''};this._haschanged=true;" style="float:left; width:100px; margin-top:5px;"> <input type="image" style="float:left; margin-top:5px; border: 0pt none ; width: 22px; height:17px;" src="images/nav/bottom/linkbar/btn_search_btn.gif" onClick="findLda();"> </form> The script being passed thru is: function findLda(x){ marketName = new Array(); marketURL = new Array(); zip = new Array(); zip_temp = new Array(); zipMatch = false; var shareZip = "Shared Zips"; var thisMarket = "Market value"; xmlDoc=loadXML("/_includes/market.xml"); var Offer,node; document.getElementById('market').innerHTML=''; for(var j=0; j<xmlDoc.getElementsByTagName('market').length; j++){ node = xmlDoc.getElementsByTagName('market')[j]; marketName.push(node.childNodes[3].textContent); marketURL.push(node.childNodes[5].textContent); for(var k=0; k<node.getElementsByTagName('zip').length; k++){ if(node.getElementsByTagName('zip')[k].textContent!=null){ zip_temp.push(node.getElementsByTagName('zip')[k].textContent); } } zip.push(zip_temp); zip_temp = new Array(); } //loop the zip Array to find a match for the query Zip. for(k=0; k<zip.length; k++){ for(m=0; m<zip[k].length; m++){ if(x == zip[k][m].toString()){ zipMatch=true; thisMarket=marketName[k].toString(); } } } alert(thisMarket); } The objective naturally is to take field input (A), pass it thru market.xml - initialize a loop and match a zip (B), alert the result (C). Looking for any direction with what is existing or a completely new direction. Thanks!

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  • Help with XML path views

    - by xmlpath
    Hi all, is there any tool that will give me a view for XML fields like so. I want something that will show me the a view like so, if i select element1 Service/Body/element1 Is there any tool for eclipse for doing the above. Thanks.

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  • AS3 XML problem

    - by dd
    My Flash project is made of several .swf files, one of them loads XML gallery. everything works fine on my machine, but when I upload it to the testing server gallery content doesn't load. All my paths are relative to Main swf file. I can't make them absolute URLs, b/c I have to deliver zip package. What could be wrong?

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  • c# update xml file

    - by Pila
    I want to replace a xml node that is not a child of the root element. how can I do it - not in .Net 3.5? I don't know the exact path to the node I want to replace, I get the node by XPath query like : XmlElement root = doc.DocumentElement; oldItem = root.SelectSingleNode("//Node1[@name='aaa']//Node2[Item='bbb']/Value"); how can I replace this olditem?

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  • update XML file

    - by Pila
    I want to replace an XML node that is not a child of the root element. How can I do it - not in .NET 3.5? I don't know the exact path to the node I want to replace, I get the node by XPath query like: XmlElement root = doc.DocumentElement; oldItem = root.SelectSingleNode("//Node1[@name='aaa']//Node2[Item='bbb']/Value"); How can I replace this old item?

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  • One log4j.xml - many scripts

    - by psed
    One of my utility jar files is used by different nix scripts, located in different categories. Problem: unable to initialize log4j framework (unable to find log4j.xml). Solution, that allows to configure logger correctly while launching jar classes by different scripts - usage of env vars and force configuring using DOMConfigurtor.configure(pathToConfXml) method. is it possible to avoid path hardcoding and configure logger inside of a script? Appreciate all your help. Thanks.

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  • php DOM, get values from xml document, php xml

    - by Michael
    I'm trying to get some information (itemID, title, price and mileage) for multiple listings from ebay website using their api . So far I got this link up http://open.api.ebay.com/shopping?callname=GetMultipleItems&responseencoding=XML&appid=Morcovar-c74b-47c0-954f-463afb69a4b3&siteid=0&version=525&IncludeSelector=ItemSpecifics&ItemID=220617293997,250645537939,230485306218 I've saved the document as .xml file using php curl and now I need to get/extract the values(itemID, title, price and mileage) into arrays and store them in database. Unfortunately I never worked with php dom and I can't figure it out how to extract the values . I tried to follow the tutorial found on IBM website http://www.ibm.com/developerworks/library/os-xmldomphp/ but I had no success. Some help would be highly appreciated.

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  • Trying to send XML via EMail and the XML includes a byte[]

    - by barbary
    Hello All, I want to send an email that has a machine readable part you cut and paste into an asp.net page and you get the information. I have stored all the information in an object and then used an XMLSerizer to create some xml. It all worked fine until I added some Images as byte[] to the object. If I dump the resulting string to disk then I can recreate the object fine but after it appears in the email client and I try to cut and paste it it never works. Clearly there are non standard characters coming out that email clients don't like. Is there some encoding I could apply to my XML that would make it display correctly in an email client? Then I could cut, paste, decode and deserilize to get my object back. Please an example of how to encode the string in c# would be great.

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  • XML Parsing Error: junk after document element

    - by Jake
    I am using the following script to generate a RSS feed for my site: <?php class RSS { public function RSS() { $root = $_SERVER['DOCUMENT_ROOT']; require_once ("../connect.php"); } public function GetFeed() { return $this->getDetails() . $this->getItems(); } private function dbConnect() { DEFINE ('LINK', mysql_connect (DB_HOST, DB_USER, DB_PASSWORD)); } private function getDetails() { $detailsTable = "rss_feed_details"; $this->dbConnect($detailsTable); $query = "SELECT * FROM ". $detailsTable ." WHERE feed_category = ''"; $result = mysql_db_query (DB_NAME, $query, LINK); while($row = mysql_fetch_array($result)) { $details = '<?xml version="1.0" encoding="ISO-8859-1" ?> <rss version="2.0"> <channel> <title>'. $row['title'] .'</title> <link>'. $row['link'] .'</link> <description>'. $row['description'] .'</description> <language>'. $row['language'] .'</language> <image> <title>'. $row['image_title'] .'</title> <url>'. $row['image_url'] .'</url> <link>'. $row['image_link'] .'</link> <width>'. $row['image_width'] .'</width> <height>'. $row['image_height'] .'</height> </image>'; } return $details; } private function getItems() { $itemsTable = "rss_posts"; $this->dbConnect($itemsTable); $query = "SELECT * FROM ". $itemsTable ." ORDER BY id DESC"; $result = mysql_db_query (DB_NAME, $query, LINK); $items = ''; while($row = mysql_fetch_array($result)) { $items .= '<item> <title>'. $row["title"] .'</title> <link>'. $row["link"] .'</link> <description><![CDATA['.$row["readable_date"]."<br /><br />".$row["description"]."<br /><br />".']]></description> </item>'; } $items .= '</channel> </rss>'; return $items; } } ?> The baffling thing is, the script works perfectly fine on my localhost but gives the following error on my remote server: XML Parsing Error: junk after document element Location: http://mysite.com/rss/main/ Line Number 2, Column 1:<b>Parse error</b>: syntax error, unexpected T_STRING in <b>/home/studentw/public_html/rss/global-reach/rssClass.php</b> on line <b>1</b><br /> ^ Can someone please tell me what's wrong?

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  • How do I create self-relationships in polymorphic inheritance in Elixir and Pylons?

    - by Turukawa
    I am new to programming and am following the example in the Pylons documentation on creating a Wiki. The database I want to link to the wiki was created with Elixir so I rewrote the Wiki database schema and have continued from there. In the wiki there is a requirement for a Navigation table which is inherited by Pages and Sections. A section can have many pages, while a page can only have one section. In addition, each sibling node can be chain-referenced to each other. So: Nav has "section" (OneToMany) and "before" (OneToOne - to reference preceeding node) Page has "section" (ManyToOne - many pages in one section) and inherits "before" Section inherits all from Nav The code I've written looks like this: class Nav(Entity): using_options(inheritance='multi') name = Field(Unicode(30), default=u'Untitled Node') path = Field(Unicode(255), default=u'') section = OneToMany('Page', inverse='section') after = OneToOne('Nav', inverse='before') before = OneToMany('Nav', inverse='after') class Page(Nav): using_options(inheritance='multi') content = Field(UnicodeText, nullable=False) posted = Field(DateTime, default=now()) title = Field(Unicode(255), default=u'Untitled Page') heading = Field(Unicode(255)) tags = ManyToMany('Tag') comments = OneToMany('Comment') section = ManyToOne('Nav', inverse='section') class Section(Nav): using_options(inheritance='multi') Errors received on this: sqlalchemy.exc.OperationalError: (OperationalError) table nav has no column named aftr_id u'INSERT INTO nav (name, path, aftr_id, row_type) VALUES (?, ?, ?, ?)' I've also tried: before = ManyToMany('Nav', inverse='before') on Nav in the hopes this might break the problem, but also not. The original SQLAlchemy code from the tutorial for these declarations is as follows: nav_table = schema.Table('nav', meta.metadata, schema.Column('id', types.Integer(), schema.Sequence('nav_id_seq', optional=True), primary_key=True), schema.Column('name', types.Unicode(255), default=u'Untitled Node'), schema.Column('path', types.Unicode(255), default=u''), schema.Column('section', types.Integer(), schema.ForeignKey('nav.id')), schema.Column('before', types.Integer(), default=None), schema.Column('type', types.String(30), nullable=False) ) page_table = schema.Table('page', meta.metadata, schema.Column('id', types.Integer, schema.ForeignKey('nav.id'), primary_key=True), schema.Column('content', types.Text(), nullable=False), schema.Column('posted', types.DateTime(), default=now), schema.Column('title', types.Unicode(255), default=u'Untitled Page'), schema.Column('heading', types.Unicode(255)), ) section_table = sa.Table('section', meta.metadata, schema.Column('id', types.Integer, schema.ForeignKey('nav.id'), primary_key=True), ) orm.mapper(Nav, nav_table, polymorphic_on=nav_table.c.type, polymorphic_identity='nav') orm.mapper(Section, section_table, inherits=Nav, polymorphic_identity='section') orm.mapper(Page, page_table, inherits=Nav, polymorphic_identity='page', properties={ 'comments':orm.relation(Comment, backref='page', cascade='all'), 'tags':orm.relation(Tag, secondary=pagetag_table) }) Any help is much appreciated.

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  • What is this XML Parse Error?

    - by Jake
    I am using the following script to generate a RSS feed for my site: <?php class RSS { public function RSS() { $root = $_SERVER['DOCUMENT_ROOT']; require_once ("../connect.php"); } public function GetFeed() { return $this->getDetails() . $this->getItems(); } private function dbConnect() { DEFINE ('LINK', mysql_connect (DB_HOST, DB_USER, DB_PASSWORD)); } private function getDetails() { $detailsTable = "rss_feed_details"; $this->dbConnect($detailsTable); $query = "SELECT * FROM ". $detailsTable ." WHERE feed_category = ''"; $result = mysql_db_query (DB_NAME, $query, LINK); while($row = mysql_fetch_array($result)) { $details = '<?xml version="1.0" encoding="ISO-8859-1" ?> <rss version="2.0"> <channel> <title>'. $row['title'] .'</title> <link>'. $row['link'] .'</link> <description>'. $row['description'] .'</description> <language>'. $row['language'] .'</language> <image> <title>'. $row['image_title'] .'</title> <url>'. $row['image_url'] .'</url> <link>'. $row['image_link'] .'</link> <width>'. $row['image_width'] .'</width> <height>'. $row['image_height'] .'</height> </image>'; } return $details; } private function getItems() { $itemsTable = "rss_posts"; $this->dbConnect($itemsTable); $query = "SELECT * FROM ". $itemsTable ." ORDER BY id DESC"; $result = mysql_db_query (DB_NAME, $query, LINK); $items = ''; while($row = mysql_fetch_array($result)) { $items .= '<item> <title>'. $row["title"] .'</title> <link>'. $row["link"] .'</link> <description><![CDATA['.$row["readable_date"]."<br /><br />".$row["description"]."<br /><br />".']]></description> </item>'; } $items .= '</channel> </rss>'; return $items; } } ?> The baffling thing is, the script works perfectly fine on my localhost but gives the following error on my remote server: XML Parsing Error: junk after document element Location: http://mysite.com/rss/main/ Line Number 2, Column 1:<b>Parse error</b>: syntax error, unexpected T_STRING in <b>/home/studentw/public_html/rss/global-reach/rssClass.php</b> on line <b>1</b><br /> ^

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  • How to find specific value of the node in xml file

    - by user2735149
    I am making windows phone 8 app based the webservices. This is my xml code: - <response> <timestamp>2013-10-31T08:30:56Z</timestamp> <resultsOffset>0</resultsOffset> <status>success</status> <resultsLimit>8</resultsLimit> <resultsCount>38</resultsCount> - <headlines> - <headlinesItem> <headline>City edge past Toon</headline> <keywords /> <lastModified>2013-10-30T23:45:22Z</lastModified> <audio /> <premium>false</premium> + <links> - <api> - <news> <href>http://api.espn.com/v1/sports/news/1600444?region=GB</href> </news> </api> - <web> <href>http://espnfc.com/uk/en/report/381799/city-edge-toon?ex_cid=espnapi_public</href> </web> - <mobile> <href>http://m.espn.go.com/soccer/gamecast?gameId=381799&lang=EN&ex_cid=espnapi_public</href> </mobile> </links> <type>snReport</type> <related /> <id>1600444</id> <story>Alvardo Negredo and Edin Dzeko struck in extra-time to book Manchester City's place in the last eight of the Capital One Cup, while Costel Pantilimon kept a clean sheet in the 2-0 win to keep the pressure on Joe Hart. </story> <linkText>Newcastle 0-2 Man City</linkText> - <images> - <imagesItem> <height>360</height> <alt>Man City celebrate after Edin Dzeko scored their second extra-time goal at Newcastle.</alt> <width>640</width> <name>Man City celeb Edin Dzeko goal v nufc 20131030 [640x360]</name> <caption>Man City celebrate after Edin Dzeko scored their second extra-time goal at Newcastle.</caption> <type>inline</type> <url>http://espnfc.com/design05/images/2013/1030/mancitycelebedindzekogoalvnufc20131030_640x360.jpg</url> </imagesItem> </images> Code behind: myData = XDocument.Parse(e.Result, LoadOptions.None); var data = myData.Descendants("headlines").FirstOrDefault(); var data1 = from query in myData.Descendants("headlinesItem") select new UpdataNews { News = (string)query.Element("headline").Value, Desc = (string)query.Element("description"), Newsurl = (string)query.Element("links").Element("mobile").Element("href"), Imageurl=(string)query.Element("images").Element("imagesItem").Element("url").Value, }; lstShow.ItemsSource = data1; I am trying to get value from xml tags and assign them to News,Desc, etc. Everything works fine except Imageurl, it shows NullException. I tried same method for Imageurl, i dont know whats going wrong. Help..

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  • How to convert XML to a HTML table using XSL for-each

    - by Meeeee
    I am trying to convert some XML with XSL, to make the output look better and more readable for other users. I have some XML along the lines of: <G> <OE> <example1>Sample 1</example1> <example2>Sample 2</example2> <var name="name1"> <integer>1</integer> </var> </OE> </G> I want to get all the details from it and display it in a table so I use the following XSL code: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:template match="/"> <html> <body> <h2>Heading</h2> <table border="1"> <tr bgcolor="#3399FF"> <th>Example 1</th> <th>Example 2</th> <th>Var name</th> <th>Int</th> </tr> <xsl:for-each select="G/OE"> <xsl:for-each select="var"> <tr> <td> <xsl:value-of select="Example 1" /> </td> <td> <xsl:value-of select="Example 2" /> </td> <td> <xsl:value-of select="@name" /> </td> <td> <xsl:value-of select="integer" /> </td> </tr> </xsl:for-each> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> I know that the following XSL won't work properly. I want the output to be: Sample 1, Sample 2, name1, 1 - in a table format. My problem is I don't know how to do this. In the above XSL code it will only retrieve var and integer. If I only use the top <xsl:for-each>, then only the first two are retrieved. I have tried moving the 2nd <xsl:for-each> after the first to have been selected, so between: <td><xsl:value-of select="Example 2"/></td> and <td><xsl:value-of select="@name"/></td> I get an error. Is there any way to solve this problem? Thanks for the help.

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  • Binding Combobox to XML (wpf)

    - by mortor
    <EssenceList> <Essence GUID="464"> <Properties> <Property Name="Name"> <value>mt-1232-1. (1-1-3)</value> </Property> </Properties> <Characteristics> <Characteristic GUID="78"> <value>gadget</value> </Characteristic> <Characteristic GUID="79"> <value>measures</value> </Characteristic> </Characteristics> <LinkedEssences> <LinkType Type="ObjGroup"> <LinkedEssence GUID="369" /> </LinkType> <LinkType Type="ObjGroupProp" /> <LinkType Type="RoleObject"> <LinkedEssence GUID="5747"/> </LinkType> </LinkedEssences> </Essence> ... <Essence GUID="5747" Type="Role"> <Properties> <Property Name="Name"> <value>????-22</value> </Property> <Property Name="ShortName"> <value>UKPG-22</value> </Property> <Property Name="TagPrefix"> <value>UKPG22</value> </Property> <Property Name="useParentTagPrefix"> <value>0</value> </Property> </Properties> </Essence> ... <Essence GUID="5748" Type="Role"> </Essence> ... in example is a xml file with data from database. now i need to bind it to some fields... i use the XMLDataProvider here <Grid.DataContext> <XmlDataProvider x:Name="dataxml" XPath="EssenceList/Essence" Source="464.xml"/> </Grid.DataContext> and mostof simple texboxes i bind like <TextBox Text="{Binding XPath=/EssenceList/Essence/LinkedEssences/LinkType[1]/LinkedEssence/@GUID}" /> but now i need to bind a combobox this way: - the first Essence in the document contains LinkedEssences, that contains and - in document below there is a full description for it that contains the NAME property i need ????-22 UKPG22 0 and many other available Essences for this combobox i managed to bind the list of thems to combobox <ComboBox ItemTemplate="{StaticResource rolelistTemplate}" ItemsSource="{Binding XPath=/EssenceList/Essence[@Type]}" /> so it displays it well, but i can't bind it to my LinkedEssences.

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  • How to check if string is a valid XML element name?

    - by xsaero00
    I need a regex or a function in PHP that will validate a string to be a good XML element name. Form w3schools: XML elements must follow these naming rules: Names can contain letters, numbers, and other characters Names cannot start with a number or punctuation character Names cannot start with the letters xml (or XML, or Xml, etc) Names cannot contain spaces I can write a basic regex that will check for rules 1,2 and 4, but it won't account for all punctuation allowed and won't account for 3rd rule \w[\w0-9-]

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  • Reading an XML file and store data to mysql database.

    - by Jack Brown
    Hi I need the following php script to do a currency conversion using a different XML file. Its a script from white-hat design http://www.white-hat-web-design.co.uk/articles/php-currency-conversion.php The script needs to be amended to do the following: 1, The php script downloads every 24 hours an xml file from rss.timegenie.com/foreign_exchange_rates_forex rss.timegenie.com/forex.xml rss.timegenie.com/forex2.xml 2, It then stores the xml file data/contents to a mysql database file ie currency and rate. Any advice would be appreciated.

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  • linq to xml query returning a list of all child elements

    - by Xience
    I have got an xml document which looks something like this. <Root> <Info>....</Info> <Info>....</Info> <response>....</response> <warning>....</warning> <Info>....</Info> </Root> How can i write a linqToXML query so that it returns me an IEnumerable containing each child element, in this case all five child elements of , so that i could iterate over them. The order of child elements is not definite, neither is number of times the may appear. Thanks in advance

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  • Android vertical line xml

    - by Kaspa
    Hello, I'm trying to figure out how to define a verical line (1px thick) to be used as a drawable. to make a horizontal one, it's pretty straightforward: <shape xmlns:android="http://schemas.android.com/apk/res/android" android:shape="line"> <stroke android:width="1dp" android:color="#0000FF"/> <size android:height="50dp" /> </shape> The question is, how to make this line vertical? Yes, there are workarounds, such as drawing a rectangle shape 1px thick, but that complicates the drawable xml, if it consists of multiple <item> elements. Anyone had any chance with this?

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