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  • zend form check record no exists in database

    - by Yafa Su
    I have a form that check if email exists in the database within 2 tables. I'm using Zend_Validate_Db_NoRecordExists for both validate, but it only check the second one. Any idea why it's not working? class Application_Form_ReferUser extends Zend_Form { public $email, $freeDownload, $buyNow; public function init() { $this->setName('referUser'); $EmailExists = new Zend_Validate_Db_NoRecordExists( array( 'table' => 'referrals', 'field' => 'email' ) ); $EmailExists2 = new Zend_Validate_Db_NoRecordExists( array( 'table' => 'users', 'field' => 'email' ) ); $EmailExists->setMessage('This e-mail is already taken'); $EmailExists2->setMessage('This e-mail is already taken'); $this->email = $this->createElement('text', 'email') ->setLabel('Email') ->addValidator($EmailExists) ->addValidator($EmailExists2) ->addValidator('EmailAddress') ->setRequired(true); $this->freeDownload = $this->createElement('button', 'btn_free_download') ->setLabel('Free Download') ->setAttrib('type', 'submit'); $this->buyNow = $this->createElement('button', 'btn_buy_now') ->setLabel('Buy Now') ->setAttrib('type', 'submit'); $this->addElements(array($this->email, $this->freeDownload, $this->buyNow)); $elementDecorators = array( 'ViewHelper' ); $this->setElementDecorators($elementDecorators); } }

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  • How to set title and class in the HTML for the options of a ModelChoiceField?

    - by celopes
    I have a model class MyModel(models.Model): name = models.CharField(max_length=80, unique=True) parent = models.ForeignKey('self', null=True, blank=True) I want to render a ModelChoiceField for that model that looks like: <select name="mymodel" id="id_mymodel"> <option value="1" title="Value 1" class="">Value 1</option> <option value="2" title="Value 2" class="Value 1">Value 2</option> </select> The differences between this output and the default output for a ModelChoiceField are the title and class elements in the OPTION tag. They don't exist in ModelChoiceField's default output. For my purposes: The title element is supposed to be the Option Name. The class element is supposed to be self.parent.name. (this is my problem) So, in the HTML snippet above, Value 1 has no parent and Value 2 has a parent of Value 1. What is the best mechanism to change ModelChoiceField's default HTML output? EDIT: I understand how to create a new Widget for rendering HTML. The problem is how to render a value from the underlying model in each of the options.

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  • form_for called in a loop overloads IDs and associates fields and labels incorrectly

    - by Katy Levinson
    Rails likes giving all of my fields the same IDs when they are generated in a loop, and this causes trouble. <% current_user.subscriptions.each do |s| %> <div class="subscription_listing"> <%= link_to_function s.product.name, "toggle_delay(this)"%> in <%= s.calc_time_to_next_arrival %> days. <div class="modify_subscription"> <%= form_for s, :url => change_subscription_path(s) do |f| %> <%= label_tag(:q, "Days to delay:") %> <%= text_field_tag(:query) %> <%= check_box_tag(:always) %> <%= label_tag(:always, "Apply delay to all future orders") %> <%= submit_tag("Change") %> <% end %> <%= link_to 'Destroy', s, :confirm => 'Are you sure?', :method => :delete %> </div> </div> <% end %> Produces <div class="subscription_listing"> <a href="#" onclick="toggle_delay(this); return false;">Pasta</a> in 57 days. <div class="modify_subscription"> <form accept-charset="UTF-8" action="/subscriptions/7/change" class="edit_subscription" id="edit_subscription_7" method="post"><div style="margin:0;padding:0;display:inline"><input name="utf8" type="hidden" value="&#x2713;" /><input name="_method" type="hidden" value="put" /><input name="authenticity_token" type="hidden" value="s5LJffuzmbEMkSrez8b3KLVmDWN/PGmDryXhp25+qc4=" /></div> <label for="q">Days to delay:</label> <input id="query" name="query" type="text" /> <input id="always" name="always" type="checkbox" value="1" /> <label for="always">Apply delay to all future orders</label> <input name="commit" type="submit" value="Change" /> </form> <a href="/subscriptions/7" data-confirm="Are you sure?" data-method="delete" rel="nofollow">Destroy</a> </div> </div> <div class="subscription_listing"> <a href="#" onclick="toggle_delay(this); return false;">Gummy Bears</a> in 57 days. <div class="modify_subscription"> <form accept-charset="UTF-8" action="/subscriptions/8/change" class="edit_subscription" id="edit_subscription_8" method="post"><div style="margin:0;padding:0;display:inline"><input name="utf8" type="hidden" value="&#x2713;" /><input name="_method" type="hidden" value="put" /><input name="authenticity_token" type="hidden" value="s5LJffuzmbEMkSrez8b3KLVmDWN/PGmDryXhp25+qc4=" /></div> <label for="q">Days to delay:</label> <input id="query" name="query" type="text" /> <input id="always" name="always" type="checkbox" value="1" /> <label for="always">Apply delay to all future orders</label> <input name="commit" type="submit" value="Change" /> </form> <a href="/subscriptions/8" data-confirm="Are you sure?" data-method="delete" rel="nofollow">Destroy</a> </div> </div> And that's a problem because now no matter which "Apply delay to all future orders" I select it always very helpfully checks the first box for me. How can I override the ID without doing something ugly and un-rails-like?

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  • How to pass a variable inside a jquery fonction $.each($("abc")...?

    - by Rock
    I'm trying to iterate a bunch of SELECT OPTION html drop-down fields and from the ones that are NOT empty, take the values and add a hidden field for a PAYPAL shopping cart. My problem is that for some reason, the variable "curitem" is not passed inside the each function and I can't add the hidden field like they should. All I get is "NaN" or "undefined". What PAYPAL expect is : item_name_1, item_name_2, etc. All numbers must iterate by +1. How can I do this? Thanks a bunch in advance var curitem; $.each($("select"), function(index, item) { var attname = $(this).attr("name"); var nom = $(this).attr("data-nom"); var prix = $(this).attr("data-val"); var partname = attname.substring(0, 1); var qte = $(this).val(); // i want all my <select option> items that the NAME start with "q" AND have a value selected if (partname == "q" && isNaN(qte) == false && qte > 0) { // item name var inp2 = document.createElement("input"); inp2.setAttribute("type", "hidden"); inp2.setAttribute("id", "item_name_"+curitem); inp2.setAttribute("name", "item_name_"+curitem); inp2.setAttribute("value", nom); // amount var inp3 = document.createElement("input"); inp3.setAttribute("type", "hidden"); inp3.setAttribute("id", "amount_"+curitem); inp3.setAttribute("name", "amount_"+curitem); inp3.setAttribute("value", prix); // qty var inp4 = document.createElement("input"); inp4.setAttribute("type", "hidden"); inp4.setAttribute("id", "quantity_"+curitem); inp4.setAttribute("name", "quantity_"+curitem); inp4.setAttribute("value", qte); // add hidden fields to form document.getElementById('payPalForm').appendChild(inp2); document.getElementById('payPalForm').appendChild(inp3); document.getElementById('payPalForm').appendChild(inp4); // item number curitem = curitem + 1; } });

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  • Best way to manage the persistence of a form state, to and from a database

    - by Laurent.B
    In a JSP/Servlet webapp, I have to implement a functionality that allows a user to save or restore a form state, that latter containing for instance some search criteria. In other words, the user must be able to save or restore field values of a form, at any time. On the same page that contains that form, there's also another little form that allows him to name his form state before saving it. Then, later he'll be able to recall that state, via a combobox, and refill dynamically the form with the state he selected. I know how to implement that by hand but I would prefer not to reinvent the wheel then I'd like to know if there are some frameworks managing that kind of functionality ? A mix between JSP taglib, filter class, jQuery or other JavaScript frameworks... My research has not give anything yet. Thank you in advance.

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  • Toggle classes with radio button in jQuery

    - by dardub
    I have a set of radio buttons where when I click a radio button, I want the label to change color or whatever. But when I click another radio button, the color goes away. Therefore I have something like this: jQuery('label').mouseup(function(){ jQuery(this).prev().attr('checked', 'checked'); jQuery('input').next().removeClass('selected'); jQuery('input:checked').next().addClass('selected'); }); if you need to see some html: <input type="radio" id="radio1" name="myRadio" value="option-1" /> <label for="radio1">Swing Gate</label> <input type="radio" id="radio2" name="myRadio" value="option-2" /> <label for="radio2">Swing Gate</label> This first removes 'selected' class from all the labels and then re-applies to only the checked labels. It works and is simple, but I was thinking this might not be the most efficient way of doing this. I imagine that javascript is iterating through each input element and using more resources than necessary. I'm curious if anyone knows of a common way of doing this more efficiently. I seem to be doing this type of thing quite often in my jQuery code. I've just been using jQuery for the past 3 months or so btw.

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  • submitting a form inside a modalbox with jquery

    - by birdy
    submitting form with jQuery works $('#testform').submit(); doesn't work $('#testform').submit(function () { alert('test1'); return true; }); This is just an exmaple but at times i'd like to do stuff before submission of the form. Like for example submit the form using $.POST Update: If I keep both then the $.POST has no value because the form still gets submitted the traditional way, without ajax... $("#testform").submit(function() { $.post('/myajaxcontroller', function(data) { $('#result').html(data); }); }); $("#testform").submit();

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  • Drop down selection not registered when form submitted quickly?!

    - by Abs
    Hello all, I have noticed a strange thing that happens on my web app when the server is under heavy loads (I am remoting on to the Windows Server). I have a drop down box which is generated dynamically (server side). When I make a selection and quickly press the submit button to indicate my selection the next page does not register my selection but if I do it a bit more slowly it will. I have not come across this before, has anyone? I know its a small issue but there are a lot of "trigger happy", including me... should I put a delay before the form is submitted? If I do, I can only guess the right amount of time. Or is there an underlying problem with my web app? Thanks all

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  • [Rails] Accessing error_messages on form_tag

    - by aaronrussell
    I have built a custom form for creating a joining model on a has_many :through relationship. The models look roughly like this: class Team has_many :team_members has_many :members, :through => :team_members end class Member has_many :team_members has_many :teams, :through => :team_members end class TeamMember belongs_to :team belongs_to :member # and this model has some validations too end The form I have built is for selecting which members should be in a team. I won't paste the form, but it uses the form_tag method and basically sends an array of hashes which contain a member_id and a squad_number. I then update the database with an action that looks roughly like this (simplified a bit, but you get the jist): @team.transaction do @team.team_members = params[:team_members].collect{|tm| @team.team_members.new(tm)} if @team.save redirect_to ... else render :action => :members end end Everything works great but I am validating the squad_number for uniqueness and numerically. So, when any of those validations fail, how do I get access to them in my view, and how do I ascertain which of the many members it has failed on?

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  • How to get the right row in a sorted DataView?

    - by ZeissS
    Hi, I have a DataGrid containing a small table. Until now, I had a double click handler on this grid which iterated over all rows to find the selected one: DataTable table = (DataTable)this.dataGrid.DataSource; int selectedRow = -1; for (int i=0; i<table.Rows.Count; i++) if (this.dataGrid.IsSelected(i)) selectedRow = i; break; } if ( selectedRow != -1 ) { DataRow row = table.Rows[selectedRow]; // More code ... } Problem: When the user clicks on a column header and sort the table, table.Rows does not return the right rows. It still contains the unsorted rows. How can I get the right column?

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  • Need help with tweaking a Dropdown with three options, user selects one - a hidden div appears with correct fields

    - by Jack
    Hello Again, I posted a question on here and got an answer within minutes I'm hoping the wizards on here can help me again. Okay so I'm using a script I found online to try and add this function to a shopping cart form. Here's the setup. I have a payment method dropdown with Visa, Mastercard and Bank Withdrawal as the options. For the credit cards I have one hidden div with a certain set of fields, and for the bank I have another hidden div. Each of the divs have named ID's - #payCredit and #payBank The css for both have margin: 0px and display: none; Here's a peice of javascript I used successfuly on a shipping address checkbox `function toggleLayer( whichLayer ) { var elem, vis; if( document.getElementById ) // this is the way the standards work elem = document.getElementById( whichLayer ); else if( document.all ) // this is the way old msie versions work elem = document.all[whichLayer]; else if( document.layers ) // this is the way nn4 works elem = document.layers[whichLayer]; vis = elem.style; // if the style.display value is blank we try to figure it out here if(vis.display==''&&elem.offsetWidth!=undefined&&elem.offsetHeight!=undefined) vis.display = (elem.offsetWidth!=0&&elem.offsetHeight!=0)?'block':'none'; vis.display = (vis.display==''||vis.display=='block')?'none':'block'; }` I was hoping I could change it slightly to meet my needs. Here's the dropdown <label>Payment Method:</label> <select name="payment" id="payment" class="dropdown3" style="width:8em"> <option selected="selected">Select</option> <option value="Visa" onclick="javascript:toggleLayer('payCredit');">Visa</option> <option value="MasterCard" onclick="javascript:toggleLayer('payCredit');">Mastercard</option> <option value="Direct" onclick="javascript:toggleLayer('payBank');">Direct Withdraw</option> </select></li> The current result is that it kinda works. I can open the dropdown and select Visa and it appears, if I select Visa again it disappears, if I select Visa and then select bank, both appear. You can see what i'm working on here - http://test.sharevetcare.com/bestfriends/cart3.html

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  • Rails - Update a single attribute : link with custom action or form with hidden fields?

    - by MrRuru
    Let's say I have a User model, with a facebook_uid field corresponding to the user's facebook id. I want to allow the user to unlink his facebook account. Do do so, I need to set this attribute to nil. I currently see 2 ways of doing this First way : create a custom action and link to it # app/controllers/users_controller.rb def unlink_facebook_account @user = User.find params[:id] # Authorization checks go here @user.facebook_uid = nil @user.save # Redirection go here end # config/routes.rb ressources :users do get 'unlink_fb', :on => :member, :as => unlink_fb end # in a view = link_to "Unlink your facebook account", unlink_fb_path(@user) Second way : create a form to the existing update action # app/views/user/_unlink_fb_form.html.haml = form_for @user, :method => "post" do |f| = f.hidden_field :facebook_uid, :value => nil = f.submit "Unlink Facebook account" I'm not a big fan of either way. In the first one, I have to add a new action for something that the update controller already can do. In the second one, I cannot set the facebook_uid to nil without customizing the update action, and I cannot have a link instead of a button without adding some javascript. Still, what would you recommend as the best and most elegant solution for this context? Did I miss a third alternative?

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  • Javascript - Text Input Attributes

    - by bobrusha
    I need to create a form element <input disabled type="text" value="smth" /> which is disabled by default. It enables when onmouseover occures. onmouseover="this.disabled=false;" And is disabled by onmouseout onmouseout="this.disabled=true;" What I need is to check the following. If the <input> is focused then it shouldn't be disabled. And if the form element loses focus it disables. Please help me to complete the events. <input disabled type="text" value="smth" onmouseover="this.disabled=false;" onfocus="???" onblur="???" onmouseout="if(???){this.disabled=true;}" />

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  • How can I make my password fields always empty?

    - by ggfan
    I have a form field where users can change their passwords, but if they set their settings to remember passwords, their password shows up. Is there a way to make the field always empty? So that they always have to type their password. <label for="oldpassword" class="styled">Old password:</label> <input type="password" id="oldpassword" name="oldpassword"/><br />

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  • how to avoid storing several times a repeated field of a Symfony form?

    - by user454760
    Hello everybody, I am working with Symfony 1.4 and Doctrine. I have a model A with an email field. The form of A displays an input in which the user should insert the email correctly. But as everybody knows, sometimes they don't do it. To fix this I have inserted an extra field in the model (and in the form), called *repeat_email* to prevent the misspellings. Then, in the validation process, after validating all the fields, i use a global validator to compare the data of the two fields. This works, but I don't want to have the email stored two times in the database (I don't want the *repeat_email*). Is there any mechanism to use it in the validation process, but not to store it in the database? Thanks,

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  • (Python/Pyramid) Better ways to have standard list/form editors?

    - by badcat
    I'm working on a number of Pyramid (former Pylons) projects, and often I have the need to display a list of some content (let's say user accounts, log entries or simply some other data). A user should be able to paginate through the list, click on a row and get a form where he/she can edit the contents of that row. Right now I'm always re-inventing the wheel by having Mako templates which use webhelpers for the pagination, Jquery UI for providing a dialog and I craft the editor form and AJAX requests on the client and server side by hand. As you may know, this eats up painfully much time. So what I'm wondering is: Is there a better way of providing lists, editor dialog and server/client communication about this, without having to re-invent the wheel every time? I heard Django takes off a big load of that by providing user accounts and other stuff out of the box; but in my case it's not just about user accounts, it can be any kind of data that is stored on the server-side in a SQL database, which should be able to be edited by a user. Thanks in advance!

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  • form element not showing up after adding in through jquery

    - by ooo
    inside a jquery method (on a click event of a button) i have the following code: $(selector).html("<form action='/Tracker/CopyFood' method='post'><input type='hidden' name='Id' value=" + id + "><input class='very-small-input' type='text' name='Quantity' value='1' /> for <select name='Date'><option value='Today'>Today</option><option value='Yesterday'>Yesterday</option></select><select name='Meal'><option value='Breakfast'>Breakfast</option><option value='Lunch'>Lunch</option><option value='Dinner'>Dinner</option><option value='Evening Snack'>Evening Snack</option></select><input type='button' class='submitCopyFood' value='Add'> or <div style='display:inline' class='CancelCopy'>Cancel</div></form> "); it seems to work on the screen, but the button click "submitCopyFood" wasn't firing. When i click "View Selection Source" in firefox, i see the issue. All i see is this: <input name="Id" value="128" type="hidden"><input class="very-small-input" name="Quantity" value="1" type="text"> for <select name="Date"><option value="Today">Today</option><option value="Yesterday">Yesterday</option></select><select name="Meal"><option value="Breakfast">Breakfast</option><option value="Lunch">Lunch</option><option value="Dinner">Dinner</option><option value="Evening Snack">Evening Snack</option></select><input class="submitCopyFood" value="Add" type="button"> or <div style="display: inline;" class="CancelCopy">Cancel</div> Its like i never added the form anywhere. Is there any reason why i dont see the: <form action='/Tracker/CopyFood' method='post'> or the </form> in the source code inside the selected source. Is there something special that i need to do here?

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  • Select multiple submit issue - POST is empty if not selected

    - by Dasun
    I have a multiple select as below. It allows me to select options as below. Assume that 3 sports are selected. When the items are select as shown above form submit is successful. But unfortunately if the sports are not selected like below when the form is submitted post is empty. Select box <select style="width: 100px; height: 80px;" class="input" id="selected_sport_list" name="selected_sport_list[]" multiple=""> <option value="2">sport 2</option> <option value="3">sport 3</option> <option value="5">sport test x</option></select> How can I make sure that when the form is submitted particular items are selected? Is it possible to use jquery to fix this ? or how? Thanks

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  • Setting variable to value of form [drupal 6]

    - by N Schleder
    I have this form $form['title'] = array( '#type' => 'textfield', '#title' => t('Title of Notice'), '#description' => t('Use_underscores_as_spaces'), '#size' => 30, // '#required' => TRUE ); and I want whatever the user types in to be the value of $test I've tried $test = $form['title']; which gives me $test = array also I've tried $test = current($form['title']); which gives me $test = textfield $form['values']['title'] doesn't work dont know what else to try

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  • Change Image in Resources at Runtime

    - by zaidwaqi
    Hi, My understanding of Resources is that I can combine resources i.e. images and my program into single executable. Let's say I have image pic1.png and I put it into Resource of my project, and is accessible with Properties.Resource.pic1. For example, PictureBox pb = new PictureBox(); pb.Image = Properties.Resource.pic1; What I want to do is for that my program will be able to replace this image at runtime. For example, my program runs, and locate newPicture.png, and use this new image to replace pic1.png that was originally used. Maybe my question is better reworded as "Can I include new image into Resources at runtime?" Please help. Thanks.

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  • $_POST Variable Detected in Chrome but not in Firefox

    - by user1707973
    I am using 2 images in a form to sort out query results from the database. The form is submitted using the POST method. When i click on the first image, the query results have to be sorted in ascending order, and when i click on the second, the results have to be sorted in the descending order. This is the code for the form: <form name="" action="" method="post"> <input type="hidden" name="typep" value="price" /> <input type="image" name="sort" value="asc" src="images/asc-ar.png" /> <input type="image" name="sort" value="desc" src="images/dsc-ar.png" /> </form> Now this is the code for checking if the $_REQUEST['sort'] variable is set and therefore whether sorting is required or not. if ($_REQUEST['sort'] != "") { $sort = $_REQUEST['sort']; $typep = $_REQUEST['typep']; //query to be executed depending on values of $sort and $typep } Firefox does detect the $_REQUEST['typep'] variable but not the $_REQUEST['sort'] one. This works perfectly in Chrome though. When i test the site in Firefox, it doesn't detect the $_REQUEST['sort'] variable and therefore the if condition evaluates to false and the search results don't get sorted.

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  • submit button on html to output result on same page

    - by amateur
    Hi, Although this seems like something very basic, but no matter what I tried I couldn't get my head around it. Basically I want a html form where a user types in their ID number in an input text box and when they hit the submit button it displays their email address which is their company ID number @ company.com, such as below <form action=""> ID Number: <input type="text" name="idnumber" /><br/> <input type="submit" value="Whats my email address" /> </form> <p>Your email address is 'idnumber'@email.com</p> Can this even be done using html or would I need to use Javascript or PHP for it? Thanks

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  • how to don't store a repeated field of a Symfony form?

    - by user454760
    Hello everybody, I am working with Symfony 1.4 and Doctrine. I have a model A with a email field. The form of A, display an input in which the user should insert the email correctly. But as everybody know sometiemes they don't do it. To fix this i have insert an extra field in the model (and in the form), called *repeat_email* to prevent the misspellings. Then, in the validation process, after validates all the fields, i use a global validator to compare the data of the two fields. This works, but i don't want to have the email stored two times in the database (i don't want the *repeat_email*). Is there any mechanism to use it in the validation process, but not to store it in the database? Thanks,

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