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  • Django: get count of ForeignKey item in template?

    - by AP257
    Straightforward question - apologies if it is a duplicate, but I can't find the answer if so. I have a User model and a Submission model, like this: class Submission(models.Model): uploaded_by = models.ForeignKey('User') class User(models.Model): name = models.CharField(max_length=250 ) How can I show the number of Submissions made by each user in the template? I've tried {{ user.submission.count }}, like this: for user in users: {{ user.name }} ({{ user.submission.count }} submissions) but no luck...

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  • Per instance dynamic fields django model

    - by Roberto Rosario
    I have a model with a JSON field or a link to a CouchDB document. I can currently access the dynamic informaction in a way such as: genericdocument.objects.get(pk=1) == genericdocument.json_field['sample subfield'] instead I would like genericdocument.sample_subfield to maintain compatibility with all the apps the project currently shares.

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  • Can this django query be improved?

    - by Hobhouse
    Given a model structure like this: class Book(models.Model): user = models.ForeignKey(User) class Readingdate(models.Model): book = models.ForeignKey(Book) date = models.DateField() One book may have several readingdates. How do I list books having at least one readingdate within a specific year? I can do this: from_date = datetime.date(2010,1,1) to_date = datetime.date(2010,12,31) book_ids = Readingdate.objects\ .filter(date__range=(from_date,to_date))\ .values_list('book_id', flat=True) books_read_2010 = Book.objects.filter(id__in=book_ids) Is it possible to do this with one queryset, or is this the best way?

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  • django model relation definition

    - by Laurent Luce
    Hello, Let say I have 3 models: A, B and C with the following relations. A can have many B and many C. B can have many C Is the following correct: class A(models.Model): ... class B(models.Model): ... a = ForeignKey(A) class C(models.Model): ... a = ForeignKey(A) b = ForeignKey(B)

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  • django sort by manytomany relationship

    - by Marconi
    I have the following model: class Service(models.Model): ratings = models.ManyToManyField(User) Now if I wanna get all the service with ratings sorted in descending order I did something: services_list = Service.objects.filter(ratings__gt=0).distinct() services_list = list(services_list) services_list.sort(key=lambda service: service.ratings.all().count(), reverse=True) As you can see its a three step process and I don't feel right about this. Anybody who knows a better way to do this?

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  • Django | how to append form field to the urlconf

    - by MMRUser
    I want to pass a form's field value to the next page (template) after user submit the page, the field could be user name, consider the following setup def form_submit(request): if request.method == 'POST': form = UsersForm(request.POST) if form.is_valid(): cd = form.cleaned_data try: newUser = form.save() return HttpResponseRedirect('/mysite/nextpage/') except Exception, ex: return HttpResponse("Ane apoi %s" % str(ex)) else: return HttpResponse('Error') "nextpage" is the template that renders after user submit the form, so I want to know how to append the form's field (user name) to the url and get that value from the view in order to pass it to the next page.. thanks.

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  • Creating a Group of Groups in Django

    - by Greg
    I'm creating my own Group model; I'm not referring to the builtin Group model. I want each hroup to be a member of another group (it's parent), but there is the one "top" group that doesn't have a parent group. The admin interface won't let me create a group without entering a parent. I get the error personnel_group.parent_id may not be NULL. My Group model looks like this: class Group(models.Model): name = models.CharField(max_length=50) parent = models.ForeignKey('self', blank=True, null=True) order = models.IntegerField() icon = models.ImageField(upload_to='groups', blank=True, null=True) description = models.TextField(blank=True, null=True) How can I accomplish this? Thanks.

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  • Wordpress & Django -- One domain, two servers. Possible?

    - by DomoDomo
    My question is about hosting Django and Wordpress under one domain, but two physical machines (actually, they are VMs but same diff). Let's say I have a Django webapp at example.com. I'd like to start a Wordpress blog about my webapp, so any blog page rank mojo flows back to my webapp, I'd like the blog address t be example.com/blog. My understanding is blog.example.com would not transfer said page rank mojo. Because I'm worried about Wordpress security flaws compromising my Django webapp, I want to host Django and Wordpress on two physically separate machines. Given all that, is it possible using re-write rules or a reverse proxy server to do this? I know the easy way is to make my Wordpress blog a subdomain, but I really don't want to do that. Has anyone done this in the past, is it stable? If I need a third server to be a dedicated reverse proxy, that's totally fine. Thanks!

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  • Keeping filters in Django Admin

    - by Tomo
    What I would like to achive is: I go to admin site, apply some filters to the list of objects I click and object edit, edit, edit, hit 'Save' Site takes me to the list of objects... unfiltered. I'd like to have the filter from step 1 remembered and applied. Is there an easy way to do it?

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  • django ifequal naturalday

    - by Scott Willman
    I'm not sure why, but this condition will never evaluate True for me. I'm feeding it datetime.today() in the urls file. Am I missing something? Template: {% load humaize %} {{ entry.date|naturalday }} {# Evals to "today" #} {% ifequal entry.date|naturalday "today" %} True {{ entry.date|date:"fA"|lower }} {{ entry.date|naturalday|title }} {% else %} False {{ entry.date|naturalday|title }} {% endifequal %}

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  • Django Template Inheritance -- Missing Images?

    - by user367817
    Howdy, I have got the following file heirarchy: project   other stuff   templates       images           images for site       app1           templates for app1       registration           login template       base.html (base for entire site)       style.css (for base.html) In the login template, I am extending 'base.html.' 'base.html' uses 'style.css' along with all of the images in the 'templates/images' directory. For some reason, none of the CSS styles or images will show up in the login template, even though I'm extending it. Does this missing image issue have something to do with screwed up "media" settings somewhere? I never understood those, but this is a major roadblock in my proof-of-concept, so any help is appreciated. Thanks!

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  • Passing list of values to django view via jQuery ajax call

    - by finspin
    I'm trying to pass a list of numeric values (ids) from one web page to another with jQuery ajax call. I can't figure out how to pass and read all the values in the list. I can successfully post and read 1 value but not multiple values. Here is what I have so far: jQuery: var postUrl = "http://localhost:8000/ingredients/"; $('li').click(function(){ values = [1, 2]; $.ajax({ url: postUrl, type: 'POST', data: {'terid': values}, traditional: true, dataType: 'html', success: function(result){ $('#ingredients').append(result); } }); }); /ingredients/ view: def ingredients(request): if request.is_ajax(): ourid = request.POST.get('terid', False) ingredients = Ingredience.objects.filter(food__id__in=ourid) t = get_template('ingredients.html') html = t.render(Context({'ingredients': ingredients,})) return HttpResponse(html) else: html = '<p>This is not ajax</p>' return HttpResponse(html) With Firebug I can see that POST contains both ids but probably in the wrong format (terid=1&terid=2). So my ingredients view picks up only terid=2. What am I doing wrong? EDIT: To clarify, I need the ourid variable pass values [1, 2] to the filter in the ingredients view.

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  • Django | capture sub domain as a string

    - by MMRUser
    How do I capture a part of sub-domain name and get that name as a string in my views through a request. ex: user.domain.com developer.domain.com I want to capture the user part of this domain name through a request (lets say when the first time user hits the page). Thanks.

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  • How to disable translations during unit tests in django?

    - by Denilson Sá
    I'm using Django Internationalization tools to translate some strings from my application. The code looks like this: from django.utils.translation import ugettext as _ def my_view(request): output = _("Welcome to my site.") return HttpResponse(output) Then, I'm writing unit tests using the Django test client. These tests make a request to the view and compare the returned contents. How can I disable the translations while running the unit tests? I'm aiming to do this: class FoobarTestCase(unittest.TestCase): def setUp(self): # Do something here to disable the string translation. But what? # I've already tried this, but it didn't work: django.utils.translation.deactivate_all() def testFoobar(self): c = Client() response = c.get("/foobar") # I want to compare to the original string without translations. self.assertEquals(response.content.strip(), "Welcome to my site.")

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  • Putting links into text in Django

    - by Dane Larsen
    I have a notifications app that generates notifications for users. The notification class has to be really general, because notifications are generated by all sorts of different things. My question is this: How do I insert links into the text of the notifications? What I tried was this: note = Notification(..., notification="""%s %s has accepted the task: <a href="/tasks/%d/">%s</a>.""" % (request.user.first_name, request.user.last_name, task.id, task.name), ...) In retrospect, it's obvious this wouldn't work. How should I go about this? Thanks in advance!

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  • Asynchronous database update in Django?

    - by Mark
    I have a big form on my site. When the users fill it out and submit it, most of the data just gets dumped to the database, and then they get redirected to a new page. However, I'd also like to use the data to query another site, and then parse the results. That might take a bit longer. It's not essential that the user sees these results right away, so I was wondering if it's possible to asynchronously call a function that will handle this, and then return an HttpResponse from my view like usual without making them wait? If so... how? Any particular libraries I should look at?

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  • Django Aggregation Across Reverse Relationship

    - by Tom
    Given these two models: class Profile(models.Model): user = models.ForeignKey(User, unique=True, verbose_name=_('user')) about = models.TextField(_('about'), blank=True) zip = models.CharField(max_length=10, verbose_name='zip code', blank=True) website = models.URLField(_('website'), blank=True, verify_exists=False) class ProfileView(models.Model): profile = models.ForeignKey(Profile) viewer = models.ForeignKey(User, blank=True, null=True) created = models.DateTimeField(auto_now_add=True) I want to get all profiles sorted by total views. I can get a list of profile ids sorted by total views with: ProfileView.objects.values('profile').annotate(Count('profile')).order_by('-profile__count') But that's just a dictionary of profile ids, which means I then have to loop over it and put together a list of profile objects. Which is a number of additional queries and still doesn't result in a QuerySet. At that point, I might as well drop to raw SQL. Before I do, is there a way to do this from the Profile model? ProfileViews are related via a ForeignKey field, but it's not as though the Profile model knows that, so I'm not sure how to tie the two together. As an aside, I realize I could just store views as a property on the Profile model and that may turn out to be what I do here, but I'm still interested in learning how to better use the Aggregation functions.

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  • Django model help

    - by dotty
    Does anyone have any clue why this doesn't work as expected. If i use the python shell and do team.game_set or team.games It returns an error AttributeError: 'Team' object has no attribute 'game' If i create a Game object and call game.home_team it returns the correct team object Heres my model class Team(models.Model): name = models.CharField(blank=True, max_length=100) class Game(models.Model): home_team = models.ForeignKey(Team, related_name="home_team")

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