Search Results

Search found 3554 results on 143 pages for 'django modelformsets'.

Page 85/143 | < Previous Page | 81 82 83 84 85 86 87 88 89 90 91 92  | Next Page >

• Django query - join on the same table

  - by dana

  i have a mini blog app, and a 'timeline' . there i want to be displayed all the posts from all the friends of a user, plus the posts of that user himself. For that, i have to make some kind of a 'join' between the results of two queries (queries on the same table) , so that the final result will be the combination of the user - posesor of the account, and all his friends. My query looks like this: blog = New.objects.filter(created_by = following,created_by = request.user) By that ',' i wanted to make a 'join' -i found something like this on a doc- but this method is not correct- i'm getting an error. How else could be done this 'join' ? Thanks!

  Read the article

• How to join the results of two tables in django python

  - by user1787524

  I have two models class Weather(model.model): region = models.ForeignKey(Region) district = models.ForeignKey(District) temp_max = models.IntegerField(blank=True, null=True, verbose_name='Max temperature (C)') temp_min = models.IntegerField(blank=True, null=True, verbose_name='Min temperature (C)') and class Plan(model.model): name = tinymce_models.HTMLField(blank=True, null=True) region = models.ForeignKey(Region) district = models.ForeignKey(District) Provided for every region and district have unique row. I want to combine the result so that i can get all the columns of both tables These two Models are not related to each other. ' I need to make the join like join weather w on w.region = A.region and w.distric = A.district so that result contains all the columns in everyobject like obj.temp_max etc

  Read the article

• Django user get_all_permissions() is empty while user_permissions is set

  - by Murkin

  Hello I added some permissions to a user via the admin interface. From some reason all the perm functions fail, e.g >>> user.get_all_permissions() set([]) But accessing the table directly, works: >>> user.user_permissions.all() (list of permissions as expected) What can cause the "get_all_permissions" (and all the perm functions like has_perm()) to fail ? Thanks

  Read the article

• Python/Django tests running only one test at a time

  - by user2876296

  I have a unittest for my view class TestFromAllAdd(TestCase): fixtures = ['staging_accounts_user.json', 'staging_main_category.json', 'staging_main_dashboard.json', 'staging_main_location.json', 'staging_main_product.json', 'staging_main_shoppinglist.json'] def setUp(self): self.factory = RequestFactory() self.c = Client() self.c.login(username='admin', password='admin') def from_all_products_html404_test(self): request = self.factory.post('main/adding_from_all_products', {'product_id': ''}) request.user = User.objects.get(username= 'admin') response = adding_from_all_products(request) self.assertEqual(response.status_code, 404) But I have a few more classes with tests and I cant run them all at the same time: python manage.py test main doesnt run tests, but if i run; python manage.py test main.TestFromAllAdd.from_all_products_html404_test , runs one test;

  Read the article

• good django source browser app?

  - by Nick

  I need that works at least with svn, that reads your svn repository and displays information about files and folders contained in it as well as maybe revision info too.

  Read the article

• How do I query for this in Django?

  - by alex

  | random_code | varchar(200) | YES | UNI | NULL | | MyTable.objects.filter(random_code = None) Is this correct? Will this SELECT where there is no random code set? Above is my table.

  Read the article

• Django forms: where is POST data received?

  - by Rosarch

  I have a widget that allows user to enter data for a model field. The data in the form can't be directly converted to Python - it requires some coercion. Where do I put this code? Is the widget responsible for translating its post data to a python value? The field itself? I thought that maybe value_from_datadict() would be correct, but now it looks like that serves a different purpose. (I'm using the form in the admin interface, if it makes any difference.)

  Read the article

• Django template tag for Model query result

  - by dynback.com

  I wonna simple tag, for showing table of any model arrays like: {% table city_list %} Do anybody see such things?

  Read the article

• Django get() query not working

  - by pimcoooooooo

  this_category = Category.objects.get(name=cat_name) gives error: get() takes exactly 2 non-keyword arguments (1 given) I am using the appengine helper, so maybe that is causing problems. Category is my model. Category.objects.all() works fine. Filter is also similarily not working. Thanks,

  Read the article

• Deleting files associated with model - django

  - by alexBrand

  I have the following code in one of my models class PostImage(models.Model): post = models.ForeignKey(Post, related_name="images") # @@@@ figure out a way to have image folders per user... image = models.ImageField(upload_to='images') image_infowindow = models.ImageField(upload_to='images') image_thumb = models.ImageField(upload_to='images') image_web = models.ImageField(upload_to='images') description = models.CharField(max_length=100) order = models.IntegerField(null=True) IMAGE_SIZES = { 'image_infowindow':(70,70), 'image_thumb':(100,100), 'image_web':(640,480), } def delete(self, *args, **kwargs): # delete files.. self.image.delete(save=False) self.image_thumb.delete(save=False) self.image_web.delete(save=False) self.image_infowindow.delete(save=False) super(PostImage, self).delete(*args, **kwargs) I am trying to delete the files when the delete() method is called on PostImage. However, the files are not being removed. As you can see, I am overriding the delete() method, and deleting each ImageField. For some reason however, the files are not being removed.

  Read the article

• How to setup a django site with Cherokee, DynDNS and virtual_env?

  - by e-satis

  I have a django project running with the dev server, and would like to try run it in a production environment. I wanted to try Cherokee for a change, so I installed it. We don't have a domain name yet, so I set up a DynDNS looking like stuff.gotdns.org. It works fine, I can see the Cherokee welcome page (so red, I first believed I got an error :-p). I ran the wizard to create a new virtual server for Django. No everything is setup, but I have nothing. Still the default Cherokee welcome page. What should I do now if I want to go to "http://stuff.gotdns.org" and see my website? What should I do now if I next want to make it available only at "http://project.stuff.gotdns.org"? Important fact, I use virtual_env, so your can call Python directly, you have to activate it first.

  Read the article

• Django, wsgi, py. what's the difference?

  - by Kenny

  I'm trying to get a django application up and running on my cpanel system. I've installed mod_wsgi, and am following the guide here: http://www.nerdydork.com/setting-up-django-on-a-whm-cpanel-vps-liquidweb.html However, I'm now confused as I don't know what to do next. The application has .py files, and I am able to run it via this: python manage.py runserver 211.144.131.148:8000 However, that's via command line and binds to port 8000. I want to use Apache instead. The question is, that tutorial doesn't go further into how to get apache to recognize .py files and run the application as I want it. What do I do next?

  Read the article

• Google App Engine (python): TemplateSyntaxError: 'for' statements with five words should end in 'rev

  - by Phil

  This is using the web app framework, not Django. The following template code is giving me an TemplateSyntaxError: 'for' statements with five words should end in 'reversed' error when I try to render a dictionary. I don't understand what's causing this error. Could somebody shed some light on it for me? {% for code, name in charts.items %} <option value="{{code}}">{{name}}</option> {% endfor %} I'm rendering it using the following: class GenerateChart(basewebview): def get(self): values = {"datepicker":True} values["charts"] = {"p3": "3D Pie Chart", "p": "Segmented Pied Chart"} self.render_page("generatechart.html", values) class basewebview(webapp.RequestHandler): ''' Base class for all webapp.RequestHandler type classes ''' def render_page(self, filename, template_values=dict()): filename = "%s/%s" % (_template_dir, filename) path = os.path.join(os.path.dirname(__file__), filename) self.response.out.write(template.render(path, template_values))

  Read the article

• Hooking up Sproutcore frontend and custom Python backend

  - by Suvir

  Hello everyone, I am building a web-based application. The frontend has been designed in Sproutcore. For the backend, we have our own python API which handles all transactions with multiple databases. What is the best way to hook up the front-end with the back-end. AFAIK django is pretty monolithic (correct me if i am wrong) and it would be cumbersome if I dont use its native ORM...I would prefer a python-based solution..any ideas? thanks! Suvir

  Read the article

• Why don't these class attributes register?

  - by slypete

  I have a factory method that generates django form classes like so: def get_indicator_form(indicator, patient): class IndicatorForm(forms.Form): #These don't work! indicator_id = forms.IntegerField(initial=indicator.id, widget=forms.HiddenInput()) patient_id = forms.IntegerField(initial=patient.id, widget=forms.HiddenInput()) def __init__(self, *args, **kwargs): forms.Form.__init__(self, *args, **kwargs) self.indicator = indicator self.patient = patient #These do! setattr(IndicatorForm, 'indicator_id', forms.IntegerField(initial=indicator.id, widget=forms.HiddenInput())) setattr(IndicatorForm, 'patient_id', forms.IntegerField(initial=patient.id, widget=forms.HiddenInput())) for field in indicator.indicatorfield_set.all(): setattr(IndicatorForm, field.name, copy(field.get_field_type())) return type('IndicatorForm', (forms.Form,), dict(IndicatorForm.__dict__)) I'm trying to understand why the top form field declarations don't work, but the setattr method below does work. I'm fairly new to python, so I suspect it's some language feature that I'm misunderstanding. Can you help me understand why the field declarations at the top of the class don't add the fields to the class? In a possibly related note, when these classes are instantiated, instance.media returns nothing even though some fields have widgets with associated media. Thanks, Pete

  Read the article

• Search over multiple fields

  - by schneck

  Hi there, I think I don't unterstand django-haystack properly: I have a data model containing several fields, and I would to have two of them searched: class UserProfile(models.Model): user = models.ForeignKey(User, unique=True, default=None) twitter_account = models.CharField(max_length=50, blank=False) My search index settings: class UserProfileIndex(SearchIndex): text = CharField(document=True, model_attr='user') twitter_account = CharField(model_attr='twitter_account') def get_queryset(self): """Used when the entire index for model is updated.""" return UserProfile.objects.all() But when I perform a search, only the field "username" is searched; "twitter_account" is ignored. When I select the Searchresults via dbshell, the objects contain the correct values for "user" and "twitter_account", but the result page shows a "no results": {% if query %} <h3>Results</h3> {% for result in page.object_list %} <p> <a href="{{ result.object.get_absolute_url }}">{{ result.object.id }}</a> </p> {% empty %} <p>No results</p> {% endfor %} {% endif %} Any ideas?

  Read the article

• Cache for everybody except staff members.

  - by Oli

  I have a django site where I want to stick an "admin bar" along the top of every non-admin page for staff members. It would contain useful things like page editing tools, etc. The problem comes from me using the @cache_page decorator on lots of pages. If a normal user hits a page, the cached version comes up without the admin bar (even for admin users) and if an admin hits the page first, normal users see the admin bar. I could tediously step through the templates, adding regional cache blocks but there are a lot of templates, and life is altogether too short. Ideally, there would be a way of telling the caching to ignore cache get/set requests from admin users... But I don't know how to best implement that. How would you tackle this problem?

  Read the article

• How do I prevent a ManyToManyField('self') from linked an object to itself?

  - by dyve

  Consider this model (simplified for this question): class SecretAgentName(models.Model): name = models.CharField(max_length=100) aliases = ManyToManyField('self') I have three names, "James Bond", "007" and "Jason Bourne". "James Bond" and "007" are aliases of each other. This works exactly like I want it to, except for the fact that every instance can also be an alias of itself. This I want to prevent. So, there can be many SecretAgentNames, all can be aliases of each other as long as "James Bond" does not show up as an alias for "James Bond". Can I prevent this in the model definition? If not, can I prevent it anywhere else, preferably so that the Django Admin understands it?

  Read the article

• Removing a result from Queryset

  - by Enrico

  Is there a simple way to discard/remove the last result in a queryset without affecting the db? I am trying to paginate results in Django, but don't know the total number of objects for a given query. I was planning on using next/previous or older/newer links, so I only need to know if this is the first and/or last page. First is easy to check. To check for the last page I can compare the number of results with the pagesize or make a second query. The first method fails to detect the last page when the number of results in the last set equals the pagesize (ie 100 records get broken into 10 pages with the last page containing exactly 10 results) and I would like to avoid making a second query. My current thought is that I should fetch pagesize + 1 results from the db. If the queryset length equals 11, I know this is not the last page and I want to discard the last result in the queryset before passing the queryset to the template.

  Read the article

• Quering distinct values throught related model

  - by matheus.emm

  Hi! I have a simple one-to-many (models.ForeignKey) relationship between two of my model classes: class TeacherAssignment(models.Model): # ... some fields year = models.CharField(max_length=4) class LessonPlan(models.Model): teacher_assignment = models.ForeignKey(TeacherAssignment) # ... other fields I'd like to query my database to get the set of distinct years of TeacherAssignments related to at least one LessonPlan. I'm able to get this set using Django query API if I ignore the relation to LessonPlan: class TeacherAssignment(models.Model): # ... model's fields def get_years(self): year_values = self.objects.all().values_list('year').distinct().order_by('-year') return [yv[0] for yv in year_values if len(yv[0]) == 4] Unfortunately I don't know how to express the condition that the TeacherAssignment must be related to at least one LessonPlan. Any ideas how I'd be able to write the query? Thanks in advance.

  Read the article

• Passing session data to ModelForm inside of ModelAdmin

  - by theactiveactor

  I'm trying to initialize the form attribute for MyModelAdmin class inside an instance method, as follows: class MyModelAdmin(admin.ModelAdmin): def queryset(self, request): MyModelAdmin.form = MyModelForm(request.user) My goal is to customize the editing form of MyModelForm based on the current session. When I try this however, I keep getting an error (shown below). Is this the proper place to pass session data to ModelForm? If so, then what may be causing this error? TypeError at ... Exception Type: TypeError Exception Value: issubclass() arg 1 must be a class Exception Location: /usr/lib/pymodules/python2.6/django/forms/models.py in new, line 185

  Read the article

• Is it ok to hardcode dynamic links in a permanent view?

  - by meder

  Let's say I wanted to showcase 2-3 clickable buttons on my homepage which will be there permanently. These are links to the css, html, and javascript tag listing pages. Is it fine to just hardcode href=/tags/css and href=/tags/html right in my django templates/view? I won't change them for at least a year or so, meaning I don't think I need to add a column to the tags table to distinguish them - is this common or should I try to make it somewhat dynamic? These tags are in a table but so are 1000 other tags.

  Read the article

• Select distinct users with referrals

  - by Mark

  I have a bunch of Users. Since Django doesn't really let me extend the default User model, they each have Profiles. The Profiles have a referred_by field (a FK to User). I'm trying to get a list of Users with = 1 referral. Here's what I've got so far Profile.objects.filter(referred_by__isnull=False).values_list('referred_by', flat=True) Which gives me a list of IDs of the users who have referrals... but I need it to be distinct, and I want the User object, not their ID. Or better yet, it would be nice if it could return the number of referrals a user has. Any ideas?

  Read the article

• Saving related model objects

  - by iHeartDucks

  I have two related models (one to many) in my django app and When I do something like this ObjBlog = Blog() objBlog.name = 'test blog' objEntry1 = Entry() objEntry1.title = 'Entry one' objEntry2 = Entry() objEntry2.title = 'Entry Two' objBlog.entry_set.add(objEntry1) objBlog.entry_set.add(objEntry2) I get an error which says "null value in column and it violates the foreign key not null constraint". None of my model objects have been saved. Do I have to save the "objBlog" before I could set the entries? I was hoping I could call the save method on objBlog to save it all. NOTE: I am not creating a blog engine and this is just an example.

  Read the article

• Overwrite queryset which builds filter sidebar

  - by cw

  Hi, I'm writing a hockey database/manager. So I have the following models: class Team(models.Model): name = models.CharField(max_length=60) class Game(models.Model): home_team = models.ForeignKey(Team,related_name='home_team') away_team = models.ForeignKey(Team,related_name='away_team') class SeasonStats(models.Model): team = models.ForeignKey(Team) Ok, so my problem is the following. There are a lot of teams, but Stats are just managed for my Club. So if I use "list_display" in the admin backend, I'd like to modify/overwrite the queryset which builds the sidebar for filtering, to just display our home teams as a filter option. Is this somehow possible in Django? I already made a custom form like this class SeasonPlayerStatsAdminForm(forms.ModelForm): team = forms.ModelChoiceField(Team.objects.filter(club__home=True)) So now just the filtering is missing. Any ideas?

  Read the article

< Previous Page | 81 82 83 84 85 86 87 88 89 90 91 92  | Next Page >