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  • How can get autosuggest in cake php

    - by rajesh
    i hav entered my code in controller like below function keyup(){ $this-Note-simple(); if(strlen($searchq)0){ while ($row = mysql_fetch_array($getRecord)) { echo $row['name']; echo $row['department']; } return $row; } } as soon as i entered this one it doesn't display any info .... what correction should require.......

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  • Making a Login Work After Cache, Cookies, etc. Have Been Cleared

    - by John
    Hello, I am using the code below for a user login. The first I try to login after cache / cookies, etc. have been cleared, the browser refreshes and the user name is not logged in. After that, logging in works fine. Any idea how I can make it work the first time? Thanks in advance, John index.php: <?php if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../index.php?username='.$username.'&password='.$password.'');} require_once "header.php"; include "login.php"; require_once "footer.php"; ?> login.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } ?> show_loginform function: function show_loginform($disabled = false) { echo '<form name="login-form" id="login-form" method="post" action="./index.php?'.$_SERVER['QUERY_STRING'].'"> <div class="usernameformtext"><label title="Username">Username: </label></div> <div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div> <div class="passwordformtext"><label title="Password">Password: </label></div> <div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div> <div class="registertext"><a href="http://www...com/.../register.php" title="Register">Register</a></div> <div class="lostpasswordtext"><a href="http://www...com/.../lostpassword.php" title="Lost Password">Lost password?</a></div> <p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" '; if ($disabled == true) { echo 'disabled="disabled"'; } echo ' /></p></form>'; }

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  • How does the bitwise operator '^' work?

    - by SpawnCxy
    I'm a little confused when I see the output of following code: $x = "a"; $y = "b"; $x ^= $y; $y ^= $x; $x ^= $y; echo $x; //got b echo $y; //got a And I wonder how does the operator ^ work here?Explanations with clarity would be greatly appreciated!

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  • unix `tee` - chain of commands

    - by Mike
    In a unix environment, I want to use tee on a chain of commands like so $ echo 1; echo 2 | tee file 1 2 $ cat file 2 Why does file only end up as having the output from the final command? For the purpopses of this discussion, let's assume I can't break them apart and run the commands seperately.

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  • mootools fx working except in ie9

    - by Craig
    This is my first attempt with Mootools, so I welcome a critique of the code. I have a dynamic list of images that expand on the 'click" event and contract on the 'mouseout' event. The code works fine in all browsers (FF, Safari, Chrome, even the smartphones) but not in IE9 (JS is enabled) Anyone with similar problem or solution? I plan to use a lightbox effect, downloading a larger & clearer image to the center of the page, instead of just resizing a small image. However, I am hesitant to attempt this, if there is problems with IE9. I have coded three image sizes with the upload commit, so the larger image is available for the lightbox, but, I don't see anything in mootools for a lightbox, or am I missing it? $i = 0; while($i < count($validate)) { <div class="validate"> <div class="validate_image_<?php echo $validate[$i]['validate_type']; ?>"> <div class="validate_image" id="validate_image_wrapper_<?php echo $i; ?>"> <?php if ($validate[$i]['validate_image_filename'] != '') { if (file_exists(UPLOAD_DIR . 'validate_image/' . str_replace('.', '_medium.', $validate[$i]['validate_image_filename']))) { echo '<img src="' . UPLOAD_URL . 'validate_image/' . str_replace('.', '_medium.', $validate[$i]['validate_image_filename']) . '" alt="Listing Image" />'; } else { echo '<img src="' . UPLOAD_URL . 'validate_image/' . str_replace('.', '_large.', $validate[$i]['validate_image_filename']) . '" alt="Listing image" />'; } } else { ?> <img src="/images/no_image_posted_validate.png" alt="no image posted" /> <?php } ?> </div> ... remainder of HTML display code function setupEnlargeImage() { window.myFx = new Fx({ duration: 200, transition: Fx.Transitions.Sine.easeOut }); $$('.validate_image').addEvent('click', function() { window.selectedImage = this.id; myFx.start(1,2.0); }); $$('.validate_image').addEvent('mouseout', function() { window.selectedImage = this.id; myFx.start(1.0,1); }); myFx.set = function(value) { var style = "scale(" + (value) + ")"; $(window.selectedImage).setStyles({ "-webkit-transform": style, "-moz-transform": style, "-o-transform": style, "-ms-transform": style, transform: style }); } }

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  • Codeigniter not returning me to upload form after image upload.

    - by Drew
    I'm still very new to codeigniter. The issue i'm having is that the file uploads fine and it writes to the database without issue but it just doesn't return me to the upload form. Instead it stays in the do_upload and doesn't display anything. Even more bizarrely there is some source code behind the scenes. Can someone tell my what it is i'm doing wrong because I want to be returning to my upload form after submission. Thanks in advance. Below is my code: Controller: function do_upload() { if($this->Upload_model->do_upload()) { $this->load->view('home/upload_form'); }else{ $this->load->view('home/upload_success', $error); } } Model: function do_upload() { $config['upload_path'] = './uploads/'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = '2000'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); return $error; } else { $data = $this->upload->data(); $full_path = 'uploads/' . $data['file_name']; $spam = array( 'image_url' => $full_path, 'url' => $this->input->post('url') ); $id = $this->input->post('id'); $this->db->where('id', $id); $this->db->update('NavItemData', $spam); return true; } } View (called upload_form): <html> <head> <title>Upload Form</title> </head> <body> <?php if(isset($buttons)) : foreach($buttons as $row) : ?> <h2><?php echo $row->image_url; ?></h2> <p><?php echo $row->url; ?></p> <p><?php echo $row->name; ?></p> <p><?php echo anchor("upload/update_nav/$row->id", 'edit'); ?></p> <?php endforeach; ?> <?php endif; ?> </body> </html>

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  • Split string with zsh as in Python

    - by Olivier
    In python: s = '1::3' a = s.split(':') print a[0] # '1' good print a[1] # '' good print a[2] # '3' good How can I achieve the same effect with zsh? The following attempt fails: s="1::3" a=(${(s/:/)s}) echo $a[1] # 1 echo $a[2] # 3 ?? I want an empty string, as in Python

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  • SVN: and bash: How to tell if there are uncommitted changes

    - by fishtoprecords
    I'm trying to wrap a standard sequence of steps in a shell script (linux/bash) and can't seem to figure out how to tell of the execution of svn status returned anything. For example ~/sandbox/$svn status ? pat/foo ~/sandbox/$echo $? 0 If I delete the foo file, then the svn status return nothing, but the echo $? is still 0 I want to not do some steps if there are uncommitted changes. Pointers greatly appreciated.

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  • Running an array of processes

    - by User1
    I have the following array: procs=( 'one a b c' 'two d e f' 'three g h i' ) I try run these processes from a loop (using echo instead of eval so I can debug): for proc in ${procs[@]} do echo $proc done I get: one a b c two d e f three g h i I wanted: one a b c two d e f three g h i What went wrong?

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  • PHP curly string syntax question

    - by zildjohn01
    I'm running PHP 5.3.0. I've found that the curly string syntax only works when the first character of the expression is $. Is there a way to include other types of expressions (function calls, etc)? Trivial example: <?php $x = '05'; echo "{$x}"; // works as expected echo "{intval($x)}"; // hoped for "5", got "{intval(05)}"

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  • basic JSON pulling data help..

    - by Webby
    New to json data and struggling i guess the answer is real easy but been bugging me for the last hour.. Sample data { "data": { "userid": "17", "dates": { "timestame": "1275528578", }, "username": "harino54", } } Ok I can pull userid or username easy enough with echo "$t->userid" or echo "$t->username " but how do I pull data from the brackets within ? in this case timestame? cant seem to figure it out.. any ideas?

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  • unix shell, redirect output but keep on stdin

    - by Mike
    I'd like to have a shell script redirect stdout of a child process in the following manner Redirect stdout to a file Display the output of the process in real time I know I could do something like #!/bin/sh ./child > file cat file But that would not display stdout in real time. For instance, if the child was #!/bin/sh echo 1 sleep 1 echo 2 The user would see "1" and "2" printed at the same time

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  • preg_replace not working for charachter \

    - by krike
    I'm trying to replace \' with ' but it won't work This is the text I want to replace from Using Twitter\'s @Anywhere Service in 6 Steps and this is the code $tutorial = "Using Twitter\'s @Anywhere Service in 6 Steps "; echo $tutorial."<br /><br />"; $tut_title = preg_replace("/\\'/", "'", $tutorial); echo $tut_title;

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  • Can highlight the current menu item, but can't add the class= to style unhighleted menu items

    - by bradpotts
    <?php $activesidebar[$currentsidebar]="id=isactive";?> <div class="span3"> <div class="well sidebar-nav hidden-phone"> <ul class="nav nav-list"> <li class="nav-header" <?php echo $activesidebar[1] ?>>Marketing Services</li> <li><a href="#">Marketing Technology</a></li> <li><a href="#">Generate More Sales</a></li> <li><a href="#">Direct Email Marketing</a></li> <li class="nav-header" <?php echo $activesidebar[2] ?>>Advertising Services</li> <li><a href="../services-advertising-mass-media-network.php">Traditional Medias</a></li> <li><a href="#">Online & Social Medias</a></li> <li><a href="#">Media Planing & Purchasing</a></li> <li class="nav-header" <?php echo $activesidebar[3] ?>>Technology Services</li> <li><a href="#">Managed Websites</a></li> <li><a href="#">Managed Web Servers</a></li> <li><a href="#">Managed Databases</a></li> <li class="nav-header" <?php echo $activesidebar[4] ?>>About Us</li> <li><a href="../aboutus-contactus.php">Contact Us</a></li> </ul> </div> This is added to the current page I want to add this on. <?php $currentsidebar =2; include('module-sidebar-navigation.php');?> I had programmed this menu individually on each page, but to make my website dynamic I used one file and use php includes to load the file. I can get the menu to highlight on the current page assigning an id="isactive", how can I assign id="notactive" to the other 3 menu items that are not active on that page. Is there an else or elseif I have to include?

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  • opening and viewing a file in php

    - by Christian Burgos
    how do i open/view for editing an uploaded file in php? i have tried this but it doesn't open the file. $my_file = 'file.txt'; $handle = fopen($my_file, 'r'); $data = fread($handle,filesize($my_file)); i've also tried this but it wont work. $my_file = 'file.txt'; $handle = fopen($my_file, 'w') or die('Cannot open file: '.$my_file); $data = 'This is the data'; fwrite($handle, $data); what i have in mind is like when you want to view an uploaded resume,documents or any other ms office files like .docx,.xls,.pptx and be able to edit them, save and close the said file. edit: latest tried code... <?php // Connects to your Database include "configdb.php"; //Retrieves data from MySQL $data = mysql_query("SELECT * FROM employees") or die(mysql_error()); //Puts it into an array while($info = mysql_fetch_array( $data )) { //Outputs the image and other data //Echo "<img src=localhost/uploadfile/images".$info['photo'] ."> <br>"; Echo "<b>Name:</b> ".$info['name'] . "<br> "; Echo "<b>Email:</b> ".$info['email'] . " <br>"; Echo "<b>Phone:</b> ".$info['phone'] . " <hr>"; //$file=fopen("uploadfile/images/".$info['photo'],"r+"); $file=fopen("Applications/XAMPP/xamppfiles/htdocs/uploadfile/images/file.odt","r") or exit("unable to open file");; } ?> i am getting the error: Warning: fopen(Applications/XAMPP/xamppfiles/htdocs/uploadfile/images/file.odt): failed to open stream: No such file or directory in /Applications/XAMPP/xamppfiles/htdocs/uploadfile/view.php on line 17 unable to open file the file is in that folder, i don't know it wont find it.

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  • What's the best way/practice to get the extension of a uploaded file in PHP

    - by Roland
    I have a form that allow users to upload files, I however need to get the file extension, which I am able to get, but not sure if I'm using the most effective solution I can get it using the following ways $fileInfo = pathinfo($_FILES['File']['name']); echo $fileInfo['extension']; $ext = end(explode('.',$_FILES['File']['name'])); echo $ext; Which method is the best to use or are there even better solutions that would get the extension?

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  • PHP coding question?

    - by tag
    Does the following code below do the same thing and if so which one is better when coding? And is there a name for when PHP code is missing curly brackets? The PHP code. <?php if (isset($_POST['email'])) { echo $_POST['email']; }?> <?php if (isset($_POST['email'])) echo $_POST['email'];?>

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  • What does Apache need to support both mysqli and PDO?

    - by Nathan Long
    I'm considering changing some PHP code to use PDO for database access instead of mysqli (because the PDO syntax makes more sense to me and is database-agnostic). To do that, I'd need both methods to work while I'm making the changeover. My problem is this: so far, either one or the other method will crash Apache. Right now I'm using XAMPP in Windows XP, and PHP Version 5.2.8. Mysqli works fine, and so does this: $dbc = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password); echo 'Connected to database'; $sql = "SELECT * FROM `employee`"; But this line makes Apache crash: $dbc->query($sql); I don't want to redo my entire Apache or XAMPP installation, but I'd like for PDO to work. So I tried updating libmysql.dll from here, as oddvibes recommended here. That made my simple PDO query work, but then mysqli queries crashed Apache. (I also tried the suggestion after that one, to update php_pdo_mysql.dll and php_pdo.dll, to no effect.) Test Case I created this test script to compare PDO vs mysqli. With the old copy of libmysql.dll, it crashes if $use_pdo is true and doesn't if it's false. With the new copy of libmysql.dll, it's the opposite. if ($use_pdo){ $dbc = new PDO("mysql:host=$hostname;dbname=$dbname", $username, $password); echo 'Connected to database<br />'; $sql = "SELECT * FROM `employee`"; $dbc->query($sql); foreach ($dbc->query($sql) as $row){ echo $row['firstname'] . ' ' . $row['lastname'] . "<br>\n"; } } else { $dbc = @mysqli_connect($hostname, $username, $password, $dbname) OR die('Could not connect to MySQL: ' . mysqli_connect_error()); $sql = "SELECT * FROM `employee`"; $result = @mysqli_query($dbc, $sql) or die(mysqli_error($dbc)); while ($row = mysqli_fetch_array($result,MYSQLI_ASSOC)) { echo $row['firstname'] . ' ' . $row['lastname'] . "<br>\n"; } } What does Apache need in order to support both methods of database query?

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  • Selecting only the first item of an xpath result set in PHP

    - by IkimashoZ
    I am currently achieving the desired outcome with two PHP statements: $thisBlarg = $xmlResource->xpath('//blarg[@ID='.$someBlargID.']'); echo $thisBlarg[0]->name; But, not wanting to settle for second best, I'd really prefer this to be one statement, but PHP doesn't like this: echo $xmlResource->xpath('//blarg[@ID='.$someBlargID.']')[0]->name; And for good reason. But I can't find a way to force an xpath query to return the result directly. Any suggestions?

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  • [bash] checking wget's return value [if]

    - by wwrob
    I'm writing a script to download a bunch of files, and I want it to inform when a particular file doesn't exist. r=`wget -q www.someurl.com` if [ $r -ne 0 ] then echo "Not there" else echo "OK" fi But it gives the following error on execution: ./file: line 2: [: -ne: unary operator expected What's wrong?

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