I have a site with index.
php in the root folder, images in /img , and overview.
php in /content . I have a sidebar.
php file that is included in both index.
php and overview.
php . How should I refer to /img/image.gif if I include a link in each file?
The location of image.gif changes relative to the location of the file that references it. Using /img/image.gif in sidebar.
php will work in index.
php, but it fails for the file located at /content/overview.
php. The only solution that I can see is to either include a seperate sidebar.
php in each subdirectory, or include an /img directory in every sub-directory.
The best suggestion that I can find is to use the <base html tag as suggested here:
Change relative link paths for included content in
PHP
However, in the same link, SamGoody suggests that the <base tag "is no longer properly supported in Internet Explorer, since version 7."
I'd like some insight on the matter before committing to a course of action.
Thanks.
EDIT: I am using the wrong approach below with "../"
Example-
root/index.php:
...
<link rel="stylesheet" type="text/css" href="style.css" />
<title>title</title>
</head>
<body>
<?php include('include/header.
php'); ?>
<?php include('include/menu.
php'); ?>
...
root/include/header.php:
...
<div id="header">
<span class="fl"><img src="img/dun1.png"/></span><span class="fr"><img src="img/dun2.png"/></span>
...
root/content/overview.php:
...
<link rel="stylesheet" type="text/css" href="../style.css" media="screen" />
<title>Overview</title>
</head>
<body>
<?php include('../include/header.
php'); ?>
<?php include('../include/menu.
php'); ?>
...
