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  • Pattern matching for lambda expressions

    - by alphomega
    21 --Primitive recursion constructor 22 pr :: ([Int] -> Int) -> ([Int] -> Int) -> ([Int] -> Int) 23 pr f g = \xs 0 -> f xs 24 pr f g = \xs (y+1) -> g xs y ((pr f g) xs y) I want the function this function creates to act differently on different inputs, so that it can create a recursive function. As expected, the above code doesn't work. How do I do something like pattern matching, but for the function it creates? Thanks

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  • Creating Delegates With Lambda Expressions in F#

    - by Matt H
    Why does... type IntDelegate = delegate of int -> unit type ListHelper = static member ApplyDelegate (l : int list) (d : IntDelegate) = l |> List.iter (fun x -> d.Invoke x) ListHelper.ApplyDelegate [1..10] (fun x -> printfn "%d" x) not compile, when: type IntDelegate = delegate of int -> unit type ListHelper = static member ApplyDelegate (l : int list, d : IntDelegate) = l |> List.iter (fun x -> d.Invoke x) ListHelper.ApplyDelegate ([1..10], (fun x -> printfn "%d" x)) does? The only difference that is that in the second one, ApplyDelegate takes its parameters as a tuple. Error 1 This function takes too many arguments, or is used in a context where a function is not expected

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  • How to get only a filename (not full path) into $1, using the PERL, regular expressions

    - by Scott
    I want to keep only the filenames (not full paths) and add the filename to some bbcode. Here is the HTML to be converted: <a href=/path/to/full/image.jpg rel=prettyPhoto><img rel=prettyPhoto src=/path/to/thumb/image.jpg /></a> Notice I cannot have rel="foo" (no double quotes).. Here is what I have in PERL, to perform the conversion: s/\<a href=(.+?)\ rel=prettyPhoto\>\<img rel=prettyPhoto src=(.+?) \/>\<\/a\>/\[box\]$1\[\/box\]/gi; This converts the HTML to: [box]/path/to/image.jpg[/box] But this is what I want as a result: [box]image.jpg[/box] The HTML must remain the same. So how do I change my PERL so that $1 contains only the filename?

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  • parsing of mathematical expressions

    - by gcc
    (in c90) (linux) input: sqrt(2 - sin(3*A/B)^2.5) + 0.5*(C*~(D) + 3.11 +B) a b /*there are values for a,b,c,d */ c d input: cos(2 - asin(3*A/B)^2.5) +cos(0.5*(C*~(D)) + 3.11 +B) a b /*there are values for a,b,c,d */ c d input: sqrt(2 - sin(3*A/B)^2.5)/(0.5*(C*~(D)) + sin(3.11) +ln(B)) /*max lenght of formula is 250 characters*/ a b /*there are values for a,b,c,d */ c /*each variable with set of floating numbers*/ d As you can see infix formula in the input depends on user. My program will take a formula and n-tuples value. Then it calculate the results for each value of a,b,c and d. If you wonder I am saying ;outcome of program is graph. /sometimes,I think i will take input and store in string. then another idea is arise " I should store formula in the struct" but i don't know how I can construct the code on the base of structure./ really, I don't know way how to store the formula in program code so that I can do my job. can you show me? /* a,b,c,d is letters cos,sin,sqrt,ln is function*/

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  • regular expressions: ignoring certain chars globally

    - by shi kui
    Consider it that '_'s in a number doesn't change that number's value so 1000==1_000==10_00. The Problem: given numbers like 1_244_23 1412_2 1_1111 etc..., how could I decide whether certain number appears in that collection? For example: 1244_23 yes, 11_111 yes, 1412_1 no. How could using regex to solve this? I mean, if I could tell the regex engine just ignore these '_''s when matching then this problem becomes trivial? How could I do so?

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  • Regular Expressions - Match all alphanumeric characters except individual numbers

    - by imaginonic
    I would like to create a RegEx to match only english alphanumeric characters but ignore (or discard) isolated numbers in Ruby (and if possible in JS too). Examples: 1) I would like the following to be matched: 4chan 9gag test91323432 asf5asdfaf35edfdfad afafaffe But not: 92342424 343424 34432 and so on.. The above is exactly what I would want. 2) However, I would be really thankful if someone could also include French letters like: é ë ê (These are just few examples of many) 1) is my priority, it's totally okay if 2) is impossible or difficult to implement. Sorry, my regex skills aren't that great (hence this question!) Thank you.

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  • Only assignment, call, increment, decrement, and new object expressions can be used as a statement : Messagebox

    - by Nuru Salihu
    This what i am trying to achieved if(this.BeginInvoke((Action)(() => MessageBox.Show("Test", MessageBoxButtons.YesNo) == DialogResult.No))) The above gives error. I try seperating the delegate to an outside method like delegate void test(string text); private void SetTest(string text) { if(MessageBox.Show(text,"", MessageBoxButtons.YesNo) == DialogResult.No) } But it breach the very reason why i need the delegate. I found out the first works for me but i don't know how to put it in an if/else statement. Pls any help in a better way i can achieve some thing like below would be appreciated. if(this.BeginInvoke((Action)(() => MessageBox.Show("Test", MessageBoxButtons.YesNo) == DialogResult.No)))

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  • Good starting point to learn regular expressions.

    - by Jeremy Rudd
    I'm good at learning new languages and platforms, though whenever I try to learn Reg Ex I cannot make sense of it. I once even used the Regular Expression Designer to try and put some together. What's a good starting point to understanding what looks like the only rocket-science programming language in the world? Links to articles, books or anything else that could help me get my grounding would be appreciated.

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  • Regular Expressions .NET

    - by Fosa
    I need a regular expression for some arguments that must match on a string. here it is... The string exists out of minimum 8 en maximum 20 characters. These characters of this string may be characters of the alfabet or special chars --With other words..all charachters except from the whitespaces In the complete string there must be atleast 1 number. The string cannot start with a number or an underscore The last 2 characters of the string must be identical, But it doenst matter if those last --identical characters are capital or non-capital (case insensitive) Must match all : +234567899 a_1de*Gg xy1Me*__ !41deF_hij2lMnopq3ss C234567890123$^67800 *5555555 sDF564zer"" !!!!!!!!!4!!!!!!!!!! abcdefghijklmnopq9ss May not match : Cannot be less then 8 or more then 20 chars: a_1+Eff B41def_hIJ2lmnopq3stt Cannot contain a whitespace: A_4 e*gg b41def_Hij2l nopq3ss Cannot start with a number or an underscore: __1+Eff 841DEf_hij2lmnopq3stt cannot end on 2 diffrent characters: a_1+eFg b41DEf_hij2lmnopq3st Cannot be without a number in the string: abCDefghijklmnopqrss abcdef+++dF !!!!!!!!!!!!!!!!!!!! ------------------------------------------------------ This is what I have so far...But I'm really breaking my head on this... If you Don't know the answer completely it's not a problem... I just want to get in the right direction ([^0-9_])(?=.*\d)(\S{8,20})(?i:[\S])\1

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  • Getting dialogue snippets from text using regular expressions

    - by sheldon
    I'm trying to extract snippets of dialogue from a book text. For example, if I have the string "What's the matter with the flag?" inquired Captain MacWhirr. "Seems all right to me." Then I want to extract "What's the matter with the flag?" and "Seem's all right to me.". I found a regular expression to use here, which is "[^"\\]*(\\.[^"\\]*)*". This works great in Eclipse when I'm doing a Ctrl+F find regex on my book .txt file, but when I run the following code: String regex = "\"[^\"\\\\]*(\\\\.[^\"\\\\]*)*\""; String bookText = "\"What's the matter with the flag?\" inquired Captain MacWhirr. \"Seems all right to me.\""; Pattern p = Pattern.compile(regex); Matcher m = p.matcher(bookText); if(m.find()) System.out.println(m.group(1)); The only thing that prints is null. So am I not converting the regex into a Java string properly? Do I need to take into account the fact that Java Strings have a \" for the double quotes?

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  • Can you help with regular expressions in Java?

    - by Matt
    I have a bunch of strings which may of may not have random symbols and numbers in them. Some examples are: contains(reserved[j])){ close(); i++){ letters[20]=word I want to find any character that is NOT a letter, and replace it with a white space, so the above examples look like: contains reserved j close i letters word What is the best way to do this?

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  • mysql query not running correctly from inside the application

    - by Mala
    I am completely stumped. Here is my php (CodeIgniter) code: function mod() { $uid = $this->session->userdata('uid'); $pid = $this->input->post('pid'); if ($this->_verify($uid,$pid)) { $name = $this->input->post('name'); $price = $this->input->post('price'); $curr = $this->input->post('curr'); $url = $this->input->post('url'); $query = $this->db->query("UPDATE items SET name=".$this->db->escape($name).", price=".$this->db->escape($price).", currency=".$this->db->escape($curr),", url=".$this->db->escape($url)." WHERE pid=".$this->db->escape($pid)." LIMIT 1"); } header('location: '.$this->session->userdata('current')); } The purpose of this code is to modify the properties (name, price, currency, url) of a row in the 'items' table (priary key is pid). However, for some reason, allowing this function to run once modifies the name, price, currency and url of ALL entries in the table, regardless of their pid and of the LIMIT 1 thing I tacked on the end of the query. It's as if the last line of the query is being completely ignored. As if this wasn't strance enough, I replaced "$query = $this->db->query(" with an "echo" to see the SQL query being run, and it outputs a query much like I would expect: UPDATE items SET name='newname', price='newprice', currency='newcurrency', url='newurl' WHERE pid='10' LIMIT 1 Copy-pasting this into a MySQL window acts exactly as I want: it modifies the row with the selected pid. What is going on here???

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  • Mixing expressions and expression language (<%= %> inside of c:if)

    - by Jack
    I need to access some constants in my jsp, and sadly the EL does not offer any functionality for it. There are some options like the unstandard tag library, but I'd like to keep it a bit more standard. I tried: <%@ page import = "com.jackdane.Constants"%> <c:if test="${object.display == '<%=com.jackdane.Constants.YES %>}'"> //some display logic </c:if> But that doesn't appear to do the trick. It's been a while since I've used an expression so I might have made an error. Any input is appreciated. Edit: To clarify, the constants class is not in my control. It's inside a jar file that I recieved. It contains no getters/setters. Just private static final Strings.

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  • SSIS Expressions - EvaluateAsExpression Problem

    - by Randy Minder
    In a Data Flow, I have an Derived Column task. In the expression for one of the columns, I have the following expression: [siteid] == "100" ? "1101" : [siteid] == "110" ? "1001" : [siteid] == "120" ? "2101" : [siteid] == "140" ? "1102" : [siteid] == "210" ? "2001" : [siteid] == "310" ? "3001" : [siteid] This works just fine. However, I intend to reuse this in at least a dozen other places so I want to store this to a variable and use the variable in the Derived Column instead of the hard-coded expression. When I attempt to create a variable, using the expression above, I get a syntax error saying 'siteid' is not defined. I guess this makes sense because it isn't. But how can I get this the expression to work by using a variable? It seems like I need some sort of way to tell it that 'siteid' will be the column containing the data I want to apply the expression to.

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  • Regular expressions in java

    - by rookie
    String s= "(See <a href=\"/wiki/Grass_fed_beef\" title=\"Grass fed beef\" " + "class=\"mw-redirect\">grass fed beef.) They have been used for " + "<a href=\"/wiki/Paper\" title=\"Paper\">paper-making since " + "2400 BC or before."; In the string above I have inter-mixed html with text. Well the requirement is that the output looks like:- They have been used for paper-making since 2400 BC or before. Could some one help me with a generic regular expression that would produce the desired output from the given input? Thanks in advance!

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  • Assistance with regular expressions in Python

    - by da5id
    I am still learning REGEX, and I've run into an issue ... I am trying to separate a string that is composed of a mixture of letters and numbers that are in decimal format: AB0.500CD1.05EF2.29 Into something like this: list1 = AB,CD,EF list2 = 0.500,1.05,2.29 A complication to all this is that I also have strings that look like this: AB1CD2EF3 Which I'd also like to separate into this: list1 = AB,CD,EF list2 = 1,2,3 A previous inquiry yielded the following snippet, import re pattern = re.compile(r'([a-zA-Z]+)([0-9]+)') for (letters, numbers) in re.findall(pattern,cmpnd): print numbers print letters This example works fine for strings of the 2nd kind, but only "finds" the leading digit in the numbers that contain decimal places in the strings of the first kind. I've attempted an approach using the following line: pattern = re.compile(r'([a-zA-Z]+)([0-9]+(\.[0-9]))') But this results in an error: "ValueError: too many values to unpack" Thanks for any and all assistance!

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  • python regular expressions, how to extract longest of overlapping groups

    - by xulochavez
    Hi How can I extract the longest of groups which start the same way For example, from a given string, I want to extract the longest match to either CS or CSI. I tried this "(CS|CSI).*" and it it will return CS rather than CSI even if CSI is available. If I do "(CSI|CS).*" then I do get CSI if it's a match, so I gues the solution is to always place the shorter of the overlaping groups after the longer one. Is there a clearer way to express this with re's? somehow it feels confusing that the result depends on the order you link the groups.

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  • Google calendar query returns at most 25 entries

    - by Dean Hill
    I'm trying to delete all calendar entries from today forward. I run a query then call getEntries() on the query result. getEntries() always returns 25 entries (or less if there are fewer than 25 entries on the calendar). Why aren't all the entries returned? I'm expecting about 80 entries. As a test, I tried running the query, deleting the 25 entries returned, running the query again, deleting again, etc. This works, but there must be a better way. Below is the Java code that only runs the query once. CalendarQuery myQuery = new CalendarQuery(feedUrl); DateFormat dfGoogle = new SimpleDateFormat("yyyy-MM-dd'T00:00:00'"); Date dt = Calendar.getInstance().getTime(); myQuery.setMinimumStartTime(DateTime.parseDateTime(dfGoogle.format(dt))); // Make the end time far into the future so we delete everything myQuery.setMaximumStartTime(DateTime.parseDateTime("2099-12-31T23:59:59")); // Execute the query and get the response CalendarEventFeed resultFeed = service.query(myQuery, CalendarEventFeed.class); // !!! This returns 25 (or less if there are fewer than 25 entries on the calendar) !!! int test = resultFeed.getEntries().size(); // Delete all the entries returned by the query for (int j = 0; j < resultFeed.getEntries().size(); j++) { CalendarEventEntry entry = resultFeed.getEntries().get(j); entry.delete(); } PS: I've looked at the Data API Developer's Guide and the Google Data API Javadoc. These sites are okay, but not great. Does anyone know of additional Google API documentation?

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  • Parsing Range Expressions

    - by sameer karjatkar
    I have a string (R(46 - 9900)) AND ( NOT (R(48 - 9900))) where R denotes Range . If you evaluate the expression it results in R(46-47) , considering the logical operators (AND,NOT). I have a requirement where I need to parse such a string and evaluate it to a correct result . I have to use C++ as a programming tool to achieve this result . Can anyone suggest a few guide lines as to how do I proceed on this ?

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