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  • How do i make divs go into another row when full?

    - by acidzombie24
    My code is something like the below. When theres 3 images everything is fine once theres 4 it gets full and moves the entire div.top into another row. How do i make the div inside top just start a new row instead? I tried writing .top width=500px but once it hits or passes it instead the images inside are squeeze together instead of each being 150x150. I tried max-width on top instead and in opera and chrome i see the border of top as 500width but the images continue to render pass it. (i have a firefox problem with my div so the width looks fixed to something else). So how do i make these divs go into another row? and not try to squeeze together <div class="top"> <div><a href><img/></a></div> <div><a href><img/></a></div> <div><a href><img/></a></div> </div>

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  • Jqplot - How to have vertical lines and make xaxis go up in plotted values?

    - by Beginner
    I have plotted a line graph using jqplot. What i would like is vertical lines and to start from 3 and go up in the plotted values along the bottom. so 3, 6, 9, 12 , 15, 29, 36 Also a dash marker along the left. This is what i have at the moment: $(document).ready(function(){ $.jqplot('chart2', [[[3, @(Model.LearnerWeek[0])], [6, @(Model.LearnerWeek[1])], [9, @(Model.LearnerWeek[2])], [12, @(Model.LearnerWeek[3])], [15, @(Model.LearnerWeek[4])], [29, @(Model.LearnerWeek[5])], [36, @(Model.LearnerWeek[6])]], [[3, @(Model.ManagerWeek[0])], [6, @(Model.ManagerWeek[1])], [9, @(Model.ManagerWeek[2])], [12, @(Model.ManagerWeek[3])], [15, @(Model.ManagerWeek[4])], [29, @(Model.ManagerWeek[5])], [36, @(Model.ManagerWeek[6])]]], { axes: { yaxis: { tickOptions: { show: false}, min: 0, max: 100, label: 'Participation Rate', labelRenderer: $.jqplot.CanvasAxisLabelRenderer }, xaxis: { min: 3, max: 36, label: 'Week', tickOptions: { formatString: '%d' } } }, seriesDefaults: { showMarker: false , rendererOptions: { diameter: undefined, // diameter of pie, auto computed by default. padding: 10, // padding between pie and neighboring legend or plot margin. fill: true, // render solid (filled) slices. shadowOffset: 2, // offset of the shadow from the chart. shadowDepth: 15, // Number of strokes to make when drawing shadow. Each stroke // offset by shadowOffset from the last. shadowAlpha: 1 // Opacity of the shadow } }, seriesColors: ['#3591cf', '#ef4058', '#73C774', '#C7754C', '#17BDB8'] }); }); I have played around with render options and xasis but cant seem to work it out

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  • Where does the delete control go in my Cocoa user interface?

    - by Graham Lee
    Hi, I have a Cocoa application managing a collection of objects. The collection is presented in an NSCollectionView, with a "new object" button nearby so users can add to the collection. Of course, I know that having a "delete object" button next to that button would be dangerous, because people might accidentally knock it when they mean to create something. I don't like having "are you sure you want to..." dialogues, so I dispensed with the "delete object". There's a menu item under Edit for removing an object, and you can hit Cmd-backspace to do the same. The app supports undoing delete actions. Now I'm getting support emails ranging from "does it have to be so hard to delete things" to "why can't I delete objects?". That suggests I've made it a bit too hard, so what's the happy middle ground? I see applications from Apple that do it my way, or with the add/remove buttons next to each other, but I hate that latter option. Is there another good (and preferably common) convention for delete controls? I thought about an action menu but I don't think I have any other actions that would go in it, rendering the menu a bit thin.

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  • What is the best way to go about grouping rows by the same timestamp?

    - by Luke
    Hello all. I am looking for some advice. I have rows of data in the database that i want to group together. There is a timestamp involved. That column is called date. What is the best way to go about grouping rows by the same timestamp. EDITED..... <? $result = mysql_query("SELECT * FROM ".TBL_FIXTURES." ORDER BY date"); $current_week = null; while ($row = mysql_fetch_assoc($result)) { if ($row['date'] != $current_week) { $current_week = $row['date']; echo 'Week ' . $current_week .': '; } echo $row['home_user']; echo $row['home_team']; echo $row['away_user']; echo $row['away_team']; } ?> I have this code. What i am trying to do is organise each round of fixtures in a row with a title Week 1 - date. I want Week 1 and the date and all fixtures with that date displayed. Then move onto week 2 and the date and all fixtures again. This should be done for every fixture in the database, so if there are 6 rounds of fixtures, there will be 6 dates and therefore 6 blocks of fixtures.. Please help, thanks

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  • Where does authentication and loader go in Zend Framework?

    - by Joel
    Hi guys, Still trying to learn the basics of MVC. I'm making use of Zend_Loader for Google Calendar feed. What file would this information go in? The .phtml view? // load library Zend_Loader::loadClass('Zend_Gdata'); Zend_Loader::loadClass('Zend_Gdata_ClientLogin'); Zend_Loader::loadClass('Zend_Gdata_Calendar'); Zend_Loader::loadClass('Zend_Http_Client'); // create authenticated HTTP client for Calendar service $gcal = Zend_Gdata_Calendar::AUTH_SERVICE_NAME; $user = "xxxxxxxxxxxx"; $pass = "xxxxxxxxxxxx"; $client = Zend_Gdata_ClientLogin::getHttpClient($user, $pass, $gcal); $gcal = new Zend_Gdata_Calendar($client); $query = $gcal->newEventQuery(); $query->setUser('xxxxxxxxxxxx'); $secondary=true; $query->setVisibility('private'); $query->setProjection('basic'); $query->setOrderby('starttime'); $query->setSortOrder('ascending'); //$query->setFutureevents('true'); $startDate=date('Y-m-d h:i:s'); $endDate="2015-12-31"; $query->setStartMin($startDate); $query->setStartMax($endDate); $query->setMaxResults(30); try { $feed = $gcal->getCalendarEventFeed($query); } catch (Zend_Gdata_App_Exception $e) { echo "Error: " . $e->getResponse(); } Thanks!

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  • SQL SERVER – Update Statistics are Sampled By Default

    - by pinaldave
    After reading my earlier post SQL SERVER – Create Primary Key with Specific Name when Creating Table on Statistics, I have received another question by a blog reader. The question is as follows: Question: Are the statistics sampled by default? Answer: Yes. The sampling rate can be specified by the user and it can be anywhere between a very low value to 100%. Let us do a small experiment to verify if the auto update on statistics is left on. Also, let’s examine a very large table that is created and statistics by default- whether the statistics are sampled or not. USE [AdventureWorks] GO -- Create Table CREATE TABLE [dbo].[StatsTest]( [ID] [int] IDENTITY(1,1) NOT NULL, [FirstName] [varchar](100) NULL, [LastName] [varchar](100) NULL, [City] [varchar](100) NULL, CONSTRAINT [PK_StatsTest] PRIMARY KEY CLUSTERED ([ID] ASC) ) ON [PRIMARY] GO -- Insert 1 Million Rows INSERT INTO [dbo].[StatsTest] (FirstName,LastName,City) SELECT TOP 1000000 'Bob', CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 1 THEN 'New York' WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 5 THEN 'San Marino' WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 3 THEN 'Los Angeles' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Update the statistics UPDATE STATISTICS [dbo].[StatsTest] GO -- Shows the statistics DBCC SHOW_STATISTICS ("StatsTest"PK_StatsTest) GO -- Clean up DROP TABLE [dbo].[StatsTest] GO Now let us observe the result of the DBCC SHOW_STATISTICS. The result shows that Resultset is for sure sampling for a large dataset. The percentage of sampling is based on data distribution as well as the kind of data in the table. Before dropping the table, let us check first the size of the table. The size of the table is 35 MB. Now, let us run the above code with lesser number of the rows. USE [AdventureWorks] GO -- Create Table CREATE TABLE [dbo].[StatsTest]( [ID] [int] IDENTITY(1,1) NOT NULL, [FirstName] [varchar](100) NULL, [LastName] [varchar](100) NULL, [City] [varchar](100) NULL, CONSTRAINT [PK_StatsTest] PRIMARY KEY CLUSTERED ([ID] ASC) ) ON [PRIMARY] GO -- Insert 1 Hundred Thousand Rows INSERT INTO [dbo].[StatsTest] (FirstName,LastName,City) SELECT TOP 100000 'Bob', CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%2 = 1 THEN 'Smith' ELSE 'Brown' END, CASE WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 1 THEN 'New York' WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 5 THEN 'San Marino' WHEN ROW_NUMBER() OVER (ORDER BY a.name)%10 = 3 THEN 'Los Angeles' ELSE 'Houston' END FROM sys.all_objects a CROSS JOIN sys.all_objects b GO -- Update the statistics UPDATE STATISTICS [dbo].[StatsTest] GO -- Shows the statistics DBCC SHOW_STATISTICS ("StatsTest"PK_StatsTest) GO -- Clean up DROP TABLE [dbo].[StatsTest] GO You can see that Rows Sampled is just the same as Rows of the table. In this case, the sample rate is 100%. Before dropping the table, let us also check the size of the table. The size of the table is less than 4 MB. Let us compare the Result set just for a valid reference. Test 1: Total Rows: 1000000, Rows Sampled: 255420, Size of the Table: 35.516 MB Test 2: Total Rows: 100000, Rows Sampled: 100000, Size of the Table: 3.555 MB The reason behind the sample in the Test1 is that the data space is larger than 8 MB, and therefore it uses more than 1024 data pages. If the data space is smaller than 8 MB and uses less than 1024 data pages, then the sampling does not happen. Sampling aids in reducing excessive data scan; however, sometimes it reduces the accuracy of the data as well. Please note that this is just a sample test and there is no way it can be claimed as a benchmark test. The result can be dissimilar on different machines. There are lots of other information can be included when talking about this subject. I will write detail post covering all the subject very soon. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Index, SQL Optimization, SQL Performance, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: SQL Statistics

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  • SQL SERVER – Merge Operations – Insert, Update, Delete in Single Execution

    - by pinaldave
    This blog post is written in response to T-SQL Tuesday hosted by Jorge Segarra (aka SQLChicken). I have been very active using these Merge operations in my development. However, I have found out from my consultancy work and friends that these amazing operations are not utilized by them most of the time. Here is my attempt to bring the necessity of using the Merge Operation to surface one more time. MERGE is a new feature that provides an efficient way to do multiple DML operations. In earlier versions of SQL Server, we had to write separate statements to INSERT, UPDATE, or DELETE data based on certain conditions; however, at present, by using the MERGE statement, we can include the logic of such data changes in one statement that even checks when the data is matched and then just update it, and similarly, when the data is unmatched, it is inserted. One of the most important advantages of MERGE statement is that the entire data are read and processed only once. In earlier versions, three different statements had to be written to process three different activities (INSERT, UPDATE or DELETE); however, by using MERGE statement, all the update activities can be done in one pass of database table. I have written about these Merge Operations earlier in my blog post over here SQL SERVER – 2008 – Introduction to Merge Statement – One Statement for INSERT, UPDATE, DELETE. I was asked by one of the readers that how do we know that this operator was doing everything in single pass and was not calling this Merge Operator multiple times. Let us run the same example which I have used earlier; I am listing the same here again for convenience. --Let’s create Student Details and StudentTotalMarks and inserted some records. USE tempdb GO CREATE TABLE StudentDetails ( StudentID INTEGER PRIMARY KEY, StudentName VARCHAR(15) ) GO INSERT INTO StudentDetails VALUES(1,'SMITH') INSERT INTO StudentDetails VALUES(2,'ALLEN') INSERT INTO StudentDetails VALUES(3,'JONES') INSERT INTO StudentDetails VALUES(4,'MARTIN') INSERT INTO StudentDetails VALUES(5,'JAMES') GO CREATE TABLE StudentTotalMarks ( StudentID INTEGER REFERENCES StudentDetails, StudentMarks INTEGER ) GO INSERT INTO StudentTotalMarks VALUES(1,230) INSERT INTO StudentTotalMarks VALUES(2,255) INSERT INTO StudentTotalMarks VALUES(3,200) GO -- Select from Table SELECT * FROM StudentDetails GO SELECT * FROM StudentTotalMarks GO -- Merge Statement MERGE StudentTotalMarks AS stm USING (SELECT StudentID,StudentName FROM StudentDetails) AS sd ON stm.StudentID = sd.StudentID WHEN MATCHED AND stm.StudentMarks > 250 THEN DELETE WHEN MATCHED THEN UPDATE SET stm.StudentMarks = stm.StudentMarks + 25 WHEN NOT MATCHED THEN INSERT(StudentID,StudentMarks) VALUES(sd.StudentID,25); GO -- Select from Table SELECT * FROM StudentDetails GO SELECT * FROM StudentTotalMarks GO -- Clean up DROP TABLE StudentDetails GO DROP TABLE StudentTotalMarks GO The Merge Join performs very well and the following result is obtained. Let us check the execution plan for the merge operator. You can click on following image to enlarge it. Let us evaluate the execution plan for the Table Merge Operator only. We can clearly see that the Number of Executions property suggests value 1. Which is quite clear that in a single PASS, the Merge Operation completes the operations of Insert, Update and Delete. I strongly suggest you all to use this operation, if possible, in your development. I have seen this operation implemented in many data warehousing applications. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Joins, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: Merge

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  • SQL SERVER – Updating Data in A Columnstore Index

    - by pinaldave
    So far I have written two articles on Columnstore Indexes, and both of them got very interesting readership. In fact, just recently I got a query on my previous article on Columnstore Index. Read the following two articles to get familiar with the Columnstore Index. They will give you a reference to the question which was asked by a certain reader: SQL SERVER – Fundamentals of Columnstore Index SQL SERVER – How to Ignore Columnstore Index Usage in Query Here is the reader’s question: ” When I tried to update my table after creating the Columnstore index, it gives me an error. What should I do?” When the Columnstore index is created on the table, the table becomes Read-Only table and it does not let any insert/update/delete on the table. The basic understanding is that Columnstore Index will be created on the table that is very huge and holds lots of data. If a table is small enough, there is no need to create a Columnstore index. The regular index should just help it. The reason why Columnstore index was needed is because the table was so big that retrieving the data was taking a really, really long time. Now, updating such a huge table is always a challenge by itself. If the Columnstore Index is created on the table, and the table needs to be updated, you need to know that there are various ways to update it. The easiest way is to disable the Index and enable it. Consider the following code: USE AdventureWorks GO -- Create New Table CREATE TABLE [dbo].[MySalesOrderDetail]( [SalesOrderID] [int] NOT NULL, [SalesOrderDetailID] [int] NOT NULL, [CarrierTrackingNumber] [nvarchar](25) NULL, [OrderQty] [smallint] NOT NULL, [ProductID] [int] NOT NULL, [SpecialOfferID] [int] NOT NULL, [UnitPrice] [money] NOT NULL, [UnitPriceDiscount] [money] NOT NULL, [LineTotal] [numeric](38, 6) NOT NULL, [rowguid] [uniqueidentifier] NOT NULL, [ModifiedDate] [datetime] NOT NULL ) ON [PRIMARY] GO -- Create clustered index CREATE CLUSTERED INDEX [CL_MySalesOrderDetail] ON [dbo].[MySalesOrderDetail] ( [SalesOrderDetailID]) GO -- Create Sample Data Table -- WARNING: This Query may run upto 2-10 minutes based on your systems resources INSERT INTO [dbo].[MySalesOrderDetail] SELECT S1.* FROM Sales.SalesOrderDetail S1 GO 100 -- Create ColumnStore Index CREATE NONCLUSTERED COLUMNSTORE INDEX [IX_MySalesOrderDetail_ColumnStore] ON [MySalesOrderDetail] (UnitPrice, OrderQty, ProductID) GO -- Attempt to Update the table UPDATE [dbo].[MySalesOrderDetail] SET OrderQty = OrderQty +1 WHERE [SalesOrderID] = 43659 GO /* It will throw following error Msg 35330, Level 15, State 1, Line 2 UPDATE statement failed because data cannot be updated in a table with a columnstore index. Consider disabling the columnstore index before issuing the UPDATE statement, then rebuilding the columnstore index after UPDATE is complete. */ A similar error also shows up for Insert/Delete function. Here is the workaround. Disable the Columnstore Index and performance update, enable the Columnstore Index: -- Disable the Columnstore Index ALTER INDEX [IX_MySalesOrderDetail_ColumnStore] ON [dbo].[MySalesOrderDetail] DISABLE GO -- Attempt to Update the table UPDATE [dbo].[MySalesOrderDetail] SET OrderQty = OrderQty +1 WHERE [SalesOrderID] = 43659 GO -- Rebuild the Columnstore Index ALTER INDEX [IX_MySalesOrderDetail_ColumnStore] ON [dbo].[MySalesOrderDetail] REBUILD GO This time it will not throw an error while the update of the table goes successfully. Let us do a cleanup of our tables using this code: -- Cleanup DROP INDEX [IX_MySalesOrderDetail_ColumnStore] ON [dbo].[MySalesOrderDetail] GO TRUNCATE TABLE dbo.MySalesOrderDetail GO DROP TABLE dbo.MySalesOrderDetail GO In the next post we will see how we can use Partition to update the Columnstore Index. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Index, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Editing files without race conditions?

    - by user2569445
    I have a CSV file that needs to be edited by multiple processes at the same time. My question is, how can I do this without introducing race conditions? It's easy to write to the end of the file without race conditions by open(2)ing it in "a" (O_APPEND) mode and simply write to it. Things get more difficult when removing lines from the file. The easiest solution is to read the file into memory, make changes to it, and overwrite it back to the file. If another process writes to it after it is in memory, however, that new data will be lost upon overwriting. To further complicate matters, my platform does not support POSIX record locks, checking for file existence is a race condition waiting to happen, rename(2) replaces the destination file if it exists instead of failing, and editing files in-place leaves empty bytes in it unless the remaining bytes are shifted towards the beginning of the file. My idea for removing a line is this (in pseudocode): filename = "/home/user/somefile"; file = open(filename, "r"); tmp = open(filename+".tmp", "ax") || die("could not create tmp file"); //"a" is O_APPEND, "x" is O_EXCL|O_CREAT while(write(tmp, read(file)); //copy the $file to $file+".new" close(file); //edit tmp file unlink(filename) || die("could not unlink file"); file = open(filename, "wx") || die("another process must have written to the file after we copied it."); //"w" is overwrite, "x" is force file creation while(write(file, read(tmp))); //copy ".tmp" back to the original file unlink(filename+".tmp") || die("could not unlink tmp file"); Or would I be better off with a simple lock file? Appender process: lock = open(filename+".lock", "wx") || die("could not lock file"); file = open(filename, "a"); write(file, "stuff"); close(file); close(lock); unlink(filename+".lock"); Editor process: lock = open(filename+".lock", "wx") || die("could not lock file"); file = open(filename, "rw"); while(contents += read(file)); //edit "contents" write(file, contents); close(file); close(lock); unlink(filename+".lock"); Both of these rely on an additional file that will be left over if a process terminates before unlinking it, causing other processes to refuse to write to the original file. In my opinion, these problems are brought on by the fact that the OS allows multiple writable file descriptors to be opened on the same file at the same time, instead of failing if a writable file descriptor is already open. It seems that O_CREAT|O_EXCL is the closest thing to a real solution for preventing filesystem race conditions, aside from POSIX record locks. Another possible solution is to separate the file into multiple files and directories, so that more granular control can be gained over components (lines, fields) of the file using O_CREAT|O_EXCL. For example, "file/$id/$field" would contain the value of column $field of the line $id. It wouldn't be a CSV file anymore, but it might just work. Yes, I know I should be using a database for this as databases are built to handle these types of problems, but the program is relatively simple and I was hoping to avoid the overhead. So, would any of these patterns work? Is there a better way? Any insight into these kinds of problems would be appreciated.

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  • How would you go about tackling this problem? [SOLVED in C++]

    - by incrediman
    Intro: EDIT: See solution at the bottom of this question (c++) I have a programming contest coming up in about half a week, and I've been prepping :) I found a bunch of questions from this canadian competition, they're great practice: http://cemc.math.uwaterloo.ca/contests/computing/2009/stage2/day1.pdf I'm looking at problem B ("Dinner"). Any idea where to start? I can't really think of anything besides the naive approach (ie. trying all permutations) which would take too long to be a valid answer. Btw, the language there says c++ and pascal I think, but i don't care what language you use - I mean really all I want is a hint as to the direction I should proceed in, and perhpas a short explanation to go along with it. It feels like I'm missing something obvious... Of course extended speculation is more than welcome, but I just wanted to clarify that I'm not looking for a full solution here :) Short version of the question: You have a binary string N of length 1-100 (in the question they use H's and G's instead of one's and 0's). You must remove all of the digits from it, in the least number of steps possible. In each step you may remove any number of adjacent digits so long as they are the same. That is, in each step you can remove any number of adjacent G's, or any number of adjacent H's, but you can't remove H's and G's in one step. Example: HHHGHHGHH Solution to the example: 1. HHGGHH (remove middle Hs) 2. HHHH (remove middle Gs) 3. Done (remove Hs) -->Would return '3' as the answer. Note that there can also be a limit placed on how large adjacent groups have to be when you remove them. For example it might say '2', and then you can't remove single digits (you'd have to remove pairs or larger groups at a time). Solution I took Mark Harrison's main algorithm, and Paradigm's grouping idea and used them to create the solution below. You can try it out on the official test cases if you want. //B.cpp //include debug messages? #define DEBUG false #include <iostream> #include <stdio.h> #include <vector> using namespace std; #define FOR(i,n) for (int i=0;i<n;i++) #define FROM(i,s,n) for (int i=s;i<n;i++) #define H 'H' #define G 'G' class String{ public: int num; char type; String(){ type=H; num=0; } String(char type){ this->type=type; num=1; } }; //n is the number of bits originally in the line //k is the minimum number of people you can remove at a time //moves is the counter used to determine how many moves we've made so far int n, k, moves; int main(){ /*Input from File*/ scanf("%d %d",&n,&k); char * buffer = new char[200]; scanf("%s",buffer); /*Process input into a vector*/ //the 'line' is a vector of 'String's (essentially contigious groups of identical 'bits') vector<String> line; line.push_back(String()); FOR(i,n){ //if the last String is of the correct type, simply increment its count if (line.back().type==buffer[i]) line.back().num++; //if the last String is of the wrong type but has a 0 count, correct its type and set its count to 1 else if (line.back().num==0){ line.back().type=buffer[i]; line.back().num=1; } //otherwise this is the beginning of a new group, so create the new group at the back with the correct type, and a count of 1 else{ line.push_back(String(buffer[i])); } } /*Geedily remove groups until there are at most two groups left*/ moves=0; int I;//the position of the best group to remove int bestNum;//the size of the newly connected group the removal of group I will create while (line.size()>2){ /*START DEBUG*/ if (DEBUG){ cout<<"\n"<<moves<<"\n----\n"; FOR(i,line.size()) printf("%d %c \n",line[i].num,line[i].type); cout<<"----\n"; } /*END DEBUG*/ I=1; bestNum=-1; FROM(i,1,line.size()-1){ if (line[i-1].num+line[i+1].num>bestNum && line[i].num>=k){ bestNum=line[i-1].num+line[i+1].num; I=i; } } //remove the chosen group, thus merging the two adjacent groups line[I-1].num+=line[I+1].num; line.erase(line.begin()+I);line.erase(line.begin()+I); moves++; } /*START DEBUG*/ if (DEBUG){ cout<<"\n"<<moves<<"\n----\n"; FOR(i,line.size()) printf("%d %c \n",line[i].num,line[i].type); cout<<"----\n"; cout<<"\n\nFinal Answer: "; } /*END DEBUG*/ /*Attempt the removal of the last two groups, and output the final result*/ if (line.size()==2 && line[0].num>=k && line[1].num>=k) cout<<moves+2;//success else if (line.size()==1 && line[0].num>=k) cout<<moves+1;//success else cout<<-1;//not everyone could dine. /*START DEBUG*/ if (DEBUG){ cout<<" moves."; } /*END DEBUG*/ }

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  • Automatically release resources RAII-style in Perl

    - by Philip Potter
    Say I have a resource (e.g. a filehandle or network socket) which has to be freed: open my $fh, "<", "filename" or die "Couldn't open filename: $!"; process($fh); close $fh or die "Couldn't close filename: $!"; Suppose that process might die. Then the code block exits early, and $fh doesn't get closed. I could explicitly check for errors: open my $fh, "<", "filename" or die "Couldn't open filename: $!"; eval {process($fh)}; my $saved_error = $@; close $fh or die "Couldn't close filename: $!"; die $saved_error if $saved_error; but this kind of code is notoriously difficult to get right, and only gets more complicated when you add more resources. In C++ I would use RAII to create an object which owns the resource, and whose destructor would free it. That way, I don't have to remember to free the resource, and resource cleanup happens correctly as soon as the RAII object goes out of scope - even if an exception is thrown. Unfortunately in Perl a DESTROY method is unsuitable for this purpose as there are no guarantees for when it will be called. Is there a Perlish way to ensure resources are automatically freed like this even in the presence of exceptions? Or is explicit error checking the only option?

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  • PHP MySQL database problem

    - by Jordan Pagaduan
    Code 1: <?php class dbConnect { var $dbHost = 'localhost', $dbUser = 'root', $dbPass = '', $dbName = 'input_oop', $dbTable = 'users'; function __construct() { $dbc = mysql_connect($this->dbHost,$this->dbUser,$this->dbPass) or die ("Cannot connect to MySQL : " . mysql_error()); mysql_select_db($this->dbName) or die ("Database not Found : " . mysql_error()); } } class User extends dbConnect { var $name; function userInput($q) { $sql = "INSERT INTO $this->dbTable set name = '".$q."'"; mysql_query($sql) or die (mysql_error()); } } ?> Code 2: <?php $q = $_GET['q']; $dbc=mysql_connect("localhost","root","") or die (mysql_error()); mysql_select_db('input_oop') or die (mysql_error()); $sql = "INSERT INTO users set name = '".$q."'"; mysql_query($sql) or die (mysql_error()); ?> My Code 1 save in my database: Saving Multiple! My Code 2 save in my database: What is wrong with my code 1?

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  • How can I automatically release resources RAII-style in Perl?

    - by Philip Potter
    Say I have a resource (e.g. a filehandle or network socket) which has to be freed: open my $fh, "<", "filename" or die "Couldn't open filename: $!"; process($fh); close $fh or die "Couldn't close filename: $!"; Suppose that process might die. Then the code block exits early, and $fh doesn't get closed. I could explicitly check for errors: open my $fh, "<", "filename" or die "Couldn't open filename: $!"; eval {process($fh)}; my $saved_error = $@; close $fh or die "Couldn't close filename: $!"; die $saved_error if $saved_error; but this kind of code is notoriously difficult to get right, and only gets more complicated when you add more resources. In C++ I would use RAII to create an object which owns the resource, and whose destructor would free it. That way, I don't have to remember to free the resource, and resource cleanup happens correctly as soon as the RAII object goes out of scope - even if an exception is thrown. Unfortunately in Perl a DESTROY method is unsuitable for this purpose as there are no guarantees for when it will be called. Is there a Perlish way to ensure resources are automatically freed like this even in the presence of exceptions? Or is explicit error checking the only option?

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  • Addresses stored in SQL server have many small variations(errors)

    - by MAW74656
    I have a table in my database which stores packing slips and their information. I'm trying to query that table and get each unique address. I've come close, but I still have many near misses and I'm looking for a way to exclude these near duplicates from my select. Sample Data CompanyCode CompanyName Addr1 City State Zip 10033 UNITED DIE CUTTING & FINISHIN 3610 HAMILTON AVE CLEVELAND Ohio 44114 10033 UNITED DIE CUTTING & FINISHING 3610 HAMILTON AVE CLEVELAND Ohio 44114 10033 UNITED DIE CUTTING & FINISHING 3610 HAMILTON AVE. CLEVELAND Ohio 44114 10033 UNITED DIE CUTTING & FINISHING 3610 HAMILTON AVENUE CLEVELAND Ohio 44114 10033 UNITED DIECUTTING & FINISHING 3610 HAMILTON AVE CLEVELAND Ohio 44144 10033 UNITED FINISHING 3610 HAMILTON AVE CLEVLAND Ohio 44114 10033 UNITED FINISHING & DIE CUTTING 3610 HAMILTON AVE CLEVELAND Ohio 44114 And all I want is 1 record. Is there some way I can get the "Average" record? Meaning, if most of the records say CLEVELAND instead of CLEVLAND, I want my 1 record to say CLEVELAND. Is there any way to par this data down to what I'm looking for? Desired Output CompanyCode CompanyName Addr1 City State Zip 10033 UNITED DIE CUTTING & FINISHING 3610 HAMILTON AVE CLEVELAND Ohio 44114

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  • Cannot exit in CodeIgniter constructor

    - by gzg
    I'm basically trying a session control. If the user is logged in, it's ok to move on. But if he's not logged in, then it will show a log-in screen and then die. However, when I use die or exit in the constructor, it does not show the log-in screen; it immediately dies. The code is as following: private $username = null; private $mongoid = null; private $neoid = null; public function __construct(){ parent::__construct(); // session to global $this->username = $this->session->userdata( 'username'); $this->mongoid = $this->session->userdata( 'mongoid'); $this->neoid = $this->session->userdata( 'neoid'); // check if user is logged in if( $this->username == "" || empty( $this->username)){ $this->load->view( 'access/login'); die; } } It shows the log-in page if die is not written there, but with die, it does not show. Why do I want to use die? Because if I don't use, it moves on the index function and I don't want it to execute index function if the user is not logged in. What is wrong here? What should I use to stop executing?

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  • how do I copy value from one table and inserted to another in the same database??

    - by mathew
    I am having a tough time to do this... I have created two table say table-1 and table-2 in same database.what I want is I need to copy some values from table-1 and insert the same to table-2. I have tried many ways but it does not seems work. below is my code can any one tell me where I am missing?? $db = mysql_connect("localhost", "user", "pass") or die("Could not connect."); mysql_select_db("comdata",$db)or die(mysql_error()); $resultb = mysql_query("SELECT * FROM table-2")or die(mysql_error()); $row = mysql_fetch_array($resultb); $days = (strtotime(date("Y-m-d")) - strtotime($row['regtime'])) / (60 * 60 * 24); if($row > 0 && $days < 1){ $person = $row['person']; $catogr = $row['catog']; $position = $row['position']; $location = $row['location']; $rank = $row['rank']; mysql_close($db); }else{ $db = mysql_connect("localhost", "user", "pass") or die("Could not connect."); mysql_select_db("comdata",$db)or die(mysql_error()); $result = mysql_query("SELECT * FROM table-1 WHERE regtime = DATE(NOW()) ORDER BY rank ASC LIMIT 1;")or die(mysql_error()); $row = mysql_fetch_array($result); $person = $row['person']; $catogr = $row['catog']; $position = $row['position']; $location = $row['location']; $rank = $row['rank']; mysql_query("INSERT INTO table-2 (regtime,person,catog,position,location,rank) VALUES(NOW(),'$person','$catogr','$position','$location','$rank')"); mysql_close($db); }

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  • Perl Capture and Modify STDERR before it prints to a file

    - by MicrobicTiger
    I have a perl script which performs multiple external commands and prints the outputs from STDERR and STDOUT to a logfile along with a series of my own print statements to act as documentation on the process. My problem is that the STDERR repeats ~identical prints as example below. I'd like to capture this before it prints and replace with the final result for each of the commands i run. blocks evaluated : 0 blocks evaluated : 10000 blocks evaluated : 20000 blocks evaluated : 30000 ... blocks evaluated : 3420000 blocks evaluated : 3428776 Here's how I'm getting STDOUT and STDERR my $logfile = "Logfile.log"; #log file name #--- Open log file for append if specified --- if ( $logfile ) { open ( OLDOUT, ">&", STDOUT ) or die "ERROR: Can't backup STDOUT location.\n"; close STDOUT; open ( STDOUT, ">", $logfile ) or die "ERROR: Logfile [$logfile] cannot be opened.\n"; } if ( $logfile ) { open ( OLDERR, ">&", STDERR ) or die "ERROR: Can't backup STDERR location.\n"; close STDERR; open ( STDERR, '>&STDOUT' ) or die "ERROR: failed to pass STDERR to STDOUT.\n"; } and closing them close STDERR; open ( STDERR, ">&", OLDERR ) or die "ERROR: Can't fix that first thing you broke!\n"; close STDOUT; open ( STDOUT, ">&", OLDOUT ) or die "ERROR: Can't fix that other thing you broke!\n"; How do I access the STDERR when each print is occurring to do the replace? Or prevent it from printing if it isn't the last of the batch. Many Thanks in advance.

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  • SQL SERVER – Importance of User Without Login – T-SQL Demo Script

    - by pinaldave
    Earlier I wrote a blog post about SQL SERVER – Importance of User Without Login and my friend and SQL Expert Vinod Kumar has written excellent follow up blog post about Contained Databases inside SQL Server 2012. Now lots of people asked me if I can also explain the same concept again so here is the small demonstration for it. Let me show you how login without user can help. Before we continue on this subject I strongly recommend that you read my earlier blog post here. In following demo I am going to demonstrate following situation. Login using the System Admin account Create a user without login Checking Access Impersonate the user without login Checking Access Revert Impersonation Give Permission to user without login Impersonate the user without login Checking Access Revert Impersonation Clean up USE [AdventureWorks2012] GO -- Step 1 : Login using the SA -- Step 2 : Create Login Less User CREATE USER [testguest] 9ITHOUT LOGIN WITH DEFAULT_SCHEMA=[dbo] GO -- Step 3 : Checking access to Tables SELECT * FROM sys.tables; -- Step 4 : Changing the execution contest EXECUTE AS USER   = 'testguest'; GO -- Step 5 : Checking access to Tables SELECT * FROM sys.tables; GO -- Step 6 : Reverting Permissions REVERT; -- Step 7 : Giving more Permissions to testguest user GRANT SELECT ON [dbo].[ErrorLog] TO [testguest]; GRANT SELECT ON [dbo].[DatabaseLog] TO [testguest]; GO -- Step 8 : Changing the execution contest EXECUTE AS USER   = 'testguest'; GO -- Step 9 : Checking access to Tables SELECT * FROM sys.tables; GO -- Step 10 : Reverting Permissions REVERT; GO -- Step 11: Clean up DROP USER [testguest]Step 3 GO Here is the step 9 we will be able to notice that how a user without login gets access to some of the data/object which we gave permission. What I am going to prove with this example? Well there can be different rights with different account. Once the login is authenticated it makes sense for impersonating a user with only necessary permissions to be used for further operation. Again this is very basic and fundamental example. There are lots of more points to be discussed as we go in future posts. Just do not take this blog post as a template and implement everything as it is. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Security, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL SERVER – Index Created on View not Used Often – Observation of the View – Part 2

    - by pinaldave
    Earlier, I have written an article about SQL SERVER – Index Created on View not Used Often – Observation of the View. I received an email from one of the readers, asking if there would no problems when we create the Index on the base table. Well, we need to discuss this situation in two different cases. Before proceeding to the discussion, I strongly suggest you read my earlier articles. To avoid the duplication, I am not going to repeat the code and explanation over here. In all the earlier cases, I have explained in detail how Index created on the View is not utilized. SQL SERVER – Index Created on View not Used Often – Limitation of the View 12 SQL SERVER – Index Created on View not Used Often – Observation of the View SQL SERVER – Indexed View always Use Index on Table As per earlier blog posts, so far we have done the following: Create a Table Create a View Create Index On View Write SELECT with ORDER BY on View However, the blog reader who emailed me suggests the extension of the said logic, which is as follows: Create a Table Create a View Create Index On View Write SELECT with ORDER BY on View Create Index on the Base Table Write SELECT with ORDER BY on View After doing the last two steps, the question is “Will the query on the View utilize the Index on the View, or will it still use the Index of the base table?“ Let us first run the Create example. USE tempdb GO IF EXISTS (SELECT * FROM sys.views WHERE OBJECT_ID = OBJECT_ID(N'[dbo].[SampleView]')) DROP VIEW [dbo].[SampleView] GO IF EXISTS (SELECT * FROM sys.objects WHERE OBJECT_ID = OBJECT_ID(N'[dbo].[mySampleTable]') AND TYPE IN (N'U')) DROP TABLE [dbo].[mySampleTable] GO -- Create SampleTable CREATE TABLE mySampleTable (ID1 INT, ID2 INT, SomeData VARCHAR(100)) INSERT INTO mySampleTable (ID1,ID2,SomeData) SELECT TOP 100000 ROW_NUMBER() OVER (ORDER BY o1.name), ROW_NUMBER() OVER (ORDER BY o2.name), o2.name FROM sys.all_objects o1 CROSS JOIN sys.all_objects o2 GO -- Create View CREATE VIEW SampleView WITH SCHEMABINDING AS SELECT ID1,ID2,SomeData FROM dbo.mySampleTable GO -- Create Index on View CREATE UNIQUE CLUSTERED INDEX [IX_ViewSample] ON [dbo].[SampleView] ( ID2 ASC ) GO -- Select from view SELECT ID1,ID2,SomeData FROM SampleView ORDER BY ID2 GO -- Create Index on Original Table -- On Column ID1 CREATE UNIQUE CLUSTERED INDEX [IX_OriginalTable] ON mySampleTable ( ID1 ASC ) GO -- On Column ID2 CREATE UNIQUE NONCLUSTERED INDEX [IX_OriginalTable_ID2] ON mySampleTable ( ID2 ) GO -- Select from view SELECT ID1,ID2,SomeData FROM SampleView ORDER BY ID2 GO Now let us see the execution plans for both of the SELECT statement. Before Index on Base Table (with Index on View): After Index on Base Table (with Index on View): Looking at both executions, it is very clear that with or without, the View is using Indexes. Alright, I have written 11 disadvantages of the Views. Now I have written one case where the View is using Indexes. Anybody who says that I am being harsh on Views can say now that I found one place where Index on View can be helpful. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Optimization, SQL Performance, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQL View, SQLServer, T SQL, Technology

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  • WORD CERTIFIED IMPLEMENTATION SPECIALIST EN LAAT ORACLE UNIVERSITY U ASSISTEREN HIERMEE

    - by mseika
    WORD CERTIFIED IMPLEMENTATION SPECIALIST EN LAAT ORACLE UNIVERSITY U ASSISTEREN HIERMEE Word gespecialiseerd!Oracle weet exact welke competenties implementatie specialisten moeten opbouwen en beseft de bijbehorende inspanning die hiervoor nodig is. Het nieuwe Specialized programma van Oracle PartnerNetwork biedt een scala van certificering mogelijkheden aan (Specializations) die aantonen dat de benodigde kennis en vaardigheden bij u en bij uw teamleden aanwezig zijn.Word erkend! Bevestig uw kennis en vaardigheden en ontvang de beloning die u verdient door examens te halen voor de hele portefeuille van producten en oplossingen die Oracle aanbiedt. Haal het examen en ontvang uw OPN Specialist Certificaat. Stap 1: Kies uw SpecialisatieBekijk de Specialization Guide (PDF) - ons aanbod van Specialisaties voor de individu. Stap 2: Bereik de vereiste kennis en de vaardighedenBoek een Oracle University OPN Only Bootcamp en bereik de vereiste kennis en de vaardigheden om een Certified Implementation Specialist te worden.Wij hebben voor u de volgende Bootcamps geselecteerd en de komende maanden ingepland bij Oracle University in Utrecht, The Netherlands: Boot Camp Duur Data Voorbereiding voor Specialization (Exam Code) Database Oracle Database 11g Specialist 5 21-25 jan 12 Oracle Database 11g Certified Implementation Specialist (1Z0-514) Oracle Data Warehousing 11g Implementation 5 3-7 dec 12 3-7 apr 13 Data Warehousing 11g Certified Implementation Specialist (1Z0-515) Exadata Oracle Exadata 11g Technical Boot Camp 3 28-30 jan 13 Oracle Exadata 11g Certified Implementation Specialist (1Z0-536) Fusion Middleware Oracle AIA 11g Implementation 4 20-22 feb 13 Oracle Application Integration Architecture 11g Certified Implementation Specialist (1Z0-543) Oracle BPM 11g Implementation 4 15-18 okt 12 14-17 jan 12 15-18 apr 13 Oracle Unified Business Process Management Suite 11g Billing Certified Implementation Specialist (1Z0-560) Oracle WebCenter 11g Implementation 4 10-13 okt 12 5-8 feb 13 Oracle WebCenter Portal 11g Certified Implementation Specialist (1Z0-541) Oracle Identity Administration and Analytics 11g Implementation 3 7-9 nov 12 6-8 mrt 13 Identity Administration and Analytics 11g Certified Implementation Specialist (1Z0-545) Business Intelligence and Datawarehousing Oracle BI Enterprise Edition 11g Implementation 5 24-28 sep12 11-15 mrt 13 Boek een Boot Camp: U kunt online boeken of gebruik maken van dit inschrijfformulier Prijzen: U merkt dat de ‘OPN Only’ Boot Camps in prijs sterk gereduceerd zijn en bovendien is uw OPN korting (silver, gold, platinum of diamond) nog steeds van toepassing! Stap 3: Boek en neem uw examen afBezoek de examenregistratie web-pagina en lees de instructies voor het boeken van uw examen bij een Pearson VUE Authorized Testcentrum. Examens kunnen betaald worden door één van de gratis examen vouchers die uw bedrijf heeft, door een voucher aan te schaffen bij Oracle University of met uw creditcard bij het Pearson VUE Testcentrum. Stap 4: Ontvang uw OPN Specialist CertificateGefeliciteerd! U bent nu een Certified Implementation Specialist. Heeft u meer informatie of assistentie nodig?Neem dan contact op met uw Oracle University Account Manager of met onze Education Service Desk: eMail: [email protected]:+ 31 30 66 99 244 Bij het boeken graag de volgende code vermelden: E1229

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  • Dutch for once: op zoek naar een nieuwe uitdaging!

    - by Dennis Vroegop
    Originally posted on: http://geekswithblogs.net/dvroegop/archive/2013/10/11/dutch-for-once-op-zoek-naar-een-nieuwe-uitdaging.aspxI apologize to my non-dutch speaking readers: this post is about me looking for a new job and since I am based in the Netherlands I will do this in Dutch… Next time I will be technical (and thus in English) again! Het leuke van interim zijn is dat een klus een keer afloopt. Ik heb heel bewust gekozen voor het leven als freelancer: ik wil graag heel veel verschillende mensen en organisaties leren kennen. Dit werk is daar bij uitstek geschikt voor! Immers: bij iedere klus breng ik niet alleen nieuwe ideeën en kennis maar ik leer zelf ook iedere keer ontzettend veel. Die kennis kan ik dan weer gebruiken bij een vervolgklus en op die manier verspreid ik die kennis onder de bedrijven in Nederland. En er is niets leukers dan zien dat wat ik meebreng een organisatie naar een ander niveau brengt! Iedere keer een ander bedrijf zoeken houdt in dat ik iedere keer weg moet gaan bij een organisatie. Het lastige daarvan is het juiste moment te vinden. Van buitenaf gezien is dat lastig in te schatten: wanneer kan ik niets vernieuwends meer bijdragen en is het tijd om verder te gaan? Wanneer is het tijd om te zeggen dat de organisatie alles weet wat ik ze kan bijbrengen? In mijn huidige klus is dat moment nu aangebroken. In de afgelopen elf maanden heb ik dit bedrijf zien veranderen van een kleine maar enthousiaste groep ontwikkelaars naar een professionele organisatie met ruim twee keer zo veel ontwikkelaars. Dat veranderingsproces is erg leerzaam geweest en ik ben dan ook erg blij dat ik die verandering heb kunnen en mogen begeleiden. Van drie teams met ieder vijf of zes ontwikkelaars naar zes teams met zeven tot acht ontwikkelaars per team groeien betekent dat je je ontwikkelproces heel anders moet insteken. Ook houdt dat in dat je je teams anders moet indelen, dat de organisatie zelf anders gemodelleerd moet worden en dat mensen anders met elkaar om moeten gaan. Om dat voor elkaar te krijgen is er door iedereen heel hard gewerkt, is er een aantal fouten gemaakt, is heel veel van die fouten geleerd en is uiteindelijk een vrijwel nieuw bedrijf ontstaan. Het is tijd om dit bedrijf te verlaten. Ik ben benieuwd waar ik hierna terecht kom: ik ben aan het rondkijken naar mogelijkheden. Ik weet wèl: het bedrijf waar ik naar op zoek ben, is een bedrijf dat openstaat voor veranderingen. Veranderingen, maar dan wel met het oog voor het individu; mensen staan immers centraal in de software ontwikkeling! Ik heb er in ieder geval weer zin in!

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  • Service Broker, not ETL

    - by jamiet
    I have been very quiet on this blog of late and one reason for that is I have been very busy on a client project that I would like to talk about a little here. The client that I have been working for has a website that runs on a distributed architecture utilising a messaging infrastructure for communication between different endpoints. My brief was to build a system that could consume these messages and produce analytical information in near-real-time. More specifically I basically had to deliver a data warehouse however it was the real-time aspect of the project that really intrigued me. This real-time requirement meant that using an Extract transformation, Load (ETL) tool was out of the question and so I had no choice but to write T-SQL code (i.e. stored-procedures) to process the incoming messages and load the data into the data warehouse. This concerned me though – I had no way to control the rate at which data would arrive into the system yet we were going to have end-users querying the system at the same time that those messages were arriving; the potential for contention in such a scenario was pretty high and and was something I wanted to minimise as much as possible. Moreover I did not want the processing of data inside the data warehouse to have any impact on the customer-facing website. As you have probably guessed from the title of this blog post this is where Service Broker stepped in! For those that have not heard of it Service Broker is a queuing technology that has been built into SQL Server since SQL Server 2005. It provides a number of features however the one that was of interest to me was the fact that it facilitates asynchronous data processing which, in layman’s terms, means the ability to process some data without requiring the system that supplied the data having to wait for the response. That was a crucial feature because on this project the customer-facing website (in effect an OLTP system) would be calling one of our stored procedures with each message – we did not want to cause the OLTP system to wait on us every time we processed one of those messages. This asynchronous nature also helps to alleviate the contention problem because the asynchronous processing activity is handled just like any other task in the database engine and hence can wait on another task (such as an end-user query). Service Broker it was then! The stored procedure called by the OLTP system would simply put the message onto a queue and we would use a feature called activation to pick each message off the queue in turn and process it into the warehouse. At the time of writing the system is not yet up to full capacity but so far everything seems to be working OK (touch wood) and crucially our users are seeing data in near-real-time. By near-real-time I am talking about latencies of a few minutes at most and to someone like me who is used to building systems that have overnight latencies that is a huge step forward! So then, am I advocating that you all go out and dump your ETL tools? Of course not, no! What this project has taught me though is that in certain scenarios there may be better ways to implement a data warehouse system then the traditional “load data in overnight” approach that we are all used to. Moreover I have really enjoyed getting to grips with a new technology and even if you don’t want to use Service Broker you might want to consider asynchronous messaging architectures for your BI/data warehousing solutions in the future. This has been a very high level overview of my use of Service Broker and I have deliberately left out much of the minutiae of what has been a very challenging implementation. Nonetheless I hope I have caused you to reflect upon your own approaches to BI and question whether other approaches may be more tenable. All comments and questions gratefully received! Lastly, if you have never used Service Broker before and want to kick the tyres I have provided below a very simple “Service Broker Hello World” script that will create all of the objects required to facilitate Service Broker communications and then send the message “Hello World” from one place to anther! This doesn’t represent a “proper” implementation per se because it doesn’t close down down conversation objects (which you should always do in a real-world scenario) but its enough to demonstrate the capabilities! @Jamiet ----------------------------------------------------------------------------------------------- /*This is a basic Service Broker Hello World app. Have fun! -Jamie */ USE MASTER GO CREATE DATABASE SBTest GO --Turn Service Broker on! ALTER DATABASE SBTest SET ENABLE_BROKER GO USE SBTest GO -- 1) we need to create a message type. Note that our message type is -- very simple and allowed any type of content CREATE MESSAGE TYPE HelloMessage VALIDATION = NONE GO -- 2) Once the message type has been created, we need to create a contract -- that specifies who can send what types of messages CREATE CONTRACT HelloContract (HelloMessage SENT BY INITIATOR) GO --We can query the metadata of the objects we just created SELECT * FROM   sys.service_message_types WHERE name = 'HelloMessage'; SELECT * FROM   sys.service_contracts WHERE name = 'HelloContract'; SELECT * FROM   sys.service_contract_message_usages WHERE  service_contract_id IN (SELECT service_contract_id FROM sys.service_contracts WHERE name = 'HelloContract') AND        message_type_id IN (SELECT message_type_id FROM sys.service_message_types WHERE name = 'HelloMessage'); -- 3) The communication is between two endpoints. Thus, we need two queues to -- hold messages CREATE QUEUE SenderQueue CREATE QUEUE ReceiverQueue GO --more querying metatda SELECT * FROM sys.service_queues WHERE name IN ('SenderQueue','ReceiverQueue'); --we can also select from the queues as if they were tables SELECT * FROM SenderQueue   SELECT * FROM ReceiverQueue   -- 4) Create the required services and bind them to be above created queues CREATE SERVICE Sender   ON QUEUE SenderQueue CREATE SERVICE Receiver   ON QUEUE ReceiverQueue (HelloContract) GO --more querying metadata SELECT * FROM sys.services WHERE name IN ('Receiver','Sender'); -- 5) At this point, we can begin the conversation between the two services by -- sending messages DECLARE @conversationHandle UNIQUEIDENTIFIER DECLARE @message NVARCHAR(100) BEGIN   BEGIN TRANSACTION;   BEGIN DIALOG @conversationHandle         FROM SERVICE Sender         TO SERVICE 'Receiver'         ON CONTRACT HelloContract WITH ENCRYPTION=OFF   -- Send a message on the conversation   SET @message = N'Hello, World';   SEND  ON CONVERSATION @conversationHandle         MESSAGE TYPE HelloMessage (@message)   COMMIT TRANSACTION END GO --check contents of queues SELECT * FROM SenderQueue   SELECT * FROM ReceiverQueue   GO -- Receive a message from the queue RECEIVE CONVERT(NVARCHAR(MAX), message_body) AS MESSAGE FROM ReceiverQueue GO --If no messages were received and/or you can't see anything on the queues you may wish to check the following for clues: SELECT * FROM sys.transmission_queue -- Cleanup DROP SERVICE Sender DROP SERVICE Receiver DROP QUEUE SenderQueue DROP QUEUE ReceiverQueue DROP CONTRACT HelloContract DROP MESSAGE TYPE HelloMessage GO USE MASTER GO DROP DATABASE SBTest GO

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  • How can I evaluate a candidate's knowledge of Html/CSS during an interview?

    - by webnoob
    I am trying to determine some good interview questions to assess the ability of people coming in for a Html/CSS job, however that topic is extremely broad, and I'm not sure what sort of questions I can ask to properly evaluate someone's HTML/CSS knowledge. What sort of questions can I ask to evaluate a candidate's Html/CSS abilities during an interview? Ideally I would like to ask few questions and then give them a real life scenario to combat.

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  • Oracle Excellence Awards 2012

    - by A&C Redaktion
    Spezialisierte Partner können sich ab sofort bis 29. Juni als „Specialized Partner of the Year“ bewerben. Damit honoriert Oracle diejenigen OPN Partner in EMEA, die sich mithilfe der Spezialisierung besonders ausgezeichnet haben, sei es durch einen hohen Mehrwert für deren Endkunden oder innovativen Lösungen und Services. Voraussetzung für eine Bewerbung ist mindestens eine abgeschlossene Spezialisierung in diesen sieben Kategorien: Specialized Partner of the Year: Database Specialized Partner of the Year: Applications Specialized Partner of the Year: Middleware Specialized Partner of the Year: Industry Specialized Partner of the Year: Oracle Accelerate Specialized Partner of the Year: Servers and Storage Systems Specialized Partner of the Year: Oracle on Oracle Der Gewinner eines “Specialized Partner of the Year” EMEA Awards erhält 5.000 US-Dollar MDF und vielfältige Möglichkeiten, sich in Szene zu setzen. Wie auch im letzten Jahr wird der Award wieder auf der Oracle OpenWorld in San Francisco überreicht. Interviews, Videos, Werbung, Berichte im Oracle Magazine und ein kostenloser Konferenzpass sind natürlich inklusive. Wie immer, gilt die Bewerbung für den EMEA-Award gleichzeitig als Bewerbung für den deutschen Partner-Award 2012, der auf dem Oracle Partner Day (im Herbst nach der OpenWorld) verliehen wird. Normal 0 21 false false false DE X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Die Nominierung Ihres erfolgreichen Projektes muss diesmal hier auf Englisch eingereicht werden, da eine internationale Jury entscheidet. Beschreiben Sie Ihr Projekt so ausführlich wie möglich, damit sich die Juroren ein gutes Bild Ihrer Leistungen und Services machen können. Wenn Sie hierbei Unterstützung benötigen, fragen Sie einfach Ihren Channel Manager. Denn: Je aussagekräftiger Ihre Unterlagen sind, desto höher ist Ihre Chance zu gewinnen! Alle Informationen zu den diesjährigen Awards finden Sie auf der Oracle Excellence Awards Website. Wir drücken Ihnen die Daumen!

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  • Oracle Excellence Awards 2012

    - by A&C Redaktion
    Spezialisierte Partner können sich ab sofort bis 29. Juni als „Specialized Partner of the Year“ bewerben. Damit honoriert Oracle diejenigen OPN Partner in EMEA, die sich mithilfe der Spezialisierung besonders ausgezeichnet haben, sei es durch einen hohen Mehrwert für deren Endkunden oder innovativen Lösungen und Services. Voraussetzung für eine Bewerbung ist mindestens eine abgeschlossene Spezialisierung in diesen sieben Kategorien: Specialized Partner of the Year: Database Specialized Partner of the Year: Applications Specialized Partner of the Year: Middleware Specialized Partner of the Year: Industry Specialized Partner of the Year: Oracle Accelerate Specialized Partner of the Year: Servers and Storage Systems Specialized Partner of the Year: Oracle on Oracle Der Gewinner eines “Specialized Partner of the Year” EMEA Awards erhält 5.000 US-Dollar MDF und vielfältige Möglichkeiten, sich in Szene zu setzen. Wie auch im letzten Jahr wird der Award wieder auf der Oracle OpenWorld in San Francisco überreicht. Interviews, Videos, Werbung, Berichte im Oracle Magazine und ein kostenloser Konferenzpass sind natürlich inklusive. Wie immer, gilt die Bewerbung für den EMEA-Award gleichzeitig als Bewerbung für den deutschen Partner-Award 2012, der auf dem Oracle Partner Day (im Herbst nach der OpenWorld) verliehen wird. Normal 0 21 false false false DE X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Die Nominierung Ihres erfolgreichen Projektes muss diesmal hier auf Englisch eingereicht werden, da eine internationale Jury entscheidet. Beschreiben Sie Ihr Projekt so ausführlich wie möglich, damit sich die Juroren ein gutes Bild Ihrer Leistungen und Services machen können. Wenn Sie hierbei Unterstützung benötigen, fragen Sie einfach Ihren Channel Manager. Denn: Je aussagekräftiger Ihre Unterlagen sind, desto höher ist Ihre Chance zu gewinnen! Alle Informationen zu den diesjährigen Awards finden Sie auf der Oracle Excellence Awards Website. Wir drücken Ihnen die Daumen!

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