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  • Does an XPathDocument load the whole xml document?

    - by Wires
    If I do XPathDocument doc = new XPathDocument("filename.xml"); Does that load the entire document into memory? I'm writing a mobile phone app and the document might store lots of data that doesn't ever need to all be loaded at the same time. Mobile phones don't usually have too much ram!

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  • Merging XML records into one

    - by BhanuPratap Tarigopula
    I am new to XSLT. I have requirement of merging and adding. XML: <OrderDetails> <OrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <OrderDetail action="add"> <OrderedUnits>12</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <IOrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295762</PONumber> </OrderDetail> <OrderDetails> If the LocationCode, Date, and PONumber fields match, I need to add the OrderedUnits and make it only one entry. Expected output XML: <OrderDetails> <OrderDetail action="add"> <OrderedUnits>30</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295755</PONumber> </OrderDetail> <IOrderDetail action="add"> <OrderedUnits>18</OrderedUnits> <Date>2013-09-30T00:00:00</Date> <LocationCode>3202</LocationCode> <PONumber>022548295762</PONumber> </OrderDetail> <OrderDetails> How can I write this XSLT?

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  • Convert text to xml

    - by Nave
    I want to convert a tab delimited text file to a XML file. I was able to do it with a single character delimiter. But how do i extend it to tabs? I am coding in C# and using Visual Studio 2010.

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  • xml appending issue - in ie, chrome browsers

    - by 3gwebtrain
    Hi, i am using this coding for my xml information to append in to html. As well it works fine. but in the ie7,ie8 as well chrome browser it's not propelry. This code work9ing well with firefox,opera, safari.. i unable to find, what is the mistake i made this.. any one help me please? $(function(){ var thisPage; var parentPage; $('ul.left-navi li a').each(function(){ $('ul.left-navi li a').removeClass('current'); var pathname = (window.location.pathname.match(/[^\/]+$/)[0]); var currentPage = $(this).attr('href'); var pathArr = new Array(); pathArr = pathname.split("."); var file = pathArr[pathArr.length - 2]; thisPage = file; if(currentPage==pathname){ $(this).addClass("active"); } }) $.get('career-utility.xml',function(myData){ var receivedData = myData; var myXml = $(myData).find(thisPage); parentPage = thisPage; var overviewTitle = myXml.find('overview').attr('title'); var description = myXml.find('discription').text(); var mainsublinkTitle = myXml.find('mainsublink').attr('title'); var thisTitle = myXml.find("intro").attr('title'); var thisIntro = myXml.find("introinfo").text(); $('<h3>'+overviewTitle+'</h3>').appendTo('.overViewInfo'); $('<p>'+description+'</p>').appendTo('.overViewInfo'); var sublinks = myXml.find('mainsublink').children('sublink'); $('#intro h3').append(thisTitle); $('#intro').append(thisIntro); sublinks.each(function(numsub){ var newSubLink = $(this); var sublinkPage = $(this).attr('pageto'); var linkInfo = $(this).text(); $('ul.career-link').append('<li><a href="'+sublinkPage+'">'+linkInfo+'</a></li>'); }) // alert('thisTitle : '+thisTitle+'thisIntro :'+thisIntro); $(myXml).find('listgroup').each(function(index){ var count = index; var listGroup = $(this); var listGroupTitle = $(this).attr('title'); var shortNote = $(this).attr('shortnote'); var subLink = $(this).find('sublist'); var firstList = $(this).find('list'); $('.grouplist').append('<div class="list-group"><h3>'+listGroupTitle+'</h3><ul class="level-one level' + count + '"></ul></div>'); firstList.each(function(listnum) { $(this).wrapInner('<li>') .find('sublistgroup').wrapInner('<ul>').children().unwrap() .find('sublist').wrapInner('<li>').children().unwrap(); // Append content of 'list' node $('ul.level'+count).append($(this).children()); }); }); }); })

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  • Saving an XML that has invalid characters

    - by BDotA
    there are code snippets that strip the invalid characters inside a string before we save it as an XML ... but I have one more problem: Let's say my user wants to have a column name like "[MyColumnOne] ...so now I do not want to strip these "[","] well because these are the ones that user has defined and wants to see them so if I use some codes that are stripping the invalid characters they are also removing "[" and "[" but in this case I still need them to be saved... what can I do?

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  • Write xml file with lxml

    - by systempuntoout
    Having a code like this: from lxml import etree root = etree.Element("root") root.set("interesting", "somewhat") child1 = etree.SubElement(root, "test") How do i write root Element object to an xml file using write() method of ElementTree class?

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  • 'How decode my encode xml data?

    - by Alex
    Hi <% 'Stage 1 datas=Server.URLencode("<PaginationData currentPage=""1"" totalPages=""9""/>") response.write "Encode = " datas &"</br></br>" 'Stage 2 response.write "Decode = " 'How i again decode my encode data? %> In the "Stage 1" , i encode my xml data In the "Stage 2", How i decode the "Stage 1" Encode data? hoping your support

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  • TouchCode XML parsing error

    - by itsaboutcode
    Hi, I have a xml document which has only one element in the document, which is <error>error string<error> But when i try to parse it, it says this document has no element at all. In other words when i try to access the rootElement it says "null" CXMLDocument *rssParser = [[[CXMLDocument alloc] initWithContentsOfURL:url options:0 error:nil] autorelease]; NSLog(@"Root: %@",[[rssParser rootElement] name]); Please tell me what is wroing with this. Thanks

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  • Programatically upload XML file to SSRS server

    - by xt_20
    Hi all, How do I programatically upload an XSLT file to an SSRS server database? I would like exactly the same functionality as the 'Upload File', preferably using the 'rs' command. I have tried rs.CreateResource, but it doesn't seem to work for XML/XSLT files (though it works for Excel and image files) I understand that manipulating the SSRS db is not supported. Thanks

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  • Actionscript 3 E4X working with MMS values in XML

    - by user150946
    I am building an application using Action script 3 I am retrieving some XML from the web however the node names are mms:Image mms:Results etc my action script compiler is throwing an error becuase it is not expecting to see the semi colon in the node name. How to I access the nodes? thanks

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  • Replace XML Bullet Points Found in Feed in Classic ASP

    - by StevieB
    Hey I am currently reading in a XML file which contains bullet list in the following container i.e. ? the average pension contribution rate for executive directors . I am having a problem with symbol directly before the text of each bullet point I want to remove it i.e Replace(text,"old","new") but i cant seem to find what value that bullet point actually is to replace of that makes sense. Thanks

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  • Is there any way to get the combine two xml into one xml in Linux.

    - by Tattat
    XML one is something like that: <dict> <key>2</key> <array> <string>A</string> <string>B</string> </array> <key>3</key> <array> <string>C</string> <string>D</string> <string>E</string> </array> </dict> XML Two is something like that: <dict> <key>A</key> <array> <string>A1</string> <false/> <false/> <array> <string>Apple</string> <string>This is an apple</string> </array> <array> <string>Apple Pie</string> <string>I love Apple Pie.</string> </array> </array> <key>B</key> <array> <string>B7</string> <false/> <false/> <array> <string>Boy</string> <string>I am a boy.</string> </array> </array> </dict> I want to convert to this: <dict> <key>2</key> <array> <string>A, Apple, Apple Pie</string> <string>B, Boy</string> </array> ... </dict>

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  • Easy XML Serializer for Java

    - by sdoca
    I'm looking for a way to serialize Java objects into XML for use by a RESTful web service. I don't have an XSD. I have looked at the following: JAXB - fairly heavy weight with annotations required on classes and also an ObjectFactory class and/or a jaxb.index file Simple - requires annotations but no other config classes/files. Unfortunately it can't serialize Sets. XStream - no annotations etc. required, but doesn't support generics Does anyone else have any suggestions?

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  • Having problems creating an array from XML data in Acrobat Javascript, please help if you can

    - by Kevin Minke
    I have a manually created array that already works example below: var PartsData = { 179: { ref:"", partNum: "201-2007-C00-00", descript: "System Monitor Card (Tracewell Only)", cage: "39764", qty: "1", SMR: "XBOZZ", UOC: "A" }}; Now this array above is is just one value in the array and it works fine. Here is the XML that I am trying to use to dynamically change the values. <?xml version="1.0" encoding="utf-8"?> <partsTables> <partsList> <part sheetNum="ta1"> <breakDownIndexNo>-1 </breakDownIndexNo> <referenceDesg/> <indent>20534220P01 </indent> <description/> <cage>TAC RI, GRADE-A SHOCK (TEC RACK), ALT P/N 72304-1</cage> <qtyPerAssy>23991 </qtyPerAssy> <smr>1 </smr> <uoc>ADODD </uoc> <blank/> </part> </partsList> </partsTables> I have this parsing just fine in Acrobat. Now I want to make the array work for me in using these values. if I have the following below it will work. Where part.item(i).indent.value equals the value of the indent node, etc. newArr = { 179: { ref: part.item(i).referenceDesg.value, partNum: part.item(i).indent.value, descript: part.item(i).cage.value, cage: part.item(i).qtyPerAssy.value, qty: part.item(i).smr.value, SMR: part.item(i).uoc.value, UOC: part.item(i).blank.value}}; As soon as I try to make the 179 value, which is in the breakDownIndexNo node, dynamic by using the direct part.item(i).breakDownIndexNo.value it will not compile. Acrobat is using javascript so I'm not sure why I can not get this to parse. I have tried to create a variable out of the breakDownIndexNo node and typed it to both a String and an Integer. this will let it create the array but it will not let me output from the array. newArr[indexNum].partNum gives me "no properties" where newArr[179].partNum if I were to manually set the index number to 179 will print out the value of part.item(i).indent.value. If any of you have an idea or an answer please let me know.

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