Search Results

Search found 12055 results on 483 pages for 'password complexity'.

Page 86/483 | < Previous Page | 82 83 84 85 86 87 88 89 90 91 92 93  | Next Page >

  • setting up ssh on minix 3.2

    - by Mark
    I have install MINIX 3.20 on VMware player on LINUX. Now, I am trying to ssh into Minix from the same Linux machine, but I am encountering some problems. First I installed openssh on MINIx then I tried to ssh onto the Minix virtual machine with ssh [email protected] but I got the following output: [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied (publickey,password,keyboard-interactive). I am sure the password I entered is correct, I have tried to ssh into MINIX on MINIX and it worked but not when I tried it from my linux machine. I have followed the steps for setting up ssh from this webpage, but it didn't work as shown above.

    Read the article

  • I'm a contract developer and I think I'm about to get screwed [closed]

    - by kagaku
    I do contract development on the side. You could say that I'm a contract developer? Considering I've only ever had one client I'd say that's not exactly the truth - more like I took a side job and needed some extra cash. It started out as a "rebuild our website and we'll pay you $10k" type project. Once that was complete (a bit over schedule, but certainly not over budget), the company hired me on as a "long term support" contractor. The contract is to go from March of this year, expiring on December 31st of this year - 10 months. Over which a payment is to be paid on the 30th of each month for a set amount. I've been fulfilling my end of the contract on all points - doing server maintenence, application and database changes, doing huge rush changes and pretty much just going above and beyond. Currently I'm in the middle of development of an iPhone mobile application (PhoneGap based) which is nearing completion (probably 3-4 weeks from submission). It has not been all peaches and flowers though. Each and every month when my paycheck comes due, there always seems to be an issue of sorts. These issues did not occur during the initial project, only during the support contract. The actual contract states that my check should be mailed out on the 30th of the month. I have received my check on time approximately once (on time being about 2-3 days within the 30th). I've received my paycheck as late as the 15th of the next month - over two weeks late. I've put up with it because I need the paycheck. There have been promises and promises of "we'll send it out on time next time! I promise" - only to receive it just as late the next month. When I ask about payment they give me a vibe like "why are you only worried about money?" - unfortunately I don't have the luxury of not worrying about money. The last straw was with my August payment, which should have been mailed on August 30th. I received it on September 12th. The reason for the delay? "USPS is delaying it man! we sent it out on the 1st!" is the reason I got. When I finally got the check in the mail, the postage on the envelope was marked September 10th - the date it was run through the postage machine. I've been outright lied to, at this point. I carry on working, because again - I need a paycheck. I orchestrated the move of our application to a new server, developed a bunch of new changes and continued work on the iPhone app. All told I probably went over my hourly allotment (I'm paid for 40 hours a month, I probably put in at least 50). On Saturday, the 1st, I gave the main contact at the company (a company of 3, by the way - this is not some big corporation) a ring and filled him in on the status of my work for the past two weeks. Unusually I hadn't heard from him since the middle of September. His response was "oh... well, that is nice and uh.. good job. well, we've been talking within the company about things and we've certainly got some decisions ahead of us..." - not verbatim but you get the idea (I hope?). I got out of this conversation that the site is not doing very well (which it's not) and they're considering pulling the plug. Crap, this contract is going to end early - there goes Christmas! Fine, that's alright, no problem. I'll get paid for the last months work and call it a day. Unfortunately I still haven't gotten last months check, and I'm getting dicked around now. "Oh.. we had problems transferring funds, we'll try and mail it out tomorrow" and "I left a VM with the finance guy, but I can't get ahold of him". So I'm getting the feeling I'm not getting paid for all the work I put in for September. This is obviously breach of contract, and I am pissed. Thinking irrationally, I considered changing all their passwords and holding their stuff hostage. Before I think it through (by the way, I am NOT going to do this, realized it would probably get me in trouble), I go and try some passwords for our various accounts. Google Apps? Oh, I'm no longer administrator here. Godaddy? Whoops, invalid password. Disqus? Nope, invalid password here too. Google Adsense / Analytics? Invalid password. Dedicated server account manager? Invalid password. Now, I have the servers root password - I just built the box last week and haven't had a chance to send the guy the root password. Wasn't in a rush, I manage the server and they never touch it. Now all of a sudden all the passwords except this one are changed; the writing is on the wall - I am out. Here's the conundrum. I have the root password, they do not. If I give them this password all the leverage I have is gone, out the door and out of my hands. During this argument of why am I not getting paid the guy sends me an email saying "oh by the way, what's the root username and password to the server?". Considering he knows absolutely nothing, I gave him an "admin" account which really has almost no rights. I still have exclusive access to the server, I just don't know where to go. I can hold their data hostage, but I'm almost positive this is the wrong thing to do. I'd consider it blackmail, regardless of whether or not I have gotten paid yet. I can "break" something on the server and give them the whole "well, if you were paying me I could fix it!" spiel. This works from a "well he's not holding their stuff hostage" point of view, but what stops them from hiring some one else to just fix the issue at hand? For all I know the guys nephew is a "l33t hax0r" and can figure it out for free. I can give in, document as much as I can and take him to small claims court. This is breach of contract, I'm not getting paid. I have a case, right? ???? Does anyone have any experience in this? What can I do? What are my options? I'm broke, I can't afford a lawyer and I can barely afford not getting this paycheck. My wife doesn't work (I work two jobs so she doesn't have to work - we have a 1 year old) and is already looking at getting a part time job to cover the bills. Long term we'll be fine, but this has pissed me off beyond belief! Help me out, I'm about to get screwed.

    Read the article

  • the requested resource is not available [closed]

    - by James Pj
    I have written a Java servlet program and run it through local Tomcat 7, But it was showing following error : HTTP Status 404 - /skypark/registration type Status report message /skypark/registration description The requested resource is not available. Apache Tomcat/7.0.33 I don't know what was the reason for it my Html page is <html> <head> <title> User registration </title> </head> <body> <form action="registration" method="post"> <center> <h2><b>Skypark User Registration</b></h2> <table border="0"> <tr><td> First Name </td><td> <input type="text" name="fname"/></br> </td></tr><tr><td> Last Name </td><td> <input type="text" name="lname"/></br> </td></tr><tr><td> UserName </td><td> <input type="text" name="uname"></br> </td></tr><tr><td> Enter Password </td><td> <input type="password" name="pass"></br> </td></tr><tr><td> Re-Type Password </td><td> <input type="password" name="pass1"></br> </td></tr><tr><td> Enter Email ID </td><td> <input type="email" name="email1"></br> </td></tr><tr><td> Phone Number </td><td> <input type="number" name="phone"> </td></tr><tr><td> Gender<br> </td></tr><tr><td> <input type="radio" name="gender" value="Male">Male</input></br> </td></tr><tr><td> <input type="radio" name="gender" value="Female">Female</input></br> </td></tr><tr><td> Enter Your Date of Birth<br> </td><td> <Table Border=0> <tr> <td> Date </td> <td>Month</td> <td>Year</td> </tr><tr> <td> <select name="date"> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> . . . have some code . . . </table> <input type="submit" value="Submit"></br> </center> </form> </body> </html> My servlet is : package skypark; import skypark.*; import java.io.*; import javax.servlet.*; import javax.servlet.http.*; import java.sql.*; public class Registration extends HttpServlet { public static Connection prepareConnection()throws ClassNotFoundException,SQLException { String dcn="oracle.jdbc.driver.OracleDriver"; String url="jdbc:oracle:thin:@JamesPJ-PC:1521:skypark"; String usname="system"; String pass="tiger"; Class.forName(dcn); return DriverManager.getConnection(url,usname,pass); } public void doPost(HttpServletRequest req,HttpServletResponse resp)throws ServletException,IOException { resp.setContentType("text/html"); PrintWriter out=resp.getWriter(); try { String phone1,uname,fname,lname,dob,address,city,state,country,pin,email,password,gender,lang,qual,relegion,privacy,hobbies,fav; uname=req.getParameter("uname"); fname=req.getParameter("fname"); lname=req.getParameter("lname"); dob=req.getParameter("date"); address=req.getParameter("address"); city=req.getParameter("city"); state=req.getParameter("state"); country=req.getParameter("country"); pin=req.getParameter("pin"); email=req.getParameter("email1"); password=req.getParameter("password"); gender=req.getParameter("gender"); phone1=req.getParameter("phone"); lang=""; qual=""; relegion=""; privacy=""; hobbies=""; fav=""; int phone=Integer.parseInt(phone1); Connection con=prepareConnection(); String Query="Insert into regdetails values(?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)"; PreparedStatement ps=con.prepareStatement(Query); ps.setString(1,uname); ps.setString(2,fname); ps.setString(3,lname); ps.setString(4,dob); ps.setString(5,address); ps.setString(6,city); ps.setString(7,state); ps.setString(8,country); ps.setString(9,pin); ps.setString(10,lang); ps.setString(11,qual); ps.setString(12,relegion); ps.setString(13,privacy); ps.setString(14,hobbies); ps.setString(15,fav); ps.setString(16,gender); int c=ps.executeUpdate(); String query="insert into passmanager values(?,?,?,?)"; PreparedStatement ps1=con.prepareStatement(query); ps1.setString(1,uname); ps1.setString(2,password); ps1.setString(3,email); ps1.setInt(4,phone); int i=ps1.executeUpdate(); if(c==1||c==Statement.SUCCESS_NO_INFO && i==1||i==Statement.SUCCESS_NO_INFO) { out.println("<html><head><title>Login</title></head><body>"); out.println("<center><h2>Skypark.com</h2>"); out.println("<table border=0><tr>"); out.println("<td>UserName/E-Mail</td>"); out.println("<form action=login method=post"); out.println("<td><input type=text name=uname></td>"); out.println("</tr><tr><td>Password</td>"); out.println("<td><input type=password name=pass></td></tr></table>"); out.println("<input type=submit value=Login>"); out.println("</form></body></html>"); } else { out.println("<html><head><title>Error!</title></head><body>"); out.println("<center><b>Given details are incorrect</b>"); out.println(" Please try again</center></body></html>"); RequestDispatcher rd=req.getRequestDispatcher("registration.html"); rd.include(req,resp); return; } } catch(Exception e) { out.println("<html><head><title>Error!</title><body>"); out.println("<b><i>Unable to process try after some time</i></b>"); out.println("</body></html>"); RequestDispatcher rd=req.getRequestDispatcher("registration.html"); rd.include(req,resp); return; } out.flush(); out.close(); } } And the web.xml file is <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0" metadata-complete="true"> <servlet> <servlet-name>reg</servlet-name> <servlet-class>skypark.Registration</servlet-class> </servlet> <servlet-mapping> <servlet-name>reg</servlet-name> <url-pattern>/registration</url-pattern> </servlet-mapping> This i kept in C:\Program Files\Apache Software Foundation\Tomcat 7.0\webapps\skypark\WEB_INF\web.xml and servlet class in C:\Program Files\Apache Software Foundation\Tomcat 7.0\webapps\skypark\WEB_INF\classes\skypark and registration.html in C:\Program Files\Apache Software Foundation\Tomcat 7.0\webapps\skypark\ if any mistake in this makes above error means please help me.Thanks in advance....

    Read the article

  • Only one user can connect to Ubuntu samba server

    - by StaticMethod
    I setup a samba server on 12.04 LTS, and it works great for one user but not the others. I am trying to map a network drive from a windows 7 laptop. I can successfully authenticate with one user, but the other two both get "Access is denied" errors. Here is my smb.conf file. [global] server string = %h server (Samba, Ubuntu) map to guest = Bad User obey pam restrictions = Yes pam password change = Yes passwd program = /usr/bin/passwd %u passwd chat = *Enter\snew\s*\spassword:* %n\n *Retype\snew\s*\spassword:* %n\n *password\supdated\ssuccessfully* . unix password sync = Yes syslog = 0 log file = /var/log/samba/log.%m max log size = 1000 dns proxy = No usershare allow guests = Yes panic action = /usr/share/samba/panic-action %d idmap config * : backend = tdb [printers] comment = All Printers path = /var/spool/samba create mask = 0700 printable = Yes print ok = Yes browseable = No [print$] comment = Printer Drivers path = /var/lib/samba/printers [share] comment = Ubuntu File Server Share path = /srv/share read only = No create mask = 0755 I know that the service is successfully reading from the /etc/passwd file because if I change the Linux password for the user that works, I have to use the new password when I connect. I changed all the users so they are all members of the same groups (all three users are admins anyway). I only ever have one user connected at a time. Here are the permissions on the shared folder /srv$ ls -l drwxrwxrwx 1 nobody nogroup 16 Feb 22 17:05 share Any ideas?

    Read the article

  • Making Room for Innovation - Oracle Interactive eBook

    - by Javier Puerta
    Innovation and complexity are two critical topics on the minds of business leaders. Innovation is what gives them a competitive edge; increased complexity is their greatest challenge. Learn how Oracle is helping customers change the game and make room for innovation by simplifying IT. Access the new Oracle interactive e-book, “Simplify IT and Unleash Innovation”. You can download it here.

    Read the article

  • SSH access failure from Ubuntu 12.04 LTS VM

    - by begueradj
    I installed 2 VMs on VirtualBox. VM 1: Windows XP with FreeSSHd and PuTTY installed.IP address: 10.0.0.2 VM 2: Ubuntu 12.04 LTS Server Edition with OpenSSH installed.IP address: 10.0.0.3 From VM 1, I run PuTTY with the IP address of VM 2 (10.0.0.3) and port number 22. I get prompted to input the username and password of VM 2 and everything works fine.From VM 2, I run on the terminal (Ubuntu): ssh [email protected] , I get prompted to enter the password of VM 1. I do so, but it says my password is invalid (while it is the correct one). I even deactived the Firewall on VM 1, but still the problem is here: my password is not accepted from VM 2. Is this due to some settings maybe I must do on VM 1 (Windows XP) so as I can access it with SSH ? Maybe it has something to do with the Firewall of Windows XP ?Important information: ping 10.0.0.2 from VM 1 and ping 10.0.0.3 from VM 2 are working successfully.

    Read the article

  • Using mongodump with an auth enabled mongodb server

    - by bb-generation
    I'm trying to do a daily backup of my mongodb server (auth enabled) using the mongodump tool. mongodump provides two parameters to set the credentials: -u [ --username ] arg username -p [ --password ] arg password Unfortunately they don't provide any parameter to read the password from stdin. Therefore everytime I run this command, everyone on the server can read the password (e.g. by using ps aux). The only workaround I have found is stopping the database and directly accessing the database files using the --dbpath parameter. Is there any other solution which allows me to backup the mongodb database without stopping the server and without "publishing" my password? I am using Debian squeeze 6.0.5 amd64 with mongodb 1.4.4-3.

    Read the article

  • "save the changes" message after removing the protection from workbook Excel 2010

    - by abbasi
    Some time ago I protected the Excel 2010 file from the path File Protect workbook Encrypt with password and gave it a password. Now that I removed that password via below method: Open the workbook and use Save As In the lower right of the file window will be "Tools" Choose "General Options" Clear the password. Save over your old file. the file is openable without wanting a password. But the problem is when I open it and close it immediately, even without moving the active cell, the message "Do you want to save the changes you made to 'test.lsx'?" appears. While there hasn't occurred any changes to that file so why I face this message any time I want to close the file? Hasn't the file been corrupted?

    Read the article

  • Can't access windows 7 shared files on Ubuntu 11.10

    - by Corey
    I just set up ubuntu 11.10 and Samba. I got it to access shares on a Vista machine, but when I try to access the shares on a windows 7 machine it asks for a Username, Domain, and Password. I have no password set up on the windows 7 machine so I put in the username, and domain try to connect and the password prompt keeps appearing...also tried guest and admin with no luck...I've tried many different fixes(modifying registry entries & advanced securities on the win 7 machine) with no luck. Thanks

    Read the article

  • Login keyring box frozen

    - by Maddie
    I'm new to ubuntu and I'm afraid I've done something really stupid. After booting, When prompted to enter a password to unlock my login keyring, I tried to enter in my password, but it won't let me. I can move my cursor but everything else is frozen. I tried to access the terminal by using Ctrl + Alt + F2, I entered my login and password from there and it worked, I just don't know what to do afterwards. Don't know what other information I can provide other than the fact that I am using Ubuntu 10.04

    Read the article

  • Custom Rule Sets in JohnTheRipper

    - by user854619
    I'm trying to create a custom rule set to do hash cracking. I have a SHA1 hash and a rule set that was enforced to create the password. The password must be of the form, 6-8 characters Every other letter changes case Password "shifts" characters at least one degree and at most three One odd number and one even number are at the beginning of the password One special character and one punctuation character are appended to the end of the password How can I defined a brute force attack in JohnTheRipper or similar hash cracking program? I've also attempted to write code to generate a wordlist of possible passwords, with no success. Thanks!

    Read the article

  • No access to Samba shares

    - by koanhead
    I have three shared folders in my local home directory- that is to say, on my Ubuntu desktop's /home/me/. All were set up using "Sharing Options" in Nautilus' right-click menu. The standard "Music" and "Videos" folders are configured identically: the "Guest Access" box is checked, but the "Allow others to create and delete" is not. The third folder, called "shared", is configured to not allow Guest access but to allow others to modify files. I have not altered /etc/samba/smb.conf by hand, I have only used Sharing Options to create and modify these so-called "shares". My roommates have two Windows 7 computers and one Ubuntu Netbook Remix netbook. I have the aforementioned desktop machine and laptop running 10.04. None of these machines can access any of the shares. Attempts to access the Guest shares result in the message \\machine\directory is not accessible. The network name could not be found. This is the error message generated by a VM running Windows 2000. The other Windows machines generate a similar error. The Ubuntu laptop gives the error Unable to mount location: Failed to mount Windows share. Hurrah, once again, for informative error messages. That really helps a lot. When attempting to browse the folder called "shared" from the laptop, I'm confronted with a password dialog. This behavior is the same will all machines I've tried in the situation. On entering my username and password for the account to which the shares belong, the password dialog briefly disappears and is replaced with an identical dialog. No error message, useful or not, appears. When attempting to browse this folder with the VM, the outcome is the same except that the password dialog helpfully states "incorrect username or password". My assumption is that the username and password in question is that of the user which owns the shares. I have tried all other username and password combinations available in this context and the outcome is the same. I would like to be able to share files. Sharing them with Windows machines is a nice feature, or would be if it was available. Really I consider sharing files between two machines with the same version of the same operating system kind of a minimum condition for network usability. Samba last functioned reliably for me more than ten years ago. I have attempted to use it on and off since then with only intermittent success. Oh, and "Personal File Sharing" from the Preferences menu does not result in an entry in Places → Network → my-server. In fact, the old entry "MY-SERVER" goes away and is replaced by "koanhead's public files on my-server", which when I attempt to open it from the laptop gives a "DBus.Error.NoReply: Message did not receive a reply." I know I come here and gripe about Ubuntu a lot, but on the other hand I spend literally hours every day trying to fix things in Ubuntu. It's a good system which aspires to greatness, which is why things like this either Need to work; or Be adequately documented. Ideally both would be the case. Anyway, rant over. Hopefully someone will have some insight on this issue. Thanks all who bother to read this wall o'text for your time.

    Read the article

  • Ubuntu One Client 3.02 for windows - Authentication Failure signing in with existing account

    - by steigerj
    I have logged into ubuntu one using a browser successfully. But using the very same login email address and password in the windows client 3.02 gets me an 'authentication failed' message. I am 100% sure I used the same email address and password. My password does not contain any non-ascii characters. Someone suggested to use an older version of the client. Where could i possibly download a complete installer?

    Read the article

  • No access to Samba shares

    - by koanhead
    I have three shared folders in my local home directory- that is to say, on my Ubuntu desktop's /home/me/. All were set up using "Sharing Options" in Nautilus' right-click menu. The standard "Music" and "Videos" folders are configured identically: the "Guest Access" box is checked, but the "Allow others to create and delete" is not. The third folder, called "shared", is configured to not allow Guest access but to allow others to modify files. I have not altered /etc/samba/smb.conf by hand, I have only used Sharing Options to create and modify these so-called "shares". My roommates have two Windows 7 computers and one Ubuntu Netbook Remix netbook. I have the aforementioned desktop machine and laptop running 10.04. None of these machines can access any of the shares. Attempts to access the Guest shares result in the message \\machine\directory is not accessible. The network name could not be found. This is the error message generated by a VM running Windows 2000. The other Windows machines generate a similar error. The Ubuntu laptop gives the error Unable to mount location: Failed to mount Windows share. Hurrah, once again, for informative error messages. That really helps a lot. When attempting to browse the folder called "shared" from the laptop, I'm confronted with a password dialog. This behavior is the same will all machines I've tried in the situation. On entering my username and password for the account to which the shares belong, the password dialog briefly disappears and is replaced with an identical dialog. No error message, useful or not, appears. When attempting to browse this folder with the VM, the outcome is the same except that the password dialog helpfully states "incorrect username or password". My assumption is that the username and password in question is that of the user which owns the shares. I have tried all other username and password combinations available in this context and the outcome is the same. I would like to be able to share files. Sharing them with Windows machines is a nice feature, or would be if it was available. Really I consider sharing files between two machines with the same version of the same operating system kind of a minimum condition for network usability. Samba last functioned reliably for me more than ten years ago. I have attempted to use it on and off since then with only intermittent success. Oh, and "Personal File Sharing" from the Preferences menu does not result in an entry in Places → Network → my-server. In fact, the old entry "MY-SERVER" goes away and is replaced by "koanhead's public files on my-server", which when I attempt to open it from the laptop gives a "DBus.Error.NoReply: Message did not receive a reply." I know I come here and gripe about Ubuntu a lot, but on the other hand I spend literally hours every day trying to fix things in Ubuntu. It's a good system which aspires to greatness, which is why things like this either Need to work; or Be adequately documented. Ideally both would be the case. Anyway, rant over. Hopefully someone will have some insight on this issue. Thanks all who bother to read this wall o'text for your time.

    Read the article

  • How to access UbuntOne when it asks for default keyring which has never been set?

    - by obu-tim
    I am trying to set up UbuntuOne on a new computer and after I enter the email and password, it asks for the keyring 'default'. I don't know what it is and I never set it. Makes it difficult to enter so it seems to be a counterproductive security default. I understand that if autologin is set the keyring is called. I tried setting the main user to need a password but if I reboot it doesn't ask for the password so it sort of autoboots still. So How do I set the keyring default password? If I can't set it I can't install UbuntOne

    Read the article

  • Why doesn't phpMyAdmin connect to MySQL server?

    - by Grafica
    I'm running xampp on Windows 7, and when I type localhost/phpmyadmin, there is an error: phpMyAdmin tried to connect to the MySQL server, and the server rejected the connection. You should check the host, username and password in your configuration and make sure that they correspond to the information given by the administrator of the MySQL server. Here's what I did, but I'm still not able to connect: In config.inc.php, changed from true to false: $cfg['Servers'[$i]['AllowNoPassword'] = false; Changed password here: localhost/security/xamppsecurity.php In resetroot.bat, typed new password where it says 'password': echo REPLACE INTO user VALUES ('localhost', 'pma', 'password', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', 'N', '', '', '', '', 0, 0, 0, 0, '', ''); >>resetroot.sql Restarted apache and mySQL I still get the same error message. Thanks in advance!

    Read the article

  • Dual Monitor Lock Screen Problem

    - by Justin Carver
    Ubuntu 12.04 Nvidia GTX 550-Ti x-swat Nvidia driver Problem: Using 2 monitors. When screen locks there is a blue box on top of the wallpaper and password dialog box that hides the field for entering your password or switching users. Problem is on 2 systems with similar hardware (Nvidia card, x-swat driver, dual monitors) You can still type your password in blindly and hit enter to login but it's irritating to not be able to see the dialog box.

    Read the article

  • Remote connect to mysql server?

    - by LF4
    I've been trying to figure out why I keep getting this error when I try to connect to the MySQL server with the following commands. $~ mysql -u username -h SQLserver -p Enter password: ERROR 1045 (28000): Access denied for user 'username'@'myIP' (using password: YES) I've done the following: Port is open in the firewall other wise I wouldn't get the error it'd just timeout. MySQL server not running with skip-networking or bind-address username has host as '%' and I can connect locally so the password is correct. GRANT USAGE ON *.* TO username@% IDENTIFIED BY 'password'; FLUSH PRIVILEGES; I wanted to know if anyone had ideas or ran into this issue before and solved it? mysql> select user, host from mysql.user where user='username'; +----------+------+ | user | host | +----------+------+ | username | % | +----------+------+ 1 row in set (0.00 sec) mysql> show grants for 'username'; +----------------------------------------------------------------------------------------------------------------+ | Grants for username@% | +----------------------------------------------------------------------------------------------------------------+ | GRANT ALL PRIVILEGES ON *.* TO 'username'@'%' IDENTIFIED BY PASSWORD '*F42AD03PASSWORDHASHADF4021C86B' | | GRANT ALL PRIVILEGES ON `DB2`.* TO 'username'@'%' | +----------------------------------------------------------------------------------------------------------------+ 2 rows in set (0.00 sec)

    Read the article

  • Having problem to login after upgrading from 11.10 to 12.04

    - by LinuxIsMyFriend
    I just update to 12.04 from 11.10 and I get to the login screen w/o problems. When I enter my password the screen turns black and returns to the login screen half a second later. There is a related question out there which was solved by creating more space on the disk but my disks (or rather partitions) are all below 30%. I can log in as guest. I can also login at the cmd prompt (going to tty with Alt+Ctrl+F1) with my normal user credentials. When logged in as guest I can also install programs using my normal account password. There is the normal authentication error when I mistype my password so I'm also sure the password works. Any suggestions?

    Read the article

  • Cannot change User Accounts settings

    - by eimmy
    I recently changed the name of the administrator and turned off passwords then clicked lock. After some time, I decided to add a password so I clicked on unlock and it's prompting me to enter a password. I tried typing the old password and it didn't accepted it. I also tried to set password and keys as "set to default" but still nothing happened. Now I'm stuck and can't get to change the administrator settings. I did my research but nothing seems to work. Please help.

    Read the article

  • Why my register form don't accept spry validation in dw? [migrated]

    - by shaghayeh
    Why my register form don't accept spry validation in dw? Here is my code: <?php if(isset($_POST['go_register'])) { $last_login=jdate('Y/n/j ,H:i:s'); $firstname=trim($_POST['firstname']); $lastname=trim($_POST['lastname']); $email=trim($_POST['username']); $password=sha1($_POST['password']); $register_date=$_POST['register_date']; if(!empty($firstname)&& !empty($lastname)&& !empty($email)&& !empty($password)&& !empty($register_date)){ $reg_query="insert into users(firstname,lastname,email,password,register_date,last_login)values('$firstname','$lastname','$email','$password','$register_date','$last_login')"; $reg_result=mysqli_query($connection,$reg_query); if($reg_result){ echo "ok"; } }//end of not empty }//end of isset ?> <div class="sectionclass"> <script src="../SpryAssets/SpryValidationTextField.js" type="text/javascript"></script> <link href="../SpryAssets/SpryValidationTextField.css" rel="stylesheet" type="text/css"> <h2>??? ??? ???</h2> <form method="post" action="<?php echo $_SERVER['PHP_SELF']."?catid=2"; ?>"> <div> <span style="color:#F00">*</span> <label>??? </label> <span id="sprytextfield1"> <input type="text" name="firstname" /> <span class="textfieldRequiredMsg">A value is required.</span></span></div> <div> <span style="color:#F00">*</span> <label>??? ????????</label><input type="text" name="lastname" /> </div> <div> <span style="color:#F00">*</span> <label>??? ??????(?????)</label><input dir="ltr" type="text" name="username" /> </div> <div> <span style="color:#F00">*</span> <label>??? ????</label><input type="password" name="password" /> </div> <input type="hidden" name="register_date" value="<?php echo jdate('Y/n/j'); ?>"> <div> <input type="submit" name="go_register" value="??? ???"/> </div> </form> </div> <script type="text/javascript"> var sprytextfield1 = new Spry.Widget.ValidationTextField("sprytextfield1"); </script>

    Read the article

  • Securing Web Service communication with SSL using CXF

    - by reef
    Hi all, I am trying to secure communications via SSL/TLS for one of our Web Service using CXF 2.2.5. I am wondering how to update client and server Spring configuration file to activate this feature. I found some information on CXF's website (CXF Wiki) for the client configuration, here is the given example: <http:conduit name="{http://apache.org/hello_world}HelloWorld.http-conduit"> <http:tlsClientParameters> <sec:keyManagers keyPassword="password"> <sec:keyStore type="JKS" password="password" file="src/test/java/org/apache/cxf/systest/http/resources/Morpit.jks"/> </sec:keyManagers> <sec:trustManagers> <sec:keyStore type="JKS" password="password" file="src/test/java/org/apache/cxf/systest/http/resources/Truststore.jks"/> </sec:trustManagers> <sec:cipherSuitesFilter> <!-- these filters ensure that a ciphersuite with export-suitable or null encryption is used, but exclude anonymous Diffie-Hellman key change as this is vulnerable to man-in-the-middle attacks --> <sec:include>.*_EXPORT_.*</sec:include> <sec:include>.*_EXPORT1024_.*</sec:include> <sec:include>.*_WITH_DES_.*</sec:include> <sec:include>.*_WITH_NULL_.*</sec:include> <sec:exclude>.*_DH_anon_.*</sec:exclude> </sec:cipherSuitesFilter> </http:tlsClientParameters> <http:authorization> <sec:UserName>Betty</sec:UserName> <sec:Password>password</sec:Password> </http:authorization> <http:client AutoRedirect="true" Connection="Keep-Alive"/> </http:conduit> Concerning this configuration, the Concerning the server side configuration I am unable to launch the server properly, here is the configuration I have: <http:destination name="{urn:ihe:iti:xds-b:2007}DocumentRepository_Port_Soap12.http-destination"> </http:destination> <httpj:engine-factory> <httpj:engine port="9043"> <httpj:tlsServerParameters> <sec:keyManagers keyPassword="changeit"> <sec:keyStore type="JKS" password="changeit" file="security/keystore.jks" /> </sec:keyManagers> <sec:trustManagers> <sec:keyStore type="JKS" password="changeit" file="security/cacerts.jks" /> </sec:trustManagers> <sec:cipherSuitesFilter> <!-- these filters ensure that a ciphersuite with export-suitable or null encryption is used, but exclude anonymous Diffie-Hellman key change as this is vulnerable to man-in-the-middle attacks --> <sec:include>.*_EXPORT_.*</sec:include> <sec:include>.*_EXPORT1024_.*</sec:include> <sec:include>.*_WITH_DES_.*</sec:include> <sec:include>.*_WITH_NULL_.*</sec:include> <sec:exclude>.*_DH_anon_.*</sec:exclude> </sec:cipherSuitesFilter> <sec:clientAuthentication want="true" required="true" /> </httpj:tlsServerParameters> </httpj:engine> </httpj:engine-factory> But when I run my application server (JOnas) with this configuration I have the following error message: Line 20 in XML document from ServletContext resource [/WEB-INF/beans.xml] is invalid; nested exception is org.xml.sax.SAXParseException: cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'httpj:engine-factory'. Do you guys know how to solve this issue? Thanks in advance,

    Read the article

  • ASP.NET Membership API not working on Win2008 server/IIS7

    - by Program.X
    I have a very odd problem. I have a web app that uses the .NET Membership API to provide login functionality. This works fine on my local dev machine, using WebDev 4.0 server. I'm using .NET 4.0 with some URL Rewriting, but not on the pages where login is required. I have a Windows Server 2008 with IIS7 However, the Membership API seemingly does not work on the server. I have set up remote debugging and the LoginUser.LoggedIn event of the LoginUser control gets fired okay, but the MembershipUser is null. I get no answer about the username/password being invalid so it seems to be recognising it. If I enter an invalid username/password, I get an invalid username/password response. Some code, if it helps: <asp:ValidationSummary ID="LoginUserValidationSummary" runat="server" CssClass="validation-error-list" ValidationGroup="LoginUserValidationGroup"/> <div class="accountInfo"> <fieldset class="login"> <legend>Account Information</legend> <p> <asp:Label ID="UserNameLabel" runat="server" AssociatedControlID="UserName">Username:</asp:Label> <asp:TextBox ID="UserName" runat="server" CssClass="textEntry"></asp:TextBox> <asp:RequiredFieldValidator ID="UserNameRequired" runat="server" ControlToValidate="UserName" CssClass="validation-error" Display="Dynamic" ErrorMessage="User Name is required." ToolTip="User Name is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p> <asp:Label ID="PasswordLabel" runat="server" AssociatedControlID="Password">Password:</asp:Label> <asp:TextBox ID="Password" runat="server" CssClass="passwordEntry" TextMode="Password"></asp:TextBox> <asp:RequiredFieldValidator ID="PasswordRequired" runat="server" ControlToValidate="Password" CssClass="validation-error" Display="Dynamic" ErrorMessage="Password is required." ToolTip="Password is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p> <asp:CheckBox ID="RememberMe" runat="server"/> <asp:Label ID="RememberMeLabel" runat="server" AssociatedControlID="RememberMe" CssClass="inline">Keep me logged in</asp:Label> </p> </fieldset> <p class="login-action"> <asp:Button ID="LoginButton" runat="server" CommandName="Login" CssClass="submitButton" Text="Log In" ValidationGroup="LoginUserValidationGroup"/> </p> and the code behind: protected void Page_Load(object sender, EventArgs e) { LoginUser.LoginError += new EventHandler(LoginUser_LoginError); LoginUser.LoggedIn += new EventHandler(LoginUser_LoggedIn); } void LoginUser_LoggedIn(object sender, EventArgs e) { // this code gets run so it appears logins work Roles.DeleteCookie(); // this behaviour has been removed for testing - no difference } void LoginUser_LoginError(object sender, EventArgs e) { HtmlGenericControl htmlGenericControl = LoginUser.FindControl("errorMessageSpan") as HtmlGenericControl; if (htmlGenericControl != null) htmlGenericControl.Visible = true; } I have "Fiddled" with the Login form reponse and I get the following Cookie-Set headers: Set-Cookie: ASP.NET_SessionId=lpyyiyjw45jjtuav1gdu4jmg; path=/; HttpOnly Set-Cookie: .ASPXAUTH=A7AE08E071DD20872D6BBBAD9167A709DEE55B352283A7F91E1066FFB1529E5C61FCEDC86E558CEA1A837E79640BE88D1F65F14FA8434AA86407DA3AEED575E0649A1AC319752FBCD39B2A4669B0F869; path=/; HttpOnly Set-Cookie: .ASPXROLES=; expires=Mon, 11-Oct-1999 23:00:00 GMT; path=/; HttpOnly I don't know what is useful here because it is obviously encrypted but I find the .APXROLES cookie having no value interesting. It seems to fail to register the cookie, but passes authentication

    Read the article

  • C#, AES encryption check!

    - by Data-Base
    I have this code for AES encryption, can some one verify that this code is good and not wrong? it works fine, but I'm more concern about the implementation of the algorithm // Plaintext value to be encrypted. //Passphrase from which a pseudo-random password will be derived. //The derived password will be used to generate the encryption key. //Password can be any string. In this example we assume that this passphrase is an ASCII string. //Salt value used along with passphrase to generate password. //Salt can be any string. In this example we assume that salt is an ASCII string. //HashAlgorithm used to generate password. Allowed values are: "MD5" and "SHA1". //SHA1 hashes are a bit slower, but more secure than MD5 hashes. //PasswordIterations used to generate password. One or two iterations should be enough. //InitialVector (or IV). This value is required to encrypt the first block of plaintext data. //For RijndaelManaged class IV must be exactly 16 ASCII characters long. //KeySize. Allowed values are: 128, 192, and 256. //Longer keys are more secure than shorter keys. //Encrypted value formatted as a base64-encoded string. public static string Encrypt(string PlainText, string Password, string Salt, string HashAlgorithm, int PasswordIterations, string InitialVector, int KeySize) { byte[] InitialVectorBytes = Encoding.ASCII.GetBytes(InitialVector); byte[] SaltValueBytes = Encoding.ASCII.GetBytes(Salt); byte[] PlainTextBytes = Encoding.UTF8.GetBytes(PlainText); PasswordDeriveBytes DerivedPassword = new PasswordDeriveBytes(Password, SaltValueBytes, HashAlgorithm, PasswordIterations); byte[] KeyBytes = DerivedPassword.GetBytes(KeySize / 8); RijndaelManaged SymmetricKey = new RijndaelManaged(); SymmetricKey.Mode = CipherMode.CBC; ICryptoTransform Encryptor = SymmetricKey.CreateEncryptor(KeyBytes, InitialVectorBytes); MemoryStream MemStream = new MemoryStream(); CryptoStream CryptoStream = new CryptoStream(MemStream, Encryptor, CryptoStreamMode.Write); CryptoStream.Write(PlainTextBytes, 0, PlainTextBytes.Length); CryptoStream.FlushFinalBlock(); byte[] CipherTextBytes = MemStream.ToArray(); MemStream.Close(); CryptoStream.Close(); return Convert.ToBase64String(CipherTextBytes); } public static string Decrypt(string CipherText, string Password, string Salt, string HashAlgorithm, int PasswordIterations, string InitialVector, int KeySize) { byte[] InitialVectorBytes = Encoding.ASCII.GetBytes(InitialVector); byte[] SaltValueBytes = Encoding.ASCII.GetBytes(Salt); byte[] CipherTextBytes = Convert.FromBase64String(CipherText); PasswordDeriveBytes DerivedPassword = new PasswordDeriveBytes(Password, SaltValueBytes, HashAlgorithm, PasswordIterations); byte[] KeyBytes = DerivedPassword.GetBytes(KeySize / 8); RijndaelManaged SymmetricKey = new RijndaelManaged(); SymmetricKey.Mode = CipherMode.CBC; ICryptoTransform Decryptor = SymmetricKey.CreateDecryptor(KeyBytes, InitialVectorBytes); MemoryStream MemStream = new MemoryStream(CipherTextBytes); CryptoStream cryptoStream = new CryptoStream(MemStream, Decryptor, CryptoStreamMode.Read); byte[] PlainTextBytes = new byte[CipherTextBytes.Length]; int ByteCount = cryptoStream.Read(PlainTextBytes, 0, PlainTextBytes.Length); MemStream.Close(); cryptoStream.Close(); return Encoding.UTF8.GetString(PlainTextBytes, 0, ByteCount); } Thank you

    Read the article

  • Moving from MySQL to MySQLi? I have the code here but I don't get it

    - by MuqMan
    I have posted the code there, please help me out as I am a newbie, I don't know much in terms of deprecation and stuff. <?php session_start(); include('settings.php'); $issub = $_POST['issub']; if($issub == "yes") { require('settings.php'); $dbcon = mysql_connect($dbhost, $dbuser, $dbpword); if(!dbcon) { die('Could not connect'.mysql_error()); } $selectdb = mysql_select_db($db, $dbcon); $formset = 'yes'; $val = 0; $user = trim($_POST['username'], ' '); $luser = mysql_real_escape_string($user); $password = $_POST['password']; $lpassword = mysql_real_escape_string($password); $selectdb; $userq = mysql_query("SELECT user FROM users WHERE user='".$luser."'"); $userresult = @mysql_result($userq, 0); //echo $userresult; if($userresult == $user) { $val = $val + 1; $usercorrect = 'yes'; } else { $usercorrect = 'no'; } $dbselect; $passwordq = mysql_query("SELECT password FROM users where user='".$luser."'"); $passresult = @mysql_result($passwordq, 0); if($passresult == sha1($password)) { $val = $val + 1; $passcorrect = 'yes'; } else { $passcorrect = 'no'; } if ($val == 2) { $_SESSION['loggedin'] = 'yes'; $_SESSION['uloggedin'] = $user; header('location: logged.php'); } }?> <?php ini_set('display_errors', 1); require('testinclude.php'); ?> <body> <div id="loginform"> <form action="/login.php" method="post" > <input type="hidden" name="issub" value="yes" /> <?php if($usercorrect == 'no') { echo '<span class="required"><i><small>The email address or password you entered is incorrect, please try again.</a></small></i></span>'; } ?> <br /> email: <?php if ($issub == 'yes') { if($user == null){ echo '<br /><span class="required"><i><small>Please enter your email address</a></small></i></span>'; } } ?> <br /><input type="text" name="username" id="usename" /> <br /> password: <br /><input type="password" name="password" id="password" /> <br /> <input type="submit" value="login" /> </form> <div> </body>

    Read the article

< Previous Page | 82 83 84 85 86 87 88 89 90 91 92 93  | Next Page >