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  • Get page url using javascript

    - by Alex
    Hello, could some one recommend a way to get page name from a url using JavaScript? For instance if I have http://www.cnn.com/news/1234/news.html?a=1&b=2&c=3 I just need to get "news.html" string Thanks!

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  • Double "!!" in Ruby [closed]

    - by Alex Maslakov
    Possible Duplicate: What does !! mean in ruby? Ruby, !! operator (a/k/a the double-bang) Sometimes I see a Ruby code like this def sent? !!@sent_at end It seems to be not logical. Is it necessary to use here double !? As far as I'm concerned, it might be just def sent? @sent_at end UPDATE: then what is the difference between these def sent? !!@sent_at end def sent? @sent_at.nil? end def sent? @sent_at == nil end

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  • Select <a> which is the second <a> on a page that contains the same href text? jQuery

    - by Alex
    Hello there, I'm working with a page that has several links that contain the same href text, and I need to select the second anchor element on the page that contains said href text. Here's a simplified version of the link structure of the page: <a href="same/link/to/stuff/">same link</a> <a href="same/link/to/stuff/">same link</a> How do I fashion my selector so that it only selects the second anchor in the above example? Currently I'm trying: $('a[href=same/link/to/stuff/] :eq(1)') but it is not working. Thanks!!

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  • mysql connect error issue

    - by Alex
    I've php page which update Mysql Db. I don't understand why my following php code is saying that "Could not update marker. No database selected". Strange!! can you please tell me why it's showing error message. Thanks. Php code: <?php // database settings $db_username = 'root'; $db_password = ''; $db_name = 'parkool'; $db_host = 'localhost'; //mysqli $mysqli = new mysqli($db_host, $db_username, $db_password, $db_name); if (mysqli_connect_errno()) { header('HTTP/1.1 500 Error: Could not connect to db!'); exit(); } ################ Save & delete markers ################# if($_POST) //run only if there's a post data { //make sure request is comming from Ajax $xhr = $_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest'; if (!$xhr){ header('HTTP/1.1 500 Error: Request must come from Ajax!'); exit(); } // get marker position and split it for database $mLatLang = explode(',',$_POST["latlang"]); $mLat = filter_var($mLatLang[0], FILTER_VALIDATE_FLOAT); $mLng = filter_var($mLatLang[1], FILTER_VALIDATE_FLOAT); $mName = filter_var($_POST["name"], FILTER_SANITIZE_STRING); $mAddress = filter_var($_POST["address"], FILTER_SANITIZE_STRING); $mId = filter_var($_POST["id"], FILTER_SANITIZE_STRING); /*$result = mysql_query("SELECT id FROM test.markers WHERE test.markers.lat=$mLat AND test.markers.lng=$mLng"); if (!$result) { echo 'Could not run query: ' . mysql_error(); exit; } $row = mysql_fetch_row($result); $id=$row[0];*/ //$output = '<h1 class="marker-heading">'.$mId.'</h1><p>'.$mAddress.'</p>'; //exit($output); //Update Marker if(isset($_POST["update"]) && $_POST["update"]==true) { $results = mysql_query("UPDATE parkings SET latitude = '$mLat', longitude = '$mLng' WHERE locId = '94' "); if (!$results) { //header('HTTP/1.1 500 Error: Could not Update Markers! $mId'); echo "coudld not update marker." . mysql_error(); exit(); } exit("Done!"); } $output = '<h1 class="marker-heading">'.$mName.'</h1><p>'.$mAddress.'</p>'; exit($output); } ############### Continue generating Map XML ################# //Create a new DOMDocument object $dom = new DOMDocument("1.0"); $node = $dom->createElement("markers"); //Create new element node $parnode = $dom->appendChild($node); //make the node show up // Select all the rows in the markers table $results = $mysqli->query("SELECT * FROM parkings WHERE 1"); if (!$results) { header('HTTP/1.1 500 Error: Could not get markers!'); exit(); } //set document header to text/xml header("Content-type: text/xml"); // Iterate through the rows, adding XML nodes for each while($obj = $results->fetch_object()) { $node = $dom->createElement("marker"); $newnode = $parnode->appendChild($node); $newnode->setAttribute("name",$obj->name); $newnode->setAttribute("locId",$obj->locId); $newnode->setAttribute("address", $obj->address); $newnode->setAttribute("latitude", $obj->latitude); $newnode->setAttribute("longitude", $obj->longitude); //$newnode->setAttribute("type", $obj->type); } echo $dom->saveXML();

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  • JQuery validation using is() and multiple CSS classes

    - by Alex
    Hi Folks, Trying to debug something that basically .trim()'s, .val()'s and .length's a textarea input as HTML below (truncated): <form id="Kontaktanfrage" method="post" action="tests/testform/"> ... <textarea cols="50" rows="8" id="el_12" name="FORM[Kontaktanfrage][el_12]" title="Ihre Nachricht: *" class="textarea required"></textarea> ... </form> JavaScript: function validateField(formId, fieldId) { if (fieldId) { var element = "form#"+formId+" input#"+fieldId; var fieldValue = jQuery.trim(jQuery(element).val()); var fieldLength = fieldValue.length; var fieldError = ""; if ($(element).is('.textarea.required') && fieldLength == 0) { fieldError = "error message"; } } } The above if check is never true. Using JQuery: 1.4.1. Having seen other examples online, I can't see what the difference should be. Feel free to test it in FireBug at (http://www.initiat.de/tests/testform/). Any help appreciated, can't see what I'm doing wrong.

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  • contents().find() not producing the same result as changing selector context? - jQuery

    - by Alex
    Hello all, I have a function that looks somewhat like this: function(domObj) { var currentObj = $(domObj); ... currentObj.contents().find(".ws").after("foobar"); } My problem is that the above method of using .contents().find() is not working. "foobar" never gets stuffed after the specified dom element, represented by the selector, .ws However if I do this: $(".ws", currentObj).after("foobar"); Then the string, "foobar" gets appended every time. My question: Are not these two methods supposed to be equivilant? How/what am I doing wrong in my use of .contents().find() so that it is not working? Thanks!

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  • How do I access the array submit() calls in the dom?

    - by Alex
    I want to grab all the inputs inside a form, in order to submit them. The point of this is to use jquery's ajax to submit a dynamically sized form. Surely there must be an array inside the dom somewhere which i can just do something like... docment.forms['form'].elements which only lists inputs for that form, meaning I can loop through them and grab their values to play around with?

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  • jquery - how to get number from a string with mixture of letters and number

    - by Alex
    How do I use JQuery to get number from the drop down select? <select aria-invalid="false" id="RatePercent" class="wpcf7-form-control wpcf7-select ratePercent" name="RatePercent"> <option value="">---</option> <option value="Floating-6.5%">Floating-6.5%</option> <option value="6 Months-5.65%">6 Months-5.65%</option> <option value="1 Year-5.85%">1 Year-5.85%</option> <option value="18 Months-5.99%">18 Months-5.99%</option> <option value="2 Years-6.19%">2 Years-6.19%</option> <option value="3 Years-6.85%">3 Years-6.85%</option> <option value="4 Years-7.19%">4 Years-7.19%</option> <option value="5 Years-7.40%">5 Years-7.40%</option> </select> If you choose 1 Year-5.85%, it returns '5.85', instead of '1 Year-5.85%'?

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  • What would be the most efficient way to do this search (mysql or text)?

    - by alex
    Suppose I have 500 rows of data, each with a paragraph of text (like this paragraph). That's it.I want to do a search that is not only based on words. (%LIKE%, not FULL_TEXT) What would be faster? SELECT * FROM ...WHERE LIKE "%query%"; This would put load on the database server. Select all. Then, go through each one and do .find = 0 This would put load on the web server. This is a website, and people will be searching frequently.

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  • What is the easiest way to set the value of an entire array?

    - by Alex
    My current project requires me to fill an array based upon some other values. I know there's the shortcut: int arr[4][4] = { {0,0,0,0} , {0,0,0,0} , {0,0,0,0} , {0,0,0,0} }; But in this case, I need to fill the array after its declaration. I currently have my code formatted like this: int arr[4][4]; if(someothervariable == 1){ arr = { {1,1,1,1}, {1,2,3,4}, {2,,3,4,5}, {3,4,5,6} }; } But it won't compile. Is there a way to make use of the mentioned shortcut in my case? If not, whats the best fix available? I'd appreciate a way to set it without explicitly assigning each element? ie: arr[0][0] = ...

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