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  • Updating .XML through SQL server 2000

    - by neeraj
    Hello Everyone, I want to apply a update trigger on a table in SQL server 2000. Trigger should update .XML file present on another server. I have full access to both servers. I am unable to figure how to do it, please help me out.

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  • best book to start XML and Html5?

    - by asad26
    hey every one can some one help that , how can start XML and Html and what i have to start first and what steps should I take , and because I know Objective c as iphone programmer but i what to know more about web base application so please some one help me with steps should I take and as beginner? thanks

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  • linq to xml return second element

    - by Phil
    Hi Im trying to return to the second element in the xml from flickr. This always returns the first element: ImageUrl = item.Element(ns + "link").Attribute("href").Value, and this errors? ImageUrl = item.Elements(ns + "link")[1].Attribute("href").Value, Thanks

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  • Can't parse XML from AJAX response.

    - by Pavel
    Hi everyone. I'm having some problems with parsing the xml response from my ajax script. The XML looks like this: <IMAGE> <a href="address"> <img width="300" height="300" src="image.png class="image" alt="" title="LINKING"/> </a> </IMAGE> <LINK> www.address.com </LINK> <TITLE> This <i>is title</i> </TITLE> <EXCERPT> <p> And some excerpt </p> </EXCERPT> The code for js looks like this. function loadTab(id) { if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { xmlDoc=xmlhttp.responseXML; var title=""; var image=""; x=xmlDoc.getElementsByTagName("TITLE"); for (i=0;i<1;i++) { title=title + x[i].childNodes[0].nodeValue; } document.getElementById("ntt").innerHTML=title; x1=xmlDoc.getElementsByTagName("IMAGE"); for (j=0;j<1;j++) { image=image + x1[j].childNodes[0].nodeValue; } document.getElementById("nttI").innerHTML=image; } } var url = 'http://www.factmag.com/staging/page/?id='+id; xmlhttp.open("GET",url,true); xmlhttp.send(); } When I'm parsing it it pulls out the title but not the IMAGE tag contents. What I'm doing wrong? Can someone please tell me? Thanks in advance!

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  • C#: Deal with xml, treeview datagridview and datatables

    - by renulren
    Hi all, I am working on a project that pulls data out of an xml files and also uses a tree-grid combination in order to display the data. For example depending on the selected treeview node, the datagridview will display only the records related to that node. What do you think it would be the appropriate approach in dealing with this? Thanks!

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  • Joomla plugin install XML files <folder> tag

    - by Rixius
    While developing a joomla plugin, if my plugin folder looks like so: /install.xml /mainPg.php /subfolder/lib.php /subfolder/config.php Would the tag look like this? <files> <filename plugin="mainPg">mainPg.php</filename> <folder>subfolder</folder> </files>

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  • Viewing large XML files in eclipse?

    - by Paul Wicks
    I'm working on a project involving some large XML files (from 50MB to over 1GB) and it would be nice if I could view them in eclipse (simple text view is fine) without Java running out of heap space. I've tried tweaking the amount of memory available to the jvm in eclipse.ini but haven't had much success. Any ideas?

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  • XML Parsing Error: not well-formed

    - by jcure
    I get the above error when viewing a xml document. The problem seems to be the second ( = ) in the following link. http://mysite.com/viewpage.php?u=1020&op=new In the link & is replaced by & amp; without the space. Any help as to why this is throwing an error would be greatly appreciated.

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  • How to merge 2 XML streams in Java by XSLT

    - by user327933
    I'd like to merge 2 XML streams (strings) in Java, necessarily by XSLT (that I could change the transformation), but the problem is that the XMLs come as a string. There are many examples, but through the files. Can this be done without saving them in files? Thanks.

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  • XML Import how would you do it?

    - by Rico
    XML is used as one of our main integration points. it comes over by many clients at a time but too many clients importing at the same time can slow down our database to a crawl. Someone has to have solved a problem like this. I am basically using VB to parse through the data and import what i want and don't want. Is there a better way?

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  • programming language xml reader

    - by matt
    Indentify a suitable programming language that will read the XML document and insert its contents into the database. i need help with this question i am getting really confused can some one show me and guide me thorught how to do this

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  • How to get search results in XML format

    - by Shibin Moideen
    Hi, I am planning to make an iPhone search app. the user types in the search string. the string will be searched by some search engines like Google, Live, Yahoo ... I need to get the search result in the XML format. Is there any way to do this. Help needed. Please. Thanks and regards, Shibin

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  • Passing input value thru XML loop and return value

    - by Mike Dyer
    "X" is reading the form value, but it is still passing and older "var thisMarket" value. The objective is to take a zip code via HTML form: <form id="market" name="market" onSubmit="return validateZIP(this.zip.value);" method="get" action=""> <input type="text" name="zip" id="zip" value="zipcode" onfocus="if(!this._haschanged){this.value=''};this._haschanged=true;" style="float:left; width:100px; margin-top:5px;"> <input type="image" style="float:left; margin-top:5px; border: 0pt none ; width: 22px; height:17px;" src="images/nav/bottom/linkbar/btn_search_btn.gif" onClick="findLda();"> </form> The script being passed thru is: function findLda(x){ marketName = new Array(); marketURL = new Array(); zip = new Array(); zip_temp = new Array(); zipMatch = false; var shareZip = "Shared Zips"; var thisMarket = "Market value"; xmlDoc=loadXML("/_includes/market.xml"); var Offer,node; document.getElementById('market').innerHTML=''; for(var j=0; j<xmlDoc.getElementsByTagName('market').length; j++){ node = xmlDoc.getElementsByTagName('market')[j]; marketName.push(node.childNodes[3].textContent); marketURL.push(node.childNodes[5].textContent); for(var k=0; k<node.getElementsByTagName('zip').length; k++){ if(node.getElementsByTagName('zip')[k].textContent!=null){ zip_temp.push(node.getElementsByTagName('zip')[k].textContent); } } zip.push(zip_temp); zip_temp = new Array(); } //loop the zip Array to find a match for the query Zip. for(k=0; k<zip.length; k++){ for(m=0; m<zip[k].length; m++){ if(x == zip[k][m].toString()){ zipMatch=true; thisMarket=marketName[k].toString(); } } } alert(thisMarket); } The objective naturally is to take field input (A), pass it thru market.xml - initialize a loop and match a zip (B), alert the result (C). Looking for any direction with what is existing or a completely new direction. Thanks!

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  • WP7 Return the last 7 days of data from an xml web service

    - by cvandal
    Hello, I'm trying to return the last 7 days of data from an xml web service but with no luck. Could someone please explain me to how I would accomplish this? The XML is as follows: <node> <api> <usagelist> <usage day="2011-01-01"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-02"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-03"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-04"> <traffic name="total" unit="bytes">23579797</traffic> </usage> </usagelist> </api> </node> EDIT The data I want to retrieve will be used to populate a line graph. Specificly I require the day attribute value and the traffic element value for the past 7 days. At the moment, I have the code below in place, howevewr it's only showing the first day 7 times and traffic for the first day 7 times. XDocument xDocument = XDocument.Parse(e.Result); var values = from query in xDocument.Descendants("usagelist") select new History { day = query.Element("usage").Attribute("day").Value, traffic = query.Element("usage").Element("traffic").Value }; foreach (History history in values) { ObservableCollection<LineGraphItem> Data = new ObservableCollection<LineGraphItem>() { new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, }; lineGraph1.DataSource = Data; }

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